Answer:
1) f(x) = 4·x² - 3·x + 6
2) f(x) = -2·x² + 5·x - 1
3) y = 2·(x - 3)² + 5
Step-by-step explanation:
1) The quadratic function that is represented by the points (0, 6), (2, 16), (3, 33) is found as follows
The general form of a quadratic function is f(x) = a·x² + b·x + c
Where, in (x, y), f(x) = y, and x = x
Therefore for the point (0, 6), we have;
6 = 0·x² + 0·x + c
c = 6
We have c = 6
For the point (2, 16), we have;
16 = a·2² + b·2 + 6
10 = 4·a + 2·b.............................(1)
For the point (3, 33), we have;
33 = a·3² + b·3 + 6
27 = 9·a + 3·b............................(2)
Multiply equation (1) by 1.5 and subtract it from equation (2), we have;
1.5 × (10 = 4·a + 2·b)
15 = 6·a + 3·b
27 = 9·a + 3·b - (15 = 6·a + 3·b) gives;
27 - 15 = 9·a - 6·a+ 3·b - 3·b
12 = 3·a
a = 12/3 = 4
a = 4
From equation (1), we have;
10 = 4·a + 2·b = 4×4 + 2·b
10 - 4×4 = 2·b
10 - 16 = 2·b
-6 = 2·b
b = -3
The function, f(x) = 4·x² - 3·x + 6
2) Where the points are (-1, -8), (0, -1), (1, 2), we have;
For point (-1, -8), we have -8 = a·(-1)² - b·(-1) + c = a - b + c......(1)
For point (0, 1), we have -1 = a×0² + b×0 + c = c.........................(2)
For point (1, 2), we have 2 = a×1²+ b×1 + c = a + b + c..............(3)
Adding equation (1) to equation (3) gives
-8 + 2 = a - b + c + a + b + c = 2·a + 2·c where, c = -1, we have
-8 + 2 = -6 = 2·a + 2
2·a = -6 + 2 = - 4
a = -8/2 = -2
From equation (3), we have;
2 = a + b + c
b = 2 - a - c = 2 - (-2) - (-1) = 2 + 2 + 1 = 5
f(x) = -2·x² + 5·x - 1
3) The equation of a parabola that has vertex (3, 5) and passing through the point (1, 13) is given by the vertex equation of a parabola
The vertex equation of a parabola is y = a(x - h)² + k
Where;
(h, k) = Vertex (3, 5)
(x, y) = (1, 13)
We have
13 = a·(1 - 3)² + 5
13 = a·(-2)² + 5
13 - 5 = a·(-2)² = 4·a
4·a = 8
a = 8/4 = 2
The equation is y = 2·(x - 3)² + 5.
A girl who normally gets A's didn't do the first assignment given on the first day of school and now has 0%. How many 95% grades will she need to achieve an average of 90% overall? The points for each assignment are based on what she scores.
Answer:
19 of 95% grades
Step-by-step explanation:
90= (0+95(x-1))/x
90x=0+95(x-1)
90x=95(x-1)
90x=95x-95
90x-95x=-95
-5x=-95
x=-95/-5
x=19
Use the discriminant to determine the number of real solutions to the equation. −4x^2=−8−10x
Answer:
4
Step-by-step explanation:
Answer:
Step-by-step explanation:
You don't get a free answer. I am, after all, a high school math teacher, so there has to be a lesson in with this.
The discriminant is part of the quadratic formula. It is:
[tex]b^2-4ac[/tex]. If this value is found to be > 0 and a perfect square, there are 2 real roots; if this value is found to >0 and not a perfect square, there are 2 complex roots; if this value is found to be = 0, then there is 1 real root with a multiplicity of 2; and finally, if this value is found to be < 0, then there are 2 imaginary roots. Also, it would help to know that, because we are dealing with the discriminant, which comes from the quadratic formula, and quadratics, by definition, have 2 solutions, you must have 2 solutions listed as the possible roots for the equation. Our equation is:
[tex]-4x^2=-8-10x[/tex] but in order to determine the a, b, and c for the discriminant, that equation has to be in standard form, set equal to 0:
[tex]-4x^2+10x+8=0[/tex]
From this we can see that a = -4, b = 10, and c = 8. Filling in the discriminant:
[tex]10^2-4(-4)(8)[/tex] which gives us a value of
100 - [4(-4)(8)] (don't forget orders of operation here!)
100 - (-128) = 100 + 128 = 228
This value is greater than 0 but is not a perfect square, so there are 2 complex roots. That means that there will be radicals in the solutions.
Select the correct answer.
Which phrase best describes taxable income?
A.
all income and wages received from working
B.
all income received
C.
adjusted gross income minus any allowable tax credits
D.
adjusted gross income minus any allowable tax deductions
E.
income from sources other than wages, such as interest and dividends
Answer:A
Step-by-step explanation:
The phrase can be described broadly as adjusted gross income (AGI) minus allowable tax deductions.
What is adjusted gross income ?"Adjusted gross income, or AGI, is your gross income minus certain adjustments. The IRS uses this number as a basis for calculating your taxable income. AGI can also determine which deductions and credits you may qualify for."
Since, Taxable income is the portion of your gross income used to calculate how much tax you owe in a given tax year.
It can be described broadly as adjusted gross income (AGI) minus allowable itemized or standard deductions.
Taxable income includes wages, salaries, bonuses, and tips, as well as investment income and various types of unearned income.
Hence, the phrase can be described broadly as adjusted gross income (AGI) minus allowable tax deductions.
Learn more about adjusted gross income visit:
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Jessie works at a car manufacturing plant. One day she installed a total of 46 axles, 2 in each car she worked on. She wants to know how many
cars she installed axles on. You can write an equation that relates the total number of cars, the total number of axles, and the number of axles
installed per car. This equation will have two known quantities and one unknown quantity.
Part A
Write an equation forj, the number of cars Jessie installed axles in.
BIŲ X, Font Sizes
EEE 를 를
!!!
Characters used: 0 / 15000
Answer:
Jessie instaled axels on 23 cars The equation: 2·j = 46Step-by-step explanation:
j - total number of cars she installed axles on
2 - number of axles she installed on one car
2·j - total number of axles she installed on
46 - total number of axles she installed on
2·j = 46 {divide both sides by 2}
j = 23Find the midpoint between two points on a number line if one of the points is at -7, and the other point is at 12.
A. 9.5
B. 5
C. -2
D. 2.5
Answer:
D
Step-by-step explanation:
The midpoint is the average of the 2 endpoints, that is
midpoint = [tex]\frac{-7+12}{2}[/tex] = [tex]\frac{5}{2}[/tex] = 2.5 → D
Could anyone help me with number 25 THANK YOU!!!
Answer:
ΔABC ~ ΔQPR by the Angle-Angle (AA) similarity theorem of two triangles
Step-by-step explanation:
The coordinates of the vertices are given as follows;
A = (1, 2), B =(9, 8), C = (1, 8)
P= (5, -3), Q = (-7, 6), R = (-7, -3)
The given dimensions of AB and PQ are 10, and 15 respectively
The, l lengths of the sides of triangles are found as follows;
[tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]
For segment BC, we have;
B =(9, 8), C = (1, 8)
(x₁, y₁) = (9, 8), (x₂, y₂) = (1, 8), substituting gives;
Length BC = 8
For length CA, C = (1, 8) A = (1, 2)
(x₁, y₁) = (1, 8)
(x₂, y₂) = (1, 2)
The length found by substituting the values for (x₁, y₁), (x₂, y₂) in the length equation gives; Length CA = 6
Given that length CA² + BC² = 8² + 6² = 64 + 36 = 100 = BA², we have by Pythagoras theorem, we have ΔABC is a right triangle
Similarly, for ΔQPR, we have;
Length QR, Q = (-7, 6), R = (-7, -3) = 9
Length PR, P= (5, -3), R = (-7, -3) = 12
QR² + PR² = 9² + 12² = 225 = 15² = PQ²
∴ ΔQPR is a right triangle
By comparing the ratio of the sides, we have;
cos(θ) = PR/PQ = 12/15 = 4/5, θ = cos⁻¹(4/5) = 36.9°
∠RPQ = 36.9°
sin(θ) = QR/PQ = 9/15 = 3/5
Similarly in triangle ΔABC, we have;
cos(θ) = BC/AB = 8/10 = 4/5
∠CBA = 36.9°
Therefore, ∠CBA ≅ ∠RPQ = 36.9°
Also ∠PRQ ≅ ∠BCA = 90° (Angle opposite hypotenuse side of right triangle
Therefore, ΔABC and ΔQPR are similar triangles by the Angle-Angle (AA) similarity theorem of two triangles.
Express the following in scientific notation: 0.0000079
Answer:
7.9 * 10 ^-6
Step-by-step explanation:
Move the decimal 6 places to the left so there is one number before the decimal
0.0000079
7.9
The exponent is -6 ( negative because we moved it to the left)
7.9 * 10 ^-6
Answer:
Hey there!
7.9 × 10-6 is your answer.
Hope this helps :)
Pls Answer A and B. You don’t need to explain. Thank you!!
trigonometry help got one right need help with another
Answer:
B. [tex] \frac{HI}{GI} [/tex]
Step-by-step explanation:
The trigonometric ratio formula for tangent of any angle in a right triangle is given as:
tan(θ) = [tex] \frac{opposite}{adjacent} [/tex]
Note: it is the length of the side opposite to the θ, and the length of the side adjacent to θ.
Thus, in the right triangle given, ∆GHI,
θ = <G
The length of side the opposite <G = HI
The length of the side adjacent to <G = GI
Therefore, the equivalent of tan(<G) = [tex] \frac{HI}{GI} [/tex]
help me please asap!!
Answer:
136^3 cm
Step-by-step explanation:
Big square:
5 × 4 × 6 = 20 × 6 = 120
Small rectangle:
7 - 5 = 2
2 × 2 × 4 = 4 × 4 = 16
Both:
120 + 16 = 136
The volume of this figure is 136 cm^3.
Hope this helped.
Answer:
Below
Step-by-step explanation:
First you can find the front area and just multiply it by the length
Find the area of the small square
A = lw
= (2)(2)
= 4 cm^2
Find the area of the large square
A = lw
= (6)(5)
= 30 cm^2
Now just multiply the area of the two by the length
34 x 4 = 136 cm^3
Hope this helps!
David is selling floral arrangements. Each arrangement uses 1 vase and 12 roses. Each vase costs David $2.00. Let C be the total cost of the arrangement and r be the cost of 1 rose. Which equation should David use to find the total cost of each arrangement? C = 12r + 2 12 = C + 2r C = 2r + 12 12C = r + 12
Answer:
C = 12r + 2Step-by-step explanation:
To model the equation for the cost of Each Arrangement.
We need to itemize all parameters needed.
An arrangement consists of
1. one vase
2. twelve roses
Given that 1 vase cost $2 and
The cost of one rose is r
Let the total cost of the arrangement be C
Hence C is the cost of the vase plus the cost of 12 roses combined, this is given as
[tex]C = 12r + 2[/tex]
Wrapping a Package It takes 70 inches of ribbon to make a bow and wrap the ribbon
round a box. The bow takes 32 inches of ribbon. The width of the box is 14 inches. What
the height of the box?
-14 in. -
First subtract the amount the bow takes from the total:
70 - 32 = 38 inches
The width is 14 on top and bottom so subtract 14 x 2 = 28 from 38:
38-28 = 10
Divide 10 by the 2 sides:
10/2 = 5
The height is 5 inches.
The formula for centripetal acceleration, a, is given below, where v is the velocity of the object and r is the object's distance from the center of the circular path.
This is the same as writing v = sqrt(ar)
===========================================
Work Shown:
[tex]a = \frac{v^2}{r}\\\\ar = v^2\\\\v^2 = ar\\\\v = \sqrt{ar}\\\\[/tex]
I multiplied both sides by r to isolate the v^2 term, then I applied the square root to fully isolate v.
50 points! I would appreciate an explanation, I actually want to know how to do this. Thanks! :P
Answer:
1.
(a) The Domain is the set of inputs of the function.
Considering that the function takes a period of 3 weeks (21 days), the domain is [0, 21], once we can't evaluate what happens after the 21st day.
[tex]\text{Domain is } [0, 21][/tex]
Otherwise, it could be [tex][0, \infty)[/tex]
Note: We include 0 and 21.
Once the greatest balance was $400, it will not exceed $400, either it doesn't show negative values.
[tex]\text{Range is } [0, 400][/tex]
Note: We include 0 and 400.
(b)
Once the greatest balance was $400, when x=0, it seems that the y-value is half of $400, therefore, approximately $200. It also represents the initial value, the amount of money when she opened the account.
(c)
[tex]f(x)=B(d)[/tex]
[tex]B(12)=0[/tex]
(d)
It is in segment 4.
The balance equal to zero means that the y-value of the graph is zero, therefore in the x-axis.
Enter the coordinates of the point
on the unit circle at the given angle.
60°
Answer:
(1/2, [tex]\frac{\sqrt{3} }{2}[/tex])
Step-by-step explanation:
Don't totally trust me on this...
A school system is reducing the amount of dumpster loads of trash removed each week. In week 5, there were 40 dumpster loads of waste removed. In week 10, there were 30 dumpster loads removed. Assume that the reduction in the amount of waste each week is linear. Write an equation in function form to show the amount of trash removed each week. A f(x) = −2x + 40. B f(x) = 2x + 40 C f(x) = −2x + 50 D f(x) = 2x + 50
Answer:
The answer is A f(x) = -2x + 40
Step-by-step explanation:
it has a negative 2 because the dumps are decreasing by 2 every week and x is the amount of weeks and + 40 because that is the amount you started with.
please do the steps Solve for d: 1/6d-8=5/8 2. Solve for x: 3x-4+5x=10-2z 3. Solve for c: 7(c-3)=14 4. Solve for m: 11(m/22+3/44)=87m+m 5. Solve for k: ck+5k=a
Answer:
d = 55.5
x = 1
c = 11
m = [tex]\frac{1}{122}[/tex]
k = [tex]\frac{a}{(c + 5)}[/tex]
Step-by-step explanation:
Sorry, the formatting is slightly hard to understand, but I think this is what you meant.
Q1.
[tex]\frac{1}{6}[/tex]d - 8 = [tex]\frac{5}{8}[/tex] x 2
Step 1. Simplify.
[tex]\frac{5}{8}[/tex] x 2 = [tex]\frac{5}{8}[/tex] x [tex]\frac{2}{1}[/tex] = [tex]\frac{10}{8}[/tex]
Step 2. Cancel out the negative 8.
[tex]\frac{1}{6}[/tex]d - 8 = [tex]\frac{10}{8}[/tex]
+ 8 to both sides (do the opposite: [tex]\frac{1}{6}[/tex]d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)
[tex]\frac{1}{6}[/tex]d = [tex]\frac{10}{8}[/tex] + 8
Step 3. Simplify.
[tex]\frac{10}{8}[/tex] + 8 = [tex]\frac{10}{8}[/tex] + [tex]\frac{8}{1}[/tex] = [tex]\frac{10}{8}[/tex] + [tex]\frac{64}{8}[/tex] = [tex]\frac{74}{8}[/tex] = [tex]\frac{37}{4}[/tex]
Step 4. Cancel out the [tex]\frac{1}{6}[/tex].
[tex]\frac{1}{6}[/tex]d = [tex]\frac{37}{4}[/tex]
÷ [tex]\frac{1}{6}[/tex] from both sides (do the opposite: d is multiplied by [tex]\frac{1}{6}[/tex] right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)
÷ [tex]\frac{1}{6}[/tex] = x 6
So....
x 6 to both sides
d = [tex]\frac{37}{4}[/tex] x 6 = [tex]\frac{37}{4}[/tex] x [tex]\frac{6}{1}[/tex] = [tex]\frac{222}{4}[/tex] = [tex]\frac{111}{2}[/tex] = 55.5
Step 5. Write down your answer.
d = 55.5
Q2.
3x - 4 + 5x = 10 - 2x × 3
Step 1. Simplify
3x - 4 + 5x = 3x + 5x - 4 = 8x - 4
10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x
Step 2. Cancel out the negative 6x
8x - 4 = 10 - 6x
+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)
14x - 4 = 10
Step 3. Cancel out the negative 4
14x - 4 = 10
+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)
14x = 14
Step 4. Divide by 14
14x = 14
÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])
x = 1
Step 5. Write down your answer.
x = 1
Q3.
7(c - 3) = 14 × 4
Step 1. Expand the brackets
7(c - 3) = (7 x c) - (7 x 3) = 7c - 21
Step 2. Simplify
14 x 4 = 56
Step 3. Cancel out the negative 21
7c - 21 = 56
+ 21
7c = 56 + 21
7c = 77
Step 4. Cancel out the ×7
7c = 77
÷ 7
c = 77 ÷ 7
c = 11
Step 5. Write down your answer.
c = 11
Q4.
11([tex]\frac{m}{22}[/tex] + [tex]\frac{3}{44}[/tex]) = 87m + m × 5
Step 1. Expand the brackets
11([tex]\frac{m}{22}[/tex] + [tex]\frac{3}{44}[/tex]) = (11 x [tex]\frac{m}{22}[/tex]) + (11 x [tex]\frac{3}{44}[/tex]) = ([tex]\frac{11}{1}[/tex] x [tex]\frac{m}{22}[/tex]) + ([tex]\frac{11}{1}[/tex] x [tex]\frac{3}{44}[/tex]) = [tex]\frac{11m}{22}[/tex] + [tex]\frac{33}{44}[/tex] = [tex]\frac{m}{2}[/tex] + [tex]\frac{3}{4}[/tex]
Step 2. Simplify.
87m + m x 5 = 87m + 5m = 92m
Step 3. Cancel out the add [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] + [tex]\frac{3}{4}[/tex] = 92m
- [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] = 92m - [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] = [tex]\frac{92m}{1}[/tex] - [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] = [tex]\frac{368m}{4}[/tex] - [tex]\frac{3}{4}[/tex]
[tex]\frac{m}{2}[/tex] = [tex]\frac{368m - 3}{4}[/tex]
Step 4. Cancel out the ÷ 4
[tex]\frac{m}{2}[/tex] = [tex]\frac{368m - 3}{4}[/tex]
x 4
2m = 368m - 3
Step 5. Cancel out the 368m
2m = 368m - 3
- 368m
-366m = - 3
Step 6. Cancel out the × -366
-366m = -3
÷ -366
m = [tex]\frac{-3}{-366}[/tex]
m = [tex]\frac{1}{122}[/tex]
Step 7. Write down your answer.
m = [tex]\frac{1}{122}[/tex]
Q5.
ck + 5k = a
Step 1. Factorise
ck + 5k = (c × k) + (5 × k) = (c + 5) x k = k(c + 5)
Step 2. Cancel out the × (c + 5)
k(c + 5) = a
÷ (c + 5)
k = a ÷ (c + 5)
k = [tex]\frac{a}{(c + 5)}[/tex]
please help me on number 4!!
Answer: B) 5 inches
======================================================
Explanation:
1 ft = 12 in
9 ft = 108 in ... multiply both sides by 9
9 ft, 9.5 in = 108 in + 9.5 in = 117.5 in
The board's length of 9 ft, 9.5 inches is the same as 117.5 inches.
It's cut into sections of 11.25 inches, so we have (117.5)/(11.25) = 10.44 approximately which rounds down to 10.
Having 10 sections of length 11.25 inches each, takes up 10*11.25 = 112.5 inches so far. That leaves 117.5 - 112.5 = 5 inches as the remaining piece of the board.
50 apples cost 25$ how much would 75$ apples cost?
Answer:
100
Step-by-step explanation:
Hey there!
First, to find the cost of one apple, 50 ÷ 25, which equals 2.
At this point, i am not very sure if you meant to say 75 apples, or $75 apples, so I am just going to give both solutions.
If you meant 75 apples: 75 x 2 = $150
If you meant $75 apples: $75 ÷ 2 = 37.5
Since it isn't realistic to buy 37 apples and one half, round it to 37 apples.
Hope this helps!
Have a great day!
Drag a vertex of the triangle to change its shape.
Double-click or double-tap a vertex or side to prevent it from
changing.
Problem: Construct a triangle with interior angle
measures of 60° and 75°.
What is the measure of the third angle?
O 30°
2C = 41°
O 45°
48°
9.2
10
50°
ZA = 49°
6.0 ZB = 90°
Answer:
The correct option is;
45°
Step-by-step explanation:
By angle sum theorem, we have that the sum of angles in a triangle = 180°
Therefore, we have;
When the interior angles of the triangle are constructed to be 60° and 75°, we have by the angle sum theorem;
The third angle + 60° + 75° = 180°
Which gives;
The third angle = 180°- 60° - 75° = 180°- 135° = 45°
The measurement of the third angle by the angle sum theorem will be 45°
The correct option is ∠third angle = 45°.
The area of a triangle is 30
square inches. The height is
5 in. Find the base.
Answer:
12 inches
Step-by-step explanation:
A=1/2bh
30=1/2b5
(30*2)/5=b
B=12
Name the quadrants in which of the following points (3, 0) (-9,-3) lie.
Answer:
(3,0) lie between quadrants I and II. (-9, -3) lie in quadrant III
Write down inequalities,that are satisfied by these sets of integers between -10 and 10
1,2,3,4,5,6,7,8,9,10
-3,-4,-5,-6,-7,-8,-9,-10
9,10
-10
Answer:
Below
Step-by-step explanation:
Notice that x is between 10 and -10 but takes only the values that are integers.
The inequalities:
● we can write an inequality that includes all these values.
● -10 《 x 《 10
This is a possible inequality
Multiply both sides by 2 and you will get a new one:
● -20 《 2x 《 20
You can multiply it by any number to generate a new inequality.
Or you can add or substract any number.
The following expression is a polynomial: 4x + 5y True False
Answer: False. This expression is a monomial!
Answer:
false
Step-by-step explanation:
it is molonomial
simplify (b^4)^3 because the nun of the answers answer my question
Answer:
b^12
Step-by-step explanation:
(b^4)^3
We know that x^y^z = x^(y*z)
b^4^3 = b^*4*3) = b^12
If the amount of VAT paid for an item at 13% was Rs 390, at what price was the item sold?
Answer:
Step-by-step explanation:
Let the price of the item = Rs x
13% of x = 390
[tex]\frac{13}{100}*x=390\\\\\\x = 390*\frac{100}{13}\\\\\\[/tex]
x = Rs. 3000
The combined weight of three basset hounds is 185 pounds. The two smaller dogs weigh the same. The difference between the larger weight and the smaller weight is 20 pounds. How many pounds does the largest dog weigh?
Answer:
75 pounds
Step-by-step explanation:
(x) + (x) + (x+20) = 185
3x + 20 = 185
3x = 165
x = 55
Large dog = 55 + 20 = 75
Select the correct answer.
Simplify the following expression.
(3x^2 - 11x - 4) – (x – 2) (2x + 3)
Answer choices
5x^2 - 12x - 10
x^2 - 10x + 2
x^2 + 10x - 2
x^2 – 12x – 10
Answer:
x^2 -10x+2
Step-by-step explanation:
(3x^2 - 11x - 4) – (x – 2) (2x + 3)
FOIL
(3x^2 - 11x - 4) – (2x^2-4x+3x-6)
Combine like terms
(3x^2 - 11x - 4) – (2x^2 -x-6)
Distribute the minus sign
3x^2 - 11x - 4 – 2x^2 +x+6
Combine like terms
x^2 -10x+2
A family has four children. What is the probability that two children are girls and two are boys? Assume the the probability of having a boy (or a girl) is 50%.
Answer:The first issue one most notice is the words “at least” We are trying to find the probability of at least 2 girls.
The five possible outcomes for girls are 0,1,2,3,4. The odds of 1 girl out of 4 is .25 and the odds of 1 boy out of 4 is .25 (same as the odds of 3 out of 4 girls). Therefore the odds of 1 OR 3 girls must be .5 because 1 girl and 3 girls each has a .25 probability. If the probability of (1 OR 3 girls) equals .5, then the probability of 2 girls must be a different number.
The probability of 2 or more girls, is the sum of the probability of 4 girls (.06125)(—-.5 to the 4th power—— ), plus the probability of 3 girls (.25)——(the same as the probability of 1 boy)—- plus the probability of 2 girls. Since we know the probability of zero boys is .0625 (again, .5 to the 4th power) and the probability of 1 boy is .25 (the same as the probability of 3 girls )———then the probability of 2 girls is ((1 minus (the sum of the probability of 0 OR 1 boys) plus the (sum of the probability of 3 or 4 girls)), or 1-((.0625+.25)+(.0625+.25)), or .375. We had to derive the probability of two from the other known probabilities. Therefore .375+.25+.0625=.6875 is the probability of both AT LEAST 2 girls and also NO MORE than 2 boys. Notice this adds up to 1.375 because the probability of the central number 2 (i.e., .375) appears on both sides.
At what rate per annum will N250 amount to N330 in 4 years.
Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{8 \: \% \: }}}}}[/tex]Step-by-step explanation:
Given,
Principal ( P ) = N 250
Time ( T ) = 4 years
Amount ( A ) =N 330
Rate ( R ) = ?
First, finding the Interest :
According to definition of Amount ,
Amount = Principal + Interest
plug the values
⇒[tex] \sf{330 = 250 + I}[/tex]
Move i to left hand side and change it's sign
⇒[tex] \sf{ - I = 250 - 330}[/tex]
Calculate
⇒[tex] \sf{ - I = - 80}[/tex]
Change the signs of the both equation
⇒[tex] \sf{I = 80 }[/tex]
Interest = 80
Finding the rate :
Simple Interest = [tex] \sf{ \frac{PTR}{100} }[/tex]
plug the values
⇒[tex] \sf{80 = \frac{250 \times 4 \times R}{100} }[/tex]
Multiply the numbers
⇒[tex] \sf{80 = \: \frac{1000 \: R}{100} }[/tex]
Apply cross product property
⇒[tex] \sf{1000R = 100 \times 80}[/tex]
Multiply the numbers
⇒[tex] \sf{1000R = 8000}[/tex]
Divide both sides of the equation by 1000
⇒[tex] \sf{ \frac{1000R}{1000} = \frac{8000}{1000} }[/tex]
Calculate
⇒[tex] \sf{R = 8 \: \% \: }[/tex]
Thus, Rate = 8 %
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Let's learn about Principal , Interest , Time , Rate and Amount :
Principal = The money which is borrowed or deposited is called principal.Interest = The additional amount of money which is paid by borrower to the lender is called interest.Time = The duration of time for which principal us deposited or borrowed is termed as time period.Rate = The condition under which the insterest is charged is called rate.Amount = The sum of principal and Interest is called an amount.Hope I helped!
Best regards!!