18. Calculate the molar mass, by titration calculations, of oxalic acid (H2C204) if 25.00 mL of a 0.750
M KOH solution were required to titrate 0.846 grams of oxalic acid.

Answers

Answer 1

Explanation:

[tex]1000 \: ml \: contain \: 0.750 \: moles \\ 25.00 \: ml \: will \: contain \: ( \frac{25 \times 0.75}{1000} ) \: moles \\ = 0.01875 \: moles \\ from \: reaction \: eqn \\ H _{2} C _{2} 0 _{4} + 2KOH - - > K _{2}C _{2} 0 _{4} +2H _{2} 0 \\ 1 \: mole \: of \: oxalic \: reacts \: with \: 2 \: moles \: of \: KOH \\ 0.01875 \: moles \: react \: with \: ( \frac{0.01875 \times 2}{1} ) \\ = 0.0375 \: moles \\ 0.0375 \: moles \: weigh \: 0.846g \\ 1 \: mole \: weighs \: 56g[/tex]


Related Questions

C5H12 + 8O2 —> 5CO2 +6 2O

Balance it

Answers

Answer:

it is already balanced

c5h12+8O2-->5CO2 +6h2o

Explanation:

Use Hess’s Law to calculate the heat of reaction for the following reaction:

2H2O2 → 2H2O +O2 ∆H=?
2H2 +O2 → 2H2O ∆H=-572 KJ
2H2O2 → 2H2 + 2O2 ∆H=376 KJ

Answers

2H2O2 ===> 2H2O + O2 ... TARGET EQUATION
We want to use the other equations that are given in order to make the target equation.
1) 2H2 + O2 ==> 2H2O ∆H = -572 kJ
2) H2 + O2 ==> H2O2 ∆H = -188 kJ

Reverse eq. 2 and multiply by 2 to get 2H2O2 on the left
2H2O2 ==> 2H2 + 2O2 ∆H = +376 kJ (change sign of ∆H and multiply by 2)
Copy eq.1
2H2 + O2 ==> 2H2O ∆H = -572
Add the two to get...
2H2O2 + 2H2 + O2 ==> 2H2 + 2O2 + 2H2O and cancel like terms on each side to get...
2H2O2 ==> 2H2O + O2 <==TARGET EQUATION
∆H = +376 kJ - 572 kJ = -196 kJ

The heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ

Calculating heat of reaction using Hess's law

From the question, we are to calculate the heat of reaction for the reaction

2H₂O₂ → 2H₂O +O₂               ∆H=?

Using Hess's law

Hess's Law of constant heat summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes

From the given equations,

2H₂ +O₂ → 2H₂O                   ∆H= -572 KJ ---------- (1)

2H₂O₂ → 2H₂ + 2O₂              ∆H= 376 KJ ----------- (2)

Adding equations (1) and (2), we get

2H₂O₂ → 2H₂O +O₂               ∆H= -572 KJ + 376 KJ

2H₂O₂ → 2H₂O +O₂               ∆H= -196 KJ

Hence, the heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ.

Learn more on Calculating heat of reaction using Hess's law here: https://brainly.com/question/26491956

Give all possible, accurate, correct IUPAC names for the following compounds:

Answers

Answer:

A. 4-ethyl-hex-3,5-dien-2-ol.

B. 2-chloro-3-methyl-5-tert-butylphenol.

Explanation:

Hello there!

In this case, according to the given problems, it is possible to apply the IUPAC rules to obtain the following names:

A. 4-ethyl-hex-3,5-dien-2-ol because we have an ethyl radical at the fourth carbon and the beginning of the parent chain is on the Me (CH3) because it is closest to first OH.

B. 2-chloro-3-methyl-5-tert-butylphenol: because we start at the alcohol and have a chlorine atom on the second carbon, a methyl radical on the third carbon, a tert-butyl on the fifth carbon and the parent chain is benzene which is phenol as an alcohol.

Regards!

what is the valence number of HCO3-.​

Answers

-1 is the answer

So it requires one cation (i.e. positively charged ion). So according to this, its valency is -1. A hydrogen carbonate ion has the formula HCO3-, so the valency of a hydrogen carbonate ion is -1.

When the pH test is done with a yellow litmus paper, it turns blue. This color change indicates that the solution is___
Acidic
Basic
Water
Neutral

Answers

Answer:

A basic solution such as hydroxyls

What is the Chemical formula for K and P

Answers

Answer:

Potassium phosphide (K3P)

This element has an oxidation number of -3 and it has 16 neutrons. What element is this room made of

Answers

Answer: Element is P, phosphor

Explanation:  Phosphor has oxidation number -III and it has 15 protons. So it is possible to have 16 neutrons. Other elements having oxidation number -III are N and As which can not have an isotope with 16 neutrons.

How many molecules are present in 135 g of Teflon C2F4

Answers

I think its about 1.34 molecules in a 135g of teflon.

The elemental particles like the atoms, molecules and compounds present in a given substance is called an Avogadro's number. This number is expressed as [tex]N_{A}[/tex] and is equal to [tex]6.022 \times 10^{23} \;\rm mol^{-1}[/tex].

[tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].

How to calculate the molecules?

Given,

Mass of the Teflon = 135 gThe molecular weight of [tex]\rm C_{2}F_{4}[/tex] = 100.02 g/mol

We have 135 g, so moles will be:

[tex]\begin{aligned}\rm Moles (n) &=\dfrac{ \rm Mass }{\;\rm Molar \;\rm mass}\\\\\rm n &= \dfrac{135 \rm g }{100.02 \rm g/mol} \\\\\rm n &= 1.34 \;\rm mole\end{aligned}[/tex]

Hence,

1 mole contains [tex]6.022140857 \times 10^{23}[/tex] (Avogadro's number)

So 1.34 moles will contain,

[tex]\begin{aligned}&=1.34 \times 6.022140857 \times 10^{23}\\\\&= 8.06 \times 10 ^{23}\;\rm molecules\end{aligned}[/tex]

Therefore, [tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].

Learn more about Avogadro's number here:

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Which two come together to form an ionic bond?

a. a positive cation and a ngetaive cation
b. a positive cation and a negative anion
c. a positive cation and a positive anion
d. a positive anion and a negative anion

Answers

[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]

b. a positive cation and a negative anion

✏ Anions are negative in nature while cations are positive in nature. Together they come together by an attractive electrostatic force to form an ionic bond.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

[tex] \huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}[/tex]

Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction:
2H+(aq) + Cu(s) H2(g) + Cu2+(aq)
Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. You may use the OWL references to find the values you may need in this question.

Answers

Answer:

3.3 * 10^-12

Explanation:

The balanced equation of the reaction is;

2H+(aq) + Cu(s) ---------> H2(g) + Cu2+(aq)

Hence two electrons were transferred so n=2

E°cell = E°cathode - E°anode

E°cell = 0 V - 0.34 V

E°cell = - 0.34 V

Then;

E°cell = 0.0592/n log K

Substituting values;

- 0.34 = 0.0592/2 log K

- 0.34/0.0296 = log K

-11.486 = log K

K = Antilog (-11.486)

K = 3.3 * 10^-12

What's the balanced chemical equation for sodium azide + water?

Answers

2NaN3 + H2O —> 2HN3 + Na2O

1) A container holds 5,000 mL of CO2 at 742 atm. What will be the volume of the CO2 if the pressure is increased to 795 atm?​

Answers

Answer:

[tex]V_2=4667mL[/tex]

Explanation:

Hello there!

In this case, based on the given information, it is possible for us to provide an answer to this question by using the Boyle's law as directly proportional relationship between volume and pressure:

[tex]P_2V_2=P_1V_1[/tex]

Thus, by solving for the final volume, V2, as required, we obtain the following:

[tex]V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{5,000mL*742atm}{795atm}\\\\V_2=4667mL[/tex]

Regards!

How many grams of product might form for the following reaction if 33.8 L of Oxygen gas is used in the following reaction? LiCl + O2 -> LiClO3

Answers

Answer:

91.41 g of LiClO₃.

Explanation:

We'll begin by calculating the number of mole of O₂ that occupied 33.8 L. This can be obtained as follow:

22.4 L = 1 mole of O₂

Therefore,

33.8 L = 33.8 L × 1 mole / 22.4 L

33.8 L = 1.51 mole of O₂

Next, the balanced equation for the reaction.

2LiCl + 3O₂ —> 2LiClO₃

From the balanced equation above,

3 moles of O₂ reacted to produce 2 moles of LiClO₃.

Therefore, 1.51 mole of O₂ will react to produce = (1.51 × 2)/3 = 1.01 mole of LiClO₃.

Finally, we shall determine the mass of 1.01 mole of LiClO₃. This can be obtained as follow:

Mole of LiClO₃ = 1.01 mole

Molar mass of LiClO₃ = 7 + 35.5 + (3×16)

= 7 + 35.5 + 48

= 90.5 g/mol

Mass of LiClO₃ =?

Mass = mole × molar mass

Mass of LiClO₃ = 1.01 × 90.5

Mass of LiClO₃ = 91.41 g

Thus, 91.41 g of LiClO₃ were obtained from the reaction.

Calculate the molarity of a solution that contains 5 mol of Li2O in 2.35 L of solution.

Answers

Answer:

2.13 M

Explanation:

To solve this problem we need to keep in mind the definition of molarity:

Molarity = moles / liters

As the problem gives us both the number of moles and the volume of solution, we can proceed to calculate the molarity:

Molarity = 5 mol / 2.35 LMolarity = 2.13 M

The answer is 2.13 M.

The pressure inside your
bike tire is 12.2 psi. What is this pressure if expressed in
millimeters of mercury (mm Hg)? (14.7 psi = 1 atm = 760mmHg)

Answers

Answer: The pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.

Explanation:

Given: Pressure = 12.2 psi

According to the standard conversion of units, 14.7 psi = 1 atm = 760mmHg.

Therefore, 1 psi equal to how many mm Hg is calculated as follows.

[tex]14.7 psi = 760 mm Hg\\1 psi = \frac{760}{14.7} mm Hg\\= 51.7149 mm Hg[/tex]

Hence, 12.2 psi will be converted into mm Hg as follows.

[tex]1 psi = 51.7149 mm Hg\\12.2 psi = 12.2 psi \times \frac{51.7149 mm Hg}{1 psi}\\= 630.9221 mm Hg[/tex]

Thus, we can conclude that the pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.

For the reaction: 2H2 + O2 → 2H2O, how many grams of water are produced from

6.00 moles of H2?

Answers

Answer:

108 g

Explanation:

2H₂ + O₂ → 2H₂O

First we convert 6.00 moles of H₂ into moles of H₂O, using the stoichiometric coefficients of the reaction:

6.00 mol H₂ * [tex]\frac{2molH_2O}{2molH_2}[/tex] = 6.00 mol H₂O

Then we can convert 6.00 moles of H₂O into grams, using the molar mass of water:

6.00 mol H₂O * 18 g/mol = 108 g

The answer is 108 grams of water.

A saline solution has 1.9 grams of NaCI in 100 mL of solution. Calculate the molarity

Answers

Answer:  Molality = concentration = 0,33 mol/l

Explanation: Concentration c = n/V   and  n = m/M

M = 55,44 g/mol  and m = 1.9 g , V = 0.100 l

c = m/(MV)

For a solution, [OH-] = 4 x 10-11M.
What is the pOH?
What is the pH?

Answers

Answer:

answer is what is the pH number is that Our New account last name is Our brothers name he will be happy to

The pOH of the solution is 10.4

The pH of the solution is 3.6

Calculating pOH & pH

From the question, we are to determine the pOH and pH of the solution

pOH can be calculated by using the formula

pOH = -log[OH⁻]

From the question,

[OH⁻] = 4×10⁻¹¹ M

∴ pOH = -log(4×10⁻¹¹)

pOH = 10.4

Hence, the pOH of the solution is 10.4

Now, for the pH

Using the formula,

pH + pOH = 14

Then, we can write that

pH = 14 - pOH

pH of the solution is

pH = 14 - 10.4

pH = 3.6

Hence, the pH of the solution is 3.6

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I need help with the question please help

Answers

Answer:

Explanation:

u are right

Answer:

An icicle

Explanation:

An icicle is heavier and has more mass making it fall quicker then a smaller and lighter item like a snow flake.

Please Help me if you can!:) i appreciate anything.

1. What is the mass of 3.32 mols of N2

2. How many molecules are in 4.67 mols of H2O

3. How many Sodium atoms are in 2.00 mols of Na2O

4. What is the mass of 3.57 mols of NaOH

5. How many mols are in 57g of H2O

Answers

Explanation:

1

Number of nucleon =

Molarmassofnucleon

Massofatom

=

1.6726×10

−24

g/nucleon

3.32×10

−23

g

=19.8=20(approximately)

It is given that element comprises of 2 atoms

Hence,number of nucleon = 2×20=40

2

You have 4.70 mol H2O

There are two H atoms in 1 molecule H2O.

Therefore, there must be 2*4.70 = 9.40 mols H in 4.70 mols H2O.

How many mols O in 4.70 mols H2O? That's 4.70 mols, of course.

Said another way, you have 2 mols H for every 1 mol H2O and 1 mol O for every 1 mol H2O.

So for 50 mols H2O you have 100 mols H and 50 mol O.

Decide whether below chemical reaction iis an oxidation-reduction ("redox") reaction. If the reaction is a redox reaction, write down the formula of the reducing agent and the formula of the oxidizing agent.

3O2 + 4Fe → 2Fe2O3

Answers

Answer:

Explanation:

Yes , it is a redox reaction .

3O₂ + 4Fe → 2Fe₂O₃.

Increase of oxidation number shows oxidation and decrease of oxidation number shows reduction .

Neutral atoms have zero oxidation number .

O₂ and Fe are neutral atoms so their oxidation number is zero.

In Fe₂O₃ , charge on each Fe atom is + 3 . So its oxidation number is + 3 . Similarly charge on each of O in this compound is - 2 . So its oxidation number is -2 .

Oxidation number of Fe increases from 0 to + 3 . Hence it is oxidized .

Oxidation number of O decreases from 0 to  -2  . Hence it is reduced  .

Fe is oxidized by O ( oxygen ) so oxygen is the oxidizing agent .

O is reduced  by Fe ( iron  ) so iron  is the reducing agent .

How many structural isomers does CH4 have?
a. two
b. five
c. three
d. one

Answers

Answer: Hello,  there! your Answer is Below

My Answer Would be A. Two

Explanation:

Structural Isomers are molecules which have the same molecular formula but have different connectivities

Hope this helps you!!

Have a great day!!!

Consider the incorrectly balanced combustion equation:
2C6H6 + 602 => 12CO2 + 6H2O
Select ALL elements that are not balanced.
Carbon
Hydrogen
Oxygen

Answers

Oxygen is balanced incorrectly.
The correct balanced equation: 2C6H6+15O2=12CO2+6H2O

What is the scientific method?
O A. A book describing scientific experiments
B. A description of proper laboratory techniques
O C. A scientific approach to answering questions
D. A way of thinking about scientific problems

Answers

Answer:

C. A scientific approach to answering questions

Explanation:

I believe the correct answer is C. A scientific approach to answering questions

Empirical formula of C6H10O6

Answers

Answer:

I don't know.

Explanation:

I actually don't know the answer so I wrote the answer is "I don't know" or simply "I dunno".

There are ____ neutrons, ___ protons, and ____ electrons in 238U+5

Answers

Answer:

Explanation:

The atomic number of uranium (see periodic table) is 92, and the mass number of the isotope is given as 238. Therefore, it has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons

Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5. The number of neutrons can vary from 141 to 146.

What is uranium ?

Chemical element uranium has the atomic number 92 and the letter U. It is an actinide metal in the periodic table's silvery-gray series. There are 92 protons and 92 electrons in an atom of uranium, of which 6 are valence electrons.

Since uranium has an atomic number of 92, its atomic structure consists of 92 protons and 92 electrons. The nucleus of U-238 contains 146 neutrons, but this number can range from 141 to 146.

With 92 protons and 146 neutrons, Uranium-238 is the heaviest element in nature. The overall mass and charge of the nucleus are 238 nucleons, or +92.

Thus, Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5.

To learn more about uranium, follow the link;

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In alkanes with three or fewer carbon atoms,
a. the chains can be straight or branched.
b. usually one but sometimes more than one molecular structure is possible.
c. structural isomers exist.
d. only one molecular structure is possible.

Answers

Answer: Only one molecular structure is possible.

How did we discover the Milky Way is a spiral galaxy?

Answers

A lot of data and making theories

An atom or ion has 16 protons, 15 neutrons, and 17 electrons. Is it positive, negative, or
neutral? Why? What element is it?
I really need help on this so can someone tell me the answer please!

Answers

Its negative I think, if I remember correctly it is phosphorus-32....

A solution has a [OH−] of 1 x 10^−11 M. What is the [H3O+] of the solution?

Answers

Explanation:

Ionic product of water, Kw

[tex]Kw = [OH {}^{ - } ][H _{3} O {}^{ + } ] \\ 1.0 \times {10}^{ - 14} = (1 \times {10}^{ - 11} )[H _{3} O {}^{ + } ] \\ [H _{3} O {}^{ + } ] = \frac{(1.0 \times {10}^{ - 14}) }{(1 \times 10 {}^{ - 11}) } \\ ][H _{3} O {}^{ + } ] = 0.001 \: M[/tex]

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