Answer:
The total normal force acting on the system is approximately 58.8 N
Explanation:
The masses arranged in the stack are;
3 kg, 2 kg, and 1 kg
The mass of the stack system, m = 3 kg + 2 kg + 1 kg = 6 kg
Weight = The force of gravity on an object = m·g
Where;
m = The mass of the object
g = The acceleration due to gravity ≈ 9.8 m/s²
∴ The weight of the stack system, W ≈ 6 kg × 9.8 m/s² ≈ 58.8 N
The direction of the weight force = Perpendicular to the surface (acting downwards)
From Newton's third law of motion, the normal force acts perpendicular to the plane and it is equal in magnitude to the force acting perpendicular to the plane
∴ The magnitude of the total normal force acting on the system = The magnitude of the weight of the system ≈ 58.8 N
The (magnitude of the) total normal force acting on the system ≈ 58.8 N
According to the Law of Reflection, a light ray strikes a mirror ________________________________.
moves into the mirror at a slightly different angle.
continues moving through the mirror in the same direction.
bounces off the mirror towards the direction it came from.
bounces off the mirror at the same angle it hits the solid surface.
Answer:
bounces off the mirror at the same angle it hits the solid surface.
Explanation:
According to the Law of Reflection, a light ray strikes a mirror at the point of incidence bounces off the mirror at the same angle it hits the solid surface.
The incident ray and the reflected ray lie in the same plane
The angle of incidence is equal to the angle of reflection as a ray of light reflects off a solid surface.
So,
correct answer is ''bounces off the mirror at the same angle it hits the solid surface.''
Solar energy heats the surface of the Earth, including the ground, rocks, and even roadways. As the temperature of these surfaces increases, heat energy is released back into the atmosphere, forming a pocket of warm air. As the warm air pocket rises, it is replaced by cooler air. This process is responsible for many of the weather patterns in our atmosphere and is known as
Answer:
convection
Explanation:
I hope this helps
Which of the following is an example of an electromagnetic wave ?
Answer:
Its a wave
Explanation:
THis is one
Answer: a light wave
Explanation: a pex
A room is 5.0 m long, 4.0 m wide, and 3.0 m high. What is the mass of the air it contains?
Answer:
Here u go
Explanation:
Mass of air in the room m= volume of room×density of air
=(5m×4m×3m)(1.20kgm3)=72kg
Weight of air, W=mg=(72kg)(9.8ms2)=706N.
Answer:
person above is correct, i did the work and got the smae answer
A rolling ball has 18 J of kinetic energy and is rolling 3 m/s. Find its mass.
If you did 3x18 this would equal 54
Find the acceleration due to gravity on Titan's surface, given that its mass is 1.35 x 102kg and its radius is 2570 km
Answer:
1.36 x [tex]10^{-15}[/tex][tex]ms^{-2}[/tex]
Explanation:
The equation [tex]g = \frac{G*M}{R^2}[/tex] would be used where:
g = acceleration due to gravity
G = universal gravitational constant (6.67408 × [tex]10^{-11}[/tex] [tex]m^{3} kg^{-1} s^{-2}[/tex])
M = mass
R = radius.
assuming the value following 10 is its exponent, which is a little confusing, the values given would simply be substituted.
Anyone can correct me if I'm wrong.
Write down the letter of the substance that represents water
Answer:
If you are talking about it's "scientific" name, it is H_2O
Explanation:
The attached image is what the name really looks like, it wouldn't let me type it correctly on here.
Please consider giving me brainliest if this helped you! :)
Find out about organisms that has been bred by humans. It could be a pet such as a dog. A farm animal such as chicken or a crop, such as corn.
An object with a velocity of
1 m s-l accelerates with an
acceleration of 1 m s2.
What is its velocity after
moving 1 m?
A 1.4 ms s-1
B 1.7 m s -1
C) 2.0 m s-
D 3.0 m s-1
-1
Answer:
v = 1.7 m/s
Explanation:
Given that,
Initial velocity of the object, u = 1 m/s
Acceleration of the object, a = 1 m/s²
We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.
[tex]v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v^2=2(1)(1)+1^2\\\\v=\sqrt3\\\\v=1.7\ m/s[/tex]
So, the final velocity of the object is 1.7 m/s.
help me, what is the shape of solid?
Explanation:
Solids have a definite shape and definite volume.
Answer:
Solids have a definite shape and volume because the particles in them are held together tightly.
Explanation:
Liquids have a definite volume but their particles aren't held together as tightly as solids, so liquids take on the shape of the container they are in. Gases have no definite shape OR volume they just float around because the particles in them are so loose they can take on the shape and volume of any container.
Anyone know the answer
A body of mass m1 = 1.5 kg moving along a directed axis in the positive sense with a velocity
of 11 ms-1 collides head-on with a body of mass m2 = 14 kg moving in the negative sense
with a velocity of 5 ms-1. If the velocity of m1 after the collision is 1 m s-1 in the negative
sense, Apply your scientific knowledge and understanding of collisions to solve the problem
and find the final velocity of m2.
Answer:
3.71 m/s in the negative direction
Explanation:
From collisions in momentum, we can establish the formula required here which is;
m1•u1 + m2•v2 = m1•v1 + m2•v2
Now, we are given;
m1 = 1.5 kg
m2 = 14 kg
u1 = 11 m/s
v1 = -1 m/s (negative due to the negative direction it is approaching)
u2 = -5 m/s (negative due to the negative direction it is moving)
Thus;
(1.5 × 11) + (14 × -5) = (1.5 × -1) + (14 × v2)
This gives;
16.5 - 70 = -1.5 + 14v2
Rearranging, we have;
16.5 + 1.5 - 70 = 14v2
-52 = 14v2
v2 = - 52/14
v2 = 3.71 m/s in the negative direction
The final velocity of the body 2 is 3.71 m/s in the negative sense.
The given parameters:
Mass of the body 1, m1 = 1.5 kgMass of the body 2, m2 = 14 kgInitial velocity of body 1, u1 = 11 m/sInitial velocity of the body 2, u2 = - 5m/sFinal velocity of body 1, v1 = -1 m/sThe final velocity of the body 2 is calculated by applying the principle of conservation of linear momentum;
[tex]m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\1.5(11) + 14(-5) = 1.5(-1) + 14(v_2)\\\\-53.5 = -1.5+ 14v_2\\\\-52 = 14v_2\\\\v_2 = \frac{-52}{14} \\\\v_2 = -3.71 \ m/s[/tex]
Thus, the final velocity of the body 2 is 3.71 m/s in the negative sense.
Learn more about conservation of momentum here: https://brainly.com/question/7538238
What is the definition of input force?
Answer:
The input force (effort) is the amount of effort used to push down on a rod, or pull on a rope in order to move the weight. In this example, the force the little guy is using to pull the elephant is the input force.
Explanation:
Who created the periodic table
Answer:
Dimitri Mendeleev
In 1869 Russian chemist Dimitri Mendeleev started the development of the periodic table, arranging chemical elements by atomic mass. He predicted the discovery of other elements, and left spaces open in his periodic table for them.
fast need answers
Find the amount of force if the body has pressure of 178 Pa on 18 mm²
Answer:
Force = 3.204Newton
Explanation:
Given the following data;
Pressure = 178
Area = 18 mm² to meter = 18/1000 = 0.018 m²
To find the force;
Force = pressure * area
Force = 178 * 0.018
Force = 3.204 Newton.
Which of the following is/are true about magnetic field lines? *
Points away from the south pole and toward the north pole
Uniformly intersect other magnetic field lines
They present the direction and not the force of the magnetic field
They represent the strength of the magnetic field
All of the above
None of the above
Answer:
Explanation:
Interest to
Answer:
Points away from the south pole and toward the north pole
Explanation:
They're magnets fam
A crowbar is used to lift a load of 1200 N by placing it at a distance of 25 cm from the fulcrum.
the force required at 60 cm from the fulcrum to balance the load.
Answer:
500 N
Explanation:
From the question,
Sum of clockwise moment = sum of anti clockwise moment.
F×d = F'×d'.................. Equation 1
Where F = Force applied to lift the load, d = distance, F' = Force required, d' = distance of the required force from the fulcrum
Make F' the subject of the equation
F' = F×d/d'.................. Equation 2
Given: F = 1200 N, d = 25 cm, d' = 60cm.
Substitute these values into equation 2
F' = 1200×25/60
F' = 500 N.
Hence the force required to balance the load is 500 N
I need help haha, I need to get 5 brainiest to move on to the next stage, anyone help me plz! I've tried answering normal questions and no one gives it to me so ugh help.
Answer:
ohk but u also thank me and mark as brainliest
a ball rolls from rest down an incline with a uniform acceleration of 4m/s². what is it speed after 8 seconds
Three charges lie along the x-axis. One positive charge, q1 = 4.80*10^-18 C, is at x = 3.72 m, and another positive charge, q2 = 1.60*10^-19 C, is at the origin.
At what point on the x-axis must a negative charge, q3, be placed so that the resultant force on it is zero?
Answer:
The third charge needs to be placed at [tex]x \approx 0.57\; \rm m[/tex].
Explanation:
Both [tex]q_1[/tex] and [tex]q_2[/tex] would attract [tex]q_3[/tex].
These two electrostatic attractions need to balance one another. Hence, they need to be opposite to one another. Therefore, [tex]q_1[/tex] and [tex]q_2[/tex] need to be on opposite sides of [tex]q_3[/tex]. That is possible only if [tex]q_3 \![/tex] is on the line segment between [tex]q_1 \![/tex] and [tex]q_2 \![/tex].
Assume that [tex]q_3[/tex] is at [tex]x\; \rm m[/tex], where [tex]0 < x < 3.72[/tex] (in other words, [tex]q_3 \![/tex] is on the line segment between [tex]q_1[/tex] and [tex]q_2[/tex], and is [tex]x\; \rm m \![/tex] away from [tex]q_2 \![/tex].)
Let [tex]k[/tex] denote Coulomb's constant.
The magnitude of the electrostatic attraction between [tex]q_1[/tex] and [tex]q_3[/tex] would be:
[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}}[/tex].
Similarly, the magnitude of the electrostatic attraction between [tex]q_2[/tex] and [tex]q_3[/tex] would be:
[tex]\displaystyle \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].
The magnitudes of these two electrostatic attractions need to be equal to one another for the resultant electrostatic force on [tex]q_3[/tex] to be [tex]0[/tex]. Equate these two expressions and solve for [tex]x[/tex]:
[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}} = \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].
[tex]\displaystyle \frac{q_1}{(3.72 - x)^{2}} = \frac{q_2}{x^{2}}[/tex].
[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1}[/tex].
[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1} = \frac{1}{30}[/tex].
By the assumption that [tex](0 < x < 3.72)[/tex], it should be true that [tex](x > 0)[/tex] and [tex](3.72 - x > 0)[/tex]. Therefore, [tex]\displaystyle \frac{x}{(3.72 - x)} > 0[/tex].
Take the square root of both sides of the equation [tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{1}{30}[/tex].
[tex]\displaystyle \sqrt{\frac{x^2}{(3.72 - x)^{2}}} = \sqrt{\frac{1}{30}}[/tex].
[tex]\displaystyle \frac{x}{3.72 - x} = \frac{1}{\sqrt{30}}[/tex].
[tex]\sqrt{30}\, x = 3.72 - x[/tex].
Therefore:
[tex]\left(1 + \sqrt{30}\right)\, x = 3.72[/tex].
[tex]\displaystyle x = \frac{3.72}{1 + \sqrt{30}} \approx 0.57[/tex].
Hence, [tex]q_3[/tex] should be placed at [tex]x \approx 0.57\; \rm m[/tex].
For which angle of projection range of projectile is maximum
(a) 40°
(b) 35°
(e) 43°
(d) 48°
Answer:
the correct answer is e
Explanation:
In projectile launching, the range or distance on the x-axis is given by the expression
R = [tex]\frac{v_o^2 \ sin 2 \theta }{g}[/tex]
where v₀ is the initial velocity θ the launch angle.
When analyzing this expression is maximum when the sine function is maximum
sin 2 θ = 1
2θ = sin⁻¹ 1
2 θ = 90
θ = 90/2
θ = 45º
reviewing the answers there are no correct ones since the maximum angle occurs for 45º
if we analyze with these angles we have
θ = 40
sin 2θ = sin 2 40 = 0.98
θ = 35
sin 2 35 = 0.939
θ = 43
sin 2 43 = 0.998
θ = 48
sin 2 48 = 0.994
if we take the written angles the range is maximum for 43º
therefore the correct answer is e
If a light bulb uses 60J of electrical energy and produces 30 J of light energy, what is the percent efficiency of the light bulb?
Answer:
50%
Explanation:
If a light bulb uses 60J of electrical energy and produces 30 J of light energy, the percent efficiency of the light bulb is 50%.
What is percent efficiency?The total amount of beneficial work accomplished, excluding waste and spoilage, is known as output or work output.
This pulp creates 30 jewels' worth of light energy, for a total of 60 jewels. So that's the energy output. Let's use E. O. to symbolize it. Those are 30 Jews.
Additionally, we must calculate the light bulb's efficiency %. Therefore, we will start by computing the efficiency, which is defined as the ratio of energy output to energy input in this book.
And 30/60 is the efficiency that we obtain. Moreover, this is 1 x 2.
The straightforward ratio between output and input energy—by 100. And the result is that this is 50%. That is the required efficiency percentage for this light bulb.
Therefore, the percent efficiency of the light bulb is 50%
To learn more about percent efficiency, refer to the link:
https://brainly.com/question/23818307
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determine the indication of voltmeter
Answer:
Hey mate.....
Explanation:
This is ur answer.....
A voltmeter is an instrument used for measuring electric potential difference between two points in an electric circuit. It is connected in parallel. It usually has a high resistance so that it takes negligible current from the circuit.
Hope it helps you,
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A worker drives a .500kg spike into a rail tie with a 2.50kg sledgehammer. The hammer hits the spike with a speed of 65.0 m/s. If one-third of the hammer's kenetic energy is converted to the internal energy of the hammer and spike, how much does the total internal energy increase?
Answer:
The increase internal energy is 1,760.41[tex]\overline 6[/tex] J
Explanation:
The given parameters of the worker, sledgehammer, and rail line are;
The mass of the spike driven into the rail, m₁ = 0.500 kg
The mass of the sledgehammer, m₂ = 2.50 kg
The speed of the sledgehammer, v = 65.0 m/s
The fraction of the hammers kinetic energy, KE, converted to the internal energy of the hammer and the spike, Δ[tex]E_{internal}[/tex] = 1/3 × KE
Therefore, we have;
The kinetic energy, KE, of the sledgehammer is given by KE = 1/2·m₂·v²
Where;
m₂ = The mass of the sledge hammer = 65.0 m/s
v = The velocity o the sledgehammer
∴ KE = 1/2 × 2.50 kg × (65.0 m/s)² = 5,281.25 J
Therefore;
The increase internal energy, Δ[tex]E_{internal}[/tex] = 1/3 × 5,281.25 J = 1760.41[tex]\overline 6[/tex] J
Which statement accurately describes renewable energy sources?
A. They include fossil fuels and hydroelectric power.
B. They are found in nearly limitless supply.
C. They take millions of years to form and should be used responsibly.
D. They provide the majority of the energy for the United States.
PLS HELP!! I WILL GIVE BRAINLYIST!!
Answer:
A, They include fossil fuels and hydroelectric power.
Explanation:
Hope this helped!!!! :)) <3
1.
Two children sit on a uniform seesaw such that a 400. N child is 2.0 m from the support. How
far from the center should the second child of weight 475 N sit in order to balance the system
if the support is at the center of the plank?
Answer:
The other child must sit the same meters as the N child so they an be balanced.
Explanation:
A pitcher requires about 3 seconds to throw a baseball if the ball leaves his hand with with a speed of 30 m/s what is its acceleration
Answer:
Explanation:
300m/s2
Simplify the expression in part H. Following the five payments, what is the net change in the loan amount from Qulana's viewpoint?
Answer:
I'm not sure but, this video's pretty cool: gestyy.com/eyRkH2
Explanation:
pretty scary gameplay
Answer:
After five monthly payments, Quiana’s loan amount changes by $1,237.15.
Explanation:
Brainliest to correct answer
Calculate the focal length of a concave mirror whose image distance is 0.080m when the object distance is 0.25m.
Answer:
0.061m
Explanation:
Given the following
image distance v = 0.080m
Object distance u = 0.25m
For concave mirror, the image distance is positive
Using the mirror formula;
1/f = 1/u + 1/v
1/f = 1/0.25 + 1/0.080
1/f = 4 + 12.5
1/f = 16.5
f = 1/16.5
f = 0.061m
Hence the focal length of the mirror is 0.061m
If you go twice as fast, your kinetic energy becomes. . .Immersive Reader
(1 Point)
2 times smaller
4 times smaller
2 times bigger
4 times bigger
Answer:
Our kinetic energy becomes 4 times bigger