Answer:
x^4 - x^3 + 2x -6
Step-by-step explanation:
(f-g)(x) = x^4-3x^2+5x-7 - ( x^3-3x^2+3x-1 ) = x^4 - 3x^2+5x-7 - x^3 + 3x^2 - 3x + 1 = x^4 - x^3 + 2x -6
Step-by-step explanation:
x^4-3x^2+5x-7 – x^3-3x^2+3x-1
x^4-3x^2+5x-7 – x^3+3x^2-3x+1
x^4-3x^2+3x^2-3x +5x -x^3 -7+1
x^4+2x -x^3 -6
x^4-x^3+2x-6
5. (08.01) Line M is represented by the following equation: x + y = -1 What is most likely the equation for line P so the set of equations has infinitely many solutions?
O 2x + 2y = 2
O 2x + 2y = 4
O 2x + 2y = -2
O x - y = 1
Answer:
2x + 2y = -2
Step-by-step explanation:
you can divide a 2 from all three terms in 2x + 2y = -2 to get x + y = -1 which overlaps the original equation to provide an infinite number of solutions
Which graphs are functions ( select all that apply
Answer:
The second and third option are both functions!!
Glad to help!!
Step-by-step explanation:
'na1 18 43 written in expanded form?
A.
B.
C.
D.
4x3
4+4+4
3x3 x3 x3
4 x 4 x 4
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4. Using the empirical rule (as presented in the book), what is the approximate percentage of lightbulb replacement requests numbering between 51 and 55
Answer:
percentage of lightbulb replacement requests = 34.15 %
Step-by-step explanation:
According to Empirical Rule
interval %
μ ± σ 55 ± 4 ( 51 ; 59 ) 68.3
As the question is a percentage between 55 and 51
or between 51 and μ - σ by symmetry is 68.3/2
% of lightbulb replacement requests = 34.15 %
find the difference between the points (-7,6) and (7,6) IM GOING CRAZY WITH THE POINT TODAY WORTH A LIFE TIME GET IT CORRECT YOU GET BRAINLEST YES SIRR
Answer: 14
Step-by-step explanation:
For:
(X1, Y1) = (-7, 6)
(X2, Y2) = (7, 6)
Distance Equation Solution:
=(7−(−7))2+(6−6)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
=(14)2+(0)2‾‾‾‾‾‾‾‾‾‾‾√
=196+0‾‾‾‾‾‾‾√
=1‾√96
=14
Is there an error in this problem explain pls do all
Answer:
C
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
you did it wrong
this is the one thats not wrong:
7(6+4(−10+9))
=(7)(6+4(−10+9))
=(7)(6)+(7)(4(−10+9))
=42−28
=14
What is the area and perimeter?
Answer:
Perimeter: 26 units
Area: 24 units²
Step-by-step explanation:
12 + 9 + 5 = 26
A = 1/2BH
A = 1/2 12(4)
A = 1/2 48
A = 24
7) what is the approximate value of x? (Hint: there are two right angle triangles here, round to the nearest tenth)
Answer:
x= 8.2
Step-by-step explanation:
first we need to find the hypotenuse of the smaller triangle
3² + 4² = C
9 + 16 = 25
√25 = 5
now that we found the hypotenuse of the smaller triangle then we now find the hypotenuse of the larger one (x)
6.5² + 5² = C
42.25 + 25 = 67.25
√67.25 = 8.2
the answer? wowisoososksks
Answer:
1/6
Hope that this helps!
1) Base of an isosceles triangle is five more than three times the equal sides and perimeter of the triangle is 75 cm. Find the lengths of the sides of the triangle.
Answer:
Equal sides of triangle = 14 cm
Base of an isosceles triangle = 47 cm
Step-by-step explanation:
Given:
Perimeter of the triangle = 75 cm
Base of an isosceles triangle = five more than three times the equal side
Find:
Lengths of isosceles triangle
Computation:
Assume;
Equal sides of triangle = a
So,
Base of an isosceles triangle = 3a + 5
Perimeter of the triangle = Base of an isosceles triangle + 2[Equal sides of triangle]
Perimeter of the triangle = 3a + 5 + 2[a]
Perimeter of the triangle = 5a + 5
75 = 5a + 5
5a = 70
a = 14
Equal sides of triangle = 14 cm
Base of an isosceles triangle = 3a + 5
Base of an isosceles triangle = 3(14) + 5
Base of an isosceles triangle = 42 + 5
Base of an isosceles triangle = 47 cm
PLS HELP ASAP BRAINLIEST!!!
Suppose that the distance a car travels varies directly with the amount of gasoline it uses. A certain car uses 5 gallons of gasoline to travel 130 miles. If the car travels 442 miles, how much gasoline does it need?
Answer:
17 gallons
Step-by-step explanation:
A birthday present is placed into a rectangular shoe-box. The box has the following dimensions: 3 inches by 7 inches by 8 inches. What is the minimum amount of wrapping paper needed to cover the entire box?
a.146 sq. in.
b.101 sq. in.
c.202 sq. in.
d.168 sq. in.
Answer:
c. 202 sq. in
Step-by-step explanation:
2× (3×7 + 3×8 + 7×8)
= 2 × ( 21+24+56)
= 2× (101)
= 202
x^2 + y^2 =-6x-14-6y
Answer:
x=−3+√(−y−1)(y+5)
Step-by-step explanation:
thats if your solving for x if not to math w l ay
Which of these are the constant?
4y+1+9x
Answer:
1 is the constant
Step-by-step explanation:
What are the coordinates of the end point? Please help
Answer:
1, -16
Step-by-step explanation:
-5+6=1
-3-13=-16
(1, -16)
Find the mean of the following data set.
42, 45, 58, 63
1.42
2.47
3.52
Answer:
52
Step-by-step explanation:
[tex]\frac{42+45+58+63}{4}=52[/tex]
From the set {2, 6, 42}, use substitution to determine which value of x makes the equation true.
6(x + 40) = 252
A.
2
B.
none of these
C.
6
D.
42
how can you find the area of a composite figure
4 Students is___% of 20 students.
Answer:
20%
Step-by-step explanation:
4 / 20 = 0.2 = 20%
Hope this helps :)
Answer:
4 Students is 20% of 20 students.
Step-by-step explanation:
[tex] \frac{4}{20} \times 100[/tex]
= 4 × 5 %
= 20%
Evaluate the expression.
3 + (50- 5^2)
can someone please help
question: An airplane is flying at an elevation of 1500 feet. What is the airplane's angle of elevation from the runway when it is 5000 feet from the runway?
Answer:
Angle of elevation of the airplane = 17.46 degrees
Step-by-step explanation:
From the picture attached,
An airplane is flying at an altitude of 1500 ft at point A.
Runway starts from point B from which distance of the airplane is 5000 ft.
Now we apply sine rule in the given triangle ABC to measure the angle θ.
sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
sinθ = [tex]\frac{AC}{AB}[/tex]
= [tex]\frac{1500}{5000}[/tex]
[tex]\theta=\text{sin}^{-1}(\frac{3}{10})[/tex]
[tex]\theta=17.46[/tex] degrees
The third-degree Taylor polynomial about x = 0 of In(1 - x) is
Answer:
[tex]\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
FunctionsFunction NotationCalculus
Derivatives
Derivative Notation
Derivative Rule [Quotient Rule]: [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
MacLaurin/Taylor Polynomials
Approximating Transcendental and Elementary functionsMacLaurin Polynomial: [tex]\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + ... + \frac{f^{(n)}(0)}{n!}x^n[/tex]Taylor Polynomial: [tex]\displaystyle P_n(x) = \frac{f(c)}{0!} + \frac{f'(c)}{1!}(x - c) + \frac{f''(c)}{2!}(x - c)^2 + \frac{f'''(c)}{3!}(x - c)^3 + ... + \frac{f^{(n)}(c)}{n!}(x - c)^n[/tex]Step-by-step explanation:
*Note: I will not be showing the work for derivatives as it is relatively straightforward. If you request for me to show that portion, please leave a comment so I can add it. I will also not show work for elementary calculations.
Step 1: Define
Identify
f(x) = ln(1 - x)
Center: x = 0
n = 3
Step 2: Differentiate
[Function] 1st Derivative: [tex]\displaystyle f'(x) = \frac{1}{x - 1}[/tex][Function] 2nd Derivative: [tex]\displaystyle f''(x) = \frac{-1}{(x - 1)^2}[/tex][Function] 3rd Derivative: [tex]\displaystyle f'''(x) = \frac{2}{(x - 1)^3}[/tex]Step 3: Evaluate Functions
Substitute in center x [Function]: [tex]\displaystyle f(0) = ln(1 - 0)[/tex]Simplify: [tex]\displaystyle f(0) = 0[/tex]Substitute in center x [1st Derivative]: [tex]\displaystyle f'(0) = \frac{1}{0 - 1}[/tex]Simplify: [tex]\displaystyle f'(0) = -1[/tex]Substitute in center x [2nd Derivative]: [tex]\displaystyle f''(0) = \frac{-1}{(0 - 1)^2}[/tex]Simplify: [tex]\displaystyle f''(0) = -1[/tex]Substitute in center x [3rd Derivative]: [tex]\displaystyle f'''(0) = \frac{2}{(0 - 1)^3}[/tex]Simplify: [tex]\displaystyle f'''(0) = -2[/tex]Step 4: Write Taylor Polynomial
Substitute in derivative function values [MacLaurin Polynomial]: [tex]\displaystyle P_3(x) = \frac{0}{0!} + \frac{-1}{1!}x + \frac{-1}{2!}x^2 + \frac{-2}{3!}x^3[/tex]Simplify: [tex]\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}[/tex]Topic: AP Calculus BC (Calculus I/II)
Unit: Taylor Polynomials and Approximations
Book: College Calculus 10e
I will give brainlest please help
The center of the circle would be (5,-8)
This is because you inverse the sign within the equation for the x/y coordinate part of it. Therefore, for this question:
(x-5)^2+(y+8)^2 = 121
The center would be (5,-8), since there is (x-5) and (y+8).
The radius of the circle would be 11
This is because within the equation for the circle, the finishing number is the radius squared. This means that if you square root this finishing number, you would get the radius. So with this question:
(x-5)^2+(y+8)^2 = 121
By doing √121, you would get 11 as the radius.
Help please anyone ?!
Answer:
.62
Step-by-step explanation:
first move the decimal 3 places to make it a whole number and now we have 4960, now we divide 4960 by 8 giving us 620, now we move the decimal 3 places back and it gives us the decimal .62.
HELP ASAP!! Click the picture to make it bigger
:)
thanks
Answer:
the answer is C.
Step-by-step explanation:
Carry a book bag: Female is 57
Mr. pope lost 10 pounds in one month. At the end of the month, he weighed 240 pounds. By what percentage did Mr. Pope decrease he weight?
a. (4%)
b. (7%)
c.(10)
d.(15%)
AND ACTUALLY GIVE STEP-BY-STEP
Answer:
A. 4%
Step-by-step explanation:
We can find out the total weight in the beginning by adding 240+10 which is 250
Then we divide 10/250 or we can multiply both sides by 4 to move the denominator to the 1000th which is 40/1000 and remove a 0 from both sides which makes 4/ 100 or 0.04 which is 4%
If the simple interest earned on $6000 for 9 years is $2,160. Then what is the interest rate?
Answer:
4 %
Step-by-step explanation:
1 year interest =2160÷9
= £240
Interest rate=240/6000 ×100
=4%
Can I get some help with this please.
The table models how the population of a city has changed over time. What does the y-intercept represent?
Answer:
The y-intercept represent:
122,000 (1985) represents the starting population from when they began calculating the data.
Step-by-step explanation:
Find the surface area of the rectangular prism.
8 mi
2 mi
1 mi
Answer:
A = 2 ( wl + hl + hw ) = 2 · ( 2 · 8 + 1 · 8 + 1 · 2) = 52
Step-by-step explanation:
find a
polynomial P(x) of 2nd degree if P(1)=0
P (2) 3
P(-3)=0
Given:
P(x) is a 2nd degree polynomial.
[tex]P(1)=0,\ P(2)=3,\ P(-3)=0[/tex]
To find:
The polynomial P(x).
Solution:
If P(x) is a polynomial and P(c)=0, then c is a zero of the polynomial and (x-c) is a factor of polynomial P(x).
We have, [tex]P(1)=0,\ P(-3)=0[/tex]. It means 1 and -3 are two zeros of the polynomial P(x) and (x-1) and (x+3) are two factors of the polynomial P(x).
So, the required polynomial is defined as:
[tex]P(x)=a(x-1)(x+3)[/tex] ...(i)
Where, a is a constant.
We have, [tex]P(2)=3[/tex]. So, substituting [tex]x=2,\ P(x)=3[/tex] in (i), we get
[tex]3=a(2-1)(2+3)[/tex]
[tex]3=a(1)(5)[/tex]
[tex]3=5a[/tex]
[tex]\dfrac{3}{5}=a[/tex]
Putting [tex]a=\dfrac{3}{5}[/tex] in (i), we get
[tex]P(x)=\dfrac{3}{5}(x-1)(x+3)[/tex]
Therefore, the required polynomial is [tex]P(x)=\dfrac{3}{5}(x-1)(x+3)[/tex].