1/3log125/8-2log2/5+log80/125
[tex] \frac{1}{3} log( \frac{125}{8} ) - 2 log( \frac{2}{5} ) + log( \frac{80}{125} ) [/tex]

Answers

Answer 1

Answer:

[tex]3log2[/tex]

Step-by-step explanation:

Given

[tex]\frac{1}{3} log( \frac{125}{8} ) - 2 log( \frac{2}{5} ) + log( \frac{80}{125} )[/tex]

Required

Solve

Apply logarithm rules

[tex]log( \frac{125^{\frac{1}{3}}}{8^{\frac{1}{3}}} )- log( \frac{2^2}{5^2} ) + log( \frac{80}{125} )[/tex]

[tex]log( \frac{5}{2}} )- log( \frac{4}{25} ) + log( \frac{80}{125} )[/tex]

Apply quotient rule

[tex]log( \frac{5}{2} / \frac{4}{25} ) + log( \frac{80}{125} )[/tex]

[tex]log( \frac{5}{2} * \frac{25}{4} ) + log( \frac{80}{125} )[/tex]

[tex]log( \frac{100}{8} ) + log( \frac{80}{125} )[/tex]

Apply product rule

[tex]log( \frac{100*80}{8*125} )[/tex]

[tex]log( \frac{8000}{1000} )[/tex]

[tex]log(8)[/tex]

Express 8 as 2^3

[tex]log(2^3)[/tex]

[tex]3log2[/tex]


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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Mean value:

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1

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Answers

Answer:

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Step-by-step explanation:

Given that 8 million tonnes of fish were caught in the North sea in 2005, if the catch is reduced by 20% each year for four years, to determine what amount can be caught at the end of this time the following calculation must be performed :

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Answers

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Answers

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Step-by-step explanation:

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Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

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Answers

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Answers

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Answers

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