The **mass **of **potassium nitrate** (KNO₃) **crystals **that will be separated is calculated as **6.25 g.**

The given parameters:

The **mass **of **KNO**₃ at **95 ⁰C** is calculated as follows;

[tex]m = \frac{25\ g \times 100\ g}{100\ g} \\\\m = 25 \ g[/tex]

mass of water = 100 g - 25 g = 75 g

The **mass **of KNO₃ at **55 ⁰C **is calculated as follows;

[tex]m = \frac{75 \ g \times 25 \ g}{100 \ g} \\\\m = 18.75 \ g[/tex]

The **mass **of **potassium nitrate** (KNO₃) **crystals **that will be separated is calculated as;

[tex]m= 25\ g \ - \ 18.75 \ g\\\\m = 6.25 \ g[/tex]

Thus, the **mass **of **potassium nitrate** (KNO₃) **crystals **that will be separated is calculated as **6.25 g.**

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which statement about metals is true?

All metals are solid at (our) living temperatures except for mercury which is a liquid. Metals are shiny for a while at least when properly finished. Metals are good conductors of both heat and electricity. This is due to the excess electrons in their valence clouds that facilitate energy transfer.What are 5 characteristics of metal?

Metals are lustrous, malleable, ductile, good conductors of heat and electricity

Silver conducts electricity better than any other metal.

Brass is an alloy made from zinc and copper.

Pure gold is too soft for many things so most gold is combined with other metals to make it stronger. ...

World time periods are often listed by the metal used.

The qualitative equivalent of external validity is:

A- Credibility

B- Dependability

C- Transformability

D- Confirmability

c transformability i think

The security alarm on a parked car goes off and produces a frequency of 769 Hz. The speed of sound is 343 m/s. As you drive toward this parked car, pass it, and drive away, you observe the frequency to change by 69.5 Hz. At what speed are you driving

**Answer:**

**Explanation:**

ASSUMING your speed is constant

f₀ = f(v + vo)/(v + vs)

Δf = f approach - f depart

69.5 = (769(343 + vo)/(343 + 0)) **-** (769(343 - vo)/(343 + 0))

69.5 = 769(2vo/343)

** vo = 15.5 m/s**

The **speed **of car driving is 15.5 m/s as the car is **parked **and drive away.

**Speed **is defined as a measurement of the length of time it takes for an object to travel a certain **distance**. You can determine an object's speed if you know how far it moves in a given amount of time. Time does not move, hence there is no concept of a speed of time. Time refers to how we move through the **temporal realm**. Speed is a unit of measurement for how quickly something is moving. A change in velocity results in a change in speed.

To calculate the speed we use the formula

**f₀ = f (v + vo) / (v + vs)**

Δf = f approach - f depart

69.5 = (769(343 + vo) / (343 + 0)) - (769(343 - vo)/(343 + 0))

69.5 = 769(2vo/343)

vo = 15.5 m/s

Thus, the **speed **of car driving is 15.5 m/s as the car is **parked **and drive away.

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How much power does it take to lift 30.0 N 10.0 m high in 10.00 s?

**Answer:**

60w

**Explanation:**

The **power **required is **30 Watt.**

Let us recall that **power **is defined as the **rate **of doing **work**. Hence, we can write as follows;

Power = **Work done**/ **time taken**

Now;

work done = Force × distance

Force = 30.0 N

Distance = 10.0 m

work done = 30.0 N × 10.0 m = **300 J**

The power expended = 300 J/10.00 s = **30 Watt**

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48.36

g.

MgSO4 to motes

**Answer:120.3676**

**Explanation: using the molecular calculator and molar mass of MgSO4. hope this helps!**

A cyclist rides in a circle with speed 8.1 m/s. What is his centripetal

acceleration if the circle has a radius of 27 m?

**Explanation:**

We know that the tangent velocity is 8.1 m/s. We also know that the tangent velocity can be written in the following way:

Vt = ωr with ω being the angular velocity.

We now calculate ω:

ω = Vt/r = 8.1 m/s / 27m = 0.3 rad/s

Now that we have ω we can calculate the centripetal aceleration:

a = ω^2 * r = ( 0.3 )^2 * 27 = 2.43 m/s^2

A pendulum with a length of 2 m has a period of 2.8 s. What is the period of a pendulum with a length of 8 m

**Answer:**

P = 2 pi (L / g)^1/2

P2 / P1 = (8 / 2)^1/2 = 2

The period would be twice as long or 5.6 sec.

the turns ratio for a transformer with 225 turns of wire in its primary winding and 675 turns in the secondary is: n

The **ratio** of the **primary turns** to the **secondary turns** is **1****/****3**

The correct answer to the question is **Option A. 1/3**

From the question given above, the following data were obtained:

Primary turn (Nₚ) = 225 turnsSecondary turn (Nᵣ) = 675 turnsRatio = Nₚ/Nᵣ

Nₚ/Nᵣ = 225 / 675

**Nₚ/Nᵣ**** ****=**** ****1****/****3**

Therefore, the **ratio** of the **primary turns **to the **secondary turns **is **1****/****3**

**Complete**** ****question****:**

See attached photo

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Shorter the vibrating part more will be the pitch. How?

Answer:When the length of a string is changed, it will vibrate with a different frequency.Shorter strings have higher frequency and therefore higher pitch.

What is work? A. What happens when energy is destroyed B. The number of molecules in a substance C. The total size of an object divided by its mass D. What happens when a force causes an object to move

**Answer:**

Which extended definition would be most helpful to add to this body paragraph?

Laughter Yoga, a new form of yoga, is becoming increasingly popular.

Laughter Yoga, which is becoming more and more popular, was created in the 1990s.

Laughter Yoga is modeled after traditional yoga but includes laughter exercises.

Laughter Yoga is a form of yoga that was created by Dr. Madan Kataria in the 1990s.

**Explanation:**

c

The primary evidence that has led astronomers to conclude that the expansion of the universe is accelerating comes from __________.

The **Universe **is often studied by **Scientist**. The primary form of **evidence **that has led **astronomers **to conclude that the expansion of the universe is accelerating is the **Observations **of white dwarf **supernovae**.

The key **evidence **for that made scientist to talk about the expansion of the universe is accelerating comes from viewing and studying of **white** dwarf **supernovae**. It has been found that most distant **stars **all orbit at approximate **speed **as stars found about 30,000 **light**-years from their **center**.

Learn more about **white** **dwarf **from

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This is an image of a satellite traveling around Earth. Explain what are the two forces that are keeping the satelite around Earth without flying off or hitting the ground.

**Answer:**

One force will be gravity & inertia.

**Explanation:**

Bioth are combine to keep Earth in orbit around the sun, and the moon in orbit around Earth

how far from the lens is the image of the house if the house is 16 ft from the thin convex lens with a focal length of 8 ft

This question involves the concepts of the **thin lens formula**, **focal length**, and **image distance**.

The image of the house is **"16 ft" **away from the lens.

According to the **thin lens formula**:

[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]

where,

f = **focal length **= 8 ft

p = object distance = 16 ft

q = **image distance **= ?

Therefore,

[tex]\frac{1}{8\ ft}=\frac{1}{16\ ft}+\frac{1}{q}\\\\\frac{1}{q}=\frac{1}{8\ ft}-\frac{1}{16\ ft}\\\\\frac{1}{q}=0.125\ ft^{-1}-0.0625\ ft^{-1}\\\\q=\frac{1}{0.0625\ ft^{-1}}\\\\[/tex]

**q = 16 ft**

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The diagram shows the velocity-time graph for a car travelling in a straight line along a road. Calculate the acceleration between t = 2.0 s and t = 5.0 s.

**Answer:**

a = Δv/Δt = (0 - 20) / (5 - 2) = **-6⅔ m/s²**

A car slams on its brakes creating an acceleration of -4.7 m/s^2. It comes to rest after traveling a distance of 235 m. What was its velocity before it began to accelerate?

**Answer:**

**Explanation:**

v² = u² + 2as

0² = u² + 2(-4.7)(235)

u² = 2209

**u = 47 m/s**

A 10kg object is 15 meters up a hill. Find its potential energy

**Answer:**

**Explanation:**

Relative to an origin at the bottom of the hill,

PE = mgh = 10(9.8)(15) =** 1470 J**

A person sitting in a chair with wheels stands up, causing the chair to roll backward across the floor. The momentum of the chair

a. was zero while stationary and increased when the person stood.

b. was greatest while the person sat in the chair.

c. remained the same.

d. was zero when the person got out of the chair and increased while the person sat.

**Answer:**

a. was zero while stationary and increased when the person stood.

**Explanation:**

momentum is mass times velocity.

initial velocity was zero

final velocity was NOT zero.

K

Mission CG9: Weightlessness

Consider the several locations along a roller coaster

track. In which location(s) would the riders feel less

than their normal weight? Select all that apply.

Location A

Location B

Location C

a

=-10 m/s/s, dn

--2 m/s/s, up

a--6 m/s/s, dn

Location D

Location E

x=-12 m/s/s, dn

---6 m/s/s, up

The **locations **where the **riders **feel less than their **normal weight** are Location **A**,** **Location **C **and Location **D**.

The given parameters;

The **normal weight **of the **riders **is calculated by applying **Newton's second law of motion** as follows;

W = mg

W = 9.8m

The **apparent weight** of the **riders **for the **upward acceleration** is calculated as follows;

[tex]R = m(g + a)[/tex]

The **apparent weight** of the **riders **for the **downward acceleration** is calculated as follows;

[tex]R = m(g - a)[/tex]

The** apparent weight** of the **riders **at **location A** is calculated as follows;

[tex]R_ A = m(9.8 - 10)\\\\R_ A = -0.2 m[/tex]

The** apparent weight** of the **riders **at **location B** is calculated as follows;

[tex]R_B = m(9.8 + 2)\\\\R_B = 11.8 m[/tex]

The** apparent weight** of the **riders **at **location C** is calculated as follows;

[tex]R_C = m(9.8 - 6)\\\\R_C = 3.8 m[/tex]

The** apparent weight** of the **riders **at **location D** is calculated as follows;

[tex]R_D = m(9.8 - 12)\\\\R_D = -2.2 m[/tex]

The** apparent weight** of the **riders **at **location E** is calculated as follows;

[tex]R_E = m(9.8 + 6)\\\\R_E = 15.8 m[/tex]

Thus, the **locations **where the **riders **feel less than their **normal weight** are;

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Identify the type of chemical reaction:

CaCO3 -->CaO + CO2

**Explanation:**

*decomposition **reaction.**.**.**.**.*

**Answer:**

caco₃--cao+co₂

calcium oxide + carbon die oxide gives us calcium carbonate

this is the reaction of Acidic oxide(cao) and Basic oxide (co₂) to form salt.

What is the approximate value of k when 30 = e^5k?

**Answer:**

**Explanation:**

30 = e^5k

ln30 = lne^5k

ln30 = 5k

k = ln30/5

**k = 0.68023947...**

round to your heart's content.

Why does the earth stay in orbit around the sun instead of drifting away from it into space?

A Electric force between the Sun and Earth

B Magnetic force between the Sun and Earth

Gravitational force between the Sun and Earth

**Answer:**

b it is b part answer i think so

Which feature of a balanced chemical equation demonstrates the law of

conservation of mass?

O A. It has the same types of atoms on both sides of the reaction

arrow.

O B. It shows the reactants of a chemical reaction to the left of the

reaction arrow.

O C. It has coefficients to show how much of each substance a

chemical reaction uses.

Thing

D. It shows the products of a chemical reaction to the right of the

reaction arrow.

Answer: A) It has the same types of atoms on both sides of the reaction

arrow.

Explanation:** **A balanced equation demonstrates the conservation of mass **by having the same number of each type of atom on both sides of the arrow.**

1 point

Kinetic friction is defined as a force that acts between moving surfaces. A

body moving on the surface experiences a force in the opposite direction

of its movement. A student is investigating the motion of a block sliding

down a ramp onto the floor. The diagram below shows the block at five

points during the investigation. The block is at rest at point V. The student

releases the block so that it slides down the ramp and stops at point Z.

Which of the following best explains where kinetic friction is acting on the

block?

**Answer:**

**Explanation:**

Not sure what your options are but anything that says something like

"at the block surface in contact with the ramp along the line from V to Z" is probably a good shot.

Mechanical energy conservation states that

The total amount of energy will eventually be destroyed.

Potential energy will be conserved, but kinetic energy will be destroyed.

The total amount of energy, kinetic plus potential, remains the same.

Kinetic energy will be conserved, but potential energy will be destroyed.

Pls hurry I’ll give 50 points

**Answer:**

The total amount of energy, kinetic plus potential, remains the same.

**Explanation:**

At the local hockey rink, a puck with a mass of 0.12kg is given an initial speed of 5.3m/s. If the coefficient of friction between the puck and ice is 0.11, how much time does it take the puck to come to rest?

Here’s my work to your question. I used Newton’s Second Law and a kinematics equation to arrive at the answer.

At the local hockey rink, a puck with a mass of 0.12kg is given an initial **speed** of 5.3m/s. If the coefficient of** friction** between the puck and ice is 0.11, time it take the puck to come to** rest **is 4.51 sec.

The **speed **of an item, which is a scalar quantity in everyday usage and kinematics, is the size of the** change** in that object's** position** over time or the size of the change in that object's position** per unit of time**.

Given in the question at the local hockey rink, a puck with a mass of 0.12kg is given an initial **speed** of 5.3m/s. If the coefficient of friction between the puck and ice is 0.11,

**force** = ma = μmg, putting the value,

a = - 1.175 m/sec²

now using equation of motion

v = u + at

t = 4.51 sec

So,** time** taken by the puck to come to rest is 4.51 sec.

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Would you please help me with this? I can't figure it out, please! I need to know what the E means!

**Answer:**

Without the full content of your question, I will have to GUESS at the context and assume

**E = Energy **

released when glucose is broken down.

PLEASE HELP FOR PHYSICS!

All objects exert a gravitational force on all other objects. This force is given by, F = GMm r2 , where the value of G = 6.673 × 10–11 N–m2/kg2 , M is the mass of the heavier object, m is the mass of the lighter object, and r is the distance between the two objects.

What is the force of gravity between two balls of mass 50 kg each if the distance between them is 25 m. Assume that there is no interference from any other gravitational field.

Hi there!

Recall Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]

Where:

Fg = Force of gravity (N)

G = Gravitational Constant

m1, m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the given values stated in the problem:

[tex]F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}[/tex]

The 0.15kg baseball has a speed of v=30 m/s just before it is struck by the bat. It then travels along the trajectory shown before the outfielder catches it. Determine the magnitude of the average impulsive force imparted to the ball if it is in contact with the bat for 0.75 ms

The** magnitude** of the average **impulsive force** imparted to the ball if it is in contact with the bat is **6000 N**

The **mass** of the baseball, m = 0.15 kg

The **speed** at which it moves, v = 30 m/s

**Time** at which the **baseball** was in contact with the bat, t = 0.75 ms

t = 0.75/1000 s

t = 0.00075 s

The** impulsive force** is given by the **formula**:

[tex]F=\frac{mv}{t}[/tex]

**Substitute** m = 0.15 kg, v = 30, and t = 0.00075s into the **formula** above:

[tex]F=\frac{0.15 \times 30}{0.00075} \\\\F=6000N[/tex]

The** magnitude** of the average **impulsive force** imparted to the ball if it is in contact with the bat is **6000 N**

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A 1200 kg car moves due north with a speed of 15m/s. An identical car moves due east with the same speed of 15m/s what are the direction and the magnitude of the system’s total momentum

a.

The **direction** of the **total momentum** is **45°**

The **momentum **of the **first car** is given by **p = mv **where **m = mass of car** = 1200 kg and **v = velocity of car **= 15 m/sj (since it moves due north).

So,** p = mv **

= 1200 kg × (15 m/s)j

**= (18000 kgm/s)j**

Also, the **momentum** of the **identical car**, **p' = mv' **where **m = mass of car **= 1200 kg and **v' = velocity of car** = (15 m/s)i (since it moves due east).

So, **p' = mv' **

= 1200 kg × (15 m/s)i

**= (18000 kgm/s)i**

So, the **total momentum** of the system **P = p + p' **

= (18000 kgm/s)j + (18000 kgm/s)i

**= (18000 kgm/s)i + (18000 kgm/s)j **

The **direction** of the **total momentum **of the system P is gotten from

**tanФ = p'/p **

= 18000 kgm/s ÷ 18000 kgm/s

= 1

Ф = tan⁻¹(1)

**= 45°**

The **direction** of the **total momentum** is **45°**

b.

The **magnitude** of the** total momentum** of the system is **25455.84 kgm/s**

The **magnitude** of the** total momentum** of the system **P = √(p'² + p²) **

= √[(18000 kgm/s)² + (18000 kgm/s)²]

= (18000 kgm/s)√(1 + 1)

= (18000 kgm/s)√2

**= 25455.84 kgm/s**

The **magnitude** of the** total momentum** of the system is **25455.84 kgm/s**

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please help 9.2.1 project in science just ned an example

**Answer:**

Give me what kind of example you need please so I can help you. Put it in the comments.

**Explanation:**

Please help asap! I will give a person the brainliest crown! Inappropriate comment will get report. Do you think the government have the right to limit its its citizens during the war? If yes, then under what circumstances? This is Canadian History
use these terms in to show they are related, radiant energy, solar collector, active solar heating system
5/50 divided by 15/30 solve it out for me please
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