The system or equations can be used to find b, the number of black-and-white copies,
and c, the number of color copies that the customer paid for at the print shop is
b + c = 68
b + c = 680.08b + 0.15c = 6
Given:
Total amount paid = $6.00
Total copies = 68
cost of black-and-white copy = $0.08
cost of color copy = $0.15
let
number of black-and-white copies = b
number of color copies = c
The equation:
b + c = 68
b + c = 680.08b + 0.15c = 6
Therefore, the system or equations can be used to find b, the number of black-and-white copies,
and c, the number of color copies that the customer paid for at the print shop is
b + c = 68
b + c = 680.08b + 0.15c = 6
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id like 75% of my order to be 9 chocolate and the rest vanilla. how many vanilla cupcakes are there
Answer:
3 vanilla
Step-by-step explanation:
If 75% of the order equates to 9 chocolate, then the remaining of the dozen would leave three.
Unless there is more than 12 in the order. The question is vague
What is the volume of this rectangular prism?
1
cm
2
4 cm
ola
3
cm
cm3. Because this is hard
Step-by-step explanation:
Volume=length*width*height
V = (3/2)*(4)*(1/2)
= 12/4 = 3cm^3
Which triangle is a 30°-60°-90° triangle?
Answer:
-90
Step-by-step explanation:
it's right
Answer:
The first one.
Step-by-step explanation:
I took the quiz and got a 100, hope this helps :))
when the height of a rectangular prism was halved, the volume was 168 cubic cm. if the original prism had a length, width, and height of consecutive integers, increasing in that order,
(a) write and equation to solve for the length, x, of the original figure,
(b) solve length, x,
(c) show that the equation is unique
show all work.
a) The equation is therefore; x³ + 3x² + 2x = 336
b) Solving for the length, we get the length to be; x = 6.
c) All workings are as shown below;
According to the question;
When the height of a rectangular prism was halved, the volume was 168 cubic cm.In essence, the volume of the original prism is;
Volume = 168 × 2.Volume = 336cm³Since, the original prism had a length, width, and height of consecutive integers, increasing in that order.
Therefore, length = xwidth = (x +1)height = (x +2)Volume = x (x+1) (x+2) = 336a) The equation is therefore;
x³ + 3x² + 2x = 336b) Solving for the length, x is as follows;
(x-6) (x² + 9x + 56) = 0By testing values and checking;
Upon solving the polynomial, x = 6.c) All workings are as shown above.
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the inequality –1 + 6(–1 – 3x) > –39 – 2x.
Answer:
x > 2
Step-by-step explanation:
-1+6(-1-3x)>-39-2x
-1-6 - 18x > -39 - 2x
-7 - 18x + 2x > -39 - 2x + 2x
-7 - 16x + 7 > -39 + 7
16x / 16 > -32 / 16
x > 2
If sin θ = 1/2 , then find the value of (sin 3 θ)/(1+ cos 2 θ)
EXPLANATION:
Given that
sin θ = 1/2
We know that
sin 3θ = 3 sin θ - 4 sin³ θ
⇛sin 3θ = 3(1/2)-4(1/2)³
⇛sin 3θ = (3/2)-4(1/8)
⇛sin 3θ = (3/2)-(4/8)
⇛sin 3θ = (3/2)-(1/2)
⇛sin 3θ = (3-1)/2
⇛sin 3θ = 2/2
⇛sin 3θ = 1
and
cos 2θ = cos² θ - sin² θ
⇛cos 2θ = 1 - sin² θ - sin² θ
⇛cos 2θ = 1 - 2 sin² θ
Now,
cos 2θ = 1-2(1/2)²
⇛cos 2θ = 1-2(1/4)
⇛cos 2θ = 1-(2/4)
⇛cos 2θ = 1-(1/2)
⇛cos 2θ = (2-1)/2
⇛cos 2θ = 1/2
Now,
The value of sin 3θ /(1+cos 2θ
⇛1/{1+(1/2)}
⇛1/{(2+1)/2}
⇛1/(3/2)
⇛1×(2/3)
⇛(1×2)/3
⇛2/3
Answer : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.
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Harry read 1/3 of a book on Saturday and three force of the remainder on Sunday. If he still had 75 pages left how many pages were in the book?
There are two spheres; the radius of the big sphere is two times the radius of the small sphere. How many times larger is the volume of the big sphere compared to the small one?
The volume of the bigger sphere is 8 times larger than the volume of the smaller sphere.
The formula of the volume of a sphere is given below
⇒ Formula:
V = 4/3(πr³)................. Equation 1⇒ Where:
V = Volume of the spherer = radius of the sphereπ = constant called pieFrom the question, There are two spheres.
If the radius of the bigger sphere is two times the radius of the smaller sphere.
R = 2r⇒ Where
R = bigger radiusr = smaller radiusFor the bigger sphere
⇒ Substitute these values into equation 1
V = 4/3(π(2r)³)V = 4/3(π8r³)............. Equation 2For the smaller sphere,
V' = 4/3(πr³)............... Equation 3⇒ Comparing equation 2 and equation 3
V = 8V'Hence, The volume of the bigger sphere is 8 times larger than the volume of the smaller sphere.
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After sitting in a refrigerator for a while, a turkey at a temperature of 34^\circ34
∘
F is placed on the counter and slowly warms closer to room temperature (67^\circ67
∘
F). Newton's Law of Heating explains that the temperature of the turkey will increase proportionally to the difference between the temperature of the turkey and the temperature of the room, as given by the formula below:
T=T_a+(T_0-T_a)e^{-kt}
T=T
a
+(T
0
−T
a
)e
−kt
T_a=T
a
= the temperature surrounding the object
T_0=T
0
= the initial temperature of the object
t=t= the time in minutes
T=T= the temperature of the object after tt minutes
k=k= decay constant
The turkey reaches the temperature of 45^\circ45
∘
F after 15 minutes. Using this information, find the value of kk, to the nearest thousandth. Use the resulting equation to determine the Fahrenheit temperature of the turkey, to the nearest degree, after 60 minutes.
Enter only the final temperature into the input box.
The temperature of the body after 60 minutes is 60.5° F.
Using the Newton's law of cooling;
T(t) =[tex]Ts + (To - Ts)e^-kt[/tex]
T(t) = temperature at time t
Ts = temperature of the surrounding
To = Temperature of object
t = time taken
k = cooling constant
Now;
[tex]T(t) -Ts=(To - Ts)e^-kt\\45 - 67 = (34 - 67)e^-15k\\-22 = -33e^-15k\\-22/-33 = e^-15k\\0.667 = e^-15k\\ln(0.667) = ln( e^-15k)\\-0.405 = -15k\\k = -0.405/ -15\\k = 0.027[/tex]
At t = 60 min
[tex]T(t) = Ts + (To - Ts)e^-ktT(60) = 67 + (34 - 67)e^-( 0.027*60)\\T(60) = \\67 + (-33)e^-( 0.027 * 60)\\T(60) = \\60.5 F[/tex]
T(60) = 60.5° F
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Answer:
T≈169
Step-by-step explanation:
Enter only the final temperature into the input box.
T_a = 67\hspace{50px}T_0=210
T
a
=67T
0
=210
\text{Write Formula:}
Write Formula:
T=67+(210-67)e^{-kt}
T=67+(210−67)e
−kt
Plug in givens
\color{blue}{T}=67+143e^{-k\color{green}{t}}
T=67+143e
−kt
Simplify
\text{Plug in given time and temperature:}
Plug in given time and temperature:
\color{blue}{193}=67+143e^{-k(\color{green}{1.5})}
193=67+143e
−k(1.5)
Simplify
\text{Solve for }k\text{:}
Solve for k:
193=
193=
\,\,67+143e^{-1.5k}
67+143e
−1.5k
-67\phantom{=}
−67=
\,\,-67
−67
126=
126=
\,\,143e^{-1.5k}
143e
−1.5k
\frac{126}{143}=
143
126
=
\,\,\frac{143e^{-1.5k}}{143}
143
143e
−1.5k
Divide by 143
0.8811189=
0.8811189=
\,\,e^{-1.5k}
e
−1.5k
\ln\left(0.8811189\right)=
ln(0.8811189)=
\,\,\ln\left(e^{-1.5k}\right)
ln(e
−1.5k
)
Take ln of both sides
\ln\left(0.8811189\right)=
ln(0.8811189)=
\,\,-1.5k
−1.5k
\frac{\ln\left(0.8811189\right)}{-1.5}=
−1.5
ln(0.8811189)
=
\,\,\frac{-1.5k}{-1.5}
−1.5
−1.5k
Divide by -1.5
0.0843751=
0.0843751=
\,\,k
k
k\approx
k≈
\,\,\color{blue}{0.084}
0.084
Round k to nearest thousandth
\text{Complete Formula:}
Complete Formula:
T=67+143e^{-\color{blue}{0.084}t}
T=67+143e
−0.084t
Plug in k
\text{Find temperature after }\color{green}{4}\text{ minutes:}
Find temperature after 4 minutes:
T=67+143e^{-0.084(\color{green}{4})}
T=67+143e
−0.084(4)
Plug in time
T=67+143e^{-0.336}
T=67+143e
−0.336
Multiply
T=169.1911041
T=169.1911041
Plug into the calculator
T\approx 169
T≈169
Suppose ΔDEF has an exterior angle at vertex D. The measure of the exterior angle is (8x−2)º, m∠E=(3x−8)°, and m∠F=(4x+13)°. What is the measure of the exterior angle at vertex D?
A. 7°
B. 13°
C. 41°
D. 54°
The measure of the exterior angle at vertex D is: D. 54°
Recall:
The exterior angle theorem of a triangle states that the measure of an exterior angle equals the sum of the measures of two opposite interior angles of the triangle.Thus:
In ΔDEF, (8x−2)º is an exterior angle at vertex D.
m∠E = (3x−8)° (interior angle)
m∠F = (4x+13)° (interior angle)
Therefore:
(8x−2)º = (3x−8)° + (4x+13)°
Solve for x8x - 2 = 3x - 8 + 4x + 13
Combine like terms8x - 2 = 7x + 5
8x - 7x = 2 + 5
x = 7
Exterior angle at vertex D = (8x−2)º
Plug in the value of x= 8(7) - 2
= 54º (option D)
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A calf weighs 18 lbs. when it is 2 months old, and after 8 months it weighs 36 lbs.
Let x be the calf's age and y be the weight.
a. Write an equation in slope-intercept form that represents the situation.
The equation in slope-intercept form that represents the situation is y = 3x + 12
A linear equation is on the form:
y = mx + b
where y, x are variables, m is the rate of change and b is the initial value of y.
Let x be the calf's age in month and y be the weight.
A calf weighs 18 lbs. when it is 2 months old, and after 8 months it weighs 36 lbs. Hence it can be represented by:
(2, 18) and (8, 36). The equation is given by:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-18=\frac{36-18}{8-2}(x-2) \\\\y=3x+12[/tex]
The equation in slope-intercept form that represents the situation is y = 3x + 12
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What are the coordinates of B
Answer: (-7,-5)
Step-by-step explanation:
Because when you mark point M and A if you mirror point M and A on the x Axis then you will get (-7,-5)
Pls help fast i will mark brainlyest
Answer:
x = 20
Hope you could get an idea from here.
Doubt clarification - use comment section
One number is eight more than twice another. If their difference is 25, what is the larger
number?
35
42
17
Answer:
17
Step-by-step explanation:
Let the smaller number = x
Let the larger number = y
y = 2x + 8
y - x = 25 Add x to both sides
y = x + 25 Substitute this into the first equation
x + 25 = 2x + 8 Subtract 8 from both sides
x + 25 - 8 = 2x Combine
x + 17 = 2x Subtract x from both sides.
17 = 2x - x Combine
17 = x
Show all work to multiply
(3+ square root -16) (5 – square root -25)
[tex]\left(3+\sqrt{-16} \right) \left(5-\sqrt{-25} \right)\\\\=\left(3+\sqrt{-1} \cdot \sqrt{16} \right) \left(5- \sqrt{-1} \cdot \sqrt{25} \right)\\\\=(3+4i)(5-5i)~~~~~~~~~~~~~~;\left[i=\sqrt{-1} \right]\\\\=15-15i + 20i - 20i^2\\\\=15+5i -20(-1)~~~~~~~~~~~~;[i^2 =-1]\\\\=15+5i +20\\\\=35+5i[/tex]
Someone please help, I think I have an idea but just wanna make sure i'm on the right track
Answer:
As per graph the rate of Printer A is 15 pages per minute.
Missing words are:
(a) greater than
(b) greater than
(c) 15
The rate for Printer B is greater than the rate for Printer A because the rate of 25 pages per minute is greater than the rate of 15 pages per minute for Printer A.
or
The printing rate for Printer B is 10 pages more than the rate of printer A because the rate of 25 pages per minute is 10 pages more than the rate 15 pages per minute for Block A
Step-by-step explanation: it's either greater than or more than
From the graph of the printing rate of Printer A, we can see that;
At 1 minute, number of pages printed = 15
At 2 minutes, number of pages printed = 30 minutes
At 3 minutes, number of pages printed = 45
Thus printing rate for printer A is; 15/1 = 30/2 = 45/3 = 15 pages per minutes
Since printer B can print 25 pages per minute, we can conclude that;
The printing rate for Printer B is 10 pages more than the rate of printer A because the rate of 25 pages per minute is 10 pages more than the rate 15 pages per minute for Block A
Part 1 of 2
O Points
What are the lateral surface area and total surface area of a cylindrical oil storage tank that has a 44-ft diameter and 18-ft height?
The lateral surface area of the cylindrical oil storage tank is
(Round to one decimal place as needed.)
The Lateral Surface Area of the cylindrical oil storage tank is [tex]2486.9\text{ sq.ft}[/tex]
The Total Surface Area of the cylindrical oil storage tank is [tex]5526.4\text{ sq.ft}[/tex]
If the height and base radius of the cylindrical oil storage tank are represented by [tex]h[/tex] and [tex]r[/tex] respectively, then
The Lateral Surface Area, also known as the Curved Surface Area, of the cylindrical oil storage tank has the formula
[tex]L=2\pi rh[/tex]
The Total Surface Area of the cylindrical oil storage tank has the formula
[tex]T=2\pi rh+2\pi r^2\\T=2\pi r(h+r)[/tex]
The values for the height and base radius are [tex]18ft[/tex] and [tex]22ft[/tex] respectively.
Calculate the Lateral Surface Area
[tex]L=2\pi rh\\=2\times 3.14\times 22\times 18\\\approx 2486.9\text{ sq.ft}[/tex]
Calculate the Total Surface Area
[tex]T=2\pi r(h+r)\\=2\times 3.14\times22(18+22)\\=5526.4\text{ sq.ft}[/tex]
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Area =12
X+2
X+4
X =
Answer:
To find area of the square you'll need to square one side
(3X)^2 = 81
9(X)^2 = 81
(x)^2 = 81/9
x^2 = 9
X = (9)^1/2
X = 3
Alfredo's Towing Service charges $53.27 for its hook-up fee plus $29.25 for every mile, m, they tow your car. The equation that models the total cost (T) is T(m) = 29.25m + 53.27
Which value in the equation represents the rate of change?
A - $82.52
B - $29.25
B - The number of miles towed
C - $53.27
What is the solution to the equation 8b+32=104?
Answer: the answer is b=9
Step-by-step explanation:
Step 1: Subtract 32 from both sides.
104-32= 72
Step 2: Divide both sides by 8.
72 divided by 8 is 9
therefor the answer is 9
x=y^2+4y+4 solve for y
Answer:
y=
x
−2
y=−
x
−2, x≥0
y=−
x−2, x≥0
Step-by-step explanation:
16,40 and 56 LCM
Solve please
Answer:
pic?
Step-by-step explanation:
send me the picture please
6x+3y=13 find the value
6x+3y=13
6x+3y-13=13--13
6x+3y-13=0
Please hurry!! This assignment is almost due!!
Answer: x = 17
Step-by-step explanation:
Hi there!
First, since we know that these two lines are parallel, 3x+14 is going to be congruent to the supplementary side of 7x-4. Given this, we are able to solve for x as we know that the sum of supplementary angles is 180. All you have to do is set up 3x+14+7x-4=180
Now, just use simple order of operations and combining like terms to isolate x. you will end with 17! :)
Hope this helps!
Nick wants to buy a pair of shoes. The original cost of the shoes is $56.75, and the markup is 12 percent. How much will he have to pay for the shoes?
Answer:
Nick will have to pay $63.56 for the shoes.
Step-by-step explanation:
f the original cost of the shoes is $56.75 and the markup is 12% greater than the original price, the final price would be $63.56.
$56.75 • 0.12 = $6.81
$56.75 + $6.81 = $63.56
$56.75 + 12% = $63.56
Answer:
Nick will have to pay $63.56 for the shoes.
A Quadrilateral ABCD is rotated 55° about point R to create quadrilateral A' B'C'D'. QUICK. PLEASE
Answer:
2.8
Step-by-step explanation:
Answer:
Step-by-step explanation:
2.8 units
The tree in Manuel’s backyard is 6.8 m high. How high is it in centimeters?
A rectangular pool has a length of
4x + 7 feet and a width of 15x - 2 feet. Which
expression represents the perimeter of the
pool?
Hi need help for this maths question
a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have
[tex]\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}[/tex]
so both conditions are met and f(y) is indeed a PDF.
b) The probability P(Y > 4) is given by the integral,
[tex]\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}[/tex]
c) The mean is given by the integral,
[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy[/tex]
Integrate by parts, with
[tex]u = y \implies du = dy[/tex]
[tex]dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}[/tex]
Then
[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)[/tex]
[tex]\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy[/tex]
[tex]\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}[/tex]
Can someone solve this, please?
AND FAST
Answer: 40
Step-by-step explanation: yes make me brainlist (its the crown)