Answer:
c, 280,000J
Explanation:
You should use the equation KE (Kinetic Energy) = [tex]\frac{1}{2} mv^2[/tex]
m = 2500
v = 15
KE = [tex]\frac{1}{2} * 2500 * (15)^2\\[/tex]
KE = 281250 Joules.
This is consistent with the answer B, as all of the parameters given to you are rounded to 2 significant figures so naturally, the answer should also be rounded to 2 sig figs.
KE = 280,000 J
a car takes 4 hours to cover a distance if it takes at a speed of 40mph. what should be it's speed to cover the same distance in 1.5 hours
Answer:
Speed = 106.67mph
Explanation:
Let the first motion be A.
Given the following data;
Speed A = 40mph
Time A = 4 hours
To find the distance covered in A;
Distance = speed * time
Distance = 40 * 4
Distance = 160 miles.
To find the speed required to cover the above distance in 1.5 hours;
Speed = distance/time
Speed = 160/1.5
Speed = 106.67mph
Which examples best demonstrate likely tasks for Legal Services workers? Check all that apply.
Cisco inspects an office building to make sure it meets fire safety regulations.
Gina gathers information about a court case.
Saul oversees inmates at a correctional facility.
Hana interviews and advises a person who has been accused of a crime.
Pamela pursues and arrests a person suspected of a crime.
Dewayne creates the paperwork for a business contract.
Answer:
b. d. f.
Explanation:
Got it right on Edge
Answer:
2. Gina gathers information about a court case.
4. Hana interviews and advises a person who has been accused of a crime.
6. Dewayne creates the paperwork for a business contract.
There is a current of 2.95 A in one of the copper wires for 60 seconds. Calculate the charge flow through the wire.
Answer:
177 coulomb
Explanation:
Given data
I=2.95A
T=60
The relationship between current I and quantity of charge Q.
Q=IT
Substitute
Q=2.95*60
Q=177 coulomb
If a man with
with long-sighted eye want to
a' text book, what shoðld be the distance between
book and the lens? Give reason
Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?
Answer:
The net charge on each sphere is -1.5 q
Explanation:
Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]
The net charge on each sphere, Q = -1.5 q.
The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
What is charge?Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]
Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
To know more about Charge follow
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Hell it’s due soon??
Explanation:
don't know don't know don't know
Sometimes, a crackling sound is heard while taking off a sweater during winters. Explain
Answer:
it is somewhat frozen
Explanation:
Suman with a mass of 45kg climbs in 3m heigh ladder in 10 seconds. Calculate her power. Plz help me
Answer:
work done=fdcosø
f=mg=450N
d=+3m
ø=180
450×3×cos(180°) power=work done/
time taken
1350×-1 p=135watts
John slides down a hill at a 4 m height initially at rest. If all energy is conserved and friction is excluded, what is John's velocity at the bottom of the ramp?
The velocity at the bottom : v = 8.85 m/s
Further explanationGiven
height of the hill = 4 m
Required
The velocity at the bottom
Solution
The law of conservation energy :
ME₁=ME₂
(PE+KE)₁ = (PE+KE)₂
initially at rest⇒vo=0⇒KE₁=0
At the bottom⇒h=0⇒PE₂=0
So the equation becomes :
PE₁=KE₂
mgh=1/2.mv²
gh = 1/2v²
[tex]\tt v=\sqrt{2gh}[/tex]
v = √2x9.8x4
v = 8.85 m/s