2- write a scheme function that returns a list containing all elements of a given list that satisfy a given premise. for example, (fun (lambda (a) (< a 10)) ‘(1 2 12 14 15)) should return (1 2).

Answers

Answer 1

The `fun` function takes a premise and a list, and returns a new list containing elements of the input list that satisfy the given premise.

Here is a scheme function that takes a premise and a list, and returns a new list containing all elements of the input list that satisfy the given premise:
```
(define (fun premise lst)
 (cond ((null? lst) '())         ; base case: empty list
       ((premise (car lst))     ; if premise is true for first element
        (cons (car lst)         ; include it in the result
              (fun premise (cdr lst))))
                               ; recur on the rest of the list
       (else (fun premise (cdr lst))))) ; premise is false, recur on rest of list
```
Here's how to use the function:
```
> (fun (lambda (a) (< a 10)) '(1 2 12 14 15))
(1 2)
```
In this example, the premise is `(lambda (a) (< a 10))`, which tests whether a given element is less than 10. The input list is `(1 2 12 14 15)`, and the expected output is `(1 2)`. The `fun` function filters out all elements of the input list that are not less than 10, and returns the result list.

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Related Questions

how do bi systems differ from transaction processing systems?

Answers

Business intelligence (BI) systems and transaction processing systems (TPS) are two different types of information systems that are commonly used by organizations to manage their operations. While both systems are designed to handle data, they differ in their purpose, structure, and functionality.

Transaction processing systems are designed to handle day-to-day operational transactions such as sales, purchases, and inventory updates. TPS is primarily concerned with recording and processing individual transactions and generating reports that provide detailed information about each transaction. TPS are usually structured as online transaction processing (OLTP) systems, which means that they process transactions in real-time as they occur. TPS are characterized by high transaction volumes, low data complexity, and strict data accuracy requirements.

On the other hand, BI systems are designed to support strategic decision-making by providing executives with timely and accurate information about their organization's performance. BI systems collect and analyze data from multiple sources, such as TPS, external databases, and other data sources, to identify trends, patterns, and insights that can help organizations make better decisions. BI systems are usually structured as online analytical processing (OLAP) systems, which means that they use multidimensional databases to store and analyze data. BI systems are characterized by low transaction volumes, high data complexity, and the need for flexible data analysis capabilities.

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: In Principles that guide process, it is stated that we should examine our approach to development and be ready to change it as required. Which of the 8 principles focuses on that fact? 1 & 2 1 & 3 1 & 3 & 8 none of the above

Answers

Principle 3 focuses on the fact that we should examine our approach to development and be ready to change it as required.

What does the third principle state?

To successfully navigate development endeavors, Principle 3 - "Be Ready to Adapt" - proposes that we must assess our strategies regularly and remain flexible enough to adjust them when necessary.

The principle asserts that approaches should not be treated as strict guidelines with no room for variation. Stated within Principle 3: "Process is not a religious experience and dogma has no place in it." Thus, it becomes imperative to modify our methods depending on constraints imposed by multiple factors such as the problem itself, people involved, or project specifications.

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Consider the code segment below.
PROCEDURE Mystery (number)
{
RETURN ((number MOD 2) = 0)
}
Which of the following best describes the behavior of the Mystery PROCEDURE?

Answers

The Mystery procedure behaves as a function that determines whether a given number is even or odd by returning a Boolean value.

How does a mystery procedure behave

The Mystery system takes a single parameter range, and the expression range MOD 2 calculates the remainder while number is split by way of 2.

If this the rest is zero, it means that range is even, and the manner returns actual (considering the fact that zero in Boolean context is fake or false, and the expression variety MOD 2 = 0 evaluates to proper whilst number is even).

If the the rest is 1, it means that quantity is true, and the technique returns fake (seeing that 1 in Boolean context is proper, and the expression variety MOD 2 = 0 evaluates to false whilst number is unusual).

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CSM Tech Publishing has four buildings connected by fiber-optic cabling and 12 subnets connected by several routers running RIPv2. One building has flooded, so employees and their equipment have moved to a temporary building on the same site. A router with three interfaces in the flooded building was also damaged. There are no spare routers, and the router can't be replaced for several days. Five servers running Windows Server 2016 have been moved to the temporary building. One of these servers is available as a spare or for other purposes. What can you do to solve your routing problem? Be specific about how you would carry out your solution, and state whether you would use static or dynamic routing

Answers

To solve the routing problem in the temporary building, I would configure the spare server as a temporary router. I would connect the three interfaces of the damaged router to three network switches in the temporary building.

Then, I would assign IP addresses to each interface of the spare server and configure it to perform routing functions using a dynamic routing protocol like RIPv2. This would allow the spare server to exchange routing information with the other routers in the network and maintain connectivity between the subnets. By using dynamic routing, the spare server would dynamically update its routing table based on the network changes, ensuring efficient and automated routing without the need for manual configuration.

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Use Rice's theorem, which appears in Problem 5.28, to prove the undecidability of each of the following languages. Aa. INFINITETM = {(M)|M is a TM and L(M) is an infinite language}. b. {{M) M is a TM and 1011 € L(M)}. c. ALLTM = {( MM is a TM and L(M) = *}.

Answers

Rice's theorem states that any non-trivial property of a language, i.e., a property that is not shared by all languages, is undecidable. This means that it is impossible to design an algorithm that can decide whether a given Turing machine accepts a language with a particular non-trivial property.

Using Rice's theorem, we can prove the undecidability of each of the following languages:

a. INFINITETM = {(M)|M is a TM and L(M) is an infinite language}.

To prove that INFINITETM is undecidable, we must show that the property of having an infinite language is non-trivial. This is true because there exist Turing machines that accept infinite languages and Turing machines that accept finite languages.

For instance, the language {a^n | n is a positive integer} is infinite, while the language {a} is finite. Since there are TMs with both properties, the property of having an infinite language is non-trivial.

Now suppose there exists a decider D for INFINITETM. We can use D to construct a decider for the Halting problem, which is known to be undecidable.

Given an input (M, w), we construct a new Turing machine M' that ignores its input and simulates M on w. If M accepts w, then M' enters an infinite loop.

Otherwise, M' halts immediately. Now, we can run D on M'. If D accepts M', then L(M') is infinite, which means M accepts w, and so we return "yes". Otherwise, L(M') is finite, which means M does not accept w, and so we return "no".

Thus, we have a decider for the Halting problem, which contradicts its undecidability. Hence, INFINITETM must be undecidable.

b. {{M) M is a TM and 1011 € L(M)}.

To prove that {{M) M is a TM and 1011 € L(M)} is undecidable, we must show that the property of containing the string 1011 is non-trivial. This is true because there exist Turing machines that accept the string 1011 and Turing machines that do not accept the string 1011.

For instance, the language {1011} is finite, while the language {0,1}^1011{0,1}^ is infinite. Since there are TMs with both properties, the property of containing the string 1011 is non-trivial.

Now suppose there exists a decider D for {{M) M is a TM and 1011 € L(M)}. We can use D to construct a decider for the language A_TM, which is known to be undecidable.

Given an input (M, w), we construct a new Turing machine M' that ignores its input and simulates M on w followed by the string 1011. Now, we can run D on M'. If D accepts M', then L(M') contains 1011, which means M accepts w, and so we return "yes". Otherwise, L(M') does not contain 1011, which means M does not accept w, and so we return "no".

Thus, we have a decider for A_TM, which contradicts its undecidability. Hence, {{M) M is a TM and 1011 € L(M)} must be undecidable.

c. ALLTM = {( M | M is a TM and L(M) = *}.

To prove that ALLTM is undecidable, we must show that the property of accepting all strings is non-trivial. This is true because there exist Turing machines

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What is true of foreign keys. Select the best answer from the following. A foreign key is a column or columns that is the same as the primary key of some table in the database. A foreign is created by giving it the same name as the column that it matches in the primary (parent) table. A foreign key is only found in Many-To-Many relationships and is the mechanism that makes this relationship possible in a relational database. Foreign keys are not used in relational database design

Answers

The statement "A foreign key is a column or columns that is the same as the primary key of some table in the database" is true.

What is the  foreign keys?

A foreign key functions as a connection between a particular table within a database and another table, utilizing a column or set of columns. The connection between two tables is established by the reference of the primary key in one table to the foreign key in the other.

To create a foreign key in the table, the column(s) must be specified to match the primary key of the parent table. Although it is customary to name the foreign key the same as the corresponding column in the primary table.

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what is the 95onfidence interval of heating the area if the wattage is 1,500?

Answers

A confidence interval is a statistical range of values that is likely to contain the true value of a population parameter, such as the mean heating value of a material. The interval is calculated from a sample of measurements, and its width depends on the sample size and the desired level of confidence.

For example, a 95% confidence interval for the heating value of a material might be 4000 ± 50 BTU/lb, meaning that we are 95% confident that the true mean heating value of the population falls between 3950 and 4050 BTU/lb based on the sample data.

To determine the 95% confidence interval of heating the area with a wattage of 1,500, we need to know the sample size, mean, and standard deviation of the heating data. Without this information, we cannot accurately calculate the confidence interval.

However, we can provide some general information about confidence intervals. A confidence interval is a range of values that we are 95% confident contains the true population mean. The larger the sample size and smaller the standard deviation, the narrower the confidence interval will be.

In the case of heating the area with a wattage of 1,500, if we assume that the sample size is large enough and the standard deviation is small, we can estimate the confidence interval. For example, a possible 95% confidence interval might be (25, 35) degrees Celsius. This means that we are 95% confident that the true population mean of heating the area with a wattage of 1,500 falls between 25 and 35 degrees Celsius.

It's important to note that without more information about the data, this is just a hypothetical example and the actual confidence interval may be different. Additionally, it's always best to consult a statistical expert to ensure accuracy in calculating confidence intervals.

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Explain the following situation. In Europe, many cell phone service providers give away for free what would otherwise be very expensive cell phones when a service contract is purchased. Explain why might a company want to do that?

Answers

Cell phone service providers in Europe often give away expensive cell phones for free when a service contract is purchased.

Many cell phone service providers in Europe offer free cell phones as an incentive to customers who sign a service contract.

This strategy is known as a loss leader, where a company offers a product at a lower price or for free to attract customers and generate revenue from other sources. This strategy can benefit the company by attracting customers, ensuring long-term commitment, and increasing overall revenue through the contract's monthly fees and usage charges.In this case, the cell phone company expects to make a profit from the service contract over the duration of the contract. By offering a free phone, the company is able to lure in more customers and increase their subscriber base, which in turn increases their revenue. Additionally, giving away expensive phones can create a positive brand image for the company, leading to more customers and better customer loyalty.

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Suppose that an algorithm performs f(n) steps, and each step takes g(n) time. How long does the algorithm take? f(n)g(n) f(n) + g(n) O f(n^2) O g(n^2)

Answers

The total time the algorithm takes is given by f(n) multiplied by g(n), or f(n)g(n). This is because for each of the f(n) steps, the algorithm takes g(n) time to complete.

It is important to note that this is just a general formula and may not accurately represent the actual running time of the algorithm. The big-O notation can be used to give an upper bound on the running time of the algorithm. For example, if g(n) is a polynomial function of degree k, then the running time can be expressed as O(n^k), and if f(n) is a polynomial function of degree m, then the running time can be expressed as O(n^(m+k)).

if an algorithm performs f(n) steps and each step takes g(n) time, then the total time the algorithm takes is the product of the two functions: f(n) * g(n).

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jonny wants to buy a 1024 node machine. what fraction of parallel execution can be sequential for achieving the scaled speedup of 512?

Answers

For achieving the scaled speedup of 512, only about 0.1998% of the program can be executed sequentially. The vast majority of the program must be executed in parallel to achieve such a high speedup.

The scaled speedup S is given by:
S = N / (1 + (N-1)*F)
where N is the number of processors (nodes) and F is the fraction of the program that must be executed sequentially.
We are given S = 512 and N = 1024, and we want to find F.
Substituting the given values, we get:
512 = 1024 / (1 + (1024-1)*F)
Simplifying and solving for F, we get:
F = (1023/1024) / 511
F ≈ 0.001998
Therefore, for achieving the scaled speedup of 512, only about 0.1998% of the program can be executed sequentially. The vast majority of the program must be executed in parallel to achieve such a high speedup.


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when discussing functions we can refer to the name, return type and the types of the formal parameters. what subset of these three makeup the function signature?

Answers

The function signature is a crucial aspect of any function because it helps to define the function's behavior and how it can be used. It essentially tells us what inputs the function expects, what it will do with those inputs, and what output it will produce.

When we talk about functions, we often refer to the name of the function, the return type, and the types of the formal parameters. These three elements together make up what is known as the function signature.

The name of the function is an important part of the signature because it allows us to identify the function and call it by name. The return type tells us what kind of value the function will produce when it is called, while the types of the formal parameters describe the kind of data that the function expects as input.

Together, these three elements make up the function signature and provide us with a clear understanding of what the function does and how it can be used. When working with functions, it is essential to understand the function signature and how it impacts the behavior of the function.

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what is the main purpose of a software-defined product?

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The main purpose of a software-defined product is to provide flexibility, scalability, and easier management of resources through automation and programmability.

In a software-defined product, the underlying hardware is abstracted, allowing users to configure and control the system using software applications. This enables the efficient use of resources and reduces the dependency on specific hardware components.
In conclusion, software-defined products offer a more adaptable and cost-effective approach to managing technology infrastructure, catering to the dynamic needs of businesses and organizations in today's rapidly evolving digital landscape. By utilizing software-defined solutions, organizations can enhance their agility, optimize resource usage, and streamline management processes, leading to improved overall efficiency and productivity.

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IT 120 Homework 5 Page 2 of 2 4. (16pts) The overall IP datagram is 1130 bytes and assume there are no options in the network layer hender or the transport layer hender for any of the protocols a) (2pts) What are the following values based on the information above? Total Length field in the IPv4 the Payload Length field for the IPv6 b) (Spts) Determine what the amount of data is being sent for each of the protocols below Remember the base hender for IPv6 is 40bytes, the standard header for IPv4 is 20bytes, the UDP header is bytes, and the TCP header is 20bytes, Transport Protocols UDP TCP Network IPv4 Protocols IPv6 c) (5pts) During the review of IPv6 there was great concern about the larger base header for IPv6 verses IPv4 and how this would impact transmission. Using the information from part a. determine the overhead for each of the 4 boxes in the diagram. Please show results with 2 decimal places for full credit Transport Protocols UDP TCP Network IPv4 Protocols IPv6 d) (4pts) Include a standard wired Ethernet frame and calculate the overhead, to 2 decimal points, for IPv6 using TCP datagram without options. You must show your work to get full credit

Answers

The homework problem asks to calculate various values and overhead for IPv4 and IPv6 with TCP/UDP transport protocols, and Ethernet frame overhead for IPv6 with TCP.

a) The Total Length field in the IPv4 header would be 1130 bytes, and the Payload Length field for the IPv6 header would be 1090 bytes.

b) For IPv4 with TCP, the amount of data being sent would be 1090 - 20 - 20 = 1050 bytes.

For IPv4 with UDP, it would be 1090 - 20 - 8 = 1062 bytes.

For IPv6 with TCP, it would be 1090 - 40 - 20 = 1030 bytes.

For IPv6 with UDP, it would be 1090 - 40 - 8 = 1042 bytes.

c) For IPv4 with TCP, the overhead would be (1130 - 1050) / 1130 * 100 = 7.08%.

For IPv4 with UDP, it would be (1130 - 1062) / 1130 * 100 = 5.98%.

For IPv6 with TCP, it would be (1130 - 1030) / 1130 * 100 = 8.85%.

For IPv6 with UDP, it would be (1130 - 1042) / 1130 * 100 = 7.85%.

d) The standard Ethernet frame overhead is 18 bytes (preamble and start frame delimiter = 8 bytes, destination and source addresses = 12 bytes, length/type field = 2 bytes).

For IPv6 with TCP datagram without options, the overhead would be (1130 + 40 + 20 + 18) / 1130 * 100 = 6.37%.

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consider a computer system that has a cache with 4096 blocks each block can store 16 bytes, and the memory is byte addressable. What will be the value stored in the TAG field of the cache block that holds the memory block containing the address Ox3FBCF:

Answers

The cache block's TAG field that stores the memory block holding the address Ox3FBCF will be encoded in 16-bit binary format, representing the most significant bits of the address.

How to solve

In order to ascertain the value residing in the TAG field, it is necessary to compute the number of bits needed to express the memory address. 4

We can cleverly indicate that the cache contains 2^12 blocks by noting that it has 4096 blocks.

To represent each byte within a block, we require 4 bits since 16 bytes can be accommodated in each block.

The memory address can be adequately expressed using 16 bits, which is the sum of 12 and 4 bits.

Therefore, the cache block's TAG field that stores the memory block holding the address Ox3FBCF will be encoded in 16-bit binary format, representing the most significant bits of the address.

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how would you assign a tuple to variable mytuple?

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A tuple is an ordered, immutable collection of objects in Python. It is defined using parentheses and can contain any combination of data types. Tuples are often used to store related but different types of data together, and can be indexed or sliced like lists.

To assign a tuple to the variable "mytuple", you simply need to use the assignment operator "=" followed by the tuple values enclosed in parentheses. Here is an example:

mytuple = (1, 2, 3, "apple", "orange", True)

In this example, we have assigned a tuple containing six elements to the variable "mytuple". The tuple contains three integers, two strings, and a boolean value. Once the tuple is assigned to the variable, we can access its elements by using indexing or slicing.

It is important to note that tuples are immutable, which means that once they are created, their values cannot be changed. This makes tuples useful for storing data that should not be modified. Additionally, tuples can be used as keys in dictionaries due to their immutability.

In summary, to assign a tuple to the variable "mytuple", use the "=" operator followed by the tuple values enclosed in parentheses. Tuples are useful for storing data that should not be modified and can be used as keys in dictionaries.
Hi! To assign a tuple to the variable "mytuple", you can follow these simple steps:

1. Start with the variable name "mytuple".
2. Use the equal sign (=) to assign the tuple to the variable.
3. Create the tuple using parentheses () and separate the elements with commas.

Here's an example:

python
mytuple = (1, 2, 3, 4)


In this example, a tuple containing four integers (1, 2, 3, and 4) is assigned to the variable "mytuple".

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Show all steps needed for Booth algorithm to perform (a)x(b) where b is the multiplier: I. a=(-21) and b= (+30) II. a=(+30) and b=(-21) III. a=(+13) and b= (-32)

Answers

The results of performing (a) × (b) using the Booth algorithm are: I. (-21) × (+30) = (-64), II. (+30) × (-21) = (-30), III. (+13) × (-32) = (+0).

I. a = (-21) and b = (+30):

Step 1: Convert the numbers to their binary representation:

a = (-21)10 = (-10101)2

b = (+30)10 = (+11110)2

Step 2: Extend the sign bit of a by one position to the left:

a = (-10101)2 = (-010101)2

Step 3: Initialize the product P and the multiplicand A:

P = 0

A = (-010101)2

Step 4: Perform the following steps for each bit of the multiplier, starting from the least significant bit:

Bit 0: Multiplicand A is shifted right, and the least significant bit of the multiplier is examined.

      Since bit 0 is 0, no action is taken.

Bit 1: Multiplicand A is shifted right, and the least significant bit of the multiplier is examined.

      Since bit 1 is 1, subtract the original value of a from the shifted A:

      A = A - a = (-010101)2 - (-10101)2 = (-111010)2

Bit 2: Multiplicand A is shifted right, and the least significant bit of the multiplier is examined.

      Since bit 2 is 0, no action is taken.

Bit 3: Multiplicand A is shifted right, and the least significant bit of the multiplier is examined.

      Since bit 3 is 1, subtract the original value of a from the shifted A:

      A = A - a = (-111010)2 - (-10101)2 = (-1000000)2

Bit 4: Multiplicand A is shifted right, and the least significant bit of the multiplier is examined.

      Since bit 4 is 0, no action is taken.

Step 5: The final product is obtained by combining A and P:

Product = (P || A) = (0 || -1000000)2 = (-01000000)2 = (-64)10

Therefore, (-21) × (+30) = (-64).

II. a = (+30) and b = (-21):

Performing the steps similar to the previous case, we have:

a = (+30)10 = (+11110)2

b = (-21)10 = (-10101)2

a = (+011110)2

P = 0

A = (+011110)2

Bit 0: No action

Bit 1: A = A - a = (+011110)2 - (+11110)2 = (+000000)2

Bit 2: No action

Bit 3: A = A - a = (+000000)2 - (+11110)2 = (-11110)2

Bit 4: No action

Final product: (-11110)2 = (-30)10

Therefore, (+30) × (-21) = (-30).

III. a = (+13) and b = (-32):

a = (+13)10 = (+1101)2

b = (-32)10 = (-100000)2

a = (+01101)2

P = 0

A = (+01101)2

Bit 0: No action

Bit 1: A = A - a = (+01101)2 - (+1101)2 = (+00000)2

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Design and implement an iterator to flatten a 2d vector. It should support the following operations: next and hasNext. Example:Vector2D iterator = new Vector2D([[1,2],[3],[4]]);iterator. Next(); // return 1iterator. Next(); // return 2iterator. Next(); // return 3iterator. HasNext(); // return trueiterator. HasNext(); // return trueiterator. Next(); // return 4iterator. HasNext(); // return false

Answers

In 3D computer graphics, 3D modeling is the process of developing a mathematical coordinate-based representation of any surface of an object (inanimate or living) in three dimensions via specialized software by manipulating edges, vertices, and polygons in a simulated 3D space.[1][2][3]

Three-dimensional (3D) models represent a physical body using a collection of points in 3D space, connected by various geometric entities such as triangles, lines, curved surfaces, etc.[4] Being a collection of data (points and other information), 3D models can be created manually, algorithmically (procedural modeling), or by scanning.[5][6] Their surfaces may be further defined with texture mapping.

given a queue q of integer elements, please write code to check if the elements are:

Answers

This code assumes that the queue contains only integer elements, and that the queue is implemented using the built-in queue module in Python.

Here is an example code in Python to check if the elements of a queue are in non-descending order:

def isNonDescending(queue):

   prev = None

   while not queue.empty():

       current = queue.get()

       if prev is not None and current < prev:

           return False

       prev = current

   return True

In this code, we define a function called isNonDescending that takes a queue queue as its parameter. We initialize a variable prev to be None, which will store the previous element in the queue. We then use a loop to remove elements from the queue one by one using the get() method. For each element current in the queue, we check if it is less than the previous element prev.

If it is, we immediately return False, indicating that the elements are not in non-descending order. If the loop completes without returning False, we return True, indicating that the elements are in non-descending order.

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We want to make sure that when we add into the Friend table, the tuple is also inserted into the Friend table. Write stored procedure "insert_friend" that takes two input parameters (ID1 and ID2) of type INT as the ID of highschooler and insert two tuples in the Friend. Make sure to insert the tuples if they do not already exist in the Friend table. For example, we run "call insert_friend (1934, 1661);"BELOW IS THE SQL CODE/* Delete the tables if they already exist */DROP DATABASE IF EXISTS social_network;CREATE DATABASE social_network;USE social_network;drop table if exists Highschooler;drop table if exists Friend;drop table if exists Likes;/* Create the schema for our tables */create table Highschooler(ID int, name text, grade int);create table Friend(ID1 int, ID2 int);create table Likes(ID1 int, ID2 int);/* Populate the tables with our data */insert into Highschooler values (1510, 'Jordan', 9);insert into Highschooler values (1689, 'Gabriel', 9);insert into Highschooler values (1381, 'Tiffany', 9);insert into Highschooler values (1709, 'Cassandra', 9);insert into Highschooler values (1101, 'Haley', 10);insert into Highschooler values (1782, 'Andrew', 10);insert into Highschooler values (1468, 'Kris', 10);insert into Highschooler values (1641, 'Brittany', 10);insert into Highschooler values (1247, 'Alexis', 11);insert into Highschooler values (1316, 'Austin', 11);insert into Highschooler values (1911, 'Gabriel', 11);insert into Highschooler values (1501, 'Jessica', 11);insert into Highschooler values (1304, 'Jordan', 12);insert into Highschooler values (1025, 'John', 12);insert into Highschooler values (1934, 'Kyle', 12);insert into Highschooler values (1661, 'Logan', 12);insert into Friend values (1510, 1381);insert into Friend values (1510, 1689);insert into Friend values (1689, 1709);insert into Friend values (1381, 1247);insert into Friend values (1709, 1247);insert into Friend values (1689, 1782);insert into Friend values (1782, 1468);insert into Friend values (1782, 1316);insert into Friend values (1782, 1304);insert into Friend values (1468, 1101);insert into Friend values (1468, 1641);insert into Friend values (1101, 1641);insert into Friend values (1247, 1911);insert into Friend values (1247, 1501);insert into Friend values (1911, 1501);insert into Friend values (1501, 1934);insert into Friend values (1316, 1934);insert into Friend values (1934, 1304);insert into Friend values (1304, 1661);insert into Friend values (1661, 1025);insert into Friend select ID2, ID1 from Friend;insert into Likes values(1689, 1709);insert into Likes values(1709, 1689);insert into Likes values(1782, 1709);insert into Likes values(1911, 1247);insert into Likes values(1247, 1468);insert into Likes values(1641, 1468);insert into Likes values(1316, 1304);insert into Likes values(1501, 1934);insert into Likes values(1934, 1501);insert into Likes values(1025, 1101);

Answers

Here is the stored procedure "insert_friend" that takes two input parameters (ID1 and ID2) of type INT as the ID of highschooler and inserts two tuples in the Friend table if they do not already exist:
DELIMITER $$
CREATE PROCEDURE insert_friend(IN ID1 INT, IN ID2 INT)
BEGIN
   IF NOT EXISTS (SELECT * FROM Friend WHERE ID1 = ID1 AND ID2 = ID2) AND NOT EXISTS (SELECT * FROM Friend WHERE ID1 = ID2 AND ID2 = ID1) THEN
       INSERT INTO Friend (ID1, ID2) VALUES (ID1, ID2), (ID2, ID1);
   END IF;
END$$
DELIMITER ;
To use this stored procedure, you can simply call it with the two ID parameters you want to add as friends, like this:
CALL insert_friend(1934, 1661);
This will insert the tuple (1934, 1661) and its reciprocal (1661, 1934) into the Friend table if they do not already exist.

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I am stationary in a reference system but if my reference system is not an inertial reference system, then, relative to me, a system that is an inertial reference system must:
a. remain at rest.
b. move with constant velocity.
c. be accelerating.
d. be none of the above.

Answers

The correct answer is (b) move with constant velocity.

An inertial reference system is a frame of reference in which a body remains at rest or moves with constant velocity unless acted upon by a force. In contrast, a non-inertial reference system is a frame of reference in which a body may appear to move even when no external forces are acting upon it due to the presence of fictitious forces.

If a reference system is non-inertial, then any object that appears to move in that reference system may actually be subject to fictitious forces. However, if there exists an inertial reference system relative to the non-inertial reference system, then any object that is at rest or moves with constant velocity relative to the inertial reference system will also appear to be at rest or move with constant velocity in the non-inertial reference system, without being subject to fictitious forces.

Therefore, relative to an observer in a non-inertial reference system, an inertial reference system must move with constant velocity to be free from fictitious forces.

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Copy and paste your code from the previous code practice. If you did not successfully complete it yet, please do that first before completing this code practice.

After your program has prompted the user for how many values should be in the list, generated those values, and printed the whole list, create and call a new function named diffList. In this method, accept the list as the parameter. Inside, you should add up the negatives of all the values in the list and then return the result back to the original method call. Finally, print that difference of values.

Sample Run
How many values to add to the list:
8
[117, 199, 154, 188, 155, 147, 111, 197]
Total -1268

My Previous Code:
import random

def buildList(num1, num2):

for i in range(num2):

num1.append(random.randint(100, 199))

return num1

x = int(input("How many values to add to the list: "))

list = []

buildList(list , x)

print(list)

list.sort()

print(list)

Answers

The diffList() function is called with the list as a parameter, and the resulting difference of negative values is printed to the console.

Here's the updated code:

```python
import random

def buildList(num1, num2):
   for i in range(num2):
       num1.append(random.randint(100, 199))
   return num1

def diffList(lst):
   negative_sum = 0
   for num in lst:
       negative_sum += (-1 * num)
   return negative_sum

x = int(input("How many values to add to the list: "))
list = []
buildList(list , x)
print(list)

negative_total = diffList(list)
print("Total", negative_total)
```In this updated code, I added the new function `diffList`, which takes a list as input, calculates the sum of the negative values of the list, and returns the result. After generating the list using `buildList`, I called the `diffList` function and printed the result as "Total".

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characters in c/c are only 8 bits and therefore can address anywhere. group of answer choices true false

Answers

The statement "characters in c/c are only 8 bits and therefore can address anywhere" is false.

While it is true that characters in C/C++ are represented using 8 bits (or 1 byte), this does not mean that they can address anywhere. The memory address space of a computer system is much larger than 8 bits, and it is not possible for a single character to address anywhere in memory.

In fact, in C/C++, characters are typically used as basic building blocks for larger data types, such as strings or arrays. These larger data types are then used to store and manipulate more complex data structures in memory.

It is also worth noting that the size of a character in C/C++ is not fixed at 8 bits. The C/C++ standard allows for implementation-defined character sizes, and some systems may use larger or smaller character sizes depending on their specific hardware architecture and design.

In summary, while characters in C/C++ are typically represented using 8 bits, they cannot address anywhere in memory. The memory address space of a computer system is much larger than 8 bits, and characters are typically used as building blocks for larger data types.

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True/False: The edge with the lowest weight will always be in the minimum spanning tree

Answers

The statement "The edge with the lowest weight will always be in the minimum spanning tree" is true. True.

In a weighted undirected graph, a minimum spanning tree (MST) is a tree that spans all the vertices of the graph with the minimum possible total edge weight.

The edges of an MST are chosen in such a way that they form a tree without any cycles, and the sum of the weights of the edges in the tree is as small as possible.

The process of constructing an MST using Kruskal's algorithm or Prim's algorithm, the edge with the lowest weight is always considered first.

This is because, in order to create a tree with minimum weight, we need to start with the edge that has the smallest weight.

By choosing the edge with the lowest weight first, we can guarantee that we are on the right track towards building an MST.

As we proceed, we add edges to the MST in increasing order of their weights, while ensuring that no cycle is formed.

This ensures that the MST that is constructed at the end contains the edge with the lowest weight, and all other edges are selected in such a way that they don't form any cycles and have minimum weights.

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the process of working with the value in the memory at the address the pointer stores is called?

Answers

The process of working with the value in the memory at the address the pointer stores is called "dereferencing" a pointer. In this process, you access the memory location pointed to by the pointer and retrieve or modify the value stored there. Here's a step-by-step explanation:

1. Declare a pointer variable: A pointer is a variable that stores the memory address of another variable. It enables you to indirectly access and manipulate the data stored in the memory.

2. Initialize the pointer: Assign the memory address of the variable you want to work with to the pointer. This can be done using the address-of operator (&).

3. Dereference the pointer: Use the dereference operator (*) to access the value in the memory at the address the pointer stores. This allows you to read or modify the value indirectly through the pointer.

4. Perform operations: Once you've accessed the value through the pointer, you can perform various operations, such as arithmetic, comparisons, or assignments, depending on your specific needs.

5. Manage memory: It's essential to manage memory carefully when working with pointers, as improper handling can lead to memory leaks or crashes.

Remember, working with pointers and memory requires precision and attention to detail, as it involves direct manipulation of memory addresses and their values.

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t1 leased lines run at a speed of about ________. t1 leased lines run at a speed of about ________. 10 mbps 1 mbps 250 kbps 45 mbps

Answers

T1 leased lines run at a speed of approximately 1.5 Mbps (megabits per second). T1 leased lines, also known as DS1 lines. This type of connection is typically used for data transmission and is commonly utilized by businesses and organizations that require reliable and secure network connectivity.

T1 leased lines are also often used for voice communication, such as for telephone systems, as they can carry up to 24 voice channels simultaneously.

While T1 lines may seem relatively slow compared to more modern technologies such as fiber optic connections or T3 leased lines, they still offer a number of benefits. For example, T1 leased lines are generally considered to be highly reliable, as they use dedicated circuits that are not shared with other users.

Additionally, T1 lines can be easily expanded to support additional bandwidth as needed, making them a flexible and scalable solution for businesses that anticipate growth or changes in their connectivity needs. Overall, T1 leased lines offer a dependable and cost-effective solution for organizations that require reliable and secure connectivity.

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modify the extended_add procedure in section 7.5.2 to add two 256-bit (32-byte) integers. data vall BYTE '8' val2 BYTE '9' . code mov ah,0 mov al, vall sub al, val2 = ; AX ; AX aas ; AX 0038h = OFFh FFO9h save the Carry flag FF39h restore the Carry flag i pushf or al,30h popf ; AX = i

Answers

To modify the extended_add procedure to add two 256-bit integers, you need to change the loop counter to 32, since we will process the integers 8 bytes at a time (32 pairs of 8 bytes). You also need to define two arrays of 32 bytes each to hold the two 256-bit integers, and a third array of 32 bytes to hold the result.

How can you modify the extended_add procedure to add two 256-bit integers in Assembly language?

To modify the extended_add procedure in section 7.5.2 to add two 256-bit (32-byte) integers, you can use the following code:

.data
val1 QWORD 0x1234567890ABCDEF
val2 QWORD 0x9876543210FEDCBA
result QWORD ?

.code
extended_add PROC
pushf ; Save the flags
xor rax, rax ; Clear the accumulator
mov rcx, 4 ; Loop counter
loop_start:
mov rdx, 0 ; Clear the carry flag
mov r8, [val1 + rcx*8] ; Load 8 bytes from val1
adc rax, r8 ; Add 8 bytes to the accumulator
mov r8, [val2 + rcx*8] ; Load 8 bytes from val2
adc rax, r8 ; Add 8 bytes to the accumulator
mov [result + rcx*8], rax ; Store 8 bytes in result
sub rcx, 1 ; Decrement loop counter
jnz loop_start ; Loop until all 32 bytes are processed
popf ; Restore the flags
ret
extended_add ENDP

In this code, we define two 64-bit (8-byte) integers val1 and val2, and a 64-bit integer result to hold the sum of the two integers. The extended_add procedure takes no arguments and returns no value, but modifies the contents of result.

The procedure starts by pushing the flags onto the stack to save their values. It then clears the accumulator (rax) to prepare for the addition. The loop counter (rcx) is set to 4, since we will process the integers 8 bytes at a time (4 pairs of 8 bytes).

Inside the loop, we load 8 bytes from val1 and add them to the accumulator using the adc (add with carry) instruction. We then load 8 bytes from val2 and add them to the accumulator again using adc. The carry flag is cleared before each addition to ensure that any carry from the previous addition is accounted for.

Finally, we store the 8-byte sum in result and decrement the loop counter. We continue looping until all 32 bytes have been processed. After the loop, we restore the flags by popping them from the stack, and return from the procedure.

To test the procedure, you can call it from your main program like this:

mov ecx, LENGTHOF result ; Set the loop counter to 8
lea rsi, result ; Load the address of result
call extended_add ; Call the extended_add procedure
; Result is now the sum of val1 and val2

This will call the extended_add procedure to add val1 and val2, and store the result in the result variable. You can then use the result variable as needed in your program.

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If a function of a class is static, it is declared in the class definition using the keyword static in its ____.
a. return type b. parameters
c. heading d. main function

Answers

If a function of a class is declared as static, it means that it belongs to the class rather than an instance of the class. This means that it can be called without creating an object of the class. When declaring a static function in a class definition, the keyword "static" should be included in the function's heading.

The function's return type and parameters should also be included in the heading, just like any other function. However, since the function is static, it is associated with the class rather than a specific object of the class. This means that the function can be called using the class name, rather than an object instance. In summary, when declaring a static function in a class definition, the keyword "static" should be included in the function's heading along with the return type and parameters.

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(Count positive and negative numbers and compute the average of numbers) Write a program that reads an unspecified number of integers, determines how many positive and negative values have been read, and computes the total and average of the input values (not counting zeros). Your program ends with the input 0. Display the average as a floating-point number. Sample Run 1 Sample Output 1: Enter an integer, the input ends if it is 0: 1 Enter an integer, the input ends if it is 0: 2 Enter an integer, the input ends if it is 0: -1 Enter an integer, the input ends if it is 0: 3 Enter an integer, the input ends if it is 0: 0 The number of positives is 3 The number of negatives is 1 The total is 5 The average is 1. 25 Sample Run 2 Sample Output 2: Enter an integer, the input ends if it is 0: 0 No numbers are entered except 0

Answers

The program prompts the user to enter integers until they input 0. It counts the number of positive and negative values, computes the total sum, and calculates the average (excluding zeros).

If no numbers are entered except 0, it displays an appropriate message. The main code uses a while loop to repeatedly read the input and update the variables. Finally, it prints the counts, total, and average values based on the entered numbers.

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a problem with live systems forensics in which data is not acquired at a unified moment is:

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A problem with live systems forensics in which data is not acquired at a unified moment is that it may result in "inconsistencies and inaccuracies" in the acquired data.

Live systems are constantly changing and updating, which means that any evidence collected may not be entirely representative of the state of the system at any given point in time.

Furthermore, if data is not acquired at a unified moment, it can be difficult to piece together a timeline of events, which can make it challenging to identify the root cause of an issue or to trace the actions of a particular user or process. To address this issue, forensic investigators may use techniques such as memory analysis or network traffic analysis to help piece together a more complete picture of what was happening on the system at a particular point in time. They may also use tools that can help to track changes and updates to the system over time, such as file system analysis tools or system log analysis tools. Ultimately, the goal is to gather as much information as possible in order to build a complete and accurate picture of the events that occurred on the system, even if that information was not acquired at a unified moment.

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find the indicated derivative by finding the first few derivatives and recognizing the pattern that occurs. d87 dx87 (sin(x))

Answers

The 87th derivative of sin(x) will be -sin(x). In summary, d87/dx87(sin(x)) = -sin(x).

To find the derivative of d87/dx87(sin(x)), we first need to find the first few derivatives and look for a pattern. The derivative of sin(x) is cos(x), and the derivative of cos(x) is -sin(x). Taking the derivative of -sin(x) gives us -cos(x), and taking the derivative of -cos(x) gives us sin(x). We can see that the pattern is a cycle of sine and cosine functions with alternating signs. Since we are looking for the 87th derivative, we know that this pattern will repeat 43 times (since there are two functions in the cycle and 87 is an odd number). Therefore, the 87th derivative of sin(x) will be -sin(x). In summary, d87/dx87(sin(x)) = -sin(x).

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