Answer:
The answer is "[tex]20 \ mL[/tex]"
Explanation:
Given:
Molarity= number of moles
because it is 1 Liter
[tex]\to \frac{0.03\ moles}{1.5 moles}=0.02\ L= 20 \ mL \ of\ Tris\\\\[/tex]
therefore,
it takes 20 mL of Tris.
[tex]\to \frac{0.150 \ moles}{5\ moles} =0.03\ L\\\\[/tex]
[tex]= 30 \ mL \ of\ Nacl[/tex]
So, take [tex]20 \ mL\ of\ NaCl.[/tex]
Calculate the molality of a solution that contains 75.0-grams of methyl alcohol, CH3OH, dissolved in 600.0-grams of
water.
Answer:
[tex]m=3.90mol/kg[/tex]
Explanation:
Hello there!
In this case, since the molality of a solution is calculated by dividing moles of solute by kilograms of solvent, it turns out firstly necessary for us to calculate the moles of methyl alcohol in 75.0 grams as shown below:
[tex]n=\frac{75.0g}{32.04g/mol}=2.34mol[/tex]
Then, the kilograms of water, 0.600 kg, and finally, the resulting molality:
[tex]m=\frac{2.34mol}{0.600kg}\\\\m=3.90mol/kg[/tex]
Regards!
Suppose that you add 21.0 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 2.58 oC compared to pure benzene. What is the molar mass (in g/mol) of the unknown compound
If a swimming pool contains 2850 kg liters of water how many gallons of water does it contain
If a light beam strikes a shiny object at a 90-degree angle, to what are the angle of incidence and the angle of reflection equal?
Answer:
Angle of incidence = angle of reflection = 0
Explanation:
Given that,
A light beam strikes a shiny object at a 90-degree angle.
The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.
Here, the beam strikes normally. So, the angle of incidence is 0.
A/c to the law of reflection,
Angle of incidence = angle of reflection
So, the angle of reflection is also equal to 0.
Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures PA and inside the flasks are measured.
a. PA will be greater than
b. PA will be less than PB
c. PA will be equal to PB
d. It's impossible to predict whether PA or will be greater without more information.
The question is incomplete, the complete question is:
Liquid A is known to have a lower viscosity and lower vapor pressure than Liquid B. Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures [tex]p_A[/tex] and [tex]p_B[/tex] inside the flasks are measured.
a. [tex]p_A[/tex] will be greater than
b. [tex]p_A[/tex] will be less than [tex]p_B[/tex]
c. [tex]p_A[/tex] will be equal to [tex]p_B[/tex]
d. It's impossible to predict whether [tex]p_A[/tex] or will be greater without more information.
Answer: The correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
Explanation:
Vapor pressure is defined as the equilibrium pressure which is exerted by the vapor phase to be in thermodynamic equilibrium with its condensed state (liquid phase) in a closed system at a given temperature.
We are given:
Vapor pressure of A < Vapor pressure of B
This means that a lesser number of gaseous molecules will form over its surface and thus, will experience lower pressure.
Thus, [tex]p_A<p_B[/tex]
Hence, the correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
Which one of the mixtures would most likely produce a chemical reaction?
F2 + At- OR At2 + F-
Answer:
F₂ + At⁻
Explanation:
Astatine is the only Halogen that does not exist as a diatomic molecule. One Astatine atom would have a charge of 1⁻. Fluorine is the most electronegative element, and therefore very reactive and commonly forms a diatomic molecule.
How many grams of oxygen are present in 93.98 g of CO2?
Answer:
There are about 68.33 grams of oxygen present in 93.98 g of CO2.
Two hundred forty-eight milliliters of an acid with an unknown concentration are titrated with a base that has a
concentration of 1.4 M. The indicator changed color when 82 milliliters of base were added. What is the concentration of
the unknown acid?
O 0.46 M
4.2 M
Answer:0.46
Explanation:
Calculate the pKa of hypochlorous acid (HClO, a weak acid). A 0.015 M solution of hypochlorous acid has a pH of 4.64.
Answer:
"7.46" is the correct answer.
Explanation:
Given that:
[tex]pH=4.64[/tex]
[tex]C=0.015 \ M[/tex]
The equation:
⇒ [tex]HA \rightleftharpoons H^++A^-[/tex]
HA = C - Cα
H⁺ = Cα
A⁻ = Cα
now,
⇒ [tex]pH=-log(H^+)[/tex]
[tex]=-log(C \alpha)[/tex]
[tex]=4.64[/tex]
[tex]C \alpha = 2.3\times 10^-5 \ M[/tex]
As we know,
⇒ [tex]K_a=C \alpha^2[/tex]
[tex]=(\frac{C \alpha}{C} )^2\times C[/tex]
[tex]=\frac{(2.3\times 10^{-5})^2}{0.015}[/tex]
[tex]=3.5\times 10^{-8}[/tex]
hence,
⇒ [tex]pK_a=-log(K_a)[/tex]
[tex]=7.46[/tex]
The normal boiling point of a certain liquid X is 130.9 °C, but when 19.9 g of urea (NH2) CO are dissolved in 200. g of X, it is found that the solution boils at 134.1 °C instead. Use this information to calculate the molal boiling point elevation constant K, of X. Be sure your answer has the correct number of significant digits x 1 ℃.mol -kg
Answer:
K = 1.93 °C/m
Explanation:
This question can be solved by formula of elevation of boiling point.
Boiling T° of solution - Boiling T° of pure solvent = K . m . i
Our solute is urea.
Our solvent is X.
We convert mass of urea to moles: 19.9 g . 1 mol / 60.06g = 0.331 mol
We convert g of solute to kg = 200 g . 1 kg/ 1000g = 0.2kg
m = molality → moles of solute / kg of solvent
m = 0.331 mol / 0.2 kg = 1.66 m
As urea is an organic compound, no ions will be formed.
i = 1 (a non ionizing compound)
Let's replace data in formula:
134,1°C - 130.9°C = K . 1.66 m . 1
3.2 °C / 1.66 m = K
K = 1.93 °C/m
The ideal gas law is PV = nRT.
Use 8.31 for R. (8.31 Lx kPa / Kx mol)
What is the temperature of 3.0 moles of a gas that is in a closed container of
volume 9L, and has a pressure of 85kPa?
1. 3.4 kelvin
2. 0.03 kelvin
3. 30.7 kelvin
4. 28.6 kelvin
Answer: 30.66945 kelvin
Explanation:
Explain the science of water pressure
"At sea level, the air that surrounds us presses down on our bodies at 14.7 pounds per square inch . (gooxgle) "
Basically the deeper you go under the water, whether that be a pool or the sea the pressure will increase because of the weight of the water above you. Which causes greater force.
PLS HELP ME PLZ AND THANKS
Answer:
q6= third option
q7= third option
Explanation:
kinetic molecular theory deals with temperature
pressure inversely proportional to volume so when volume doubled, pressure halved given that mass and temperature constant
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the metal (M). Please provide your answer in 2 decimal places.
a. How many moles of oxygen atoms are found in 4.00 g of O2?
b. How many atoms of hydrogen are found in 0.400 mol of H2S?
c. How many hydrogen atomsare present in 0.235 g of NH3?
Answer:
See solution.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:
[tex]\% M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\% =\frac{m_M}{m_M+32.00}*100 \%[/tex]
Thus, we solve for the molar mass of the metal to obtain:
[tex]59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol[/tex]
For the subsequent problems, we proceed as follows:
a.
[tex]4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2[/tex]
b.
[tex]0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH[/tex]
c.
[tex]0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH[/tex]
Regards!
Write the Ka expression for an aqueous solution of hypochlorous acid: (Note that either the numerator or denominator may contain more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as , and not as )
Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
Explanation:
The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.
[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]
When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.
Hence, the expression for acid dissociation constant of this reaction is as follows.
[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]
Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
What is 0.29km in mm
Select the correct answer.
Which value of Keq represents a scenario where the reactants of an equilibrium reaction are favored?
A.
Keq=1
B.
Keq = 6.0 x 10-2
O C.
Keq = 3.8 x 104
OD
Keq = 490.5
O E. Keq = 2.5
Answer:
B. Keq = 6.0 x 10-2.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to remember that any equilibrium constant is computed by dividing the concentration of products by that of reactants:
[tex]Keq=\frac{[Prod]}{[Reac]}[/tex]
Thus, a reaction that is reactant-favored will have a Keq>1 because the concentration of reactants prevail over that of products at equilibrium, and thus, the correct answer is B. Keq = 6.0 x 10-2.
Regards!
Given that vat contains 9600 kg of milk, what is the mass of mg of the milk that vat contains?
Answer:
9.6x10⁹ mg
Explanation:
In order to solve this problem we need to convert 9600 kg into mg.
First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:
9600 kg * [tex]\frac{1000g}{1kg}[/tex] = 9.6x10⁶ g
Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:
9.6x10⁶ g * [tex]\frac{1000mg}{1g}[/tex] = 9.6x10⁹ mg
The mass of milk miligrams is 9.6x10⁹.
An aqueous salt solution is 15.0% mass sodium chloride. How many grams of salt are in 250.0 grams of this solution? Use correct
significant figures.
Answer:
37.5 g NaCl
Explanation:
Step 1: Given data
Concentration of NaCl: 15.0% m/mMass of the solution: 250.0 gStep 2: Calculate how many grams of NaCl are in 250.0 g of solution
The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.
250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl
The reaction of iron (III) oxide with carbon monoxide produces iron and carbon dioxide.
Fe2O3(s) + 3C0(9) - 2Fe(s) + 3CO (9)
How many grams of Fe2O3 are required to produce 4.65g Fe? You must show your work to receive full credit.
Answer:
6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.
Explanation:
The balanced reaction is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Fe₂O₃: 1 moleCO: 3 molesFe: 2 molesCO₂: 3 molesThe molar mass of each compound is:
Fe₂O₃: 159.7 g/moleCO: 28 g/molFe: 55.85 g/moleCO₂: 44 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Fe₂O₃: 1 mole* 159.7 g/mole= 159.7 gramsCO: 3 moles* 28 g/mol= 84 gramsFe: 2 moles* 55.85 g/mole= 111.7 gramsCO₂: 3 moles* 44 g/mole= 132 gramsThen you can apply the following rule of three: if by stoichiometry 111.7 grams of Fe are produced from 159.7 grams of Fe₂O₃, 4.65 grams of Fe are produced from how much mass of Fe₂O₃?
[tex]mass of Fe_{2} O_{3} =\frac{4.65 grams of Fe*159.7 grams of Fe_{2} O_{3}}{111.7grams of Fe}[/tex]
mass of Fe₂O₃= 6.65 grams
6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.
3 enzimas presentes en nuestro organismo e indique en que procesos actúan
Answer:
ATP asa, Helicasa, Proteasa, ARN polimerasa
Explanation:
Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.
Al momento de referirse a ellas, se utiliza la terminación asa.
ATPasa → Sintetizando ATP para el funcionamiento celular
Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.
Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.
ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.
How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?
Answer:
63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid
I'm sorry if it's wrong, I tried.
Explanation:
Which bodies of water in the list are found to the west of the Philippines?
Answer:
South China sea
Explanation:
To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).
which of the following can cause muscle fatigue ?
A.A build up of lactic acid
b.an inadequate supply of oxygen
C.an inadequate supply of glycogen
D.all of the above
Answer:
The correct answer is -all of the above.
Explanation:
Muscle fatigue is a reduced ability in work capacity caused by work itself. It is known that altering oxygen is contracting skeletal muscle affects performance. Reduced O2 supply increases the rate of muscle fatigue.
The lactic acid is accumulated as it forms rapidly but the breaking of the lactic acid is slow down, which causes muscle fatigue. Less ATP and glycogen in muscle results in fatigue as the muscle is not able to generate energy to power contractions and therefore contributes to muscle fatigue.
Se prepara una solución agregando sal en 500 g de agua. Calcular la masa de sal, cuando se tiene una solución al 6,4 % en masa
Answer:
x~ 34.19 grams del sal o ~ 34 grams!
Explanation:
el porcentaje de masa se escribe como
% de masa = masa de sal / (masa de sal + masa de disolvente) * 100%
aquí, el disolvente se da como 500 g de agua.
usa x en lugar de masa de sal y resuelve usando álgebra
6.4 = x / (x+ 500) * 100
0.064 = x / (x+500)
0.064 x + 32 = x
32 = x-0.064x
32 = 0.936 x
x~ 34.19 grams del sal o ~ 34 grams!
How many molecules are in 4.44 mol of CF4? 4.44 mol CF4 =
I am not sure abt the ans
molar mass= 88
1 molecule = 6.022×10^23
4.44 moles = 6.022×10^23×4.44/88
= 26.73768 × 10^23/88
= 0.3038372727 ×10^23
PLEASE HELP ME SOLVE THIS.Thank you so much!
Answer: The coefficients for the given reaction species are 1, 6, 2, 3.
Explanation:
The given reaction equation is as follows.
[tex]Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}[/tex]
Now, the two half-reactions can be written as follows.
Reduction half-reaction: [tex]Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}[/tex]
This will be balanced as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O[/tex] ... (1)
Oxidation half-reaction: [tex]Cl^{-} \rightarrow Cl_{2} + 1e^{-}[/tex]
This will be balanced as follows.
[tex]6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}[/tex] ... (2)
Adding both equation (1) and (2) we will get the resulting equation as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O[/tex]
Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.
How would the accuracy of your determined Keq change if all of your volume measurements were made with graduated cylinders rather than pipets
Answer:
Accuracy decreases
Explanation:
All meaurements have an uncertainty (That is, the error of the measurement). The uncertainty of graduated cylinders is higher than uncertainty of pipets.
The accuracy is how close is the measurement to the real value.
If you use graduated cylinders rather than pipets, accuracy decreases because you will have more uncertainty in the measurements putting of the real value and the real value.
The accuracy of the determined value decreases if all measurement is done with graduated cylinders.
What is Accuracy?The accuracy is the measurement of how close the calculated value is to the real value.
When a student measures the volume with a graduated cylinder the chances of error increase.
Therefore, the accuracy of the determined value decreases if all measurement is done with graduated cylinders.
Learn more about accuracy:
https://brainly.com/question/24869562
2
Drag the tiles to the correct locations on the equation. Not all tiles will be used.
Two atoms interact with each other as shown by the equation. Complete the equation by filling in the missing parts.
1
2
3
4
5
5
H
le
Li
?H + He -
+
TH
H
Reset
Next
Answer:
4 on the top
He in the middle
2 on the bottom
Explanation:
Correct on plato
The missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.
What is interaction of the two atoms?The two atoms interact with each other as shown by the equation below;
[tex]^4_2He[/tex]
where;
He is Helium atom4 is the mass number of the helium atom2 is the atomic number of the helium atom.Thus, the missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.
Learn more about helium atom here: https://brainly.com/question/26226232
#SPJ5
Which compounds, on heating with an excess of concentrated sulfuric acid, produce only one product with molecular formula C7H10? [choices on the picture]
Answer:
1 and 2
Explanation:
When Concentrated H2SO4 reacted with the alcohols, they produce cycloalkenes. This is a mechanism known as dehydration of alcohols with an acid catalyst. This is because concentrated H2SO4 acts as a great oxidizing agent. In the process, the alcohols are heated to a high temperature with an excess of pure sulfuric acid. By passing the gases through a sodium hydroxide solution, the carbon dioxide and sulfur dioxide produced by reactive species are eliminated. The reaction mechanism shown in the image below indicates that only compounds 1 and 2 produce only one product.