Answer:
true
because with the both states we increase the surface of reaction
When the pressure and number of particles of a gas are constant, which of the following is also constant
In this image, which fundamental interaction is responsible for attracting the electron?
a. electromagnetism
b. nuclear weak force
c. gravitation
d. nuclear strong force
Answer:
a.
Explanation:
electromagnetism
In the titration, 15 mL of CsOH solution is neutralized by 38.2 mL of 0.250 M HBr solution. What is the molarity of the CsOH solution?
Answer: 0.637M
10.2M
1.36M
0.0982M
Explanation: the answer is 1.36M
The molarity of the CsOH solution is 0.636 M.
What is molarity?Molarity is the concentration of any substance in a place.
The reaction is
HBr + CsOH —> CsBr + H₂O
The formula of molarity
[tex]M = \dfrac{n}{V}[/tex]
[tex]\dfrac{0.25 \times 38.2 }{15} = 0.6366[/tex]
Thus, the molarity of the CsOH solution is 0.636 M.
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A 0.457-M aqueous solution of (CH3)2NH (dimethylamine) has a pH of 12.2. Calculate the pH of a buffer solution that is 0.457 M in (CH3)2NH and 0.280 M in (CH3)2NH2 .
Answer:
pH = 10.95
Explanation:
To solve this question we must, as first, find pKb of dimethylamine. Then, using H-H equation we can solve the pH of the buffer:
pKb dimethylamine:
Based on the equilibrium:
(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH2⁺(aq) + OH-(aq)
Kb is defined as:
Kb = [OH-] [(CH3)2NH2⁺] / [(CH3)2NH]
Both (CH3)2NH2⁺(aq) + OH- comes from the same equilibrium, that means:
[OH-] = [(CH3)2NH2⁺]
And: [(CH3)2NH] = 0.457M
[OH-] can be obtained from pH as follows:
14 -pH = pOH
14-12.2 = 1.8 =pOH
10^-pOH = [OH-] = 0.01585M
Replacing:
Kb = [0.01585M] [(0.01585M] / [0.457M]
Kb = 5.50x10⁻⁴
pKb = -logkb = 3.26
pH of the buffer:
Using H-H equation for bases:
pOH = pKb + log [conjugate acid] / [weak base]
pOH = 3.26 + log [0.280M] / [0.457M]
pOH = 3.05
pH = 14 - pOH
pH = 10.95Hypothetical element A has three stable isotopes. The first isotope has a mass of 35.01 amu and an abundance of 35.00%. The second isotope has a mass of 36.01 amu and an abundance of 15.00%. The third isotope has a mass of 37.02 amu and an abundance of 50.00%. What is the atomic mass of element A
Answer:
36.16 amu
Explanation:
From the question given above, the following data were obtained:
1st Isotope:
Mass of 1st isotope = 35.01 amu
Abundance of 1st isotope = 35%
2nd isotope:
Mass of 2nd isotope = 36.01 amu
Abundance of 2nd isotope = 15%
3rd isotope:
Mass of 3rd isotope = 37.02 amu
Abundance of 3rd isotope = 50%
Atomic mass of element A =?
The atomic mass of element A can be obtained as follow:
Atomic mass = [(mass of 1st × Abundance)/100] + [(mass of 2nd × Abundance)/100] + [(mass of 3rd × Abundance)/100]
= [(35.01 × 35)/100] + [(36.01 × 15)/100] + [(37.02 × 50)/100]
= 12.25 + 5.40 + 18.51
= 36.16 amu
Thus, the atomic mass of element A is 36.16 amu
g a 144 g metal bar requires 2500 J to change its temperature from 23.5 to 100 degree C what is the specific heat of the metal
Answer:
226.9 J·kg⁻¹·°C⁻¹
Explanation:
The specific heat of a substance can be defined as the amount is heat that has to be added in order for a given mass of the substance to increase its temperature:
c = ΔQ/(m*ΔT)In this case:
ΔQ = 2500 Jm = 144 g ⇒ 144 g / 1000 = 0.144 kgΔT = 100 - 23.5 = 76.5 °CWe input the data:
c = 2500 J / (0.144 kg * 76.5 °C)And calculate c:
c = 226.9 J·kg⁻¹·°C⁻¹How many grams of the bromide salt of the conjugate acid must be combined with how many grams of the weak base, to produce 1.00 L of a buffer that is
Answer:
79.1g of weak base must be combined with 56.0g of conjugate acid
Explanation:
that is 1.00 M in the weak base?
The weak base is C5H5N with a pKa of 5.17 (Ka=6.7×10-6)and a desire pH of 5.63
The equilibrium of the weak base is with the bromide salt of the conjugate acid is:
C5H5N(aq) + H2O(l) + Br- ⇄ C5H5NHBr(aq) + OH-(aq)
Where Kb = Kw / Ka = 1x10⁻¹⁴ / 6.7x10⁻⁶
Kb = 1.49x10⁻⁹ is defined as:
Kb = 1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]
Where [OH-] = 10^-(14- pH) = 10^-(14- 5.63) = 4.255x10⁻⁹M
[C5H5N] = 1.00M
Replacing:
1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]
1.49x10⁻⁹ = [C5H5NHBr] [4.255x10⁻⁹M] / [1.00M]
[C5H5NHBr] = 0.35M
In 1L the moles of C5H5NHBr are 0.35 moles
Mass C5H5NHBr: 160.0118g/mol
0.35 moles * (160.0118g / mol) =
56.0g of C5H5NHBr are necessaries
The mass of C5H5N is -79.1g/mol-:
1.00moles * (79.1g/mol) =
79.1g of C5H5N are necessarieswhat is the definition of isomerism
Answer:
Isomerism is the phenomenon in which more than one compounds have the same chemical formula but different chemical structures. Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called isomers. Therefore, the compounds that exhibit isomerism are known as isomers.
The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”. This term was coined by the Swedish chemist Jacob Berzelius in the year 1830.
Explanation:
The steps of preparing 2M solution of NaOH
Answer:
And 500 mL of 2M NaOH solution contains 80.02g NaOH=40.0 g of NaOH .
Explanation:
So, If we mix 40.0 g of NaOH with enough distilled water to make 500 mL, we will get a 2.00 M NaOH solution.
I hope this answers help you! :>1.00 x 10-7 moles to grams
If 5.0 liters of hydrogen react with excess oxygen, what mass of water would be produced?
Answer:
our equation specifies that
32
⋅
g
of dioxygen and
4
⋅
g
of dihydrogen give
36
⋅
g
of water upon reaction, so..........
Explanation:
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
g
)
We started with
5.0
⋅
g
32.00
⋅
g
⋅
m
o
l
−
1
=
0.156
⋅
m
o
l
dioxygen
.
Given excess dihydrogen, this molar quantity thus gives
2
×
0.156
⋅
m
o
l
water.
And thus,
2
×
0.156
⋅
m
o
l
×
18.01
⋅
g
⋅
m
o
l
−
1
≅
6
⋅
g
water are evolved. Is this reaction exothermic or endothermic?
I
Gggggggggggggsgstststsysgtetwtwtst
Answer:
ummm u ok?
Explanation:
Please hurry!!! And help!!
*URGENT*
Best answer gets marked Brainliest!
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Why is elemental zinc considered a pure substance
A) it is a metal
B) it is a mixture of different atoms
C) it must be created in a lab
D) all elements are considered pure substances
Answer:
D
Explanation:
Answer:
D
Explanation:
Because it is true
What is the present Ba in Ba(NO3)2?
Answer:
Percentage of Ba = 52.5%
Explanation:
We'll begin by calculating the molar mass of Ba(NO3)₂. This can be obtained as follow:
Molar mass of Ba(NO3)₂ = 137 + 2[14 +(16×3)]
= 137 + 2[14 + 48]
= 137 + 2[62]
= 137 + 124
= 261 g/mol
Next, we shall determine the mass of Ba in Ba(NO3)₂. This can be obtained as follow:
Mass of Ba in Ba(NO3)₂ = 137 g/mol
Finally, we shall determine the percentage of Ba in Ba(NO3)₂. This can be obtained as follow:
Percentage of Ba = mass of Ba / mass of Ba(NO3)₂ × 100
Percentage of Ba = 137 / 261 × 100
Percentage of Ba = 13700 / 261
Percentage of Ba = 52.5%
Thus, the percentage of Ba in Ba(NO3)₂ is 52.5%
HEEELP! What are some examples of nuclear fusion? Select all the correct answers.
A: Being the power source of stars
B: Forming heavier elements from light elements
C: Generating electricity in power plants
D: Being used in thermonuclear weapons
E: Supplying the power source in nuclear submarines
Answer:
A B D
Explanation:
Answer: A: Being the power source of stars
B: Forming heavier elements from light elements
D: Being used in thermonuclear weapons
Explanation: (Edmentum)
A 2.00 L flask is filled with propane gas (C3H8) at a pressure of 1.10 atm and a temperature of 258 K. What is the mass of propane in the flask?
Answer:
m = 4.58 g.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:
[tex]PV=nRT[/tex]
As we can calculate the moles of propane given the pressure, temperature and volume as shown below:
[tex]n=\frac{PV}{RT} \\\\n=\frac{1.10atm*2.00L}{0.08206\frac{atm*L}{mol*K}*258K} \\\\n=0.104mol[/tex]
Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:
[tex]m=0.104mol*\frac{44.1g}{1mol}\\\\m= 4.58g[/tex]
Regards!
Which of the following has the greatest mass for one mole of the compound?
A. SIHA
B. CO
C. CH3OH
D. C2H6
The concept molar mass is used here to determine the compound which has the greatest mass for its one mole. The correct option is C.
What is molar mass?The molar mass also defined as the molecular weight of a compound is generally the sum of the atomic masses of each atoms present in the given compound. Its unit is g mol⁻¹.
The mass of 1 mole of any substance is also called the molar mass. Evidently molar mass is equal to the atomic mass or the molecular mass denoted in grams depending upon whether the substance contains atoms or molecules.
Here (SiHA) is known as the most important bioceramic which is used in the field of bioactive bone implants. The compound CO is carbon monoxide, CH₃OH is methanol and C₂H₆ is ethane.
The molar mass of the given compounds are obtained by adding their atomic masses :
CO = (12.011 g/mol+ 15.999 g/mol) = 28.01 g/mol
CH₃OH = (12.011 g/mol + 3 × 1.007 g/mol + 15.999 g/mol + 1.007 g/mol) = 32.04 g/mol
C₂H₆ = (2 × 12.011 g/mol + 6 × 1.007 g/mol) = 30.07 g/mol
Here among the given compounds CH₃OH has the greatest mass for one mole of the compound.
Thus the correct option is C - CH₃OH.
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Helpppp pleaseee ill give brainliest
Answer:
The answers are in the explanation.
Explanation:
The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:
Increasing temperature of ice from -10°C - 0°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g
Q = 2.06J/g°C*10°C*10g
Q = 206J
Change from solid to liquid:
The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:
Q = 333.55J/g*10g
Q = 3335.5J
Increasing temperature of liquid water from 0°C - 100°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g
Q = 4.18J/g°C*100°C*10g
Q = 4180J
Change from liquid to gas:
The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:
Q = 2260J/g*10g
Q = 22600J
Increasing temperature of gas water from 100°C - 120°C:
Q = S*ΔT*m
Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g
Q = 1.87J/g°C*20°C*10g
Q = 374J
Total Energy:
206J + 3335.5 J + 4180J + 22600J + 374J =
30695.5J =
30.7kJ
What is the molar mass of 4.23 g of an elemental gas in a 2.5L container at 282K and 1.4 atm?
Answer:
27.98g/mol
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
T = temperature (K)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
According to the information given:
V = 2.5L
P = 1.4 atm
T = 282K
n = ?
Using PV = nRT
n = PV/RT
n = 1.4 × 2.5/0.0821 × 282
n = 3.5/23.1522
n = 0.151mol
Using the formula to calculate molar mass of the elemental gas:
mole = mass/molar mass
Molar mass = mass/mole
Molar mass = 4.23g ÷ 0.151mol
Molar mass = 27.98g/mol
The picture below shows a NASA image of the Oort cloud, a sphere of objects that are thought to surround Earth's solar system at a distance of up to one light-year from the Sun.
If the Oort cloud does exist, which of the following could explain why the objects in it may have formed this spherical shape?
A
They are held in orbits by the Sun's gravitational force.
B
They are held in Earth's solar system by Neptune's magnetic field.
C
They float freely in space because the Sun's gravitational force is too weak to hold them in orbit.
D
They are held in stationary positions around Earth's solar system by other stars in space.
The gravitational pull of the Sun keeps them in their orbits. The gravitational pull of the Sun and surrounding stars combined is most likely what gives the Oort cloud its spherical shape.
What does NASA's Oort Cloud mean?The Oort Cloud is a spherical layer of ice objects that is thought to be located between 2,000 and 100,000 astronomical units (AU) from our Sun, a star.
What makes it the Oort Cloud?The Oort cloud, so named after the Dutch astronomer Jan Oort who first confirmed its existence, is a collection of objects with a combined mass estimated to be 10-100 times that of Earth that are less than 100 km (60 miles) across and maybe trillions in number.
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What is the equation for the reaction between ethanoic acid and butanol in the presence of H2SO4?
Answer:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this is a question about esterification, process whereby a carboxylic acid and an alcohol react to produce water an an ester, we can set it up as shown below:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH[/tex]
For the reaction between ethanoic acid and butanol; and therefore, the products side is:
[tex]CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
It means that the overall equation is:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
And the ester product is butyl ethanoate.
Regards!
HELP HELP HELP
NH3 + NO + N2 + H2O
5. Given 8.25 x 1025molecules of ammonia, determine the number of grams of
nitrogen produced.
Answer:
4NH3+6NO+5N2+6H20
Explanation:
Assume a substance X has a body centered cubic lattice. The edge length is 379.0 pm. The atomic mass of X is 195.0 amu What is the density of Xin g/cc
Answer:
[tex]\rho=12g/cm^3[/tex]
Explanation:
From the question we are told that:
Length[tex]l=379.0pm=>379*10^{-10}cm[/tex]
Atomic mass of X [tex]M= 195.0 amu=>gmol^{-1}[/tex]
Where
[tex]Avogadro\ constant = 6.023 * 10^{23} mol-1[/tex]
Let
The Number of units in BCC unit cell [tex]n= 2[/tex]
Generally the equation for Density is mathematically given by
[tex]\rho= \frac{M x n}{l^3*Avogadro constant}[/tex]
[tex]\rho=\frac{197 x 2}{(379*10^{-10})^3*6.023 x 10^{23}}[/tex]
[tex]\rho=12g/cm^3[/tex]
Therefore he density of Xin g/cc
[tex]\rho=12g/cm^3[/tex]
Which of the following statements about the pH of 0.010 M HClO4 is correct?
pH=2.00, because [H+]=1.0×10−2M.
A: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH=2.00, because [H+]=2.0×10−2M.
B: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH>2.00, because HClO4 is a strong acid.
C: p H is greater than 2.00 , because H C l O 4 is a strong acid.
pH<2.00, because HClO4 is a weak acid.
Answer:
Option B: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH = 2 because [H⁺] = 1×10¯² M
Explanation:
To know which option is correct, we shall determine the pH of the 0.010 M HClO₄ solution. This can be obtained as follow:
We'll begin by calculating the concentration of the hydrogen ion [H⁺] in the solution. This is illustrated below:
HClO₄ is a strong acid and will dessociates as follow:
HClO₄ (aq) —> H⁺ (aq) + ClO₄¯ (aq)
From the balanced equation above,
1 mole of HClO₄ produced 1 mole H⁺.
Therefore, 0.010 M HClO₄ will also produce 0.010 M H⁺.
Finally we shall determine the pH of the solution. This can be obtained as follow:
Concentration of the hydrogen ion [H⁺] = 0.010 = 1×10¯² M
pH =?
pH = –Log [H⁺]
pH = –Log 1×10¯²
pH = 2
Thus,
The pH = 2
because,
[H⁺] = 1×10¯² M
Thus, option B gives the correct answer to the question.
Based on the definition of pH, pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.
What is pH?The pH of a solution is the negative logarithm of the hydrogen ion concentration of a solution.
pH of a solution is a measure of the acidity of the solution.
pH = - log[H+]where
[H+] is hydrogen ion concentrationFor the 0.010 M solution of HClO4, [H+} = 0.01 M
pH = -log(0.01)
pH = 2.00
Therefore, pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.
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How many of the planets have an orbital period of less than one Earth year?
Since orbital period depends on how far you are from the sun, planets closer to the sun have a orbital period less than one earth year.
These planets are Mercury and Venus
In the reaction below does water acts as the acid or as the base?
H2S + H20 - HS1- + H30+ *
O a. Neither, water is neutral
O b. Acid
O C. Base
Answer:
C. Base.
Explanation:
Hello there!
In this case, according to the given information, it turns out convenient for us to realize that the concept acid and base we should use here is based off the Bronsted-Lowry one, which says that an acid is a hydrogen donor. In such a way, since water accepts one H ion as it goes to H3O⁺, we infer it is C. Base and the H2S the acid.
Also, we can tell HS⁻ is the conjugate base and H3O⁺ the conjugate acid.
Regards!
How many moles are in 150g of Li2O?
Answer:
moles= w/mm
moles=150/30
moles=5
What is a metal oxide + acid
Metal oxide + acid —> __+__
Answer:
Metal oxide + acid —> salt + water
Explanation:
Quais são os nomes dos planetas anões
Answer:
Can you translate it on English so we can understand
The gases in a hair spray can are at a temperature of 26.0 °C and a pressure of 25.0 lbs/in2. If the gases in the can reach a pressure of
90.0 Ibs/in?, the can will explode. To what temperature in Celsius must the gases be raised in order for the can to explode?
Answer:
The gases in a hair spray can are at a temperature of 26.0 °C and a pressure of 25.0 lbs/in2.
If the pressure becomes [tex]90.0lbs/in^{2}[/tex], what is the temperature of the gases?
Explanation:
According to Gay lussac's law:
the pressure of a gas is directly proportional to its absolute temperature.
[tex]P\alpha T[/tex]
[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }[/tex]
Given,
[tex]P1=25.0lbs/in^{2} \\P2=90.0lbs/in^{2} \\T1=26^{o} C=(26+273)K=299K\\T2=?[/tex]
Substitute these values in the above formula:
[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }\\\\\frac{25lbs/in^{2} }{299K} }=\frac{90.0lbs/in^{2} }{T{2} }\\\\\\On simplification \\T2=1076.4K\\T2=(1076.4-273)^{o} C=803.4^{o} C[/tex]
Answer:
The gases will be raised to a temperature of 803.4[tex]^{o} C[/tex].