Answer:
15.32 days
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 3.83 days
Original amount (N₀) = 225 g
Amount remaining (N) = 14.06 g
Time (t) =.?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Original amount (N₀) = 225 g
Amount remaining (N) = 14.06 g
Number of half-lives (n) =?
N = N₀ / 2ⁿ
14.06 = 225 / 2ⁿ
Cross multiply
14.06 × 2ⁿ = 225
Divide both side by 14.06
2ⁿ = 225 / 14.06
2ⁿ = 16
Express 16 in index form with 2 as the base
2ⁿ = 2⁴
n = 4
Thus, 4 half-lives has elapsed.
Finally, we shall determine the time. This can be obtained as follow:
Half-life (t½) = 3.83 days
Number of half-lives (n) = 4
Time (t) =.?
n = t / t½
4 = t / 3.83
Cross multiply
t = 4 × 3.83
t = 15.32 days
Therefore the time for 225 g sample of Radon to decay to 14.06 g is 15.32 days
What type(s) of intermolecular forces are expected between SO3 molecules? ball & stick -+labels Indicate with a Y (yes) or an N (no) which apply. dipole forces ___ induced dipole forces ___ hydrogen bonding ___
Answer:
dipole forces Y
induced dipole forces N
hydrogen bonding N
Explanation:
Oxygen is highly electronegative than sulphur, hence SO3 is polar
A 37.2 g sample of copper at 99.8 °C is carefully placed into an insulated container containing 188 g of water at 18.5 °C. Calculate the final temperature when thermal equilibrium is reached. Assume there is no energy transferred to or from the container. Specific heat capacities: Cu = 0.385 J g-1 °C-1 H2O = 4.184 J g-1 °C-1
Answer:
T₂ = 19.95°C
Explanation:
From the law of conservation of energy:
[tex]Heat\ Lost\ by\ Copper = Heat\ Gained\ by\ Water\\m_cC_c\Delta T_c = m_wC_w\Delta T_w[/tex]
where,
mc = mass of copper = 37.2 g
Cc = specific heat of copper = 0.385 J/g.°C
mw = mass of water = 188 g
Cw = specific heat of water = 4.184 J/g.°C
ΔTc = Change in temperature of copper = 99.8°C - T₂
ΔTw = Change in temperature of water = T₂ - 18.5°C
T₂ = Final Temperature at Equilibrium = ?
Therefore,
[tex](37.2\ g)(0.385\ J/g.^oC)(99.8\ ^oC-T_2)=(188\ g)(4.184\ J/g.^oC)(T_2-18.5\ ^oC)\\99.8\ ^oC-T_2 = \frac{(188\ g)(4.184\ J/g.^oC)}{(37.2\ g)(0.385\ J/g.^oC)}(T_2-18.5\ ^oC)\\\\99.8\ ^oC-T_2 = (54.92) (T_2-18.5\ ^oC)\\54.92T_2+T_2 = 99.8\ ^oC + 1016.02\ ^oC\\\\T_2 = \frac{1115.82\ ^oC}{55.92}[/tex]
T₂ = 19.95°C
What happens when earth rotates on its axis and how long take?
Answer:
We get Day and Night... It takes 24 hours for the earth to rotate on its axis
In the formula H2SO4, what is the 4 called?
Answer:
Well 4 in H2SO4 would be called Sulfuric Acid
Explanation:
The Reason why its called by its name because the form lua is called this its because its a colorless Acid that burns it also has dissolving metals and other stuff inside of it. it has another name called oil of vitriol. hopefully this helps ^^!
State the methods of preparing salts
Answer:
Preparation of Salts by The Action of An Acid Upon a Metal.
Preparation of Salts by Double Decomposition.
Preparation of Salts by Neutralization.
Using A Soluble Base (alkali)
(b). Using An Insoluble Base.
Preparation of Salts by the Action of An Acid on The Trioxocarbonate (IV) of A Metal.
Explanation:
t-Butyl alcohol was produced by the liquid-phase hydration (using water, W) of isobutene (I) over an Amberlyst-15 catalyst.
a. True
b. False
Answer:
True
Explanation:
This is because, The hydroboration oxidation of an alkene which is isobutene in the presence of a catalyst will result to alcohol as the product . Therefore, the OH group will attach or link itself to the carbon which is less obstructed. Thus this reaction is in accordance to Anti-Markownikoff's rule.
So isobutene on hydroboration oxidation will produce ter isobutyl alcohol.
Genes influence an organism's traits by coding for:
A
Cells
Answer:
First, the protein may be a structural protein, contributing to the physical properties of cells or organisms. ... Second, the protein may be an enzyme that catalyzes one of the chemical reactions of the cell. Therefore, by coding for proteins, genes determine two important facets of biological structure and function.
Explanation:
i think it will help you
If there are 1.55 x 1024 molecules of hydrogen peroxide (H2O2), what is the mass of the
sample?
Answer:
87.54 g of H₂O₂
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 1.55×10²⁴ molecules
Mass of H₂O₂ =.?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole of H₂O₂
Next, we shall determine the mass of 1 mole of H₂O₂. This can be obtained as follow:
1 mole of H₂O₂ = (2×1) + (2×16)
= 2 + 32
= 34 g
Thus,
6.02×10²³ molecules = 34 g of H₂O₂
Finally, we shall determine mass of H₂O₂ that contains 1.55×10²⁴ molecules. This can be obtained as follow:
6.02×10²³ molecules = 34 g of H₂O₂
Therefore,
1.55×10²⁴ molecules
= (1.55×10²⁴ × 34)/6.02×10²³
1.55×10²⁴ molecules = 87.54 g of H₂O₂
Thus, 87.54 g of H₂O₂ contains 1.55×10²⁴ molecules.
What is the empirical formula for a compound if a 2.50g sample contains 0.900g of calcium and 1.60g
of chlorine? (3pts]
Answer:
CaCl₂
Explanation:
First we convert the given masses of elements into moles, using their respective molar masses:
0.900 g Ca ÷ 40 g/mol = 0.0225 mol Ca1.60 g Cl ÷ 35.45 g/mol = 0.045 mol ClNow we divide those numbers of moles by the lowest value among them:
0.0225 mol Ca / 0.0225 mol = 10.045 mol Cl / 0.0225 mol = 2Meaning the empirical formula for the compound is CaCl₂.
20 grams of hydrogen fluoride gas, HF, is dissolved in 0.5 liters of solution. Determine the molarity (M).
Answer:
40
Explanation:
M = n/v hope this helps :b
Excessive use of chemical fertilizer causes chemical pollution.how?
Answer:
Chemical fertilizers contain various chemicals that cause harm to soil and water.
Explanation:
Chemical fertilizers contain various chemicals such as phosphates, nitrates which can cause water pollution. Eutrophication caused by the environmental nitrogen and phosphorous that causes rich minerals and chemicals in the water.
These can cause excessive growth of the algae and phytoplankton that will cause depletion of the oxygen from the water body and organisms will die due to this.
advantages
of corrosion
Answer:
Protection : Surface corrosion forms an oxide layer which further protects the inner metal form corrosion
.
Corrosion prevents corrosion : Some metals like zinc are used as sacrificial anodes to prevent corrosion to other metal.
Galvanic corrosion : The principle on which primary batteries work.
Λλ(Lamda) Represents what??
Answer:
λ Represents:-
one wavelength of electromagnetic radiationthe decay constant in radioactivityfunction expressions in the lambda calculusa general eigenvalue in linear algebrathe expected number of occurrences in a Poisson distribution in probabilitythe arrival rate in queueing theorythe failure rate in reliability engineeringthe Lagrange multiplier in mathematical optimization, known as the shadow price in economicsthe Lebesgue measure denotes the volume or measure of a Lebesgue measurable setlongitude in geodesylinear densityecliptic longitude in astronomythe Liouville function in number theorythe Carmichael function in number theorythe empty string in formal grammara formal system in mathematical logicthermal conductivitythe Lorentz transformation-TheUnknownScientist
what is a factor of a solution
Answer:
Normality factor is defined as the ratio of observed wt. of solute to the theoretical wt. of the solute required to prepare a solution of desired normality. ... The principle states that, “the product of volume and concentration factor of the solution at any dilution is constant provided mass of the solution is constant.”
Explanation:
What is the mass (in grams) of 2.55 x 1022 molecules of water?
Explanation:
hope the picture above make sense:)
A saline solution, NaCl in water, is 0.92 % (m/v). How many grams of NaCl are required to prepare 35.0 mL of this solution?
Answer:
0.322 g
Explanation:
Since our concentration is given in mass per volume percent % (m/v)
% (m/v) = mass of solute in g/volume of solution in mL × 100%
Since % (m/v) = 0.92 and volume of the required solution is 35.0 mL, we find the mass of NaCl from
mass of NaCl = % (m/v)/100 % × volume of solution
= 0.92 % (m/v)/100 %× 35 mL
= 0.0092 × 35
= 0.322 g
The study of a chemical is called chemistry.
The correct answer is 0.322 g
The saline is said that the amount of salt present in the solution. The formula used to solve the question is as follows:-
[tex]\frac{m}{v} = \frac{mass \ of\ solute}{volume\ of\ solution} * 100[/tex]
The data is given as follows:-
0.92 %(m/v)Volume is 35.0 mL,Mass of NaCl is as follows:-
[tex]\frac{0.92}{100} * 35 mL[/tex]
[tex]0.0092 * 35\\= 0.322 g[/tex]
Hence, the correct answer is 0.322g.
For more information, refer to the link:-
https://brainly.com/question/14698383
The breakdown of proteins produces
A. Carbon dioxide
B. Urea
C. Water
Answer:
B.Urea
Explanation:
When an amino acid is broken down, the nitrogen it contains is converted into urea by the liver which then is excreted via the kidneys.
Answer:
urea
Explanation:
when u eat proteins the body breaks them down into amino acids . Ammonia is produced from leftover amino acids and it must be removed from the body. the liver produces many chemicals (enzymes) that change ammonia into a form called ureas
The formula for the pH of a solution of hydronium ions is given by the logarithmic equation pH= -log[h3o^+], where [H3o^+] is the hydronium ion concentration. Find the pH of a certain agricultural product with the hydronium ion concentration of 4.7x10^-4
The pH is =?
Answer:
pH = 3.3
Explanation:
Step 1: Given data
Concentration of hydronium ions in the agricultural product ([H₃O⁺]): 4.7 × 10⁻⁴ M
Step 2: Calculate the pH of the agricultural product
We will use the definition of pH.
pH = -log [H₃O⁺]
pH = -log 4.7 × 10⁻⁴
pH = 3.3
Since the pH < 7, the agricultural product is acidic.
All solutes will dissolve at some point.
O True
O False
Answer:
False
Explanation:
5. A 23.9 g piece of metal heated to 97.8 °C is placed in 52.4 g water at 21.9 °C. After the
metal is added, the temperature of the water rises to 29.9 °C. Calculate the specific heat of the
metal. Express your answer in the units of cal/g°C.
Answer:
Explanation:
Here we'll use our formula for specific heat, Q=mcΔT.
Q= Heat (Joules), m=mass (g), c=specific heat
ΔT= (final temperature - initial temperature)
When we add a heated piece of metal in water at a lower temperature, the metal will lose heat and the water will absorb that heat. Over time they will eventually reach an equilibrium, here we have it at 21.9 C. If you recall in thermodynamics, , when we lose heat it is exothermic and the values of exothermic reactions are negative, and the values of endothermic reactions are positive. So we can say the heat of the metal is exothermic and releasing heat into the water until they reach equilibrium, thus they are equal. Keeping in mind Q= heat,
-Q metal = Q water.
We can expand this equation to -mcΔT= mcΔT.
Our equation reflects what is happening to the metal and the water.
Before we start, it might be helpful to remember that the
c=specific heat of water= 4.186 J/g C
Let's plug in what we know and solve for c=specific heat of metal. I'll start with the left side then go to the right side.
-(23.9g)(c)(29.9-97.8) = (52.4g)(4.184)(29.9 - 21.9)
-(23.9gc)(29.9-97.8) = (52.4g)(4.184)(29.9 - 21.9)
-(23.9g)(c)(-67.9) = (52.4g)(4.184)(29.9 - 21.9)
1623c = (52.4g)(4.184)(29.9 - 21.9)
1623c = (52.4g)(4.184)(8)
1623c = 1754
c= [tex]\frac{1754}{1623}[/tex]
c= 1.08
This means it takes less heat to raise the temperature of the piece of metal ( in comparison to the water, which require more ).
how many liters of N2 gas is needed to produce 500 L NH3?
Balance this reaction:
___Naz3(PO4)+ ___K(OH) ---> ___Na(OH) +___K3(PO4)
Describe the effects lenses have on light and their possible technological applications.
Answer:
lenses is used to refract light inward or outward
there are two type of lenses. Concave and convex lense
Convex lense converge ray of light
Concave lense diverge ray of light
useful application =:
=> camera
=> flashlight
=> lasers
=> Binoculars and Telescope
hope it helps
Answer:
Explanation:
Lenses are made of glass or other transparent materials for light. They are optically dense so light slows down on entering it. It is called refraction which bends the light on entering and leaving the lenses.
Refraction by lenses can be used for all kinds of optical applications, e.g. camera, telescope, magnifying glasses, solar heating.
what would be the observation when you dipp magnesium hydroxide in a blue litmus paper and a red litmus paper. also what would be the conclusion for it
Answer:
red litmus will turn blue
blue litmus will remain blue
Explanation:
magnesium hydroxide is a base therefore turns red litmus paper blue
Viscosity is a measure of:
A. how much resistance to flowing a fluid has.
B. how much space a fluid takes up.
C. how much matter a fluid is made of.
D. how much fluid is in a given volume.
Viscosity is the measure of how much resistance to flowing any given fluid has; answer choice A. The formula to calculate the viscosity of a liquid is...
F = μA(u/y)
Real world scenario: cancer prevention
Answer:
for skin cancer use sunscreen but for cancer that's most common eat healthy and take vitamins as much as you can.
Explanation:
Why is it important that the perodic table is structured as a table rathe than a list of elements. please answer me
Answer:
According to the b word, this is the answer
Explanation:
Learning a periodic table is more important as it is systematically arranged to give a lot of information about the elements and the way they relate to each other in various ways. Moreover, chemistry is all more about chemical elements. Hence a good understanding of the chemical elements will discover more about chemistry.
Please answer I will give you brainliest!!
Answer:
Warm front
Explanation:
A warm front forms when a warm air mass pushes into a cooler air mass, shown in the image to the right (A). Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. Warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface. Warm fronts often form on the east side of low-pressure systems where warmer air from the south is pushed north.
You will often see high clouds like cirrus, cirrostratus, and middle clouds like altostratus ahead of a warm front. These clouds form in the warm air that is high above the cool air. As the front passes over an area, the clouds become lower, and rain is likely. There can be thunderstorms around the warm front if the air is unstable.
On weather maps, the surface location of a warm front is represented by a solid red line with red, filled-in semicircles along it, like in the map on the right (B). The semicircles indicate the direction that the front is moving. They are on the side of the line where the front is moving. Notice on the map that temperatures at ground level are cooler in front of the front than behind it.
How much energy (kJ) is required to change 0.18 mole of ice (s) at 0 C to water (l) at 0 C?
Answer:25,06 kJ of energy must be added to a 75 g block of ice.
ΔHfusion(H₂O) = 6,01 kJ/mol.
T(H₂O) = 0°C.
m(H₂O) = 75 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 75 g ÷ 18 g/mol.
n(H₂O) = 4,17 mol.
Q = ΔHfusion(H₂O) · n(H₂O)
Q = 6,01 kJ/mol · 4,17 mol
Q = 25,06 kJ.
Explanation:
Soil comes in different colors.
Answer: yes they come in different colors.
Explanation:
Most shades of soil is mostly black,brown,red,gray,and white the color of soil and other properties including texture, structure, and consistency are used to distinguish and identify soil.