1.Anna Traveled 500 m to their house in 600 s. What is the speed of Anna?
A. 0.83 m/s B.2 m/s C.2.7m/s D. 3 m/s
2.What is the velocity of an object that traveled a distance of 100m due east in 10s?
A.10 m/s² B. 10m/s due east C. 10 m east D.10 m/s
3.An object traveled a distance of 50 m in 10 s,What is the speed is the object?
A. 5m/s B.5m/s² C.5m/s2 D. 5m/s due west ​

This question is in complete, the missing table is uploaded along this answer.

Answer:

the maximum possible kinetic energy K of the electrons emitted from this new surface is 4.9 eV

Explanation:

Given the data in the question;

copper K = 2.7 eV

If the copper is replaced with a piece of sodium ( Na )

the maximum possible kinetic energy K of the electrons emitted from this new surface = ?

we know that;

Kinetic energy of emitted electrons can be written as;

K = hv - hv₀

where v is frequency, h is Plank's constant, and hv₀ is work function of metal

so lets make hv the subject of formula;

hv = K + hv₀

from the table below, work function of copper is 4.5 eV

so we substitute

hv = 2.7 eV + 4.5 eV

hv = 7.2 eV

Now, If the copper is replaced with a piece of sodium ( Na )

we have;

K = hv - hv₀

from the table below, work function of Sodium is 2.3 eV

so we substitute

K = 7.2 eV - 2.3 eV

K = 4.9 eV

Therefore,  the maximum possible kinetic energy K of the electrons emitted from this new surface is 4.9 eV

Answer:

According to the parallelogram law of vector addition if two vectors act along two adjacent sides of a parallelogram(having magnitude equal to the length of the sides) both pointing away from the common vertex, then the resultant is represented by the diagonal of the parallelogram passing through the same common vertex

Explanation:

Answer:

[tex]W_m=183.495N[/tex]

Explanation:

From the question we are told that:

Weight [tex]W=248Ibs[/tex]

Mass of Weight  [tex]m= 248*0.453[/tex]

                          [tex]m=112.344kg[/tex]

Generally the acceleration due to gravity on the Moon is one-sixth that on Earth.

Therefore

The equation for Weight on Moon is given as

 [tex]W_m=m*g/6[/tex]

 [tex]W_m=122.344*\frac{9.8}{6}[/tex]

 [tex]W_m=183.495N[/tex]

Answer:

F ’= 40.9 lb

Explanation:

The weight of a body is the attraction of the Earth on the body

          F = [tex]G \frac{m M_e}{R_e^2}[/tex]

          F = mg

          m = F / g

          m = 248/32

         m = 7.75 slug

The weight of the body on the moon is the attraction of the body for the satellite

         F ’= [tex]G \frac{mM}{R^2}[/tex]

from the tables the mass and radius of the moon are M = 7.34 10²² kg and R = 1.74 10⁶ m

let's reduce the mass to the SI system

         m = 7.75 slug (14.59 kg / 1 slug) = 113 kg

         F ’= 6.67 10⁻¹¹ 113 7.34 10²² / (1.74 10⁶) ²

         F ’= 1.82 10² N

         F ’= 1.82 10² N (0.2248 lb / 1 N)

         F ’= 40.9 lb

Answer:

20J

Explanation:

[tex]KE = \frac{1}{2} mv^{2} = \frac{1}{2} (10)(2)^{2} =20J[/tex]

Answer:

Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.

Answer:

Explanation:

GPE =weight * height

       = 2000*(25-20)

      =  10000 J

Gain of Gravitation Potential energy  = 10,000 J

It is the energy acquired by an object due to a change in its position when it is present in a gravitational  field .

To calculate gravitational potential energy at height h , formula used is                                                                  =                     m g h where m = mass of the body

                                            g = acceleration due to gravity

                                            h = height from the ground

Gain of Gravitation Potential energy  = mg(h2 - h1 )      h2 = final height

                                                                             h1 = initial height

                                                = 2000  (25 -20)    (since , mg =weight)

Gain of Gravitation Potential energy  = 10,000 J

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Answer:

correct answer is b

Explanation:

The frequency of a wave depends on the properties of medium density and the elasticity properties change the amplitude depends on the energy carried by the wave, that is, the amplitude is proportional to the height of the wave (oscillation).

Consequently the amplitude of independent of the frequency because it depends on different factors.

Therefore when changing the amplitude the wavelength remains constant

the correct answer is b

Answer:

c

Explanation:

Answer:C

Explanation:

Answer:

correct answer is c

The balls will hit the ground simultaneously

Explanation:

This is an exercise in kinematics, let's analyze each case separately

Carla. Holds the ball at an initial height y = 1,5m and releases the ball therefore its initial velocity is zero v₀ = 0

          y = y₀ + v₀ t - ½ gt²

          0 = y₀ + 0 - ½ g t²

          t = [tex]\sqrt{\frac{2y_o}{g} }[/tex]

Daniel This holds the ball at I = 1.5 m and releases the ball as it passes by Carla, therefore the initial velocity is

horizontal vox = 40 mph

vertical   v_{oy} = 0

           y = y_{oy}I + v_{oy} t - ½ g t²

            0 = y_{oy} + 0 - ½ g t²

            t = [tex]\sqrt{\frac{2 y_o}{g} }[/tex]

we can see that they both spend the same time reaching the ground

           t = [tex]\sqrt{2 \ 1.5 / 9.8}[/tex]

           t = 0.55 s

The correct answer is c

The balls will hit the ground simultaneously

Answer:

[tex]\boxed {\boxed {\sf a \approx 0.4 \ m/s^2}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F= m \times a[/tex]

The net force is 5 Newtons and the mass is 13 kilograms. Let's convert the units for force to make the problem and unit cancellation easier.

Now we know the values for 2 variables:

Substitute the values into the formula.

[tex]5 \ kg *m/s^2 = 13 \ kg * a[/tex]

Since we are solving for the accleration we must isolate the variable, a. It is being multiplied by 13 kilograms and the inverse of multiplication is division. Divide both sides by 13 kg

[tex]\frac {5 \ kg *m/s^2}{13 \ kg}= \frac{ 13 \ kg *a}{13 \ kg}[/tex]

[tex]\frac {5 \ kg *m/s^2}{13 \ kg}=a[/tex]

The units of kilograms (kg) cancel.

[tex]\frac {5 m/s^2}{13 }=a[/tex]

[tex]0.384615385\ m/s^2=a[/tex]

The original measurements of force and mass ( 5 and 13) have 1 and 2 significant figures. We must round our answer to the least number of sig figs: 1.

For the number we found, that is the tenths place. The 8 in the hundredth place (0.384615385) tells us to round the 3 up to a 4.

[tex]0.4 \ m/s^2 \approx a[/tex]

The acceleration is approximately 0.4 meters per square second.

P = F / A

P = 2400 / 4

P = 24 × 100 / 4

P = 6 × 100

P = 600 N/m^2

Answer:

Impulse = 1000 Ns

Explanation:

Given the following data;

Force of collision = 1000 kg•m/s.

Time = 1 seconds

To find the impulse;

Mathematically, the impulse experienced by an object or body is given by the formula;

Impulse = force * time

Substituting into the formula, we have;

Impulse = 1000 * 1

Impulse = 1000 Ns

Answer:

The correct answer is - 6.49 × 10^3 mm.

Explanation:

The correct scientific notation of the given subtraction problem is:

6.94 × 10^3 mm - 4.5 × 10^2 mm = _____.

The correct number of significant digits is

a. 6.94 × 10^3 mm = 3

b. 4.5 × 10^2 mm = 2

So subtracting the 6.94 × 10^3 mm - 4.5 × 10^2 mm

= 6940 - 450

= 6.49× 10^3 mm.

Answer:

6.5x 10^3 mm

Explanation:

Answer:

2.0km/h.

Explanation:

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Answer:

P = 0.25 W

Explanation:

Given that,

The emf of the battry, E = 2 V

The resistance of a bulb, R = 16 ohms

We need to find the power delivered to the bulb. We know that, the formula for the power delivered is given by :

[tex]P=\dfrac{V^2}{R}\\\\P=\dfrac{2^2}{16}\\\\=0.25\ W[/tex]

So, 0.25 W power is delivered to the bulb.

Answer:

the animals are 26.2 meters apart.

Explanation:

Let's define t = 0s as the moment when the cheetah starts accelerating.

The gazelle moves with constant velocity, thus, it is not accelerating, then the acceleration of the gazelle is:

a₁(t) = 0m/s^2

where I will use the subscript "1" to refer to the gazelle and "2" to refer to the cheetah.

for the velocity of the gazelle we just integrate over time to get:

v₁(t) = V0

where V0 is the initial speed of the gazelle, which we know is 19.3 m/s

v₁(t) = 19.3 m/s

To get the position of the gazelle we integrate again:

p₁(t) = ( 19.3 m/s)*t + P0

where P0 is the position of the gazelle at t = 0s, let's define P0 = 0m

p₁(t) = ( 19.3 m/s)*t

The equations that describe the motion of the gazelle are:

a₁(t) = 0m/s^2

v₁(t) = 19.3 m/s

p₁(t) = ( 19.3 m/s)*t

Now let's do the same for the cheetah.

We know that its acceleration is 7.1 m/s^2

then:

a₂(t) =  7.1 m/s^2

for the velocity of the cheetah we integrate:

v₂(t) = (7.1 m/s^2)*t + V0

where v0 is the initial velocity of the cheetah, which we know its zero.

v₂(t) = (7.1 m/s^2)*t

Finally, for the position equation we integrate again, and remember that we have defined the initial position for the gazelle as zero, then the same happens for the cheetah.

p₂(t) = (1/2)*(7.1 m/s^2)*t^2

The equations for the cheetah are:

a₂(t) =  7.1 m/s^2

v₂(t) = (7.1 m/s^2)*t

p₂(t) = (1/2)*(7.1 m/s^2)*t^2

Now, we want to find the distance between both animals when the speed of the cheetah is 19.3 m/s, then first we need to solve:

v₂(t) = (7.1 m/s^2)*t =  19.3 m/s

t = (19.3 m/s)/(7.1 m/s^2) = 2.72s

Now, to find the distance between the two animals, we just compute the difference between the position equations for t = 2.72s

Distance = p₁(2.72s)  -  p₂(2.72s)

               = ( 19.3 m/s)*2.72s -  (1/2)*(7.1 m/s^2)*(2.72s)^2

               = 26.2 m

So the animals are 26.2 meters apart.

Answer:

3.416 m/s

Explanation:

Given that:

mass of cannonball [tex]m_A[/tex] = 72.0 kg

mass of performer [tex]m_B[/tex] = 65.0 kg

The horizontal component of the ball initially [tex]\mu_{xA}[/tex] = 6.50 m/s

the final velocity of the combined system v = ????

By applying the linear momentum of conservation:

[tex]m_A \mu_{xA}+m_B \mu_{xB} = (m_A+m_B) v[/tex]

[tex]72.0 \ kg \times 6.50 \ m/s+65.0 \ kg \times 0 = (72.0 \ kg+65.0 \ kg) v[/tex]

[tex]468 kg m/s + 0 = (137 kg)v[/tex]

[tex]v = \dfrac{468\ kg m/s }{137 \ kg}[/tex]

v = 3.416 m/s

Answer: Minimum speed needed by the Olympic champion at launch if he was traveling at 6.8 m/s at the top of the arc is 11.65 m/s.

Explanation:

Velocity is only in horizontal direction at the top most point which is similar to the velocity in the horizontal direction at the time of launch.

Now, according to the law of conservation of energy the formula used is as follows.

[tex]mgh = \frac{1}{2} mv^{2}_{y}\\v_{y} = \sqrt{2gh}\\= \sqrt{2 \times 9.8 m/s^{2} \times 1.2}\\= 4.85 m/s[/tex]

As speed at which the person is travelling was 6.8 m/s. Hence, the initial velocity will be calculated as follows.

[tex]v = \sqrt{v^{2}_{x} + v^{2}_{y}}\\= \sqrt{(6.8)^{2} + (4.85 m/s)^{2}}\\= 11.65 m/s[/tex]

Thus, we can conclude that minimum speed needed by the Olympic champion at launch if he was traveling at 6.8 m/s at the top of the arc is 11.65 m/s.

Answer:

75%

Explanation:

We'll begin by calculating the final volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Initial temperature (T₁) = T

Initial pressure (P₁) = P

Final pressure (P₂) = 2P

Final temperature (T₂) = ½T

Final volume (V₂) =?

P₁V₁/T₁ = P₂V₂/T₂

PV/T = 2P × V₂ / ½T

Cross multiply

T × 2P × V₂ = PV × ½T

T × 2P × V₂ = PV × ½T

Divide both side by T × 2P

V₂ = (PV × ½T) / T × 2P

V₂ = ¼V

Next, we shall determine the absolute change in the volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Final volume (V₂) = ¼V

Absolute change in volume |ΔV| =?

|ΔV| = |V₂ – V₁|

|ΔV| = |¼V – V|

|ΔV| = |0.25V – V|

|ΔV| = 0.75V

Finally, we shall determine percentage change in the volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Absolute change in volume |ΔV| = 0.75V

Percentage change =?

Percentage change = |ΔV| / V × 100

Percentage change = 0.75V / V × 100

Percentage change = 0.75 × 100

Percentage change = 75%

Thus, the percentage change in the volume of the gas is 75%

Answer:

the inductive reactance of the coil is 1335.35 Ω

Explanation:

Given;

inductance of the coil, L = 250 mH = 0.25 H

effective current through the coil, I = 5 mA

frequency of the coil, f = 850 Hz

The inductive reactance of the coil is calculated as;

[tex]X_l = \omega L = 2\pi f L\\\\X_l = 2\pi \times 850 \times 0.25\\\\X_l = 1335.35 \ ohms[/tex]

Therefore, the inductive reactance of the coil is 1335.35 Ω

Answer:

A wave with a frequency of 60 hertz will have 60 successive wave crests occurring every second

Explanation:

A crest is the highest point the medium rises to in a wave. That means that the crest is a point on the wave where the displacement is at a maximum.

Frequency is the number of oscillations of a wave in one second. Hence, frequency of a wave is the number of successive crests occurring in a second.

Therefore a wave with a frequency of 60 hertz will have 60 successive wave crests occurring every second.

Answer:

C: Mass of body

Explanation:

Upthrust is defined as the upward force that a liquid will exert on a body floating atop it.

Now, Formula for upthrust is;

Upthrust = density of liquid × volume of the body × acceleration due to gravity.

From the formula, we can see that upthrust depends on density, volume and acceleration due to gravity.

Thus, looking at the options, the one that doesn't apply is mass of body.

Answer:

120N Hacia arriba

Answer: A. The acceleration of an object is determined by its mass and the net force acting on it.

Explanation:

Newton's second law of motion explains that the acceleration of an object will depend on two vital variables which are the mass of the object and the net force that's acting on it.

It should be noted that the acceleration of the object directly depend on the net force while it depends inversely on the mass. Therefore, when the force that's acting on such object is increased, then the acceleration will increase as well. On the other hand, when there is an increase in mass, there'll be a reduction in the acceleration.

DL: Activity 2.3 Resistance

Complete the questions based on the Resistance presentation.

a. All resistors ___________ or _____________ the flow of electrons.

b. As resistance __________________ current _______________________

a) limits or opposes

b) increases, decreases

Resistors are electrical devices used to resist, limit, oppose or hinder the flow of electrons in a circuit. This resistance causes a reduction in current and an increase in voltage in the circuit. In order words, as resistance increases, the current decreases and voltage increases.

This was further stated by Ohm's law that states that as long as the resistance in a wire/conductor remains constant, the voltage across it is directly proportional to the current flowing through a conductor. i.e

V = IR

Where;

R = constant called resistance

I = current flowing through the wire

V = voltage across the wire

Answer:

carbon dioxide (CO2)

Explanation:

the burning or combustion of these fossil fuels creates gases that are released into the atmosphere. Of these gases, carbon dioxide (CO2) is the most common and is the gas most responsible for exacerbating the green- house effect that is changing global climate patterns.

Answer:

D) 0.008

Explanation:

I just did it on Edg22 and I got it correct :D (Picture above)

Option D) 0.008T is the correct answer.

Hence, if the current is increased to the given value, the strength of the magnetic field around the wire carrying the current increases to 0.008T

Given the data in the question;

First scenario

Second scenario

Magnetic field is a vector field or region around a magnet or electric charge upon which magnetic force is exerted.

To determine the strength of the magnetic field if the current is changed, we equate the two scenario.

[tex]\frac{B}{I} = \frac{B'}{I'}[/tex]

We substitute our given values into the expression

[tex]\frac{0.004T}{20A} = \frac{B'}{40A}\\ \\ B' * 20A = 0.004T * 40A\\\\B' = \frac{0.004T * 40A}{20A} \\\\B' = \frac{0.004T * 40}{20}\\ \\B' = \frac{0.16T}{20}\\ \\B' = 0.008T[/tex]

Option D) 0.008T is the correct answer.

Hence, if the current is increased to the given value, the strength of the magnetic field around the wire carrying the current increases to 0.008T

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