Answer:
1. 0.0500 moles K, 0.0250 moles Cr and 0.1000 moles O.
2. 9.00 moles ammonium ions are present.
Explanation:
1. In 1mol of K2CrO4 there are 2 moles of K, 1 mole of Cr and 4 moles of O.
The moles in 0.0250 moles K2CrO4 are:
0.0250mol * 2 = 0.0500 moles K
0.0250mol * 1 = 0.0250 moles Cr
0.0250mol * 4 = 0.1000 moles O
2. In 1 mole of (NH4)2CO3 there are 2 moles of ammonium ions, NH₄⁺.
In 4,50 moles are:
4.50 moles * 2 = 9.00 moles ammonium ions are present
If 5.60 mol of a substance releases 14.9 kJ when it decomposes, what is ΔH for the process in terms of kJ/mol of reactant?
Answer:
The correct approach is "-2.67 kJ/mole". A further solution is described below.
Explanation:
The given values are:
No. of moles,
= 5.60 mol
Substance releases,
ΔH = 14.9 kJ
Now,
The ΔH in terms of kJ/mol will be:
= [tex]\frac{\Delta H}{5.60}[/tex]
On putting the given values of ΔH, we get
= [tex]\frac{-14.9}{5.60}[/tex]
= [tex]-2.67 \ kJ/mole[/tex]
HELP ASAP
Which of these atoms ihas the HIGHEST reactivity?
Answer:
aaaaaaaaaaaaaaaaaaaaaaaaassaaaa
If an object is on top of a hill or in a position raised above the ground, it must have __________.
Answer:
The force applied to the object is an external force, from outside the system. When it does positive work it increases the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0.
If an object is on top of a hill or in a position raised above the ground, it must have gravitational potential energy.
What is Potential Energy ?
In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors
If an object is lifted, work is done against the force of gravity.
When work is done energy is transferred to the object and it gains gravitational potential energy.
If the object falls from that height, the same amount of work would have to be done by the force of gravity to bring it back to the Earth’s surface.
Due to the Principle of Conservation of Energy we can say that:
Gravitational potential energy at the top = kinetic energy at the bottom
To know more about Potential Energy
https://brainly.com/question/24284560
#SPJ2
Calculate the amount of heat energy is needed to raise the temperature of 5.00 grams of lead from 25.0 to 35.0 degrees Celsius, if the specific heat capacity of lead is 0.129 J/g/C.
Answer: 6.45 Joules
Explanation: I just did it
Zn + 2HCl → ZnCl2 + H2
How many moles of hydrogen are produced from the reaction of
6.0 moles of zinc?
Answer:
6
Explanation:
6.0mol ( 1 mol H2/ 1 mol Zn ) = 6.0 mol of H2
H2 is hydrogen gas (hydrogen in the air).
____Al+____O2 → ____Al2O3
Which of the following sets of coefficients would correctly balance the equation and why?
A. 2, 2, 2; because you must use the same coefficient for each substance.
B. 2, 3, 2; because you must have the same number of atoms on each side of the equation.
C. 4, 3, 2; because you must have the same number of compounds on each side of the equation.
D. 4, 3, 2; because you may have the same number of atoms on each side of the equation
Answer:
D
Explanation:
You balance an equation so that all the elements have the same number of atoms on each side of the equation.
.What is the significance of genetic variation within the population of moths during and after the Industrial Revolution in London?
Answer:
The evolution of the peppered moth is an evolutionary instance of directional colour change in the moth. The frequency of dark-coloured moths increased at that time, an example of industrial melanism.
Explanation:
I did this on Savvas Realize got it right.
Genetic variation is said to be the difference in the hereditary sequence. After the industrial revolution, the frequency of the dark-colored moth increased dramatically more than the light-colored moths.
What is industrial melanism?
Industrial melanism was an example of the evolutionary effect that occurred in the moths where the dark-colored species were favored over the light-colored species of peppered moths.
Before the industrial population, light-colored moths were large in number which later decreased with an increase in pollution. This occurred due to an increase in the pollutants and dust deposition that altered the environment.
As the pollution increased over time the dark-colored moths became dominant and increased their population over time. This is an example of industrial melanism as the color of the body was the determining factor in survival.
Therefore, dark-colored moths were prevalent after the industrial revolution.
Learn more about industrial melanism here:
https://brainly.com/question/15283847
#SPJ5
How much energy is released when 75g of liquid water is reduced from 65c to 0c and completely freezes?
Answer:
Q = 20377.5 Joules
Explanation:
Given the following data;
Mass = 75g
Initial temperature = 65°C
Final temperature = 0°C
Specific heat capacity of water = 4.18 J/g°C.
To find the quantity of heat released;
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Substituting into the equation, we have;
[tex] Q = 75 * 4.18 * 65 [/tex]
Q = 20377.5 Joules
Which of the following is NOT a type of mucle tissue?
Cardiac
Smooth
Striped
Skeletal
Answer:
Striped should be the answer
Describe how you could show that a compound is an acid
Given the following equation: Na2O + H2O ---> 2 NaOH
How many moles of NaOH are produced from 1.02 moles of Na2O?
Answer:
2.04 moles
Explanation:
Since the ratio of Na2O to NaOH is 1:2, you multiply the number of moles by 2, equaling 2.04 moles.
how to calculate the mass percent of hydrogen
Answer:
divide the mass of element in 1 mole of the compound by the compound's molar mass and multiply the answer by 100.
Explanation:
take the molar mass of hydrogen in the water molecule, divide by the total molar mass of water, and multiply by 100.
does it help?
If we were to add a piece of solid Cu to an aqueous solution (in water) of silver nitrate, the Silver would be replaced in a single replacement reaction forming aqueous copper (II) nitrate and solid silver. How much silver, in grams, is produced if 15.00 grams of Cu is added to the solution of silver nitrate
Answer:
50.9 g of Ag
Explanation:
Reaction is:
Cu (s) + 2AgNO₃(aq) → 2Ag (s) + Cu(NO₃)₂ (aq)
1 mol of Cu react to 2 moles of silver nitrate in order to produce 2 moles of solid silver and 1 mol of copper (II) nitrate.
We assume, the silver nitrate in excess.
We determine moles of copper → 15 g . 1mol / 63.55 g = 0.236 moles
Ratio is 1:2. 1 mol of copper produce 2 moles of silver
0.236 moles of Cu will produce (0.236 . 2) / 1 = 0.472 moles of Ag
We deterine mass of silver:
0.472 mol . 107.87 g /mol = 50.9 g
In order to calculate the number of neutrons you must subtract the what from the what?
Answer:
You take the atomic, or proton number of the element, and you subtract it from the element's mass number.
Answer:
protons
Explanation:
neutrons and protons make up the mass of the atom
How many moles are in 15.3 grams of KNO3?
Answer:
0.151 mol
Explanation:
molar mass of KNO3 = (39.1 + 14 + 3×16) g/mol = 101.1 g/mol
number of moles = mass/molar mass
n = m/M = 15.3 g/(101.1 g/mol) = 0.151 mol
A cylinder is filled with 10.0 L of gas and a piston is put into it. The initial pressure of the gas is measured to be 273. kPa.
The piston is now pulled up, expanding the gas, until the gas has a final volume of 50.0 L. Calculate the final pressure of the gas. Be sure your answer has the
correct number of significant digits.
P2 = 54.6 kPa
Explanation:
Given:
V1 = 10.0 L. V2 = 50.0 L
P1 = 273 kPa. P2 = ?
We can use Boyle's law to solve this problem.
P1V1 = P2V2
Solving for P2,
P2 = (V1/V2)P1
= (10.0 L/50.0 L)(273 kPa)
= 54.6 kPa
B. Radiation
D. roasting
How do vibrations of particles behave when sounds travel through solids?
A occurs fast
C. occurs moderately
B. occurs very slowly
D. cannot be determined
Hurry please need fast
In the following chemical phrase how many moles of O are there? 6
C2H602* 2
6
12
3
1.16g of methane burns completely with 4.16g of oxygen to form 3.52g of carbon dioxide and
water If the reaction obeys the law of conservation of mass, the weight of water formed is
Answer:
weight of H₂O formed = 2.3 grams H₂O (2 sig. figs.)
Explanation:
Rxn: CH₄(g) + 2O₂(g) => CO₂(g) + 2H₂O(g)
Given: 1.16g 4.16g 3.52g ? (g)
Moles: 1.16g/16g·mol⁻¹ 4.16g/32g·mol⁻¹ 3.52g/44g·mol⁻¹
= 0.0725mol. = 0.13mol. = 0.08mol. => ? (moles)
Limiting Reactant: Divide each mole value by related coefficient of balanced standard equation (that is, balanced with coefficients in lowest whole number ratios). The smaller value is the limiting reactant.
0.0725/1 0.13/2 0.080/1
= 0.0725 = 0.065 = 0.080
Limiting Reactant is O₂(g) => 0.065 is smaller value after dividing each mole value by related coefficient of balanced equation.
NOTE: When working problem, however, one must use the mole value calculated from given amount in grams. That is, in this case 0.13 mole O₂. The 'divide by related coefficient and check smaller value' is ONLY for identifying the limiting reactant. This trick works for ALL general chemistry problems.
Moles H₂O formed: Since the coefficient of the limiting reactant (O₂) equals the coefficient of water (H₂O), then the moles of water formed is 0.065 mole H₂O.
Weight (in grams) of H₂O formed:
Grams H₂O = moles H₂O x formula weight H₂O
= 0.13 mole H₂O x 18 g H₂O/mole H₂O
= 2.34 g H₂O (calculator answer)
= 2.3 g H₂O (final answer should be rounded to 2 sig. figs.) => form of final answer should be based on data in final computation having the least number of sig. figs.
Review: Sequence of calculations
Write and balance equation to smallest whole no. ratio of coefficients.If not in moles, convert given 'measured' data to dimension of moles. => moles = mass (g)/formula wt(g·mol⁻¹) => moles = volume of gas in Liters/Std Molar Volume (= 22.4L·mole⁻¹ at STP) => moles = no. of particles / Avogadro's No. (= 6.02 x 10²³ part's/mole)Determine Limiting Reactant => mole values of each compound given / related coefficient in standard equation => smallest value is L.R.Determine moles of unknown needed/used/formed from limiting reactant in moles and coefficient of unknown compound in standard equation given data values.=> moles of limiting reactant / coefficient of same cpd. in std. equation = unknown (X) / coefficient of same (unknown) cpd. in std. equation
=> cross multiply and solve for unknown (X)
=> L.R.(moles) / eqn. coef. of L.R. = X / eqn. coef. of X
=> (L.R.(calc'd moles)(eqn. coef. of X) = (X)(eqn. coef. of L.R.)
=> X (in moles) = (L.R.(calc'd. moles)(eqn. coef. of X) / (eqn. coef. of L.R.)
Convert X-answer in moles to desired dimension specified in problem.=> grams = moles x formula wt.
=> volume (L) = moles x std. volume (= 22.4L/mole)
=> #particles = moles x Avogadro's Number (= 6.02 x 10²³ parts/mole)
gu khayo bhana m hunxa hola
Answer:
[tex] \huge\pink{\boxed{\mathfrak{Hola}}}[/tex]
I didn't understand the rest of your question, it's not in English or Spanish.
[tex]\huge\fbox{HôLLa}[/tex]
The decomposition of water into hydrogen gas Hy and oxygen gas Oz can be modeled by the balanced chemical equation
A)
H2 + 02 - H20
B)
H20 - H2 + O2
C) 2H2 + 02 - 2H20
D)
2H20 - 2H2 + O2
Answer:
D. ) 2H2O - 2H2 + O2
Look at the diagram below. According to the diagram, what substance(s) are the
reactant(s)? What substance(s) are the product(s)? Explain your reasoning.
NH3(aq) + HCI (aa)
Ammonia Hydrochloric acid
NHCI (aa)
Ammonium chloride
You will be graded on the following rubric:
luje
Answer:
NH3(aq) and HCl(aq) are the reactants, while NH4Cl(aq) is the product.
Explanation:
The hydrogen atom from the HCl molecule joins the other three in NH3 creating a four hydrogen molecule, NH4Cl.
What must happen to uranium before it can be used as a fuel source?
A. No changes are necessary.
B. Stable U-235 must be enriched with 3% radioactive U-238.
C. Stable U-238 must be enriched with 3% radioactive U-235.
D. Unstable U-235 must be enriched with 5% U-238 to stabilize it.
Answer:
D
Explanation:
Before it can be used in a reactor for electricity generation, however, it must undergo a series of processes to produce a useable fuel. For most of the world's reactors, the next step in making the fuel is to convert the uranium oxide into a gas, uranium hexafluoride (UF6), which enables it to be enriched.
Unstable U-235 must be enriched with 5% U-238 to stabilize it. Hence, option D is correct.
What is radioactive?Radioactivity is the phenomenon of the spontaneous disintegration of unstable atomic nuclei into atomic nuclei to form more energetically stable atomic nuclei.
Before uranium can be used in a reactor for electricity generation, however, it must undergo a series of processes to produce a useable fuel.
For most of the world's reactors, the next step in making the fuel is to convert the uranium oxide into a gas, uranium hexafluoride (UF6), which enables it to be enriched.
Hence, option D is correct.
Learn more about radioactive here:
https://brainly.com/question/1770619
#SPJ2
Atoms that have become negatively charged by gaining extra electrons are called
Answer:
CATION
Explanation:
If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion. If it loses an electron, it becomes positively charged and is known as a cation.
How is a TV like our brain?
Answer:
Explanation:
Because your brain and the TV are programed to do certain things. As if you're going back into a memory, and you're simply rewatching a season of Beyblade: Metal Fusion on the TV.
Use the information provided in the table to
determine the K, for methylammonium ion, the
conjugate acid of methylamine.
X6.8 x 10-19
4.4 x 1010
2.8 x 109
2.3 x 10-11
Answer: D
Explanation:
2.3x10-11
Answer:
D. 2.3 x 10^-11
Explanation:
Look at the image below
A gas occupies 4.31 liters at a pressure of 150 mm Hg. Determine the volume if the pressure is increased to 725 mm Hg.
Answer:
0.89 L
Explanation:
Applying,
Boyle's Law,
PV = P'V'..................... Equation 1
P represent initial pressure, V represent initial volume, P' represent final pressure, V' represent final volume
Make V' the subject of the equation
V' = PV/P'.............. Equation 2
From the question,
Given: P = 150 mm Hg, V = 4.31 liters, P' = 725 mm Hg
Substitute these values into equation 2
V' = (150×4.31)/725
V' = 0.89 L
Hii! i’m timed so can someone please answer quickly!
What is the frequency of this wave? 1,2,3, or 4
I cant find any answers to this question! i really appreciate it!
Count the in between joint bunches of curve lines .
First one at beginninglast one at end .And one is in middleFrequency is 3-1=2
What happens when a current is applied to two electrodes immersed in pure water?
A. No electrolysis occurs, and current does not flow.
B. Oxygen, but not hydrogen, is released as a gas.
C. Electrolysis occurs, releasing oxygen and hydrogen gas.
Answer:
b
Explanation:
Gucci ghhvhjhsgjjn hvh
Answer:
B
Explanation:
Which is not an example of a
parasite/host relationship?
A flea on a dog
A tick on a horse
A toad on a lily pad
A barnacle on a whale
Answer:
A toad on lily pad
Explanation:
have a great day