(30 POINTS!!!) If anyone could please help me with any of the questions they know the answer too!!!!!!! Please only answer if you actually do know the answer because this is the third time I’m posting this and people just keep taking advantage of me giving a lot of points.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The kinetic energy for particle a is  [tex]K_a  =  \frac{9}{2}  mr^2 w^2[/tex]

The kinetic energy for particle b is   [tex]K_b  =  m w^2r^2 [/tex]

Explanation:

From the question we are told that

   The mass of particle a  is  [tex]m[/tex]  

   The mass of particle b is  [tex]2 m[/tex]  

Generally the kinetic energy for  particle a is mathematically represented as  

       [tex]K_a  =  \frac{1}{2} m v^2[/tex]

Here [tex]v_a[/tex] is the linear velocity of particle a which is mathematically represented as

         [tex]v_b  =  w *  3r[/tex]

So

      [tex]K  =  \frac{1}{2} m {w *  3r}^2[/tex]

=>   [tex]K_a  =  \frac{9}{2}  mr^2 w^2[/tex]

Generally the kinetic energy for  particle a is mathematically represented as  

    [tex]K_b  =  \frac{1}{2} 2m v_b^2[/tex]

Here [tex]v_b[/tex] is the linear velocity of particle a which is mathematically represented as

         [tex]v_b  =  w *  r[/tex]

So

      [tex]K_b  =  m (wr)^2[/tex]

=>    [tex]K_b  =  m w^2r^2[/tex]

The kinetic energy of the particle in terms of angular speed (ω), mass of the object (m) and the radius of the path is [tex]\frac{1}{2} m \omega ^2 r^2[/tex].

The given parameters;

The kinetic energy of the of the particle in terms of the angular velocity is calculated as follows;

[tex]K_b = \frac{1}{2} m (\omega r)^2\\\\K_b = \frac{1}{2} m \omega ^2 r^2[/tex]

where;

Thus, the kinetic energy of the particle in terms of angular speed (ω), mass of the object (m) and the radius of the path is [tex]\frac{1}{2} m \omega ^2 r^2[/tex].

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Option D) 1.5 m/s² is the correct answer.

The magnitude of the acceleration of the car is 1.5 m/s².

given the data in the question;

record of the observation;

Time(s)      Speed(m/s)

3.0                4.0

5.0                7.0

6.0                8.5

Since its undergoing constant acceleration, we can make use any two from the three data recorded.

So, lets consider motion between t₁ = 3.0s and t₂ = 5.0s

Initial velocity at t₁ ; u = 4.0 m/s

final velocity at t₂; v = 7.0 m/s

Now, Time Elapsed; [tex]t = t_2 - t_1 = 7.0s - 5.0s = 2.0s[/tex]

To determine the magnitude of acceleration "a", we use the first equation of motion which says;

[tex]v = u + at[/tex]

we make "a" the subject of the formula

[tex]a =\frac{v - u}{t}[/tex]

so we substitute in our values;

[tex]a = \frac{(7.0m/s) - (4.0m/s)}{2.0s}[/tex]

[tex]a = \frac{3.0m/s}{2.0s}[/tex]

[tex]a = 1.5 m/s^2[/tex]

Therefore, the magnitude of the acceleration of the car is 1.5 m/s².

Option D) 1.5 m/s² is the correct answer.

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Answer:

B. the object will begin to move

Explanation:

If energy is transferred the object will definitely change so it CANNOT be "A". If you add energy the object will have more force so it CANNOT be "C". The mass of an object can't increase just by giving an object energy so it CANNOT be "D"

Answer:

grav times mass equals force

Explanation:

As current increases, the magnetic field strength increases.

Answer:

Answer is a force liquid that cannot be compresed

on edgenuity

Explanation:

Answer:

E = V / d       125 V / .018 m = 6940 V/m     electric field

F = E Q       force on Q due to E

F = E n e     where n is the number of electrons in Q

m g = E n e

n = m g / E e     where n is the number of electrons e needed to support drop

n = 1.6 * 10E-16 * 9.8 / (6940 * 1.6 * 10E-19)

n = 1.41

Since n needs to be an integral number of charges, the drop would

not be suspended (motionless under these conditions).

Answer: B. Ax = 6, Ay=8

Explanation:

Answer: There are different kinds of conductors, most notably electrical and thermal conductors. But they are often inclusive of each other (electrical conductors are typically good thermal conductors). A conductor transmits something through its body with high efficiency while an insulator does not transmit very well. In the case of electricity, a conductor transmits electrical energy between two points while an insulator blocks the flow of electricity. Two examples of conductors are copper and silver. Two examples of insulators are wood and styrofoam.

Explanation:

Answer:

The candy before was fluffy, and the candy after was compacted.

Explanation:

By definition, something that is fluffy is something very soft, and when you talk about fluffy food (e.g. cakes, cotton candy) it is food that has a lot of air in it. In this case, the cotton candy originally had the shape of a cloud and was not dense, therefore, it was fluffy.

Something that is compact, it something that is dense, solid and generally small. Since Chanel wanted her cotton candy to be more dense, she compacted it .

Answer:

c

Explanation:

We know that we can write the speed of something as the quotient between the distance it moves and the time it takes to move that distance.

speed = distance/time

Using this, we will find that the correct option is the first one, 9.0 m

The information we know is:

The student, on average, catches the meter stick after it has traveled 0.64m

We need to transform this into time.

Assuming that the meter stick is just released, the only acceleration it will have is the gravitational one, so we have:

a(t) = -9.8m/s^2

To get the velocity of the stick we need to integrate over time, as the it is just released, it will not have initial velocity, thus the constant of integration is zero:

v(t) = (-9.8m/s^2)*t

To get the position equation we need to integrate again, and as the initial position is relative, we can define it as zero, so again the constant of integration is zero:

p(t) = (1/2)(-9.8m/s^2)*t^2

p(t) = (-4.9 m/s^2)*t

We know that the student catches the stick after it traveled (downwards) 0.64m

Then we need to solve:

-0.64m =  (-4.9 m/s^2)*t

√[(-0.64m)/(-4.9m/s^2)] = t = 0.36s

So the reaction time of the student is 0.36 seconds.

Now we can use the first equation:

speed = distance/time

And rewrite it as:

distance = speed*time

So if the car moves at 25m/s and the student needs 0.36 s to react, the distance that he/she will move in that time frame is:

d = (25m/s)*0.36s = 9.0m

So the correct option is the first one.

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Answer: 5.5

Explanation: its simply different from the others

The position of an object is where it sits on the number line. When the object moves to another position, its displacement is the second position minus the first position.

Δ x = x2 − x1

The word displacement implies we keep track of which way the movement occurs. In one dimension the direction is indicated by the sign: negative if to the left and positive if to the right. The word distance means how far the object moves regardless of direction. It is always positive and is equal to the absolute value, or magnitude, of the displacement.

If one follows the rule of always subtracting the first position from the second, the sign always works out to be positive if the displacement is to the right and negative if the displacement is to the left.

Answer:

Explanation:

The circulatory system is made up of blood vessels that carry blood away from and towards the heart. Arteries carry blood away from the heart and veins carry blood back to the heart. The circulatory system carries oxygen, nutrients, and hormones to cells, and removes waste products, like carbon dioxide.

Heat moves in three ways: Radiation, conduction, and convection. Radiation happens when heat moves as energy waves, called infrared waves, directly from its source to something else. This is how the heat from the Sun gets to Earth. In fact, all hot things radiate heat to cooler things.

Answer:

O: girl- aww your so sweeet thanks for that!!!!! like fr ive

been feeling so sad):

hey! i just wanted to ask if you found the answer because i’m looking for it

Given that,

The initial speed of a ball, u = 17.3 m/s

It is shot from the roof of a 52 m tall building, h = 52 m

It is required to find the distance from the base of the building the ball land. Let the distance be d.

Final velocity of the ball, v = 0 (when it lands)

We can use third equation of motion to find it.

[tex]v^2-u^2=2ad[/tex]

a = -g

[tex]-u^2=-2gd\\\\d=\dfrac{u^2}{2g}\\\\d=\dfrac{(17.3)^2}{2\times 9.8}\\\\d=15.26\ m[/tex]

So, it will land at a distance of 15.26 m.

Answer:

v =2.02

Explanation:

v^2=0.05-4.9

v^2=-4.85

square root both side

v=2.02

^^^^this is a not a perfect square  

Answer:

3000

Explanation:

Answer:

7 kg

Explanation:

Mass remains the same, regardless of gravity. If the mass of the bowling ball is 7kg on Earth, the mass on the moon will be 7kg as well.

Answer:

???????? please give for info

Answer:2 km

Explanation:

Answer:

C.

Explanation:

Wave energy is directly proportional to the amplitude of the wave.  It is a square function.. double the amplitude (wind/solar power picks up) the energy in the ocean wave is quadrupled.

Wave energy is directly proportional to the amplitude of the wave. Therefore, option C is correct.

Waves of heat, light, sound, and water carry a variety of energies. All types of energy can be converted into work because energy is defined as the capacity to perform work. The movement of an object in the direction of the force acting on it is referred to as work in science. When they move items, waves do really work. This process is evident when sand is carried or large logs are moved across ocean basins.

Work can also be transformed into the acoustic energy produced when waves crash on the coast. The potent force of waves can also be used to move generator components and generate electricity.

A wave's energy content is influenced by its height, wavelength, and breaking point in addition to other factors. When waves of identical wavelengths fall back to sea level, the wave with the greater amplitude will release more energy than the wave with the lesser amplitude. Therefore, option C is correct.

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Answer:

if you pull on a spring and stretch it, then you do work. that's bc you're applying a force over a displacement. your pull is the force and the amount that you stretch the spring is the displacement. a spring can be stretched or compressed.