Answer:
a) the distance that the solid steel sphere sliding down the ramp without friction is 1.55 m
b) the distance that a solid steel sphere rolling down the ramp without slipping is 1.31 m
c) the distance that a spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping is 1.2 m
d) the distance that a solid aluminum sphere rolling down the ramp without slipping is 1.31 m
Explanation:
Given that;
height of the ramp h1 = 0.40 m
foot of the ramp above the floor h2 = 1.50 m
assuming R = 15 mm = 0.015 m
density of steel = 7.8 g/cm³
density of aluminum = 2.7 g/cm³
a) distance that the solid steel sphere sliding down the ramp without friction;
we know that
distance = speed × time
d = vt --------let this be equ 1
according to the law of conservation of energy
mgh₁ = [tex]\frac{1}{2}[/tex] mv²
v² = 2gh₁
v = √(2gh₁)
from the second equation; s = ut + [tex]\frac{1}{2}[/tex] at²
that is; t = √(2h₂/g)
so we substitute for equations into equation 1
d = √(2gh₁) × √(2h₂/g)
d = √(2gh₁) × √(2h₂/g)
d = 2√( h₁h₂ )
we plug in our values
d = 2√( 0.40 × 1.5 )
d = 1.55 m
Therefore, the distance that the solid steel sphere sliding down the ramp without friction is 1.55 m
b)
distance that a solid steel sphere rolling down the ramp without slipping;
we know that;
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] [tex]I_{}[/tex]ω²
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] ([tex]\frac{2}{5}[/tex]mR²) ω²
v = √( [tex]\frac{10}{7}[/tex]gh₁ )
so we substitute √( [tex]\frac{10}{7}[/tex]gh₁ ) for v and t = √(2h₂/g) in equation 1;
d = vt
d = √( [tex]\frac{10}{7}[/tex]gh₁ ) × √(2h₂/g)
d = 1.69√( h₁h₂ )
we substitute our values
d = 1.69√( 0.4 × 1.5 )
d = 1.31 m
Therefore, the distance that a solid steel sphere rolling down the ramp without slipping is 1.31 m
c)
distance that a spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping;
we know that;
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] [tex]I_{}[/tex]ω²
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] ([tex]\frac{2}{3}[/tex]mR²) ω²
v = √( [tex]\frac{6}{5}[/tex]gh₁ )
so we substitute √( [tex]\frac{6}{5}[/tex]gh₁ ) for v and t = √(2h₂/g) in equation 1 again
d = vt
d = √( [tex]\frac{6}{5}[/tex]gh₁ ) × √(2h₂/g)
d = 1.549√( h₁h₂ )
d = 1.549√( 0.4 × 1.5 )
d = 1.2 m
Therefore, the distance that a spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping is 1.2 m
d) distance that a solid aluminum sphere rolling down the ramp without slipping.
we know that;
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] [tex]I_{}[/tex]ω²
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] ([tex]\frac{2}{5}[/tex]mR²) ω²
v = √( [tex]\frac{10}{7}[/tex]gh₁ )
so we substitute √( [tex]\frac{10}{7}[/tex]gh₁ ) for v and t = √(2h₂/g) in equation 1;
d = vt
d = √( [tex]\frac{10}{7}[/tex]gh₁ ) × √(2h₂/g)
d = 1.69√( h₁h₂ )
we substitute our values
d = 1.69√( 0.4 × 1.5 )
d = 1.31 m
Therefore, the distance that a solid aluminum sphere rolling down the ramp without slipping is 1.31 m
We have that for the Question it can be said that
[tex]A solid steel sphere sliding down the ramp without friction = 1.55m[/tex][tex]A solid steel sphere rolling down the ramp without slipping = 1.309m[/tex]A spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping =[tex]1.2m[/tex]A solid aluminum sphere rolling down the ramp without slipping = [tex]1.309m[/tex]From the question we are told
Suppose the height of the ramp is h1= 0.40m, and the foot of the ramp is horizontal, and is h2= 1.5m above the floor. What will be the horizontal distance traveled by the following four objects before they hit the floor? Assume that R= 15mm in each case; assume that the density of steel is 7.8 g/cm3; and assume that the density of aluminum is 2.7 g/cm3.
Generally the equation for sliding without friction is mathematically given as
[tex]V = \sqrt{4Hh}[/tex]
the equation for sliding without slipping is mathematically given as
[tex]X = \sqrt{\frac{4Hh}{1+I/mR^2}}[/tex]
A) A solid steel sphere sliding down the ramp without friction.[tex]V = \sqrt{4*1.5*0.4}\\\\= 1.55m[/tex]
B) .A solid steel sphere rollingdown the ramp without slipping.[tex]I = 2/5 mR^2\\\\X = \sqrt{\frac{4*1.5*0.4}{1+2/5}}\\\\= 1.309m[/tex]
C) A spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping.
[tex]I = 2/3 mR^2\\\\X = \sqrt{\frac{4*1.5*0.4}{1+2/3}}\\\\= 1.2m[/tex]
D) A solid aluminum sphere rolling down the ramp without slipping.
[tex]X = \sqrt{\frac{4*1.5*0.4}{1+2/5}}\\\\= 1.309m[/tex]
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A battery connected to two wires in parallel. Both wires are made of the same material and are of the same length, but the diameter of wire A is twice the diameter of wire B.
True or False for the following:
1) The resistance of wire B is four times as large as the resistance of wire A.
2) The power dissipated in wire A is 16 times the power dissipated in wire B.
3) The voltage drop across wire B is larger than the voltage drop across wire A.
4) The resistance of wire B is twice as large as the resistance of wire A.
5) The current through the battery is five times larger than the current through wire B.
Answer:
true 1
2 is false 2. 3 . 4. 5
Explanation:
For this exercise, let's calculate the different parameters and analyze the corresponding statements.
the resistance of each wire
R = ρ [tex]\frac{L}{A}[/tex]
wire B.
has a diameter of d₀
therefore its radius is r₀ = d₀ / 2
the area is A = pi r₀²
A = π d₀²/ 4
we subtitle
Ro = ρ [tex]\frac{L \ 4}{\pi d_o^2}[/tex]
R_b = R₀
wire A
the diameter is d = 2d₀
therefore the radius is r = d/2
r = d₀
resistance is
R_a = ρ [tex]\frac{L}{\pi d_o}[/tex]
R_a = 4 R₀
when examining the answers
1 is true
4 is false
Now let's calculate the power
P = V I
V = I R
P = V² / R
as they indicate that the cables are connected in parallel, the voltage in them is the same, therefore the potency depends on the resistance
wire B
P = V² / R_b
P_b = V² / R₀
wire A
P_a = v² / R_a
P_a = V² / 4R₀
P_a = ¼ P_b
2 is false
in a parallel circuit the waves are the same therefore
3 False
ohm's law is
V = I r
I = V / R
wire B
I_b = V / R_b
I_b = V / Ro
wire
I_a = V / R_a
I_a = V / 4 Ro
I_a = ¼ I_a
5 is false
Add a suffix to each of the following words to make new words?
Where's the following words?
SOLVE for potential energy! You are at the top of water slide that is 80 meters tall. You have a mass of 65 kilograms. The gravity of Earth is 9.8!! What is your potential energy?? (use the picture attached to see the formula!) * (1 Point)
Answer:
Given :-mass = 65 kg
Height = 80 m
Acceleration = 9.8 m/s²
To Find :-Potential energy
Solution :-We know that
PE = mass × acceleration × height
PE = 65 × 80 × 9.8
PE = 50,960 Joules
[tex] \\ [/tex]
Friction occurs when microscopic hills and valleys stick together
true or false
Answer:
true
Explanation:
Friction occurs because no surface is perfectly smooth. Rougher surfaces have more friction between them. Heavier objects also have more friction because they press together with greater force. Friction produces heat because it causes the molecules on rubbing surfaces to move faster and have more energy.
Explanation:
true but not going to copy and paste,
A high frequency sound will have a ?
Answer:
The frequency of a sound wave is what your ear understands as pitch. A higher frequency sound has a higher pitch and the lower the period
Answer:
High-frequency sound waves produce high-pitched sounds, and low-frequency sound waves produce low-pitched sounds.
An electric current is made up of _____ charged electron.
An Electric current is made up of a negatively charged electron.
What is an Electric current?Electric current is defined as the flow of charge per unit time in a conductor. It is a scalar quantity.
I=Q/T where,
I= Electric Current
Q= Flow of charge and,
T=Time
The electron consists of a negative charge and the flow of electrons takes place from the negative end to the positive end, but the current flow in the circuit takes place from positive to negative, which is opposite to the direction of the flow of electrons.
The current flow takes place due to the Potential difference (V).
SI unit of Electric current is Ampere.
1 ampere= 1c/1s and
1 mA= [tex]10^{-3}[/tex] A.
An ammeter is a device to measure the electric current in the circuit, and it is connected in series.
Hence, electric current is made up of negatively charged electrons.
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An uncharged capacitor and a resistor are connected in series with a switch and a 12 V battery. At the instant the switch is closed, the voltage across the resistor is
Answer:
V = 12 V
Explanation:
Since a capacitor can't change the voltage between its plates instantaneously, this means that just after the switch is closed, the voltage through the capacitor is zero.So, the current that flows in this moment is the same that would flow in a series circuit with only one resistor connected to the battery.Applying KVL to the circuit (neglecting the presence of the capacitor which can be replaced by a short circuit just after closing the switch), the voltage through the resistor must be equal to the one of the battery, i.e., 12 V.Which is the best description of biodiversity?
1. All animals in an ecosystem
2. The variety of the type of life within the biosphere
3. The study of life
3. The variety of plants on Earth
Answer:2
Explanation:
Describe the relationship between Mass & Acceleration (if you change one, what happens to the other):
Answer:
As mass increase acceleration decrease so the relationship is opposite
Answer:
It is an inverse relationship, if you increase one the other will decrease, and vice versa
Explanation:
How is the chemical bonding within a molecule of carbon dioxide (CO2) different from the chemical bonding within a crystal of iron (Fe)?
A.
In an iron crystal, the atoms are joined by sharing electrons. In carbon dioxide, atoms of carbon and oxygen are held together by freely moving electrons.
B.
In a carbon dioxide molecule, atoms of carbon and oxygen are joined by sharing electrons. In an iron crystal, the atoms are held together by freely moving electrons.
C.
In an iron crystal, the atoms are joined by their opposite electrical charges. In carbon dioxide, atoms of carbon and oxygen are held together by freely moving electrons.
D.
In a carbon dioxide molecule, atoms of carbon and oxygen are joined by their opposite electrical charges. In an iron crystal, the atoms are held together by freely moving electrons.
Answer:
I'ts B
Explanation:
:p
The chemical bonding within a molecule of carbon dioxide (CO2) different from the chemical bonding within a crystal of iron (Fe) in a carbon dioxide molecule, atoms of carbon and oxygen are joined by sharing electrons. In an iron crystal, the atoms are held together by freely moving electrons. Therefore, option B is correct.
What is chemical bonding ?The term chemical bonding is defined as the formation of a chemical bond between two or more atoms, molecules, or ions to form a chemical compound.
There are three main types of chemical bonding that are ionic bonding, covalent bonding, and metallic bonding.
The chemical bonding within a molecule of carbon dioxide (CO2) different from the chemical bonding within a crystal of iron (Fe) because in a carbon dioxide molecule, atoms of carbon and oxygen are joined by sharing electrons. In an iron crystal, the atoms are held together by freely moving electrons.
Thus, option B is correct.
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Gauss's law: Group of answer choices can always be used to calculate the electric field. relates the electric field throughout space to the charges distributed through that space. only applies to point charges. relates the electric field at points on a closed surface to the net charge enclosed by that surface. relates the surface charge density to the electric field.
Answer:
relates the electric field at points on a closed surface to the net charge enclosed by that surface.
Explanation:
Gauss Law states that overall electric flux of a closed surface is equivalent right to charge enclosed which is divided by the permittivity. In other words Gauss Law stress that
net electric flux that pass through an hypothetical closed surface is equivalent to overall electric charge present within that closed surface.
The Gauss law can be expressed mathematically as
ϕ = (Q/ϵ0)
Q = total charge within the surface,
ε0 = the electric constant
If you let yourself fall from a bridge above the water for .4 seconds your speed is?
Answer:
3.91m/s
Explanation:
We can use the equation h=16t^2 to find the height in feet for a free-falling object. The height from the bridge to the water is h=16(0.4)^2=16(0.16)=2.56 ft
Next, we use the equation v=sqrt(2gh) to determine velocity from vertical height. First we must convert feet to meters as velocity is measured in m/s. 2.56ft is about 0.78 meters. Since h=0.78m from the previous equation and g=9.81m/s^2, then your velocity is v=sqrt(2*9.81*0.78)=sqrt(15.3036)=3.911981595
So, your speed/velocity is approximately 3.91m/s
g A particle is trapped in a 20 nm wide infinite potential well. What is the wavelength of the particle corresponding to n
Question:
A particle is trapped in a 20 nm wide infinite potential well. What is the wavelength of the particle corresponding to n = 7 in nm?
Answer:
[tex]\lambda_n = 5.71\ nm[/tex]
Explanation:
Given
[tex]L = 20nm[/tex] --- the width
[tex]n = 7[/tex]
Required
Determine the wavelength ([tex]\lambda[/tex])
This is calculated as:
[tex]\lambda_n = \frac{2L}{n}[/tex]
Substitute values for L and n
[tex]\lambda_n = \frac{2*20nm}{7}[/tex]
[tex]\lambda_n = \frac{40nm}{7}[/tex]
[tex]\lambda_n = \frac{40}{7}nm[/tex]
[tex]\lambda_n = 5.71428571\ nm[/tex]
[tex]\lambda_n = 5.71\ nm[/tex] --- approximated to 3 significant figures
A solid weighs 16.5N on the surface of the moon. The force of gravity on the moon is 1.7N/Kg.
Determine the mass of the solid.
Answer:
mass = 9.7 kg
Explanation:
Weight = Mass x Acceleration due to gravity (g)
16.5 = mass x 1.7
mass = [tex]\frac{16.5}{1.7}[/tex] = 9.7 kg
The mass for the given solid on the surface of moon is 9.7 kg.
What is gravity?The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.
The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.
Given a solid weighs 16.5N on the surface of the moon. The force of gravity on the moon is 1.7N/Kg
Weight = Mass x Acceleration due to gravity (g)
Substituting the values, we have
16.5 = M x 1.7
M = 9.7 kg
Thus, the mass of the solid is 9.7 kg.
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A polycondensation reaction takes place between 1.2 moles of a dicarboxylic acid, 0.4 moles of glycerol (a triol) and 0.6 moles of ethylene glycol (a diol). A.Calculate the critical extents of reaction for gelation using (i) the statistical theory of Flory and (ii) the Carothers theory.B.Comment on the observation that the measured value of the critical extent of reaction is 0.866.
Answer:
A) i) using statistical theory of floxy
(Pa)c = 0.816
(Pb)c = 0.816
ii) using Carothers theory
( Pc ) = 0.917
B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different
Explanation:
Given data :
Polycondensation reaction takes place between : 1.2 moles of dicarboxylic acid , 0.4 moles of glycerol and 0.6 moles of ethylene glycol
A) Calculate the critical extents of reaction for gelation
i) using statistical theory of floxy
(Pa)c = 0.816
(Pb)c = 0.816
ii) using Carothers theory
( Pc ) = 0.917
attached below is the detailed solution
B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different
A 5 kg block rests on a rough horizontal table. A rope is
attached to the block and is pulled with a force of 11N to the
left. As a result, the block accelerates at 2 m/s2. The coefficient
of kinetic friction between the block and the table is (round
to the nearest hundredth)
Answer:
Approximately [tex]0.02[/tex] (assuming that [tex]g = 9.81\; \rm N \cdot kg^{-1}[/tex], and that the block was initially moving to the left.)
Explanation:
Apply Newton's Second Law to find the net force on this block.
Mass of this block: [tex]m = 5\; \rm kg[/tex].
Acceleration of this block: [tex]a = 2\; \rm m \cdot s^{-2}[/tex].
[tex]\begin{aligned}\text{Net force} &= m \cdot a \\ &= 5\; \rm kg \times 2\; \rm m \cdot s^{-1} = 10\; \rm N\end{aligned}[/tex].
The block is moving and accelerating towards the left. Hence, friction (which opposes motion) would be towards the right and would be opposite to the direction of the [tex]11\; \rm N[/tex] pulling force.
Therefore, the expression for the net force on this object would be:
[tex](\text{Net force} ) = (\text{Pulling force}) - (\text{Friction})[/tex].
[tex]10\; \rm N = 11\; \rm N - (\text{Friction})[/tex].
Hence:
[tex]\text{Friction} = 11\; \rm N - 10\; \rm N = 1\; \rm N[/tex].
The question states that this table is horizontal. Weight of the block (downwards) and normal force from the table (upwards) are the only two forces on this block in the vertical direction. Hence, the magnitude of the normal force on this block would equal to that of the weight of the block:
[tex]\begin{aligned} |\text{Normal force}| &= |\text{Weight}| \\ &= m \cdot g \\ &= 5 \; \rm kg \times 9.81\; \rm N \cdot kg^{-1} = 49.05\; \rm N\end{aligned}[/tex].
Calculate the constant of kinetic friction between this block and the table:
[tex]\begin{aligned}\mu_{\text{k}} &= \frac{\text{Friction}}{\text{Normal force}} \\ &= \frac{1\; \rm N}{49.05\; \rm N} \approx 0.02\end{aligned}[/tex].
After a long day of driving you take a late-night swim in a motel swimming pool. When you go to your room, you realize that you have lost your room key in the pool. You borrow a powerful flashlight and walk around the pool, shining the light into it. The light shines on the key, which is lying on the bottom of the pool, when the flashlight is held 1.2 m above the water surface and is directed at the surface a horizontal distance of 1.5 m from the edge (Fig. P33.44). If the water here is 4.0 m deep, how far is the key from the edge of the pool
Answer:
Total length of pool [tex]4.4[/tex] meter
Explanation:
The image for the question is attached for better understanding
[tex]Tan \Theta= \frac{1.5}{1.2}\\\Theta_a = tan^{-1} (1.25)\\\Theta_a = 51.34[/tex]degree
Using the Snell’s law –
[tex]n_a * sin\Theta_a = n_b * sin\Theta_b\\1 * sin 51.34 = 1.33 * sin\Theta_b\\sin\Theta_b = 0587\\\Theta_b = 35.94\\Tan \Theta_b = \frac{BC}{4} \\BC = 4 * tan (35.94) \\BC = 2.9[/tex]
Total length of pool [tex]= 1.5 +2.9 = 4.4[/tex] meter
Answer:
Explanation:
i is angle of incidence and r is angle of refraction .
Tan i = 1.5 / 1.2 = 1.25
i = 51.34⁰
refractive index of water = 1.33
sin i / sinr = 1.33
sin 51.34 / sin r = 1.33
sinr = .78 / 1.33 = .5864
r = 36⁰
From the figure given ,
AB / AP = Tan 36
AB = AP tan 36 = 4 x tan 36 = 2.9 m
D = OA + AB
= 1.5 + 2.9
= 4.4 M
Distance of key from edge = 4.4 m .
A monk is sitting atop a mountain in complete rest in meditation. What is the Kinetic
Energy of the monk? (assume mass of 65 kg and the mountain's height was 1000 m)
4,225,000
No Kinetic Energy - because there is no movement
637,000
65.000
Answer:
No kinetic energy-because there is no movement
Explanation:
It states that the monk is at complete rest so there is no movement.
The manufacturer of a 9V dry-cell flashlight battery says that the battery will deliver 20 mA for 80 continuous hours. During that time the voltage will drop from 9 V to 6 V. Assume the drop in voltage is linear with time. How much energy does the battery deliver in this 80 h interval
Answer:
17280 J or 17.28 kJ
Explanation:
Given that the voltage drop,
U = U2 - U1
U = 9 - 6
U = 3V
Also, we're told that the current, I is equal to 20 mA with the discharge time, t being 80 hrs.
Converting the time from h oi urs to seconds, we have
t = 80 * 3600
t = 288000
Now, to find the energy needed, we're going to use the formula
w = pt, where p = U * I
p = 3 * 20*10^-3
p = 60*10^-3
w = 60*10^-3 * 288000
w = 17280 J or 17.28 kJ
Therefore, the total energy the battery delivers in the 80 hrs is 17.28 kJ
A 80 Kg monkey climbs a 15 meter tree in half a minute. What is the magnitude of power the monkey demonstrated?
a. 13.1 J/S
b. 392 J/S
c. 784 J/s
d. 11760 J/s
Answer:
Power = Work / Time
P = m g h / t = 80 kg * 9.8 m/s^2 * 15 m / 39 s = 320 N m/ s = 392 J / s
= 392 Watts
The magnitude of power the monkey demonstrated is equal to 392 J/S.
Power calculation
To measure the power of a given body, one must relate its weight, the displacement performed and the time in which the movement was performed, in such a way:
[tex]P = \frac{m\times g\times d}{t}[/tex]
Thus, applying the values given by the statement we have:
[tex]P = \frac{80 \times 9.8 \times 15}{30}[/tex]
[tex]P = 392 J/s[/tex]
So, the power performed by the monkey climbing 15 meters is equal to 392J/s.
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A wire of cross-sectional area 5.00 106 m2 has a resistance of 1.75 O. What is the resistance of a wire of the same material and length as the first wire, but with a cross-sectional area of 8.75 106 m2
Answer:
the resistance of the second wire is 1 ohm.
Explanation:
Given;
cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²
resistance of the first wire, R₁ = 1.75 ohms
cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²
resistance of the second wire, R₂ = ?
The resistance of a wire is given as;
R ∝ [tex]\frac{L}{A}[/tex]
Since the length of the two wires is constant
R₁A₁ = R₂A₂
[tex]R_2 = \frac{R_1A_1}{A_2} \\\\R_2 = \frac{1.75\ \times \ 5.00\times 10^6}{8.75\times 10^6} \\\\R_2 = 1 \ ohm[/tex]
Therefore, the resistance of the second wire is 1 ohm.
How do intermolecular forces (IF) and internal kinetic energy (KE) compare in gases?
IF = 0, KE is large
IF < KE
IF ≥ KE
IF > KE
Please help me!
Answer:
IF < KE
Explanation:
The kinetic energy of the gas is greater than the intermolecular forces making the molecules have room to move around without disruption. In a lot of gases, there are sometimes no intermolecular forces between all the particles.
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How long will it take a 200kg stationary man in space to travel 20m if he throws a 10 kg object at a velocity of 30m/s?
POSSIBLE POINTS: 1.92
When the heater stopped working in a hair dryer, the fan stopped working
as well. Which of the following is the most likely explanation?
They were connected in a series circuit
They were connected in a parallel circuit.
They were no longer connected to the switch
They developed a short circuit
1
2
3
4 5 6 7 8 9 10
Next
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Answer:
jnfal4u4ryhfsbjls5
Explanation:
duehdakjweyedufkbshegygfr
(a) What is the electric field 4.00 m from the center of the terminal of a Van de Graaff with a 3.00 mC charge, noting that the field is equivalent to that of a point charge at the center of the terminal?
______ N/C
(b) At this distance, what force does the field exert on a 2.00C charge on the Van de Graaff's belt?
_____ N
Answer:
a) E = 1.69 10⁶6 N / C, b) F = 3.38 10⁶ N
Explanation:
a) In this exercise using Gauss's law we can consider the charge of the generator sphere as if it were at its center, therefore the electric field is
E = k [tex]\frac{q}{r^2}[/tex]
let's calculate
E = 9 10⁹ 3.00 10⁻³ / 4²2
E = 1.6875 10⁶ N / C
E = 1.69 10⁶6 N / C
b) let's calculate the electric force
F = q E
F = 2.00 1.69 10⁶
F = 3.38 10⁶ N
liquids have higher coefficents of expansion than solids do in general. ture or false worth 29 points!
Answer:
true
Explanation:
10/12
11.
You drive the 10 miles to the mall at an average speed of 40 mph. On
the way home, you hit severe traffic and had to drive at an average
speed of 10 mph. What is your average speed for the trip?
Help me please I wrote some but I am still stuck
Answer:
write something like after the spacecraft launched all of the potential energy transformed into kinetic energy causing the spacecraft to go at an abnormal spped.
Explanation:
Which one of the following is an example of an acid-base reaction?
Answer:
B
Explanation:
Acid reacts with base to give salt and water.
HCL - Acid
Mg(OH)2 - Base
H2O - Water
MgCl2 - Salt
Answer: B because A p e x
Explanation:
PLZ HELP IT URGENT
Describe what Rutherford would have seen in his gold foil experiment if J.J. Thompson's Plum Pudding model was completly accurate.
Answer: i use this in ss class
Explanation: