(a) The statement assumes that the population mean of radon in New Brunswick houses (β) is equal to the EPA cutoff of 4.
The null hypothesis can be written as:
H0: β = 4
(b) The alternative hypothesis can be written as:
Ha: β ≠ 4
This statement suggests that the population mean of radon in New Brunswick houses (β) is not equal to the EPA cutoff of 4.
(c) When testing this null hypothesis, a two-tailed test is used. This is because the alternative hypothesis does not specify a direction (greater than or less than), but instead allows for the possibility that the population mean can differ from the EPA cutoff in either direction.
(d) To test the null hypothesis, we need to use an estimator of β. In this case, the sample mean (x) will serve as the estimator of β. The formula for the variance of this estimator, assuming simple random sampling, is:
Var(x) = σ²/n
Here, σ represents the population standard deviation and n is the sample size. To estimate this variance formula, we need the sample standard deviation (s). The estimated variance formula becomes:
Var(x)≈ s²/n
To obtain a standard error for the estimator of β, we take the square root of the estimated variance:
SE(x) ≈ √(s²/n)
4. To test the null hypothesis using a t-test, we will compute the t-statistic using the formula:
t = (x-β) / (SE(x))
In this case, since β is known (4), the formula simplifies to:
t = (x- 4) / (SE(x))
To carry out the test at the 5% significance level (α = 0.05), we will compare the computed t-statistic to the critical value(s) from the t-distribution with appropriate degrees of freedom. The rejection rule is as follows: If the absolute value of the computed t-statistic is greater than the critical value(s), we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.
The result of the test will indicate whether there is sufficient evidence to reject the null hypothesis or not.
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5. Given two curves as follows: y = x² +2 and y=4-x a. Sketch and shade the region bounded by the curves and determine the interception point. b. Find the area of the region bounded by the curves.
A: The points of interception are (1, 3), and (-2, 6).
B. The region enclosed by the curves y = x^2 + 2 and y = 4 - x has a surface area of 7/6 square units.
a. To sketch and shade the region bounded by the curves y = x² + 2 and y = 4 - x, we first need to find the interception point.
Setting the two equations equal to each other, we have:
x² + 2 = 4 - x
Rearranging the equation:
x² + x - 2 = 0
Factoring the quadratic equation:
(x - 1)(x + 2) = 0
This gives us two possible values for x: x = 1 and x = -2.
Plugging these values back into either of the original equations, we find the corresponding y-values:
For x = 1: y = (1)² + 2 = 3
For x = -2: y = 4 - (-2) = 6
Therefore, the interception points are (1, 3) and (-2, 6).
To sketch the curves, plot these points on a coordinate system and draw the curves y = x² + 2 and y = 4 - x. The curve y = x² + 2 is an upward-opening parabola that passes through the point (0, 2), and the curve y = 4 - x is a downward-sloping line that intersects the y-axis at (0, 4). The curve y = x² + 2 will be above the line y = 4 - x in the region of interest.
b. To find the area of the region bounded by the curves, we need to find the integral of the difference of the two curves over the interval where they intersect.
The area is given by:
Area = ∫[a, b] [(4 - x) - (x² + 2)] dx
To determine the limits of integration, we look at the x-values of the interception points. From the previous calculations, we found that the interception points are x = 1 and x = -2.
Therefore, the area can be calculated as follows:
Area = ∫[-2, 1] [(4 - x) - (x² + 2)] dx
Simplifying the expression inside the integral:
Area = ∫[-2, 1] (-x² + x + 2) dx
Integrating this expression:
Area = [-((1/3)x³) + (1/2)x² + 2x] evaluated from -2 to 1
Evaluating the definite integral:
Area = [(-(1/3)(1)³) + (1/2)(1)² + 2(1)] - [(-(1/3)(-2)³) + (1/2)(-2)² + 2(-2)]
Area = [(-1/3) + (1/2) + 2] - [(-8/3) + 2 + (-4)]
Area = (5/6) - (-2/3)
Area = 5/6 + 2/3
Area = 7/6
Therefore, the area of the region bounded by the curves y = x² + 2 and y = 4 - x is 7/6 square units.
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Evaluate the expression if a=2, b=6 , and c=3 .
\frac{1}{2} c(b+a)
Substituting a = 2, b = 6, and c = 3 into the expression:
1
2
(
3
)
(
6
+
2
)
2
1
(3)(6+2)
Simplifying the expression:
1
2
(
3
)
(
8
)
=
12
2
1
(3)(8)=12
Therefore, when a = 2, b = 6, and c = 3, the expression
1
2
�
(
�
+
�
)
2
1
c(b+a) evaluates to 12.
To evaluate the expression
1
2
�
(
�
+
�
)
2
1
c(b+a) when a = 2, b = 6, and c = 3, we substitute these values into the expression and perform the necessary calculations.
First, we substitute a = 2, b = 6, and c = 3 into the expression:
1
2
(
3
)
(
6
+
2
)
2
1
(3)(6+2)
Next, we simplify the expression following the order of operations (PEMDAS/BODMAS):
Within the parentheses, we have 6 + 2, which equals 8. Substituting this result into the expression, we get:
1
2
(
3
)
(
8
)
2
1
(3)(8)
Next, we multiply 3 by 8, which equals 24:
1
2
(
24
)
2
1
(24)
Finally, we multiply 1/2 by 24, resulting in 12:
12
Therefore, when a = 2, b = 6, and c = 3, the expression
1
2
�
(
�
+
�
)
2
1
c(b+a) evaluates to 12.
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a) Given d8 day +3 dn³ Find the values of ai 6) Using values of value problem d³y a dn³ e-nz homogenous linear constant + d₂ d²y +9, dy +9。y = 0 dn Ina where a; In (9) below. is the fundamental fcs, Scanned with tamsoje 2 y coeffrerents i=0₁3. solve the initra/ + do day to dy + day = > cite-x) dn² dn 9" (0)=2
The values of ai in the given equation are not specified. More information is needed to determine the values of ai.
In the given equation, "d8 day +3 dn³ Find the values of ai," it is not clear what the specific values of ai are. The equation seems to involve derivatives (d) with respect to time (t), and the symbols day and dn represent different orders of differentiation.
However, without further information or context, it is not possible to determine the specific values of ai.
To provide a solution, we would need additional details or equations that define the relationship between the variables and derivatives involved. Without these details, it is not possible to solve the equation or find the values of ai.
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Use the formula for future value, A=P(1+rt), and elementary algebra to find the missing quantity. A=$2,160; r=5%; 1= 4 years
Answer:
Step-by-step explanation:
To find the missing quantity in the formula for future value, A = P(1 + rt), where A = $2,160, r = 5%, and t = 4 years, we can rearrange the formula to solve for P (the initial principal or present value).
The formula becomes:
A = P(1 + rt)
Substituting the given values:
$2,160 = P(1 + 0.05 * 4)
Simplifying:
$2,160 = P(1 + 0.20)
$2,160 = P(1.20)
To isolate P, divide both sides of the equation by 1.20:
$2,160 / 1.20 = P
P ≈ $1,800
Therefore, the missing quantity, P, is approximately $1,800.
From Mathematical Modeling Book by Stefan Heinz 7. 2. 1 A cup of coffee at 90C is poured into a mug and left in a room at 21C After one minute, the coffee temperature is 85C. Suppose that the coffee temperature does obey Newton's Law of Cooling. The coffee becomes safe to drink after it cools to 60C. How long will it take before you can drink the coffee, this means at which time is the coffee temperature 60C?
Answer:
To determine the time it takes for the coffee to cool to 60°C, we can use Newton's Law of Cooling, which states that the rate of change of temperature of an object is proportional to the difference between its current temperature and the surrounding temperature.
Let's denote:
- T(t) as the temperature of the coffee at time t
- T_r as the room temperature (21°C)
- k as the cooling constant
According to Newton's Law of Cooling, we can write the differential equation:
dT/dt = -k(T - T_r)
To solve this differential equation, we need an initial condition. In this case, we know that at t = 0 (when the coffee is poured into the mug), the temperature of the coffee is T(0) = 90°C.
Now we can solve the differential equation to find the time when the coffee temperature reaches 60°C.
Separating variables and integrating, we get:
∫(1 / (T - T_r)) dT = -∫k dt
ln|T - T_r| = -kt + C
Taking the exponential of both sides:
T - T_r = Ce^(-kt)
Applying the initial condition T(0) = 90°C, we have:
90 - 21 = Ce^(0) => C = 69
Therefore, the equation becomes:
T - 21 = 69e^(-kt)
To find the value of k, we can use the information given that after 1 minute, the coffee temperature is 85°C:
85 - 21 = 69e^(-k * 1)
64 = 69e^(-k)
Dividing both sides by 69:
e^(-k) = 64/69
Taking the natural logarithm of both sides:
-k = ln(64/69)
Solving for k:
k ≈ -0.065
Now we can plug in the values into the equation T - 21 = 69e^(-kt) and solve for the time t when the temperature T equals 60°C:
60 - 21 = 69e^(-0.065t)
39 = 69e^(-0.065t)
Dividing both sides by 69:
e^(-0.065t) = 39/69
Taking the natural logarithm of both sides:
-0.065t = ln(39/69)
Solving for t:
t ≈ -ln(39/69) / 0.065
Using a calculator, we find that t ≈ 4.44 minutes.
Therefore, it will take approximately 4.44 minutes before the coffee temperature reaches 60°C and becomes safe to drink.
[4 points] a. Find the solution of the following initial value problem. -51 =[₁² = 5] x, x(0) = [1]. -3. x' b. Describe the behavior of the solution as t → [infinity] . [3 [1
(a) The solution of the initial value problem is x(t) = -51e^(-5t), and x(0) = 1.
(b) As t approaches infinity, the behavior of the solution x(t) is that it approaches zero. In other words, the solution decays exponentially to zero as time goes to infinity.
To find the solution of the initial value problem -51x' = x^2 - 5x, x(0) = 1, we can separate the variables and integrate.
Starting with the differential equation:
-51x' = x^2 - 5x
Dividing both sides by x^2 - 5x:
-51x' / (x^2 - 5x) = 1
Now, let's integrate both sides with respect to t:
∫ -51x' / (x^2 - 5x) dt = ∫ 1 dt
On the left side, we can perform a substitution: u = x^2 - 5x, du = (2x - 5) dx. Rearranging the terms, we get dx = du / (2x - 5).
Substituting this into the left side of the equation:
∫ -51 / u du = ∫ 1 dt
Simplifying the integral on the left side:
-51ln|u| = t + C₁
Now, substituting back u = x^2 - 5x and simplifying:
-51ln|x^2 - 5x| = t + C₁
To find the constant C₁, we can use the initial condition x(0) = 1. Substituting t = 0 and x = 1 into the equation:
-51ln|1^2 - 5(1)| = 0 + C₁
-51ln|1 - 5| = C₁
-51ln|-4| = C₁
-51ln4 = C₁
Therefore, the solution to the initial value problem is:
-51ln|x^2 - 5x| = t - 51ln4
Simplifying further:
ln|x^2 - 5x| = -t/51 + ln4
Taking the exponential of both sides:
|x^2 - 5x| = e^(-t/51) * 4
Now, we can remove the absolute value by considering two cases:
1) If x^2 - 5x > 0:
x^2 - 5x = 4e^(-t/51)
2) If x^2 - 5x < 0:
-(x^2 - 5x) = 4e^(-t/51)
Simplifying each case:
1) x^2 - 5x = 4e^(-t/51)
2) -x^2 + 5x = 4e^(-t/51)
These equations represent the general solution to the initial value problem, leaving it in implicit form.
As for the behavior of the solution as t approaches infinity, we can analyze each case separately:
1) For x^2 - 5x = 4e^(-t/51):
As t approaches infinity, the exponential term e^(-t/51) approaches zero, which implies that the right side of the equation approaches zero. Therefore, the left side x^2 - 5x must also approach zero. This implies that the solution x(t) approaches the roots of the quadratic equation x^2 - 5x = 0, which are x = 0 and x = 5.
2) For -x^2 + 5x = 4e^(-t/51):
As t approaches infinity, the exponential term e^(-t/51) approaches zero, which implies that the right side of the equation approaches zero. Therefore, the left side -x^2 + 5x must also approach zero. This implies that the solution x(t) approaches the roots of the quadratic equation -x^2 + 5x = 0, which are x = 0 and x = 5.
In both cases, as t approaches infinity, the solution x(t) approaches the values of 0 and 5.
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A box contains 12 distinct colored balls (for instance, we could label them as 1, 2, ..., 12 to distinguish them). Three of them are red, four are yellow, and five are green. Three balls are selected at random from the box, with replacement. Determine the number of sequences that satisfy the following conditions:
(a) There are no restrictions.
(b) The first ball is red, the second is yellow, and the third is green.
(c) The first ball is red, and the second and third balls are green.
(d) Exactly two balls are yellow.
(e) All three balls are green.
(f) All three balls are the same color.
(g) At least one of the three balls is red.
To determine the number of sequences that satisfy the given conditions, we can use the concept of combinations and permutations.
(a) There are no restrictions:
Since there are no restrictions, we can select any of the 12 balls for each of the three positions, with replacement. Therefore, the number of sequences is 12^3 = 1728.
(b) The first ball is red, the second is yellow, and the third is green:
For this condition, we need to select one of the three red balls, one of the four yellow balls, and one of the five green balls, in that order. The number of sequences is 3 * 4 * 5 = 60.
(c) The first ball is red, and the second and third balls are green:
For this condition, we need to select one of the three red balls and two of the five green balls, in that order. The number of sequences is 3 * 5C2 = 3 * (5 * 4) / (2 * 1) = 30.
(d) Exactly two balls are yellow:
We can select two of the four yellow balls and one of the eight remaining balls (red or green) in any order. The number of sequences is 4C2 * 8 = (4 * 3) / (2 * 1) * 8 = 48.
(e) All three balls are green:
Since there are five green balls, we can select any three of them in any order. The number of sequences is 5C3 = (5 * 4) / (2 * 1) = 10.
(f) All three balls are the same color:
We can choose any of the three colors (red, yellow, or green), and then select one ball of that color in any order. The number of sequences is 3 * 1 = 3.
(g) At least one of the three balls is red:
To find the number of sequences where at least one ball is red, we can subtract the number of sequences where none of the balls are red from the total number of sequences. The number of sequences with no red balls is 8^3 = 512. Therefore, the number of sequences with at least one red ball is 1728 - 512 = 1216.
In summary:
(a) 1728 sequences
(b) 60 sequences
(c) 30 sequences
(d) 48 sequences
(e) 10 sequences
(f) 3 sequences
(g) 1216 sequences
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Donna puso $ 450 en un 6-certificado de depósito mensual que gana 4.6% de interés anual simple. ¿Cuánto interés ganó el certificado me ayudas plis
El certificado de depósito ganó un interés de aproximadamente $1.72. Cabe mencionar que este cálculo se basa en la suposición de que el certificado de depósito no tiene ninguna penalización o retención de impuestos.
Para calcular el interés ganado en el certificado de depósito, necesitamos utilizar la fórmula del interés simple: Interés = (Principal × Tasa de interés × Tiempo).
En este caso, el principal es de $450 y la tasa de interés es del 4.6% anual. Sin embargo, debemos convertir la tasa de interés a una tasa mensual, ya que el certificado de depósito es mensual.
Para convertir la tasa anual a una tasa mensual, dividimos la tasa anual entre 12: 4.6% / 12 = 0.3833% (aproximadamente). Ahora tenemos la tasa mensual: 0.3833%.
El tiempo es de un mes, por lo que sustituimos los valores en la fórmula del interés simple: Interés = ($450 × 0.3833% × 1 mes).
Calculando el interés: Interés = ($450 × 0.003833 × 1) = $1.72 (aproximadamente).
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Evaluate the surface integral of the function g(x,y,z) over the surface s, where s is the surface of the rectangular prism formed from the coordinate planes and the planes x=2 y=2 z=3
The surface integral of the function g(x, y, z) over the surface S is evaluated.
To evaluate the surface integral, we consider the rectangular prism formed by the coordinate planes and the planes x = 2, y = 2, z = 3. This prism encloses a six-sided surface S. The surface integral of a function over a surface measures the flux or flow of the function across the surface.
In this case, we are integrating the function g(x, y, z) over the surface S. The specific form of the function g(x, y, z) is not provided in the given question. To evaluate the surface integral, we need to know the expression of g(x, y, z).
Once we have the expression for g(x, y, z), we can set up the integral by parameterizing the surface S and calculating the dot product of the function g(x, y, z) and the surface normal vector. The integral will involve integrating over the appropriate range of the parameters that define the surface.
Without the specific expression for g(x, y, z) or further details, it is not possible to provide the exact numerical evaluation of the surface integral. However, the general procedure for evaluating a surface integral involves parameterizing the surface, setting up the integral, and then performing the necessary calculations.
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PLS ANSWER QUICKLY ASAP
There is screenshot I need help
uwu
Answer:
What are you trying to find???
Step-by-step explanation:
If it is median, then it is the line in the middle of the box, which is on 19.
Identify the shape of the traffic sign and classify it as regular or irregular.
caution or warning
The traffic sign described as "caution" or "warning" is typically in the shape of an equilateral triangle. It is an irregular shape due to its three unequal sides and angles.
The caution or warning signs used in traffic control generally have a distinct shape to ensure easy recognition and convey a specific message to drivers.
These signs are typically in the shape of an equilateral triangle, which means all three sides and angles are equal. This shape is chosen for its visibility and ability to draw attention to the potential hazard or caution ahead.
Unlike regular polygons, such as squares or circles, which have equal sides and angles, the equilateral triangle shape of caution or warning signs is irregular.
Irregular shapes do not possess symmetry or uniformity in their sides or angles. The three sides of the triangle are not of equal length, and the three angles are not equal as well.
Therefore, the caution or warning traffic sign is an irregular shape due to its distinctive equilateral triangle form, which helps alert drivers to exercise caution and be aware of potential hazards ahead.
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Solución de este problema matemático
The value of x, considering the similar triangles in this problem, is given as follows:
x = 2.652.
El valor de x es el seguinte:
x = 2.652.
What are similar triangles?Two triangles are defined as similar triangles when they share these two features listed as follows:
Congruent angle measures, as both triangles have the same angle measures.Proportional side lengths, which helps us find the missing side lengths.The proportional relationship for the side lengths in this triangle is given as follows:
x/3.9 = 3.4/5
Applying cross multiplication, the value of x is obtained as follows:
5x = 3.9 x 3.4
x = 3.9 x 3.4/5
x = 2.652.
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Do not use EXCEL One of the fast food restaurants near my neighbourhood claims that the average delivery time of its service is less than 6 minutes. Using a random sample of 12 delivery times with a sample mean of 5.69 minutes and 1.58 minutes sample standard deviation, determine if there is sufficient evidence to support this restaurant's claim of the delivery time at the 5% level of significance. (i) Formulate the hypothesis (2 Points) (ii) State your conclusion using the critical value approach with a distribution graph (4 Points) (iii) State your conclusion using the p-value approach a distribution graph
By following the critical value approach and the p-value approach, we have examined the hypothesis and reached conclusions based on the test statistic and the significance level.
(i) Formulate the hypothesis:
The hypothesis testing can be done by following the given steps:
Step 1: State the hypothesis
Step 2: Set the criteria for the decision
Step 3: Calculate the test statistic and probability of the test statistic
Step 4: Make the decision in light of steps 2 and 3
The null hypothesis H0: μ ≥ 6
The alternative hypothesis H1: μ < 6
Where μ = Population Mean
(ii) State your conclusion using the critical value approach with a distribution graph:
The critical value is determined by:
α/2 = 0.05/2 = 0.025
Degrees of freedom = n - 1 = 12 - 1 = 11
Level of significance = α = 0.05
Critical value = -t0.025, 11 = -2.201
The test statistic, t = (x - μ) / (s / √n)
Where,
x = Sample Mean = 5.69
μ = Population Mean = 6
s = Sample Standard Deviation = 1.58
n = Sample size = 12
t = (5.69 - 6) / (1.58 / √12) = -1.64
The rejection region is (-∞, -2.201)
The test statistic is outside of the rejection region, thus we reject the null hypothesis. Hence, there is sufficient evidence to support the claim that the delivery time is less than 6 minutes.
(iii) State your conclusion using the p-value approach and a distribution graph:
The p-value is given as P(t < -1.64) = 0.0642
The p-value is greater than α, thus we accept the null hypothesis. Therefore, we cannot support the restaurant's claim that the average delivery time of its service is less than 6 minutes.
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What is the distance a car will travel in 12 minutes of it is going 50mph ?
If a car is traveling at a constant rate of 50 miles per hour, we can determine how far it will travel in 12 minutes. We know that 1 hour is equivalent to 60 minutes. Therefore, 50 miles per hour is the same as 50/60 miles per minute, or 5/6 miles per minute.
To find the distance traveled in 12 minutes, we can multiply the speed by the time:distance = speed × time
= (5/6) miles/minute × 12 minutes
= 10 milesSo, a car traveling at a constant rate of 50 miles per hour will travel a distance of 10 miles in 12 minutes.
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Solve each equation by completing the square.
x²+3 x=-25
The solution to the equation x² + 3x = -25 by completing the square is:
x = -3/2 ± √(-91)/2, where √(-91) represents the square root of -91.
To solve the equation x² + 3x = -25 by completing the square, we follow these steps:
Step 1: Move the constant term to the other side of the equation:
x² + 3x + 25 = 0
Step 2: Take half of the coefficient of x, square it, and add it to both sides of the equation:
x² + 3x + (3/2)² = -25 + (3/2)²
x² + 3x + 9/4 = -25 + 9/4
Step 3: Simplify the equation:
x² + 3x + 9/4 = -100/4 + 9/4
x² + 3x + 9/4 = -91/4
Step 4: Rewrite the left side of the equation as a perfect square:
(x + 3/2)² = -91/4
Step 5: Take the square root of both sides of the equation:
x + 3/2 = ±√(-91)/2
Step 6: Solve for x:
x = -3/2 ± √(-91)/2
The solution to the equation x² + 3x = -25 by completing the square is:
x = -3/2 ± √(-91)/2, where √(-91) represents the square root of -91.
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(30%) Using the method of Least Squares, determine to 3-decimal place the necessary values of the coefficient (A and B) in the equation y = A e-Bx from the given data points 77 2.4 X y 100 185 3.4 7.0 239 11.1 285 19.6
The values of the coefficients A and B in the equation y = A e^(-Bx) are A ≈ 289.693 and B ≈ 0.271.
To determine the values of the coefficients A and B in the equation y = A * e^(-Bx) using the method of least squares, we need to minimize the sum of the squared residuals between the predicted values and the actual data points.
Let's denote the given data points as (x_i, y_i), where x_i represents the x-coordinate and y_i represents the corresponding y-coordinate.
Given data points:
(77, 2.4)
(100, 3.4)
(185, 7.0)
(239, 11.1)
(285, 19.6)
To apply the least squares method, we need to transform the equation into a linear form. Taking the natural logarithm of both sides gives us:
ln(y) = ln(A) - Bx
Let's denote ln(y) as Y and ln(A) as C, which gives us:
Y = C - Bx
Now, we can rewrite the equation in a linear form as Y = C + (-Bx).
We can apply the least squares method to find the values of B and C that minimize the sum of the squared residuals.
Using the linear equation Y = C - Bx, we can calculate the values of Y for each data point by taking the natural logarithm of the corresponding y-coordinate:
[tex]Y_1[/tex] = ln(2.4)
[tex]Y_2[/tex] = ln(3.4)
[tex]Y_3[/tex] = ln(7.0)
[tex]Y_4[/tex] = ln(11.1)
[tex]Y_5[/tex] = ln(19.6)
We can also calculate the values of -x for each data point:
-[tex]x_1[/tex] = -77
-[tex]x_2[/tex] = -100
-[tex]x_3[/tex] = -185
-[tex]x_4[/tex] = -239
-[tex]x_5[/tex] = -285
Now, we have a set of linear equations in the form Y = C + (-Bx) that we can solve using the least squares method.
The least squares equations can be written as follows:
ΣY = nC + BΣx
Σ(xY) = CΣx + BΣ(x²)
where Σ represents the sum over all data points and n is the total number of data points.
Substituting the calculated values, we have:
ΣY = ln(2.4) + ln(3.4) + ln(7.0) + ln(11.1) + ln(19.6)
Σ(xY) = (-77)(ln(2.4)) + (-100)(ln(3.4)) + (-185)(ln(7.0)) + (-239)(ln(11.1)) + (-285)(ln(19.6))
Σx = -77 - 100 - 185 - 239 - 285
Σ(x^2) = 77² + 100² + 185² + 239² + 285²
Solving these equations will give us the values of C and B. Once we have C, we can determine A by exponentiating C (A = [tex]e^C[/tex]).
After obtaining the values of A and B, round them to 3 decimal places as specified.
By applying the method of Least Squares to the given data points, the calculated values are A ≈ 289.693 and B ≈ 0.271, rounded to 3 decimal places.
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Find the work required to pitch a 6. 6 oz softball at 90 ft/sec. GOODS The work required to pitch a 6. 6 oz softball at 90 ft/sec is ft-lb. (Do not round until the final answer. Then round to the neares
The work required to pitch a 6.6 oz softball at 90 ft/sec is approximately 37.125 ft-lb.
To find the work required to pitch a softball, we can use the formula:
Work = Force * Distance
In this case, we need to calculate the force and the distance.
Force:
The force required to pitch the softball can be calculated using Newton's second law, which states that force is equal to mass times acceleration:
Force = Mass * Acceleration
The mass of the softball is given as 6.6 oz. We need to convert it to pounds for consistency. Since 1 pound is equal to 16 ounces, the mass of the softball in pounds is:
6.6 oz * (1 lb / 16 oz) = 0.4125 lb (rounded to four decimal places)
Acceleration:
The acceleration is given as 90 ft/sec.
Distance:
The distance is also given as 90 ft.
Now we can calculate the work:
Work = Force * Distance
= (0.4125 lb) * (90 ft)
= 37.125 lb-ft (rounded to three decimal places)
Therefore, the work required to pitch a 6.6 oz softball at 90 ft/sec is approximately 37.125 ft-lb.
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Given u = <3, -4>, v = <-1, 2> and w = <-2, -5>. Find: u+v+W (i) (ii) || u + v + w|| the vector unit in the direction of u + v + w Determine the area of the triangle PQR with vertices P(1,2,3), Q(2,3,1) and R(3,1,2) Given that Z=-4-j7 (1) (ii) (iii) (iv) AQB10102 Draw the projection of the complex number on the Argand Diagram Find the modulus, and argument, 0 Express Z in trigonometric form, polar form and exponential form Determine the cube roots of Z ENGINEERING MATHEMATICS 1 Page 7 of 9
For vectors u = <3, -4>, v = <-1, 2>, and w = <-2, -5>:
(i) u + v + w = <3, -4> + <-1, 2> + <-2, -5>
= <3-1-2, -4+2-5>
= <0, -7>
(ii) ||u + v + w|| = ||<0, -7>||
= sqrt(0^2 + (-7)^2)
= sqrt(0 + 49)
= sqrt(49)
= 7
The magnitude of u + v + w is 7.
To find the unit vector in the direction of u + v + w, we divide the vector by its magnitude:
Unit vector = (u + v + w) / ||u + v + w||
= <0, -7> / 7
= <0, -1>
The unit vector in the direction of u + v + w is <0, -1>.
For the triangle PQR with vertices P(1, 2, 3), Q(2, 3, 1), and R(3, 1, 2):
To find the area of the triangle, we can use the formula for the magnitude of the cross product of two vectors:
Area = 1/2 * || PQ x PR ||
Let's calculate the cross product:
PQ = Q - P = <2-1, 3-2, 1-3> = <1, 1, -2>
PR = R - P = <3-1, 1-2, 2-3> = <2, -1, -1>
PQ x PR = <(1*(-1) - 1*(-1)), (1*(-1) - (-2)2), (1(-1) - (-2)*(-1))>
= <-2, -3, -1>
|| PQ x PR || = sqrt((-2)^2 + (-3)^2 + (-1)^2)
= sqrt(4 + 9 + 1)
= sqrt(14)
Area = 1/2 * sqrt(14)
For the complex number Z = -4-j7:
(i) To draw the projection of the complex number on the Argand Diagram, we plot the point (-4, -7) in the complex plane.
(ii) To find the modulus (absolute value) of Z, we use the formula:
|Z| = sqrt(Re(Z)^2 + Im(Z)^2)
= sqrt((-4)^2 + (-7)^2)
= sqrt(16 + 49)
= sqrt(65)
(iii) To find the argument (angle) of Z, we use the formula:
arg(Z) = atan(Im(Z) / Re(Z))
= atan((-7) / (-4))
= atan(7/4)
(iv) To express Z in trigonometric (polar) form, we write:
Z = |Z| * (cos(arg(Z)) + isin(arg(Z)))
= sqrt(65) * (cos(atan(7/4)) + isin(atan(7/4)))
To express Z in exponential form, we use Euler's formula:
Z = |Z| * exp(i * arg(Z))
= sqrt(65) * exp(i * atan(7/4))
To determine the cube roots of Z, we can use De Moivre's theorem:
Let's find the cube roots of Z:
Cube root 1 = sqrt(65)^(1/3) * [cos(atan(7/4)/3) + isin(atan(7/4)/3)]
Cube root 2 = sqrt(65)^(1/3) * [cos(atan(7/4)/3 + 2π/3) + isin(atan(7/4)/3 + 2π/3)]
Cube root 3 = sqrt(65)^(1/3) * [cos(atan(7/4)/3 + 4π/3) + i*sin(atan(7/4)/3 + 4π/3)]
These are the three cube roots of Z.
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You are planning a trip to Europe. you would like to visit 20 country, but you only have time yo visit 9 of them in how many ways can you choose which country you will visit
There are 167,960 ways to choose which countries to visit from a total of 20 countries when you can only visit 9 of them.
To calculate the number of ways you can choose which countries to visit from a total of 20 countries when you have time to visit only 9 of them, we can use the concept of combinations.
The number of ways to choose a subset of k elements from a set of n elements is given by the binomial coefficient, also known as "n choose k," denoted as C(n, k). The formula for C(n, k) is:
C(n, k) = n! / (k! * (n - k)!)
In this case, you want to choose 9 countries out of 20, so the number of ways to do this is:
C(20, 9) = 20! / (9! * (20 - 9)!)
Calculating the above expression:
C(20, 9) = (20 * 19 * 18 * 17 * 16 * 15 * 14 * 13 * 12) / (9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)
Simplifying the calculation:
C(20, 9) = 167,960
Therefore, there are 167,960 ways to choose which countries to visit from a total of 20 countries when you have time to visit only 9 of them.
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The indicate function y1(x) is a solution of the given differential equation. Use reduction of order or formula
y2=y1(x)∫ e−∫P(x)dx/ y2(x)dx a
s Instructed, to find a second solution y2(x). x2y′′−xy4+17y=0; y1=xsin(4ln(x))
y1=___
y1 = x * sin(4ln(x))
The second solution y2(x) of the given differential equation, we can use the reduction of order method. Let's denote y2(x) as the second solution.
The reduction of order technique states that if we have one solution y1(x) of a linear homogeneous second-order differential equation, then we can find the second solution y2(x) by the following formula:
y2(x) = y1(x) * ∫[e^(-∫P(x)dx) / y1(x)^2] dx
Where P(x) is the coefficient of the first derivative term.
In the given differential equation:
x^2y'' - xy^4 + 17y = 0
We have y1(x) = x * sin(4ln(x)), so we need to find y2(x) using the formula mentioned above.
First, we need to find P(x):
P(x) = -1/x
Next, we substitute y1(x) and P(x) into the formula to find y2(x):
y2(x) = x * sin(4ln(x)) * ∫[e^(-∫(-1/x)dx) / (x * sin(4ln(x)))^2] dx
y2(x) = x * sin(4ln(x)) * ∫[e^(ln(x)) / (x * sin(4ln(x)))^2] dx
y2(x) = x * sin(4ln(x)) * ∫[x / (x^2 * sin^2(4ln(x)))] dx
To simplify this integral, we can cancel out one factor of x from the numerator and denominator:
y2(x) = sin(4ln(x)) * ∫[1 / (x * sin^2(4ln(x)))] dx
This integral is not straightforward to solve, so the resulting expression for y2(x) will be complicated.
Therefore, the second solution y2(x) using the reduction of order method is given by y2(x) = sin(4ln(x)) * ∫[1 / (x * sin^2(4ln(x)))] dx.
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Find an equation of the line that passes through the point (5,−3) and is perpendicular to the line that passes through the points (−1,1) and (−2,2).
The equation of the line passing through the point (5,-3) and perpendicular to the line passing through the points (-1,1) and (-2,2) is y = x - 8.
To find the equation of the line passing through the point (5,-3) and perpendicular to the line passing through the points (-1,1) and (-2,2), we follow these steps:
Step 1: Find the slope of the line passing through (-1,1) and (-2,2).
Using the slope formula, we have:
m = (y2 - y1) / (x2 - x1),
where (x1, y1) = (-1, 1) and (x2, y2) = (-2, 2).
Plugging in the values, we get:
m = (2 - 1) / (-2 - (-1)) = -1.
Step 2: Find the slope of the line perpendicular to the line passing through (-1,1) and (-2,2).
Perpendicular lines have negative reciprocal slopes. Therefore, the slope of the line perpendicular to the line passing through (-1,1) and (-2,2) is the negative reciprocal of -1.
i.e. m' = -1/m' = -1/-1 = 1.
Step 3: Find the equation of the line passing through (5,-3) with slope 1.
We have the slope (m') of the line passing through (5,-3), and we also have a point (5,-3) on the line. We can use the point-slope form of the equation of a line to find the equation of the line passing through (5,-3) and perpendicular to the line passing through (-1,1) and (-2,2).
Point-slope form: y - y1 = m'(x - x1),
where (x1, y1) = (5,-3) and m' = 1.
Plugging in the values, we get:
y - (-3) = 1(x - 5),
y + 3 = x - 5,
y = x - 5 - 3,
y = x - 8.
Thus,y = x - 8 is the equation of the line travelling through the point (5,-3) and perpendicular to the line going through the points (-1,1) and (-2,2).
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1. Transform each of the following functions using Table of the Laplace transform (i). (ii). t²t³ cos 7t est 2. (a) Find Fourier Series representation of the function with period 27 defined by f(t)= sin (t/2). (b) Find the Fourier Series for the function as following -1 -3
(i) The Laplace transform of t² is (2/s³), the Laplace transform of t³ is (6/s⁴), the Laplace transform of cos(7t) is (s/(s²+49)), and the Laplace transform of [tex]e^(^s^t^)[/tex] is (1/(s-[tex]e^(^-^s^t^)[/tex])))). Therefore, the transformed function is (2/s³) + (6/s⁴) * (s/(s²+49)) + (1/(s-[tex]e^(^-^s^t^)[/tex])).
(ii) The Fourier series representation of the function f(t) = sin(t/2) with period 27 is given by f(t) = (4/π) * (sin(t/2) + (1/3)sin(3t/2) + (1/5)sin(5t/2) + ...).
In the first step, we are asked to transform each of the given functions using the Table of the Laplace transform. For function (i), we have to find the Laplace transforms of t² , t³, cos(7t), and [tex]e^(^s^t^)[/tex]. Using the standard formulas from the Laplace transform table, we can find their respective transforms. The transformed function is the sum of these individual transforms.
For t² its (2/s³),
For t³ its (6/s⁴),
For cos(7t) its (s/(s²+49)),
For [tex]e^(^s^t^)[/tex] its (1/(s-[tex]e^(^-^s^t^)[/tex])))).
the transformed function is (2/s³) + (6/s⁴) * (s/(s²+49)) + (1/(s-[tex]e^(^-^s^t^)[/tex])).
In the second step, we are asked to find the Fourier series representation of the function f(t) = sin(t/2) with a period of 27. The Fourier series representation of a function involves expressing it as a sum of sine and cosine functions with different frequencies and amplitudes.
For the given function, the Fourier series representation can be obtained by using the formula for a periodic function with a period of 27. The formula allows us to find the coefficients of the sine terms, which are then multiplied by the respective sine functions with different frequencies to obtain the final representation.
The function f(t) = sin(t/2) with a period of 27 can be represented by its Fourier series as f(t) = (4/π) * (sin(t/2) + (1/3)sin(3t/2) + (1/5)sin(5t/2) + ...).
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Find a basis B for the domain of T such that the matrix T relative to B is
diagonal.
a. T: R3 ⟶ R3; T(x, y, z) = (−2x + 2y − 3z, 2x + y − 6z, −x − 2y)
b. T: P1 ⟶ P1; T(a + bx) = a + (a + 2b)x
The basis B for the domain of T such that the matrix T relative to B is diagonal is:
a. B = {(2, 1, -2)}
b. B = {1, x}
To find a basis for the domain of T such that the matrix T relative to that basis is diagonal, we need to find a set of linearly independent vectors that span the domain of T.
a. For T: R3 ⟶ R3; T(x, y, z) = (−2x + 2y − 3z, 2x + y − 6z, −x − 2y):
To find the basis for the domain of T, we need to solve the homogeneous equation T(x, y, z) = (0, 0, 0). This will give us the kernel (null space) of T, which represents the vectors that get mapped to the zero vector.
Setting each component of T equal to zero, we have:
-2x + 2y - 3z = 0
2x + y - 6z = 0
-x - 2y = 0
Solving this system of equations, we obtain:
x = 2y
z = -2y
Taking y = 1, we get:
x = 2(1) = 2
z = -2(1) = -2
Thus, the kernel of T consists of the vector (2, 1, -2).
Since the kernel of T consists of only one vector, this vector forms a basis for the domain of T. Therefore, the basis B for the domain of T such that the matrix T relative to B is diagonal is B = {(2, 1, -2)}.
b. For T: P1 ⟶ P1; T(a + bx) = a + (a + 2b)x:
The domain of T is the set of polynomials of degree 1 or less. To find a basis for this domain such that the matrix T relative to that basis is diagonal, we can choose the standard basis {1, x} for P1.
The matrix T relative to this basis is:
|1 1 |
|0 2 |
The matrix is already diagonal, so the standard basis {1, x} forms a basis for the domain of T such that the matrix T relative to B is diagonal.
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Consider the following deffinitions for sets of charactets: - Dights ={0,1,2,3,4,5,6,7,8,9} - Special characters ={4,8,8. #\} Compute the number of pakswords that sat isfy the given constraints. (i) Strings of length 7 . Characters can be special claracters, digits, or letters, with no repeated charscters. (ii) Strings of length 6. Characters can be special claracters, digits, or letterss, with no repeated claracters. The first character ean not be a special character.
For strings of length 7 with no repeated characters, there are 1,814,400 possible passwords. For strings of length 6 with no repeated characters and the first character not being a special character, there are 30,240 possible passwords.
To compute the number of passwords that satisfy the given constraints, let's analyze each case separately:
(i) Strings of length 7 with no repeated characters:
In this case, the first character can be any character except a special character. The remaining six characters can be chosen from the set of digits, special characters, or letters, with no repetition.
1. First character: Any character except a special character, so there are 10 choices.
2. Remaining characters: 10 choices for the first position, 9 choices for the second position, 8 choices for the third position, and so on until 5 choices for the sixth position.
Therefore, the total number of passwords that satisfy the constraints for strings of length 7 is:
10 * 10 * 9 * 8 * 7 * 6 * 5 = 1,814,400 passwords.
(ii) Strings of length 6 with no repeated characters and the first character not being a special character:
In this case, the first character cannot be a special character, so there are 10 choices for the first character (digits or letters). The remaining five characters can be chosen from the set of digits, special characters, or letters, with no repetition.
1. First character: Any digit (0-9) or letter (a-z, A-Z), so there are 10 choices.
2. Remaining characters: 10 choices for the second position, 9 choices for the third position, 8 choices for the fourth position, and so on until 6 choices for the sixth position.
Therefore, the total number of passwords that satisfy the constraints for strings of length 6 is:
10 * 10 * 9 * 8 * 7 * 6 = 30,240 passwords.
Note: It seems there's a typo in the "Special characters" set definition. The third character, "8. #\", appears to be a combination of characters rather than a single character.
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Raja's is 200cm tall. His friend Anjum is 250cm
tall. what is the ratio of their heights in it's
Simplest from form.
Answer:
26ocm
Step-by-step explanation:
you do 2 plus 4 plus 5.
A circle has a diameter with endpoints at A (-1. -9) and B (-11, 5). The point M (-6, -2) lies on the diameter. Prove or disprove that point M is the center of the circle by answering the following questions. Round answers to the nearest tenth (one decimal place). What is the distance from A to M? What is the distance from B to M? Is M the center of the circle? Yes or no?
Answer:
AM: 8.6 units
BM: 8.6 units
M is the center
Step-by-step explanation:
Pre-SolvingWe are given that the diameter of a circle is AB, where point A is at (-1, -9) and point B is (-11, 5).
We know that point M, which is at (-6, -2) is on AB. We want to know if it is the center of the circle.
If it is the center, then it means that the distance (measure) of AM is the same as the distance (measure) of BM.
Recall that the distance formula is [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex], where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are points.
SolvingLength of AMThe endpoints are point A and point M. We can label the values of the points to get:
[tex]x_1=-1\\y_1=-9\\x_2=-6\\y_2=-2[/tex]
Now, plug them into the formula.
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(-6--1)^2+(-2--9)^2}[/tex]
[tex]d=\sqrt{(-6+1)^2+(-2+9)^2}[/tex]
[tex]d=\sqrt{(-5)^2+(7)^2}[/tex]
[tex]d=\sqrt{25+49}[/tex]
[tex]d=\sqrt{74}[/tex] ≈ 8.6 units
Length of BMThe endpoints are point B and point M. We can label the values and get:
[tex]x_1=-11\\y_1=5\\x_2=-6\\y_2=-2[/tex]
Now, plug them into the formula.
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(-6--11)^2+(-2-5)^2}[/tex]
[tex]d=\sqrt{(-6+11)^2+(-2-5)^2}[/tex]
[tex]d=\sqrt{(5)^2+(-7)^2}[/tex]
[tex]d=\sqrt{25+49}[/tex]
[tex]d=\sqrt{74}[/tex] ≈ 8.6 units.
Since the length of AM an BM are the same, M is the center of the circle.
Which scenario is modeled in the diagram below?
you may first send the diagram
Consider the following regression on 110 college students: Estimated (Studenth) = 19.6 +0.73 (Midparh), R² = 0.45, SER= 2.0 Standard errors are as hereunder: SE(intercept) = (7.2) SE(Midparh) = (0.10) (Values in parentheses are heteroskedasticity-robust standard errors). where "Studenth" is the height of students in inches, and "Midparh" is the average of the parental heights. (a) Using a t-test approach and 5% level of significance, test if slope coefficient can be positive. Make sure you write both hypothesis claims properly. (b) If children, on average, were expected to be of the same height as their parents, then this would imply that the coefficient of intercept becomes zero and the coefficient of slope will be 1: (i) Test if the coefficient of intercept is zero at 1% level of significance. (ii) Test if the slope coefficient is 1 at 5% level of significance. (Note: the statistical table is attached hereto) (c) Repeat part (B)-(i) using the p-value approach. (d) Repeat part (B)-(ii) using the p-value approach.
(a) The slope coefficient can be positive.
(b) the slope coefficient is not equal to 1.
(c) the coefficient of intercept is not zero.
(d) The slope coefficient is not equal to 1.
(a) Testing of Slope Coefficient for Positivity:
Hypothesis:
H0: β1 ≤ 0 (null hypothesis)
H1: β1 > 0 (alternative hypothesis)
Using the t-test approach:
t = β1 / SE(β1), where β1 is the slope coefficient and SE(β1) is the standard error of the slope coefficient.
Calculating the t-value:
t = 0.73 / 0.10 = 7.30
With 108 degrees of freedom (n-k-1 = 110-2-1=107), at a 5% significance level, the critical value is 1.66.
Since the calculated value of t (7.30) is greater than the critical value (1.66), we can reject the null hypothesis.
Therefore, the slope coefficient can be positive.
(b) Testing Coefficient of Intercept and Slope:
Testing the Coefficient of Intercept at 1% significance level:
Hypothesis:
H0: β0 = 0 (null hypothesis)
H1: β0 ≠ 0 (alternative hypothesis)
Using the t-test approach:
t = β0 / SE(β0) = 19.6 / 7.2 = 2.72
At a 1% significance level, the critical value is 2.61.
Since the calculated value of t (2.72) is greater than the critical value (2.61), we can reject the null hypothesis.
Therefore, the coefficient of intercept is not zero.
Testing the Slope Coefficient at 5% significance level:
Hypothesis:
H0: β1 = 1 (null hypothesis)
H1: β1 ≠ 1 (alternative hypothesis)
Using the t-test approach:
t = (β1 - 1) / SE(β1) = (0.73 - 1) / 0.10 = -2.7
At a 5% significance level, the critical value is 1.98.
Since the calculated value of t (-2.7) is less than the critical value (1.98), we fail to reject the null hypothesis.
Therefore, the slope coefficient is not equal to 1.
(c) Testing Coefficient of Intercept by p-value approach:
The p-value is the probability of obtaining results as extreme or more extreme than the observed results in the sample data, assuming that the null hypothesis is true.
If the p-value ≤ α (level of significance), then we reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.
For the coefficient of intercept:
P-value = P(t ≥ t0) = P(t ≥ 2.72) = 0.004
At a 1% significance level, the p-value is less than 0.01. Therefore, we reject the null hypothesis.
Therefore, the coefficient of intercept is not zero.
(d) Testing Slope Coefficient by p-value approach:
For the slope coefficient:
P-value = P(t ≥ t0) = P(t ≥ -2.7) = 0.007
At a 5% significance level, the p-value is less than 0.05. Therefore, we reject the null hypothesis.
Therefore, The slope coefficient is not one.
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In a class test containing 20 questions, 5 marks are awarded for each correct
answer and 2 marks is deducted for each wrong answer. If Riya get 15 correct
answers out of all the questions attempted. What is her total score?
Answer:
Her total score is 65.
Step-by-step explanation:
Out of 20 questions, Rita get 15 correct answer.
Riya get = 20-15=5 wrong answers.
according to the question,
5 marks awarded for each correct answer and 2 marks deducted for each wrong answer.
so, her total score = (15 * 5 = 75) - (5 * 2 =10)
= 75 - 10 =65
: therefore, her total score is 65.
Answer:
Riya's total score is 65/100
Step-by-step explanation:
You can calculate the total score for a class test by using the following formula:
(Let t = total score)
t = (number of correct answers × marks per correct answer) - (number of wrong answers × marks per wrong answer)In our case, if Riya got 15 correct answers out of 20 questions, then she got 5 wrong answers (20 - 15 = 5).
If each question is worth 5 marks for a correct answer and 2 marks for a wrong answer, we can plug in the numbers into the formula:
t = (15 x 5) - (5 x 2) =?Solving what is inside of the parenthesis gives us:
75 - 10 = 65Therefore, Riya’s total score is 65 out of a possible 100.
Helppp pleaseeeeeeeeeee
Answer :
Here trigonometric ratio will be used.
As we can see the figure where 5 is the perpendicular and we have to calculate the value of x.
x is Hypotenuse
Using trigonometric ratio:
[tex] \sf \: \dfrac{P}{H} = \sin \theta[/tex]
Where P is perpendicular and H is Hypotenuse.
Since hypotenuse is x and the value of perpendicular is 5. Therefore by substituting the values of Perpendicular and Hypotenuse in the above trigonometric ratio we will get required value of x.
Also, The value of [tex]\theta[/tex] will be 45°
[tex] \sf\dfrac{5}{x} = \sin 45\degree [/tex]
[tex] \sf\dfrac{5}{x} = \dfrac{1}{ \sqrt{2} } \: \: \: \: \: \: \: \: \: \: \: \bigg( \because \sin45 \degree = \dfrac{1}{ \sqrt{2} } \bigg)[/tex]
Further solving by cross multiplication,
[tex] \sf x = 5 \sqrt{2} [/tex]
So the value of x is [tex] \sf 5 \sqrt{2} [/tex]