(2x^3-4x^2+7x-3)/(2x^2 +5)
Divide using long division

Answer:

he is 36 months old or 3 years old, and he ways 82 kilograms.

Step-by-step explanation:

quick mafs

The point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.

In a graph, the line which is horizontal is known as the x-axis of the graph. The vertical line in the graph is called the y-axis of it. These axis helps to read the data from graph in following way-

In the given graph, the x-axis is labeled with age in months and y-axis is labeled with weight of panda.

The point with coordinates (36,82) tells that the age of panda is 36 months and the weight of the panda is 82 kilograms.

Hence, the point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.

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Answer:

2=3^2?????

Step-by-step explanation:

y=x^2

(3,2)

substitute

2=3^2

Answer:

hi

Step-by-step explanation:

First of all let’s find out the slope of the line y = x +10

As, we know the equation y= mx + c . So comparing the given equation with the general equation we get, m = 1

Now, we know that the product of two perpendicular lines is -1.

Thus, mn = -1 (considering slope of the second line as n)

Putting the value of m we get , n = -1

Now , y+5= -1( x -15) i.e y=-x + 10

if we compare again with the general equation then we find that.

The y intercept of the required equation is 10.

Thank You

Answer:

10

Step-by-step explanation:

First of all let’s find out the slope of the line y = x +10

As, we know the equation y= mx + c . So comparing the given equation with the general equation we get, m = 1

Now, we know that the product of two perpendicular lines is -1.

Thus, mn = -1 (considering slope of the second line as n)

Putting the value of m we get , n = -1

Now , y+5= -1( x -15) i.e y=-x + 10

if we compare again with the general equation then we find that.

The y intercept of the required equation is 10.

Thank You

Answer:

D

Step-by-step explanation:

It must first translate 1 unit to the left because quadrilateral F'G'H'I is one unit away from to y axis. It can then translate across the y-axis.

Answer:

ITS B!

Step-by-step explanation:

Ape x!

Answer:

48

Step-by-step explanation:

round off 3.8 to 4 and 11.9 to 12 and multiply the values

Answer:

?

Step-by-step explanation:

don't get your question

Answer:

Step-by-step explanation:

The proportion between the first two and the second two numbers are:

Simplifying the second fraction:

Comparing the fractions:

The answer is no

Answer:

Cddd

Step-by-step explanation:

Answer:

0.3

Step-by-step explanation:

Answer:

3/10

Step-by-step explanation:

1. find the lowest common denominator which is 10.

2. for 4/5 you have to multiply 5 by 2 in order to get 10, so you multiply the numerator by 2 as well which gives you 8/10.

3. for 1/2 you have to multiply 2 by 5 in order to get 10, so you multiply the numerator by 5 also which gives you 5/10

4. you work out the difference between both numerators which is 3 and keep the denominator the same

Answer:

<B = 56.25°

Step-by-step explanation:

Reference angle = B

Hypotenuse = AB = 9

Adjacent = BC = 5

Applying trigonometric ratio:

[tex] cos (B) = \frac{adj}{hyp} [/tex]

[tex] cos (B) = \frac{5}{9} [/tex]

[tex] B = cos^{-1}(\frac{5}{9}) [/tex]

B = 56.25° (nearest hundredth)

Answer:

[tex]x=\sqrt{14}[/tex]

Step-by-step explanation:

This triangle is a 45-45-90 triangle.

By using the image I posted, we can find x easily.

So, we have [tex]\sqrt{7}[/tex] as one of the sides.

They hypotenuse, which is x is just [tex]\sqrt{7} \sqrt{2}[/tex]

Simplify and we get x = [tex]\sqrt{14}[/tex]

Answer:

Step-by-step explanation:

First: work out the difference (decrease) between the two numbers you are comparing.

Decrease = Original Number - New Number

Then: divide the decrease by the original number and multiply the answer by 100.

% Decrease = Decrease ÷ Original Number × 100

If your answer is a negative number, then this is a percentage increase

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]Plot: \{24, 26, 28, 30, 32, 34\}[/tex]

Required

Determine the percentage of those who uses the bus for 27 to 30 mins

The box plot is not given. So, I will make assumptions in order to solve this question.

Assume the following readings from the box plot:

[tex]Total\ Buses= 60[/tex]

[tex]27-30\ Minutes = 20\ buses[/tex]

Using these assumptions, the required percentage is:

Total = 6

27 to 30 minutes = 2

[tex]Percent = \frac{27\ to\ 30\ mins}{Total} * 100\%[/tex]

[tex]Percent = \frac{20}{60} * 100\%[/tex]

[tex]Percent = \frac{2000}{60} * \%[/tex]

[tex]Percent = 33.33 * \%[/tex]

Answer:

50%

Step-by-step explanation:

I took the test!

Answer:

a) the probability of (2 < X < 6) is 0.6247

b) the value of c is 3.878

c) the value of E[ x² ] is 13

Step-by-step explanation:

Given that;

mean μ = 3

variance = 4

standard deviation s = √variance  = √4 = 2

(a) Find the probability P(2 < X < 6)

P(2 < X < 6) = p( (x - μ / s ) < z <  (x - μ / s ) )

= p( (2 - 3 / 2 ) < z < (6 - 3 / 2 ) )

= p( -0.5  < z <  1.5)

from z-score table, 1.5; z = 0.9332 and -0.5; z = 0.3085

so

P(2 < X < 6)  = 0.9332 - 0.3085 = 0.6247

Therefore, the probability of (2 < X < 6) is 0.6247

b) Find the value c such that P(X > c) = 0.33

with p-value = 0.33, the corresponding z -score to the right is 0.439

we know that;

z = x - μ / s

we substitute

0.439 = x - 3 / 2

x - 3 = 2 × 0.439

x - 3 = 0.878

x = 0.878 + 3

x = 3.878

Therefore, the value of c is 3.878

c) Find E[ x² ].

Variance = E[ x² ] - [ mean ]²

E[ x² ]  = Variance + [ mean ]²

we substitute

E[ x² ]  = 4 + [ 3 ]²

E[ x² ]  = 4 + 9

E[ x² ]  = 13

Therefore, the value of E[ x² ] is 13

The distribution follows a normal distribution.

The given parameters are:

[tex]\mathbf{\mu = 3}[/tex] --- mean

[tex]\mathbf{\sigma^2= 4}[/tex] --- variance

(a) P(2 < x < 6)

Start by calculating the standard deviation

[tex]\mathbf{\sigma = \sqrt{\sigma^2}}[/tex]

This gives

[tex]\mathbf{\sigma = \sqrt{4}}[/tex]

[tex]\mathbf{\sigma =2}[/tex]

Calculate the z-scores for x = 2 and 6

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{z = \frac{2 - 3}{2} = -0.5}[/tex]

[tex]\mathbf{z = \frac{6 - 3}{2} = 1.5}[/tex]

So, the probability becomes

[tex]\mathbf{P(2 < x < 6) = P(-0.5 < z < 1.5)}[/tex]

Using z table of probabilities, we have:

[tex]\mathbf{P(2 < x < 6) =0.9332 - 0.3085}[/tex]

[tex]\mathbf{P(2 < x < 6) =0.6247}[/tex]

(b) Calculate c if P(X > c) = 0.33

Start by calculating the z-score for p-value = 0.33

From the z table, z = 0.439 when p-value = 0.33

Recall that:

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{0.439 = \frac{x - 3}{2}}[/tex]

Multiply both sides by 2

[tex]\mathbf{0.878= x - 3}[/tex]

Add 3 to both sides

[tex]\mathbf{3.878= x}[/tex]

Rewrite as:

[tex]\mathbf{x = 3.878}[/tex]

Replace x with c

[tex]\mathbf{c = 3.878}[/tex]

The value of c is 3.878

(c) Calculate E[x²]

The variance of a dataset is:

[tex]\mathbf{\sigma^2 =E(x^2) - \mu^2}[/tex]

Substitute known values

[tex]\mathbf{4 =E(x^2) - 3^2}[/tex]

[tex]\mathbf{4 =E(x^2) - 9}[/tex]

Add 9 to both sides

[tex]\mathbf{13 =E(x^2) }[/tex]

Rewrite as:

[tex]\mathbf{E(x^2) = 13 }[/tex]

Hence, the value of [tex]\mathbf{E(x^2) }[/tex] is 13

Read more about normal random variables at:

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Answer:

4(x - 3)

Step-by-step explanation:

4x = 4 * x

12 = 4 * 3

GCF = 4

4x - 12 = 4*x - 4*3

           = 4(x - 3)

                                                                                    the second one.

............................

Answer:

your answer will be

A)(6,10)

B)(2,12)

C)(4,4)

Step-by-step explanation:

hope this helps

have a nice day/night ^_^

Answer:

1001/1500

Step-by-step explanation:

The easiest method for doing this is to just average the two numbers.

e.g. to find a number x between the two numbers ab and cd

x=12[ab+cd]

=12[adbd+bcbd]

=ad+bc2bd

In this case…

x=(2×5)+(3×4)2×2×5=10+1230=2230=1115

You can easily see where that came from.

23=1015 and 45=1215

and the ‘common denominator’ means you just have to pick a value between 10 and 12 . i.e. 11

But you can also say…

23=100150 and 45=120150

and choose any of 101150,102150,...,119150

or

23=10001500 and 45=12001500

and choose any of 10011500,10021500,...,11991500

Answer:4/5 and 2/3 each have a common bottom of 15 so 4/5 is

12/15 and 2/3 will be 10/15

Step-by-step explanation:So than 12/15 forget the bottom don't subtract the bottom just look at it like [12-10] then you got 2 then you go back to the bottom and put it together so your answer is [2/15]

Answer:

20 cookies

Step-by-step explanation:

Range of a data set plotted on a box plot = the maximum value - the minimum value

The maximum value is indicated by the whisker to your extreme right = 25

The minimum value is indicated by the whisker to your extreme left = 5

Range = 25 - 5 = 20

Answer:

what in the math equations is this???

Step-by-step explanation:

Answer:

Jojo makes 1000 and Trish makes 250

Step-by-step explanation:

I hope this helped

Answer:

Trish makes $125 more than Jojo after 10 hours

Step-by-step explanation:

$125 jojo

$250 Trish

Number of green marbles in the bag is equals to [tex]56.[/tex]

" Number is defined as the count of any given quantity as per condition."

According to the question,

Given,

Total number of marbles [tex]= 84[/tex]

[tex]'x'[/tex] represents the number of red marbles

As per given condition,

[tex]'2x'[/tex] represents the number of green marbles

Required equation we have,

[tex]x + 2x = 84\\\\\implies 3x =84\\\\\implies x = \frac{84}{3} \\\\\implies x = 28[/tex]

Substitute the value of [tex]'x'[/tex] to get number of green marbles ,

Number of green marbles [tex]2x = 2\times 28[/tex]

                                                 [tex]= 56[/tex]

Hence, number of green marbles in the bag is equals to [tex]56.[/tex]

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Answer:

I personally don't, but if you search up graph helper you could answer all of them. Hope you find the answer.

Step-by-step explanation:

Answer:

530.66 cm squared

Step-by-step Explanation:

Diameter of the circle = 26 cm

Radius of the circle (r) = 26/2 = 13 cm

[tex]A_{circle} = \pi {r}^{2} \\ \\ A_{circle} = 3.14 \times {(13)}^{2} \\ \\ A_{circle} = 3.14 \times 169 \\ \\ A_{circle} =530.66 \: {cm}^{2} [/tex]

Answer:

The area of 530.66 cm squared.

Option (a) 530.66 cm² is the correct answer.

Step-by-step explanation:

Given :

To Find :

Using Formulas :

[tex]\star{\small{\underline{\boxed{\sf{\red{R = \dfrac{D}{2}}}}}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = \pi{r}^{2}}}}}}}[/tex]

Solution :

Finding the radius of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Radius = \dfrac{D}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \dfrac{26}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \cancel{\dfrac{26}{2}}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = 13}}}[/tex]

[tex]\star{\underline{\boxed{\sf{\red{Radius = 13 \: cm}}}}}[/tex]

Hence, the radius of circle is 13 cm.

[tex]\rule{200}2[/tex]

Now, finding the area of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \pi{r}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 3.14 \times {(13)}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times {(13 \times 13)}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times 169}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314 \times 169}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{53066}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 530.66}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = 530.66 \: {cm}^{2}}}}}}}[/tex]

Hence, the area of circle is 530.66 cm².

[tex]\rule{300}{1.5}[/tex]

Answer:

The answer is D slope = -3 y-intercept = -2

Step-by-step explanation:

Answer

D.

Step-by-step explanation:

The first part of the equation is -3 and the second part is -2. The number attached to the variable is the "slope" and the number coming after the variable is the y intercept.

Answer:

1. [tex]x^{8}[/tex]

2. [tex]k^{45[/tex]

3. [tex]m^{6}n^{21}[/tex]

4. [tex]64w^{18}[/tex]

5. [tex]81y^{12}[/tex]

6. [tex]16x^{4}[/tex]

7. [tex]-125y^{9}[/tex]

8. [tex]a^{36}b^{4}[/tex]

9. [tex]\frac{1}{128} x^{28}[/tex]

10. [tex]54a^{6}[/tex]

11. [tex]8k^{10}[/tex]

12. [tex]-\frac{16}{9} p^{24}[/tex]

Step-by-step explanation:

Answer:

For multiplication you added the exponents and for division you minus the exponents

Answer:

kdkdjdduidddsisiodiod

Answer:

x=12

Step-by-step explanation:

Let's solve your equation step-by-step.

34(16x+16)=37((438)(x)−21)

Step 1: Simplify both sides of the equation.

18x+12=158x−9

Step 2: Subtract 15/8x from both sides.

18x+12−158x=158x−9−158x

−74x+12=−9

Step 3: Subtract 12 from both sides.

−74x+12−12=−9−12

−74x=−21

Step 4: Multiply both sides by 4/(-7).

(4−7)*(−74x)=(4−7)*(−21)

x=12

Answer:

x=12

Answer:

x = 12

Step-by-step explanation:

34(16x + 16) = 37((438)(x) − 21)

18x + 12 = 158x − 9

18x + 12 − 158x = 158x − 9 − 158x

−74x + 12 = −9

−74x + 12 −12 = −9 −12

−74x = −21

(4−7) × (−74x) = (4−7) × (−21)

x = 12

Answer:Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?

Answer:

Car A: Initial Charge = 20

Car B: Initial Charge = 30

Car A: Rate = 5

Car B: Rate = 0

At 2 miles, their charges will be the same

Step-by-step explanation:

Given

Car A

[tex]Base\ Charge = \$20[/tex]

[tex]Rate = \$5[/tex] per mile

Car B

[tex]Base\ Charge = \$30[/tex]

Solving (a): The initial charge

First, we get the  linear equation that represents both car's charges.

Represent number of miles with m.

So, the charges is:

Car A

[tex]A = Base\ Charge + Rate * m[/tex]

[tex]A = 20 + 5 * m[/tex]

[tex]A = 20 + 5m[/tex]

Set m to 0 to get the initial charge:

[tex]A = 20 + 5*0[/tex]

[tex]A=20[/tex]

and

[tex]Rate = 5[/tex]

Car B:

[tex]B = Base\ Charge + 0 * m[/tex] i.e. Rate is 0

[tex]B = 30+ 0 * m[/tex]

[tex]B = 30[/tex]

So:

[tex]Initial = 30[/tex] and [tex]Rate = 0[/tex]

Solving (b): When their charge wil be equal.

To do this, we set:

[tex]A = B[/tex]

[tex]20 + 5m = 30[/tex]

[tex]5m = 30- 20[/tex]

[tex]5m = 10[/tex]

[tex]m = 2[/tex]

At 2 miles, their charges will be equal

Answer:

[tex]n = 5[/tex]

Step-by-step explanation:

Given

[tex]^nP_2 = 20[/tex]

Required

Find n

To do this, we apply permutation formula.

[tex]^nP_r = \frac{n!}{(n-r)!}[/tex]

So, we have:

[tex]\frac{n!}{(n-2)!} = 20[/tex]

Expand the numerator

[tex]\frac{n(n-1)(n-2)!}{(n-2)!} = 20[/tex]

Divide by (n-2)!

[tex]n(n-1)= 20[/tex]

Expand

[tex]n^2 - n = 20[/tex]

[tex]n^2 - n - 20 = 0[/tex]

Expand

[tex]n^2 +4n -5n - 20 = 0[/tex]

Factorize

[tex]n(n+4)-5(n+4)= 0[/tex]

[tex](n-5)(n+4) = 0[/tex]

[tex]n - 5 = 0[/tex] or [tex]n + 4 = 0[/tex]

[tex]n = 5[/tex] or [tex]n = -4[/tex]

Since n cannot be negative, then:

[tex]n = 5[/tex]