Answer:
125 square feet of a yard.
Step-by-step explanation:
So 1 lb of grass seed will fill 25 square feet of yard. Multiply 25 by 5 and get 125.
HELP ME PLEASE I WILL GIVE BRAINLY CAN U PLEASE GRAPH IT
Answer:
The two points are (0,1) and (0.75, 0)
Step-by-step explanation:
I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!
5x=15 y 2x=6
Son ecuaciones equivalentes?
PORFAVOR AYÚDENME ES EMERGENCIA
Find the missing side length, N.
We know these triangles are congruent with the missing side, N would be equal to 15.
What is the congruent triangle?Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.
We know these triangles are congruent.
To find the missing side, N
ΔABC ≅ΔQRS
AC/QS = BC/RS
2/5 = 6/n
n = 6 x 5/2
n = 30/2
n = 15
Thus, the value of N is 15.
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delta math help plz im stuck
Step-by-step explanation:
-70x^4 + 30x
= 10x(-7x^3 + 3)
ANSWER: 10x(-7x^3 + 3)
if x and y varies directly and x = 4 when y = 16. find y when x = 9?
9514 1404 393
Answer:
36
Step-by-step explanation:
"Varies directly" means the relationship is proportional:
y/9 = 16/4
y = 9·16/4 = 36
The value of y is 36 when x = 9.
5. Grace has $39 She has 8 less than her brother. How much
money does Grace's brother have?
Answer:
Grace's brother has $47.
Need help with these
Answer:
3x
7-k
m/4
(5x)+12
Step-by-step explanation:
most of the words like and are just fillers. and basically means together in this instance
d
Evaluate
arcsin
(6)]
at x = 4.
dx
Answer:
[tex]\frac{1}{2\sqrt{5} }[/tex]
Step-by-step explanation:
Let, [tex]\text{sin}^{-1}(\frac{x}{6})[/tex] = y
sin(y) = [tex]\frac{x}{6}[/tex]
[tex]\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})[/tex]
[tex]\frac{d}{dx}\text{sin(y)}=\frac{1}{6}[/tex]
[tex]\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}[/tex] ---------(1)
[tex]\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}[/tex]
[tex]\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}[/tex]
cos(y) = [tex]\sqrt{1-\text{sin}^{2}(y) }[/tex]
= [tex]\sqrt{1-(\frac{x}{6})^2}[/tex]
= [tex]\sqrt{1-(\frac{x^2}{36})}[/tex]
Therefore, from equation (1),
[tex]\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}[/tex]
Or [tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}[/tex]
At x = 4,
[tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}[/tex]
[tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}[/tex]
[tex]=\frac{1}{6\sqrt{\frac{36-16}{36}}}[/tex]
[tex]=\frac{1}{6\sqrt{\frac{20}{36} }}[/tex]
[tex]=\frac{1}{\sqrt{20}}[/tex]
[tex]=\frac{1}{2\sqrt{5}}[/tex]
Pls help and show workings
Step-by-step explanation:
AB = 72 so, then FB would be half of that
so 72 divided by 2 would be 36
5x+1=36 then do substitution
-1 from both sides (from +1 you gotta do the inverse)
5x = 35
divide 5 from both sides because in between 5 and x is a times so the inverse of that is divide
x = 7
Mariah025 answer here please
Answer:
wht
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.
Which expression is equivalent to sqrt 2x^5/18 assume x is greater than or equal to 0
Answer:
[tex]\sqrt{\frac{2x^{5} }{18} }[/tex] = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]
Step-by-step explanation:
Given expression
[tex]\sqrt{\frac{2x^{5} }{18} }[/tex]
we know that the algebra formula
[tex]\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }[/tex]
[tex]\sqrt{\frac{2x^{5} }{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{9} \sqrt{2} }[/tex]
= [tex]\frac{\sqrt{x^{5} } }{3}[/tex]
Mr. Jenkins has 19 cases of beans on the shelves in the grocery store. He also has 6 cases of beans in the stock room. There are 14 cans of beans in each case. Which expression represents the total number of cans of beans Mr. Jenkins has? (19 + 14) x 6 14 x (19 + 6 ) (6 + 14) x 19 (6 x 19 + 14
Answer:
14 × (19 + 6)
hope it helps
The expression represents the total number of cans of beans Mr. Jenkins is, (19+6)×14, So Option B is correct.
What are expressions?An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.
For example, 2x+3
Given that,
Mr. Jenkins has 19 cases of beans
He also has 6 cases of beans in the stock room
There are 14 cans of beans in each case
Expression for total number of beans = ?
Total number of beans = Total number of cases ×beans in each case
Total number of beans = (beans in grocery store+beans in stock room)×14
Total number of beans = (19 +6) × 14
Hence, the expression is (19 +6) × 14
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a ball is randomly selected from a bag conraining 12 yellow balls,5red balls,and 7 white balls. find p(white ball). round to the nearest hundredth if necessary?
Answer:
P(white ball)=0.29
Step-by-step explanation:
12 yellow balls
5 red balls
7 white balls
12+5+7=24
so 24 balls in the bag
[tex]\frac{7}{24}[/tex]=0.2916
rounded to the nearest is 0.29
A store used to sell an MP3 for $72which is 50% more than the wholesale cost. At a special holiday sale, the price of the MP3 was 20% less than the wholesale cost. What was the special sale price of the MP3?
Answer:
$115.2
Step-by-step explanation:
Step one:
Given data
A store used to sell an MP3 for $72 and we are told that this 50% of the wholesale price.
Therefore the wholesale price is
72*2= $144
Required:
The special sales cost at 20% discount
Step two:
We are told that the special sale is at a 20% discount on the wholesale
= 20/100*144
=0.2*144
=$28.8
Therefore the special sales price is
= 144-28.8
=$115.2
PLEASE IF I DON GET THIS RIGHT I WILL HAVE TO REDO MATH PLEASE HELP
Answer:
x= 8 and y= 8 square root of 2
Step-by-step explanation:
Evaluate the expression (1/4) {x(2y+3z)} when x=8, y=3, and z=2
Answer:
24
Step-by-step explanation:
x = 8, y = 3, z = 2
(1/4) x {8[2(3)+3(2)]}
(1/4) x {8(6 + 6)}
(1/4) x {48 + 48} (by distributing)
1/4 x 96
= 24
Integrate the integral:
[tex]\int \frac{1}{\sqrt{x} \sqrt{1-x} }[/tex]
Answer:
[tex]\displaystyle \int {\frac{1}{\sqrt{x} \sqrt{1-x} } } \, dx = 2arcsin(\sqrt{x}) + C[/tex]
General Formulas and Concepts:
Calculus
U-SubstitutionIntegration Property: [tex]\int {cf(x)} \, dx = c\int {f(x)} \, dx[/tex]Arctrig Integration: [tex]\displaystyle \int\limits {\frac{1}{\sqrt{a^2-u^2} } } \, du = arcsin(\frac{u}{a} ) + C[/tex]Step-by-step explanation:
Step 1: Define
[tex]\displaystyle \int\limits {\frac{1}{\sqrt{x} \sqrt{1-x} } } \, dx[/tex]
Step 2: Identify
Set up variables for u-substitution and integral trig.
[tex]\displaystyleu = \sqrt{x}\\a = 1\\du = \frac{1}{2\sqrt{x}}dx[/tex]
Step 3: integrate
Rewrite Integral: [tex]\displaystyle 2\int {\frac{1}{2\sqrt{x} \sqrt{1-x} } } \, dx[/tex][Integral] U-Substitution: [tex]\displaystyle 2\int {\frac{du}{\sqrt{1^2-(\sqrt{x})^2 } }[/tex][Integral] U-Sub Arctrig: [tex]\displaystyle 2\int {\frac{du}{\sqrt{1^2-u^2 } }[/tex][Integral] Arctrig: [tex]\displaystyle 2arcsin(\frac{u}{1}) + C[/tex]Simplify: [tex]\displaystyle 2arcsin(u) + C[/tex]Back-substitute: [tex]\displaystyle 2arcsin(\sqrt{x} ) + C[/tex]We are given the expression:
[tex]\int\limits {\frac{1}{\sqrt[]{x} }*\frac{1}{\sqrt[]{ 1-x^{2}}} } \, dx[/tex]
U-substitution:
let u = [tex]x^{1/2}[/tex] [So, x = u²]
[tex]\frac{du}{dx} = \frac{1}{2\sqrt[]{x}}[/tex] [differentiating both sides wrt x]
dx = du*2√(x)
dx = 2u(du) [Since u = √x]
Finding the Integral:
Plugging these values in the given expression:
[tex]\int\limits {u^{-1}*(1-u^{2})^{-1/2} } \, 2\sqrt[]{x}*du[/tex]
[tex]\int\limits {\frac{1}{u}*\frac{1}{\sqrt[]{ 1-u^{2}}}*2u } \, du[/tex]
The 'u' in the numerator and denominator will cancel out
[tex]\int\limits {\frac{1}{\sqrt[]{ 1-u^{2}}}*2 } \, du[/tex]
Since 2 is a constant
[tex]2\int\limits {\frac{1}{\sqrt[]{ 1-u^{2}}} } \, du[/tex]
Using the property: [tex]\int\limits {\frac{1}{\sqrt[]{1-x^{2}} }} \, dx[/tex] = ArcSin(x) + C
2*ArcSin(u) + C
Since u = √x :
2*ArcSin(√x) + C
Answer the following Question with Appropriate Explanation
Answer:
option is B)
Step-by-step explanation:
2x is a perfect square. but x is not a perfect square, this brings us to the conclusion tht prob x is 2.
2x = 4
hence correct option is B) 4x is a perfect square, as 4x4=16, which is a perfect square...
1) Choose the correct answer.
The ___ of two sets is the set of elements that could be found in both sets at the same time.
intersection
union
conjunction
disjunction
Answer:
Intersection
Step-by-step explanation:
The intersection of two set A and B is defined as the elements which can be found in both set A and set B.
For instance :
A = {1, 3, 5, 7, 9, 11}
B = {2, 4, 6, 7, 8, 9, 10}
The intersection of the two sets A and B denoted as ;
AnB = {7, 9}
Peaches are being sold for $2 per pound.The customer created a model to represent the total cost of peaches bought. If x represents the number of pounds of peaches bought and y represents the total cost of the peaches, which best describes the values of x and y?
The values of both x and y can be any real number.
The values of both x and y will be real numbers greater than or equal to 0.
The value of x and y will always be zero
The value of x can be any real number greater than or equal to 0, but the value of y must be an integer greater than or equal to 0.
Answer:
B - The values of both x and y will be real numbers greater than or equal to 0.
The answer choice that best describes the values of x and y is B - The values of both x and y will be real numbers greater than or equal to 0.
Calculations and Parameters:Given that peaches are being sold for $2 per lb.
If we define x as the number of pounds that you buy, and y as the cost of these peaches, we can write the function:
y = $2*x
Therefore, the best description of the values of x and y is found in option B. The value of x can be any real number greater than or equal to 0, but the value of y must be an integer greater than or equal to 0.
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how do i solve this pls help me i got 30 mins left :(
A rectangular magazine cover is photocopied by using a scale factor of One-third. The length of the photocopy of the magazine cover is enlarged by a factor of 3. enlarged by a factor of One-third. reduced by a factor of 3. reduced by a factor of One-third.
Answer: "reduced by a factor of One-third."
Step-by-step explanation:
Suppose that the original magazine has a length L and a width W.
If it is photocopied using a scale factor of K, then the measures of the photocopy will be:
length = K*L
Width = K*W
In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:
length = (1/3)*L = L/3
Width = (1/3)*W = W/3
For usual notation:
When k > 1, we have an enlargement by a factor k
when 0 < k < 1, we have a reduction by a factor k
in this case, k = 1/3, then:
We have a reduction by a factor of 1/3
The correct option is:
"reduced by a factor of One-third."
Answer: D-reduced by a factor 1/3
Step-by-step explanation:
got it correct on edge 2021
2) 8(x - y); user-5, and y = 2
Answer:
8(x-y);use x=5,and y=2
8(5 - 2) = 8(3) = 24
answer
24
Step-by-step explanation:
good? Brainliest?
Anna wants to add compatible numbers to find the following sum. 27.95 + 19.37 + 34.05 + 21.63 Which pairs of numbers are compatible? Choose Yes or No for each pair. 27.95 and 34.05 Choose.. 27.95 and 21.63 Choose... 19.37 and 34.05 Choose... 19.37 and 21.63 Choose...
Answer:
27.95 and 34.05 are compatible because when you add up the decimals, the equal 0, which makes it easier to add. 27. 95 + 34.05 = 61.00.
Same with 19.37 and 21.63, it adds up to 40.00
The answer to all of this would be 101.00
A company has two factories, factory A and factory B. The cost per item to produce q items in factory A is
200 + 3/q
q
. The cost per item to produce q items in factory B is
300 + q/
3q
. Find an expression for the sum of these costs per item. Then divide this expression by 2 to find an expression for the average cost per item to produce q items in each factory.
The average cost per item to produce q items in each factory is
Answer:
(700 + 51q)/4qStep-by-step explanation:
Given costs:
(200 + 13q)/q and (300 + 25q)/2qSum of the costs:
(200 + 13q)/q + (300 + 25q/2q) =(400 + 26q)/2q + (300 + 25q)/2q =(700 + 51q)/2qAverage cost is sum divided by number:
(700 + 51q)/2q ÷ 2 = (700 + 51q)/4qIf x = 1 is a zero of the polynomial 3+ kx^2 + 2 ,find the value of k.
Plz it's urgent.
Answer:
k = i√ 5 , -i√ 5
Step-by-step explanation:
3 + kx^2 + 2 = ?
3 + k(1)^2 + 2 = ?
5 + k(1)^2 = ?
5 + k^2 = ?
k^2 = -5
k = i√ 5 , -i√ 5
Ellie bought a pair of jeans on sale for 15% off. If the jeans were originally $35, how much did she save?
Answer:5.25
Step-by-step explanation:
HELP ME RIGHT NOW GRAND PRIZE IS 10 POINTS COME ON COME ON PLEASE SJNDINKOJDEWNIOEW
Solve the system of equations using the substitution method. Make sure to check your solution.
y = 3x + 2
-4x + 4y = 16
In the blanks below, type just the number for the x-coordinate in blank 1 and just the number for the y-coordinate in blank 2.
x-coordinate:
y-coordinate:
Answer: X = 1
Y= 5
Step-by-step explanation:
Plug in y = 3x + 2 in the Y coordinate to find X
-4x + 4(3x + 2) = 16
Now you can solve for X
X = 1
Then plug in 1 in the X coordinate to find Y
-4(1)+ 4y= 16
Now you can solve for Y
Y= 5
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NEED AN ANSWER SOON
Find the slope of the line that contains the points named. A(3, 2), B(7, 8) 5/2 3/2 2/3
Answer:
3/2
Step-by-step explanation:
Pleaze help me asap
And please no fake answers.
Step-by-step explanation:
[tex] \underline{ \underline{ \text{Given}}}[/tex] :
a = dk³ , b = dk² , c = dk[tex] \underline{ \underline{ \text{To \: prove}}} : [/tex]
[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd} = \sqrt{(a - b - c)(b - c - d)} } [/tex]
[tex] \underline{ \underline{ \text{Solution}}} : [/tex]
Left hand side ( L.H.S ) :
[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd}} [/tex]
⟶ [tex] \tt{ \sqrt{d {k}^{3} \cdot \: d {k}^{2} } - \sqrt{d {k}^{2} \cdot \: dk } - \sqrt{dk \cdot \: d} }[/tex]
⟶ [tex] \tt{ \sqrt{ {d}^{2} {k}^{5} } - \sqrt{ {d}^{2} {k}^{3} } - \sqrt{ {d}^{2}k } }[/tex]
⟶ [tex] \tt{ \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: {k}^{2} \cdot \: k } - \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: k \: } - \sqrt{ {d}^{2}k } }[/tex]
⟶ [tex] \tt{ \sqrt{ {d}^{2} } \cdot \sqrt{ {k}^{2} } \cdot \: \sqrt{ {k}^{2} } \cdot \: \sqrt{k} } - \sqrt{ {d}^{2} }\cdot \: \sqrt{ {k}^{2}} \cdot \: \sqrt{k} \: - \sqrt{ {d}^{2} } \cdot \: \sqrt{k} [/tex]
⟶ [tex] \tt{d {k}^{2} \sqrt{k} - dk \sqrt{k} - d \sqrt{k} }[/tex]
⟶ [tex] \tt{ d\sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]
Right Hand Side ( R.H.S) :
[tex] \tt{ \sqrt{(a - b - c)(b - c - d)}} [/tex]
⟶ [tex] \tt{ \sqrt{(d {k}^{3} - d {k}^{2} - dk)( d{k}^{2} - dk - d)} }[/tex]
⟶ [tex] \tt{ \sqrt{ \{dk( {k}^{2} - k - 1) \} \: \{d( {k}^{2} - k - 1) \}} }[/tex]
⟶ [tex] \tt{ \sqrt{ {d}^{2}k( {k}^{2} - k - 1) ^{2} } } [/tex]
⟶ [tex] \tt{ \sqrt{ {d}^{2}k } \cdot \: \sqrt{ {( {k}^{2} - k - 1)}^{2} } } [/tex]
⟶[tex] \tt{ \sqrt{ {d}^{2} } \cdot \: \sqrt{k} \cdot \: \sqrt{( {k}^{2} - k - 1) ^{2} } }[/tex]
⟶ [tex] \tt{d \sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]
L.H.S = R.H.S
Hence , Proved !
Hope I helped ! ♡
Have a wonderful day / night ! ツ
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