2 Consider the sequence of keys (5,16,22,45,2,10,18,30,50,12,1). Draw the result of inserting entries with these keys (in the given order) into a. An initially empty (2,4) tree. b. An initially empty red-black tree.

Answer:

Following are the statement is given below

if(updateDirection ==1) // check condition

{

++numUsers; // increments the value

}

else

{

--numUsers; // decrement the value

}

Explanation:

Following are the description of statement

Answer:

Replace /* Your solution goes here */ with the following code segment

srand(seedVal);

cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;

cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;

Explanation:

From the code segment, the seedVal has already been declared and initialized to 0; The next step is to seed it as random number using srand.

The first line of the code segment in the Answer section "srand(seedVal); " is used to achieve that task.

Having done that, the next step is to write statements to generate the two random numbers using rand();

When generating random numbers, two things are to be noted;

Here, the lower bound is 0 and the upper bound is 9;

C rand() function uses the following syntax to generate random numbers

rand()%(int)(U - L + 1) + L

Where U = 9 and L = 0

Replacing U and L with there respective values; the syntax becomes

rand()%(int)(9 - 0 + 1) + 0

So, the two print statements will be written as

cout<<rand()%(int)(9 - 0 + 1) + 0;

Also, the question states that, each print statement be ended with a new line;

So, the print statements will be

cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;

Alternatively, by solving (9 - 0 + 1) + 0; the statements can be written as

cout<<rand()%(int)(10)<<endl;

Conclusively, the complete statements is as follows;

srand(seedVal);

cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;

cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;

or

srand(seedVal);

cout<<rand()%(int)(10)<<endl;

cout<<rand()%(int)(10)<<endl;

Answer:

The answer is The Cache Sets (S) = 32, Tag bits (t)=24, Set index bits(s) = 5 and Block offset bits (b) = 3

Explanation:

Solution

Given Data:

Physical address = 32 bit (memory address)

Cache size = 1024 bytes

Block size = 8 bytes

Now

It is a 4 way set associative mapping, so the set size becomes 4 blocks.

Thus

Number of blocks = cache size/block size

=1024/8

=128

The number of blocks = 128

=2^7

The number of sets = No of blocks/set size

=128/4

= 32

Hence the number of sets = 32

←Block ←number→

Tag → Set number→Block offset

←32 bit→

Now, =

The block offset = Log₂ (block size)

=Log₂⁸ = Log₂^2^3 =3

Then

Set number pc nothing but set index number

Set number = Log₂ (sets) = log₂³² =5

The remaining bits are tag bits.

Thus

Tag bits = Memory -Address Bits- (Block offset bits + set number bits)

= 32 - (3+5)

=32-8

=24

So,

Tag bits = 24

Therefore

The Cache Sets = 32

Tag bits =24

Set index bits = 5

Block offset bits = 3

Note: ←32 bits→

Tag 24 → Set index  5→Block offset 3

Answer & Explanation:

To print 10 on a line and each number separated by space; you make the following modifications.

print(str(i)+" ",end=' ')

str(i)-> represents the actual number to be printed

" "-> puts a space after the number is printed

end = ' ' -> allows printing to continue on the same line

if(count == 10):

     print(' ')

The above line checks if count variable is 10;

If yes, a blank is printed which allows printing to start on a new line;

The modified code is as follows (Also, see attachment for proper indentation)

count = 0

for i in range(100,201):

     if(i%6 == 0 and i%5!=0) or (i%5 ==0 and i%6!=0):

           print(str(i)+" ",end=' ')

           count = count + 1

           if(count == 10):

                 print(' ')

                 count = 0

Answer:

bill = 47.28

tip = bill * 0.15

total_pay = bill + tip

each_share = total_pay / 2

print("Each person needs to pay: " + str(each_share))

Explanation:

*The code is in Python.

Set the bill

Calculate the tip, multiply the bill by 0.15

Calculate the total_pay, add bill and tip

Calculate each friend's share, divide the total_pay by 2. Then, print it in required format.

Answer:

Explanation:

The degree of relationship can be defined as the number of occurrences in one entity that is associated with the number of occurrences in another entity. There is the three degree of relationship: One-to-one (1:1) One-to-many (1:M)

Answer:

What i would suggest for the organization is to use the Testing Infrastructure strategy. it is good for your consulting firm because it is less costly and provide security.

Explanation:

Solution

There are different network security strategy which is listed below:

Segment the network:

Segmentation in network is very useful for providing security.If any threat is occur only one segment is effected remaining are safe and it is less cost process. very useful for small organizations.

Test your infrastructure :

Testing infrastructure also very good technique.

Always we have to test our infrastructure whether threat is occur or not.

If any threat is happen we can detect that easily by testing our infrastructure.

Regularly update anti-virus software :

This is very useful for small organizations and it is less cost.with less cost we can provide security for all devices like computer,server,modems etc.

Frequently backup your critical data :

This is very good technique for crucial data.If we backup important data any time that will be useful if any attack is happen.

This is less costs and simple.

Change router default security settings :

Changing router password and settings also helpful for providing security.If we maintain same password and same settings for a long time that may lead to data hacking.It is cost less process very useful for small organizations.

Answer:

d. Port mirror

Explanation:

Port mirroring is a method to monitor network traffic and it is used in the Intrusion Detection Systems. It is also called Switched Port Analyzer and is used to analyse the network errors. This technique basically copies the network packets and sends or transmits these copied packed from one port to another in a network device such as a switch. This means that this technique is used to copy the network packets from one switch port and send the copy of these packets to another port where these packets are monitored. This is how it analyses the network errors and incoming traffic for irregular behavior and also this can be done without affecting the normal operation of the switch and other network processes. It is simple, inexpensive and easy to establish and use. The most important advantage of using mirrored ports is that it catches the traffic on several ports at once or can capture all of the network traffic.

Answer:

Explanation:

To explain how the Optimal Huffman code works we draw the Huffman tree for the set of symbols and the leaves of the tree are symbols

Note; the right and left moves on the tree starting from the root of the tree to the leaves contain 1 and 1

Also each letter in the tree has a code word from the the root to each letter and the code is called ; Huffman codes.

h : 0

g : 10

f  : 110

e : 1110

d : 11110

c : 111110

b : 1111110

a : 11111110

attached is the Huffman tree

Answer:

The program doesn't make use of comments (See Explanation)

Also the source code is attached as image to enable you see the proper format and indexing of the source code

The program using python is as follows

def calc_average(name):

   score = []

   sum = 0

   for j in range(8):

       inp = int(input("Test Score"+str(j+1)+": "))

       score.append(inp)

       sum = sum + inp

       if inp>=90 and inp<=100:

           print("A")

       elif inp>=80 and inp<90:

           print("B")

       elif inp>=70 and inp<80:

           print("C")

       elif inp>=60 and inp<70:

           print("D")

       else:

           print("F")

   avg = sum/8

   print("Result Details of "+name)

   print("Average Score: "+str(avg))

   return avg

def determine_grade(result):

   if float(result) >= 90.0 and float(result) <= 100.0:

       print("Letter Grade: A")

   elif float(result) >= 80.0 and float(result) <90.0:

       print("Letter Grade: B")

   elif float(result) >= 70.0 and float(result) < 80.0:

       print("Letter Grade: C")

   elif float(result) >= 60.0 and float(result) < 70.0:

       print("Letter Grade: D")

   else:

       print("Letter Grade: F")

   print(" ")

for i in range(2):

   name = input("Student Name: ")

   result = calc_average(name)

   determine_grade(result)

Explanation:

def calc_average(name):  -> Declares the function calc_average(name); It accepts local variable name from the main function

   score = []

-> Initialize an empty list to hold test scores

   sum = 0

-> Initialize sum of scores to 0

   for j in range(8):

-> Iterate from test score 1 to 8

       inp = int(input("Test Score"+str(j+1)+": "))

-> This line accepts test score from the user

       score.append(inp)

-> The user input is then saved in a lisy

       sum = sum + inp

-> Add test scores

The following lines determine the letter grade of each test score      

if inp>=90 and inp<=100:

           print("A")

---

      else:

           print("F")

   avg = sum/8  -> Calculate average of the test score

The next two lines prints the name and average test score of the student

   print("Result Details of "+name)

   print("Average Score: "+str(avg))

   return avg

-> This line returns average to the main method

The following is the determine_grade method; it takes it parameter from the main method and it determines the letter grade depending on the calculated average

def determine_grade(result):

   if float(result) >= 90.0 and float(result) <= 100.0:

       print("Letter Grade: A")

   elif float(result) >= 80.0 and float(result) <90.0:

       print("Letter Grade: B")

   elif float(result) >= 70.0 and float(result) < 80.0:

       print("Letter Grade: C")

   elif float(result) >= 60.0 and float(result) < 70.0:

       print("Letter Grade: D")

   else:

       print("Letter Grade: F")

   print(" ")

for i in range(2):

-> This is the main method

   name = input("Student Name: ")  -> A local variable stores name of the student

   result = calc_average(name)  -> store average of scores in variable results

   determine_grade(result)-> Call the determine_grade function

In this exercise we have to use the computer language knowledge in python to write the code as:

the code is in the attached image.

In a more easy way we have that the code will be:

def calc_average(name):

  score = []

  sum = 0

  for j in range(8):

      inp = int(input("Test Score"+str(j+1)+": "))

      score.append(inp)

      sum = sum + inp

      if inp>=90 and inp<=100:

          print("A")

      elif inp>=80 and inp<90:

          print("B")

      elif inp>=70 and inp<80:

          print("C")

      elif inp>=60 and inp<70:

          print("D")

      else:

          print("F")

  avg = sum/8

  print("Result Details of "+name)

  print("Average Score: "+str(avg))

  return avg

def determine_grade(result):

  if float(result) >= 90.0 and float(result) <= 100.0:

      print("Letter Grade: A")

  elif float(result) >= 80.0 and float(result) <90.0:

      print("Letter Grade: B")

  elif float(result) >= 70.0 and float(result) < 80.0:

      print("Letter Grade: C")

  elif float(result) >= 60.0 and float(result) < 70.0:

      print("Letter Grade: D")

  else:

      print("Letter Grade: F")

  print(" ")

for i in range(2):

  name = input("Student Name: ")

  result = calc_average(name)

  determine_grade(result)

See more about python at brainly.com/question/26104476

All of the following are true about hacksaws, except a coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. The correct option is b.

A hacksaw is a saw with fine teeth that were originally and primarily used to cut metal. Typically, a bow saw is used to cut wood and is the corresponding saw.

Hacksaw is used by hand, it is a small tool for cutting pipes rods wood etc that is very common and homes and in shops. The different types of hacksaws. The main three types of hacksaws are course-grade hacksaws, medium-grade hacksaws, and fine-grade hacks. The difference is just for the quality, and the design of the blade.

Therefore, the correct option is b. Cutting thick steel is easier with a coarse hacksaw blade (one with fewer teeth) than a fine one.

To learn more about hacksaw, refer to the below link:

https://brainly.com/question/15611752

#SPJ2

Answer:

Explanation:

The solution is written in Java.

Firstly, create an integer array with size 51. The array will have 51 items with initial value 0 each (Line 5).

Create a Scanner object and get user entry the number of input (Line 6-7).

Use the input number as the limit to control the number of the for loop iteration to repeatedly get integer input from user (Line 9-13). Whenever user input an integer, use that integer, k, as the index to address the corresponding items in the array and increment it by one (LINE 11-12).

At last, create another for loop to iterate through each item in the array and check if there is any item with value above zero (this means with occurrence at least one). If so, print the item value as number of occurrence (Line 14-17).

Answer:

current_price = int(input("Enter the current price: "))

last_months_price = int(input("Enter the last month's price: "))

print("This house is $" + str(current_price))

print("The change is $" + str(current_price - last_months_price) + " since last month")

print("The estimated monthly mortgage is ${:.2f}".format((current_price * 0.051) / 12))

Explanation:

Ask the user to enter the current price and last month's price

Print the current price

Print the change in the price, subtract the last month's price from the current price

Print the estimated monthly mortgage, use the given formula to calculate, in required format

Answer:

Following are the code to this question:

import java.util.*;//import package for user input

public class Exercise04_17 //defining class Exercise04_17

{

public static void main(String[] as)//defining the main method  

{

int y,d=0; //defining integer variable

String m;//defining String variable

Scanner oxc=new Scanner(System.in);//creating scanner class object oxc

System.out.print("Enter a year: ");//print message

y=oxc.nextInt();//input year value which store in y variable

System.out.print("Enter a month: ");//print message

m=oxc.next();//input month value which store in m variable

if(m.equals("Jan")||m.equals("Mar")||m.equals("May")||m.equals("Jul")||m.equals("Aug")||m.equals("Oct")||m.equals("Dec"))//defining if block to check Month value

{

d=31;//assign value in d variable

}

if(m.equals("Apr")||m.equals("Jun")||m.equals("Sep")||m.equals("Nov"))//definingif block to check month value

{

d=30;//assign value in d variable

}

if(m.equals("Feb"))//defining if block to check month value is Feb

{

if(y%4==0||y%400==0)//defining if blook to check leap year

{

d=29;//assign value in d variable

}

else//else block

{  

d=28;//assign value in d variable

}

}

if(d!=0)//defining if block that check d variable value not equal to 0

{

System.out.println(m+" "+y+" has "+d+" days");//print inserted value with message

}

else//else block

{

System.out.println(m+" is not a correct month name");//print message

}

}

}

Output:

please find the attachment.

Explanation:

Description of the code:

Answer:

Hello your question lacks the required options

A) Business impact analysis plan

B) Business continuity plan

C) Disaster recovery plan

D) Recovery point plan

answer : Disaster recovery plan ( c )

Explanation:

The Disaster recovery  plan is a comprehensive creation of a system/set procedures of recovery of the IT infrastructure from potential threats of a company. especially when the interruption is caused by a disaster, accident or an emergency.

The shutting down of the sever due to overheating and not able to restart for Business is an interruption in a critical business process and the plan to direct the recovery for this single server should be the " Disaster recovery plan"

Answer:

c. role- or function-specific.

Explanation:

The Security Configuration Wizard was  firstly used by Microsoft in its development of the Windows Server 2003 Service Pack 1. It provides guidance to network security administrators, secure domain controllers, firewall rules and reduce the attack surface on production servers.

Security Configuration Wizard saves any changes that are made as a role- or function-specific security policy which can be used as a baseline and applied to other servers in the network.

After checking the Group policy by an administrator, any changes made as a role- or function-specific security policy by the Security Configuration Wizard (SCW) is used as a baseline and can be applied either immediately or sometimes in the future to other servers in the network after testing it in a well secured environment.

Basically, the Microsoft Security Configuration Wizard (SCW) typically help administrators in running the following;

1. Role-Based Service Configuration.

2. Registry settings.

3. Network and Firewall Security settings.

4. Auditing Policy settings.

Answer:

Please see the attachment for the solution

Explanation:

Answer:

Your answer can be found in the explanation below.

Explanation:

GSM is the abbreviation for Global System for Mobile communication. Its purpose is to transmit voice and data services over a range. It is a digital cellular technology.

PLMN is the abbreviation for Public Land Mobile network. It is defined as the wireless communication service or combination of services rendered by a telecommunication operator.

The plmn consists of technologies that range from Egde to 3G to 4G/LTE.

PLMN consists of different services to its mobile subscribers or users but for the purpose of this question, i will be pointing out just 5 of them alongside its definitions.

1. Emergency calls services to fire or police: Plmn provides us with the option to make emergency calls in the event of any accident or fire incident, etc.It is available on devices either when locked or unlocked.

2. Voice calls to/from other PLMN: This entails the putting of calls across to persons we cannot reach very quickly. PLMN helps to connect persons through its network of from other networks thus making communication easier.

3. Internet connectivity: PLMN provieds us with internet services through wifi or bundles that enable us have access to the internet as well as help us communicate with people and loved ones over a distance. Internet service are possble either on GPRS or 3G or 4G networks.

4. SMS service: SMS means short messaging service. This is also know as text messages. PLMN allows us to be able to send short messages to people as oppposed to mails. It is mostly instant and can be sent or recieved from the same PLMN or others.

5. MMS service: Multimedia messaging service whose short form is MMS ccan be descibed as the exchange of heavier messages such as a picture or music or document but not from an email. It is availabel for use from one PLMN to another.

Cheers.

Answer:

During a traceroute, the router decreases the Time To Live values of the packet sent from the traceroute by one during routing, discards the packets whose Time To Live values have reached zero, returning the ICMP error message ICMP time exceeded.

Explanation:

Traceroute performs a route tracing function in a network. It is a network diagnostic commands that shows the path followed, and measures the transit delays of packets across an Internet Protocol (IP) network, from the source to the destination, and also reports the IP address of all the routers it pinged along its path. During this process, the traceroute sends packets with Time To Live values that increases steadily from packet to packet; the process is started with Time To Live value of one. At the routers, the Time To Live values of the packets is gradually decreased by one during routing, and the packets whose Time To Live values have reached zero are discarded, returning the ICMP error message ICMP Time Exceeded

Answer:

Brainliest!

Explanation:

The primary or most-commonly-used HTTP verbs (or methods, as they are properly called) are POST, GET, PUT, PATCH, and DELETE. These correspond to create, read, update, and delete (or CRUD) operations, respectively. There are a number of other verbs, too, but are utilized less frequently.

-

restapitutorial

.

com

AJAX

The word that is not an HTTP verb is AJAX.

But PUT, GET, and DELETE are HTTP verbs.

A HTTP verb is a word or method (it can also be a noun) for retrieving information (documents) in a web-based environment.  There are other HTTP verbs used for various purposes.  The most common include PUT, GET, DELETE, and POST.

HTTP is a computer-based abbreviation that means Hypertext Transfer Protocol.  It is the protocol for transferring data over the web using a client's home computer, laptop, or mobile device.

AJAX, which means Asynchronous Javascript and XML, is mainly used as a technique for creating fast and dynamic web pages using small amounts of data.

There is no suitable reference of HTTP verbs at brainly.com.

Answer:

The question seem incomplete as the list is not given and the programming language is not stated;

To answer this question, I'll answer this question using Python programming language and the program will allow user input.

Input will stop until user enters 0

The program is as follows

newlist = []

print("Input into the list; Press 0 to stop")

userinput = int(input("User Input:"))

while not userinput == 0:

     newlist.append(userinput)

     userinput = int(input("User Input:"))

is_ascending = "True"

i = 1

while i < len(newlist):  

     if(newlist[i] < newlist[i - 1]):  

           is_ascending = "False"

     i += 1

print(newlist)

print(is_ascending)

Explanation:

This line declares an empty list

newlist = []

This line prompts gives instruction to user on how to stop input

print("Input into the list; Press 0 to stop")

This line prompts user for input

userinput = int(input("User Input:"))

This next three lines takes input from the user until the user enters 0

while not userinput == 0:

     newlist.append(userinput)

     userinput = int(input("User Input:"))

The next line initialized "True" to variable is_ascending

is_ascending = "True"

The next 5 line iterates from the index element of the list till the last to check if the list is sorted

i = 1

while i < len(newlist):  

     if(newlist[i] < newlist[i - 1]):  

           is_ascending = "False"

     i += 1

The next line prints the list

print(newlist)

The next line prints the value of is_ascending

print(is_ascending)

Answer:

Explanation:

Firstly, declare the necessary variables and initialize them with zero (Line 4-8). Next create a Scanner object to get user input for score (Line 10). Create a while loop by using the counter as limit (Line 12). In the while loop, prompt user to input a number between 1 - 100 (Line 13-14). Create another while loop to check the input must be between 1 - 100 or it will print invalid message and ask for user input again (Line 15-19).

Next, create an if-else statement to check if the current score is equal or above 60. If so print pass if not print fail (Line 21-27). At the same time increment the fail and pass counter.

Create another two if statement to get the current highest and lowest score and assign them to highest and lowest variables, respectively (Line 29-35).

Increment the counter by one before proceeding to the next loop to repeat the same process (Line 37).

At last, print the required output after finishing the while loop (Line 40-43).

Answer:

The cout<<numInsects<<""; statement should be placed before numInsects = numInsects * 2;  in the while loop.

Explanation:

Your program gives the following output:

16  32  64  128

However it should give the following output:

8  16  32  64

Lets see while loop to check what you did wrong in your program:

The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100.

So the body of while loop executes. numInsects = numInsects * 2;  statement in the body multiplies the value of numInsects i.e 8 with 2 and then cout << numInsects << " ";  prints the value of numInsects  AFTER the multiplication with 2 is performed. So 8 is not printed in output but instead 16 (the result of 8*2=16) is printed as the result of first iteration.

So lets change the while loop as follows:

while (numInsects < 100) {

cout << numInsects << " ";

numInsects = numInsects * 2;

Now lets see how it works.

The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100

So the body of while loop executes. cout << numInsects << " "; first prints the value of numInsects i.e. 8. Next numInsects = numInsects * 2;  multiplies the value of numInsects i.e 8 with 2. So first 8 is printed on the output screen. Then the multiplication i.e. 8*2=16 is performed as the result of first iteration. So now value of numInsects becomes 16.

Next the while loop condition numInsects < 100 is again checked. It is true again as 16<100. Now cout << numInsects << " "; is executed which prints 16. After this, the multiplication is again performed and new value of numInsects becomes 32 at second iteration. This is how while loops continues to execute.

So this while loop stops when the value of numInsects exceeds 100.

Answer:

Let f be a function  

a) f(n) = n²  

b) f(n) = n/2  

c) f(n) = 0  

Explanation:  

a) f(n) = n²  

This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.  

Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:

                               f(a) = f(b) ⇒ a² = b² ⇒ a = b  

The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number.  For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.  

b) f(n) = n/2  

The above function example is an onto function because every natural number, let’s say n is a natural number that belongs to N, is the image of 2n. For example:

                               f(2n) = [2n/2] = n  

The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:  

When the value of n=1, then

                                  n/2 = [1/2] = [0.5] = 1  

When the value of n=2 then  

                                   n/2 = [2/2] = [1] = 1  

c) f(n) = 0

The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image.  The above function example is also not an onto function because every positive integer is not an image of any natural number.

Answer:

A bandwidth is the maximum rate of transfer of data across a given path

Latency refers to the delay of data to travel or move between a source and destination

An example of a high bandwidth and high latency network is the Satellite Internet connectivity.

An example of a low bandwidth and latency network is the telephone system connection.

Explanation:

Solution

Bandwidth: Bandwidth determines how fast data can be transferred for example, how many bits/sec it can transport.

Latency: It refers to the delay or how long it takes for data to travel between it's source and destination.

An example of a high bandwidth and high latency network is the Satellite internet connection.

Satellite internet connection: This is responsible for the connectivity of several systems, it has a high bandwidth, since satellite are in space, due to distance it has a high latency.

So, satellite internet connection is compensated with high latency and high bandwidth.

An example of a low bandwidth and low latency network is the Telephony network.

Telephone/telephony internet connection: This connection does not have much data for transfer. it has low size audio files of which a low bandwidth range. also for both end or end users to understand and talk to each other, it has low latency.

An example of a network that exhibits high bandwidth but also high latency is Satellite internet connection.

An example of one that has both low bandwidth and low latency is telephony internet connection.

Based on the provided information, we can say that Satellite internet connection posses high bandwidth but also high latency because, the fastness of data transfer is based on the bandwidth and how the data to travel between it's source and destination is based on its latency.

We can conclude that telephony internet connection has low bandwidth and low latency because of low data transfer is required.

Learn more about bandwidth at;

https://brainly.com/question/11408596

Answer:

a. cyberterrorism.

Explanation:

Cyberterrorism can be defined as an illegal attack against the information stored in a data based done so as to intimidate a target. This is done to coerce a  target to action or to frustrate and destabilize a target.

In this act, the data compilations or information systems is deliberately attacked to disrupt the psychology of a target. It is one of the major tactics used in politics to frustrate the effort of a political system by an opposition.

Answer:

The overview of the given question is described in the explanation segment below.

Explanation:

The number of casualties has occurred in recent years. The following are indeed the assaults:

Arbitrary Remote Code execution attacks:

It's also a very hazardous assault. Unsanitary working on implementing that used operating system including user actions could enable an attacker to execute arbitrary functions mostly on system files.

Sites become targeted with such a DOS assault that will cause them inaccessible whether they close the account to an offender who threatens them.

Prevention: We could protect this by preventing the call from additional assessment by the user. We will disinfect input validation if we transfer values to devise calls. The input data is permitted to transfer on requests, it should have been strictly regulated although restricted to a predetermined system of principles.

Injection attack:

The object of the Injection Attack seems to be to delete vital information from the server. Throughout the list, we have such a user, a code, as well as a lot of several other essential stuff. Assailants are taking vital data and doing the wrong stuff. This can have an impact on the web site or software application interface the SQL.

Prevention: Parameterized functions require developers must specify all of the SQL code, and afterward move the question in-parameter, allowing the server to distinguish between some of the code as well as the information. By decreasing the privilege allocated to each database. White list data validation has been used to prevent abnormal information.

Zero-day attack:

It corresponds to something like a vulnerability flaw undisclosed to the user. The security vulnerability becomes infected with malware. The attackers have access to inappropriate details.

Prevention: The organizations are releasing the patch fixes the found holes. The updated plugin is also a preventive tool.

Buffer overflow attack:

This is indeed a major security threat to the accuracy of the data. This overflow happens since more information becomes set to either a specified size than even the buffer could accommodate. Adjoining program memory is compromised. During that time, the attacker was indeed running obfuscated code. Two key forms of such attack are provided below:

Prevention: Standard library features, including such strcpy, should indeed be avoided. Standard testing should be performed to identify as well as resolve overflow.

Answer:

#include <iostream>

using namespace std;

int main()

{

   const int YEAR = 2050;

   int currentYear = 2020;

   int currentAge = 38;

   cout<<"You will be " << currentAge + (YEAR - currentYear) << " years old in " << YEAR;

   return 0;

}

Explanation:

Initialize the YEAR as a constant and set it to 2050

Initialize the currentYear as 2020, and currentAge as 38

Calculate and print the age in 2050 (Subtract the currentYear from the YEAR and add it to the currentAge)