25 POINTS what is the domain of the quadratic function graphed below?

a. all real numbers
b. x>=2
c. x>3
d. y=(0,8)

Answer:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step explanation:

Answer: 2-

Step-by-step explanation:

Answer:

4:9 is the ratio

Step-by-step explanation:

4 in Texas and 9 in Michigan

Answer:

20m-3

Step-by-step explanation: hope that helps :)

2+29m−9m−5

=2+29m+−9m+−5

Combine Like Terms:

=2+29m+−9m+−5

=(29m+−9m)+(2+−5)

=20m+−3

Given :

Each pitcher of power smoothie that Ginger makes has 2 scoops of pineapple, 4 scoops of strawberries, 1 scoop of spinach, and 1 scoop of kale.

To Find :

If Ginger makes 6 pitchers of power smoothies, how many scoops will she use in all.

Solution :

Let, Ginger makes x pitchers of power smoothies :

[tex]Total \ scoops = 2x+4x+x+x+6x[/tex]

Now, it is given that Ginger makes 6 pitchers of power smoothies.

Total scoops are :

[tex]T=2(6)+4(6)+6+6+6(6)\\\\T=84\ scoops[/tex]

Therefore, number of scoops Ginger used is 84.

Hence, this is the required solution.

Answer:

nothing at all.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

The same thing would happen over and over again.

To write fractions with denominators of 10 and 100 as decimals, the position of the zero to the right of the number in the numerator is shifted a number of places left depending on the power of 10 in the denominator

Reason:

Examples of fractions that has 10 and 100 as denominators are;

[tex]\dfrac{9}{10}, \ \dfrac{15}{100}, \ \dfrac{5}{100}[/tex]

The steps to express the above fractions as decimals are;

Place a decimal point to the right to the number in the numerator as follows;

[tex]\dfrac{9.}{10}, \ \dfrac{15.}{100}, \ \dfrac{5.}{100}[/tex]

Move the decimal point to the left a number of places equal to the number of zeros in the denominator

Where the denominator is a 10, the decimal point is moved left one place and place a zero to the left of the decimal point

Where the denominator is a 100, the decimal point is moved left two places, as follows;

[tex]\dfrac{9.}{10} = 0.9, \ \dfrac{15.}{100} = 0.15, \ \dfrac{5.}{100}= 0.05[/tex]

Therefore, the decimal point is moved left depending on the number of zeros or the power of 10 in the denominator

100 = 10² in the denominator (move the decimal point two places left)

10 = 10¹ in the denominator (move the decimal point one place left)

Learn more here:

https://brainly.com/question/3425446

Answer:

Let's take this step by step:

2x+b=w

2x+b-b=w-b (the basics to what we are trying to do is to get x alone so that it equals whatever is on the other side of the equation.)

2x=w-b(now that we got rid of the b on the left side of the equation by canceling it out, we have to subtract by b on the other side of the equation as well)

2x divided by 2=w-b/2 (For our final step x is being mulitplied by 2 so what we can do to get x alone is canel out the multiplication by dividing by 2. What this does is it leaves x alone showing us what x equals)

x=w-b/2

Step-by-step explanation:

[tex]2(3y - 8) = 8 \: \: so \: \: 6y - 16 = 8 \: \: so \: \: 6y = 24 \: \: finaly \: > > y = 4[/tex]

Step-by-step explanation:

could the conditional statement be written in another way

Answer:

1. 3 hours

2. i cant figure this one out

Step-by-step explanation:

Answer:

Haha

Step-by-step explanation:

ghgewucjbauierfyucierh kjaluchliaucwa bb

wrgwrgweg

ttrtrtttgb

trbtgrbgttr

bheetbg

etbnhtehg

bertertgetfhjgeyfguiwrehodvqeiir

rgeyshudfvr8ov

Answer:

The correct answer would be 18 which means that the decimal is in the wrong spot.

Step-by-step explanation:

Answer:

yah for some reason i cant find it

Answer:

sssssssssssssss

Step-by-step explanation:

Answer:

8 lol

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Add from left to right 2+2=4 and then add 4+4 and you get 8

Answer: 7.07 m/s

Step-by-step explanation:

I took the quiz and that was the correct answer 5 is wrong

The speed of the dog at half of its kinetic energy is 7.07 m/s. The correct option is (B).

When two quantities have some dependence in their values they can be said proportional to each other.

It can be of two types such as direct and indirect.

The direct proportionality means the values of both the quantities are increasing or decreasing at the same time while the indirect proportionality implies value of one quantity is increasing while the other is decreasing.

Given that,

The present speed of the dog is 10 m/s.

Suppose the mass of the dog be m kg.

Since, the kinetic energy of an object is given as K = 1/2mv².

As per the question, the following expression can be written,

Initial energy, K₁ = 1/2m × 10²

                           = 50m

Final energy, K₂ = K₁/2

                           = 50m/2

                           = 25m

Using the expression for kinetic energy,

1/2mv² = 25m

=> v² = 50

=> v = √50

       = 7.07

Hence, the speed of the dog when its kinetic energy is reduced to half is 7.07 m/s.

To know more about proportionality click on,

brainly.com/question/22620356

#SPJ2

y-6 =4 (1-4)

y-6=-12

y=-6

Answer:y= -6

Answer:

The answer is 1.788

Step-by-step explanation:

The question is incomplete:

The sum of the average amounts spent for veterinary expenses for​ dogs, cats, and birds in a recent year was ​$293 The average expenditure per dog exceeded the sum of the averages for cats and birds by ​$113. The amount spent per cat was 9 times the amount spent per bird. Find the average amount spent on each type of animal.

Answer:

The average amount spent in dogs is $203, in cats is $81 and in birds is $9.

Step-by-step explanation:

From the information given, you can write the following equations:

x+y+z=293 (1)

x-y-z=113 (2)

y=9z (3)

You can replace (3) in (1) and (2):

x+9z+z=293

x+10z=293 (4)

x-9z-z=113

x-10z=113 (5)

Now, you have the following equations:

x+10z=293 (4)

x-10z=113 (5)

Then, you can isolate x in (4):

x=293-10z (6)

Next, you can replace (6) in (5):

293-10z-10z=113

293-20z=113

293-113=20z

180=20z

z=180/20

z=9

Now, you can replace the value of z in (6) to find x:

x=293-10z

x=293-10(9)

x=293-90

x=203

Finally, you can replace the value z in (3) to find y:

y=9*(9)

y=81

According to this, the answer is that the average amount spent in dogs is $203, in cats is $81 and in birds is $9.

Answer:

B

Step-by-step explanation:

Answer:

I think it is B :D

Step-by-step explanation:

Answer:

48

Step-by-step explanation:

1 b = 2p

24 b = 48  p

award brainliest if this helped! :)

Answer:

2744

Step-by-step explanation:

Let Al had x pennies initially.

Al agreed to give 3/7 of his pennies to Bev if she would give 3/7 of what she got from Al to Carl and if Carl in turn would give 3/7 of what he got from Bev to Dani.

So, as per the given condition,

The number of Pennies received by Ben from Al [tex]= \frac{3}{7} x[/tex]

The number of Pennies received by Carl from Bev

[tex]=\frac{3}{7} \times \frac{3}{7} x=\frac{9}{49}x[/tex]

The number of Pennies received by Dani from Carl

[tex]= \frac{3}{7}\times \frac{9}{49}x=\frac{27}{343} x[/tex]

Now, as Dani received 216 Pennies, so

[tex]\frac{27}{343} x =216[/tex]

[tex]\Rightarrow \frac{216\times 343}{27}=2744.[/tex]

Hence, initially, Al had 2744 Pennies.

Answer:

4*(-5) = -20

Step-by-step explanation:

Multiply the amount of book Robin read by 1/2.

3/4 x 1/2 = 3/8

Mark read 3/8 of the book.

Answer:

Explained below.

Step-by-step explanation:

Let X = number of trucks that will be going over the speed limit on I-77 South between Dobson and Elkin.

The probability of X is, p = 0.75.

A random sample of n = 5 trucks are observed on this stretch of I-77.

The random variable X follows a binomial distribution with parameters n = 5 and p = 0.75.

(a)

Compute the mean as follows:

[tex]\mu=n\times p=5\times 0.75=3.75[/tex]

The mean of this probability distribution is 3.75.

(b)

The mean of 3.75 implies that on average 3.75 trucks that will be going over the speed limit on I-77 South between Dobson and Elkin.

(c)

Compute the standard deviation as follows:

[tex]\sigma=\sqrt{np(1-p)}=\sqrt{5\times 0.75\times (1-0.75)}=0.968[/tex]

Thus, the standard deviation of this probability distribution is 0.97.

(d)

Compute the probability that exactly 3 of the observed trucks are speeding as follows:

[tex]P(X=3)={5\choose 3}(0.75)^{3}(1-0.75)^{5-3}\\\\=10\times 0.421875\times 0.0625\\\\=0.263671875\\\\\approx 0.2637[/tex]

Thus, the probability that exactly 3 of the observed trucks are speeding is 0.2637.

(e)

Compute the probability that less than 3 of the observed trucks are speeding as follows:

[tex]P(X<3)=P(X=0)+P(X=1)+P(X=2)\\\\=\sum\limits^{2}_{x=0}{{5\choose x}(0.75)^{x}(1-0.75)^{5-x}}\\\\=0.0009765625+0.0146484375+0.087890625\\\\=0.103515625\\\\\approx 0.1035[/tex]

Thus, the probability that less than 3 of the observed trucks are speeding is 0.1035.

Answer:

x=1 , y=10

Step-by-step explanation:

i attached photo of steps of solution