250 mL of water is collected during a combustion reaction. The temperature in the
room is 23 °C and the pressure is 105 kPa. How many moles of water was collected?
(please show work)

Answer:

high use of mineral resources

Explanation:

brainliest pls

Answer: Anode: [tex]Pb+SO_4^{2-}\rightarrow PbSO_4+2e^-[/tex]

Cathode: [tex]PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O[/tex]

Overall cell reaction : [tex]Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O[/tex]

Explanation:

Lead storage battery is a secondary cell used in automobiles and invertors. The anode is made up of lead and undergoes oxidation during discharging and cathode is made up of lead oxide and acts as cathode during discharging. The electrolyte used is dilute .

Lead storage battery acts as electrochemical cell while discharging.

Discharging reaction for  Anode:

Discharging reaction for  Cathode: [tex]PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O[/tex]

Overall cell reaction : [tex]Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O[/tex]

A lead storage battery is an energy storage device. At the anode lead and sulfate ion reacts to produce Lead(II) sulfate and release two electrons.

In secondary cells or the recharge-discharge cells during recharge, the positive electrode is the anode, while during discharge cathode is the positive electrode.

The anode (lead) of the cell undergoes an oxidation reaction during the discharge, whereas the lead oxide or the cathode undergoes reduction.

The discharging reaction at the anode of the cell is given as,

[tex]\rm Pb + SO_{4}^{2-} \rightarrow PbSO_{4} + 2e^{-}[/tex]

The discharging reaction at the cathode of the cell is given as,

[tex]\rm PbO_{2} + 4H^{+} + SO_{4}^{2-} + 2 e^{-} \rightarrow PbSO_{4} + 2H_{2}O[/tex]

The overall cell reaction is given as,

[tex]\rm Pb + 2SO_{4}^{2-} + PbO_{2} + 4H^{+} \rightarrow 2PbSO_{4} + 2H_{2}O[/tex]

Therefore, the gain and loss of electrons are represented at the cathode and the anode of the cell.

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Answer: The standard state refers to 1 atm and [tex]25^{o}C[/tex].

Explanation:

It is known that a chemical/substance can either be present in a solid, liquid or gaseous state.

So, when the phase of a substance like solid, liquid or gas is present at 1 atmosphere pressure and at a temperature of [tex]25^{o}C[/tex] then it known as standard state of substance.

Thus, we can conclude that standard state refers to 1 atm and [tex]25^{o}C[/tex].

Answer:

Hydroxylamine and pyridine

Explanation:

Just did it

Answer: Salt is an ionic compound.

Explanation:

A compound formed by transfer of electrons from one atom to another is called an ionic compound.

For example, chemical formula of salt is NaCl (also called table salt).

Salt is formed when sodium (atomic no. 11) donates its one valence electron to chlorine (atomic no. 17). As a result, sodium ion and chlorine ion chemically combine together and form the compound NaCl.

Thus, we can conclude that salt is an ionic compound.

Answer: did you ever find the answer? I need part E, F, and G if you found them please!!!!! I’m begging, my school year ends in 30 minutes and I gotta get this submitted!!!!!!

Explanation:

Explanation:

As I think Option C is correct i.e. NH4+.

Answer:b

Explanation:

65.38 u (or g)

I just searched it up

Answer:

D Fracture

Explanation:

jus took the test

Answer: Mass is converted to the energy binding a nucleus together.

Explanation: a p e x

Mass is converted to the energy binding a nucleus together cause a mass defect.Hence , Option (C) is correct.

The actual atomic mass is less than the predicted mass calculated by adding the masses of nucleons.

This additional mass is accounted for by binding energy that is released when a nucleus is formed.

When a nucleus is formed, some of the mass is converted to energy and this results in the mass defect.

Therefore, Mass is converted to the energy binding a nucleus together cause a mass defect. Hence , Option (C) is correct.

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Answer:

Taxonomy

Explanation:

Answer:

The value becomes 0.0821 L-atm/K⁻¹-mol⁻¹.

Explanation:

The value of gas constant is 0.0821.

We know that, the ideal gas law is as follows :

[tex]PV=nRT\\\\R=\dfrac{PV}{nT}[/tex]

Where

P is pressure

V is volume

T is temperature

In order to use the Ideal Gas Constant of 0.0821, the units are follows :

Volume = Litre (L)

Pressure = atm

Amount = mol⁻¹

Temperature = K⁻¹

So, the value becomes 0.0821 L-atm/K⁻¹-mol⁻¹.

Answer:

1 - NO2 at 339 K

2 - Ne at 371 K

3 - H2 at 371 K

4 - H2 at 425 K

Explanation:

Kinetic Energy is directly related to temperature; the higher the temperature the higher the kinetic energy. Kinetic energy is also equal to 12m⋅v2, so if we want a high velocity we want high temp and low mass. So let's list out approximate masses:

m(H2)≈2

m(NO2)≈46

m(Ne)≈20

So we have NO2 at 339 K, the lowest temperature out of the mix, and the highest mass out of the mix, so this is moving the slowest.

In contrast, we have H2 at 425 K, the highest temperature out of the mix, and the lowest mass out of the mix, so this is moving the fastest.

Now we have Ne and H2 at 371 K, since they are at the same temperature they have the same kinetic energy. But H2 is lighter than Ne so it must be faster. To quantify this mathematically, let's assume (this is wrong but just as an assumption for an example) KE at 371 K is 100:

100=12⋅m⋅v2

200=m⋅v2

√200m=v

So H2 is about v=10 and Ne is about v=√10≈3

So the order to recap is:

1 - NO2 at 339 K

2 - Ne at 371 K

3 - H2 at 371 K

4 - H2 at 425 K

Hope that makes it clearer!

Explanation:

Description. Regardless of the type of hydrocarbon, combustion with oxygen produces 3 products: carbon dioxide, water and heat, as shown in the general reaction below.

Answer: There are [tex]145 \times 10^{23}[/tex] atoms in 24 moles of Fe.

Explanation:

According to the mole concept, 1 mole of a substance contains [tex]6.022 \times 10^{23}[/tex] atoms.

Therefore, atoms present in 24 moles of Fe are calculated as follows.

[tex]24 mol \times 6.022 \times 10^{23} atoms/mol\\= 144.52 \times 10^{23} atoms\\or, 145 \times 10^{23} atoms[/tex]

Thus, we can conclude that there are [tex]145 \times 10^{23}[/tex] atoms in 24 moles of Fe.

Answer:

p o e t i c o

Explanation:

no lo entenderias

Answer:

B

Explanation:

Answer: It is :B:

Explanation: also sub to technoblade

Answer:

1600J

Explanation:

1 mole of oxygen gas (O2) has a mass of 32g i.e. the molar mass = 32g/mol

Kinetic energy (K.E) = ½ × m × v²

Where;

m = mass (g)

v = speed or velocity (m/s)

From the information given in this question;

m = 32g

V = 10m/s²

K.E = ½ × 32 × 10²

K.E = 16 × 100

K.E = 1600J

Answer: An object's gravitational force depends primarily on the object's mass.

Explanation:

According to the Universal law of gravitation, every object whether is it is having large r small mass tends to exert a force on every other object, therefore this force is known as gravitational force.

Formula to calculate gravitational force is as follows.

[tex]F = \frac{G \times m_{1} \times m_{2}}{r^{2}}[/tex]

where,

F = Gravitational force

G = Gravitational constant = [tex]6.674 \times 10^{-11} m^{3}/kg s^{2}[/tex]

[tex]m_{1}[/tex] = mass of object 1

[tex]m_{2}[/tex] = mass of object 2

r = distance between the centers of the objects

Therefore, it means that gravitational force of an object primarily depends on an object's mass.

Thus, we can conclude that an object's gravitational force depends primarily on the object's mass.

Answer:

A ⟶ A⁺ + e⁻

AH + B ⟶ A + BH

A + BO ⟶ AO + B

A + e⁻ ⟶ A⁻

A + BH ⟶ AH + B

AO + B ⟶ A + BO

-TheUnknownScientist

Answer: The concentration of [tex]NO_{2}[/tex] in the given equilibrium mixture is 0.0545 M.

Explanation:

The ratio of concentration of products and reactants raised to the power of their coefficients is called equilibrium constant. The symbol used to denote equilibrium constant is [tex]K_{eq}[/tex].

As the given reaction equation is as follows.

[tex]2NO_{2}(g) \rightleftharpoons N_{2}O_{4}(g)[/tex]

The expression for equilibrium constant of this reaction is as follows.

[tex]K_{eq} = \frac{[N_{2}O_{4}]}{[NO_{2}]^{2}}[/tex]

Now, substitute the given values into above formula as follows.

[tex]K_{eq} = \frac{[N_{2}O_{4}]}{[NO_{2}]^{2}}\\67.3 = \frac{(0.2)}{[NO_{2}]^{2}}\\So, [NO] = \sqrt{\frac{0.2}{67.3}}\\= 0.0545 M[/tex]

Thus, we can conclude that the concentration of [tex]NO_{2}[/tex] in the given equilibrium mixture is 0.0545 M.

Answer:

We often want to decrease the rates of certain reactions rather than speeding them up. For example, to prolong the shelf lives of certain foods, the chemical reactions by which they spoil must be slowed down.

Answer:

W = 615.91 kJ

Explanation:

We need to use the following expression:

W = ΔG° * mol   (1)

But in order to determine the ΔG° we need the following expression:

ΔG° = -n * F * E°   (2)

Where F is a constant and is 96,500 J/V mol

n is the number of transferred electrons in the reaction. As we are passing from Al to Al³⁺ we can say that the number of electrons are 3.

Finally to get the moles, we need the the atomic weight of aluminum which is 26.98 g/mol, so the moles:

moles = m/MM   (3)

Let's calculate the moles of aluminum:

moles = 50 / 26.98 = 1.85 moles of aluminum

Now let's calculate the gibbs energy using (2):

ΔG° = -3 * 96,500 * 1.15

ΔG° = -332,925 J or simply -332.925 kJ/mol

Finally, using (1) we can determine the work done:

W = 332.925 * 1.85

Hope this helps

The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ

The cell potential, Ecell, is the measure of the potential difference between two half cells in an electrochemical cell.

Expression for work done ;

W = ΔG° x mol   (1)

But, to determine the ΔG°

ΔG° = -n x F x E°   (2)

Where,

(As there is variation from Al to Al³⁺ the change in number of electrons are 3)

To get the moles,

moles = m/MM  (3)

moles = 50 / 26.98 = 1.85 moles of aluminum

Now,

ΔG° = -3 x 96,500 x 1.15

ΔG° = -332,925 J  

       = -332.925 kJ/mol

Now, using (1) we can determine the work done:

W = 332.925 x 1.85

W = 615.91 kJ

Hence, The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ

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Answer: I believe the answer is d)  the rock crumbles at an ocean ridges

Explanation: