26. Which member of the carbon family is a non-metal?

Please help

Answer: 0 j

Explanation:

It is given that,

Mass of the box, m = 10 kg

Force with which the box is pulled, F = 50 N

It is moved a distance of 4 m

Force of friction acting on the box, f = 20 N

We need to find the initial kinetic energy the box have. It is clear that the box is at rest initially. As there is no motion in the box at that time. The formula for the kinetic energy of the box is given by :

As v = 0

So, the initial kinetic energy of the box is 0. Hence, this is the required solution.  

Answer:

T = 2.83701481512 seconds

Explanation:

Hi!

The formula that you will want to use to solve this question is:

[tex]T = 2\pi *\sqrt{\frac{L}{g} }[/tex]

T--> period

L --> length of the pendulum

g --> acceleration due to gravity (9.8m/s^2)

since we know that the mass of the bob at the end of the pendulum does not affect the period of the pendulum, we can go ahead and ignore that bit of information (unless, of course, the weight causes the pendulum to stretch)

so now we can plug in our given info into the formula above and solve!

T = 2*pi * sqrt(2/9.8)

T = 2.83701481512 seconds

*Note*

- I used 3.14 to pi, if you need to use a different value for pi (a longer version, etc) your answer will be slightly different

I hope this helped!

Answer: I think its D

Explanation: Hope this was helpful...

Answer:

Explanation:

this is the answer

Answer:

1.true

2true

3.false

Explanation:

espero que te ayude

Answer:

It is because one cannot know exactly the position of the electron within the atom.

One formulation of Heisenberg's Uncertainty Principle tells us that one cannot know simultaneously  the position and momentum of the electron, so one cannot specify exactly either coordinate because the other would be infinite.

Bohr specified the most probable position of the electron at its lowest energy level in hydrogen and the product of the two would be about the Heisenberg value.  

Answer:

0.116 N/m

Explanation:

Since the net force acting on the ring must be greater than 2.00 × 10⁻² N, and the surface tension T = F/L where F = net force = 2.00 × 10⁻² N and L = circumference of ring = 2πr where r = radius of ring = 2.75 cm = 2.75 × 10⁻² m.

So, T = F/L

= F/2πr

= 2.00 × 10⁻² N ÷ 2π(2.75 × 10⁻² m)

= 1/2.75π  N/m

= 1/8.64 N/m

= 0.116 N/m

Answer:d

Explanation:

Given

Initially, the ice cube is floating over the water

When the cube is pressed to touch the bottom, it is submerged fully

Therefore more buoyant force is acting on it

At first, a part of the volume is submerged in the water, so the buoyant force is less, but as the entire cube is immersed in the water, the buoyant force increases.

If you drag a bag across floor, you are experiencing a friction force

if you throw a paper or feather up, it floats side ways slowly. It is called air Resistance.

if you push or pull a Door, it is Normal force.

I hope this helped!

have an amazing Day!!

Answer:

C

Explanation:

trust me

D. Fixed position ,mean position , Equilibrium position.

Wave motion is the transfer of energy and momentum from one point of the medium to another point of the medium without actual transport of matter between two points.

The particles of the medium vibrate about their equilibrium position in a direction parallel to the direction of propagation of the wave is called a longitudinal waves.

Characteristics of Wave Motion

In wave motion, the disturbance travels through the medium due to repeated periodic oscillations of the particles of the medium about their mean position (or) Equilibrium position.

Energy and momentum are transferred from one point to another without any actual transfer of the particles of the medium.

There is a regular phase difference between the particles of the medium because each particle receives disturbance little later than its preceding particle.

Therefore,

In a wave, each particle of the medium vibrates, or oscillates, around a fixed position.

Learn more about wave motion here:

https://brainly.com/question/12512349

#SPJ2

Explanation:

resistance of wire can be determined by this equation

R = Rho . L / A

L = the length of wire

A = the Area, A = πr²

Rho = density of resictance

we can do some rational

R1/R2 = ( Rho L1/A1) / (Rho L2/A2)

L2 is the condition when the length is doubled and

L2 = 2 x L

A2 is the condition when the diameter is doubled

A2 = 4A1

R/R2 = (L1/A1)/(L2/A2)

R/R2 = (L/A) / (2L/4A)

R/R2 = 1 / ½

R2 = ½ R.

then we use formula of Voltage

V = I R

1st condition

V = 0.3 R

2nd condition ( V is constant)

V = I2 R2

0.3 R = I2 x ½R

i2 = 0.3/ ½

i2 = 0.6 Ampere

Answer:

6.77 minutes

Explanation:

172 degree - 78 degree = (185 degree - 78 degree)e−2 k

=> 94 = 107

e−2 k => 94 ÷ 107

k => ln (94÷107) / 2

147 - 78 = (185 - 78)e ^[ln (94÷107) / 2]

=> 69 = 107 e^ [ln (94÷107) / 2]

e^[ln (94÷107) / 2] =69 ÷ 107

=> t = [ln (69 ÷ 107)] ÷ [ln (94÷107) / 2]

t=> -0.4387 ÷ -0.0648

t => 6.77 minutes.

Therefore, the final answer to the question is 6.77 minutes.

Answer:

8512 N

Explanation:

From the work energy theorem we know that: The net work done on a particle equals the change in the particles kinetic energy:

[tex]W=\Delta K=K_{f}-K_{i} \\ \\qquad \begin{array}{r} W=F \cdot d, \Delta K=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2} \\ F \cdot d=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2}[/tex]

Where:

-W is the work done by the force.

- F is the force actin on the.

- d is the distance travelled.

- m is the mass of the car.

- [tex]v_{f}, v_{i}[/tex] are the final and the initial velocity of the car

[tex]K_{f}, K_{i}[/tex] are the final and the kinetic energy of the car.

Givens: [tex]m=830 \mathrm{~kg}, v_{i}=2 \mathrm{~m} / \mathrm{s}, v_{f}=0 \mathrm{~km} / \mathrm{h}, d=0.195 \mathrm{~m}[/tex]

Plugging known information to get:

[tex]F \cdot d &=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2} \\ F &=\frac{\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2}}{d} \\ &=\frac{0-\frac{1}{2} \times 830 \times 2^{2}}{0.195} \\ &=8.512 \times 10^{3} \\ F &=8.512 \times 10^{3} \mathrm{~N}[/tex]

Considering both boxes as one body, it would have a total mass of 4.0 kg. By Newton's second law, the 32 N force applies an acceleration a such that

∑ F = 32 N = (4.0 kg) a   →   a = 8.0 m/s²

and both boxes share this acceleration. (There is no friction, so the given force is the only one involved in the direction of the boxes' motion.)

Now consider just the smaller box. It is feeling the effect of the 32 N push in one direction and, as it comes into contact with the larger box, a normal force that points in the opposite direction. Let n be the magnitude of this normal force; this is what you want to find. By Newton's second law,

∑ F = 32 N - n = (1.0 kg) (8.0 m/s²)

n = 32 N - 8.0 N

n = 24 N

Just to make sure that this is consistent: by Newton's third law, the larger box feels the same force but pointing in the opposite direction. On the smaller box, n opposes the pushing force, so points backward. So from the larger box's perspective, n acts on it in the forward direction. This is the only force acting on the larger box, so Newton's second law gives

∑ F = 24 N = (3.0 kg) (8.0 m/s²)

Answer:

5.4 m/s

Explanation:

Given that

Mass of the safe, m1 = 1000 kg

Distance to lower the safe, d = 3 m

Mass of furniture, m2 = 500 kg.

Speed of the safe, v = ?

To get the final speed by the time that the safe hits the truck, we first find its acceleration.

The total mass of the system is M = 1000 + 500 kg = 1500 kg

One of the forces acting on the system is that of gravity, and it acts on the safe friction acting on the furniture. Using the formula, we have

= m1*g - mu*m2g

= 1000 * 9.81 - 0.5 * 500 * 9.81

= 7357.5 N

From this calculated weight, we find the acceleration.

Acceleration, a = F/m

Acceleration, a = 7357.5 / 1500

Acceleration, a = 4.905 m/s²

From the question, we know that the Initial speed = 0 m/s

So, employing the use of one of the equations of motion, we have

v² - u² = 2aS

v² - 0 = 2 * 4.905 * 3

v² = 29.43

v = √29.43

v = 5.4 m/s

Answer:

b. the cylinder

Explanation:

From the information given:

We understood that the mass of the sphere, cylinder, and rod length is the same with the same angular speed.

Taking their moments:

For the solid sphere; [tex]\text{The moment of inertia :}[/tex] [tex]I_s[/tex] = [tex]\dfrac{2}{5} \times m \times r^2[/tex]

The moment of inertia of the cylinder, [tex]I_c = 0.5\times m \times r^2[/tex]

The moment of inertia of rod, [tex]I_r =\dfrac{ m * r^2 }{12}[/tex]

The rotational kinetic energy is directly corresponding to the moment of inertia.

Thus, the cylinder has the greatest rotational kinetic energy.

Answer:

E₀ = 2.0*10⁻¹¹ J = 0.2 pJ

Ef = 3.0*10⁻¹¹ J = 0.3 pJ

Explanation:

      [tex]E = \frac{1}{2} * C * V^{2} (1)[/tex]

       [tex]C = \frac{\epsilon_{o}*A}{d} (2)[/tex]

       [tex]E_{o} = \frac{1}{2} * C_{o} * V_{o} ^{2} = \frac{1}{2} * 1.77*10^{-13}F*(1.5V)^{2} = 0.2 pJ (6)[/tex]

       [tex]E_{f} = \frac{1}{2} * C_{f} * V_{f} ^{2} = \frac{1}{2} * 1.18*10^{-13}F*(2.25V)^{2} = 0.3 pJ (9)[/tex]

Answer:

C

Explanation:

Refers to the attachment for the answer.

Let us assume that the object of mass m is kept on the Inclined plane.

Now, there will act one force called as Component of the Weight along the Incline which is given by the Relation,

mgsinθ,

where θ is the angle which the incline makes with the surface or Angle of the Incline.

Now, If there will be no friction and the object is moving along the incline

Force = mgsinθ

⇒ ma = mgsinθ

∴ a = gsinθ

This case is valid when the angle of the Incline is greater than the angle of repose, which means the object is moving with no cause or acing of the force.

But sometimes when the object does not move without the action of force, I mean that the angle of repose is greater than the angle of the incline, then we need to apply the force so that the object can move then,

Force applied = mgsinθ

∴ a = gsinθ

It will change the cases when friction is involved.

Now, For velocity, It can be found by using the equation of Motions. Time, Distance or initial velocity, etc must be given if the question will be asked related to the velocity. So by using them, you can find that.

Answer:

B

Explanation:

Because blocks 2 and 3 have sides with unequal forces while block 1 doesnt. Plz drop a follow if this helps! ❤

Answer:

lightning is a sudden electrostatic discharge during an electrical storm. This discharge allows charged regions in the atmosphere to temporarily equalize themselves, when they strike an object on the ground.

Answer:

You can see lightning before u hear it.

light travels faster than soun

Answer:

Objects between the source and observer produce possible shadows known as the umbra and the penumbra.

The umbra is a totally shadowed area, no light travels directly from the source to the observer.

The penumbra is a partially shadowed are where some of the source light travels directly to the observer an some of the source light is blocked from the observer (the object blocking the light is not a point object).

The question apparently refers to the differences seen by the observers.

Answer: [tex]0.985\times 10^{-4}\ T[/tex]

Explanation:

Given

Electron is accelerated 3.5 kV potential difference

Distance between plates d=29 mm

The potential difference between plates is V=100 V

here, the kinetic energy of an electron is acquired through a potential difference of 3.5 kV

[tex]\Rightarrow \dfrac{1}{2}m_ev^2=e\times 3.5\times 10^3\\\\\Rightarrow v=\sqrt{\dfrac{2\times 3.5\times 10^3e}{m_e}}=\sqrt{\dfrac{7\times 10^3\times 1.6\times 10^{-19}}{9.1\times 10^{-31}}}\\\\\Rightarrow v=\sqrt{1.23\times 10^{15}}=3.5\times 10^7\ m/s[/tex]

To move in a straight line Force due to magnetic field must be balanced by force due to charge

[tex]\Rightarrow F_B=F_q\\\\\Rightarrow evB=eE\\\\\Rightarrow B=\dfrac{E}{v}\\\\\Rightarrow B=\dfrac{\frac{V}{d}}{3.5\times 10^7}=\dfrac{\frac{100}{0.029}}{3.5\times 10^7}\\\\\Rightarrow B=\dfrac{3.448\times 10^3}{3.5\times 10^7}=0.985\times 10^{-4}\ T[/tex]

Answer:

τ = RC = 2.17 s

Explanation:

       [tex]V_{C} =V_{o} * e^{-t/RC} (1)[/tex]

       [tex]V_{C} = 1.00 V\\V_{o} = 100V\\t = 10.0 s[/tex]

      [tex]\frac{1.00V}{100 V} = e^{-10s/RC} (2)[/tex]

       [tex]R*C= \frac{-10s}{ln 0.01} = 2.17s (3)[/tex]

Explanation:

c willl fall fast then a and b

Answer:

true statements are: A and C

Explanation:

In geometric optics, lenses are one of the most used elements, in general the curved surface, if they are convex, form real images, that is, the light rays have to converge at a point.

Concave lenses tend to create virtual images or I know that the extensions of the rays are what form the image.

The flat surface does not create changes in the image.

With these characteristics, let's examine the different true statements are: A and C

A) the rays diverge,

c) the rays parallel to the diverges their extensions are at a point on the same side of the lens this point is called focal length.

Answer:

A I hope its not wrong I hope u do good

Answer:

The correct solution is:

(a) [tex]1.375\times 10^{-2} \ J[/tex]

(b) [tex]4.43\times 10^{-3} \ C[/tex]

(c) [tex]1.42\times 10^{-3} \ F[/tex]

(d) [tex]178.57 \ \Omega[/tex]

Explanation:

The given values are:

Effective duration of the flash,

ζ = 0.25 s

Average power,

[tex]P_{avg}=55 \ mW[/tex]

       [tex]=55\times 10^{-3} \ W[/tex]

Average voltage,

[tex]V_{avg}=3.1 \ V[/tex]

Now,

(a)

⇒ [tex]E=P_{avg}\times \zeta[/tex]

On substituting the values, we get

⇒     [tex]=55\times 10^{-3}\times 0.25[/tex]

⇒     [tex]=1.375\times 10^{-2} \ J[/tex]

(b)

⇒ [tex]E=Q\times V_{avg}[/tex]

then,

⇒ [tex]Q=\frac{E}{V_{avg}}[/tex]

On substituting the values, we get

⇒     [tex]=\frac{1.375\times 10^{-2}}{3.1}[/tex]

⇒     [tex]=4.43\times 10^{-3} \ C[/tex]

(c)

⇒ [tex]C=\frac{Q}{V}[/tex]

⇒     [tex]=\frac{4.43\times 10^{-3}}{3.1}[/tex]

⇒     [tex]=1.42\times 10^{-3} \ F[/tex]

(d)

As we know,

⇒ [tex]R=\frac{1}{4C}[/tex]

⇒     [tex]=\frac{1}{4\times 1.42\times 10^{-3}}[/tex]

⇒     [tex]=\frac{1000}{5.6}[/tex]

⇒     [tex]=178.57 \ \Omega[/tex]