Answer:
white noise is a bunch of frequencies at the same time :)
Explanation:
In regard to the Compton scattering experiment with x-rays incident upon a carbon block, as the scattering angle becomes larger, what happens to the magnitude of difference between the incident and scattered wavelengths
Answer:
Increases
Explanation:
In the Compton scattering experiment with x-rays,
The change in operation
[tex]\Delta \lambda = \frac{h}{m_oc} [1-cos\theta][/tex]
Now rest being constant, as \theta increases, cos\theta decreases
Hence, The change in wavelength will increase with the increase in \theta.
Hence, wavelength increases with an increase in the angle of scatttering.
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a) Name the graph?
b) In first 2 s the object is said to be in ______________ motion.
(uniform motion / uniform acceleration)
c) The portion BC of the graph represents which type of motion?
d) Find out acceleration in first 2 s?
I don't know♀ what is your favorite song
which way would 2 negatively charged balloons naturally move? what would that do to the amount of potential energy stored in the field?
Answer:
gsg
Explanation:
The balloons with negative charges moves apart from each other by electrostatic force of repulsion. The potential energy in them increases as they move away.
What is force of repulsion?The basic principle of charges is that, two like charges repel and unlike charge attracts. That is: two negative charged bodies or two positively charged bodies will repel each other and one negative charged body attracts a positively charged body.
In both cases attraction or repulsion the charged particles exerts a force with each other called the electrostatic force. The electrostatic force between two charges is directly proportional to the magnitude of charges and inversely proportional to the distance between them.
The balloons with negative charges moves apart from each other by electrostatic force of repulsion. The potential energy in them increases as they move away.
Find more on electrostatic repulsion:
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Which of the following best describes the formation of surf? Waves energy, rebounding from its impact with shore, crashes into oncoming waves, causing them to break. Entering shallow water forces wave energy upward, making the wave crest unstable and causing it to break. A wave encountering shallow water begins to slow at its bottom, while the top of the wave continues at its previous speed. This causes the wave to break. As waves enter shallow water, the distance between wave crests (wave length) shortens, increasing the tendency to break.
Answer:
The question above would be written again but this time with options attached to it for comprehension sake:
Which of the following best describes the formation of surf?
A. Waves energy, rebounding from its impact with shore, crashes into oncoming waves, causing them to break.
B. Entering shallow water forces wave energy upward, making the wave crest unstable and causing it to break.
C. A wave encountering shallow water begins to slow at its bottom, while the top of the wave continues at its previous speed. This causes the wave to break.
D. As waves enter shallow water, the distance between wave crests (wavelength) shortens, increasing the tendency to break.
The correct answer is option C (A wave encountering shallow water begins to slow at its bottom, while the top of the wave continues at its previous speed. This causes the wave to break).
Explanation:
Surf could mean crashing waves or breaking waves. Generally, the wave speed is constant in the same medium, however, the wave speed decreases as it enters shallow water which is largely due to the water depth which is relatively small, especially when it encounters the bottom of the shallow water. While the top of the wave overtakes the bottom of the wave, making sure the top of the wave continues at its previous speed.
-In a series LRC circuit, the frequency at which the circuit is at resonance is f0. If you double the resistance, the inductance, the capacitance, and the voltage amplitude of the ac source, what is the new resonance frequency?
A) 4 f0
B) 2 f0
C) f0
D) f0/2
E) f0/4
When you double capacitance and inductance, the new resonace frequency becomes f0/2.
Resonance frequencyThe resonace frequency of RLC series circuit, is the frequency at which the capacitivity reactance is equal to inductive reactance.
Xc = Xl
[tex]\frac{1}{2\pi f_0C} = 2\pi f_0 L\\\\4\pi^2 f_0^2 LC = 1\\\\f_0^2 = \frac{1}{4\pi^2 LC} \\\\f_0 = \sqrt{\frac{1}{4\pi^2 LC} } \\\\f_0 = \frac{1}{2\pi } \frac{1}{\sqrt{LC} }[/tex]
where;
f0 is the resonace frequencyL is the inductanceC is the capacitanceWhen you double capacitance and inductance, the new resonace frequency becomes;
[tex]f_0 = \frac{1}{2\pi } \frac{1}{\sqrt{LC} }\\\\f_1 = \frac{1}{2\pi } \frac{1}{\sqrt{2L (2C)} } \\\\f_1 = \frac{1}{2\pi } \frac{1}{\sqrt{4LC} }\\\\f_1 = \frac{1}{2}( \frac{1}{2\pi } \frac{1}{\sqrt{LC} })\\\\f_1 = \frac{1}{2} (f_0)[/tex]
Thus, When you double capacitance and inductance, the new resonace frequency becomes f0/2.
Learn more about resonance frequency here: https://brainly.com/question/9324332
An aluminum-alloy rod has a length of 10.0 cm at 20°C and a length of 10.015 cm at the boiling point of water (1000C). (a) What is the length of the rod at the freezing point of water (0 0C)? (b) What is the temperature if the length of the rod is 10.009 cm? /4mks
Answer:
a. 9.99625 cm b. 68 °C
Explanation:
(a) What is the length of the rod at the freezing point of water (0 0C)?
Before we find the length of the rod, we need to find the coefficient of linear expansion, α = (L - L₀)/[L₀(T - T₀)] where L₀ = length of rod at temperature T₀ = 10.0 cm, T₀ = 20 °C, L = length of rod at temperature T = 10.015 cm and T = 100 °C
Substituting the values of the variables into the equation, we have
α = (L - L₀)/[L₀(T - T₀)]
α = (10.015 cm - 10.0 cm)/[10.0 cm(100 °C - 20 °C)]
α = 0.015 cm/[10.0 cm × 80 °C]
α = 0.015 cm/[800.0 cm °C]
α = 0.00001875 /°C
We now find the length L₁ at T₁ = 0 °C from
L₁ = L₀(1 + α(T₁ - T₀))
So, substituting the values of the variables into the equation, we have
L₁ = L₀(1 + α(T₁ - T₀))
L₁ = 10.0 cm[1 + 0.00001875 /°C(0° C - 20 °C)]
L₁ = 10.0 cm[1 + 0.00001875 /°C × -20° C]
L₁ = 10.0 cm[1 - 0.000375]
L₁ = 10.0 cm[0.999625]
L₁ = 9.99625 cm
(b) What is the temperature if the length of the rod is 10.009 cm?
With length L₃ = 10.009 cm at temperature T₃, using
L₃ = L₀(1 + α(T₃ - T₀))
making T₃ subject of the formula, we have
L₃/L₀ = 1 + α(T₃ - T₀)
L₃/L₀ - 1 = α(T₃ - T₀)
T₃ - T₀ = (L₃/L₀ - 1)/α
T₃ = T₀ + (L₃/L₀ - 1)/α
substituting the values of the variables into the equation, we have
T₃ = 20 °C + (10.009 cm/10.0 cm - 1)/0.00001875 /°C
T₃ = 20 °C + (1.0009 - 1)/0.00001875 /°C
T₃ = 20 °C + 0.0009/0.00001875 /°C
T₃ = 20 °C + 48 °C
T₃ = 68 °C
Charges of +3 µC and –5 µC are 2 mm from each other. The –5 µC charge is replaced with a +5 µC charge.
How will the electrical force between the charges compare with the original force?
same force, but in the opposite direction
same force, but in the same direction
greater force, but in the opposite direction
greater force, but in the same direction
Answer: same force in opposite direction.
Explanation: Charges of opposite sign attracts each other and charges with same sign repel each other. Because only sign of negative charge changes, and absolute value of charge remains same, value of force is same but is in opposite direction.
Answer:
A) same force, but in the opposite direction
Explanation:
he's right
A piston is resting halfway into a cylinder containing gas in thermal equilibrium. The layer of molecules next to the closed end of the cylinder is suddenly flash-heated to a very high temperature. Which best describes what happens next
Answer: hello the options related to your question is missing attached below are the missing options
answer : The molecules with the highest temperature will bounce off their neighbors, losing energy to them and so on until the system is at a new equilibrium with the piston moved out ( option B )
Explanation:
What best describes the situation of what will happen next as explained in the question is in Option B
Because molecules with higher temperatures will always posses higher kinetic energy and they will collide more frequently with surrounding molecules passing on their energy in the process until the energy gets to the molecules closest to the piston. The molecules closest to the piston will then hit the piston until a new equilibrium is achieved
Two arrows are shot vertically upward. The second arrow is shot after the first one, but while the first is still on its way up. the initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. Suppose the that initial speed of the first arrow is 34 m/s and that the second arrow is fired 0.204081632653061 seconds after the first. Determine the initial speed of the second arrow.
Answer:
The initial speed of the second arrow is 33.8 m/s.
Explanation:
initial speed of first arrow, u = 34 m/s
Let the initial height of the second arrow is h.
Let they both reaches at maximum height H.
Let the time taken by the first arrow is t and the second arrow is t - 0.0204
Let the initial speed of the second arrow is u'.
Use first equation of motion for the first arrow.
v = u - gt
0 = u - gt
34 = gt ..... (1)
For the second arrow
v =u' - g (t - 0.0204)
0 = u' - gt + 9.8 x 0.0204
u' = 34 - 0.1999 = 33.8 m/s
a.If the hockey player exerted twice as much force (9.00 N) on the puck over the
same distance, how would the amount of work the stick did on the puck be
affected
Answer:
The work done is doubled.
Explanation:
The work done is defined as the product of the force and the displacement in the direction of force.
Work = force x displacement.
As the force is doubled and the displacement remains same, so the work done is also doubled.
Work done is a scalar quantity and its SI unit is Joule.
(answer the question or get reported) Please solve it with the steps thanks :)
Answer:
Fx = 35.36 N
Fy = 35.36 N
Explanation:
From the question,
The X component of the force is
Fx = Fcos∅.................. Equation 1
Where Fx = X component of the force, F = Force, ∅ = Angle to the horizontal.
Give: F = 50 N, ∅ = 45°
Substitute into equation 1
Fx = 50(cos45°)
Fx = 50(0.7071)
Fx = 35.36 N
Similarly,
For Y component
Fy = Fsin∅
Where F y = Y component
Fy = 50(sin45°)
Fy = 50(0.7071)
Fy = 35.36 N
After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg bowling pin initially at rest. Find the final velocity of the second pin in the following situations: a) The first pin moves to the right after the collision at 0.8 m/s. Answer in units of m/s. 010 (part 2 of 2) 10.0 points b) The first pin stops moving when it hits the second pin. Answer in units of m/s
Answer:
a) v₂ = 4.2 m/s
b) v₂ = 5 m/s
Explanation:
a)
We will use the law of conservation of momentum here:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0.8 m/s
v₂ = speed of second after before collsion = ?
Therefore,
[tex](1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s[/tex]
v₂ = 4.2 m/s
b)
We will use the law of conservation of momentum here:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0 m/s
v₂ = speed of second after before collsion = ?
Therefore,
[tex](1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)[/tex]
v₂ = 5 m/s
Juan's mother drives 12.5 miles southwest to her favorite shopping mall. What is the velocity of her
automobile if she arrives at the mall in 7.25 minutes?
Answer:
v1= 12.5miles, t= -7.25m, a= 0
v= 1/2at^2
v= 1/2×
Which type of electromagnetic radiation is responsible for the colors of
objects?
O A. Radio waves
O B. X-rays
O C. Visible light
O D. Ultraviolet radiation
Answer:
C. Visible light
Explanation:
Visible light is responsible for the colors of objects.
Hope it will help :)❤
f the voltage in a circuit is 80 volts and the resistance is 20 ohms, what is the current?
I = 4 A
Explanation:
From Ohm's law, the voltage is given by
V = IR
or
I = V/R = (80 V)/(20 ohms)
= 4 A
77. The first law of motion applies to
a. Only objects that are moving
b. Only objects that are not moving
C. All objects whether moving or not
No obiect, whether moving or not
Una lámpara requiere 5 A y presenta una resistencia de 20 Ω, cuando está
encendida.
a. ¿Cuál es la tensión?
b. ¿Qué resistencia adicional requiere si se desea operar a 120 V?
c. ¿Y 110 V?
Answer:
a. V = 100 voltios
b. Para 120 V → [tex]R_{2} = 4 \Omega[/tex]
c. Para 110 V → [tex]R_{2} = 2 \Omega[/tex]
Explanation:
a. La tensión se puede calcular mediante la ley de Ohm:
[tex] V = IR [/tex]
V: es el voltaje o tensión =?
I: es la corriente = 5 A
R: es la resistencia = 20 Ω
Entonces, la tensión es:
[tex]V = IR = 5 A*20 \Omega = 100 V[/tex]
b. La resistencia adicional es la siguiente:
[tex] R_{2} + R_{1} = \frac{V}{I} [/tex]
[tex]R_{2} = \frac{V}{I} - R_{1} = \frac{120 V}{5 A} - 20 \Omega = 4 \Omega[/tex]
c. La resistencia adicional para operar a 110 voltios es:
[tex]R_{2} = \frac{V}{I} - R_{1} = \frac{110 V}{5 A} - 20 \Omega = 2 \Omega[/tex]
Espero que te sea de utilidad!
Determine the amount of work done by the applied force when a 87 N force is applied to move a 15 kg object a horizontal
distance of 4.5 meters at a constant speed.
Answer:
391.5 J
Explanation:
The amount of work done can be calculated using the formula:
W = F║d where the force is parallel to the displacementLooking at the formula, we can see that the mass of the object does not affect the work done on it.
Substitute the force applied and the displacement of the object into the equation.
W = (87 N)(4.5 m) W = 391.5 JThe amount of work done on the object is 391.5 J in order to move it 4.5 meters with an applied force of 87 Newtons.
Mass doesn't matter on amount of work done .We can calculate amount of work done through Force and Displacement
Force=87NDisplacement=4.5m[tex]\boxed{\sf W=Fd}[/tex]
W denotes to work doneF denotes to forced denotes to displacement[tex]\\ \sf\longmapsto Work\:Done=87(4.5)[/tex]
[tex]\\ \sf\longmapsto Work\:done=391.5J[/tex]
If you were capable of converting mass to energy with 100%, efficiency, how much mass would you need to produce 3.5x10^12 Joules of energy?
Answer:
a) 3.9 x 10⁻⁵ kg
Explanation:
The amount of mass required to produce the energy can be given by Einstein's formula:
[tex]E = mc^2\\\\m = \frac{E}{c^2}[/tex]
where,
m = mass required = ?
E = Energy produced = 3.5 x 10¹² J
c = speed of light = 3 x 10⁸ m/s
Therefore,
[tex]m = \frac{3.5\ x\ 10^{12}\ J}{(3\ x\ 10^8\ m/s)^2} \\\\m = 3.9\ x\ 10^{-5}\ kg[/tex]
Hence, the correct option is:
a) 3.9 x 10⁻⁵ kg
The sunlight reaches the ground through radiation
Answer:
y e s
Explanation:
ACELLUS PHYSICS HELP!!
A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)
Answer:
Potential difference, V = -0.000224 Volts
Explanation:
Given the following data;
Quantity of charge = 6.93*10-4 C
Energy = -3.09 J
To find the electric potential V at that point?
Mathematically, the energy transferred per unit of charge is given by the formula;
E = QV
Where:
E is the energy
Q is the quantity of charge
V is the potential difference.
Substituting into the formula, we have;
[tex] -3.09 = 6.93*10^{-4} * V [/tex]
[tex] V = \frac {6.93*10^{-4}}{-3.09} [/tex]
Potential difference, V = -0.000224 Volts
What are the si units
Answer:
The uniy which is accepted all over the world is called SI unit.
Explanation:
The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.
A children's roller coaster is released from the top of a track. If its maximum speed at ground level is 3 m/s, find the height it was released from.
Answer:
h = 0.46 m
Explanation:
According to the law of conservation of energy:
Potential Energy Lost by Roller Coaster = Kinetic Energy Gained by Roller Coaster
[tex]mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\h = \frac{v^2}{2g}[/tex]
where,
h = height = ?
v = speed at bottom = 3 m/s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h = \frac{(3\ m/s)^2}{(2)(9.81\ m/s^2)}[/tex]
h = 0.46 m
CAN ANYONE HELP WITH THESE QUESTIONS :,] PLS IS URGEN IM SO CLOSE TO FAILING ALSO ITS SCIENCE PHYSICS I THINK
SEND ME A MESSAGE
Which of the following changes occurs during nuclear fission?
A. Energy is absorbed from the surroundings.
B. Atomic nuclei combine to form a larger nucleus.
C. Energy is converted into mass.
D.
The parent nucleus splits into lighter daughter elements.
Reset
Answer:
The parent nucleus splits into lighter daughter elements
Explanation:
Nuclear fission involves the splitting of nucleus of a lighter element with smaller particles
Compared to yesterday, you did three times the work in one-third the time. To do so, your power output must have been ___
Answer: 9 times yesterday's power output
Explanation:
Power is the rate at which a certain work is done. The unit of power is Watt and it's equal to work divided by the time taken to complete the work.
In this scenario, since the person did three times the work in one-third the time, then the power output will be:
= Work done / Time
= 3/⅓
= 3 × 3
= 9
Therefore, the power output must have been 9 times yesterday's power output.
pls answer my quetion i will give brainlist answer
Answer:
here's an explanation but not the answer
please kindly send No or Yes understand.
Explanation:
A 10-N force is applied to push a block across a friction free surface for a displacement of 5.0 m to the right.
See Answer
See Answer
A 10-N frictional force slows a moving block to a stop after a displacement of 5.0 m to the right.
8× +5+9×+3 how can I solve this
Answer:
collect like terms then add=>8x+9x+5+3
=>8x+9x+5+3=>17x+8
Write a short paragraph about Fruit and Seed formation of Strawberry plants.
what is fire proof plastic
Explanation:
.Flame retar,dant plastic additi,ves are compounds added to plastics and other materials to inhibit, suppress or de,lay combustion. These compounds are useful in impending burning in the ign,ition phase of fire. They do not prevent char,ring or melting nor do they increase the heat resistance of a material