At which point does the planet have the least gravitational force acting on it?
Answer:
At which point does the planet have the least gravitational force acting on it?
Explanation:
In an elliptical orbit, when a planet is at its furthest point from the Sun, it is under the least amount of gravity, meaning that the force of gravity is strongest when it is closest.
Answer:
Point A
Explanation:
Recall that gravitational force is inversely proportional to the square of the distance between the 2 objects.
This means that the farther away the objects are from each other, the lesser their gravitational interaction will be.
In this case we can see that Point A is furthest away from the star, hence this will be the location with the least gravitational force from the star.
What would be the mass of the ball described in the photo?
Answer:
- Mass of the ball = 45 Kg
Explanation:
velocity attained by the ball:
Distance/time= 54/9 = 6m/s (meter per sec)
As work done on ball = distance * force applied
= 54*15
= 810 J ----------------- (i)
acc. to the conservation of energy:
work done = kinetic energy + potential energy
= 1/2*m*[tex]v^{2}[/tex] + 0(as object is on ground)
= 1/2*m*[tex]6^{2}[/tex]
= 1/2*36*m
= 18*m ------------------- (ii)
∵,(i) =(ii)
18*m = 810
m=810/18
m= 45kg
How is a voltmeter used in a circuit?
A. It is connected in series and measures current.
B. It is connected in parallel and measures potential difference.
C. It is connected in parallel and measures current.
D. It is connected in series and measures potential difference.
Answer:
Explanation:
A voltmeter is usually connected in parallel with a part of a complete circuit. The meter itself is connected in series to a very high resistance so that the amount of current drained is very tiny.
So you see, you could answer this in two ways, but since you are asking a question at a very beginning level, I think the answer should be
B
because voltmeters are made to measure potential difference and they are placed in parallel to the part measured. How it works is interesting but is not really part of the question.
Answer:
B. It is connected in parallel and measures potential difference.
Explanation:
A voltmeter is connected in parallel.
A voltmeter is used for measuring the electrical potential difference between two points in an electric circuit.
In general, the the string or air column of a musical instrument is, the more harmonics are generated.
Answer:
In general, the LONGER the string or air column of a musical instrument is, the more harmonics are generated.
Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the displacement of the object?
the area of the rectangle under the line
the area of the rectangle above the line
the area of the rectangle plus the area of the triangle under the line
the area of the rectangle plus the area of the triangle above the line
Answer:
The area of the rectangle plus the area of the triangle under the line
Explanation:
In this case, the object moves with constant acceleration. Initial speed of the object is 0.
Equation of kinematics :
v = u +at
v = at
v is directly proportional to time. If means that the graph is straight line passing through origin. We know that area under v-t graph gives displacement. So, the correct option is (c).
Answer:
c) the area of the rectangle plus the area of the triangle under the line
Explanation:
edge2021
Priscilla is driving her car on a busy street and Harvey passes her on his motorcycle. What will happen to the sound from his motorcycle after it
passes her car?
Answer:
what will happen to the sound is the wavelength increases thus frequency decreases so the sound decreases as he move away from her car..
A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror? A. –5.0 cm B. 7.5 cm C. -7.5 cm D. 5.0 cm
Answer: D. 5cm
Explanation:
Given the following :
Focal length (f) = - 6.0 cm
Height of object = 15.0cm
Distance of object from mirror (u) = 12.0cm
Height of image produced by the mirror =?
Firstly, we calculate the distance of the image from the mirror.
Using the mirror formula
1/f = 1/u + 1/v
1/v = 1/f - 1/u
1/v = 1/-6 - 1/12
1/v = - 1/6 - 1/12
1/v = (- 2 - 1) / 12
1/v = - 3 / 12
v = 12 / - 3
v = - 4
Using the relation :
(Image height / object height) = (- image distance / object distance)
Image height / 15 = - (-4) / 12
Image height / 15 = 4 / 12
Image height = (15 × 4) / 12
Image height = 60 / 12
Image height = 5cm
Answer:
D. 5 cm
Explanation:got it right