2. The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is
58 feet.
Find the width of the rectangle.

The width of the rectangle is 12ft.

The rectangle's perimeter is calculated using its length. Given by the total of the rectangle's sides, it is stated in linear units.

The space inside the rectangle is measured by area, on the other hand. It is measured in square units and equals the sum of the rectangle's length and width.

Let us suppose the width of the given rectangle be x
According to the given question;
Length of rectangle is 5ft more than its width
Therefore, length of rectangle= x+5
We know that,

Perimeter of rectangle = 2 ( length+breadth)
Perimeter of rectangle = 2[x+(x+5)]

It is given in the question that perimeter of the rectangle is 58ft

Thus,
⇒2( length+breadth) =58
⇒ 2[x+(x+5)] = 58
⇒ 2 (2x+5) = 58
⇒ 4x + 10 = 58
⇒ 4x = 58- 10 = 48
⇒ 4x = 48
⇒ x = 12
Thus, width of rectangle = 12 ft
length of rectangle = x+5 = 12+5 = 17ft

Hence, the width of the rectangle is 12ft.

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