The wind velocity in relation to the observer is 30 km/h west-to-east.
What is the relative velocity of the plane?
The relative velocity of an object is the measure of change in velocity of the object using a common reference point, known as point of reference.
The relative velocity of the wind with respect to a stationary observer is calculated as follows;
Let A be plane velocity and W wind velocity;
A + W = 320 km/h ----- 1
A - W = 290 km/h --- 2
----------------------------------
2A = 610
A = 610/2
A = 305 km/h
The relative velocity;
W - A = 320 km/h - 305 km/h
W - A = 15 km/ (east to west)
Another west to east = 15 km/hr
= 15 km/hr + 15 km/hr
= 30 km/hr west to east
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Two moles of helium gas initially at 170 K
and 0.23 atm are compressed isothermally to
1.78 atm.
1): Find the final volume of the gas. Assume
that helium behaves as an ideal gas. The
universal gas constant is 8.31451 J/K · mol.
Answer in units of m3
2): Find the work done by the gas.
Answer in units of kJ.
3): Find the thermal energy transferred.
Answer in units of kJ.
The gas's final volume is 0.129 m³ times its beginning volume.
The work done by the gas is -2.6226 kJ, indicating that work is being done on the gas.
The transmitted thermal energy is also -2.6226 kJ.
How to calculate volume, work done and thermal energy?Using the ideal gas law to solve for the final volume of the gas:
PV = nRT
where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.
Since the process is isothermal, the temperature remains constant at 170 K, therefore:
P₁V₁ = P₂V₂
where P₁ and V₁ = initial pressure and volume, and P₂ and V₂ = final pressure and volume.
Substituting the given values:
(0.23 atm)(V₁) = (1.78 atm)(V₂)
Solving for V₂:
V₂ = (0.23/1.78)V₁ = 0.129 V₁
So the final volume of the gas is 0.129 times the initial volume.
To find the work done by the gas, use the formula:
W = -∫PdV
where the integral is taken from the initial volume V₁ to the final volume V₂. Since the process is isothermal:
W = -nRT ln(V₂/V₁)
Substituting the given values:
W = -(2 mol)(8.31451 J/K·mol)(170 K) ln(0.129) = -2622.6 J = -2.6226 kJ
So the work done by the gas is -2.6226 kJ, which means work is done on the gas.
The thermal energy transferred during the process is equal to the work done by the gas, since the process is isothermal and there is no change in internal energy. Therefore, the thermal energy transferred is also -2.6226 kJ.
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What is true about the requirements of your academic career plan
Academic career planning mainly needs, coordination of your educational requirements with your job ambitions.
ACP, or academic career planning, is a student-driven, adult-supported process whereby students develop their own distinct, knowledge-based visions for success after high school through self-exploration and career-reflection as well as the acquisition of career management and planning skills.
It requires the understanding of your abilities, values, and interests relate to potential occupations or jobs matching your abilities, matching your financial needs and career ambitions, etc.
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2. You are traveling along a highway at night at a speed of 100 km/h when you spot an object directly in front of you in the road at the limit of your headlights. (10 Marks)
a) If the maximum braking deceleration that your car can provide is 7 m/s2, and if your headlights extend out to a range of 30 m, will you hit the object before coming to a stop?
b) How long will it take to stop?
a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:
d = (v^2) / (2a)
where:
d = distance required to stop
v = initial velocity
a = acceleration/deceleration
In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)
a = -7 m/s^2 (negative sign indicates deceleration)
We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.
Plugging in the values to the formula, we get:
d = (27.78^2) / (2 x -7) = 108.61 m
Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.
b) To calculate the time required to stop, we can use the following formula:
t = v / a
where:
t = time required to stop
v = initial velocity
a = acceleration/deceleration
Plugging in the values, we get:
t = 27.78 / 7 = 3.97 s
Therefore, it will take 3.97 seconds to stop the car.
Help! Offering Brainliest & Points!
Match Letter's with image.
The correct match is A - trough, B - amplitude, C - crest, and D - wavelength.
A - A trough is the lowest point on a wave, where the displacement of the medium or the amplitude of the wave is at its minimum.
B - Amplitude refers to the maximum displacement or distance moved by a point on a vibrating body or wave, from its equilibrium position.
C - A crest is the highest point on a wave, where the displacement of the medium or the amplitude of the wave is at its maximum.
D - Wavelength is the distance between two corresponding points on a wave, such as the distance between two consecutive crests or troughs. It is often measured in meters or other units of length.
Hence, A - trough, B - amplitude, C - crest, and D - wavelength.
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Find the equivalent resistance between points A and B
shown in Figure 31.
The equivalent resistance between points A and B is 0.837Ω.
Resistors in series are connected end-to-end so that the current flows through them in sequence. The equivalent resistance of resistors in series is the sum of their individual resistances.
The formula for equivalent resistance of resistors in series: R_eq = R_1 + R_2 + ... + R_n
Resistors in parallel are connected across each other so that the voltage is the same across each resistor. The equivalent resistance of resistors in parallel is the reciprocal of the sum of the reciprocals of their individual resistances.
The formula for equivalent resistance of resistors in parallel: 1/R_eq = 1/R_1 + 1/R_2 + ... + 1/R_n
Here in the Fig.
we can simplify the second set of resistors in parallel (4.8 Ω, 3.3 Ω, and 8.1 Ω) using the same formula:
1/Req1 = 1/4.8 + 1/3.3 + 1/8.1
Req1=1.575Ω
This Req1 connected series with 6.3Ω, then Req of this two resistance given by:
Req2= 1.575Ω+ 6.3Ω
Req2=7.875Ω
Once again this req2 makes the parallel with the other two resistance i. e 1.5Ω and 2.5Ω
Their equivalent resistance is given by,
1/Req3=1/1.5 + 1/2.5 + 1/7.875
Req3=0.837Ω
Hence, The equivalent resistance between points A and B is 0.837Ω
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✦
Joey rolls several objects down a grassy hill. Which force is acting on the objects which cause the objects to slow down?
A. Friction
B. Normal
C. Applied
D Magnetic
friction
Friction is what causes moving objects to slow down and eventually stop.
• find the position at = 2.0s of mortocylist heading east through a small city accelerated After he passed The Signpost maketing the city limit his constant acceleraccetereted acceleration at time t=0 was 4- 0m/s² he was 5.0m east of the signpost moving east at Velocity of 15 m/s-
At t = 2.0 s, the rider is 43.0 m east of the marker.
How to calculate position?To solve this problem, use the kinematic equation:
x = x₀ + v₀×t + (1/2)at²
where x = final position,
x₀ = initial position, v₀ = initial velocity,
a = acceleration, and t is the time.
Given that the motorcyclist has a constant acceleration of 4.0 m/s², and initially 5.0 m east of signpost moving east at a velocity of 15 m/s, initial position and velocity:
x₀ = 5.0 m
v₀ = 15 m/s
Now, find the position at t = 2.0 s:
t = 2.0 s
a = 4.0 m/s²
x = x₀ + v₀t + (1/2)at²
x = 5.0 m + 15 m/s(2.0 s) + (1/2)4.0 m/s²(2.0 s)²
x = 5.0 m + 30 m + 8.0 m
x = 43.0 m
Therefore, the position of the motorcyclist at t = 2.0 s is 43.0 m east of the signpost.
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If you apply a greater force the spring constant will be
If you apply a greater force the spring constant will remain the same, since it is a constant.
What is Hooke's law?This law states that the force applied to an elastic material is directly proportional to the extension of the material.
That is as the force applied to an elastic material increases the extension of the elastic material increases provided the elastic limit of the material is not exceeded.
Mathematically, this law can be written as;
F = kx
where;
F is the applied forcek is the spring constx is the extension of the materialSo when the force applied is increased, the extension of the material increases as well.
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In a 'keep-fit' exercise, a student of mass 45 kg steps 40 times on and off a box of height 0.50 m. How much work does the student do to raise her body each time she steps on the box
Answer:Calculate the work done using:
work done (in joules) = force (in newtons) x distance moved (in metres)
To practice calculations involving force, distance and work done.
Explanation: I hope this helps srry if I'm wrong
Physic question help
The good conductors of heat and electricity are Penny, and An aluminum soda can.
option A and B.
What are good conductors of electricity?Good conductors of electricity are those materials that allow easy passage of electric current through them.
All metals are good conductors of electricity, and some of their examples include;
Aluminum
Copper
Silver
Zinc, etc
Poor conductors on the other hand do not allow easy passage of electric current through them.
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A physical science test book has a mass of 2.2 kg what is the weight on the earth 4 box method
The weight of the box is determined as 21.56 N.
What is the weight of the box?The weight of the box is calculated by applying Newton's second law of motion as shown below;
F = mg
where;
m is the mass of the boxg is acceleration due to gravityThe weight of the box is calculated as follows;
W = 2.2 kg x 9.8 m/s²
W = 21.56 N
Thus, the weight of the box is determined by multiplying the mass and acceleration due to gravity.
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The car of mass mc rolls from rest with negligible friction down the curved ramp and around the circular loop. The initial height of the center of mass of the car is at height H. Assume the center of mass of the car is at a height equal to the diameter d of the loop when the car is at the top of the loop.
(a) In terms of the given quantities and any fundamental constants, derive an equation for the speed vtop at the top of the loop. (Neglect the rotational kinetic energy of the wheels).
(b) The car is upside down at the top of the loop. Derive an equation for the minimum speed vmin necessary to make the loop.
The speed at the top of the loop is √gR.
Let the starting point be A, the lower point of loop be B and the top of loop be C.
So, at A the car is having only potential energy.
PE = mgh
At B, the kinetic energy,
KE = 1/2 mv²
a) At point C,
mv²/R = mg
The velocity at the top point, v(C)
v(top) = √gR
b) According to Conservation of energy, at B and C,
1/2 mv(B)² = 1/2 mv(C)² + mg(2R)
v(B)² = gR + 4gR
Therefore, v(B) = √5gR
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Do you think Kepler will be able to detect Earth-sized planets in transit?
Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.
Explanation:
Which description accurately describes the tide represented by the image below? (4 points)
Image of the sun and moon at a 90 degree angle to Earth. An oval is around Earth that points toward and away from the moon to show the tidal bulges.
High tides occur when the sun and moon are at right angles to one another.
Low tides occur when the sun and moon are at right angles to one another.
The gravitational pull of the sun and moon combined creates larger than normal tides.
The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides.
High tides occur when the sun and moon are at right angles to one another. This is because the gravitational pull of the moon and the sun combine to create larger-than-normal tides, known as spring tides. The correct option is A.
Gravitational pull is the force of attraction that exists between two objects with mass. The greater the mass of an object, the greater its gravitational pull.
Option B, "Low tides occur when the sun and moon are at right angles to one another," is incorrect. Low tides occur when the sun and moon are at a 90-degree angle (or "quarter moon") to each other, but this position also results in high tides on the opposite side of the Earth.
Option C, "The gravitational pull of the sun and moon combined creates larger than normal tides," is partially correct. The gravitational pull of both the sun and moon does contribute to the tides, but the specific position depicted in the image (sun and moon at right angles to each other) does not necessarily create larger than normal tides.
Option D, "The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides," is also incorrect. The sun's gravitational pull does have an effect on the tides, but it does not reduce the moon's gravitational pull. Rather, the combined gravitational pull of the sun and moon creates the tides we observe.
Therefore,The accurate description of the tide represented by the image below is option A: "High tides occur when the sun and moon are at right angles to one another."
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Two people hold a rope at either end. One person moves his end of the rope at a frequency of 4.0 Hz and a wavelength of 0.8 m. At what speed does the wave travel through the rope ?
Answer :
Speed = 3.2 m/sExplanation :
According to the question, It's given that Two people hold a rope at either end. One person moves his end of the rope at a frequency of 4.0 Hz and a wavelength of 0.8 m.
Frequency (f) = 4.0 HzWavelength [tex] (\lambda)[/tex] = 0.8 mWe know the relationship between frequency and Wavelength. It states that wave speed is equal to the product of frequency and Wavelength .
v = f [tex] \lambda[/tex]where,
f is frequency i.e 4.0 Hz , [tex] (\lambda)[/tex] is Wavelength i.e 0.8 mSubstituting the values,
[tex]: \implies[/tex]v = 4.0 × 0.8
[tex]: \implies[/tex] v = 3.2 m/s
Therefore, At the speed of 3.2 m/s the wave travel through the rope.
Why is DNA a useful evolutionary clock?
50 POINTS ANSWER CORRECTLY 4. Identify what elements are made in a Super Red Giant as it starts to die?
The super red giant star is the aging star and it is a dying star in the final stage of stellar evolution. From the burst of the super red giant star, magnesium is formed from the core of the red giant star.
The super red giant star has a larger mass and produces greater gravitational pressure. The giant red star is in the final stage of dying and the core of the red star has heavier elements like nitrogen, carbon, etc.
In the core of stars, nuclear fusion takes place. Nuclear fusion is the process of two lighter nuclei fusing or joining together to form a heavier nucleus.
The hydrogen fuses to form helium and helium fuses together to form carbon atoms. Carbon atoms fuse together to form oxygen atoms and it forms heavier elements like magnesium and iron.
Hence, from the burst of a super red giant star, heavier elements like magnesium, iron, carbon, and helium ions are formed.
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1. In order to generate a current from a magnet, which of the following would generate a current?
a. Spinning a magnet near a wire
b. Placing the north end of a magnet near a wire
c. Place the south end of a magnet near a wire
2. In order for a circuit to function, which of the following must be true?
a. The circuit cannot have more than 3 bulbs attached
b. The circuit must have an switch placed in the circuit in the open position
c. The circuit must make a complete loop and must have all parts connected to that loop
Spinning a magnet near a wire would generate a current.
The circuit must make a complete loop and must have all parts connected to that loop.
What is the spinning magnet?When a magnet approaches a conductor, such as a wire, the magnetic field changes, causing the wire to conduct electricity. Electromagnetic induction is a process that underlies the operation of electric motors and generators.
Electromagnetic induction and is the basis for how generators and electric motors work and it explains the fact that current is generated by a spinning a magnet near a wire.
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A bowling ball 0.005 kg moves at 100m/s. How much kinetic energy does the bowling ball have?
The kinetic energy of the bowling ball is 25 J (joules).
What is the kinetic energy of the bowling ball?
Kinetic energy is simply a form of energy a particle or object possesses due to its motion.
It is expressed as;
K = (1/2)mv²
Where m is mass of the object and v is its velocity.
Given that the mass of the bowling ball is 0.005 kg and its velocity is 100 m/s.
We can use the formula to calculate its kinetic energy:
K = (1/2)mv²
KE = (1/2) × 0.005kg × (100m/s)²
KE = (1/2) × 0.005kg × 10000 m²/s²
KE = 25 J
Therefore, the kinetic energy is 25 joules.
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an astronaut of mass m is launched from the surface of the moon in a space craft having an initial vertical acceleration of 5g, where g is the acceleration of free fall in moon. the vertical reaction of the space craft on the astronaut is
The vertical reaction force R can be calculated as R = -8.1*m N, where the negative sign indicates that it acts in the opposite direction to the initial acceleration (which is upward in this case).
A reaction force is a force that is equal in magnitude but opposite in direction to an action force. It arises from Newton's third law of motion, which states that every action has an equal and opposite reaction. Whenever an object exerts a force on another object, the second object exerts a reaction force on the first object in the opposite direction.
The vertical reaction of the spacecraft on the astronaut is equal in magnitude but opposite in direction to the force that the astronaut exerts on the spacecraft, according to Newton's third law of motion.
The initial vertical acceleration of the spacecraft is 5g, so the force that the spacecraft exerts on the astronaut is F = ma = m(5g), where m is the mass of the astronaut.
Using the acceleration due to gravity on the moon, g = 1.62 m/s^2, we can calculate the force as:
F = m*(5g) = m*(51.62) = 8.1m N
Therefore, the vertical reaction of the spacecraft on the astronaut is equal in magnitude but opposite in direction, so it is:
R = -8.1*m N
Note that the negative sign indicates that the reaction force is in the opposite direction to the initial acceleration, which is upward in this case.
Hence, R = -8.1*m N is the reaction force.
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The centrifuge at NASA Ames Research Center has a radius of 8.8 m and can produce forces on its payload of 20 gs or 20 times the force of gravity on Earth. (a) What is the angular momentum of a 20-kg payload that experiences 10 gs in the centrifuge? (b) If the driver motor was turned off in (a) and the payload lost 10 kg, what would be its new spin rate, taking into account there are no frictional forces present?
(a) The angular momentum of a 20-kg payload experiencing 10 gs in a centrifuge with a radius of 8.8 m is 5,483 kg m^2/s. (b) If the payload loses 10 kg, the new spin rate taking into account no frictional forces present is 7.54 rad/s.
(a) The angular momentum of a rotating object is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
The moment of inertia for a point mass rotating in a circle is given by:
I = mr^2
where m is the mass of the object and r is the radius of the circle.
To calculate the angular momentum of the 20-kg payload that experiences 10 gs in the centrifuge, we first need to calculate the angular velocity of the payload. The force on the payload is 10 times the force of gravity on Earth, so the net force on the payload is:
F = ma
F = (10 × 9.8 m/s^2) × 20 kg
F = 1960 N
The net force on the payload is the centripetal force, which is given by:
F = mv^2/r
where v is the velocity of the payload.
Rearranging this equation to solve for v:
v = sqrt(Fr/m)
v = sqrt((1960 N) × (8.8 m) / (20 kg))
v = 33.2 m/s
The angular velocity of the payload is:
ω = v/r
ω = 33.2 m/s / 8.8 m
ω = 3.77 rad/s
Finally, we can calculate the angular momentum of the payload:
L = Iω
L = (mr^2)ω
L = (20 kg) × (8.8 m)^2 × 3.77 rad/s
L = 5,483 kg m^2/s
(b) When the payload loses 10 kg, its new moment of inertia becomes:
I' = m'r^2
I' = (10 kg) × (8.8 m)^2
I' = 774.4 kg m^2
Conservation of angular momentum tells us that:
L = Iω = I'ω'
where ω' is the new angular velocity of the payload.
Solving for ω':
ω' = (I/I')ω
ω' = ((20 kg) × (8.8 m)^2 × 3.77 rad/s) / ((10 kg) × (8.8 m)^2)
ω' = 7.54 rad/s
So, the new spin rate of the payload is 7.54 rad/s.
Therefore,(a) For a 20-kg payload experiencing 10 gs in a centrifuge with an 8.8 m radius, the angular momentum is 5,483 kg m^2/s. (b) If the payload's mass reduces by 10 kg without any frictional forces present, the new spin rate is 7.54 rad/s.
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An object that is 0.5 m above the ground has the same
amount of potential energy as a spring that is stretched
0.5 m. Each distance is then doubled.
How will the potential energies of the object and the
spring compare after the distances are doubled?
O The gravitational potential energy of the object will be
two times greater than the elastic potential energy of
the spring.
O The elastic potential energy of the spring will be four
times greater than the gravitational potential energy of
the object.
O The elastic potential energy of the spring will be two
times greater than the gravitational potential energy of
the object.
O The potential energies will remain equal to one
another.
The gravitational potential energy of the object will be two times greater than the elastic potential energy of the spring after the distances are doubled. The correct option is A.
The gravitational potential energy of an object is given by the formula:
PE = mgh
Where m is the mass of the object, g is the acceleration due to gravity and h is the height of the object above the reference point.
In this case, the height of the object is doubled, so the potential energy will also be doubled. Therefore, when the distance is doubled, the gravitational potential energy of the object will be two times greater than before.
The elastic potential energy of a spring is given by the formula:
PE = 1/2 kx^2
Where k is the spring constant and x is the displacement of the spring from its equilibrium position.
In this case, the displacement of the spring is doubled, so the potential energy will be four times greater than before. Therefore, option B is not correct.
Option C is also not correct because the potential energy of the spring will be four times greater than the gravitational potential energy of the object.
Option D is not correct because the potential energies of the object and the spring are not equal to one another when the distances are doubled.
Therefore, The correct answer is option A.
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Victoria ran around a circular field 3 times. If she ran a total
distance of 750 meters, what are the diameter and radius of
the field?
The diameter of the field is 79.62 m and the radius is 39.81 m.
What is diameter?A diameter of a circle is any straight line segment that passes through the center of the circle and whose endpoints lie on the circle.
To calculate the diameter and the radius of the field, we use the formula below.
Formula:
P = nπD..........................Equation 1Where:
P = Total distance covered by the girlD = Diameter of the fieldn = Number of times she ran through the fieldπ = PieFrom the question,
Given:
n = 3P = 750 meterπ = 3.14Substitute these values into equation 1 and solve for D
750 = 3×3.14×DD = 750/(3×3.14)D = 79.62 mThe radius of the field = D/2 = 79.62/2 = 39.81 m.
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In which stage is the individual aware of the problem and beginning to think
about changing but has made no commitment to change, as they still believe
that the positive aspects outweigh the negative aspects?
OA. Maintenance
OB. Precontemplation
OC. Action
OD. Contemplation
Answer:
B. Pre-contemplation
Explanation:
Hope this helps :)
A strip of lead metal initially with a length of 35cm is heated so that its temperature changes by 80°c. Find the change in length of the lead and its new length at the new temperature.
Answer:
The new length at the new temperature is approximately 35.0812cm.
Explanation:
Let's use the coefficient of linear expansion of lead, which is approximately 0.000029 per degree Celsius.
The change in length can be calculated using the formula:
ΔL = αLΔT
where:
ΔL = change in length
α = coefficient of linear expansion
L = initial length
ΔT = change in temperature
In this case, ΔT = 80°C, L = 35cm and α = 0.000029/°C.
ΔL = (0.000029/°C) x (35cm) x (80°C)
ΔL = 0.0812 cm
Therefore, the change in length is 0.0812 cm.
To find the new length, we add the change in length to the original length:
New length = 35cm + 0.0812cm
New length = 35.0812cm
So
A certain rigid aluminum container contains a liquid at a gauge pressure of P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure is Pa = 1.01 × 105 Pa. The volume of the container is V0 = 2.45 × 10-4 m3. The maximum difference between the pressure inside and outside that this particular container can withstand before bursting or imploding is ΔPmax = 2.35 × 105 Pa.
For this problem, assume that the density of air maintains a constant value of ρa = 1.20 kg / m3 and that the density of seawater maintains a constant value of ρs = 1025 kg / m3.
A) The container is taken from sea level, where the pressure of air is Pa = 1.01 × 105 Pa, to a higher altitude. What is the maximum height h in meters above the ground that the container can be lifted before bursting? Neglect the changes in temperature and acceleration due to gravity with altitude.
B)What is the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding?
The maximum height the container can be lifted before bursting is 970 meters above sea level, and the maximum depth the container can be taken before imploding is 35 meters below the surface of the ocean.
Gauge pressure is the pressure measured relative to the atmospheric pressure at a particular location. It does not take into account the atmospheric pressure and only represents the pressure above or below the atmospheric pressure.
A) To find the maximum height h in meters above the ground that the container can be lifted before bursting, we need to find the new gauge pressure at this higher altitude. We can use the relationship between pressure and altitude:
P = P0 + ρgh
where P is the gauge pressure at the new altitude, ρ is the density of air, g is the acceleration due to gravity (assumed constant), and h is the height above sea level. Solving for h, we get:
h = (P - P0) / (ρg)
We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the higher altitude can be found by adding this to the sea level pressure:
P = Pa + ΔPmax = 1.01 × 105 Pa + 2.35 × 105 Pa = 3.36 × 105 Pa
Substituting this into the equation above, along with the given values for ρ and g, we get:
h = (3.36 × 105 Pa - 2.02 × 105 Pa) / (1.20 kg/m3 × 9.81 m/s2) ≈ 970 meters
So, the maximum height the container can be lifted before bursting is approximately 970 meters above sea level.
B) To find the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding, we need to find the new gauge pressure at this depth. We can use a similar equation to the one used above, but with the density of seawater instead of the density of air:
P = P0 + ρsgd
where g is the acceleration due to gravity (assumed constant), d is the depth below the surface of the ocean, and ρs is the density of seawater. Solving for d, we get:
d = (P - P0) / (ρsg)
We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the maximum depth can be found by subtracting this from the sea level pressure:
P = P0 - ΔPmax = 2.02 × 105 Pa - 2.35 × 105 Pa = -0.33 × 105 Pa
(Note that this gives a negative value for pressure, which means the container will implode rather than burst.)
Substituting this into the equation above, along with the given values for ρs and g, we get:
d = (-0.33 × 105 Pa - 1.01 × 105 Pa) / (1025 kg/m3 × 9.81 m/s2) ≈ -35 meters
So, the maximum depth the container can be taken before imploding is approximately 35 meters below the surface of the ocean.
Therefore, The container can be lifted to a maximum height of 970 meters above sea level without bursting, and it can be submerged to a maximum depth of 35 meters without imploding.
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13. A solid has a mass of 200 g in air and when partly immersed in a certain liquid it has a mass of 160 g. Given that the relative density of the liquid is 0.80, calculate the volume of the solid immersed in the liquid.
The volume of the solid immersed in the liquid is 5 x 10⁻⁵ m³.
What is the volume of the solid?The volume of the solid is calculated as follows;
V = (Ws - Wa) / (ρg)
where;
Ws is the weight of the solid in airWa is the weight of the solid in liquidρ is the density of the solidg is gravityWs = 0.2 kg x 9.8 m/s²
Ws = 1.96 N
Wa = 0.16 kg x 9.8 m/s²
Wa = 1.568 N
ρ = 0.8 x 1000 g/km³ = 800 kg/m³
The volume is calculated as;
V = (1.96 - 1.568 )/(800 x 9.8)
V = 5 x 10⁻⁵ m³
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Which part of the Scientific Method is in the right order?
Answer:
Below
Explanation:
since I’m in biology, here are he exact steps from my textbook:
The Scientific Method:
A scientific method is a series of steps for investigating questions and testing ideas. There are several versions of the scientific method, but all versions are based on rational thinking, inquiry, and experimentation. The scientific method includes five main steps. Review the steps of the overall system before diving into each one.
1. Ask a Question:
The purpose of a scientific investigation is what you are trying to find out or the question you are trying to answer. An empirical observation (e.g., the sky is blue) will prompt an appropriate question (e.g., why is the sky blue?).
2. Do Background Research:
You have learned that science is a body of knowledge. It is important that you research what other scientists have already observed and discovered. Previous investigations into your topic may lead you to new questions that need answers. If the farmer wishes to know why his plants are dying, he would research reasons why that type of plant might not grow. The farmer might conduct this research at the library or a local garden center or on the Internet.
3. Form a Hypothesis:
A hypothesis is an explanation for a specific observation, phenomenon, or scientific problem that is based on scientific knowledge and can be tested by further investigation. After researching what other scientists already know, the farmer will need to form a hypothesis about what he thinks will happen. Forming a hypothesis involves an understanding of current scientific knowledge and creativity to look at the problem or question in a way that will lead to the predicted outcome. For instance, the farmer notices that the dying plants seem to be yellow and brown, so he could conclude that there are not enough nutrients in the soil. He would form the hypothesis, ”The lack of nutrients in the soil is causing the plants to die.”
4. Test with an Experiment:
An experiment allows you to test your hypothesis to determine if it is a correct or incorrect prediction of the outcome. There are many ways to test a hypothesis, but every experiment should have at least one variable that changes while the others stay the same or are controlled. This allows the experimenter to determine if a selected change will affect a specific factor in the way their hypothesis predicts. The farmer would then design and carry out a test to try to get an answer to the original question and observation. The farmer would record the data on a data sheet. He would also want to write down the steps he used to carry out his experiment in case it needs to be repeated. This is called the procedure. The farmer would make sure his procedure and data are accurately reported, so that he could share the information with others or repeat the procedure at a later time.
5. Analyze Data:
The analysis of data from an experiment compares known and unknown values in the data. The experiments are always repeated several times to make sure the results are valid. When an experiment is valid, it means that the results are consistent over time and reproducible by you or by another scientist, following the same procedure. Based on the results of the farmer’s experiment, he would analyze the data by creating charts or graphs of the growth of the plants over time.
6. Draw Conclusions:
Based on the analysis of the collected data, a scientist will refer back to the hypothesis and ask: Was the hypothesis correct or incorrect? Sometimes this is very simple and the conclusion is obvious. On occasion, finding that the hypothesis is incorrect will lead to new discoveries. Sometimes, the results are inconclusive, and the scientist must design a new experiment or complete further research. If the farmer finds that the data supports the original hypothesis, he may conclude that the lack of soil nutrients caused the plants to poorly grow (i.e., analysis shows that changing the amount of nutrient causes the plants to grow faster). On the other hand, the data might not support the original hypothesis (i.e., analysis shows that changing the amount of nutrient does not keep the plants from dying). In this case, he would try to change a different variable in the experiment, such as the amount of water, in order to retest his hypothesis.
A box rests on a horizontal, frictionless surface. Ali pushes on the box with a force of 18 N to the right and Amina pushes on the box with a force of 12 N to the left. The box moves 4.0 m to the right.
a. Find the work done by Ali,
b. Find the work done by Amina,
c. the net force
The work done by Ali is 0 N
The work done by Amina is 72 N
The net force is 6 N
What is the work done by Ali and Amina?The work done by a body is defined as the product of the force applied and the distance through which the force is applied.
Mathematically;
Work done = force * distanceThe work done by Ali and Amina respectively is calculated using the formula above:
The work done by Ali = 12 * 0
The work done by Ali = 0 N
The work done by Amina = 18 * 4
The work done by Amina = 72 N
Net force = 18 - 12
Net force = 6 N
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1. Which of the following makes Light waves unique compared to sound waves?
a. Light travels can move without a medium, unlike sound
b. Light's velocity is calculated with frequency and wavelength, unlike sound
c. Light can carry energy, unlike sound
d. Light's frequency can be altered, unlike sound
2. If a incident light ray approachs a mirror at an angle of 37 degrees from the perpendicular. What will be the angle of the reflected ray?
a. 18.5 degrees
b. 37 degrees
c. 53 degrees
d. 143 degrees
3. If light goes through a single slit, what will be the pattern that will appear on the target screen?
a. An alternating set of bright and dark bands of light will appear on the target screen
b. A large bright band will appear directly across from the slit, that gets dimmer farther away from the center
c. Two large bright bands will appear on the target screen, with less bright bands in between them
d. Two large bright bands appear very distant from each other on the target with nothing but dark bands in between them