The correct question is: 10 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.
Answer: The temperature is [tex]21.6^{o}C[/tex] and total enthalpy when the heating is completed is 300 kJ.
Explanation:
Given: Mass = 10 kg
Volume = 14 L
Final pressure = 600 K
First, convert volume from L to [tex]m^{3}/kg[/tex] as follows.
[tex]v_{1} = \frac{14 \times 10^{-3}}{10}\\= 0.0014 m^{3}/kg[/tex]
According to the R-134a tables at 300 kPa and [tex]0.0014 m^{3}/kg[/tex].
[tex]h_{1}[/tex] = 54.6 kJ/kg
[tex]T_{sat}[/tex] = 0.7 C
[tex]u_{1}[/tex] = 54.1 kJ/kg
Now, at the state 2 [tex]p_{2}[/tex] = 600 kPa and [tex]v_{2} = v_{1} = 0.0014 m^{3}/kg[/tex]
This means that the final temperature at state 2 is [tex]T_{2} = T_{sat} = 21.6^{o}C[/tex]
Hence, the change in enthalpy is calculated as follows.
[tex]\Delta H = m(h_{2} - h_{1})\\= 10(84.6 - 54.6)\\= 300 kJ[/tex]
The first law is applied to transfer the heat transfer as follows.
[tex]Q = m(u_{2} - u_{1})\\= 10(83.8 - 54.1) kJ\\= 297 kJ[/tex]
Thus, we can conclude that the temperature is [tex]21.6^{o}C[/tex] and total enthalpy when the heating is completed is 300 kJ.
How many moles of Aluminum are in 54.0 grams of Aluminum (Al)
Answer:
2 moles!
Explanation:
Hi i hope this helped! I researched it and 2 moles was what came up first.
Science- I need help with a question really quick I’m ending school soon
3 A soil has 70% sand, 20% silt
and 10% clay. What kind of soil is it? How do its proportions need
to be changed to make it
into a loam?
Today, as part of the series of posts on soils, we are going to look at ‘soil texture’. Soil forms the basis for all life but it’s important to know about its mineral constitution as well as its biological profile.
Texture refers to the ‘feel’ of the soil. This is affected by the constituent materials found within it, specifically sand, silt and clay particles. A coarse sand will feel gritty but a wet clay will feel heavy and sticky. The texture of a soil has a direct impact on the way the soil reacts to certain environmental conditions – for example, towards drought or heavy rain (with sandy soils more freely draining).
There is a big difference in the size of the different particles.
Coarse sand = diameter 2-0.2mm
Fine sand = diameter 0.2-0.02mm
Silt = diameter 0.02-0.002mm
Clay = diameter less than 0.002mm
Note how the clay particles are much smaller than the sand particles – this is important as it means the total surface area of a clay soil is much greater and so the capacity to hold water is also much greater.
Between the sand, silt and clay particles there are lots of pores. In fact a soil as a whole is generally 45% mineral, 5% organic matter (depending on the soil) and 50% pore space through which air and water can pass.
Sand –
Made up of weathered primary rock minerals.
The particles are irregular in outline.
They are large and so do not pack together easily.
Large pore spaces in between.
Air gets in very easily and water flows rapidly through it.
Silt –
Question 2
4 pts
Inside a car that was at STP, a 0.95 L bottle warms up to 144 C. If the volume of the bottle
remains constant, what is the pressure, in atm, inside the hot water bottle?
Answer:
1.53 atm
Explanation:
From the question given above, the following data were obtained:
Volume = constant
Initial pressure (P₁) = stp = 1 atm
Initial temperature (T₁) = 273 K
Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K
Final pressure (P₂) =?
Since the volume is constant, the final pressure can be obtained as follow:
P₁ / T₁ = P₂ / T₂
1 / 273 = P₂ / 417
Cross multiply
273 × P₂ = 417
Divide both side by 273
P₂ = 417 / 273
P₂ = 1.53 atm
Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.
calculate the molecular mass of sodium trioxocarbonate (iv) decahydrate. hints (H= 1, C=12, O=16, Na=23
Given :
A compound sodium trioxocarbonate (iv) decahydrate.
To Find :
The molecular mass of sodium trioxocarbonate (iv) decahydrate.
Solution :
We know, molecular formula of sodium trioxocarbonate (iv) decahydrate is :
Na₂CO₃.10H₂O
Now, we can calculate its molecular mass :
M = ( 2 × 23 ) + 12 + ( 3 × 16 ) + 10 × ( 1 × 2 + 16)
M = 46 + 12 + 48 + ( 10 × 18 )
M = 286 gram/mol
Hence, this is the required solution.
What volume of chlorine gas at 27 °C, 812 mmHg, is required to react with an excess of carbon disulfide so that 5.00kJ of heat is evolved?
Answer:
The correct answer is 1.21 L.
Explanation:
Based on the given information, the reaction will be,
CS2 (l) + 3Cl2 (g) ⇒ CCl4 (l) + S2Cl2 (l)
By using the standard values of the substances, the standard enthalpy of the reaction is,
ΔH° = [(-139.5) + (-58.5) – 0 – (87.3)] kJ/mol
= -285.3 kJ/mol
The amount of heat evolved for 3 moles of chlorine reacted us 285.3 kJ.
Now the number of moles of chlorine needed to react to produce 5.00 kJ is,
= 5.00 kJ × 3 mol Cl2/285.3 kJ
= 0.0526 mol Cl2
Now the volume of chlorine gas at 27degree C and 812 mmHg will be,
Volume = 0.0526 mol Cl2 × 0.0821 Latm/mol K × 300 K/ 1.07 atm
= 1.21 L
Predict the effect of an eightfold pressure increase on the equilibriunm composition of the reaction 3 Nalg) + H21g) =2 NaHlg)
According to Le cha telier's principle when we increase the pressure of a equilibrium reaction the reaction shift to the side where few moles of gas present.
Your reaction (Notice - I guess the reaction you written is wrong, but still I'm solving with your given prediction)
3NaI (g) + H2 (g) = 2NaHI (g)
Where access of sodium iodide is reacting with Hydrogen gas to form NaHI molecule.
Number of moles of gas on reaction side - 3+2 = 5 moles
Number of moles of gas on product side - 2 moles
Conclusion- the reaction will shift to the right of the reaction
According to Le cha telier's principle when we increase the pressure of a equilibrium reaction the reaction shift to the side where few moles of gas present.
Your reaction (Notice - I guess the reaction you written is wrong, but still I'm solving with your given prediction)
3NaI (g) + H2 (g) = 2NaHI (g)
Where access of sodium iodide is reacting with Hydrogen gas to form NaHI molecule.
Number of moles of gas on reaction side - 3+2 = 5 moles
Number of moles of gas on product side - 2 moles
Conclusion- the reaction will shift to the right of the reaction
What is the [OH-] in a solution if the [H*] = 1.2 x 10-3 M?
We know that [OH⁻] * [H⁺] = 10⁻¹⁴
plugging the value of [H⁺]
[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ * (10³/1.2)
[OH⁻] = 833.3 * 10⁻¹⁴
[OH⁻] = 8.33 * 10⁻¹²
I have added 15 L of air to a balloon at sea level (1.0 atm). If I take the balloon with me
to Denver, where the air pressure is 0.85 atm, what will the new volume of the balloon
be?
Answer:17.65 or 18 L
Explanation:
An unknown compound (152 mg) was dissolved in water to make 75.0 mL of solution. The solution did not conduct electricity and had an osmotic pressure of 0.328 atm at 27°C. Elemental analysis revealed the substance to be 78.90% C, 10.59% H, and 10.51% O. Determine the molecular formula of this compound.
Answer:
The molecular formula of the compound is C10H16O.
Explanation:
Based on the given information, the mass of an unknown compound is 152 mg or 0.152 g, which was dissolved to produce 75 ml of solution.
The osmotic pressure of the solution is 0.328 atm at 27 degrees C or 300 K.
The formula of osmotic pressure is,
P = CRT
Now putting the values in the formula we get,
0.328 = C*0.0821*300
C = 0.013317
C = (mass/molecular mass) * (1000/volume of solution in ml)
0.013317 = (0.152/Molecular mass) * (1000/75)
Molecular mass = 152.186
C mass = 152.186 * 0.789 = 120.07 grams
C mole = 120.07/12 = 10
H mass = 152.186 * 0.1059 = 16.11 grams
H mole = 16.11/1 = 16
O mass = 152.186 - 120.07 - 16.116 = 16 grams
O mole = 16/16 = 1
Thus, the molecular formula of the compound will be,
C10H16O
Find the mass of 0oC ice that 10 gof 100oC steam will completely melt. Latent heat of fusion of ice is 80cal/g oCand heat of vaporization of water 540 cal/g oC ?
Answer:
The right approach is "80 g".
Explanation:
Given:
[tex]L_f=80 \ Cal/g[/tex]
[tex]L_v=540 \ Cal/g[/tex]
[tex]S=1 \ Cal/g[/tex]
Now,
The amount of heat cooling will be:
= [tex]mL_v+mS \Delta T[/tex]
= [tex](10\times 540)+10\times 1\times (100-0)[/tex]
= [tex]5400+1000[/tex]
= [tex]6400 \ Cal[/tex]
then,
⇒ [tex]m_{ice} L_f=6400[/tex]
[tex]m_{ice}\times 80=6400[/tex]
[tex]m_{ice}=\frac{6400}{80}[/tex]
[tex]=80 \ g[/tex]
Write a conclusion statement that addresses the following questions: • Explain what the color change indicated about the changes in the concentrations of Co(H2O)62+ and CoCl42– in each trial. • Do your data support or fail to support your hypothesis (include examples)? • How do you think the investigation can be explored further?
When the concentration of the HCl is varied, the color of the solution is changed as the equilibrium position moves to the left or right.
What is equilibrium?The term equilibrium in a chemical reaction connotes that the forward and the revers reactions proceed at the same rate. Let us note that Co(H2O)6^2+ is pink in color while CoCl4^2– is blue in color.
As such, when the concentration of the HCl is varied, the color of the solution is changed as the equilibrium position moves to the left or right.
Learn more anout equilibrium: https://brainly.com/question/365923
What is the molarity and normality of solution containing 80 g of NaOH dissolved in 2.0 liter of the solution?
AAnswer:
Explanation:
Two airplanes are flying in the sky in such a way that the gravitational attractions between them decreases. The planes must be flying:
A.
away from each other.
B.
next to each other at the same speed.
C.
towards each other.
D.
faster than the speed of sound.
Two airplanes are flying in the sky in such a way that the gravitational attractions between them decreases. The planes must be flying away from each other. Hence option A is correct.
What is gravitational attraction?Gravitational attraction is defined as a basic interaction that pulls everything with mass or energy in the same direction. All objects are subject to gravitational interactions, the strength of which is directly inversely proportional to the product of their masses. The size of an object and the separation between the objects have an impact on gravity.
In order to reduce the gravitational pull, two planes are flying in the sky. There must be a directionality between the aircraft. No matter what is in between the two bodies, there will still be gravitational pull. As a result, even if the medium between the two bodies changed, the gravitational force between them would not.
Thus, two airplanes are flying in the sky in such a way that the gravitational attractions between them decreases. The planes must be flying away from each other. Hence option A is correct.
To learn more about gravitational attraction, refer to the link below:
https://brainly.com/question/19822389
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Chemical properties of an element are primarily dependent upon Group of answer choices the electron configuration of the element atomic weight of the element the number of main energy levels (electron shells) of the element the number of electrons in the innermost shell of the atom
Answer:
The answer is "the electron configuration of the element".
Explanation:
Electronics are distributed in atomic and molecular orbit via electrons from an atom or a molecule.
It reflects a most frequent dependence on valence electrons in the outer.
Through analyzing the context of the regular periodic table, the individual atoms are helpful. That's also important to understand chemical connections, which hold electrons together. This similar approach helps to explain the specific characteristics of lasers or semiconductors for bulk materials.
Los catalizadores sirven para detener una reacción química ?
Answer:
si
Explanation:
Los catalizadores son sustancias que aceleran una reacción química, proporcionando una ruta alternativa para romper y formar nuevos enlaces entre átomos. Su importancia reside en el hecho de que este nuevo camino requiere menos energía que el original, lo que facilita el proceso.
What is baking soda chemically known as ? Excessive use of chemical
fertilizer is not good. Justify.
Answer:
Baking Soda is NaHCO3 ---Sodium hydrogen Carbonate
Excessive use of Fertilizer can cause plants to develop shallow root systems,Decrease soil fertility and reduce Quality of Crops.
Answer:
Sodium bicarbonate, also called sodium hydrogen carbonate, or bicarbonate of soda, is a source of carbon dioxide and so is used as an ingredient in baking powders, in effervescent salts and beverages, and as the main constituent of dry-chemical fire extinguishers.
Explanation:
Measure the initial temperature of the water to the nearest 0.1°C. Record in the data table.
Initial Temp. of Metal
Initial Temp. of water
Initial Temp. of Both
Subtract to find the temperature changes for the water and the metal
Water
Metal
The heat capacity of the metal is calculated using the formula:
Heat capacity = quantity of heat/(mass * temperature difference)What is temperature?
The temperature of a substance is the degree of hotness or coldness of that substance.
Temperature difference between substances enables heat flow.
Heat flows from hot to cold bodies.
In the given experiment, to determine the heat capacity of a metal, the temperature difference is obtained by substracting the initial and final temperatures.
The heat capacity of the metal is then calculated using the formula:
Heat capacity = quantity of heat/mass * temperature differenceLearn more about heat capacity at: https://brainly.com/question/21406849
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According to one acid-base theory, water can act as a base because a water molecule can
1) donate an H+ ion
2) accept an H+ ion
3) donate an H- ion
4) accept an H- ion
Answer:
1) donate an H+ ion
Explanation:
option 1 is correct
To which family of organic compounds does CH3COCH2CH2CH3 belong?
Answer:
I think:
CH3COCH2CH2CH3 belongs to ketone because it has a carbonyl group C=O in its structure.
A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?
Answer:
571.81 mL
Explanation:
Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:
V₁T₂=V₂T₁Where in this case:
V₁ = 852 mLT₂ = 200 KV₂ = ?T₁ = 298 KWe input the data:
852 mL * 200 K = V₂ * 298 KAnd solve for V₂:
V₂ = 571.81 mLThe new volume would be 571.81 mL.
If carbon can count the shared hydrogen
atoms for itself, how many electrons are
now in carbon's outer orbital?
Answer:
Mars and Orbital code saber and the alien
Is HNO3 an acid or a base
I NEED HELP ASAP
Answer:
HNO3 is a potent acid, a base, a nitrating agent and a heavy oxidising agent at times. In the presence of a stronger acid, it serves as a base.
Explanation:
Answer:
It is a strong acid
Explanation:
In a different titration, a 0.7529 g sample of a mixture of solid C6H5COOH and solid NaCl is dissolved in water and titrated with 0.150 M NaOH. The equivalence point is reached when 24.78 mL of the base solution is added. Calculate each of the following.
a. The mass, in grams, of benzoic acid in the solid sample
b. The mass percentage of benzoic acid in the solid sample
Answer:
a. 0.4539g benozic acid
b. 60.29% of benzoic acid in the solid sample
Explanation:
The benzoic acid reacts with NaOH as follows:
C6H5COOH + NaOH → C6H5COONa + H2O
Where 1 mole of the acid reacts per mole of NaOH
The NaCl doesn't react with NaOH
To solve this question we must find the moles of NaOH added = Moles of benzoic acid. With the moles of the acid and its molar mass (C6H5COOH = 122.12g/mol) we can find the mass of the acid and its mass percentage:
a. Moles NaOH = Moles Benzoic acid:
24.78mL = 0.02478L * (0.150mol / L) = 0.003717 moles Benozic acid
Mass benzoic acid:
0.003717 moles Benozic acid * (122.12g / mol) = 0.4539g benozic acid
b. Mass percentage is:
0.4539g / 0.7529g * 100 = 60.29% of benzoic acid in the solid sample
A mixture of 0.224 g of H2, 1.06 g of N2, and 0.834 g of Ar is stored in a closed container at STP. Find the volume (in L) of the container, assuming that the gases exhibit ideal behavior.
Answer: The volume of given container is 3.83 L.
Explanation:
Given: Mass of [tex]H_{2}[/tex] = 0.224 g
Mass of [tex]N_{2}[/tex] = 1.06 g
Mass of Ar = 0.834 g
Since, moles is the mass of a substance divided by its molar mass. Therefore, moles of given substances present in the mixture are as follows.
Moles of [tex]H_{2}[/tex] are:
[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.224 g}{2 g/mol}\\= 0.112 mol[/tex]
Moles of [tex]N_{2}[/tex] are:
[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.06 g}{28 g/mol}\\= 0.038 mol[/tex]
Moles of Ar are:
[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.834 g}{40 g/mol}\\= 0.021 mol[/tex]
Total moles = (0.112 + 0.038 + 0.021) mol = 0.171 mol
Now, using ideal gas equation the volume is calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
[tex]V = \frac{nRT}{P}\\= \frac{0.171 mol \times 0.0821 L atm/mol K \times 273 K}{1 atm}\\= 3.83 L[/tex]
Thus, we can conclude that the volume of given container is 3.83 L.
Calculate the pH of a solution whose H3O+ concentration is 2.1 x 10-3 M. Is the solution acidc, basic, or neutral?
a
The pH of the solution is 2.7 and the solution is acidic.
b
The pH of the solution is 13.3 and the solution is acidic.
c
The pH of the solution is 13.3 and the solution is basic.
d
The pH of the solution is 2.7 and the solution is basic.
Answer:
Option A, The pH of the solution is 2.7 and the solution is acidic
Explanation:
As we know,
pH = - log [H3O+]
Substituting the given values, we get
pH = - log [2.1 x 10-3 M]
pH = - (-2.678)
pH = 2.678 or 2.7
The solution is acidic as pH value is less than 7
Hence, option A is correct
Which of these half-reactions represents reduction?
I. Fe2+ → Fe3+
II. Cr2O72- → Cr3+
III. MnO4- → Mn2+
Answer: The half-reactions represents reduction are as follows.
[tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex][tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]Explanation:
A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element takes place is called reduction-half reaction.
For example, the oxidation state of Cr in [tex]Cr_{2}O^{2-}_{7}[/tex] is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.
[tex]Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}[/tex]
Similarly, oxidation state of Mn in [tex]MnO^{-}_{4}[/tex] is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.
[tex]MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}[/tex]
Thus, we can conclude that half-reactions represents reduction are as follows.
[tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex][tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]Acids and bases are chemical molecules with very different characteristics.
a. True
b. Fasle
Answer:
TRUE ,hope it helped you
Explanation:
If the molecule has n-C2 axes perpendicular to its Cn axis, choose True. Otherwise, choose False. Be sure to build a model or draw the structure before selecting your answer. If needed, search for the molecular structure online or in a textbook.XeF4[PdCl4]2−naphthalenefuran, C4H4O
Answer:
XeF4 True
[PdCl4]2− True
naphthalene True
Furan False
C4H4O False
Explanation:
From the given information:
Only XeF4; [PdCl4]2−; naphthalene are true. This is because their molecules contain -nC₂ axis which is perpendicular to the Cn axis. The image attached below shows the structural formula of each compound, there below, we can see that Furan only possesses one C₂ axis but not -nC₂ ⊥ C₂.
ved:
Chapter
Chapter List
CH5.3
Problem
Problem List
10SMB
Printed circuit boards are used in the electronics industry to both connect and hold components in place. In production, 0.03 in. of copper foil is laminated to an insulating plastic board. A circuit pattern made of a chemically resistant polymer is then printed on the board. Next, the unwanted copper is chemically etched away by using selected reagents. If copper is treated with Cu(NH3 ) 4Cl2 (cupric ammonium chloride) and NH4OH (ammonium hydroxide), the products are water and Cu(NH3) 4Cl (cuprous ammonium chloride). Once the copper is dissolved, the polymer is removed by solvents, leaving the printed circuit ready for further processing. If a single-sided board 4 in. by 8 in. is to have 75% of the copper layer removed using these reagents, how many grams of each reagent will be consumed? Data: The density of copper is 8.96 g/cm3.
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