3a. Write an equation in slope-intercept form of a
line that passes through (2,1) and (6,-5).

Answers

Answer 1

Answer:

[tex]y =- 3/2x + 4[/tex]

Step-by-step explanation:

[tex](2,1) and (6,-5).\\x_1 = 2\\x_2 = 6\\y_1 =1\\y_2 =-5\\\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\\ \\\frac{y-1}{x-2} = \frac{-5-1}{6-2}\\\\\frac{y-1}{x-2} = \frac{-6}{4} \\Cross-Multiply\\4(y-1) = -6(x-2)\\4y-4=-6x+12\\4y =-6x+12+4\\4y = -6x+16\\Divide- through-by ; 4\\\frac{4y = -6x+16}{4} \\\\y = -\frac{3}{2} x +4[/tex]


Related Questions

QUESTION 8
Find Future Value Using Compound Interest Formula:
You deposit $6,000 in an account earning 4% interest compounded monthly. How much will you have in the account in 5 years?
A $9,677.95
B. $6,100.67
C. $7,325.98
D. $7,200
QUESTION 9
Find Future Value Using Compound Interest Formula:
You deposit $5,000 in an account earning 5% interest compounded quarterly. How much will you have in the account in 10 years?
A $5,661.35
B. $7,500
C. $8,235.05
D. $8,218.10

Answers

Answer:

8.) $7325.98

9.) $8218.10

Step-by-step explanation:

Compounded Interest Rate Formula: A = P(1 + r/n)^nt

Simply plug in our known variables into the formula:

A = 6000(1 + 0.04/12)^60 = 7325.98

A = 5000(1 + 0.05/4)^40 = 8218.10

What is the radius of a circle what circumference is 44cm


A. 42cm
D. 24cm
B. 48cm
C. 12cm​

Answers

Hello!!

Circumference of a circle = 2πr

and

Given, 2πr = 44cm

So,

πr = 44/2 = 22

r = 22 × 7/22

r = 7cm is the answer.

Stay safe and God bless!

- eli <3

Answer:

7 cm

Step-by-step explanation:

Circumference of a circle is 2 π r

2πr = 44

Solve for radius.

r = 44/(2π)

r = 7.002817

PLEASE HELP SOLVE THIS!!!!!

Answers

Answer:

20) -43

21) 25

22)-9

Step-by-step explanation:

20) -6 (-6 + 49)/6 = -43

21) 10 - (-10 - (-1 + 6)) = 25

22) 1 - 10/2 - 5 = -9

Step-by-step explanation:

22

Let's calculate the expression khowing that m= 1 and n = 5

m-[tex]\frac{m+m}{2}[/tex] -nm- [tex]\frac{2m}{2}[/tex]-n m-m-n0-n0-5-5

20

Let's calculate the expression khowing that n= -7 and p= - 6

[tex]\frac{p(p+n^{2}) }{6}[/tex] [tex]\frac{-6(-6+(-7)^{2}) }{6}[/tex][tex]\frac{-6(-6+49)}{2}[/tex] [tex]\frac{-6*43}{6}[/tex] -1*43-43

21

Let's calculate the expression khowing that n = -6 and m = -1 and p = -10

mp-(p-(m-n))mp-(p-m+n)mp-p+m-n(-1)*(-10)-(-10)+(-1)-(-6)10+10-1+620-1+619+625

In an aquarium, there are 7 large fish and 6 small fish. Half of the small fish are red.
One fish is selected at random. Find the probability that it is a small, red fish.
Write your answer as a fraction in simplest form.

Answers

Answer:

3/13

Step-by-step explanation:

There are a total of 13 fish (6+ 7 = 13). There are 3 small, red fish. (1/2 · 6 = 3). Put the number of small, red fish over the total number of fish because the small, red fish is being selected from the entire tank of fish. 3/13 cannot be simplified any further.

Suppose that we don't have a formula for g(x) but we know that g(3) = −1 and g'(x) = x2 + 7 for all x.
(a) Use a linear approximation to estimate g(2.95) and g(3.05).
g(2.95) =
g(3.05) =
(b) Are your estimates in part (a) too large or too small? Explain.
A) The slopes of the tangent lines are positive and the tangents are getting steeper, so the tangent lines lie below the curve. Thus, the estimates are too small.
B) The slopes of the tangent lines are positive but the tangents are becoming less steep, so the tangent lines lie below the curve. Thus, the estimates are too small.
C) The slopes of the tangent lines are positive and the tangents are getting steeper, so the tangent lines lie above the curve. Thus, the estimates are too large.
D) The slopes of the tangent lines are positive but the tangents are becoming less steep, so the tangent lines lie above the curve. Thus, the estimates are too large.

Answers

Answer:

g(2.95) ≈ -1.8; g(3.05) ≈ -0.2A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.

Step-by-step explanation:

(a) The linear approximation of g(x) at x=b will be ...

  g(x) ≈ g'(b)(x -b) +g(b)

Using the given relations, this is ...

  g'(3) = 3² +7 = 16

  g(x) ≈ 16(x -3) -1

Then the points of interest are ...

  g(2.95) ≈ 16(2.95 -3) -1 = -1.8

  g(3.05) ≈ 16(3.05 -3) -1 = -0.2

__

(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)

Use a proportion to solve the problem. Round to the nearest tenth as needed.
Triangle in a triangle Find the height of the building. Assume that the height of the person is 5 ft.
104 ft
building
13 ft
5 ft

Answers

Answer:

Height of the building is 40 feet

Step-by-step explanation:

From the figure attached,

Height of the person DE = 5 feet

Let height of the building BC = h feet

Since, ΔABC ~ ΔADE,

Their corresponding sides will be proportional,

[tex]\frac{DE}{BC}=\frac{AD}{AB}[/tex]

[tex]\frac{5}{h}=\frac{13}{104}[/tex]

h = [tex]\frac{104\times 5}{13}[/tex]

h = 40 feet

Therefore, height of the building is 40 feet.

Identify the correct HYPOTHESIS used in a hypothesis test of the following claim and sample data: Claim: "The average annual household income in Warren County is $47,500." A random sample of 86 households from this county is obtained, and they have an average annual income of $48,061 with a standard deviation of $2,351. Test the claim at the 0.02 significance level.

Answers

Answer:

We accept H₀

Step-by-step explanation:

Population mean  μ₀ = 47500

Population standard deviation unknown

Sample size    n = 86   degree of freedom  df = 86 - 1  df = 85

Sample mean    μ = 48061

Sample standard deviation 2,351

The claim implies a two tail test with t-studend distributon

Null  Hypothesis                 H₀               μ  =  μ₀

Alternative Hypothesis      Hₐ               μ  ≠  μ₀      

Confidence Interval  mean α = 0,02     and   α/2  =  0,01

With α/2 and df = 85, from t-table we find  t(c)  critical value

t(c) = 2,3710

We compute t(s) as

t(s)  =  ( μ - μ₀ ) / s /√n

t(s)  = ( 48061 - 47500 )/ 2351/√86

t(s)  = 561 * 9,273 / 2351

t(s) = 2,212

Now we compare t(s) and t(c)

t(s) < t(c)       2,212  < 2,371

Then we are in the acceptance region. We accept H₀

Please answer this correctly

Answers

Answer:

Question 2 is the right answer.

Step-by-step explanation:

Answer:

Question 2

Step-by-step explanation:

Temperature in the morning =  2°F  above normal temperature = + 2

Temperature at dinner time = 2° F lower than the morning = -2

+2 - 2 = 0° F

Alonzo and Cheryl are both members of a population, and a simple random sample is being conducted. If the chance of Alonzo being selected is 1/2900, what is the chance of Cheryl being selected?

Answers

Answer:

¿Consideras que la gente que discrimina por aspectos como el color de la piel, clase social, por el género, etc., no saben lo que las personas valen y por eso no las valoran?

¿Consideras que la gente que discrimina por aspectos como el color de la piel, clase social, por el género, etc., no saben lo que las personas valen y por eso no las valoran?

Answer: 1/2900

Step-by-step explanation: if they are both in the same population and they are both being randomly selected then they both have the same possibility of being picked

Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1 to catch rainwater off his roof.he has a full 2 liters tin of paint in his store and decides to paint the tank (not the base) If he uses 25ml to cover 1m^2 will he have enough paint to cover the tank with one layer of paint

Answers

Answer:

  yes

Step-by-step explanation:

The lateral area of a cylinder is ...

  LA = πdh

Putting in the given numbers, we find the area to be ...

  LA = π(1.1 m)(1.4 m) ≈ 4.838 m²

At 25 mL per m², the amount of paint Tublu needs is ...

  (4.838 m²)(25 mL/m²) = 120.95 mL

2 liters is 2000 mL, so Tublu easily has enough paint for one layer.

___

The amount he has is enough for more than 16 coats of paint, so he could paint inside and out with the paint he has.

Answer:

he should.

Step-by-step explanation:

Plz help me plzzzzzz!!!!

Answers

Answer: D, 6

Step-by-step explanation:

Match each side from XYZ to ABC (you are trying to find the scale factor of triangle 1 to triangle 2)  into a fraction then simplify

Ex 30/5= 6 or  24/6= 6 or 18/3

It’s d)6. Because all the values in the bigger triangle is 6 times the values in the smaller one

A triangle on a coordinate plane is translated according to the rule T-3,5(x, y). Which is another way to write this rule?
(x, y) - (x - 3, y + 5)
(x, y) - (x-3, y-5)
(x,y) - (x + 3, y-5)
(x, y) = (x + 3, y + 5)

Answers

Answer: Choice A. [tex](x,y) \to (x-3, y+5)[/tex]

Explanation:

The notation [tex]T_{-3,5}(x,y)[/tex]  or means to move any point (x,y) along the vector <-3,5>. Put another way, it says to shift (x,y) three units to the left and five units up. The x portion deals with left or right shifting, the y portion deals with up or down shifting. Since the x portion is negative, we go in the negative direction on the x axis. Y being positive means we move up rather than down.

This all means we end up with the translation rule [tex](x,y) \to (x-3,y+5)[/tex]

Select the expression that is equivalent to (x - 1)2.
O A. x2 - 2x + 2
O B. x2 - x + 2
O C. x2 - x + 1
O D. x2 – 2x + 1

Answers

Answer:

x^2 -2x+1

Step-by-step explanation:

(x - 1)^2

(x-1) * (x-1)

FOIL

first: x^2

outer: -1x

inner: -1x

last: 1

Add together

x^2 -1x-1x+1

Combine like terms

x^2 -2x+1

Answer:

[tex] \boxed{\sf D. \ {x}^{2} - 2x + 1} [/tex]

Step-by-step explanation:

[tex] \sf Expand \: the \: following: \\ \sf \implies {(x - 1)}^{2} \\ \\ \sf \implies (x - 1)(x - 1) \\ \\ \sf \implies x(x - 1) - 1(x - 1) \\ \\ \sf \implies (x)(x) - (1)(x) - (1)(x) - (1)( - 1) \\ \\ \sf \implies {x}^{2} - x - x - ( - 1) \\ \\ \sf \implies {x}^{2} - 2x - ( - 1) \\ \\ \sf \implies {x}^{2} - 2x + 1[/tex]

i need this fast plz

Answers

Answer:

180-130 = 50 degrees because its same side angle

m<2 = 50

Step-by-step explanation:

the second one m<1 is 105 for the same reason

Which of the following points is NOT a solution of the inequality y ≥ Ixl + 3?

A. (-3, 0)

B. (-3, 6)

C. (0, 4)​

Answers

Hey there!

To solve this, we need to plug each of our answer options into the inequality and see if it is true. Which ever one doesn't make the inequality true when plugged in is the answer.

OPTION A

(x,y)=(-3,0)

We plug our values into the inequality.

0≥ I-3I+3

You may have noticed the bars surrounding the negative three.. If you didn't know, this is called absolute value. Absolute value is how far the number is from 0 on the number line. -7 is 7 away from 0 on a number line, so the absolute value of -7 is 7. The absolute value of 7 is 7. The absolute value of 0 is 0. Absolute value is signified by these bars. Le'ts finish evaluating.

0≥6

As you can see, zero is not greater than or equal to six. So, option A is false.

Since A is not a solution, we already know that that is the answer, so we don't even need to check B and C. But, we can still evaluate them if you want.

OPTION B

6≥I-3I+3

6≥6

This is true.

OPTION C

4≥I0I+3

4≥3

This is also true.

Therefore, the answer is A. (-3,0)

Have a wonderful day!

A piece of wire 27 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle.(a) How much wire should be used for the square in order to maximize the total area?(b) How much wire should be used for the square in order to minimize the total area?

Answers

Answer:

a).length of wire for square = 15.25 m

b). length of wire for triangle = 11.75 m

Step-by-step explanation:

Length of a piece of wire = 27 m

This wire was cut into 2 pieces of length 'x' m and (27 - x) m

One was bent into an equilateral triangle and other into a square.

Area of the square shape = Side²

A = [tex](\frac{27-x}{4})^2[/tex]                        

Similarly, Area of the equilateral triangle = [tex]\frac{\sqrt{3}}{4}(\text{Side})^2[/tex]

A' =[tex]\frac{\sqrt{3}}{4}(\frac{x}{3})^{2}[/tex]

Total area of both the figures = A + A'

                                               F = [tex]\frac{(27-x)^2}{16}+\frac{\sqrt{3}}{4}(\frac{x}{3} )^2[/tex]

Now we find the derivative of 'F' with respect to x and equate it to zero.

F' = [tex]\frac{1}{16}(-1)[2(27-x)]+\frac{\sqrt{3}}{36}(2x)[/tex] = 0

[tex]\frac{\sqrt{3}}{18}(x)=\frac{1}{8}(27-x)[/tex]

x = 15.25 m

a). Length of wire required for a square = 15.25 m

b). Length of wire required for an equilateral triangle = 11.75 m

A) The amount of wire that should be used for the square in order to maximize the area is; 0 m

B) The amount of wire that should be used for the square in order to minimize the area is; 11.74 m

A) We are told that length of wire is 27 m.

Now, let the length cut for the square be x. Thus, length cut for the triangle will be; (27 - x) m.

Since the length for the square is x, then a side of the square is;

Length of side of square = x/4

Length of side of equilateral triangle = (27 - x)/3

Thus;

Area of square; A_s = (x/4)²

Area of equilateral triangle; A_t = ((27 - x)/3)²(¹/₄√3)

Thus, total area is;

A(x) = (x/4)² + ((27 - x)/3)²(¹/₄)√3)

A(x) = ¹/₁₆x² + ¹/₃₆((27 - x)²√3)

B) Total area is;  A(x) = ¹/₁₆x + ¹/₃₆((27 - x)²√3)

To minimize the total area, we will differentiate and equate to zero.

A'(x) = ¹/₈x - ¹/₁₈((27 - x)√3)

At A'(x) = 0, we have;

¹/₈x - ¹/₁₈((27 - x)√3) = 0

¹/₈x = ¹/₁₈((27 - x)√3)

¹/₈x = ³/₂√3 - ˣ/₁₈√3

¹/₈x + ˣ/₁₈√3 = ³/₂√3

x(¹/₈ + ¹/₁₈√3) = ³/₂√3

x = (³/₂√3)/(¹/₈ + ¹/₁₈√3)

x = 11.74 m

Now, A''(x) = ¹/₈ +  ¹/₁₈√3

This is greater than zero and so x = 11.74 m is a minimum

Thus, length cut for triangle = 27 - 11.74

length cut for triangle = 15.26 m

Read more at; https://brainly.com/question/16965977

Find a parametrization, using cos(t) and sin(t), of the following curve: The intersection of the plane y= 5 with the sphere

x^2+y^2+z^2=125

Answers

The parametrization shown below,

            [tex]x(t),y(t),z(t)=10cost,5,10sint[/tex]

Given equation of sphere,

                 [tex]x^{2} +y^{2} +z^{2} =125[/tex]

Substitute y = 5 in above relation.

         [tex]x^{2} +z^{2}=125-25=100\\ \\x^{2} +z^{2}=10^{2}[/tex]

For parametrization,

Substitute [tex]x=rcos(t),z=rsin(t)[/tex] and [tex]r=10[/tex]

So that,  [tex]x(t),y(t),z(t)=10cost,5,10sint[/tex]

Learn more:

https://brainly.com/question/23070611

Use the function below to find f(4).
f(x)=1/3x4^x


A. 8/3
B.256/3
C.64/3
D.16/3

Answers

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

Simply replace X with 4

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

PLZZZ I NEED HELP I’ll give 20 POINTS
What is the median of the following data set?
(6,3, 9, 1,7)
03
06
08
09

Answers

Answer:

6

Step-by-step explanation:

Arrange the data from smallest to largest

1,3,6,7,9

The median is the middle number

1,3   ,6,   7, 9

The middle number is 6

Hurry!! Determine the intervals for which the function shown below is decreasing.

Answers

Answer:

everywhere except between 2 and 5

(between -inf and 2 and between 5 and inf)

Step-by-step explanation:

2 + 4x - 4 = 0 which gives x =

Answers

Answer:

[tex]x = \frac{1}{2} [/tex]

Step-by-step explanation:

[tex]2 + 4x - 4 = 0 \\ 2 + 4x = 0 + 4 \\ 2 + 4x = 4 \\ 4x = 4 - 2 \\ 4x = 2 \\ \frac{4x}{4} = \frac{2}{4} \\ x = \frac{1}{2} [/tex]

Answer:

x = 1/2

Step-by-step explanation:

2 + 4x - 4 = 0

4x = 0 + 4 - 2

4x = 2

x = 2⁽²/4

x = 1/2

Pls help see the picture posted

Answers

I hope this helps you

As an example, 15,000 Men 18-34 watched program X at 7-8 pm on Monday night. 32,000 Men 18-34 had their TV on during the same time period. There are 200,000 Men 18-34 in the television households in the market. What would be the rating for Men 18-34 for program X? Group of answer choices 47 rating points 7.5 rating points 16 rating points 23.5 rating points

Answers

Answer:

7.5 rating points

Step-by-step explanation:

The computation of the rating for Men 18-34 for program X is shown below:

Given that

Number of men 18 -34 watched a program X = 15,000 = X

Number of men 18 - 34 watched in a same time = 32,000

And, the total households in the market = 200,000 = Y

So, the rating for men 18-34 for program x is

[tex]= \frac{X}{Y}[/tex]

[tex]= \frac{15,000}{200,000}[/tex]

= 7.5 rating points

We simply applied the above formula

What is the circumference of the circle below? (Round your answer to the nearest tenth.)

Answers

Answer:

Its 69.1 cm

Step-by-step explanation:

To find circumstance of any circle main formula is 2*pie*r .

Here pie is equal to 3.14 approx and r =11 cm

so

2*3.14*11 = 69.08 cm

This little difference is just because of pie's approximately value used

Binomial factor of 25x2 + 40xy + 16y2 ?

Answers

Answer:

  (5x +4y)^2

Step-by-step explanation:

The first and last terms are both perfect squares, and the middle term is twice the product of their roots. That means the trinomial is the perfect square trinomial ...

  25x^2 +40xy +16y^2 = (5x +4y)^2

_____

It matches the pattern ...

  a^2 +2ab +b^2 = (a +b)^2

Answer:

(5x +4y)^2

Step-by-step explanation:

PLEASE HELP ME!!!!! A quadrilateral with vertices (0,0), (4,0), (3,2), (1,1) is mapped to a quadrilateral with vertices (6,3).(-2,3),(0,-1),(4,1). What is the center of the dilation and what is the scale factor.

Answers

Answer:

( 2,1) is the center of dilation and -2 is the scale factor

Step-by-step explanation:

We can use the formula

A' = k( x-a) +a, k( y-b)+b  where ( a,b) is the center of dilation and k is the scale factor

(0,0) becomes (6,3)

( 6,3) =  k( 0-a) +a, k( 0-b)+b

6 = -ka+a

3 = -kb+b

We also have

(4,0) becomes (-2,3)

( -2,3) =  k( 4-a) +a, k( 0-b)+b

-2 =4k -ka+a

3 = -kb+b

Using these two equations

6 = -ka+a

-2 =4k -ka+a

Subtracting the top from the bottom

-2 =4k -ka+a

-6 = ka -a

-------------------

-8 = 4k

Divide by 4

-8/4 = 4k/4

-2 = k

Now solving for a

6 = -ka +a

6 = - (-2)a +a

6 = 2a+a

6 = 3a

Divide by 3

6/3 =3a/3

2=a

Now finding b

3 = -kb+b

3 = -(-2)b+b

3 = 2b+b

3 = 3b

b=1

Answer:

hope this helps uh.....

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
a. Calculate a 95% two-sided confidence interval on the death rate from lung cancer.
b. Using the point estimate of p obtained from the preliminary sample, what sample size is needed to be 95% confident that the error in estimating the true value of p is less than 0.03?
c. How large must the sample be if you wish to be at least 95% confident that the error in estimating p is less than 0.03, regardless of the true value of p?

Answers

Answer:

a) [tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

b) [tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

c) [tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

[tex]\hat p=\frac{823}{1000}=0.823[/tex]

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by [tex]\alpha=1-0.95=0.05[/tex] and [tex]\alpha/2 =0.025[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96[/tex]

The confidence interval for the mean is given by the following formula:  

[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

If we replace the values obtained we got:

[tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

And on this case we have that [tex]ME =\pm 0.03[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

Part c

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

The monthly starting salaries of students who receive an MBA degree have a standard deviation of $110. What size sample should be selected to obtain a 0.95 probability of estimating the mean monthly income within $20 or less

Answers

Answer:

116.21

Step-by-step explanation:

Using the formula for calculating margin error to tackle the question.

Margin error = [tex]\frac{Z \sigma}{\sqrt{n} }[/tex]

Z is the value at 95% confidence

[tex]\sigma[/tex] is the standard deviation

n is the sample size to be estimated

Since the  mean monthly income is within $20 or less, our margin error will be $20

Given [tex]\sigma[/tex] = $110, Z value at 95% confidence = 1.96 we can calculate the sample side n.

Making n the subject of the formula from the equation above;

[tex]M.E = \frac{Z \sigma}{\sqrt{n} }\\\\\sqrt{n} = \frac{Z \sigma}{M.E } \\\\[/tex]

[tex]n = (\frac{Z \sigma}{M.E })^{2}[/tex]

Substituting the give value into the resulting expression;

[tex]n = (\frac{1.96 * 110}{20})^{2}\\\\n = (\frac{215.6}{20}) ^2\\\\n = 10.78^2\\\\n = 116.21[/tex]

This shows that the sample size that should be selected to obtain a 0.95 probability of estimating the mean monthly income within $20 or less is approximately 116.21

11- In
how many ways 3 mathematics books, 4 history books ,3
chemisidy books and a biology books can be arranged
on an Shelf so thet all books of the same subjects are
together!​

Answers

Answer:    20,736

Step-by-step explanation:

Math and History and Chemistry and Biology and Subjects

  3!     x        4!        x          3!          x        1!          x        4!       = 20,736

The manufacturer of a certain brand of hot dogs claims that the mean fat content per hot dog is 20 grams. Suppose the standard deviation of the population of these hot dogs is 1.9 grams. A sample of these hot dogs is tested, and the mean fat content per hot dog of this sample is found to be 20.5 grams. Find the probability that the sample mean is at least 20.5 when the sample size is 35.

Answers

Answer:

[tex]z=\frac{20.5-20}{\frac{1.9}{\sqrt{35}}}= 1.557[/tex]

And using the normal standard distribution and the complement rule we got:

[tex]P(z>1.557) =1-P(z<1.557) = 1-0.940 = 0.06[/tex]

Step-by-step explanation:

For this case we define our random variable X as "fat content per hot dog" and we know the following parameters:

[tex]\mu = 20, \sigma =1.9[/tex]

We select a sample of n=35 and we want to find the following probability:

[tex] P(\bar X>20.5)[/tex]

For this case since the sample size is >30 we can use the central limit theorem and we use the z score formula given by:

[tex]z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

Replacing we got:

[tex]z=\frac{20.5-20}{\frac{1.9}{\sqrt{35}}}= 1.557[/tex]

And using the normal standard distribution and the complement rule we got:

[tex]P(z>1.557) =1-P(z<1.557) = 1-0.940 = 0.06[/tex]

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