Answer:
-5+5i
Step-by-step explanation:
(2-i)(-3+i)=-6+3i+2i-i² (i²=-1)
-6+3i+2i-(-1)
-6+3i+2i+1=-5+5i
-5+5i
The sum of Jason’s age and his brother’s age is 55. Jason is 7 years younger than his brother. How old is Jason?
Answer:
Jason is 24 years old
Step-by-step explanation:
Lets say that Jason's age is X, and his brother's age is Y.
We know that X + Y = 55.
We also know that (X + 7) = Y.
This means (X + 7) + Y = 62 (We got the 62 by adding 55 and 7)
Anyway if X+7= Y, and X+7 + Y = 62, then X+7 = 62/2, right?
We divide the 62 by 2 and we get 31.
Alright, so X+7 = 31.
substract both sides by 7.
We get X = 24
Sorry if this seemed longer or more complicated than it should've been, I don't know how to explain it better.
The Buzz Tool Company issued 1,000 shares of common stock. If the total value of this was $50,000,what's the par value of each share.
Answer:
$50.
Step-by-step explanation:
The formula for the stocks is...
Par value of preferred stock = (Number of issued shares) * (par value per share)
So, we can say that...
Par value per share = par value of preferred stock / number of issued shares.
The par value of the Buzz Tool Company is $50,000. There are 1,000 issued shares. So, each stock would be $50,000 / 1,000 = $50 / 1 = $50.
Hope this helps!
Answer: par value is $50.00
Step-by-step explanation:
$50,000.00 ÷ 1,000
= $50.00
[tex]20+3x-15+x=27[/tex]
Answer:
x=11/2
Step-by-step explanation:
First we can combine similar terms on the left side. 3x + x is 4x and 20-15 is 5
Now that we have combined them, we are left with 4x+5=27
Subtract 5 on both sides to cancel out the 5.
4x=22
Divide both sides by 4
x=22/4
Simplify
x=11/2
Answer:
[tex] \boxed{\sf x = \frac{11}{2}} [/tex]
Step-by-step explanation:
[tex] \sf Solve \: for \: x: \\ \sf \implies 20 + 3x - 15 + x = 27 \\ \\ \sf Grouping \: like \: terms, \: 20 + 3x - 15 + x = \\ \sf (3x + x) + (20 - 15) : \\ \sf \implies \boxed{ \sf (3x + x) + (20 - 15)} = 27 \\ \\ \sf 3x + x = 4x : \\ \sf \implies \boxed{ \sf 4x} + (20 - 15) = 27 \\ \\ \sf 20 - 15 = 5 : \\ \sf \implies 4x + \boxed{ \sf 5} = 27 \\ \\ \sf Subtract \: 5 \: from \: both \: sides: \\ \sf \implies 4x + (5 - \boxed{ \sf 5}) = 27 - \boxed{ \sf 5} \\ \\ \sf 5 - 5 = 0 : \\ \sf \implies 4x = 27 - 5 \\ \\ \sf 27 - 5 = 22 : \\ \sf \implies 4x = \boxed{ \sf 22} \\ \\ \sf Divide \: both \: sides \: of \: 4x = 22 \: by \: 4 : \\ \sf \implies \frac{4x}{4} = \frac{22}{4} \\ \\ \sf \frac{ \cancel{4}}{ \cancel{4}} = 1 : \\ \sf \implies x = \frac{22}{4} \\ \\ \sf \implies x = \frac{11 \times \cancel{2}}{2 \times \cancel{2}} \sf \implies x = \frac{11}{2} [/tex]
Which statement describes this system of equations? 9x – 6y = 15, 3x – 2y = 5 The equations in the system are equivalent equations. There is no solution to the system of equations. The system of equations has one solution at (3, 2). The system of equations has one solution at (5, 5).
Answer:
There is no solution to the systems of equation.
Step-by-step explanation:
Graph the system by using y=mx+b
Both systems are y=2/5x+5/2.
Answer:
that guy is wrong. its the first option.
Step-by-step explanation:
i just took it
Instructions
Chart of Accounts
Starting Question
Joumal
Instructions
Flush Mate Co. wholesales bathroom fixtures. During the current fiscal year, Flush Mate Co. received the following notes:
Date
Face Amount
Interest Rate
Term
1.
Mar. 6
$80,000
5%
45 days
2.
Apr. 23
24,000
9
60 days
3.
July 20
42,000
6
120 days
4
Sept. 6
54,000
7
90 days
5.
Nov. 29
27,000
6.
60 days
6
Dec. 30
72,000
5
30 days
Required:
1. Determine for each note (a) the due date and (b) the amount of interest due at maturity, identifying each note by number. Assume a 360-day
Answer:
Note Due Date Interest due at Maturity
1 Mar 6 $500
2 Apr 23 $360
3 July 20 $840
4 Sept 6 $945
5 Nov 29 $270
6 Dec 30 $300
Step-by-step explanation:
Calculation to Determine the due date and the amount of interest due at maturity for Flush Mate Co.
Using this formula to Calculate for the amount of interest due at maturity.
Interest due at Maturity= [Face amount * Numbers of days to maturity / 360 * Interest rate]
Note, Due Date, Face Amount, No of days to maturity, Interest rate, Interest due at Maturity
1 Mar 6 80,000× 45/360 ×5% =$500
2 Apr 23 24,000 × 60/360 ×9% =$360
3 July 20 42,000×120/360 ×6% =$840
4 Sept 6 54,000× 90/360 ×7% =$945
5 Nov 29 27,000× 60/360 ×6% =$270
6 Dec 30 72,000× 30/360 ×5% =$300
Therefore the due date and the amount of interest due at maturity for Flush Mate Co are:
Note Due Date Interest due at Maturity
1 Mar 6 $500
2 Apr 23 $360
3 July 20 $840
4 Sept 6 $945
5 Nov 29 $270
6 Dec 30 $300
Fake Question: Should Ujalakhan01 be a moderator? (If you could answer I'd appreciate it haha.)
Real Question: Simplify [tex](a^5*a^4)+(b^2*b^3)-(c^7*c^6)[/tex]
Answer:
[tex]a^9 + b^ 5 + c^{13}[/tex]
Step-by-step explanation:
[tex](a^5 \times a^4)+(b^2 \times b^3) + (c^7 \times c^6)[/tex]
When bases are same and it is multiplication, then add the exponents.
[tex](a^{5+4})+(b^{2+3})+(c^{7+6})[/tex]
[tex](a^9)+(b^ 5) + (c^{13})[/tex]
Apply rule : [tex](a^b)=a^b[/tex]
[tex]a^9 + b^ 5 + c^{13}[/tex]
Answer:
[tex]a^9+b^5-c^{13[/tex]
Step-by-step explanation:
[tex](a^5*a^4) + (b^2*b^3)-(c^7*c^6)[/tex]
When bases are same, powers are to be added.
=> [tex](a^{5+4})+(b^{2+3})-(c^{7+6})[/tex]
=> [tex]a^9+b^5-c^{13[/tex]
Use the accompanying data set to complete the following actions. a. Find the quartiles. b. Find the interquartile range. c. Identify any outliers. 41 52 37 44 42 38 41 48 43 39 36 55 42 35 15 52 39 50 29 30
Answer:
(a) [tex]Q_1=36.5,M=Q_2=41,Q_3=46[/tex]
(b) [tex]IQR=9.5[/tex]
(c) 15
Step-by-step explanation:
The given data set is
41, 52, 37, 44, 42, 38, 41, 48, 43, 39, 36, 55, 42, 35, 15, 52, 39, 50, 29, 30
Arrange the data in ascending order.
15, 29, 30, 35, 36, 37, 38, 39, 39, 41, 41, 42, 42, 43, 44, 48, 50, 52, 52, 55
Divide the data in four equal parts.
(15, 29, 30, 35, 36), (37, 38, 39, 39, 41), (41, 42, 42, 43, 44), (48, 50, 52, 52, 55)
Now,
[tex]Q_1=\dfrac{36+37}{2}=36.5[/tex]
[tex]M=Q_2=\dfrac{41+41}{2}=41[/tex]
[tex]Q_3=\dfrac{44+48}{2}=46[/tex]
[tex]IQR=Q_3-Q_1=46-36.5=9.5[/tex]
Range for outlier is
[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[36.5-1.5(9.5),46+1.5(9.5)][/tex]
[tex]=[22.25,60.25][/tex]
Since, 15 lies outside the interval [22.25,60.25], therefore 15 is an outlier.
Hi I need this question please asap.
The amount of time to complete a physical activity in a PE class is approximately normally normally distributed with a mean of 32.9 seconds and a standard deviation of 6.4 seconds.
A) What is the probability that a randomly chosen student completes the activity in less than 33.2 seconds?
B) What is the probability that a randomly chosen student completes the activity in more than 46.6 seconds?
C) What proportion of students take between 35.5 and 42.8 seconds to complete the activity?
D) 75% of all students finish the activity in less than____seconds.
Answer:
The answer is below
Step-by-step explanation:
Given that mean (μ) of 32.9 seconds and a standard deviation (σ) of 6.4 seconds.
The z score is used to measure by how many standard deviation the raw score is above or below the mean. It is given by:
[tex]z=\frac{x-\mu}{\sigma}\\[/tex]
a) For x < 33.2 seconds
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{33.2-32.9}{6.4} =0.05[/tex]
From the normal distribution table, the probability that a randomly chosen student completes the activity in less than 33.2 seconds = P(x < 33.2) = P(z < 0.05) = 0.5199 = 51.99%
b) For x > 46.6 seconds
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{46.6-32.9}{6.4} =2.14[/tex]
From the normal distribution table, the probability that a randomly chosen student completes the activity in more than 46.6 seconds = P(x > 46.6) = P(z > 2.14) = 1 - P(z < 2.14) = 1 - 0.9927 = 0.0073 = 0.73%
c) For x = 35.5 seconds
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{35.5-32.9}{6.4} =0.41[/tex]
For x = 42.8 seconds
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{42.8-32.9}{6.4} =1.55[/tex]
From the normal distribution table, the proportion of students take between 35.5 and 42.8 seconds to complete the activity = P(35.5 < x < 42.8) = P(0.41< z< 1.55) = P(z < 1.55) - P(z < 0.41) = 0.9332 - 0.6591 = 0.2741 = 27.41%
d) A probability of 75% = 0.75 corresponds to a z score of 0.68
[tex]z=\frac{x-\mu}{\sigma}\\\\0.68=\frac{x-32.9}{6.4} \\\\x-32.9=4.4\\x=4.4+32.9\\x=37.3[/tex]
75% of all students finish the activity in less than 37.3 seconds
PLEASE HELP ?
Convert by looking at the thermometer and measure to the nearest 5 degrees F.
31 degrees Celsius to Fahrenheit
Answer:
90º
Step-by-step explanation:
just look at where 31º on the right lines up with the value on the left (aka around 90º)
Answer:
87.8 °F ≈ 90°F
Step-by-step explanation:
[tex]x \ degrees \ F = 31 \ degree \ Celsius *\frac{9}{5} + 32\\x \ degrees \ F = 55.8 + 32\\\\x \ degrees \ Fahrenheit = 87.8 \ degrees \ Farenheit[/tex]
Find C and round to the nearest tenth.
Answer:
29.4 degrees
Step-by-step explanation:
i divided sin by 55 degrees
A customer enrolled in a 1-year product purchase plan that costs $60 per month. After 6 months, the customer received a monthly discount of 20%. What is the total amount the customer will pay for the 1-year plan?
Answer:
$432
Step-by-step explanation:
60*6=360
They paid $360 for the first 6 months.
20%*60=.2*60
0.2*60=12
12*6=72
They paid $72 for the last 6 months.
360+72=432
They paid $432
$648 is the total amount the customer will pay for the 1-year plan
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
Given that a customer enrolled in a 1-year product purchase plan that costs $60 per month.
After 6 months, the customer received a monthly discount of 20%.
We need to find the total amount the customer will pay for the 1-year plan.
Product Plan = $60 per month
Money he pay for 1 month = $ 60
Money He pay for first 6 month = 6 × 60 = $ 360
after 6 month he receives 20% discount monthly,
So, Now he pay for 1 month = 60 - 20% × 60
=60-20/100×60
=60-12=48
Money he pay for last 6 month = 6 × 48 = 288
Total Money he pay in a year = 360 + 288 = $ 648
Hence, $648 is the total amount the customer will pay for the 1-year plan
To learn more on Percentage click:
https://brainly.com/question/28269290
#SPJ2
Write the equation of the line in slope intercept form that passes through the points (4,-2) and (2,-1)
Answer:
y + 2 = (-1/2)(x - 4)
Step-by-step explanation:
Let's move from (2, -1) to (4, -2) and measure the changes in x and y. x increases by 2 units from 2 to 4, and y decreases by 1 unit from -1 to -2. Thus, the slope of the line connecting the two points is m = rise / run =
-1
--- = (-1/2).
2
Using the point-slope formula, we get:
y + 2 = (-1/2)(x - 4)
g The weight of a certain type of apple is normally distributed with a mean of 10.56 ounces and standard deviation of 0.9 ounces. What is the first quartile, Q subscript 1, of the weight of this type of apple?
Answer:
First Quartile Q1 = 9.9525
Step-by-step explanation:
For a standard normal distribution,
First quartile Q1 = μ - 0.675 σ
From the question mean μ = 10.56
Standard deviation σ = 0.9
Plugging these values into the first quartile equation, we have;
Q1 = 10.56 -0.675(0.9)
Q1 = 10.56 - 0.6075
Q1 = 9.9525
HELP ASAP ALL THREE PLEASE 1. if a cyclic alkene has 12 carbon atoms, how many hydrogen atoms does it have 2.if a cyclic alkene has 12 hydrogen atoms, how many carbon atoms 3. is it possible to have an odd number of hydrogen atoms
Answer:
1. 24
2. 6
3. No
Step-by-step explanation:
The formula for cyclic alkene is [tex]C^{n} H^{2n}[/tex], so if it has 12 carbon atoms, it will have double the amount of hydrogen atoms, therefore, 24 hydrogen atoms.
The same works in reverse. If we have 12 hydrogen atoms in this, then there will be half the amount of carbon atoms, therefore 6.
Since the relationship between Carbon and Hydrogen here is double and half, odd numbers can't be divided by 2 and end up with a whole number, so an odd number of hydrogen atoms is not possible.
Hope this helped!
Sanjay makes souvenir pyramids by pouring liquid into a pyramid-shaped mold. The mold he uses has a square base with a side length of 10\text{ cm}10 cm10, start text, space, c, m, end text, and the height of the mold is 10\text{ cm}10 cm10, start text, space, c, m, end text. Sanjay wants to make a smaller pyramid using the same mold, so he plans to fill the mold 2\text{ cm}2 cm2, start text, space, c, m, end text from the top. What is the approximate volume of this smaller pyramid?
Answer:
170.67
Step-by-step explanation:
Answer:
171
Step-by-step explanation:
Modeling the situation
If we fill the pyramid mold 2\text{ cm}2 cm2, start text, space, c, m, end text from the top, we have a smaller pyramid that's similar to the original pyramid.
Since the pyramids are similar, we can set up a proportional equation to find the side lengths and height of the smaller pyramid, and then find its volume.
Hint #22 / 4
Base and height of smaller pyramid
The height of the smaller pyramid is 10-2=8\text{ cm}10−2=8 cm10, minus, 2, equals, 8, start text, space, c, m, end text.
We can solve for the length \blueE{\ell}ℓstart color #0c7f99, ell, end color #0c7f99 in the smaller pyramid using a proportional equation.
\begin{aligned} \dfrac{\blueE{\ell}}{10} &= \dfrac{8}{10} \\\\ \blueE{\ell} &= \blueE{8} \end{aligned}
10
ℓ
ℓ
=
10
8
=8
Hint #33 / 4
Volume of smaller pyramid
\begin{aligned} \text{volume}_{\text{pyramid}} &= \dfrac13(\text{base area})(\text{height}) \\\\ &= \dfrac13 \cdot (\blueE{\ell})^2\cdot (\text{height}) \\\\ &= \dfrac13 \cdot \blueE{8}^2\cdot(8)\\\\ &= \dfrac{512}{3}=170.\overline{6}\\\\ &\approx \purpleD{170.67} \end{aligned}
volume
pyramid
=
3
1
(base area)(height)
=
3
1
⋅(ℓ)
2
⋅(height)
=
3
1
⋅8
2
⋅(8)
=
3
512
=170.
6
≈170.67
Hint #44 / 4
To the nearest cubic centimeter, the volume of the smaller pyramid is about 171\text{ cm}^3171 cm
3
171, start text, space, c, m, end text, cubed.
11 Is what percent of 20?
Answer:
55%
Step-by-step explanation:
Because 11/20= 0.55
0.55=55%
I hope u can understand help asap
i think u can see sho T=5n+20
Answer:
T(n) = 5n + 20
Step-by-step explanation:
1 candy has a mass of 5 g.
n candies have a mass of 5n grams.
The box has a mass of 20 grams.
total mass = mass of candies + mass of box
T(n) = 5n + 20
n T(n)
0 20
25 145
50 270
75 395
100 520
The height of a right cylinder is 3 times the radius of the base. The volume of the cylinder is 249 cubic units.
What is the height of the cylinder?
O2 units
4 units
O 6 units
O 8 units
Answer:
h = 6 unitsStep-by-step explanation:
Volume of a cylinder = πr²h
where r is the radius
h is the height
The height of a right cylinder is 3 times the radius of the base is written as
h = 3r
Volume = 249cubic units
So we have
249 = π r²(3r)
249 = π3r³
Divide both sides by 3π
r³ = 249/3π
r = 2
h = 3(2)
h = 6 units
Hope this helps you
Get every whole number from 0−10 using exactly five 3's, and any arithmetic operations and parentheses
Answer:
Step-by-step explanation:
(3 +3 - 3 -3) / 3 = 0
3 - 3/3 - 3/3 = 1
3 + 3 - 3 - 3/3 = 2
(3*3*3/(3*3) = 3
(3 + 3+ 3+ 3) / 3 = 4
(3 * 3) - (3 + 3/3) = 5
((3*3*3)/ 3)) - 3 = 6
(3 * 3) - 3 + 3/3 = 7
(3*3*3 - 3) / 3 = 8
(3 + 3+3 + 3) - 3 = 9
3 + 3 + 3 + 3/3 = 10.
A system of equations is shown below: Equation A: 3c = d − 8 Equation B: c = 4d + 8 Which of the following steps should be performed to eliminate variable d first?
Answer:
multiplying the equation A
Step-by-step explanation:
3c=d-8 ####### *4
+ c=4d + 8
After that you will get the value of c and d.
Answer:
Multiply equation A by -4
Step-by-step explanation:
3c = d - 8
c = 4d + 8
Multiply equation A by -4.
-12c = -4d + 32
c = 4d + 8
Add the equations.
-11c = 40
Variable d is eliminated.
There are three persons aged 60, 65 and 70 years old. The survival probabilities for these
three persons for another 5 years are 0.7.0.4 and 0.2 respectively. What is the probability
that at least two of them would survive another five years?
Answer:
Probability that at least two of them would survive another five years = 0.388
Step-by-step explanation:
We are given;
Probability of Survival of 60 years old for the next 5 years;
P(60 years old surviving) = 0.7
Thus;
Probability of 60 years old not surviving for the next 5 years;
P(60 years old not surviving) = 1 - 0.7 = 0.3
Also,given;
Probability of Survival of 65 years old for the next 5 years;
P(65 years old surviving) = 0.4
Thus;
Probability of 65 years old not surviving for the next 5 years;
P(65 years not surviving) = 1 - 0.4 = 0.6
Also,given;
Probability of Survival of 70 years old for the next 5 years;
P(70 years old surviving) = 0.2
Thus;
Probability of 70 years old not surviving for the next 5 years;
P(70 years not surviving) = 1 - 0.2 = 0.8
Probability that at least two survived is;
P(at least 2 surviving) = [P(60 surviving) x P(65 surviving) x P(70 not surviving)] + [P(60 surviving) x P(65 not surviving) x P(70 surviving)] + [P(60 not surviving) x P(65 surviving) x P(70 surviving)] + [P(60 surviving) x P(65 surviving) x P(70 surviving)]
P(at least 2 surviving) = [(0.7)(0.4)(0.8)] + [(0.7)(0.6)(0.2)] + (0.3)(0.4)(0.2) + [(0.7)(0.4)(0.2)]
P(at least 2 surviving) = 0.224 + 0.084 + 0.024 + 0.056
P(at least 2 surviving) = 0.388
What is the rule of 72 used to determine? A. the approximate time it takes an investment to triple in value B. the approximate time it takes an investment to double in value C. the approximate time it takes to earn 10% interest D. the approximate time it takes to earn $72 on any investment amount
Answer:
b. the approx time it takes an investment to double in value
2. Compare the function ƒ(x) = –x^2 + 4x – 5 and the function g(x), whose graph is shown. Which function has a greater absolute maximum (vertex)?
Answer:
g(x)
Step-by-step explanation:
The vertex of g(x) as shwon in the graph is located in the point wich coordinates are (3.5,6.25) approximatively
We need to khow the coordinates of f(x) vertex
Here is a way without derivating:f(x) = -x² + 4x -5
let a be the leading factor, b the factor of x and c the constant:
a= -1b= 4c= -5The coordinates of a vertex are: ([tex]\frac{-b}{2a}[/tex] , f([tex]\frac{-b}{2a}[/tex]) )
-b/2a = -4/ (-1*2) = 4/2 = 2
f(2)= -2²+4*2-4 = -4+4-4 = -4
obviosly f(x) has a minimum wich less than g(x)'s maximum
Answer:
Step-by-step explanation:
g(x) i think
Solve the formula V=LHW for L
Answer:
L = [tex]\frac{V}{HW}[/tex]
Step-by-step explanation:
Given
V = LHW ( isolate L by dividing both sides by HW )
[tex]\frac{V}{HW}[/tex] = L
Answer:
[tex]l = \frac{v}{w \times h} [/tex]
Step-by-step explanation:
[tex]v = l \times w \times h = \frac{v}{w \times h} = \frac{l \times h \times w}{w\times h} = l = \frac{v}{w \times h} [/tex]
Hope this helps ;) ❤❤❤
Factories fully 18x-9
Answer:
Factor 9 out of 18x.
9(2x)−9
Factor 9 out of −9
9(2x)+9(−1)
Factor 9 out of 9(2x)+9(−1)
9(2x−1)
Answer:
9 ( 2x - 1 )
Step-by-step explanation:
→ Look for the HCF of the whole numbers
HCF of 18 and 9 is 9
→ Put 9 outside the brackets
9 ( ? - ? )
→ Perform the calculation 18x ÷ 9 to determine the first question mark
18x ÷ 9 = 2x ⇔ 9 ( 2x - ? )
→ Perform the calculation 9 ÷ 9 to determine the second question mark
9 ÷ 9 = 1 ⇔ 9 ( 2x - 1 )
Use the distributive property to write an equivalent expression to 2(n + 5)
Answer:
2n + 10.
Step-by-step explanation:
2(n + 5)
= 2 * n + 2 * 5
= 2n + 10.
Hope this helps!
Answer: 2n + 10
Explanation: In this problem, the 2 "distributes" through the parenthses which means that it multiplies by each of the terms inside.
So we have 2(n) + 2(5) which simplifies to 2n + 10.
A manufacturer claims that the mean tensile strength of thread A exceeds the average tensile strength of thread B. To test his claim, 16 sample pieces of each type of thread are tested under similar conditions. Type A thread had a sample average tensile strength of 185 kg with a standard deviation of 6 kg, while type B thread had a sample average tensile strength of 178 kg with a standard of 9 kg. Assume that both populations are normally distributed and the variances are equal. Test the manufacturers claim using a = 0.05 level of significance.
The complete part of the first sentence is;
A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at least 12 kilograms.
Answer:
we fail to reject the null hypothesis and conclude that the difference of the average tensile strength of thread A and thread B is less than 12
Step-by-step explanation:
We are given;
n_A = 16
n_B = 16
x'_A = 185 kg
x'_B = 178 kg
s_A = 6 kg
s_B = 9 kg
Let μ_A denote the population average tensile strength of thread A
Also, Let μ_B represent the population average tensile strength of thread B
Thus;
Null Hypothesis; H0;μ_A - μ_B ≤ 12
Alternative hypothesis;H1; μ_A - μ_B > 12
From the image attached, with a significance level of 0.05, the critical value for right tailed is 1.645. So we will reject the hypothesis is z > 1.645
Formula for z is;
z = (x'_A - x'_B - d_o)/√((s_A²/n_A) + (s_B²/n_B))
Plugging in the relevant values, we have;
z = (185 - 178 - 12)/√((6²/16) + (9²/16))
z = -5/2.7041634566
z = - 1.849
Since the z-value is less than 1.645,we fail to reject the null hypothesis and conclude that the difference of the average tensile strength of thread A and thread B is less than 12
Help with 5 questions frequency table
Answer:
The given data is:
30, 32, 11, 14, 40, 37, 16, 26, 12, 33, 13, 19, 38, 12, 25, 15, 39, 11, 37, 17, 27, 14, 36
We will fill the table with the relevant information:
Question 1: 21 - 25 (because the previous range stops at 20 and the following range starts at 26)
Question 2: III (write 3 as a tally)
Question 3: II (write 2 as a tally)
Question 4: 8 (write the tally as a number)
Question 5: 4 (write IIII as a number)
Need answers ASAP!!!! (due today)
Answer:
6. 156.6 cm
7. 687.7’
Step-by-step explanation:
45 cm and 150 cm are the legs of one triangle.
The longest side is the hypotenuse.
Apply Pythagorean theorem, since the two triangles are right triangles.
a² + b² = c²
a and b are the legs, c is the hypotenuse.
45² + 150² = c²
24525 = c²
√24525 = c
c = 156.604597634...
c ≈ 156.6
Brain hang-glided from a 520’ high cliff. He landed 450’ away from the base of the cliff. Create a right triangle and apply Pythagorean theorem. The distance he travelled is the hypotenuse of the triangle. The 520’ and 450’ are the legs.
a² + b² = c²
450² + 520² = c²
c² = 472900
c = √472900
c = 687.677249878...
c ≈ 687.7
Answer: 6) =approx 156.60 cm
7) =approx 687.68'
Step-by-step explanation:
6. Let the shortest side of the triangle is AB=45 cm ( ∡A=90° so ABCD is a rectangle). The middle side AD=150 cm. The longest side is BD
The length of BD can be calculated using Phitagore theorem because triangle BAD ia right angle.
BD=sqrt(AD²+AB²)=sqrt(2025+22500)=approx 156.60 cm
7. So we can create the model of the situation described in this problem.
The model is right-angle triangle ABC with side AB=520' ,side AC=450', right angle is A. So we have to find the length of side BC .
BC is hypotenuse of triangle ABC. We can find it using Phitagore theorem again.
BC=sqrt(AC²+AB²)=sqrt(450²+520²)=sqrt(472900)=approx 687.68'