30. Which of the following atoms would form
a trivalent anion?
A. Aluminium
B. Oxygen
C. Lithium
D. Nitrogen​

Answer:

200.0lg

Explanation:

please give a brainliest

Answer:

50 g Sucrose

Explanation:

Step 1: Given data

Step 2: Calculate the mass of sucrose needed to prepare the solution

The concentration of the solution is 2.5%, that is, there are 2.5 g of sucrose (solute) every 100 g of solution. The mass of sucrose needed to prepare 2000 g of solution is:

2000 g Solution × 2.5 g Sucrose/100 g Solution = 50 g Sucrose

Answer:

3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)

Explanation:

This is an acid-base reaction (neutralization): NaOH is a base, H3PO4 is an acid.

When the equation is balanced, and the coefficient of H₂O is 3.

To balance the chemical equation:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + H₂O

The number of atoms of each element is the same on both sides of the equation.

Balance the hydrogen atoms. There are three hydrogen atoms on the left side and two hydrogen atoms on the right side. To balance the hydrogen atoms, multiply H₂O by a coefficient of 3:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + 3H₂O

If the oxygen (O) atoms are balanced. There are four oxygen atoms on the right side, but only two oxygen atoms on the left side. To balance the oxygen atoms, we need to multiply NaOH by a coefficient of 2.

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Answer:

Explanation:

Given Information :

Mass = 4.0kg

Acceleration  due to gravity = 10 m/s

Weight= ?

[tex]Weight = \frac{mass}{acceleration\: due \:to \:gravity} \\\\W= \frac{4.0}{10} \\\\W= \frac{2}{5} \\\\W=0.4[/tex]

Answer:

203 grams

Explanation:

The no. of moles of (6.3 x 10²⁴ molecules--Avagadros number) of NH₃ = (1.0 mol)(7.2 x 10²⁴ molecules)/(6.022 x 10²³ molecules) = 11.96 mol.

The no. of grams of NH₃ present = no. of moles x molar mass = (11.96 mol)(17.0 g/mol) = 203.3 g ≅ 203.0 g.

The answer is the mass of a sample of NH3 containing 7.20 x 1024 molecules of NH3 is 203 grams.

A molecule is a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.

6.02214076 × 10²³  molecules constitutes 1 mole of NH₃

7.20 x 10²⁴ molecules constitutes of

[tex]\rm\dfrac{7.20 \times 10^{24}}{6.02\times 10^{23}}\\[/tex]

=11.19 moles

1 mole of NH₃ = 17 gm

11.19 mole will be = 17 * 11.19

= 203 grams

Therefore the mass of a sample of NH3 containing 7.20 x 1024 molecules of NH3 is  203 grams.

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Answer:

a)

For Methylcyclohexane  N₁ = 2770

For Methylcyclohexene N₂ = 2827

For Toluene N₃ = 2557

b) the standard deviation for the average in (a) is 143.31

c)

For Methylcyclohexane; H₁ = 0.01444 cm

For Methylcyclohexene; H₂ = 0.01415 cm

For Toluene; H₃ = 0.01564 cm

Explanation:

Given the data in the question;

Gas-liquid chromatography on a 40-cm packed column:

Compound                   tR, min                           W, min

Air                                   1.9                                    —

Methylcyclohexane      10.0                               0.76

Methylcyclohexene      10.9                               0.82

Toluene                        13.4                                1.06

a)

an average number of plates from the data;

To get the Number of plates N, we use the following expression;

N = 16( tR / W )², we use it for Methylcyclohexane, Methylcyclohexene and Toluene

-

For Methylcyclohexane  N₁ = 16( 10 / 0.76 )² = 16( 173.13 ) = 2770.08 ≈ 2770

-

For Methylcyclohexene N₂ = 16( 10.9 / 0.82 )² = 16( 176.7 ) = 2827.2 ≈ 2827

-

For Toluene N₃ = 16( 13.4 / 1.06 )² = 16( 159.8078 ) = 2556.9 ≈ 2557

b) standard deviation for the average in (a).

First we get the mean;

Mean N" = ( N₁ + N₂ + N₃ ) / 3 = ( 2770 + 2827 + 2557 ) / 3 = 8154 / 3 = 2718

Next we determine the deviation

d₁² = (N₁ - N")² = (2770 - 2718)² = (52)² = 2704

d₂² = (N₂ - N")² = (2827 - 2718)² = (109)² = 11881

d₃² = (N₃ - N")² = (2557 - 2718)² = (-161)² = 25,921

∴ ∑d²[tex]_i[/tex] = 40506

Standard Deviation S = √( ∑d²[tex]_i[/tex]  / ( n-1 ) )

Standard Deviation S = √( 40506 / ( 3-1 )

Standard Deviation S = √( 40506 / 2 )

Standard Deviation S = √( 20253 )

Standard Deviation S = 143.31

Therefore, the standard deviation for the average in (a) is 143.31

c)

an average plate height for the column

Given that; Gas-liquid chromatography on a 40-cm packed column, L = 40 cm

-

For Methylcyclohexane; H₁ = L/N₁ = 40 / 2770 = 0.01444 cm

-

For Methylcyclohexene; H₂ = L/N₂ = 40 / 2827  = 0.01415 cm

-

For Toluene; H₃ = L/N₃ = 40 / 2557 = 0.01564 cm

Answer:

7.15g/cm³

Explanation:

To solve this question we must know that a body-centered cubic unit cell contains 2 atoms.

The volume of the unit cell is:

289pm = (289x10⁻¹²m)³ =

2.414x10⁻²⁹m³ * (1cm³ / 1x10⁻⁶m³) = 2.414x10⁻²³cm³

And the mass is -Molar mass Chromium = 51.9961g/mol:

2atoms * (1mol / 6.022x10²³atoms) * (51.9961g / mol) =

1.727x10⁻²²g

The density is:

1.727x10⁻²²g / 2.414x10⁻²³cm³ =

Answer:

c. composed of only one type of atom or molecule.

Explanation:

Pure substances are the substances that could be made up of only one type of particles and also it contains fixed structure. They would be further categorized as the elements & compounds. It is an elements that only consist of only one type of atom or molecule

Therefore as per the given situation, the option c is the answer

Answer: correct answer is C

Explanation:

Unnillium (101)

Unnilbium (102)

Unniltrium (103)

Unnilquadium (104)

Unnilpentium (105)

Unnilhexium (106)

Unnilseptium (107)

Unniloctium (108)

Unnilennium (109)

Ununnillium (110)

Answer: When exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

Explanation:

A degree of randomness in the molecules of a substance is called entropy.

When exhaust from car engines spreads throughout our atmosphere then it means the molecules are moving at a faster speed due to which they spread into the atmosphere rapidly.

This means that the entropy of exhaust is increasing.

Thus, we can conclude that when exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

An increase in entropy

Answer:

20 moles of Iron are needed

Explanation:

In 1 mole of Iron (III) oxide, Fe₂O₃, there are 2 moles of Iron, Fe. The equation that we can write is:

2 moles Fe = 1 mole Fe₂O₃

To find the moles of iron that are needed to produce 10 moles of Fe₂O₃ we must use this equation as follows:

10 moles of Fe₂O₃ * (2 moles Fe / 1mole Fe₂O₃) =

Answer:

Sample B

Explanation:

In this case, we need to determine the empirical formula for each sample. The one that match the formula of the propene would be the sample.

Let's do Sample A:

C: 60 g;       H: 12 g

1. Calculate moles:

We need the atomic weights of carbon (12 g/mol) and hydrogen (1 g/mol):

C: 60 / 12 = 5

H: 12 / 1 = 12

2. Determine number of atoms in the formula

In this case, we just divide the lowest moles obtained in the previous part, by all the moles:

C: 5 / 5 = 1

H: 12 / 5 = 2.4    or rounded to two

3. Write the empirical formula:

Now, the prior results, represent the number of atoms in the empirical formula for each element, so, we put them with the symbol and the atoms as subscripted:

C₁H₂ = CH₂

Therefore, sample A is not the same as propene.

Sample B:

C: 72 g    H: 12 g

Following the same steps, let's determine the empirical formula for this sample

C: 72 / 12 = 6 ---> 6 / 6 = 1

H: 12 / 1 = 12 ----> 12 / 6 = 2

EF: CH₂

Sample C:

C: 84 g    H: 10 g

C: 84 / 12 = 7 ----> 7 / 7 = 1

H: 10 / 1 = 10    ----> 10 / 7 = 1.4 or just 1

EF: CH

Sample D

C: 90 g      H: 10 g

C: 90 / 12 = 7.5     -----> 7.5 / 7.5 = 1

H: 10 / 1 = 10  -------> 10 / 7.5 = 1.33 or just 1

EF: CH

Neither compound has the same empirical formula as C3H6, but C3H6 is a molecular formula, so, if we just simplify the formula we have:

C3H6  -----> CH₂

Therefore, sample B is the one that match completely. Sample B would be the one.

Hope this helps

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: [tex]V_{1}[/tex] = 571 mL,       [tex]T_{1} = 26^{o}C[/tex]

(a) [tex]T_{2} = 5^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL[/tex]

(b) [tex]T_{2} = 95^{o}F[/tex]

Convert degree Fahrenheit into degree Cesius as follows.

[tex](1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL[/tex]

(c) [tex]T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL[/tex]

Answer:

Explanation:

The boiling point will increase due to dissolution of sugar in water . Increase in boiling point ΔT

ΔT = Kb x m , where Kb is molal elevation constant water , m is molality of solution

Kb for water = .51°C /m

moles of sugar = 16.90 / 342.3

= .04937 moles

m = moles of sugar /  kg of water

= .04937 / .04090

= 1.207

ΔT = Kb x m

= .51 x 1.207

= .62°C .

So , boiling point of water = 100.62°C .

Answer:

A

Explanation:

Hydrogen isn't an alkali metal

Answer:

hydrogen

Explanation:

hydrogen is a gas not a metal

Answer:

meeting ones legal responsibility

Answer:

Sample A

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles (mol) ÷ volume (vol)

For Sample A:

V = 300ml = 300/1000 = 0.3 L

Molarity = 1M

n = number of moles (mol)

1 = n/0.3

n = 0.3moles

For Sample B:

V = 145 mL = 145/1000 = 0.145L

Molarity = 1.5 M

n = number of moles

1.5 = n/0.145

n = 1.5 × 0.145

n = 0.22 moles

Based on the above results (moles), sample A with 0.3 moles contains the larger concentration of sodium chloride.

Answer:

the molar mass for Fe and Cl

Answer:

P = 487 Torr

mN₂ = 0.347 g

mO₂ = 0.174 g

mHe = 0.0333 g

Explanation:

Step 1: Calculate the total pressure of the mixture

The total pressure of the mixture (P) is equal to the sum of the partial pressures of the gases.

P = pN₂ + pO₂ + pHe

P = 231 Torr + 101 Torr + 155 Torr = 487 Torr

Step 2: Calculate the moles of each gas

We have 3 gases in a 1.00 L container at 25.0 °C (298.2 K). We can calculate the number of moles using the ideal gas equation: P × V = n × R × T.

nN₂ = pN₂ × V / R × T

nN₂ = 231 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.0124 mol

nO₂ = pO₂ × V / R × T

nO₂ = 101 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.00543 mol

nHe = pHe × V / R × T

nHe = 155 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.00833 mol

Step 3: Calculate the mass of each gas

The molar mass of N₂ is 28.01 g/mol.

mN₂ = 0.0124 mol × 28.01 g/mol = 0.347 g

The molar mass of O₂ is 32.00 g/mol.

mO₂ = 0.00543 mol × 32.00 g/mol = 0.174 g

The molar mass of He is 4.00 g/mol.

mHe = 0.00833 mol × 4.00 g/mol = 0.0333 g

Wilma- tt

Wilbur- TT

c) 100% chance

d) 100% chance

it has been a while since I've done this so it could be wrong but im pretty sure its correct

Wilbur's family claims it is pure so they have TT

and his wife simply has big eyes so its tt

so the chances of their children having either eye shape is 100%

I'm sorry- im not too good at explaining it ><

Answer:

ecosystem i think

Answer:

B.Anything that takes up space and has mass

Answer:

The answer is:

[tex]PART \ A: CH_4\\\\PART \ B: CH_30H\\\\PART \ C: H_2CO[/tex]

Explanation:

Parts A:

The vapor pressure is higher in [tex]CH_4[/tex] because it is non-polar, while [tex]CH_3Cl[/tex] is polar. [tex]CH_4[/tex] has a lower molar weight as well.

Part B:

Although hydrogen bonding is found in both commodities, the vapor pressure is higher because of the smaller molar mass of [tex]CH_30H[/tex].

Part C:

[tex]H_2CO[/tex] does not show hydrogen due to the increased vapor pressure

[tex]CH_3OH[/tex] bonding.

Answer:

oil based paint

Explanation:

Answer:

0.60 moles of atoms of carbon

Explanation:

Step 1: Given data

Step 2: Calculate the number of carbon atoms in the given sample

According to the chemical formula of the compound, the molar ratio of C to O is 2:6, that is, there are 2 moles of atoms of C every 6 moles of atoms of O. The number of moles of atoms of C is:

1.8 mol O × 2 mol C / 6 mol O = 0.60 mol C

Answer:

What about it? I don't get the question

Answer:

90.26%

Explanation:

From the question given above, the following data were obtained:

Theoretical yield of AlCl₃ = 1551 g

Actual yield of AlCl₃ = 1400 g

Percentage yield =?

The percentage yield of the reaction can be obtained as follow:

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 1400 / 1551 × 100

Percentage yield = 140000 / 1551

Percentage yield = 90.26%

Thus, the percentage yield of the reaction is 90.26%