100N force is applied to a ball with a mass of 0.25kg. Calculate the ball acceleration.

5) a) An alpha particle consists of 4 nucleons. Two of these are protons and two are neutrons.  An alpha particle carries a charge of +2 (due to the particles having 2 protons).

b)  A beta minus particle is a fast moving electron that's emitted from the nucleus. It's created when neutrons in the nucleus decays to form a proton & the beta particle.

c) A 3rd type of ionising radiation has no mass. It's called gamma radiation (gamma rays / X - rays). This type of radiation is a type of wave with a very short / low wavelength.  (shortest wavelength among others)

d) Gamma radiation is a part of the electromagnetic spectrum.

_______

Hope it helps ⚜

Taking into account the definition of wavelength, frecuency and propagation speed, the wavelength of a light with a frequency of 3×10¹⁴ Hz is 1×10⁻⁶ m.

First of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f * λ

All electromagnetic waves propagate in a vacuum at a constant speed of 3x 10⁸ m/s, the speed of light.

In this case, you know:

Replacing:

3x 10⁸ m/s= 3×10¹⁴Hz× λ

Solving:

λ= 3x 10⁸ m/s ÷ 3×10¹⁴Hz

λ=1×10⁻⁶ m

In summary, the wavelength of a light with a frequency of 3×10¹⁴ Hz is 1×10⁻⁶ m.

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Answer:

Work done = Fs

Explanation:

(i) W = Fxs

= 84N x0.25m

= 21 Joules

(ii) Ek = 1/2mv^2

71 = 1/2×27×v^2

71×2/27 = v^2

v = 23m/s

The work done by this force is 21 Joule.

Energy transferred by the force is 21 Joule.

The boy's momentum changes periodically, that is,  in both size and direction.

An external force is an agent that has the ability to change the resting or moving condition of a body. It has a direction and a magnitude. So, it is  a vector quantity. Newton is the SI unit of force (N).

(i) Given parameter:

Steady force applied by his brother, F = 84 N.

Displacement, d = 0.25 m.

The work done by this force, W = F.d = 84×0.25 = 21 Joule.

(ii) Amount of work done is transferred by this force as an energy. So, amount of energy transferred by the force is 21 Joule.

(iii) Given parameter:

Mass of the child, m= 27 kg.

Kinetic energy, E = 71 J.

Let, velocity of the child = v, then kinetic energy is,

E = 1/2 × mv²

⇒ v = √(2E/m)

= √(2×71/27)

= 2.3 m/s.

Hence, the velocity of the boy is 2.3 m/s. (proved).

(iv) During swing, his velocity changes periodically. That's why, his momentum changes periodically, that is,  in both size and direction.

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#SPJ2

Answer:

at the center of the galaxy

Explanation:

as there r more new born stars found

Answer:

Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length.

Explanation:

If we take West to be the negative direction, then the initial velocity is -15 m/s and the acceleration (which points East) is +7.0 m/s².

After t = 4.0 s, the helicopter's velocity is

-15 m/s + (7.0 m/s²) (4.0 s) = +13 m/s

or 13 m/s [E].

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Hi there!

Weight = mass × acceleration due to gravity (or gravitational field strength)

We can write this as:

W = mg

Plug in the given values:

W = 55 × 3.7

W = 203.5 N

Hi there!

[tex]\large\boxed{ME = 50 J}}[/tex]

Mechanical Energy = Potential Energy + Kinetic Energy, or:

E = U + K

Plug in the given potential and kinetic energies:

E = 12.5 + 37.5 = 50 J

Answer:

yeah

Explanation:

hun I wish I can help you but I have the same problem here!! sorry

Answer:   Our notation is as follows : the mass of the original body is M=20.0kg ; its initial velocity is  

ν

0

​

=(200m/s)  

i

^

 ; the mass of one fragment is m  

1

​

=10.0kg ; its velocity is  

ν

1

​

=(100m/s)  

j

^

​

 ; the mass of the second fragment is m  

2

​

=4.0kg ; its velocity is  

ν

2

​

=(−500m/s)  

i

^

 ; and , the mass of the third fragment is m  

3

​

=6.00kg . Conservation of linear momentum requires  

          M  

ν

0

​

=m  

1

​

ν

1

​

m  

2

​

ν

2

​

+m  

3

​

ν

3

​

 .  

The energy released in the explosion is equal to ΔK , the change in kinetic energy .  

(a) Using the above momentum -conservation equation leads to  

ν

3

​

=  

m  

3

​

M  

ν

0

​

−m  

1

​

ν

1

​

−m  

2

​

ν

2

​

​

             =  

6.00kg

(20.0kg)(200m/s)  

i

^

−(10.0kg)(100m/s)  

j

^

​

−(4.0kg)(−500m/s)  

i

^

​

          =(1.00×10  

3

m/s)  

i

^

−(0.167×10  

3

m/s)  

j

^

​

.  

The magnitude of  

ν

3

​

 is  

                        ν  

3

​

=  

(1000m/s)  

2

+(−167m/s)  

2

​

=1.01×10  

3

m/s  

It points at θ=tan  

−1

(−167/1000)=−9.48  

∘

 (that is at 9.5  

∘

 measured clockwise from the +x axis) .  

(b) The energy released is ΔK :  

             ΔK=K  

f

​

−K  

i

​

=(  

2

1

​

m  

1

​

ν  

1

2

​

+  

2

1

​

m  

2

​

ν  

2

2

​

+  

2

1

​

m  

3

​

ν  

3

2

​

)−  

2

1

​

Mν  

0

2

​

=3.23×10  

6

J

Explanation:

Answer:

The weight, on Earth, of a book with a mass of 1.5kg is 14.7N.

Explanation:

Hi there!

Weight of an object = mass (kg) × acceleration due to gravity (N/kg)

Plug in the given values using the g constant g = 9.8 N/kg:

W = 1.5 × 9.8 = 14.7 N

Answer:

A. The electric field lines point outward and the black puck moves backwards. From this I can see that I can't put the red charge in front of the black puck because it will go away from the goal.

B. The electric field lines point inward and the black puck moves forwards and backwards. The conclusion I made from this was the blue charge by itself will not be able to get into the goal.

C.The puck moves faster when the mass increases and moves slower when the mass decreases. The more mass, the more force that is applied to the puck.

D.  The relationship between the speed of the black puck and its distance from the blue charge is when the puck is further away from the blue charge, the slower the puck moves away from it.

Explanation:

Brainlest if this helped!

Force of air and gravitational force are acting on the ball when launched from the slingshot.

When a ball is launched from a slingshot, during its travel force of air as well as gravitational force are acting on the ball because there is air which moves opposite to the motion of a ball whereas the force of gravity attracts the ball downward.

The force of air slows down the motion of the ball while on the other hand, the force of gravity brings the ball to the ground due to attraction. If these two forces are not present then the ball continues its motion forever so we can conclude that force of air and force of gravity are acting on the ball when launched from the slingshot.

Learn more: https://brainly.com/question/25533186

Explanation:

acceleration remains constant when velocity does not increase or decrease

Answer:

Two numbers

Explanation:

see it first

The magnitude of the magnetic field in the coil is 21.65 T.

The given parameters;

The induced emf in the coil is determined by applying Faradays law;

[tex]emf =N \frac{d\phi }{dt} \\\\emf = N ( \frac{\phi _2 - \phi_1}{t} )\\\\emf= N(\frac{BAsin\ 60 - BAsin\ 90}{t} )\\\\emf = NBA(\frac{sin60 - sn90}{t} )\\\\-0.058 = 500(6\times 10^{-4})\times B\times (\frac{0.866 - 1}{15} )\\\\-0.058 = -0.00268B\\\\B = \frac{0.058}{0.00268} \\\\B = 21.65 \ T[/tex]

Thus, the magnitude of the magnetic field in the coil is 21.65 T.

Learn more here:https://brainly.com/question/13369951

Answer:

what is the average speed of the toy car during the two trials to the nearest tenth of m/s

wait nvm the answer is B

Explanation:

CARRY ON LEARNING

Answer:

[tex]W=Fd \\ 50 = 25d \\ d = \frac{50}{25} \\ \color{yellow} \boxed{d = 2m}[/tex]

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Solution is in attachment ~

I hope that you got what you were looking for, and if there's different data then go through the same procedure, using same formula with different values and you will get your answer ~

[tex]\mathrm{✌TeeNForeveR✌}[/tex]

Answer:1.9 × 10³⁰

Explanation:

Answer:

[tex]v = \frac{d}{t} \rightarrow t= \frac{v}{d} \\ = 100m \div 5m. {s}^{ - 1} = \frac{100}{5} \\ \color{green} \boxed{ t = 20s}[/tex]

Answer:

R = V/I

Explanation:

Example:

V = IR

R = V/I

If we were to use V = 120 and I = 0.25

R = 120/0.25

R = 480 Ohms

Your resistence would equal Ohms

hplhevsdvakxjb1zonsvaka shdv

Answer:

its 15 J i belive

Explanation:

Answer:

Introspection is a process that involves looking inward to examine one's own thoughts and emotions. ... The experimental use of introspection is similar to what you might do when you analyze your own thoughts and feelings but in a much more structured and rigorous way.

Explanation:

Example of it: The definition of introspection is self-examination, analyzing yourself, looking at your own personality and actions, and considering your own motivations. An example of introspection is when you meditate to try to understand your feelings. noun.

Answer:   Introspection is when you examine your own thoughts, feelings, and emotions. A spiritual idea of introspection is like examining your soul while a pyschological way would be examining your mental state.

Explanation:  tried my best

Answer:

We do. It's just way too small compared to the force between the objects we're observing and the earth. It's like looking inside a room with an elephant and a grain of rice. The rice is there, it's just too small compared to the room and the elephant inside for you to notice it. Or, if you ever traveled on a plane, you can easily see the towns, or the roads, but not the single people walking the street.

Hi there!

Recall the conservation of momentum:

m1v1 + m2v2 = m1v1' + m2v2'

Let m1 = 5 kg ball and m2 = 10 kg ball

Since m2 is at rest, we can rewrite:

m1v1 = m1v1' + m2v2'

Plug in the given values:

5(2) = 5(-1) + 10v2'

Solve for v2':

10 = -5 + 10v2'

15 = 10v2'

15/10 = 1.5 m/s

We know that,

m1v1 + m2v2 = m1v1' + m2v2'

5 x 2 + 0 = 5 x -1 + 10 x v2'

10= -5 +10 x v2'

15 = 10 x v2'

v2' = 15/10

v2' = 1.5 m/s

hence , the speed of the larger ball after the collision will 1.5m/s