Answer:
B 2:2
Explanation:
Mole ratio is the comparison of the ratio of two compounds or elements in a chemical reaction. In a balanced equation, the moles of a particular compound or element is written as a coefficient. This means that mole ratio is the ratio of the coefficient of two substances in a reaction.
In this balanced chemical equation given as follows:
2CO + 02 → 2CO2
The number of moles/coefficient of carbon monoxide (CO) is 2 while that of carbon dioxide (CO2) is 2.
Hence, the mole ratio of CO to CO2 is 2:2
If HA, an acid, is 15 percent dissociated in a 2.00 molar solution, what is the Ka for the solution?
A.5.3 × 10-2
B.6.4 × 10-3
C.1.1 × 10-2
D.1.2 × 10-2
Answer:
A. 5.3 X 10^-2
Explanation:
I got 100 on PLATO
True or False all non - metal elements are gassed at room temperature.
Answer:
false
Explanation:
you have bromine , its a non metal and liquid in room temperature
Select the correct choices to complete the sentence.
In the ionic solid sodium chloride (NaCl), there is a________
ratio of sodium ions to chlorine ions.
one and half to one
tow to one
one to two
one to one
Answer:
one to one
Explanation:
Answer:
In the ionic solid sodium chloride, there is one to one ratio of sodium ions to chloride ions
A student was asked to determine the activity of four unknown metals W,X,Y and, Z.
Answer:
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
The activity of four unknown metals based on their chemical changes is option B.
What is a chemical change?Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.
There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.
There are three types of chemical changes:
1) inorganic changes
2)organic changes
3) biochemical changes
During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.
Learn more about chemical change,here:
https://brainly.com/question/23693316
#SPJ3
The diagram shows the water cycle. At point 4, condensation is occurring. How is water changing?
A) Water vapor (gas) is becoming liquid.
B) Water is being stored in the atmosphere.
C) Liquid water in the atmosphere is becoming a gas.
D) Liquid water from the earth's surface is becoming water vapor (gas)
Answer:
water vapor (gas) is becoming liquid
in the structure of an atom why are protons present in the centre and are not pulled outside by the electrons as both are positively charged with some unit of charge?
Answer:
Electrons and protons are not positively charged
Explanation:
Neutrons are the only ones positively charged in the structure of an atom.... Also like charges repel which means a -ive and a - ive will repel when together
Science
How is the total magnification of a
cell calculated?
50 POINTS PLEASE HELP!
A gas diffuses 1/7 times faster than hydrogen gas (H2).
What is the molar mass of the gas?
100.10 g/mol
98.78 g/mol
86.68 g/mol
79.98 g/mol
Answer: The molar mass of the gas is 9.878 g/mol.
Explanation:
According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.
[tex]Rate = \frac{1}{\sqrt{M}}[/tex]
where,
M = molar mass of gas
As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.
[tex]\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\[/tex]
where,
[tex]M_{1}[/tex] = molar mass of hydrogen gas
[tex]M_{2}[/tex] = molar mass of another given gas
[tex]R_{1}[/tex] = rate of diffusion of hydrogen
[tex]R_{2}[/tex] = rate of diffusion of another given gas = [tex]\frac{1}{7}R_{1}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\\frac{R_{1}}{\frac{1}{7}R_{1}} = \sqrt{\frac{M_{2}}{2}}\\7 \times 1.414 = M_{2}\\M_{2} = 9.878 g/mol[/tex]
Thus, we can conclude that the molar mass of the gas is 9.878 g/mol.
Answer:
98.78 g/mol
Explanation:
Just took the test
How many joules of heat is needed when 5 g of water is heated from 25°C to 75°C?
Answer:
1045 J
Explanation:
By using the formula Eh= mass×specific heat capacity × change in tempreture
With it being a known fact that the specific heat capacity of water is 4.16g/j/°c
Name the layers of the atmosphere and one fact about each layer.
Imagine you had HCl with a concentration of exactly 0.10 mol/dm3. If 0.023 dm3 of a sodium hydroxide solution, NaOH (aq), could exactly neutralize 0.040 dm3 of the HCl solution, what is the concentration of the NaOH (aq)
Answer:
Explanation:
Step 1: Calculate the amount of sodium hydroxide in moles
Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3
Rearrange:
Concentration in mol/dm3 =
Amount of solutein mol = concentration in mol/dm3 × volume in dm3
Amount of sodium hydroxide = 0.100 × 0.0250
= 0.00250 mol
Step 2: Find the amount of hydrochloric acid in moles
The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
So the mole ratio NaOH:HCl is 1:1
Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl
Step 3: Calculate the concentration of hydrochloric acid in mol/dm3
Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3
Concentration in mol/dm3 =
Concentration in mol/dm3 =
= 0.125 mol/dm3
Step 4: Calculate the concentration of hydrochloric acid in g/dm3
Relative formula mass of HCl = 1 + 35.5 = 36.5
Mass = relative formula mass × amount
Mass of HCl = 36.5 × 0.125
= 4.56 g
So concentration = 4.56 g/dm3
Gather data: experiment with a variety of initial concentrations of no2 and n2o4. for each set of initial concentrations, use the gizmo to determine the equilibrium concentrations of each substance. in the last column, find kc for that trial. run three trials for each set of initial conditions.
Solution :
[tex]$H_2 +I_2\rightleftharpoons 2HI$[/tex]
Initial concentration Equilibrium concentration [tex]$K_c=\frac{[HI]^2}{[H_2][I_2]}$[/tex]
(mol/L) (mol/L)
[tex]$[H_2]$[/tex] [tex]$[I_2]$[/tex] [tex]$[HI]$[/tex] [tex]$[H_2]$[/tex] [tex]$[I_2]$[/tex] [tex]$[HI]$[/tex]
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.38 \times 10^{-2}$[/tex] 0 [tex]$1.14 \times10^{-2}$[/tex] [tex]$0.12 \times 10^{-2}$[/tex] [tex]$2.52 \times 10^{-2}$[/tex] 46.42
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.68 \times 10^{-2}$[/tex] 0 [tex]$0.92 \times10^{-2}$[/tex] [tex]$0.20 \times 10^{-2}$[/tex] [tex]$2.96 \times 10^{-2}$[/tex] 47.61
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.98 \times 10^{-2}$[/tex] 0 [tex]$0.77 \times10^{-2}$[/tex] [tex]$0.31 \times 10^{-2}$[/tex] [tex]$3.34 \times 10^{-2}$[/tex] 46.73
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.76 \times 10^{-2}$[/tex] 0 [tex]$0.92 \times10^{-2}$[/tex] [tex]$0.22 \times 10^{-2}$[/tex] [tex]$3.08 \times 10^{-2}$[/tex] 46.86
[tex]$0$[/tex] [tex]$0$[/tex] [tex]$3.04 \times 10^{-2}$[/tex] [tex]$0.345 \times10^{-2}$[/tex] [tex]$0.345 \times 10^{-2}$[/tex] [tex]$2.35 \times 10^{-2}$[/tex] 46.39
[tex]$0$[/tex] [tex]$0$[/tex] [tex]$7.58 \times 10^{-2}$[/tex] [tex]$0.86 \times10^{-2}$[/tex] [tex]$0.86 \times 10^{-2}$[/tex] [tex]$5.86 \times 10^{-2}$[/tex] 46.42
Average [tex]$K_c=46.738$[/tex]
HELP ASAPPP!!! ON EXAM!
The arrangement of electrons within an atom is called it's...
a
Electron Flow
b
Electron Configuration
c
Atomic Number
d
Ionization Energy
Answer:
The arrangement of electrons within an atom is called electron configuration
If I help you, will you help other people?
Actually "this is the worst question i've ever seen use the internet bud" why don't you do that.
22.4 liters of CO2 at STP, 0◦C and 1 atm,
contains how many molecules? (Assume CO2
is an ideal gas.)
Answer:
There are [tex]6.01\times 10^{23}[/tex] number of molecules.
Explanation:
Given that,
Volume, V = 22.4 L
Temperature, T = 0°C = 273.15 K
Pressure, P = 1 atm = 1.013 bar
We need to find the number of molecules. Let there are n number of molecules. We know that, ideal gas law is as follows :
[tex]PV=nRT\\\\n=\dfrac{PV}{RT}\\\\n=\dfrac{1.013\times 22.4}{0.08 314\times 273.15}[/tex]
n = 0.999 moles
No. of molecules,
[tex]N=n\times N_A\\\\=0.999\times 6.023\times 10^{23}\\\\N=6.01\times 10^{23}[/tex]
So, there are [tex]6.01\times 10^{23}[/tex] number of molecules.
How many moles of water can be produced with 4.3 moles of H2 and 5.6 moles of O2? Which reactant is limiting? How many moles of the excess reactant will be left after the reaction? 2 H2 + O2 2 H2O
Answer:
Hydrogen H₂ will be the limiting reagent.
The excess reactant that will be left after the reaction is 3.45 moles.
4.3 moles of water can be produced.
Explanation:
The balanced reation is:
2 H₂ + O₂ → 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
H₂: 2 moles O₂: 1 mole H₂O: 2 molesTo determine the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 1 mole of O₂ reacts with 2 moles of H₂, how much moles of H₂ will be needed if 5.6 moles of O₂ react?
[tex]moles of H_{2} =\frac{5.6 moles of O_{2} *2 mole of H_{2} }{1 mole of O_{2}}[/tex]
moles of H₂= 11.2 moles
But 11.2 moles of H₂ are not available, 4.3 moles are available. Since you have less moles than you need to react with 5.6 moles of O₂, hydrogen H₂ will be the limiting reagent and oxygen O₂ will be the excess reagent.
Then you can apply the following rules of three:
If by reaction stoichiometry 2 moles of H₂ react with 1 mole of O₂, 4.3 moles of H₂ will react with how many moles of O₂?[tex]moles of O_{2} =\frac{1 mole of O_{2} *4.3 mole of H_{2} }{2 mole of O_{2}}[/tex]
moles of O₂= 2.15 moles
The excess reactant that will be left after the reaction can be calculated as:
5.6 moles - 2.15 moles= 3.45 moles
The excess reactant that will be left after the reaction is 3.45 moles.
If by reaction stoichiometry 2 moles of H₂ produce 2 moles of H₂O, 4.3 moles of H₂ produce how many moles of H₂O?[tex]moles of H_{2}O =\frac{2 moles of H_{2}O *4.3 mole of H_{2} }{2 mole of H_{2}}[/tex]
moles of H₂O= 4.3 moles
4.3 moles of water can be produced.
5.) If 6 moles of Oxygen Gas (O2) are produced in the reaction below, how
many grams of Potassium Chloride (KCI) are also produced? *
2 KCIO3 → 2 KCI + 3 O2
Answer:
im really sorry but i dont no☹
Which of the following is NOT one of the three main global climate zones?
A. Tropical
B. Latitude
C. Polar
D.Temprate
6. The fusion of 4 H-1 nuclei to produce two positrons and one other nuclei.
Explanation:
Normally, fusion involves two heavy hydrogen nuclides but since we have 4 light hydrogen nuclides, two of which underwent positron emission, thus changing two protons into neutrons plus 2 positrons and 2 neutrinos. The resulting nucleus from this fusion reaction is an He-4 nucleus.
balance the following equations:
a. ____AgI + _____Na2S → _____Ag2S + _____NaI
b. ____Na3PO4 + ____HCl →_____NaCl + _____H3PO4
c. _____Ba3N2 + _____H2O →_____Ba(OH)2 + _____NH3
d. _____TiCl4 + _____H2O →_____TiO2 + _____HCl
e. _____CaCl2 + _____Na3PO4 →_____Ca3(PO4)2 + _____NaCl
Answer:
A. 2AgI + Na2S → Ag2S + 2NaI
B. Na3PO4 + 3HCl → 3NaCl + H3PO4
C. Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3
D. TiCl4 + 2H2O → TiO2 + 4HCl
E. 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl
Explanation:
Glucose is a compound made from three elements: carbon, oxygen, and hydrogen. For glucose to be broken down into these elements, it must undergo _____.
A. filtration or distillation
B. an irreversible physical change, such as tearing or slicing
C. a reversible physical change, such as boiling or melting
D. a chemical change
Answer:
D ) Chemical Change
Explanation:
help!!!!!!!!!!!!!!!!!!!!! i have less than 3 hours please help! image below!!!!
Answer:
friction
Explanation:
conduction doesn't really need much to start it. it basically has that reaction from the start so it's not conduction. Since heat is produced by friction in this situation it causes static to happen. so i think its friction
Help me plz plz bbbbb
Answer:
The respiratory system is the network of organs and tissues that help you breathe. basically your airways, lungs, and blood vessels so you quite literally need these to survive I mean your muscles need oxygen to function and your brain needs oxygen to function so without your respiratory system you wouldn't be able to move much and you would quickly pass out and die from the lack of oxygen to your brain there are other body processes that need oxygen as well but these are just two examples.
Explanation:
Answer:
Maybe it’s dark ??????????????
Explanation:
Hm
what were Lamarck's ideas about evolution and why were those ideas incorrect
What were Lamarck's ideas about evolution and Why were those ideas incorrect?
→ These and other examples show that Lamarck's theory does not explain how life formed and became the way it is. The other way that Lamarck's theory has been proven wrong is the study of genetics. Darwin knew that traits are passed on, but he never understood how they are passed on.
[tex]#CarryOnLearning[/tex]At 298 K, the rate constant for a reaction is 0.0346 s-1. What is the rate constant at 350K if the Ea = 50.2kJ/mol
Answer:
0.702 /s
Explanation:
Rate constant at [tex][298 \mathrm{~K}, \mathrm{~K}_{1}=3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]
Rate constant at [tex]350 \mathrm{~K}, \mathrm{~K}_{2}=?[/tex]
[tex]T_{1}=298 \mathrm{~K}[/tex]
[tex]T_{2}=350 \mathrm{~K}[/tex]
Activation energy, [tex]\mathrm{Ea}=50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}[/tex]
Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]
Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]
[tex]\ln \frac{\mathrm{K}_{2}}{\mathrm{~K}_{1}}=\frac{\mathrm{Ea}}{\mathrm{R}}\left[\frac{1}{\mathrm{~T}_{1}}-\frac{1}{\mathrm{~T}_{2}}\right][/tex]
Therefore,
[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{1}{298 \mathrm{~K}}-\frac{1}{350 \mathrm{~K}}\right][/tex]
[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{52 \mathrm{~K}}{298 \mathrm{~K} \times 350 \mathrm{~K}}\right][/tex]
[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=\mathrm{e}^{3.01}[/tex]
[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=20.3[/tex]
[tex]K_{2} &=20.3 \times 3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]
[tex]&=0.702 \mathrm{~s}^{-1}[/tex]
hence, the rate constant at [tex]350 \mathrm{~K} [/tex] is 0.702[tex]\mathrm{~s}^{-1}[/tex]
What is the specific heat capacity of silver metal if 110.00 g of the metal
absorbs 396 J of heat and the temperature rises 15.0°C ?
Answer:
"0.24 J/g.k" is the appropriate solution.
Explanation:
Mass of substance,
m = 110.00 g
Heat,
q = 396 J
Change in temperature,
ΔT = 15.0°C
Now,
The specific heat will be:
⇒ [tex]q=ms \Delta T[/tex]
On putting the given values, we get
⇒ [tex]396=110.00\times s\times 15.0[/tex]
⇒ [tex]396=s\times 1650[/tex]
⇒ [tex]s=\frac{396}{1650}[/tex]
⇒ [tex]=0.24 \ J/g.k[/tex]
The primary function of a chloroplast is to -
F . Convert food into energy a cell can use
G . Control the function of a cell and control genetic traits
H . Convert radiant energy into chemical energy through photosynthesis
J . Store water and nutrients
Please help!!!
balance
Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O
Equation balance:
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
2Al(OH)3+3H2SO4
H=12
SO4=3
O=6
Al=2
Al2(SO4)3+6H2O
H=12
SO4=3
O=6
Al=2
Un profesor desea preparar una disolución de agua oxigenada al 20%v/v y dispone solamente de 50 cm3 h2o2 ¿qué volumen d disolución deberá preparar? Con procedimiento
Answer:
250cm³ de disolución se deben preparar
Explanation:
El porcentaje volumen volumen (%v/v) se define como el volumen de soluto -En este caso, H2O2- en 100cm³ de disolución.
Se desea preparar una solución que contenga 20cm³ de H2O2 por cada 100cm³
Como solamente se cuenta con 50cm³ de H2O2, el volumen que se debe preparar es:
50cm³ H2O2 * (100cm³ Disolución / 20cm³ H2O2) =
250cm³ de disolución se deben prepararCan you pls answer This question
Answer:
a) pentane
b) 1,3-dimethyl butane
c) 3,4-diethyl-5-methlyl heptane
d) 1,3,5-triethyl-2,4,6-trimethyl cyclohexane
Explanation:
The essence of IUPAC nomenclature is to provide a generally accepted nomenclature for chemical compounds which enables the structure of a compound to be drawn from its name without ambiguity.
In order to name straight chain organic compounds, we have to identify the parent chain and then give numbers to the substituents or locants such that they have the lowest possible numbers in alphabetical order.
The correct names of the organic compounds in the question are;
a) pentane
b) 1,3-dimethyl butane
c) 3,4-diethyl-5-methlyl heptane
d) 1,3,5-triethyl-2,4,6-trimethyl cyclohexane
A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?
V2 = 276 ml
Explanation:
Given:
V1 = 250 ml V2 = ?
T1 = 293K. T2 = 324K
Here, we use Charles's law:
V1/T1 = V2/T2
Solving for P2, we get
V2 = (T2/T1)V1
= (324K/293K)(250 ml)
= 276 ml