What is a joule?
1 foot/lb
1 meter per second squared
1 meter
1 N-m
Answer:
Input Output
1 ft-lb 12 in-lb
1 in-lb 0.113 Nm
1 Nm 0.7376 ft-lb
1 in-lb 0.0833 ft-lb
1 ft-lb 1.3558179 Nm
1 in-lb 15.999999461875 in-oz
1 Nm 8.850746106833 in-lb
1 l-atm 101.325 J
1 Nm 3.72506E-7 hph
1 J 1 Nm
Explanation:
please mark as briliant
Answer:
1N-m
Explanation:
teacher just taught this an hour ago for my class
Two cars start moving from the same point on a rectilinear path at the same time, heading to the same destination 90 km away. The first travels at an average speed of 50 km/h and the second at 60 km/h. Deter- mine the time interval separating the arrival of the two cars to their destination.
Answer:
0.3 hour
Explanation:
From the question given above, the following data were obtained:
Distance travelled = 90 km
Speed of 1st car = 50 km/h
Speed of 2nd car = 60 km/h
Time interval separating the two cars =?
Next, we shall determine the time taken for each car to get to the destination. This can be obtained as follow:
For the 1st car:
Distance travelled (d) = 90 km
Speed of 1st car (S₁) = 50 km/h
Time (t₁) =?
Speed = Distance /time
S₁ = d/t₁
50 = 90 / t₁
Cross multiply
50 × t₁ = 90
Divide both side by 50
t₁ = 90 / 50
t₁ = 1.8 hours
For the 2nd car:
Distance travelled (d) = 90 km
Speed of 2nd car (S₂) = 60 km/h
Time (t₂) =?
Speed = Distance /time
S₂ = d/t₂
60 = 90 / t₂
Cross multiply
60 × t₂ = 90
Divide both side by 60
t₂ = 90 / 60
t₂ = 1.5 hours
Finally, we shall determine the time interval separating the arrival of the two cars. This can be obtained as follow:
Time for the 1st car (t₁) = 1.8 hours
Time for the 2nd (t₂) = 1.5 hours
Time interval separating the two cars (tₛ) =?
tₛ = t₁ – t₂
tₛ = 1.8 – 1.5
tₛ = 0.3 h
Thus, the interval separating the arrival of the two cars is 0.3 hour
What is the distance from one peak to the next peak called?
Answer:
wavelength
Explanation:
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.
Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.
Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data.
The distance from one peak to the next peak is called wavelength. This distance is also equal to the distance from one trough of a wave to another.
Mathematically, wavelength is calculated using this formula;
[tex] Wavelength = \frac {speed}{frequency} [/tex]
Electromagnetic waves are
O
A. forms of matter.
O
B. forms of space.
O
C. longitudinal waves.
O
D. transverse waves.
A body is at equilibrium under the action of three forces. One force is 10N acting due east and one is 5N in the direction 60° north east. What is the magnitude and direction of the third force?
Answer:
If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.
F(1x)=F(1)=10 N
F(2x)=F(2)cos60=5•0.5=2.5 N
F(2y) =F(2)sin60 = 5•0.866= 4.33 N
F(3x) =- F(x)=- (10+2.5 )= -12.5 N
F(3y) =- F(2y)= - 4.33 N
F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N
tan φ = F(3y)/F(3x) =4.33/12.5=0.364
φ = 19.1⁰ (south-west)
Explanation:
Under constant acceleration, the average velocity of a particle is half the sum of its initial and final
velocities. Is this still true if the acceleration is not constant? Explain.
Answer:
It is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle is not constant
Explanation:
The motion of a particle under constant acceleration, 'a', is be given by the following kinematic equations;
v² = u² + 2·a·s
v = u + a·t
Where;
v = The final velocity of the particle
u = The initial velocity of the particle
a = The acceleration of the particle
s = The distance through which the particle travels
t = The time of motion of the particle
By simplifying the above equation, we have;
v² - u² = 2·a·s
(v² - u²)/(2·a) = s
(v - u) × (v + u)/(2 × a) = s
((v - u)/a) × ((v + u)/2) = s
From v = u + a·t, we have;
t = (v - u)/a
∴ ((v - u)/a) × ((v + u)/2) = t × ((v + u)/2) = s
∴ ((v + u)/2) = s/t
The average velocity = (Total distance traveled by the particle) ÷ (The time of travel of the particle)
∴ The average velocity = s/t = ((v + u)/2) = Half the sum of the initial and final velocity
However, it is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle, 'a', is not constant, as the velocity time graph is no longer a straight line graph and the distance traveled by the particle, 's', which is the area under the velocity time graph, 'A', (given by the sum of area of the triangle and the rectangle given by the area under straight line graph for constant velocity) cannot be given directly by the product of the time and the average velocity.
A plane taxies onto the runway, preparing for take off. It starts at rest before it's engines start. The plane's top speed, before it takes off the ground, is about 8820 km/s. If the take off takes about 32.8s, what is the acceleration of the plane?
Answer:
Explanation:
This is a fast plane! At it's takeoff speed, it could fly around the world in 5 seconds!
Acceleration is defined as the change in speed over the change in time.
[tex]a = \frac{v_f - v_o}{t}[/tex]
Where v_f is the final velocity, v_o is the original velocity, and t is the time.
We know v_f = 8820km/s.
v_o = 0 km/s. The plane "starts at rest before it's engine start." So we know it starts from zero velocity.
t = 32.8 seconds.
You can solve the equation from there.
Alyssa is taking a walk on a nature path near her neighborhood. She
carries a compass with her. As she walks along the path, she notices
the needle on the compass is occasionally deflected from its original
position. If she has not changed the direction she is walking, what is
most likely causing the occasional shift in the needle? (1 point)
O Changes in pressure
0 Changes in temperature
O Sources of electrical current
O Changes to Earth's magnetic field
Answer:
C. Sources of electrical current!
Hope this helps :)
Answer:
Sources of electrical current
Explanation:
Got it right on the test.
A minibus drives with a constant speed of 32 km/h. How long will it take to travel a distance of 48 kilometers?
Distance covered = (speed) x (time)
Time = (Distance covered) / (speed)
Time = (48 km) / (32 km/hr)
Time = (48/32) hr
Time = 1.5 hrs (1 hour 30 minutes)
A 2750 kg helicopter flies horizontally at constant speed. Air resistance creates a 7510 n backward force. What is the magnitude of the lift force created by the propellers
Answer:
Explanation:
Let lift force F be created by propellers at angle of Ф with the horizontal .
The vertical component of this force will balance the weight of helicopter and horizontal component will balance the air resistance .
F sinФ = mg = 2750 x 9.8 = 26950 N
F cosФ = 7510 N
Squaring and adding ,
F² = 26950² + 7510²
= 726302500 + 56400100
= 782702600
F = 27976.82 N .
How many different atoms are there in a compound?
Answer:
2 or more atoms
Explanation:
yes yes yes yes yes yes yes yes
Answer:
Two or more
Explanation:
It's mostly two but unique structures might compose of more than 2
Kerry drops her iPhone accidently as she is standing on an overview. How fast is the iPhone moving after 3s?
Answer:
really fast? xP
Explanation:
What will be the value of both charges if they are 5 cm apart and suffer a
attraction force of 5.2 N.
Answer:
[tex] \boxed{q = 1.2 \times {10}^{ - 6} C}[/tex]
Explanation:
[tex]f_e = \frac{{q}^{2}k }{ {r}^{2} } \\ q = \sqrt{ \frac{f_e( {r}^{2} )}{k} } = \sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } \\ q =\sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } = \sqrt{ \frac{0.013}{9 \times {10}^{9} } } \\ q = 1.2 \times {10}^{ - 6} [/tex]
Which radio wave technologies would be unaffected by satellites that are not working properly?
space communication and television broadcasting television broadcasting and GPS O MRI and radio telescopes
O radio telescopes and space communication
Answer:
MRI and Radio telescopes
MRI and radio telescopes would be unaffected by satellites that are not working properly.
What is radio wave?The longest wavelengths in the electromagnetic spectrum are found in radio waves, which typically have frequencies of 300 gigahertz (GHz) and lower. The wavelength for 300 GHz is 1 mm, which is shorter than a grain of rice, while the wavelength for 30 Hz is 10,000 km (6,200 miles) (longer than the radius of the Earth).
Radio waves move at the speed of light in a vacuum, as do all electromagnetic waves, and at a nearly identical speed in the Earth's atmosphere.
Among the given options, space communication and television broadcasting television broadcasting and GPS and radio telescopes and space communication are affected by satellites that are not working properly because they are operated by satellite technology.
Hence, only MRI and radio telescopes would be unaffected by satellites that are not working properly.
Learn more about radio waves here:
https://brainly.com/question/16188419
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The initial speed of a dropped ball is 0 m/s after 2 seconds the ball travels at a speed of 20 m/s what is the acceleration of the ball ?
Answer:
Please find attached file
Explanation:
The rate of change of velocity with respect to time is known as acceleration. The acceleration of the ball will be 10m/s.
What is acceleration?The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.
The given data in the problem is given by ;
u is the initial speed of ball = 0 m/sec
v is the final speed of the ball= 10 m/sec
t is the time interval= 2 second
a is the acceleration of ball=? m/sec²
The formula for acceleration is;
[tex]\rm a=\frac{(v-u)}{t} \\\\ \rm a=\frac{(20-0)}{2} \\\\\rm a=10\ m/sec^2[/tex]
Hence the acceleration of the ball will be 10m/s².
To learn more about the acceleration refer to the link;
https://brainly.com/question/2437624
Variables in physics often include a subscript. What are subscripts used for in physics?
A.) As a numerical coefficient used in multiplication
B.) To accurately juxtapose two congruent terms.
C.) To indicate different versions of the same variable.
D.) To indicate multiplication of the variable.
Answer:
C.) To indicate different versions of the same variable.
Explanation:
Variables in physics often include a subscript. These subscripts are used for indicating different versions of the same variable in physics.
Basically, subscripts are used to represent the beginning (initial) and ending (final) position or point of a variable in physics.
For example, we would look at Gay Lussac' Law of gases.
Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;
[tex] PT = K[/tex]
[tex] \frac{P1}{T1} = \frac{P_{2}}{T_{2}}[/tex]
Where;
[tex] T_{1} [/tex] represents the initial temperature.
[tex] T_{2} [/tex] represents the initial temperature.
[tex] P_{1} [/tex] represents the initial pressure.
[tex] P_{2} [/tex] represents the initial pressure.
Note: 1 and 2 are the subscript while T and P are the variables.
A crate moves DOWN an inclined plane below with a
diagram for the crate?
Answer:
The answer should be the one on the top in the picture.
Explanation:
Friction is opposing the downward movement of the crate therefore the friction force is pointing upwards. that is why the answer should be the one on the top of the picture.
What is the intensity of the electric current in one coil, if the number of the coils is 10, length of the coil is 5m, and magnetic induction is 8T?
Answer:
I think the answer is D...
Explanation:
a body is thrown at an angle 30°to the horizontal with kinetic energy 40J.atbthe highest point of its motion the kinetic energy will be?
When more energy is released when new bonds are formed. Which bonds are stronger. Please add why
1. The bonds that are formed
2. The bonds that are broken
Answer:
the bonds that are formed
Explanation:
Energy is absorbed in order to break bonds. Energy is released when new bonds are formed. Bond-making is a process of exothermic. Whether the reaction is endothermic or exothermic refers to the difference between the energy needed to break bonds and the energy released when new bonds are formed.
Is this spring or winter?
Which of the following is an example of an opposing force?
A.Gravity pulling a ball down a hill
B.Wind blowing a leaf off of a tree
C.Gravity holding a rock still on the ground
D.Water pushing against someone as they wade through a pool
EASY PLEASE HELP. As the rocket rises, it's kinetic energy changes. at the time the rocket reaches its highest point most of the energy of the rocket has been-
A) permanently destroyed
B) transformed into potential energy
C) converted to friction
D) stored inside the body of the
Answer:
c
Explanation:
A 2-cm tall object is located 10 cm in front of a concave lens that has a focal length of -20 cm. Calculate the image distance and the image size. (Describe the image) *
Answer:
image distance =-6.6 7cm
image size=1.3cm
Explanation:
5. If an object has an acceleration of 0 m/s2, then one can be sure that the object is not ____.
a. moving
b. changing position
c. changing velocity
6. If car A passes car B, then car A must be ____.
a. accelerating.
b. accelerating at a greater rate than car B.
c. moving faster than car B and accelerating more than car B.
d. moving faster than car B, but not necessarily accelerating.
7. Which one of the following is NOT consistent with a car which is accelerating?
a. A car is moving with an increasing speed.
b. A car is moving with a decreasing speed.
c. A car is moving at a high speed.
d. A car is changing direction.
8. A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that
a. he is accelerating
b. he is covering a greater distance in each consecutive second.
c. he is moving with a constant speed (on average).
Answer: c
Explanation: for #5 it can still be moving, just at a constant speed; therefore, it will be c.
If an object has an acceleration of 0 m/s2, then one can be sure that the object is not changing velocity.
If car A passes car B, then car A must be moving faster than car B, but not necessarily accelerating.
The not consistent with a car that is accelerating is a car is moving at a high speed.
A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that he is moving with a constant speed (on average).
What is Acceleration?Acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities (in that they have magnitude and direction). Speed is the distance covered in a unit of time while acceleration is the rate of change in speed. The unit of speed in the metric system is meters per second (m/s) while that of acceleration is meters per second squared (m/s2). Speed is a scalar quantity while acceleration is a vector quantity.To learn more about acceleration and speed, refer to: https://brainly.com/question/25086037
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The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 !" ! . Calculate the average speed of the blood in the capillaries given the total cross section of all the capillaries is about 2000 !"!
Answer:
The average speed of the blood in the capillaries is 0.047 cm/s.
Note: The question is incomplete. The complete question is as follows:
The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed of the blood in the capillaries given the total cross section of all the capillaries is about 2000 cm².
Explanation:
From the given values:
radius of the aorta, r₁ = 1 cm
speed of blood, v₁ = 30 cm/s
Area of the aorta, A₁ = πr₁² where π = 3.142
Area of aorta = 3.142 × (1)² = 3.142 cm²
Area of the capillaries, A₂ = 2000 cm²
let the average speed of the blood in the capillaries = v₂
From the continuity equation of fluid flow, the product of cross-sectional area of the pipe and the fluid speed at any point along the pipe is always constant. In formula, A₁v₁ = A₂v₂
Using the continuity equation, the average the average speed of the blood in the capillaries can be calculated thus:
A₁v₁ = A₂v₂
v₂ = (A₁v₁) / (A₂)
v₂ = (3.142 x 30) / (2000)
v₂ = 0.047 cm/s
Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.
Need help ASAP
Thankss + BRAINLIST only for correct answers
1.Which of the following statements about light waves is true? check all correct answers
A.They come from sources across space
B.They travel in a straight line from their source
C.They can travel through any type of material
D.They can be reflected by some types of material
2.Transparent allows some light through
A.True
B.false
Answer:
A, B and D
2. A
Explanation:
1.Which of the following statements about light waves is true? check all correct answers
A.They come from sources across space reason is that a light can travels form its source and its moves across the space
B.They travel in a straight line from their source reason is that the type of light that undergo these is called parallel ray of light
C.They can travel through any type of material reason not all materials light can penetrate through e.g wall
D.They can be reflected by some types of material reason is that some materals reflect light rays e.g polished mirror
A bullet of mass 50 g travelling with a speed of 15ms penetrates into a
bag of sand and is uniformly brought to rest in 0.05s.
Find
(a) How for the bullet will penetrate into the bag of sand?
(b) The Average force exerted by the sand ?
Answer:
a) The bullet will penetrate 0.375 meters into the bag of sand.
b) The average force exerted by the sand is 15 newtons.
Explanation:
The statement is incorrectly written. The correct form is presented below:
A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.
a) How far the bullet will penetrate into the bag of sand?
b) The average force exerted by the sand?
b) The average force exerted by the sand on the bullet ([tex]F[/tex]), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:
[tex]F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}[/tex] (1)
Where:
[tex]m[/tex] - Mass of the bullet, measured in kilograms.
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the bullet, measured in meter per second.
[tex]\Delta t[/tex] - Impact time, measured in seconds.
If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]\Delta t = 0.05\,s[/tex], then the average force exerted by the sand is:
[tex]F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}[/tex]
[tex]F = -15\,N[/tex]
The average force exerted by the sand is 15 newtons.
a) The distance travelled by the bullet ([tex]\Delta s[/tex]), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:
[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }[/tex] (2)
If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]F = -15\,N[/tex], then the distance travelled by the bullet is:
[tex]\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}[/tex]
[tex]\Delta s = 0.375\,m[/tex]
The bullet will penetrate 0.375 meters into the bag of sand.
Someone help me please I need to pass this quiz , this is the only quiz that It making me fail this class !!!
Select the correct items. Click the bottom right arrow to go to the next set . Click the checkmark ( Available on the last set ) to submit all your answers
Slow twitch muscle Fibers
Can contract repeatedly
Only anaerobic sources
Both aerobic & anaerobic
Produce most force
Endurance activities
Fast contraction speed
Fatigue quickly
Only aerobic sources
Speed, strength, power
Fast twitch Type lla muscle Fibers
Only aerobic sources
Fast contraction speed
Speed, strength, power
Only anaerobic sources
Fatigue quickly
Endurance activities
Produce most force
Can contract repeatedly
Both aerobic & anaerobic
Fast twitch type llx muscle Fibers
Can contract repeatedly
Only anaerobic sources
Only aerobic sources
Both aerobic & anaerobic
Fast contraction speed
Produce most force
Fatigue quickly
Endurance activities
Speed, strength, power
Answer:
1. Endurance activities
Only aerobic source
2. Can contract repeatedly
Speed strength and power.
Both aerobic and anaerobic sources
3. Fast contraction speed
Only anaerobic sources
Produce most force
Fatigue quickly
Speed, strength and power
Explanation:
I hope this helps. Although, I'm about 80% sure of the answer.
Draw the position vs. time graph for a person walking at a constant speed of 1m/s for 10 seconds. On the same axes, draw graph for a person running at a constant speed of 4m/s
Plot a graph, constant speed of movements represented as straight lines. Time on X axis (seconds) and position on Y axis (metres) , calculated by moving, e.g 4metres in a second.