Answer:
1[tex]s^{2}[/tex]2[tex]s^{2}[/tex]2[tex]p^{6}[/tex]3[tex]s^{2}[/tex]3[tex]p^{6}[/tex]3[tex]d^{10}[/tex]4[tex]s^{2}[/tex]4[tex]p^{6}[/tex] (alternatively 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6)
Explanation:
The correct configuration for bromide ([tex]Br^{-}[/tex]) is:
1[tex]s^{2}[/tex]2[tex]s^{2}[/tex]2[tex]p^{6}[/tex]3[tex]s^{2}[/tex]3[tex]p^{6}[/tex]3[tex]d^{10}[/tex]4[tex]s^{2}[/tex]4[tex]p^{6}[/tex] (it has one more electron in 4p orbital than bromine)
You can also write it as [Ar] [tex]4s^{2}[/tex] [tex]3d^{10}[/tex] [tex]4p^{6}[/tex], since noble gases are very stable
First can't be correct because there is nothing in 3p orbital and 4p has only 5 electrons here
1s² 2s2 2p6 3s2 3p 4s2 3d10 4p5
Second can't be correct because there is nothing in 2p and 4p orbitales 1s2 2s² 2p 3s2 3p6 4s2 3d10 4p
Third can't be correct because there is nothing in 3p orbital and 4p has only 5 electrons here
1s 2s2 2p6 3s2 3p' 4s2 3d10 4p5
Fourth can't be correct because there is nothing in 2p and 3d orbitales, and 4p has only 5 electrons here
1s2 2s2 2p 3s2 3p6 4s2 3dº 4p5
Amy set up the following experiment to study how plant growth is influenced by weather conditions. mc052-1 One pot will model normal growing conditions, and the other will model drought conditions. Which of the following factors is it most important for Amy to change to model drought conditions?
Answer:
lack of sunlight, overcrowded region for shelter of the plants, no nutrients and water supply, etc.
Explanation:
The plants needs favorable climatic conditions and nutrient to grow. Plants need air, sunlight, water, proper temperature, nutrients, etc. grow and make their food. They make their food with the help of sunlight and carbon dioxide by a process called as photosynthesis.
Now in the context, Amy is setting up an experiment where she will study the growth of plants in two models. One in the normal growing conditions and the other in a drought condition.
Drought is considered the most important abiotic factor that limits the growth and adversely affects the growth and the crop. The factor that is important for Amy to change the model into a drought conditions is the lack of water and carbon dioxide in the atmosphere. Also scarcity of sunlight and nutrients. The drought stress is considered as one of the crop performance limiting factors.
The octane rating of gasoline is a relationship of the burning efficiency of the given gasoline mixture to the burning efficiency of octane (C8H18). Like most hydrocarbons, octane reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reaction is
Answer:
C₈H₁₈(l) + O₂(g) ⇒ CO₂(g) + H₂O(l)
Explanation:
Let's consider the unbalanced equation for the combustion reaction of octane.
C₈H₁₈(l) + O₂(g) ⇒ CO₂(g) + H₂O(l)
We can begin balancing H atoms by multiplying H₂O by 9, and C atoms by multiplying CO₂ by 8.
C₈H₁₈(l) + O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)
Finally, we get the balanced equation by multiplying O₂ by 12.5.
C₈H₁₈(l) + 12.5 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)
Answer:
The coefficents will be 2, 25 --> 16, 18
Explanation:
WHAT IS A PLACE WHERE BOOKS ARE CLASSIFIED! I NEED HELP!
Answer:
From the Online Catalog to the Shelf
Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.
Explanation:
Answer:
From the Online Catalog to the Shelf
Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.
Look at the potential energy diagram below. What amount of energy does the products have ?
100
80
PE
50
AB
40
C D
20
Progress of the reaction
40 KJ
60 KJ
O 20 KJ
80 KJ
Answer:
20 kJ
Explanation:
The products are C + D which is on the right side of the diagram. And it says it has 20 kJ of energy.
Which element has a larger atomic size? Nitrogen or phosphorus, explain how you know.
Explanation:
The elements nitrogen and phosphorus are in the same Group 15 with nitrogen being higher, so for the neutral atoms, N with its outer electrons in the n = 2 level would have a smaller radius than P with its outer electrons in the n = 3 level. ... (a) N3- has the largest radius.
On the periodic table, nitrogen and phosphorus can both be found in group 15, with nitrogen in period two and phosphorous in period three. This indicates that phosphorus has more electron shells occupied than nitrogen. Thus, nitrogen's atomic size will be lowered.
What is atomic size ?A chemical element's atomic radius, which is typically the average or typical distance between the nucleus's core and the outermost isolated electron, serves as a gauge for the size of an atom. Considering that the boundary is not a clearly defined physical object.
Atomic radii in the periodic table decrease across a row from left to right and increase across a column from top to bottom. Due to these two patterns, the periodic table's lower left and upper right corners, respectively, contain the largest and smallest atoms.
The size of the atom or ion is determined by the size of the largest filled orbital because electrons are what occupy space in atoms.
Thus, nitrogen's atomic size will be lowered.
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Given that a 0.130 M HCl(aq) solution costs $39.95 for 500 mL, and that KCl costs $10/ton, which analysis procedure is more cost-effective
Answer:
KCl is cost effective
Explanation:
In order to know this, we need to see how much it cost 1 g of each reactant. Let's begin with HCl
HCl:
In this case, let's calculate the moles of HCl in a 0.130 M solution and then, the mass of HCl using the molecular weight of 36.5 g/mol, to get the cost the HCl at the end using the given price:
nHCl = 0.130 moles/L * 0.5 L = 0.065 moles
mHCl = 0.065 moles * 36.5 g/mol = 2.3725 g
Cost HCl = 39.95 $ / 2.3725 g = 16.84 $/g
Conclusion, 1 g of HCl costs 16.84 $
KCl:
In this case, it's pretty obvious that 1 ton of KCl cost 10$, so, there is no need to do further calculations because 1 ton (or more than 1000 kg of the salt) it's just 10$. This is less expensive than the 16.84$ for just 1 g of HCl, so, final conclusion, KCl is more cost-effective.
Hope this helps
One mole (mol) of nitrogen monoxide (NO) has a mass of 30.01 g. When
precisely 2 moles of NO(g) are produced in the following chemical reaction, 43
kcal of heat energy is "absorbed."
N2(g) + O2(g) → 2 NO(g), AH = +43 kcal
How much heat (in kJ) is exchanged when 152 g of NO(g) is produced?
Answer:
455.6 kJ.
Explanation:
Hello there!
In this case, according to the given reaction, we know that 2 moles of NO require 43 kcal of energy, thus, for the energy required by 150 g of NO we first need the moles, considering its molar mass (30.01 g/mol):
[tex]152g*\frac{1mol}{30.01g} =5.065mol[/tex]
Thus, we apply the following dimensional analysis to obtain the energy absorbed by 5.065 moles:
[tex]5.065mol*\frac{43kcal}{2mol} =108.9kcal[/tex]
Which kJ turns out:
[tex]108.9kcal*\frac{4.184kJ}{1kcal}\\\\455.6kJ[/tex]
Best regards!
What kind of solid is diamond (C)?
O A. Ionic solid
O B. Metallic solid
O C. Network solid
D. Molecular solid
Answer:
it will option C because it is formed by carbon chain
Which of the following statements is NOT true about practice?
After mixing the solutions in a separatory funnel, the stopper should be ________and the liquid should be ________and the layers allowed to separate. When you get close to the interface between the layers, ________the funnel and________until the first layer______ is collected. _______to collect the second layer.
Answer:
The answer is below
Explanation:
The separation technique is used for separating immiscible liquids.
When separating, the stopper has to be removed when draining the lower layer so as to prevent a vacuum. If vacuum is allowed, the draining rate will reduce and stop.
The liquid should be mixed by shaking the funnel and then opening the stopcock so as the vent out gases.
When near interface between the layers, you should set your eye level so that you do not drain up to the second layer.
After completely draining the first layer, the second layer should be collected in a new flask.
After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.
After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.
Separatory funnel:It is used in liquid-liquid extractions to separate (partition) the components of a mixture into two immiscible solvent phases of different densities.The lab apparatus majorly used for the separation of the two immiscible solutes in the given mixture. For example, oil and alcohol. It is applicable to separate the solvent which are immiscible and which cannot be separated by steam distillation. This method is useful for liquids only.Learn more:
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What type(s) of orbital overlap is(are) used to form the indicated bond in the following structure.
H H
\ /
C --- C O --- H
// \\ |
H --- C C --- C --- H
\ / |
C == C H
/ ↑ \
H H
A. sp3-s
B. sp2-s
C. sp2-sp2 (I chose C but it is incorrect)
D. sp3-sp2
E. sp3-sp3
F. p=p orbitals
xAl(OH)3 + yH2SO4 ⟶ zAl2(SO4)3 + kH2O?
Answer:
2Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6H2O
Explanation:
How many grams of KCl are produced if 25g of KCIO3 decompose?
2KCIO3
2KCI
+
302
Answer:
15 g
Explanation:
The reaction that takes place is:
2KCIO₃ → 2KCI + 3O₂First we convert 25 g of KCIO₃ to moles, using its molar mass:
25 g ÷ 122.55 g/mol = 0.204 mol KCIO₃Then we convert KCIO₃ moles to KCl moles, using the stoichiometric coefficients:
0.204 mol KCIO₃ * [tex]\frac{2molKCl}{2molKClO_3}[/tex] = 0.204 mol KClFinally we convert KCl moles to grams, using the molar mass of KCl:
0.204 mol KCl * 74.55 g/mol = 15.2 gUnder identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 7.88 mL of O2 had passed through the membrane, but only 3.69 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Answer:
146.5g/mol
Explanation:
The volume of gas effused is directly proportional to the square root of its relative molecular mass.
Let the volume of oxygen gas be V1
Let the volume of the unknown gas be V2
Let the molar mass of oxygen be M1
Let the molar mass of the unknown gas be M2
V1/V2 =√M2/M1
7.88/3.69 = √M2/32
2.14 = √M2/32
(2.14)^2 = M2/32
4.58 = M2/32
M2 = 32*4.58
M2 = 146.5g/mol
Which island is older Kauai or Maui
Answer:
Kauai
Explanation:
I look this up when I am doing math
HELP! URGENT Which of the following best states the relationship between erosion and deposition?
A.
When the energy transporting sediments diminishes, the sediments settle in a low-lying area; therefore, deposition always follows erosion.
B.
When the energy transporting sediments diminishes, the sediments settle in a low-lying area; therefore, erosion always follows deposition.
C.
When rock is broken down into sediments, the sediments are eventually transported to another location; therefore, deposition is a form of erosion.
D.
When rock is broken down into sediments, the sediments are eventually transported to another location; therefore, erosion is a form of deposition.
100 POINTS PLEASE ANSWER!
Read the following chemical equation.
Fe + O2 → Fe2O3
Which of the following fractions can be used for the mole ratio to determine the mass of Fe from a known mass of Fe2O3?
four over two
three over two
two over three
two over four
Answer:
Answer would be 4/2
Explanation:
A is the best answer choice because it was between A and D but 2 is not the denominator so it couldnt be D
Fe + O2 → Fe2O3 four over two fractions can be used for the mole ratio to determine the mass of Fe from a known mass of Fe2O3. Therefore, option A is correct.
What do you mean by mole ratio ?The mole ratio is a conversion factor that is derived from the coefficients of the compounds in a balanced equation. As a result, the mole ratio is used to convert between quantities of compounds in a chemical reaction.
Using the atomic masses, convert the mass of each element to moles of each element. Divide the number of moles of each element by the smallest number of moles to find the ratio or moles of each element.
Four over two is the best answer choice because it was between A and D, but 2 is not the denominator, so it couldn't be D.
Thus, four over two fractions can be used for the mole ratio to determine the mass of Fe from a known mass of Fe2O3, option A is correct.
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What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to
raise the temperature from 22ᵒC to 33.6ᵒC?
Answer:
≈ 395,8 J/(kg * °C)
Explanation:
m = 44 g = 0,044 kg
[tex]t_{1}[/tex] = 22 °C
[tex]t_{2}[/tex] = 33,6 °C
Q = 202 J
The formula is: Q = c * m * ([tex]t_{2} - t_{1}[/tex])
c = [tex]\frac{Q}{m * (t_{2} - t_{1} )}[/tex]
Calculating:
c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)
Is Ag3 PO4 ionic or covalent?
You have a 95% EtOH stock solution and want a 70% EtOH solution for sterilization purposes. If you want a final volume of 250 mL, how much 95% EtOH must you add, and how much water must you add
Answer:
65.8mL of water and 184.2mL of the 95% EtOH stock solution must be added.
Explanation:
To solve this question we need to find hoy many times the 95% EtOH must be diluted to obtain a 70% EtOH solution. That is:
95% / 70% = 1.357 times the solution must be diluted.
If we want to make 250mL of the diluted solution, the amount of 95% that must be added is:
250mL / 1.357 times =
184.2mL of the 95% solution must be added
And of water:
250mL - 184.2mL = 65.8mL of water
How many formula units are in 4.52 moles of H3SO3?
Type your answer
Answer:
The answer is 98.07848. We assume you are converting between grams H2SO4 and mole. You can view more details on each measurement unit: This compound is also known as Sulfuric Acid. The SI base unit for amount of substance is the mole. 1 grams H2SO4 is equal to 0.010195916576195 mole.
Quick conversion chart of moles H2SO3 to grams
1 moles H2SO3 to grams = 82.07908 grams
2 moles H2SO3 to grams = 164.15816 grams
3 moles H2SO3 to grams = 246.23724 grams
4 moles H2SO3 to grams = 328.31632 grams
5 moles H2SO3 to grams = 410.3954 grams
6 moles H2SO3 to grams = 492.47448 grams
7 moles H2SO3 to grams = 574.55356 grams
8 moles H2SO3 to grams = 656.63264 grams
9 moles H2SO3 to grams = 738.71172 grams
10 moles H2SO3 to grams = 820.7908 grams
Which of the following variables has the least effect on the rate a substance dissolved in a container of water?
A. The force of the stirring
B. The size of the container
C. The temperature of the water
D. The surface area of the substance
Determine the energy change in the following reaction. This reaction is considered ...
C6H12 + O2
CO2 + H2O + heat
energy absorbed is equal to the energy released
endothermic
O isothermic
O exothermic
Answer:isothermic
Explanation:
Answer:
Energy abosorbed = Energy released.
Thus ISOTHERMIC
Hard water often contains dissolved Ca^2+ and Mg^2+ ions. One way to soften water is to add phosphates. The phosphate ion forms insoluble precipitates with calcium and magnesium ions, removing them from solution. A solution is 0.055 MM in calcium chloride and 0.075 MM in magnesium nitrate. What mass of sodium phosphate would you add to 1.0 LL of this solution to completely eliminate the hard water ions? Assume complete reaction.
Answer:
14.2g of sodium phosphate are required
Explanation:
To solve this question we need to find the moles of Ca²⁺ and Mg²⁺ ions. And based on the reactions:
3Ca²⁺ + 2PO₄³⁻ → Ca₃(PO₄)₂ (s)
3Mg²⁺ + 2PO₄³⁻ → Mg₃(PO₄)₂ (s)
we can find the moles of phosphate required to precipitate all these ions and its mass:
Moles Ca²⁺:
1.0L * (0.055mol / L) = 0.055mol
Moles Mg²⁺:
1.0L * (0.075mol / L) = 0.075mol
Total moles = 0.13 moles of ions
Moles of phosphate ion required:
0.13 moles * (2 moles PO₄³⁻ / 3 moles ions) = 0.0867 moles PO₄³⁻
The moles of sodium phosphate (Na₃PO₄) are = 0.0867 moles
The mass is -Molar mass Na₃PO₄: 164g/mol-:
0.0867 moles Na₃PO₄ * (164g / mol) =
14.2g of sodium phosphate are requiredhelp! help! plz............
1)What is most important of periodicity lest 4
2)why are energies of
various energy levels in hydrogen atomic are negative?
What is the mass of 2.15X10^ 24 molecules of CO2?
Answer:
Mass of CO2 = ? Thus, the mass of 2.2x10^9 molecules of CO2 is 9.68 x 10^10 grams.
Explanation:
assume that the density of all solutions are 1.000g/ml 1. Calculate the molarity of calcium in 1.9g of calcium chloride diluted in 100 ml of Di water. 2 Calculate the concentration of both calcium and chloride lons in problem 1 in units of mg/mL, ug/L, mg/L and ug/mL. 3. Calculate the concentration of both calcium and chloride ion in problem 1 in units of ppm and ppb. You may assume that the density of the solution is 1.0 g/ml 4. You have been provided 100 ml of a 1000 ug/ml barium standard. What volume of this standard must be diluted to a final volume of 50 ml using DI water to produce a 30 ug/mL standard
Answer:
1. 0.1712M
2. 6.86mg/mL Ca, 12.14mg/mL Cl, 6860000ug/L Ca, 12140000ug/L Cl, 6860mg/L Ca, 12140mg/L Cl, 6860ug/mL Ca, 12140ug/mL Cl.
3. 6860ppm Ca and 12140ppm of Cl.
4. 1.5mL of the 1000ug/mL barium standatd must be taken.
Explanation:
1. Molarity is defined as the amount of moles of solute (Calcium chloride) present in 1L of solution.
The moles of CaCl₂ are:
1.9g CaCl₂ * (1mol / 110.98g) = 0.01712 moles
In 100mL = 0.10L:
0.01712mol / 0.10L = 0.1712M
2. The masses of Calcium and Chloride ions are:
1.9g * (40.078g Ca / 110.98g) = 0.686g Ca
And:
1.9g - 0.686g Ca = 1.214g Cl
mg/mL:
686mg Ca / 100mL = 6.86mg/mL Ca
1214mg Cl / 100mL = 12.14mg/mL Cl
ug/L:
686000ug / 0.1L = 6860000ug/L Ca
1214000ug/ 0.1L = 12140000ug/L Cl
mg/L:
686mg Ca / 0.1L = 6860mg/L Ca
1214mg Cl / 0.1L = 12140mg/L Cl
ug/mL:
686000ug Ca / 100mL = 6860ug/mL Ca
1214000ug Cl / 100mL = 12140ug/mL Cl
3. ppm are defined as mg/L, the ppm of Ca are 6860ppm Ca and 12140ppm of Cl
4. The solution must be diluted from 1000ug/mL to 30ug/mL, that is a dilution of:
1000ug/mL / 30ug/mL:
33.33 times must be diluted the solution.
As final volume of the diluted solution must be 50mL, the volume of the standard needed is:
50mL / 33.33 times = 1.5mL of the 1000ug/mL barium standatd must be taken
Which weather event usually occurs when a cold front moves into an area?
O A. mild weather, because cold air pushes warmer air to the side
O
B. mild weather, because cold air pushes warmer air up
C. a storm, because cold air pushes warmer air up
O D. a storm, because cold air pushes warmer air to the side
Pls help I’ll mark brainliest
Answer: I will answer if u Mark me
Explanation:
Which would be another way to make the ice melt faster
Answer:
d because ur heating the ice and causing friction