20. How does the graph of
g(x) = 2x + 3 differ from the
graph of f(x) = 2x?
A It is moved up 3 units.
B It is moved down 3 units.
C It is moved right 3 units.
D It is moved left 3 units.

Answer:

[tex]24[/tex]

Step-by-step explanation:

[tex] \frac{4(7 - 13)}{3 + ( - 4)} \times \frac{2 - (6 - 2)}{1} = \frac{28 - 52}{3 - 4} = \frac{ - 24}{ - 1} = 24[/tex]

Hope this helps ;) ❤❤❤

Answer:

24 (Can I have a brainlist, please?)

Step-by-step explanation:

4(7-13)/3 + (-4)2-(6-2)

First we solve the problems in the paraenthesis:

4(7-13)/3 + (-4)2-(6-2)

4(-6)/3 + -4 × 2 -(4)

Now we multiply the ones that are needed to be multiplied:

4(-6)/3 + -4 × 2 -(4)

-24/3 + -8 -(4)

-24/3 + 32

Now we divide:

-24/3 + 32

-8 + 32

And finally we solve the last:

-8 + 32

= 24

Hope that helped!

Answer:

91.8°

Step-by-step explanation:

180-88.2=91.8°

Answer: 17

Step-by-step explanation: 204/12 = 17

Answer:

204÷12=17

lexie used 17 per miles

Step-by-step explanation:

that if am right lol

Answer:

2x2x2x5 is your answer

Step-by-step explanation:

40 is a composite number. 40 = 1 x 40, 2 x 20, 4 x 10, or 5 x 8. Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40. Prime factorization: 40 = 2 x 2 x 2 x 5, which can also be written 2³ x 5.

I hope this helps you.

Answer:

2х2х2×5

Step-by-step explanation:

Answer:

f(x) = 24 miles per gallon

Step-by-step explanation:

car manufacturer claims that their car can get 33 miles per gallon minus the speed factor

f (×) =33 -0.15x

For a car going 60 mph

f (×) =33 -0.15x

X=60 mph

f (×) =33 -0.15x

f(x) = 33-0.15(60)

f(x) = 33-9

f(x) = 24 miles per gallon

Answer:

a. Equilateral

b. Scalene

c. Isosceles

d. Right

e. Obtuse

f. Acute

Step-by-step explanation:

pf

Answer: f(x)=x2-4x

Step-by-step explanation:

Answer:

x = -14/3

Step-by-step explanation:

-2(3x + 1) = 26

Distribute the -2 to the number in the parentheses.

-6x - 2 = 26

Add 2 to both sides of the equation.

(-6x - 2) + 2 = 26 + 2

-6x = 28

Divide both sides of the equation by -6.

(-6x)/-6 = 28/-6

x = -28/6

x = -14/3

Answer:

Step-by-step explanation:

"Tamara runs 5 miles each week"

Let Tamara runs 'x' weeks then equation that represents the total distance covered by Tamara will be,

1). y = 5x

2). Here 'y' is directly proportional to the number of weeks 'x'.

3). And the graph when plotted will start from 0. Therefore, graph (1) will be the graph for the given equation.

"Tamara runs 5 minutes more than she walks each day."

1). If Tamara walks 'x' minutes daily and she runs for y minutes then relation between x and y will be,

y = x + 5

2). y and x are non proportional.

3). Graph will have y-intercept = 5

Answer:

ik somebody answer already n stuff

Step-by-step explanation:

Let's use an equation to solve this problem.

Since they are consecutive integers, if we say that the first number is [tex]x[/tex], then the next two numbers (three dimensions in a rectangular prism) are [tex]x+1[/tex] and [tex]x+2[/tex] respectively.

[tex]x*(x+1)*(x+2)=4896[/tex]

[tex]x*(x+1)=x^2+x[/tex]

[tex](x^2+x)*(x+2)=x^3+2x^2+2x[/tex]

[tex]x^3+3x^2+2x=4896[/tex]

[tex]x^3+3x^2+2x-4896=0[/tex]

[tex]x=16[/tex]

B is the correct answer.

Answer:

Part A: The average car length is 9.1 feet to the nearest tenth foot

Part B: The line would be 9100 feet to contained 1000 cars

Step-by-step explanation:

* Lets explain how to solve the problem

# Part A:

- There were 62 cars in a line that stretched 567 feet

- The cars are lined up bumper-to-bumper

- That means there is no empty spaces between the cars

* To find the average length of the car we will divide the length of

 the line by the numbers of the cars

∵ The average car length = length of the line/number of cars

∵ The length of the line is 567 feet

∵ The numbers of the cars is 62 cars

∴ The average car length = 567/62 = 9.1 feet

* The average car length is 9.1 feet to the nearest tenth foot

# Part B:

- There are 1000 cars

- We need to find the length of line which contained the cars

∵ The average car length = length of the line/number of cars

∵ The average of car length is 9.1 feet

∵ The number of the cars is 1000 cars

∴ 9.1 = length of the line/1000

- Multiply both sides by 1000

∴ The length of the line = 9.1 × 1000 = 9100 feet

∴ The line would be 9100 feet to contained 1000 cars

Answer:

they are integers and also rational numbers

They are both similar but not entirely the same.

The first expression y/x means we divide y over x. We divide two values here and we are not subtracting first before division. This expression is useful for when you want to find the variation constant in the equation y = kx (for direct proportion equations).

The other expression (y2-y1)(x2-x1) is where we first subtract the y values, and do the same for the x values, before we divide. This computes the slope of the line through the two points (x1,y1) and (x2,y2). It's also useful to figure out the average rate of change (one application of slope). For problems involving time versus distance, the average rate of change is the average speed in which the object is moving.

Answer: -450 since negative minus a positive makes it even more negative

Answer: a. 1

Step-by-step explanation:

There are 4 walls in total, and each wall measures 5ft high, 8ft wide

5 × 8=40 ft² for each wall

4×40=160 ft² for 4 walls

------------------

stated one gallon cover 160 ft²

160 ÷ 160=1 gallon

Hope this helps!! :)

Please let me know if you have any question

Answer:

$1.50

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

half are choclate so the rest is 50% and 1/3 is vanilla so 2/3 are strawberry and chocolate

1/3 portion of the cupcakes are strawberry with chocolate frosting.

An individual part or share of something is called as portion.

It also refers to the divide something into parts.

Now it is given that,

Portion of chocolate cupcakes = 1/2

Portion of strawberry cupcakes = 1/2

Of the strawberry cupcakes.

frosted with vanilla frosting = 1/3

frosted with chocolate frosting = 1-1/3 =  2/3

Since, 1/2 portion of all the cupcakes are strawberry cakes and out of 1/2, 1/3 are frosted with vanilla frosting and 2/3 are frosted with chocolate frosting.

strawberry cupcakes frosted with chocolate frosting = 2/3 of 1/2 = 2/6

⇒strawberry cupcakes frosted with chocolate frosting = 1/3

Hence,1/3 portion of the cupcakes are strawberry with chocolate frosting.

Learn more about portions :

https://brainly.com/question/18884319

#SPJ2

Step-by-step explanation:

here is the ans

please check

Answer: 357.50

Step-by-step explanation:

Multiply 11.0 and 32.5 without the decimal points.

It should look like this: 110 × 325

After you solve this equation, count the numbers after the decimal points in 11.0 and 32.5. There is one number after the decimal point in 11.0, and one number after the decimal point in 32.5. In the number 35750, count from the last number and add a decimal point right before the 5.

Hope it helps!!

Answer:

Step-by-step explanation:

To get the remainder of (x-(-1)) we need to evaluate for -1,

[tex](-1)^{11}+101=-1+101=100[/tex]

So if this is divided by x+1, it means that we can write

[tex]x^{11}+101=(x+1)P(x)+R\\\\so \ for \ x = -1\\\\(-1)^{11}+101=100=0*P(-1)+R=R\\\\\text{So the remainder is 100 !!}[/tex]

thanks

Answer:

$64

Step-by-step explanation:

We can set up a percentage proportion to find the value Caleb's groceries before tax.

[tex]\frac{1.60}{x} = \frac{2.5}{100}[/tex]

We can cross multiply to find the value of x.

[tex]100\cdot1.60=160\\\\160\div2.5=64[/tex]

So the original cost before tax was $64.

Hope this helped!

Answer:

$1.64

Step-by-step explanation:

We need to find the before tax price so let that be x

100-2.5% = 97.5% (since this is the reduction before the sale)

Turn this percentage into a decimal so 0.975

To find x we must remember this price multiples 0.975 to give us $1.60

x * 0.975 = 1.60

x = 1.60 / 0.975

x = 1.64 (2dp)

Answer:to what ?

Step-by-step explanation:

Answer:

acb

Step-by-step explanation:

Answer:

1) at ( 0,0) : y = x/2.   at(-3-1) : y = -1.   at(-3,3) : y = 2x +9

2) DNE ( does not exist )

Step-by-step explanation:

The general equation of tangent line

y - y1 = m( x - x1 )

attached below is the detailed solution on how i derived the answers above

Answer:

A. 1.2 > -6.9

Step-by-step explanation:

The reasoning is because positive numbers are ALWAYS greater than negative numbers, and in this question, 1.2 is higher than -6.9. Hope this helped!

Answer:

1.2> - 6.9

Step-by-step explanation:

1.2 is greater than (>) -6.9

Answer:

[tex]\mathbf{R(\tau) = \dfrac{A^2}{2} cos (\omega \tau)}[/tex]

Step-by-step explanation:

To find Autocorrelation function of the following periodic function

Given that:

X(t) = A sin(wt +θ)

with the period T=2π/w , A, θ, and w are constants.

The autocorrelation function  of periodic function with period  and phase θ can be expressed as:

[tex]R(\tau) = \dfrac{1}{T} \int \limits ^{T/2}_{-T/2} x(t) *x(t - \tau) \ dt[/tex]

[tex]R(\tau) = \dfrac{A^2}{T} \int \limits ^{T/2}_{-T/2} \ A sin ( \omega t + \theta)*A sin [ \omega (t- \tau ) + \theta] \ dt[/tex]

where;

[tex]sinAsin B = \dfrac{1}{2}[cos (A-B) -cos (A+B)][/tex]

Then;

[tex]R(\tau) = \dfrac{A^2}{2T} \int \limits ^{T/2}_{-T/2} \ cos ( \omega t- \omega \tau + \theta - \omega t - \theta) - cos (\omega t - \omega \tau + \theta + \omega t + \theta) \ dt[/tex]

[tex]R(\tau) = \dfrac{A^2}{2T} \int \limits ^{T/2}_{-T/2} \ cos ( - \omega \tau ) - cos (2 \omega t - \omega \tau + 2 \theta) \ dt[/tex]

[tex]R(\tau) = \dfrac{A^2}{2T} \int \limits ^{T/2}_{-T/2} \ cos ( - \omega \tau ) \ dt - \dfrac{1}{2T} \int \limits ^{T/2}_{-T/2} cos (2 \omega t - \omega \tau + 2 \theta) \ dt[/tex]

The term 2  is the cosine wave of frequency and the phase = [tex]- w \tau + 2 \theta[/tex]

if we integrate that, the second term in the expansion for R(t) = zero

As such,

[tex]R(\tau) = \dfrac{A^2}{2T} \int \limits^{T/2}_{-T/2} \ cos ( - \omega \tau ) dt[/tex]

where ;

[tex]cos (-\omega \tau )[/tex]is constant

Then :

[tex]R(\tau) = \dfrac{A^2}{2T} cos (-\omega \tau) [t]^{T/2}_{-T/2}[/tex]

[tex]R(\tau) = \dfrac{A^2}{2T} cos (-\omega \tau) \times [\dfrac{T}{2}+ \dfrac{T}{2}][/tex]

[tex]R(\tau) = \dfrac{A^2}{2T} cos (-\omega \tau) \times [\dfrac{2T}{2}][/tex]

[tex]R(\tau) = \dfrac{A^2}{2T} cos (-\omega \tau) \times T[/tex]

[tex]R(\tau) = \dfrac{A^2}{2} cos (-\omega \tau)[/tex]

since [tex]cos (-\omega \tau) = cos (\omega \tau)[/tex]

[tex]\mathbf{R(\tau) = \dfrac{A^2}{2} cos (\omega \tau)}[/tex]

Answer: OPTION A

Step-by-step explanation:

The distance between any number is always positive so we should apply the absolute value.

The distance between numbers=number 1-number2 (or vise versa, and that is why we need absolute value)

In your question, the two numbers are 3/4 and 2. Applying to the expression above, the distance between two numbers should be |3/4-2| or |2-3/4|.

The only option in your case is |3/4-2| and this is it.

Hope this helps!! :)

Please let me know if you have any question

Answer:

It will take Abbey 10 seconds to move 8.5 meters

Step-by-step explanation:

100 cm makes one meter

So 85 cm=85/100

85 cm. = 0.85 meter

So Abbey travels 0.85 meters every second

One second= 0.85 meters

Let the unknown time be x

X= 8.5 meters/0.85

X= 10 seconds

It will take Abbey 10 seconds to move 8.5 meters