2) Oil with ρ= 876 kg/m3 and μ= 0.24 kg/m · s is flowing through a 1.5 cm diameter pipe that discharges into the atmosphere at 88 kPa. The absolute pressure 15 m before the exit is measured to be 135 kPa. Determine the flow rate of oil through the pipe if the pipe is (a) horizontal, (b) inclined 8° upward from the horizontal, and (c) inclined 8° downward from the horizontal.

Answers

Answer 1

The pressure in a fluid flowing with laminar flow through a pipe is given by

Hagen-Poiseuille equation.

The correct responses are;

(a) If the pipe is horizontal, the flow rate is approximately 1.622 × 10⁻⁵ m³/s(b) If the pipe is inclined upwards, the flow rate is approximately 1.003 × 10⁻³ m³/s(c) If the pipe is inclined 8° downwards, the flow rate is approximately 2.24 × 10⁻⁵ m³/s

Reasons:

When the flow is a steady incompressible flow through pipe, the flow rate

can be derived from the Hagen-Poiseuille equation as follows;

[tex]\displaystyle \dot V = \mathbf{\frac{\left[\Delta P - \rho \cdot g \cdot L \cdot sin\left(\theta \right) \right] \cdot \pi \cdot D^4 }{128 \cdot \mu \cdot L}}[/tex]

ΔP = 135 kPa - 88 kPa = 47 kPa

The density of the oil, ρ = 876 kg/m³

μ = 0.24 kg/(m·s)

L = 15 m

The diameter of the pipe, D = 1.5 cm = 0.015 m

(a) When the pipe is horizontal, we have;

θ = 0°

Which gives;

[tex]\displaystyle \dot V = \mathbf{\frac{\left[47 \times 10^3 - 876 \, kg/m^3 \times 9.81 \, m/s^2 \times 15 \, m \cdot sin\left(0^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m}}[/tex]

[tex]\displaystyle \dot V = \frac{\left[47 \times 10^3\, Pa - 128903.4\, Pa \cdot sin\left(0^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m}[/tex]

[tex]\displaystyle \dot V = \frac{\left[47 \times 10^3\, Pa - 128903.4 \, Pa \cdot sin\left(0^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m} =\frac{0.002379357\cdot \pi}{460.8}[/tex]

[tex]\displaystyle \dot V=\frac{0.002379357\cdot \pi}{460.8} = \mathbf{1.622 \times 10^{-5}}[/tex]

The flow rate when the pipe is horizontal, [tex]\displaystyle \dot V[/tex] = 1.622 × 10⁻⁵ m³/s

(b) When the pipe is inclined 8°, we have;

[tex]\displaystyle \dot V = \mathbf{\frac{\left[47 \times 10^3\, Pa - 128903.4\, Pa \cdot sin\left(8^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m}} = 1.003 \times 10^{-5} \, m^3/s[/tex]

The flow rate of oil through the pipe if the pipe is inclined 8° upwards from the horizontal, [tex]\displaystyle \dot V[/tex] = 1.003 × 10⁻⁵ m³/s

(c) If the pipe is inclined 8° downward from the horizontal, we have;

[tex]\displaystyle \dot V = \frac{\left[47 \times 10^3\, Pa - 128903.4\, Pa \cdot sin\left(-8^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m} = 2.24\times 10^{-5} \, m^3/s[/tex]

If the pipe is inclined 8° upwards from the horizontal, the flow rate of oil through the pipe is, [tex]\displaystyle \dot V[/tex] = 2.24 × 10⁻⁵ m³/s

Learn more about flow through pipes here:

https://brainly.com/question/6858718


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and

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and

[tex]90 = 7f + 6 \\ 84 = 7f \\ 12 = f[/tex]

I hope that helps!

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Step-by-step explanation:

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3 / 2 = 1.5

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

f(x) = 8.917x³ + 2x² + 0.083x - 7

Step-by-step explanation:

f(x)= y

Let the coefficients of x³, x², x be a, b, c and the constant be d

y= ax³ + bx² + cx + d

When y = -65, x = -2

-65= a(-2)³ + b(-2)² + c(-2) + d

-65= -8a + 4b - 2c + d ...eq. 1

When y = -14, x = -1

-14= a(-1)³ + b(-1)² + c(-1) + d

-14= -a + b - c + d ...eq. 2

When y = -7, x = 0

-7= a(0)³ + b(0)² + c(0) + d

-7 = d ...eq.3

When y = 4, x = 1

4= a(1)³ + b(1)² + c(1) + d

4= a + b + c + d ...eq. 4

when y = 78, x = 2

78 = a(2)³ + b(2)² + c(2) + d

78= 8a + 4b + 2c + d ...eq. 5

From eq. 3, d is - 7

putting d as - 7 in equations 1, 2, 4 and 5

In eq. 1,

-65= -8a + 4b - 2c - 7

-58= -8a + 4b - 2c ...eq. 6

In eq. 2

-14= -a + b - c - 7

-7= -a + b - c ...eq. 7

In eq. 4,

4= a + b + c - 7

11= a + b + c ...eq. 8

In eq. 5

78= 8a + 4b + 2c - 7

85= 8a + 4b + 2c ...eq.9

Subtracting eq. 9 from eq. 6

-143 = -16a - 4c... eq 10

subtracting eq. 8 from eq 7

-18= -2a - 2c

9= a + c

a = 9 - c ...eq 11

putting a as 9 - c in eq. 10

-143 = -16(9 - c) - 4c

-143 = -144 + 16c - 4c

1= 12c

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a = 9 - 1/12

a = 107/12 or 8.917

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11= 107/12 + b + 1/12

multiplying through by 13

132 = 107 + 12b + 1

132 - 108 = 12b

24= 12b

b = 24/12

= 2

Therefore, a= 8.917, b= 2, c= 0.083 and d = -7

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John made 357$ for 17 hours of work.
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Answers

Answer: 14 hours

Step-by-step explanation: First I found the unit rate of how much money per hour. So, 357 divided by 17 = 21. So know I know that she earns 21$ per hour. Then, I did 237 divided by 17 which would be 13 remainder 16. Since he only get paid if he works for a full hour, I think the answer would be 14.

[tex]\begin{array}{ccll} \$&hrs\\ \cline{1-2} 357&17\\ 237&x \end{array}\implies \cfrac{357}{237}=\cfrac{17}{x}\implies \implies \cfrac{119}{79}=\cfrac{17}{x}\implies 119x=1343 \\\\\\ x = \cfrac{1343}{119}\implies x = \cfrac{79}{7}\implies x = 11\frac{2}{7}\leftarrow \textit{11 hours, 17 minutes and 8 seconds}[/tex]

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