1.00 x 10^3 kg of clear liquid (specific heat
capacity = 5.11 x 10^2 J/kg-°C) at a temperature
of 15.0°C gains 3.33 x 10° J of heat. What is the
final temperature of the liquid? (Assume the
melting point is less than 15.0°C and the boiling
point is greater than 62.0°C.)

Answers

Answer 1

Answer:

15.00000652 °C

Explanation:

From the question,

Q = cm(t₂-t₁)................ Equation 1

Where Q = heat gained by the liquid, c = specific heat capacity of the liquid, m = mass of the liquid, t₁ = Initial Temperature of the liquid, t₂ = Final temperature of the liquid.

Given: Q = 3.33 J, c = 511 J/kg°C, m = 1000 kg, t₁ = 15°C

Substitute these values into equation 1 and solve for t₂

3.33 = 511×1000(t₂-15)

3.33 = 511000(t₂-15)

(t₂-15) = 3.33/511000

(t₂-15) = 0.0000065

t₂ = 15+ 0.0000065

t₂ = 15.00000652 °C


Related Questions

Linda, a biker, is moving along a circular path at a constant speed of 10 km/h. In a neighboring arena Kevin, another biker, is moving along a circular path at a constant speed of 12 km/h. If the acceleration of the two bikers is the same, what can you infer?
A) The centripetal force on Kevin is higher than that on Linda.
B) The centripetal force on Linda is higher than that on Kevin.
C) Kevin’s circular path has a bigger radius than Linda’s path.
D) Linda’s circular path has a bigger radius than Kevin’s path

Answers

Answer:

the answer is  C

Explanation:

i took the test just now so i am glad i can help someone in the future❣❣❣❣

Also here is the explanation

Note that the magnitude of acceleration (a) is given by a =  

v2

R

, where v is the speed and R is the radius. Because acceleration is the same for both bikers, the ratio 

v2

R

, also has to be the same for both. Given that Kevin’s speed is higher, the radius of his path must also be higher to maintain the same ratio. Therefore, Kevin’s circular path has a bigger radius than Linda’s path.

Look at pic for question pls help

Answers

B IS YOUR ANSWER.

Soft sound has small amplitude and louder sound has large amplitude. Since, the second wave has large amplitude, it will have the loudest sound.

5. You are pulling a rubber sneaker along concrete
a. Calculate force of static friction between your sneakers (2kg) and sidewalk if coefficient of
static friction is 0.9

Answers

Answer:

Fs = 17.66 N

Explanation:

The force of static friction is given by the following formula:

[tex]F_s = \mu R = \mu W\\[/tex]

where,

Fs = The force of static friction = ?

μ = coefficient of static friction = 0.9

W = weight of sneakers = mg

m = mass of sneakers = 2 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]F_s = \mu mg\\F_s = (0.9)(2\ kg)(9.81\ m/s^2)\\[/tex]

Fs = 17.66 N

An SUV has a mass of 6000 kg and a compact car has a mass of 2000 kg. They both go around the same unbanked circular curve on the freeway. Bumper to bumper they go with the same speed vo. The centripetal acceleration of the compact car is ao and the centripetal force acting is Fo. The centripetal acceleration of the SUV is _____ ao of the compact car.

Answers

Answer:

Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.

Explanation:

FOR SUV:

[tex]ac_{suv} = \frac{mv^2}{r}\\[/tex]

where,

ac_suv = centripetal acceleration of the SUV = ?

m = mass of SUV = 6000 kg

v = speed of SUV = vo

r = radius of path

Therefore,

[tex]ac_{suv} = \frac{6000\ vo^2}{r}\\[/tex]---------------- equation (1)

FOR CAR:

[tex]ao = \frac{mv^2}{r}\\[/tex]

where,

ao = centripetal acceleration of the car = ?

m = mass of car = 2000 kg

v = speed of car = vo

r = radius of path

Therefore,

[tex]ao = \frac{2000\ vo^2}{r}\\[/tex]--------------------- equation (2)

Dividing equation (1) by eq(2):

[tex]\frac{ac_{suv}}{ao} = \frac{6000}{2000}\\\\ac_{surv} = 3ao[/tex]

Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.

⦁ A certain resistor is required to dissipate 0.25 W, what standard rating should be used?

Answers

Answer:A

Explanation:

What is the similarity between pushing and lifting? What is the difference?

Answers

Answer:

the similarity is that hands are applied and force

calculate the speed of atrain
that travels 540 meters in 30
seconds?

Answers

Answer:

The train is traveling 18 meters per second.

Explanation:

540/30 = 18

To check your answer do 18 * 30 and it equals 540

Which wave has the longest wavelength?
A. A
B. B
C. C
D.D

Answers

Answer:

In my opinion, ''A" would be the longest wavelength.

So the the greater the height, the
farther something can fall, the greater
the potential energy.
True
False

Answers

The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds.

My best friend just returned from the clinic. She just found out she is HIV- positive. She invited me for dinner. What should I do? Should I go? What do I say to her and her family? Can I eat the foods she cooked or touched? Will she be all right? Imagine this letter is from a friend. Write a page response. Include reasons for your advice.

Answers

Answer:

yes, because you dont want to be mean and make her feel worse about it and hiv has something do with s3x not germs so yes go

Explanation:

What is another example of convection

Answers

radiator. A radiator puts warm air out at the top and draws in cooler air at the bottom. steaming cup of hot tea - The steam you see when drinking a cup of hot tea indicates that heat is being transferred into the air. ice melting/Ice melts because heat moves to the ice from the air

Answer:

boiling water - When water heats, the heat from the burner is transferred to the container, heating the water at the bottom. This hot water rises, creating a circular motion, as colder water descends to replace it.

4 points
Bonus: We know that a huge star went supernova in our area a long time
ago because of the large amount of
on earth.
Water
Oxygen
Iron
Carbon

Answers

Answer: i may not be 100% accurate but i believe it is iron, there is a fire work that uses iron to shine a certain way and is found on stars.

list some application of atmospheric pressure?​

Answers

Answer:

Drinking straw, syringe, Dropper, vacuum, etc.

Explanation:

According to Kepler's second law at the two shaded areas above are equal then...

A. it takes the same amount of time for planet A to travel between T1 and T2 as it does to travel between T3 and T4

B. Planet A will cause an eclipse on Planet B during those time intervals

C. it takes Planet A more time to travel between T1 and T2 as it does to travel between T3 and T4

D. it takes Planet A less time to travel between T1 and T2 as it does to travel between T3 and T4 ​

Answers

Answer:

A.  Kepler's second law says that the radius vector sweeps equal areas in             equal times.

According to Newton, which of these will determine if and how an object will move?

1. how much energy the object has
2. how unstable the object is
3. whether a net force acts on the object
4. he total mass of the object

Answers

Answer:

3

Explanation:

Answer:

whether a net force acts on the object

10 You are given the following list of vo-
lumes: 0.45 m3; 375 cm3; 75 cL; 0.6 dm3.
a. Express all the volumes of the list in
liters.
b. Arrange these volumes in a descending
order.

Answers

Volumes can be transfered to liters only when their measurement units are dm³. a) Which means that: 0.45m³=450dm³ you move the decimal place three places to the right because m³ is larger measurement unit than dm³. 375 cm³ = 0.375 dm³; 75cl = 0.75l because of the prefix centi. 0.6dm³ = 0.6 dm³

So it will be 450l; 0.375l; 0.75l; 0.6l

b) 450l>0.75l>0.6l>0.375l

0.45m³>75cl>0.6dm³>375cm³

I hope i didn't make a mistake, but it would be good if somebody else answered too, so you can compare the answers and see if i made a mistake

The given volumes in liter will be 450 L, 0.375 L, 0.75 L, 0.6 L and the arrangement in descending order will be 450 L > 0.75 L > 0.6 L > 0.37 L .

What is Volume?

Every three-dimensional item takes up space in some way. The volume of this area is what is used to describe it. The area covered within an entity's three-dimensional bounds is referred to as its volume. The object's size is another name for it.

As per the given information in the question,

a.

The given volume in a meter cube is 0.45.

Unit conversion:

1 m³ = 1000 L

So, 0.45 m³ = 0.45 × 1000

= 450 L

The given volume in a centimeter cube is 375.

Unit conversion:

1 cm³ = 0.001 L

375 cm³ = 0.001 × 375

= 0.375 L.

The given volume in a centiliter cube is 75.

Unit conversion:

1 cl³ = 0.01 L

75 cl³ = 75 × 100

= 0.75 L

The given volume in the decimeter cube is 0.6.

1 dm³ = 1 L

0.6 dm³  = 0.6 L

b.

So, the volumes in descending order will be,

450 L > 0.75 L > 0.6 L > 0.37 L or,

0.45 m³ > 75 cl³ > 0.6 dm³ > 375 cm³

To know more about Volume:

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Some types of bacteria contain chains of ferromagnetic particles parallel to their long axis. The chains act like small bar magnets that align these magnetotactic bacteria with the earth's magnetic field. In one experiment to study the response of such bacteria to magnetic fields, a solenoid is constructed with copper wire, 1.0 mmmm in diameter, evenly wound in a single layer to form a helical coil of length 40 cmcm and diameter 12 cmcm. The wire has a very thin layer of insulation, and the coil is wound so that adjacent turns are just touching. The solenoid, which generates a magnetic field, is in an enclosure that shields it from other magnetic fields. A sample of magnetotactic bacteria is placed inside the solenoid. The torque on an individual bacterium in the solenoid’s magnetic field is proportional to the magnitude of the magnetic field and to the sine of the angle between the long axis of the bacterium and the magnetic-field direction.

What current is needed in the wire so that the magnetic field experienced by the bacteria has a magnitude of 150μT?

a. 0.095 A
b. 0.12 A
c. 0.30 A
d. 14 A.

Answers

Answer:

the required current is 0.12 A

Option b) 0.12 A is the correct answer

Explanation:

Given the data in the question,

to determine the current needed in the wire, we use the following relation;

B = μ₀n[tex]I[/tex]

[tex]I[/tex] = B / μ₀n

where μ₀ is the magnetic constant   ( 4π × 10⁻⁷ T.m/A )

n is the number of turns ( 1 / 1mm[tex]\frac{10^{-3}m}{1 mm}[/tex]) = 1000 m⁻¹

B is magnitude ( 150μT ( [tex]\frac{10^{-6}m}{1uT}[/tex]) )

so we substitute

[tex]I[/tex] =  [ 150μT ( [tex]\frac{10^{-6}m}{1uT}[/tex]) ] / [ ( 4π × 10⁻⁷ T.m/A ) × 1000 m⁻¹ ]

[tex]I[/tex] =  [ 0.00015 ] / [ 0.00125 ]

[tex]I[/tex] = 0.12 A

Therefore, the required current is 0.12 A

Option b) 0.12 A is the correct answer

PLEASE HELP ME WITH THIS ONE QUESTION
A converging lens has a focal length of 40 cm. If an object is placed 50 cm in front of the image, where will the image be formed?

Answers

Answer:

the image will be real and inverted

example of kinetic energy into heat energy

Answers

Answer:

The kinetic energy of large objects can be converted into this thermal energy.

Explanation:

For example, if you drop a water balloon onto the ground, its kinetic energy is converted mostly to thermal energy. If the balloon weighs 1 kilogram and you drop it from about 2 meters, it will heat up by less.

What is the specific heat of a substance that absorbs 1600 joules of heat when a sample
of 18 g of the substance increases in temperature from 20 °C to 31°C? Round your answer
to two decimal places if necessary.

Answers

Answer:

8.08 J/g °C

Explanation:

Q=m*Cp*ΔT-->

Cp=Q/(m*ΔT) -->

Cp=1600/[18*(31-20)]-->

Cp=8.08 J/g °C

Jill doubled the force acting on an object, yet she kept the acceleration constant or unchanged.
How did she do this?

Answers

Answer:

Mass doubles

Explanation:

Since F = ma, and given that the acceleration stayed constant, the mass must have changed. (Assuming thatt when the problem states the force doubles, they mean the net force doubles). Note, that the mass does not have to change if the acceleration is zero.

HELP ME PLEASE <333, NUMBER 3 ONLY! ​

Answers

Answer:

b

Explanation:

is correct .....................

i think

The frequency, or pitch, of a musical note varies inversely with
the wavelength. The speed of sound, 340.2 meters per second, is
the constant of variation.
An "A" note in octave 3, has a frequency of 220 Hertz. What is the
wavelength of the sound made by the tuner in meters?

Answers

Answer:

0.647 meters

Explanation:

i did the quiz

is ice a fluid at room temperature?

Answers

Answer:

Ice is the solid state of water, a normally liquid substance that freezes to the solid state at temperatures of 0 °C (32 °F) or lower and expands to the gaseous state at temperatures of 100 °C (212 °F) or higher.

Explanation:

Free use of uniforms and socialization with classmates are possible advantages of ? A.)
dual sports B.)community-based sports programs C.)individual sports D.) school-based sports programs​

Answers

The answer is B community based sports program

Answer:

its d

Explanation:

Calculate the force of an object that has a mass of 10kg and an acceleration of 4m/s²
A-40N
B-8N
C-2.5N
D-0.4N

Answers

The answer is A-40N.

Pls Help Me with this problem

Answers

Answer:

explanation

Explanation:

1 = C

2 = A

3 = D

4 = E

5 = B

1) C, 2) B, 3) D, 4)A, 5)E

5. During a heat transfer investigation, students filled two cups with water. One cup contains 100mL of cold water while the other contains 100 mL of hot water.
A metal heat wire is placed inside the water of both cups and thermometers are attached to each cup. Which of the following BEST explains how the heat is transferred? Cold Water Hot Water.

A. This investigation would not result in any heat being transferred.

B. Convection, because the metal wire was heated through convection currents.

C. Radiation, because the metal wire was heated by electromagnetic waves.

D. Conduction, because the metal wire was in direct contact with water in both containers.​

Answers

Answer:

D.Conduction, because the metal wire was in direct contact with water in both containers

Conduction, because the metal wire was in direct contact with water in both containers.​ Option D is correct.

Given that,
Students filled two cups with water. One cup contains 100mL of cold water while the other has 100 mL of hot water. A metal heat wire is placed inside the water of both cups and thermometers are attached to each cup.
It is to be identified, the system contains which type of heat transfer between the cups

What is heat transfer?

Heat transfer is the process, in a thermodynamic system, when an object at a higher temperature is placed with an object at has a lower temperature, after some time the system attains equilibrium because heat flows from higher temperature to lower temperature.


In the given question,
Cups, that are connected through a metal wire, one is hot and the other is cold, Principal of conduction state that when there is a system of connected bodies the heat flows throughout the connected system till the thermal equilibrium attain. Implies heat flow from hot cup to cold cup through the wire through conduction heat transfer.

Thus, Conduction, because the metal wire was in direct contact with water in both containers.​ Option D is correct.

Learn more about heat transfer here:
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Two objects, one with a mass of 2 m and one with a mass of 4 m are attracted to each other
by a gravitational force. If the force on 2 m is F, what is the force on mass 4 m in terms of F?

Answers

It would be 7 M 4 m x 2 m equals 8 M - 1 =7

o reduce the drag coefficient and thus to improve the fuel efficiency, the frontal area of a car is to be reduced. Determine the amount of fuel and money saved per year as a result of reducing the frontal area from 18 to 14 ft2. Assume the car is driven 12,000 mi a year at an average speed of 55 mi/h. Take the density and price of gasoline to be 50 lbm/ft3 and $3.10/gal, respectively; the density of air to be 0.075 lbm/ft3, the heating value of gasoline to be 20,000 Btu/lbm; and the overall efficiency of the engine to be 30 percent. Take the drag coefficient as CD

Answers

Complete question

To reduce the drag coefficient and thus to improve the fuel efficiency, the frontal area of a car is to be reduced. Determine the amount of fuel and money saved per year as a result of reducing the frontal area from 18 to 14 ft2. Assume the car is driven 12,000 mi a year at an average speed of 55 mi/h. Take the density and price of gasoline to be 50 lbm/ft3 and $3.10/gal, respectively; the density of air to be 0.075 lbm/ft3, the heating value of gasoline to be 20,000 Btu/lbm; and the overall efficiency of the engine to be 30 percent. Take the drag coefficient as CD=0.3 for a passenger car.

Answer:

22.22%

$57

Explanation:

From the question we are told that

Initial area of frontal area [tex]a_1=18ft^2[/tex]

Final area of frontal area [tex]a_2=14ft^2[/tex]

Distance covered a year [tex]D=12000mile[/tex]

Average speed a year [tex]V_{avg}=55mile/h[/tex]

Density [tex]\rho=50 lbm/ft3[/tex]

Price [tex]P= $3.10/gal[/tex]

Density of air [tex]\rho_{air} 0.075 lbm/ft3[/tex]

Heating value of gasoline [tex]Q=20,000 Btu/lbm[/tex]

Efficiency [tex]\eta=30\%[/tex]

Drag coefficient [tex]CD=0.3[/tex]

[tex]\triangle A=18-14ft^2=4ft^2[/tex]

Generally the equation for drag force [tex]C_D[/tex] is mathematically given as

[tex]F_D=\frac{C_DAPV^2}{2}[/tex]

[tex]F_D=\frac{0.3*18*0.075*(80.685^2)*A}{2}[/tex]

[tex]F_D=73.24Alb[/tex]

where [tex]v=55mil/h*1.467=80.685ft/s[/tex]

Generally the equation for work done W is mathematically given as[tex]W=F_D*L[/tex]

where [tex]L=12000mile*5280[/tex]

[tex]L=63360000[/tex]

[tex]W=73.24A*63360000[/tex]

[tex]W=4.6*10^9A[/tex]

Generally the equation for overall efficiency [tex]\eta[/tex] is mathematically given as

where

[tex]W_{req}=required\ gasoline\ power\ efficiency[/tex]

[tex]\eta=\frac{W}{W_{req}}[/tex]

[tex]W_{req}=\frac{W}{\eta}[/tex]

[tex]W_{req}=\frac{4.6*10^9}{0.3}[/tex]

[tex]W_{req}=1.55*10^{10}A[/tex]

Generally the equation for reduction fee with change in frontal area [tex]\triangle M[/tex] is mathematically given as

[tex]\triangle M =\triangle Vgasoline*cost[/tex]

Where

[tex]\triangle Vgasoline= volume\ reduction\ of\ gasoline[/tex]

[tex]\triangle Vgasoline=\frac{E_{req}}{H*P}[/tex]

[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]

if

[tex]20000btu/ibm=20000*778.169*32.2(1bm.ft^2/s)[/tex]

[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]

[tex]\triangle Vgasoline=0.61859A[/tex]

Therefore

[tex]\triangle M =0.61859A*3.10[/tex]

if [tex]1ft^2=7.48gal[/tex]

[tex]\triangle M =0.61859(4)*3.10*7.48[/tex]

[tex]\triangle M = \$ 57.671[/tex]

Generally the equation for reduction of fuel [tex]F_r[/tex]is mathematically given as

[tex]F_r=\frac{\triangle A}{\triangle i}*100[/tex]

where

[tex]\triangle i=18ft^2[/tex]

[tex]F_r=\frac{4}{18}*100[/tex]

Fuel reduction price by reducing front area is 22.22%

Money saved per year is $57

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