Answer:
0
Step-by-step explanation:
- 2×3= - 6
2×3=6
-6+6=0
Answer:
0
Step-by-step explanation:
first
(-2x3)+(3x2)
-6+6=0
Combine like terms to simplify the
equation below.
Answer:
4a+6b
Step-by-step explanation:
4a -2a +6b +2a
Combine like terms
4a-2a+2a+6b
4a+6b
Answer:
4a + 6b
Step-by-step explanation:
4a - 2a + 6b + 2a
= 4a + 6b
(because -2a and +2a get cancelled by each other)
How many odd numbers with 4 different digits, can be formed using the digits 1, 2, 3, 4, 5, 6, 7, 8? (No repetition is allowed)
A. 71
B. 200
C. 210
D. 840
E.1680
Answer:
840 ( D )
Step-by-step explanation:
GIVEN DIGITS : 1,2,3,4,5,6,7,8
Number of odd numbers = 4
Number of even numbers = 4
therefore the number of odd numbers with 4 different digits can be formed by the same way the number of even numbers ( without repetition )
Hence the number of ways odd numbers with 4 different digits = Total number of ways of forming 4 digit numbers / 2
8*7*6*5 = 1680 / 2 = 840 ways
PLEASE gelp me with this, gelp me please oh please gelp me!
Answer:
V = 2143.57 cm^3
Step-by-step explanation:
The volume of a sphere is
V = 4/3 pi r^3
The diameter is 16 so the radius is 1/2 of the diameter or 8
V = 4/3 ( 3.14) (8)^3
V =2143.57333
Rounding to the nearest hundredth
V = 2143.57 cm^3
Answer:
2143.57 cm^3
Step-by-step explanation:
V = 4/3 * 3.14 * r^3
r = 1/2 * 16 = 8
So V = 4/3 * 3.14 * 8^3
= 2143.57 cm^3.
What is the volume of a pyramid below?
600 cm^3
750 cm^3
900 cm^3
1800 cm^3
Answer: 600 cm³
Step-by-step explanation:
Volume of square pyramid = (1/3) · b² · h
b = base edge length = 10 cmh = height = 18 cmTherefore, the volume can be calculated as
[tex]\frac{1}{3} *10^{2}*18=\frac{1}{3}*100*18=\frac{1}{3}*1800=\frac{1800}{3}=600[/tex]
Answer
900
Step-by-step explanation:
it is pyramid and finding its volume we use the 3 components that is length, with and the height
1/2 base x width x height
5 x 18 x 10 = 900cm³
Find the missing side length. Leave your answers radical in simplest form. PLEASE HURRY
Answer:
y=8 and x=8 ✔3. the check is meant to be square root symbol lol
Janet has 12 more cookies than Cody. If Janet has 60 cookies, write and solve to determine the number of cookies Cody has.
Answer: 48
Step-by-step explanation: 60-12=48
find the n^th root of z = -2i, n = 6
Answer:
2^(1/6) (cos(-pi/12)+i sin(-pi/12))
2^(1/6) (cos(3pi/12)+i sin(3pi/12))
2^(1/6) (cos(7pi/12)+i sin(7pi/12))
2^(1/6) (cos(11pi/12)+i sin(11pi/12))
2^(1/6) (cos(5pi/4)+i sin(5pi/4))
2^(1/6) (cos(19pi/12)+i sin(19pi/12))
Step-by-step explanation:
Let's convert to polar form.
-2i=2(cos(A)+i sin(A) )
There is no real part so cos(A) has to be zero and since we want -2 and we already have 2 then we need sin(A)=-1 so let's choose A=-pi/2.
So z=2(cos(-pi/2)+i sin(-pi/2)).
There are actually infinitely many ways we can write this polar form which we will need.
z=2(cos(-pi/2+2pi k)+i sin(-pi/2+2pi k))
where k is an integer
Now let's find the 6 6th roots or z.
2^(1/6) (cos(-pi/12+2pi k/6)+i sin(-pi/12+2pi k/6))
Reducing
2^(1/6) (cos(-pi/12+pi k/3)+i sin(-pi/12+pi k/3))
Plug in k=0,1,2,3,4,5 to find the 6 6th roots.
k=0:
2^(1/6) (cos(-pi/12+pi (0)/3)+i sin(-pi/12+pi (0)/3))
=2^(1/6) (cos(-pi/12)+i sin(-pi/12))
k=1:
2^(1/6) (cos(-pi/12+pi/3)+i sin(-pi/12+pi/3))
2^(1/6) (cos(3pi/12)+i sin(3pi/12))
k=2:
2^(1/6) (cos(-pi/12+2pi/3)+i sin(-pi/12+2pi/3))
2^(1/6) (cos(7pi/12)+i sin(7pi/12))
k=3:
2^(1/6) (cos(-pi/12+3pi/3)+i sin(-pi/12+3pi/3))
2^(1/6) (cos(11pi/12)+i sin(11pi/12))
k=4:
2^(1/6) (cos(-pi/12+4pi/3)+i sin(-pi/12+4pi/3))
2^(1/6) (cos(15pi/12)+i sin(15pi/12))
2^(1/6) (cos(5pi/4)+i sin(5pi/4))
k=5:
2^(1/6) (cos(-pi/12+5pi/3)+i sin(-pi/12+5pi/3))
2^(1/6) (cos(19pi/12)+i sin(19pi/12))
. A swimming pool was filling with water at a constant rate of 200 gallons per hour. The pool had
50 gallons before the timer started. Write an equation in standard form to model the situation, then
find the amount of water in the pool after 2 hours and 15 minutes.
Nicole ordered a volleyball for $9.75
Answer:
the other person is right
you should try putting the WHOLE question
Step-by-step explanation:
Please help with step by step.
When 8 is added to a certain number and the sum is multiplied by 3, the result is 57. Find the number.
Answer:
The number is 11.
Step-by-step explanation:
[tex]3(8+x)=57\\24+3x=57\\3x=33\\x=11[/tex]
What kinds of people actually read printed information on the packaging before purchasing a product? As part of a larger study on the influence of product packaging on purchase decisions, a survey of 250 citizens of Sarajevo asked if they observed printed information before purchasing a product (Poturak, 2014). Assume that the sample was a simple random one.
Complete Question
The complete question is shown on the first uploaded image
Answer:
[tex]X = 1.2857[/tex]
Step-by-step explanation:
Generally from the table the contribution to the chi-square statistic of the number of individuals in the survey aged 20 - 22 who strongly disagreed about whether they observe packing information before purchasing items is mathematically represented as
[tex]X = \frac{(10 - 7)^2 }{7}[/tex]
[tex]X = 1.2857[/tex]
What is the domain of f(x) = 5^x - 7?
O {x|x>-7)
O {XIX<-7}
O {x|x>0}
O {x | x is a real number}
Step-by-step explanation:
{ x| x all real numbers}
The domain of f(x) = 5x – 7 will be all real numbers, as the function is a straight line, with no discontinuities, thus undefined at no value of x.
The domain of the function f(x) = 5ˣ - 7 is {x | x is a real number}.
What is Function?A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.
Given function is,
f(x) = 5ˣ - 7
The domain of the function is the set of all values of x such that the function is defined.
If we use any number for x, the function will be defined.
So the domain is the set of all real numbers.
So the correct option is last one {x | x is a real number}.
Hence the domain of the given function is {x | x is a real number}.
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For what values of K does the equation (2k+1)x^2 +2x= 10x - 6 have two real and equal roots.
Answer:
Step-by-step explanation:For what values of does the equation (2 + 1) have two 2
+ 2 = 10 − 6
real and equal roots?
A quadratic equation that has 2 roots that are equal means that the discriminant of the equation is 0. The value of k that makes the equation have 2 real and equal roots is [tex]k = \frac{5}{6}[/tex]
Given that:
[tex](2k + 1)x^2 + 2x = 10x - 6[/tex]
Rewrite as:
[tex](2k + 1)x^2 + 2x - 10x + 6 = 0[/tex]
[tex](2k + 1)x^2 - 8x + 6 = 0[/tex]
A quadratic equation is represented as:
[tex]ax^2 + bx + c = 0[/tex]
By comparison:
[tex]a=2k+1\\ b =-8\\\ c =6[/tex]
If an equation has 2 real and equal roots, then:
[tex]b^2 = 4ac[/tex]
So, we have:
[tex](-8)^2 = 4 \times (2k + 1) \times 6[/tex]
[tex]64 = 4 \times (2k + 1) \times 6[/tex]
Divide by 4
[tex]16 = (2k + 1) \times 6[/tex]
Divide by 6
[tex]\frac{16}{6} = (2k + 1)[/tex]
[tex]\frac{8}{3} = 2k + 1[/tex]
Subtract 2 from both sides
[tex]2k = \frac{8}{3} -1[/tex]
Take LCM
[tex]2k = \frac{8-3}{3}[/tex]
[tex]2k = \frac{5}{3}[/tex]
Divide by 2
[tex]k = \frac{5}{6}[/tex]
Hence, the value of k that makes the equation have 2 real and equal roots is [tex]k = \frac{5}{6}[/tex]
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Aakash, Bao Ying, Chris and Donna all live on the same street as their school, which
runs from east to west.
• Aakash lives 5 blocks to the west.
• Bao Ying lives 4 blocks to the east.
• Chris lives 2: blocks to the west. .
• Donna lives 61 blocks to the east.
a. Draw a picture that represents the positions of their houses along the street.
b. Find how far is each house from every other house?
c. Represent the relative position of the houses on a number line, with the school at
zero, points to the west represented by negative numbers, and points to the east
represented by positive numbers.
d. How can you see the answers to part (b) on the number line? Using the numbers
(some of which are positive and some negative) that label the positions of houses on
the number line, represent these distances using sums or differences.
ko
The distance between each of the students' houses are:
Aakash & Bao Ying live 9 blocks away from each other
Aakash & Chris live 3 blocks away from each other
Aakash & Donna live 66 blocks away from each other
Bao Ying & Chris live 6 blocks away from each other
Bao Ying & Donna live 57 blocks away from each other
Chris & Donna live 63 blocks away from each other
To solve this question, we represent each with the first letter of their names.
So, we have:
[tex]A= 5\ west[/tex] --- Aakash
[tex]B= 4\ east[/tex] ---- Bao Ying
[tex]C = 2\ west[/tex] --- Chris
[tex]D = 61\ east[/tex] ---- Donna
I've added the picture and the number line that represent the scenario as an attachment.
To calculate how far each lives from each other's, we start by representing west as negative and east as positive.
So, the representations become:
[tex]A = -5[/tex]
[tex]B = 4[/tex]
[tex]C = -2[/tex]
[tex]D = 61[/tex]
The absolute difference of each represents how far they live from one another.
Aakash & Bao Ying Aakash & Chris Aakash & Donna
[tex]AB = |-5 -4| =9[/tex] [tex]AC = |-5 --2| =3[/tex] [tex]AD = |-5 -61| =66[/tex]
Bao Ying & Chris Bao Ying & Donna
[tex]BC = |4 --2| =6[/tex] [tex]BD = |4 -61| =57[/tex]
Chris & Donna
[tex]CD = |-2 -61| =63[/tex]
This means that
Aakash & Bao Ying live 9 blocks away from each other
Aakash & Chris live 3 blocks away from each other
Aakash & Donna live 66 blocks away from each other
Bao Ying & Chris live 6 blocks away from each other
Bao Ying & Donna live 57 blocks away from each other
Chris & Donna live 63 blocks away from each other
To carry out the above computations from the number line, we simply count the numbers from one to the other.
For instance:
There are 3 numbers from Akash to Chris.
This means that: Aakash & Chris live 3 blocks away from each other
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Find
two consecutive numbers
odd numbers such that the
sum of the
greater number
and 5 times the smaller
number is 92. Please give detailed step by step answer
Answer:
The two odd numbers are 15 and 17
Step-by-step explanation:
Given
Let the odd numbers be represented with x and y
Let x be the greater number
[tex]x + 5y = 92[/tex]
Required
Find x and y
Since x and y are consecutive odd numbers and x is greater, then
[tex]x = y + 2[/tex]
Substitute y + 2 for x in [tex]x + 5y = 92[/tex]
[tex]y + 2 + 5y = 92[/tex]
Collect Like Terms
[tex]y + 5y = 92 - 2[/tex]
[tex]6y = 90[/tex]
Divide both sides by 6
[tex]\frac{6y}{6} = \frac{90}{6}[/tex]
[tex]y = \frac{90}{6}[/tex]
[tex]y = 15[/tex]
Substitute 15 for y in [tex]x = y + 2[/tex]
[tex]x = 15 + 2[/tex]
[tex]x = 17[/tex]
Hence; the two odd numbers are 15 and 17
Answer:
Maths
Step-by-step explanation:
Answer:
The two odd numbers are 15 and 17
Step-by-step explanation:
Given
Let the odd numbers be represented with x and y
Let x be the greater number
Required
Find x and y
Since x and y are consecutive odd numbers and x is greater, then
Substitute y + 2 for x in
Collect Like Terms
Divide both sides by 6
Substitute 15 for y in
Hence; the two odd numbers are 15 and 17
Which statements can be used to compare the characteristics of the functions? Select three options.
Answer:
Step-by-step explanation:
g(x) has the smallest minimum value. All three functions share the same domain and the y-intercept is also the same for all three thus options (C),(D), and (E) is correct.
What is a graph?A graph is a diametrical representation of any function between the dependent and independent variables.
For example y = x² form a parabola now by looking at only the graph we can predict that it has only a positive value irrespective of the interval of x.
As per the given table,
The minimum value among all functions is -204 which is for g(x).
The domain is the set of x since all function defines the same x thus they have the same domain.
At y-intercept x = 0
Since at x = 0 all function is 3 thus all three will have the same y-intercept.
Hence "The smallest minimal value is for g(x). The y-intercept for all three functions is the same, and all three functions have the same domain".
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What is the probability of the spinner landing on an odd number? A spinner is split into 4 equal parts labeled 1, 2, 3, and 4. One-fourth One-third One-half Three-fourths
Answer:
One half, or 1/2.
There are an equal amount of odd numbers as there are even numbers on the spinner.
Answer:
C. 1/2
One-half
A number to be multiplied is called a?
Answer:
The number to be multiplied is the "multiplicand"
Step-by-step explanation:
a base when it is written in exponential notation
what is the volume of a unit cube?
Step-by-step explanation:
Volume of unit cube= (1)³ unit³= 1 unit³
Q-The general solution of inequality cos 2 x≤- sin x is
Answer:
x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Step-by-step explanation:
1−2sin2 x≤−sin x ⇒ (2sin x+1)(sin x−1)≥0
sin x≤−1/2 or sin x≥1
−5π/6+2nπ≤x≤−π/6+2nπ or , n ϵ I x=(4n+1)π/2, n ϵ I⇒ -5π6+2nπ≤x≤-π6+2nπ or , n ϵ I x=4n+1π2, n ϵ I (as sin x = 1 is valid only)
In general⇒ In general x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Find TAN
Instructions: Find the value of the trigonometric ratio. Make
sure to simplify the fraction if needed.
please mark this answer as brainlist
Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately Normally distributed with a mean of 2.45 microns and a standard deviation of 0.35 micron. What is the standardized score for a binding site position of 2.03 microns? (Enter your answer rounded to one decimal place.)
Answer:
The values is
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 2.45[/tex]
The standard deviation is [tex]\sigma = 0.35 \ mi[/tex]
The random value is [tex]x = 2.03[/tex]
The standardized score for a binding site position of 2.03 microns is mathematically represented as
[tex]z-score = \frac{x - \mu}{ \sigma }[/tex]
=> [tex]z-score = \frac{2.03 - 2.45}{ 0.35}[/tex]
=> [tex]z-score = -1.2[/tex]
When proving a statement using mathematical induction, part of the process is assuming that the statement is true for the nth case. (True or False).
Answer:
True
Step-by-step explanation:
We assume that is true for the nth case and prove it for the n+1 case
and show that it is true for the case when n=1
Johnny and a robot standing 5 melo (units of length) apart (in a flat area) on the
planet Rote. They spot a flying object hovering in the sky at the same time. If the
angle of elevation from Johnny to the flying object is 29°, and the angle of elevation
from the robot to the flying object is 42°, find the distance from the flying object to
the ground. For this problem, assume that the heights of Johnny and the robot are
neligible. [8 marks]
Answer:
distance from the flying object to
the ground
= 7.2 melo(unit of measurement)
Step-by-step explanation:
The distance between the robot and Jo is 5 melo( unit Of measurement)
Let the distance between the flying object and the ground= y
Let's the remaining length of the closest between robot and Jonny and the ground be x.
Y/(x+5)= tan 29.... equation 1
Y/x= tan 42.... equation 2
Equating the value of y
Tan 29(x+5) = tan42(x)
Tan29/tan 42 = x/(x+5)
0.61562(x+5)= x
3.0781= x- 0.61562x
3.0781= 0.38438x
3.0781/0.38438= x
8.008= x
8= x
Y/x= tan 42
Y/8= 0.9004
Y= 7.203
Y= 7.2 melo (unit of measurement )
A sequence of 1 million iid symbols(+1 and +2), Xi, are transmitted through a channel and summed to produce a new random variable W. Assume that the probability of transmitting a +1 is 0.4. Show your work
a) Determine the expected value for W
b) Determine the variance of W
Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
Find the area of the triangle with the following measurements: B = 67°, a = 13 cm, c = 21 cm
9514 1404 393
Answer:
125.6 cm²
Step-by-step explanation:
The relevant area formula is ...
Area = (1/2)ac·sin(B)
Area = (1/2)(13 cm)(21 cm)·sin(67°) ≈ 125.6 cm²
What is 9.3 to the 8th power
Answer: 55958180.97
Step-by-step explanation:
9.3 x 9.3 x 9.3 x 9.3 x 9.3 x 9.3 x 9.3 x 9.3
86.49 x 86.49 x 86.49 x 86.49
= 55958180.97
Un taxímetro inicia con 50 unidades y el banderazo o arranque es de $4500, las unidades comienzan a cambiar p0r cada kilometros recorrido. La función lineal que representa esta situación es y = 50x +4500 donde y representa el precio que cuesta la carrera y x la distancia recorrida en kilómetros. a) ¿ Cuanto cuesta una carrera si la distancia recorrida fue de 23 kilómetros?
Answer: $5650
Step-by-step explanation:
El precio de la carrera es:
y = ($50/km)*x + $4500.
Donde x representa la cantidad recorrida en Km.
Ahora se nos pregunta:
¿ Cuanto cuesta una carrera si la distancia recorrida fue de 23 kilómetros?
Para esto, debemos reemplazar la variable en la equacion por 23km:
x = 23km
y = ($50/km)*23km + $4500 = $5650
In a class of 70 pupils, 36 like tasty time , 34 like ice-
cream, 6 like both tasty time }
draw a Venn diagram to show the data.
find how
many
like neither tasty time nor ice-cream
Step-by-step explanation:
I think this might be the correct answer
The number of pupils that like neither tasty-time nor ice cream is 6 if in a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty times.
What is the Venn diagram?It is defined as the diagram that shows a logical relation between sets.
The Venn diagram consists of circles to show the logical relation.
We have:
In a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty time.
Total = 70 pupils
Number of like tasty time = 36
Number of like ice cream = 34
Number of like both = 6
Let x be the total number of pupils that like neither tasty-time nor ice cream
The number of pupils that like ice cream only = 34 - 6 = 28
The number of pupils that like tasty-time only = 36 - 6 = 30
From the Venn diagram:
28 + 30 + 6 + x = 70
x = 70 - 64
x = 6
Thus, the number of pupils that like neither tasty-time nor ice cream is 6 if in a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty times.
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