3. What molecule or ion acts as the nucleophile in the base-catalyzed reaction between acetic anhydride and vanillin? A. Vanillin as a neutral phenol B. Vanillin as a phenoxide ion (conjugate base) C. Acetic anhydride D. Sodium hydroxide 4. According to the class notes, the first step in the acid-catalyzed reaction between acetic anhydride and vanillin is: A. Loss of a proton from the alcohol group in vanillin B. Protonation of acetic anhydride C. Protonation of the alcohol group in vanillin D. Departure of water as a leaving group in vanillin FOR QUESTIONS 5 AND 6 USE THE FOLLOWING INFORMATION: • Vanillin (solid) MW = 152.15 g/mol • Acetic anhydride (liquid) MW = 102.04 g/mol • Acetic anhydride density = 1.082 g/mL 5. How many mmoles of vanillin and how many mmoles of acetic anhydride are being reacted in the BASE CATALYZED reaction as described in the textbook? A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride B. 45.6 mmol of vanillin and 82 mmol acetic anhydride C. 8.45 mmol of vanillin and 2 mmol acetic anhydride D. 2 mmol of vanillin and 2 mmol acetic anhydride 6. How many mmoles of vanillin and how many mmoles of acetic anhydride are being reacted in the ACID CATALYZED reaction as described in the textbook? A. 23 mmol of vanillin and 102 mmol acetic anhydride B. 11 mmol of vanillin and 1 mmol acetic anhydride C. 1 mmol of vanillin and 10.6 mmol acetic anhydride D. 1 mmol of vanillin and 9 mmol acetic anhydride

Have a wonderful day :) thanks for the points

Answer:

Relative Humidity

Air Temperature

Explanation:

Relative humidity  and air temperature are the factors that creates fog. When the moist and warm air makes contact with the cooler air, water vapor condenses due to low temperature of that region that causes for the formation of fog. So we can say that relative humidity  and air temperature are the main factors for the formation of fog in that region.

Answer:

High Cold High

Explanation:

Answer:

C4H4

Explanation:

92.31% of 52.0 g/mol is 48.0012 g/mol

7.69% of 52.0 g/mol is is 3.9988 g/mol

Carbon has a gram-formula mass of about 12, which goes into 48.0012 about 4 times, so there should be 4 atoms of Carbon

Hydrogen has a gram-formula mass of about 1, which goes into 3.9988 about 4 times, so there should also be 4 atoms of hydrogen

Answer:

The correct answer is B.2.52 mol

Explanation:

The molarity of a solution (M) expresses the number of moles of solute there is in 1 liter of solution. If we have the molarity (M) and the volume in liters (L), we simply multiply M x V to obtain the moles, as follows:

M = 2.21 = 2.21 moles/L

V = 1.14 L

M x V = 2.21 moles/L x 1.14 L = 2.5194 moles ≅ 2.52 moles

Answer: Simpe its 1

Explanation:I took that quiz before hope this helps :)

Answer:

6.25gm

half life is 66hrs 11 days is 24*11 then take that and divide by 66 to find out how many time it will have halved and half 50 by that many times

Explanation:

If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.

Molybdenum-99 follows first-order decay.

First-order decay means that for a population of atoms (e.g. radioactive), molecules, or anything else, a constant fraction/unit time is converted to something else.

The half-life (th) of Mo-99 is 66 h.

We will find its rate constant (k) using the following expression.

k = ln2 / th = ln2 / 66 h = 0.011 h⁻¹

Next, we will convert 11 days to hours, knowing that 1 day = 24 h.

11 d × 24 h/1 d = 264 h

If we start with 50 g of Mo-99, we can calculate the remaining mass after 264 h using the following expression.

[tex][Mo] = [Mo]_0 \times e ^{-k \times t} }\\\\[Mo] = 50g \times e ^{-0.011 h^{-1} \times 264 h} } = 2.7 g[/tex]

where,

If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.

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Answer:

igneous rocks

Explanation:

One type of rock that forms very quickly would be igneous rocks. These are rocks that form after a volcanic eruption, where the molten magma melts everything into lava which then hardens shortly after. This creates a new rock that is a mixture of many other materials called Igneous rocks. Once hardened they usually remain stable and unchanged for a very long time until the next volcanic eruption. An example if the eruption of Tambora which after finishing has created lots of igneous rocks and has not erupted again since 1815.

A rock form easily through volcanic eruption, and remain stable, or unchanged, for a very long period of time because of strong bonding in constitute minerals.

Rock is a solid substance which is naturally occur in the environment, it is made up from minerals. Mainly three types of rocks are present, which are igneous rock, metamorphic rock and sedimentary rock.

We obtain rocks generally by the volcanic eruption and as it is made up of minerals and different minerals have different crystal structure and bonding in these minerals are very strong which not break easily. That's why rocks remain stable or unchanged for a very long time. Only volcanic eruption will break rocks because only they have that much of energy to break. Examples of hard rocks are granite, syenite, unikite, andesite, etc.

Hence, due to strong bonds rocks will stay stable for long time.

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Answer:

Answer:

[tex]T_2 =388.50K[/tex]

Explanation:

Given

[tex]p_1 = ??[/tex] -- Initial vapour pressure

[tex]p_2 = 6.50p_1[/tex] --- Final vapour pressure

[tex]T_1 = 355K[/tex] ---- Initial temperature

[tex]T_2 = ??[/tex] --- Final temperature

[tex]\triangle _{vap}H = 64.08kJmol[/tex] --- Enthalpy of vaporization

Required

Calculate T2

To do this, we make use of Clausius-Clapeyron equation.

Which states that:

[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex]

Where:

[tex]R = 8.314 J.K^{-1}mol^{-1}[/tex] --- Universal Gas constant

[tex]\triangle _{vap}H = 64.08kJmol[/tex]

[tex]\triangle _{vap}H = 64080\ kJmol[/tex]

[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex] becomes

[tex]ln(\frac{6.50p_1}{p_1}) = \frac{64080}{8.314}(\frac{1}{355} - \frac{1}{T_2})[/tex]

[tex]ln(\frac{6.50p_1}{p_1}) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]

[tex]ln(6.50) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]

[tex]1.872 = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]

Take LCM

[tex]1.872 = 7707.48(\frac{T_2 - 355}{355T_2})[/tex]

[tex]1.872 = 7707.48*\frac{T_2 - 355}{355T_2}[/tex]

[tex]1.872 = \frac{7707.48*(T_2 - 355)}{355T_2}[/tex]

Cross Multiply

[tex]355T_2*1.872 = 7707.48*(T_2 - 355)[/tex]

[tex]664.56T_2 = 7707.48T_2 - 2736155.4[/tex]

Collect Like Terms

[tex]664.56T_2 - 7707.48T_2 =- 2736155.4[/tex]

[tex]-7042.92T_2 =- 2736155.4[/tex]

Make T2 the subject

[tex]T_2 =\frac{- 2736155.4}{-7042.92}[/tex]

[tex]T_2 =388.497299416[/tex]

[tex]T_2 =388.50K[/tex]

The final temperature is 388.50K

The temperature at which the vapor pressure will be 6.50 times higher than it was at 355K is 389 K

The Clausius-Clapeyron Equation is widely used for the determination of the vapor pressure of another temperature, provided we know the vapor pressure at a certain temperature as well as the heat of vaporization.

Given that:

By using the Clausius-Clayperon Equation:

[tex]\mathbf{In \Big( \dfrac{P_2}{P_1} \Big) = \dfrac{\Delta H_{vap}}{R} \Big (\dfrac{1}{T_1} - \dfrac{1}{T_2} \Big) }[/tex]

[tex]\mathbf{In \Big( \dfrac{6.5P_1}{P_1} \Big) = \dfrac{64.08 \times 10^3 }{8.314} \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]

[tex]\mathbf{In(6.5)=7707.48 \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]

[tex]\mathbf{1.872 =21.71 - \dfrac{7707.48}{T_2} }[/tex]

[tex]\mathbf{\dfrac{7707.48}{T_2} = 21.71- 1.872 }[/tex]

[tex]\mathbf{\dfrac{7707.48}{T_2} = 19.838 }[/tex]

[tex]\mathbf{T_2= \dfrac{7707.48}{19.838} }[/tex]

[tex]\mathbf{{T_2}=388.521 \ K }[/tex]

T₂ ≅ 389 K

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Answer:

I believe it's D!

Explanation:

B is what is being saved, C is a potential creation of, A is a method.

Answer:

91.7%

Explanation:

The percent yield when it could be used as a buffering agent should be considered as the 91.74%.

Since we know that

Number of moles = Mass in gram / Molar mass

And,

Molar mass of H3PO4 = 97.994 g/mol

So,

Number of moles of H3PO4

= 100 g / 97.994 g/mol

= 1.02 mol

Now

Molar mass of K2HPO4 = 174.2 g/mol

So,

Theoretical yield of K2HPO4 = 174.2 g/mol * 1.02 mol

= 177.684 g

So finally

Percent yield = Actual yield * 100 / Theoretical yield

= 163 g * 100 / 177.684 g

= 91.74%

hence, The percent yield when it could be used as a buffering agent should be considered as the 91.74%.

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36 ) Potassium

37 ) Calcium

38 ) fluorine

39 ) fluorine

40 ) Phosphorus

41 ) Phosphorus

42 ) Sulphur

43 ) Sodium

Answer:

mid-ocean ridges

Explanation:

Seafloor spreading occurs along mid-ocean ridges—large mountain ranges rising from the ocean floor.

Answer:

[tex]T_f=72.5\°C[/tex]

Explanation:

Hello!

In this case, since this a problem in which the cold water is heated by the hot water, we can write:

[tex]Q_{hot}+Q_{cold}=0[/tex]

Thus, by plugging in the mass, specific heat and temperatures, we obtain:

[tex]m_{hot}C_{hot}(T_f-T_{hot})+m_{cold}C_{cold}(T_f-T_{cold})=0[/tex]

Now, we can also write:

[tex]m_{hot}(T_f-T_{hot})+m_{cold}(T_f-T_{cold})=0[/tex]

Then, after applying some algebra, it is possible to obtain:

[tex]T_f=\frac{m_{hot}T_{hot}+m_{cold}T_{cold}}{m_{hot}+m_{cold}}[/tex]

If we plug in, we obtain:

[tex]T_f=\frac{350.0g*95.0\°C+150.0g*20.0\°C}{350.0g+150.0g}[/tex]

[tex]T_f=72.5\°C[/tex]

Best regards!

Answer:

Cells are the smallest living unit of an organism

Answer:

all living things living things have blood cells

Explanation:

this is because robert hooke did not make this apart of the theory

Answer:75.99

Explanation:saw it on quizlet

When the theoretical yield of Baso, is 58.35 g And, there is 44.34 g of BaSO4 are produced so the percent yield is option b 75.99%.

Since

The theoretical yield of Baso, is 58.35 g. And, there is 44.34 g of BaSO4 are produced

So, here the percent yield is

= Actual yield / theoretical yield

=  44.34 / 58.35

= 75.99%

Hence, the option b is correct.

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Answer:

please refer to the attachment above;)

Answer:

Because it contains Na+ and Cl- ions, Which are conductors of electricity

Explanation:

Answer:

An electrolytic cell is a cell that converts electrical energy into chemical energy.

Any device in which electrical energy is converted to chemical energy or vice versa is referred to as an electrolytic cell. A typical cell consists of two metallic or electronic conductors held apart and in contact with an electrolyte, which is usually a dissolved or fused ionic compound.

An electrolytic cell is a type of electrochemical cell that uses an external source of electrical energy to force a chemical reaction that would not occur otherwise. A voltage applied between the cell's two electrodes, an anode and a cathode immersed in an electrolyte solution, serves as the external energy source.

Electrons in the form of an electric current are deliberately pumped through the chemicals in the section to induce an oxidation-reduction reaction. An electrolytic cell is a setup used to electrolytically decompose water into hydrogen and oxygen.

Electrochemical cells that generate an electric current are known as voltaic or galvanic cells, whereas those that generate chemical reactions, such as electrolysis, are known as electrolytic cells.

Thus, Any device in which electrical energy is converted to chemical energy or vice versa is referred to as an electrolytic cell.

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#SPJ5

Answer: 6.75 moles

Explanation:

This is a simple stoichiometry proboe. that I would set up like this:

(13.5 moles CuCI2) (1 mol I2 / 2 moles CuCi2)

That means you all you have to do for this problem is divide by 2 and cancel out the unit moles CuCI2, which leaves you with 6.75 moles I2.

Hope this helps :)

Answer:

PV=nRT

STP is 100kPa and 273.15K

PV/RT=n

n=17.3moles

Explanation:

Answer:

2.64gram

Explanation:

Molarity, which refers to the molar concentration, is calculated thus:

Molarity = number of moles (n) ÷ volume (L)

According to the question, volume = 100 mL, molarity = 0.240 M.

Since 1L = 1000mL

100 mL = 100/1000

= 0.1L

Hence;

0.240 = n/0.1

n = 0.1 × 0.240

n = 0.024mol

Mole = mass/molar mass

Molar mass of CaCl2 = 40 + 35.5(2)

= 40 + 71

= 111g/mol

mass = molar mass × mole

mass = 110 × 0.024

Mass = 2.64gram

Answer:

0.3139 nm

Explanation:

First of all, let's Calculate the average density of the Cr −Ta alloy;

Formula to get it is;

ρ_avg = 100/[(C_cr/ρ_cr) + (C_ta/ρ_ta)]

We are given;

C_cr = 26%

C_ta = 74%

ρ_cr = 7.13 g/cm³

ρ_ta = 16.6 g/cm³

Thus;

ρ_avg = 100/[(26/7.13) + (74/16.6)]

ρ_avg = 12.34 g/cm³

Similarly, let's Calculate the average atomic weight;

A_avg = 100/[(C_cr/A_cr) + (C_ta/A_ta)]

We are given;

A_cr = 52 g/mol

A_ta = 180.95 g/mol

Thus;

A_avg = 100/[(24/52) + (74/180.95)]

A_avg = 114.88 g/mol

Formula for the volume of the unit cell is;

V = n(A_avg)/(N_A × ρ_avg)

Where;

n is number of atoms in the cell which in this case = 2

N_A is avogadro's number = 6.022 × 10^(23)

Thus;

V = (2 × 114.88)/(6.022 × 10^(23) × 12.34)

V = 30.92 × 10^(-24) cm³

Length of the unit cell edge length is given by the formula;

a = ∛V

Thus;

a = ∛(30.92 × 10^(-24))

a = 0.00000003139 cm

Converting to metre, we have;

a = 0.3139 × 10^(-9) m = 0.3139 nm

Answer:

First write the balanced equation for the reaction of HCl with Zn (NOTE: the previous answer did NOT do this and thus obtained an incorrect answer)

Zn + 2HCl ==> ZnCl2 + H2(g)

moles of H2 desired:  PV = nRT

n = PV/RT = (1 atm)(10L)/(0.0821 Latm/Kmol)(298K)

n = 0.409 mole H2 desired

moles Zn needed:

0.409 moles H2 x 1 mole Zn/2 moles HCl = 0.204 moles Zn needed

mass Zn needed = 0.204 moles Zn x 65.4 g/mol = 13.4 g Zn needed (to 3 sig. figs.)

Explanation:people always get this wrong but i got you

Answer:

I think its C I'm sorry if I'm wrong good luck guys!

Explanation:

Answer: Nucleus (Hope it is Right!)

Answer:

4.16 * 10²⁴ particles

Explanation:

1. We convert from grams to moles

4 g NaCl / 58 g of NaCl = 0.0689655172 moles

-> 0.0690 moles

2. Now we will convert from moles to particles by multiplying by avogadro's number..

0.0690 * 6.022 *10²³ = 4.15518 * 10²⁴ particles or 4.16 * 10²⁴ particles

Answer:

A. 2H₂O₂  → 2H₂O + O₂

Explanation:

If we make a net sum of both reactions, we're left with:

Grouping species:

There is OI⁻ at both sides, so it is eliminated -same goes for the catalyst, I⁻-.

Thus the answer is option A.

Answer:

C10H15N is the chemical equation for methamphetamine