10. Which property is used to show the form in maximize state
a) Selection State b) Window State c) Mode d) Opening State

Answer:

An object of type Employee can call the setDepartment method of the Programmer class on itself

Explanation:

From what can be inferred above, the programmer class is a subclass of the employee class meaning that the programmer class inherits from the employee class by the code:

Public class Programmer extends Employee

This therefore means(such as in Java) that the programmer class now has access to the methods and attributes of the employee class, the superclass which was inherited from

Answer:

Authorization

Explanation:

Answer:

class PatientData():    #declaration of PatientData class

   height_inches=0  #attribute of class is declared and initialized to 0

   weight_pounds=0 #attribute of class is declared and initialized to 0

Explanation:

Here is the complete program:

#below is the class PatientData() that has two attributes height_inches and weight_pounds and both are initialized to 0

class PatientData():  

   height_inches=0

   weight_pounds=0  

patient = PatientData()  #patient object is created of class PatientData

#below are the print statements that will be displayed on output screen to show that patient data before

print('Patient data (before):', end=' ')

print(patient.height_inches, 'in,', end=' ')

print(patient.weight_pounds, 'lbs')

#below print  statement for taking the values height_inches and  weight_pounds as input from user

patient.height_inches = int(input())  

patient.weight_pounds = int(input())  

#below are the print statements that will be displayed on output screen to show that patient data after with the values of height_inches and weight_pounds input by the user

print('Patient data (after):', end=' ')

print(patient.height_inches, 'in,', end=' ')

print(patient.weight_pounds, 'lbs')      

Another way to write the solution is:

def __init__(self):

       self.height_inches = 0

       self.weight_pounds = 0

self keyword is the keyword which is used to easily access all the attributes i.e. height_inches and weight_pounds defined within a PatientData class.

__init__ is a constructor which is called when an instance is created from the PatientData, and access is required to initialize the attributes height_inches and weight_pounds of PatientData class.

The program along with its output is attached.

In this exercise we have to use the knowledge of computational language in python to describe a code, like this:

The code can be found in the attached image.

To make it easier the code can be found below as:

class PatientData():  

  height_inches=0

  weight_pounds=0  

patient = PatientData()

print('Patient data (before):', end=' ')

print(patient.height_inches, 'in,', end=' ')

print(patient.weight_pounds, 'lbs')

patient.height_inches = int(input())  

patient.weight_pounds = int(input())  

print('Patient data (after):', end=' ')

print(patient.height_inches, 'in,', end=' ')

print(patient.weight_pounds, 'lbs')

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Answer:

The correct query is;

select * from EMPLOYEE where Employee_Name = 'JOE' or Employee_Name = 'Joe' or Employee_Name = 'joe';

where EMPLOYEE refer to the table name and type attribute name is Employee_Name

Explanation:

Here, the first thing we will do is to assume the name of the table.

Let’s assume the table name is EMPLOYEE, where the column i.e attribute from which we will be extracting our information is Employee_Name

The correct query to get the piece of information we are looking for will be;

select * from EMPLOYEE where Employee_Name = 'JOE' or Employee_Name = 'Joe' or Employee_Name = 'joe';

Answer:

wpa2 wep

Explanation:

wpa2 wep multiple choices

Answer:

string sep = "";

for (i = 0; i < NUM_VALS; i++) {

 cout << sep << hourlyTemp[i];

 sep = ", ";

}

Explanation:

Insert the snippet at the commented location.

With the absence of a join() method as found in other languages, it is always a hassle to suppress that separator comma from appearing at the beginning or the end of your output. This solution is nice since it doesn't require any magic flags to keep track of wether the first element was printed.

El número mínimo de monedas que se deben invertir para lograr esto:

45 moas

Answer:

No-force policy

Explanation:

The policy that allows a transaction to commit even if it has modified some blocks that have not yet been written back to disk is called the _NO-FORCE_ policy.

In data theory, the No-Force Policy is beneficial for the control of transaction. In this policy, when a transaction commits, changes that are made are not required to be written to disk in place. The changes recorded are preserved in order to make transaction durable. The recorded changes must be preserved at commit time.

Answer:

The main job of a web server is to display website content through storing, processing and delivering webpages to users. Besides HTTP, web servers also support SMTP (Simple Mail Transfer Protocol) and FTP (File Transfer Protocol), used for email, file transfer and storage.

Explanation:

If it helps you mark me as a brainleast

Answer:

A) for 100 : < 1 times

b) for 750 : < 1 times

c) For 2000 = 1 time

D) for  10000 = 4 times

E) for  100000 = 7 times

Explanation:

Given data:

load factor = 75%

initial capacity = 1000

The number of times the enlarge method will be called for a unique number of entries  would be 2 times the initial capacity ( 1000 ) because the load factor = 75% = 0.75

A) for 100 : < 1 times

b) for 750 : < 1 times

C) For 2000

= initial capacity * 2  = 2000   ( 1 time )

D) for 10000

= 1000 * 2 *2 *2*2 = 16000 ( 4 times )

to make it 10000 we have to add another 2000 which will make the number of times = 4 times

E)for  100000

= 1000*2*2*2*2*2*2*2= 128000 ( 7 times )

unique entry of 100000 is contained in 7 times

Answer:

Life skills, learning skills, The literacy skills

Explanation:

There are different type of skills that are required in schools, educational societies, organizations. Now these students need more attention to focus on their carrier. There are different of skills such as:

There are another three skills like

These are some skills that help students that keep up the lightening -pace in todays modern society. All skills are unique and used differently by students.

Answer:

D) Procedural

Explanation:

Answer:

Object-Oriented Programming

Explanation:

Answer:

Following are the code to this question:

In question 1:

tempReadings.push_back(newValue); //using array that store value in at 3 position

In question 2:

ticketList.pop_back(); //defining ticketList that uses the pop_back method to remove last insert value

In question 3:

currentSize = sensorReadings.size(); /defining currentSize variable holds the sensorReadings size value

In question 4:

cout<<"Last mpg reading: "<<mpgTracker.at(mpgTracker.size()-1)<<endl;

//using mpgTracker array with at method that prints last element value

Explanation:

please find the attachment of the questions output:

Using data from interviews with ESCO executives conducted in late 2012, this study examines the market size, growth forecasts, and industry trends in the United States for the ESCO sector.

Thus,  It uses the "currentSize" variable to holds the "sensorReadings" size value, which is "10". In the fourth question, It uses the mpgTracker array with the "at" method, which prints the last element value, which is "20".

There are numerous types of gateways that can operate at various protocol layer depths.

Application layer gateways (ALGs) are also frequently used, albeit most frequently a gateway refers to a device that translates the physical and link layers. It is best to avoid the latter because it complicates deployments and is a frequent source of error.

Thus, Using data from interviews with Gateway executives conducted in late 2012, this study examines the market size, growth Esco size and industry trends in the United States for the Gateway.

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#SPJ6

Answer:

Without it learning and teaching cannot take place.

Explanation:

It is worthy to note that an operating system enables a computer install and run (lunch) computer programs. In a teaching environment that involves the use of computers, sending lessons to students; would mean that they have software programs that can successfully open this lessons.

In summary, an operating system is indeed pivotal in teaching and learning.

def ultimate_math (num1, num2):

try:

array_num = [num1, num2]

print (num1 + num2)

print (num1 - num2)

print (num1 * num2)

print (num1 / num2)

print (num1 % num2)

print ((num1 + num2) / (len(array_num)))

print ((num1**2) + (num2**2))

except ValueError:

return "Invalid Input"

user_num1 = float (input (" Please enter a num: "))

user_num2 = float (input (" Please enter a second num: "))

print (ultimate_math (user_num1, user_num2))

Answer:

def power(base, expo):

   if expo == 0:

       return 1

   else:

       return base * power(base, expo-1)

Explanation:

*The code is in Python.

Create a method called power that takes base and expo as parameters

Check if the expo is equal to 0. If it is return 1 (This is our base case for the method, where it stops. This way our method will call itself "expo" times). If expo is not 0, return base * power(base, expo-1). (Call the method itself, decrease the expo by 1 in each call and multiply the base)

o_num = input ("Please enter the amount of \"o\": ")

zero_num = input ("Please enter the amount of zeros: ")

i = 0

while i < o_num and i < zero_num:

repeat_o = "Hell" + o_num

repeat_zero = repeat_o + zero_num

i+=1

print (repeat_zero)

The penalties for ignoring the requirements for protecting classified information when using social networking services are the same when using other media and methods of dissemination.

The penalties are the same because it does not matter what the medium used, the effect is that classified information and confidential details have been left unguarded and exposed.

When in hold of such information, it is not okay to leave it unguarded or exposed. A person who is found guilty of disclosure of classified materials would face sanctions such as:

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Answer:

Answered below

Explanation:

Imperative programming paradigm is a paradigm in which the programmer tells the machine how to change its state. It is divided into procedural programming, where programs are grouped as procedures, and object-oriented, where programs are grouped together with the properties they operate on.

Imperative paradigm is efficient, familiar and popular compared to others.

Functional programming paradigm implements all instructions as functions, in a mathematical sense. They take on an argument and return a single solution. The advantage of this, compared to other paradigms, is its abstraction and independence.

Logical programming, like functional programming, incorporates a declarative approach to problem solving. All known facts are first established before queries are made. Advantage of this paradigm is that programming steps are kept to a minimum.

Answer:

E-Government Act of 2002.

Explanation:

The E-Government Act of 2002 is a statute of the United States of America which was enacted by the 107th U.S Congress on the 17th of December, 2002. The E-Government Act of 2002 was signed into law to facilitate the management and promotion of the US government processes and services, as well as enhance transparency and accountability between the government and the public through the application of internet-based information technology.

Under the E-Government Act of 2002, federal agencies must;

1. Review their IT systems for privacy risks.

2. Post privacy policies on their websites.

3. Post machine-readable privacy policies on their websites.

4. Report privacy activities.

Answer:

Find the explanation below.

Explanation:

Asymmetric encryption is a system of communication in technology between two parties where keys which are variable values coined by an algorithm are used to encrypt and decrypt the messages between the sender and receiver. The two types of keys used in this process are the public and private keys. The public keys can be used by anyone to encrypt messages which are then sent to the receiver who decrypts the message using his private keys. The private keys on the other hand are only shared by the person who first set up the key. In sending messages this way, the receiver's public key is gotten from a public directory, and the message encrypted by the sender. The receiver can then decrypt the message using his private keys. But if the message is encrypted using a private key, it is decrypted by the receiver with a public key.

The one-way nature of this style of communication ensures data integrity and confidentiality since users are not required to disclose their keys and only the two parties can access the message. The two end users also preserve the right to authenticate the keys. The transport layer security protocol makes use of asymmetric encryption.

Answer:

Explanation:

Hello friend !!!!!!!!!!!!

The answer is school zone

Hope this helps

plz mark as brainliest!!!!!!!

Children walking on the sidewalk, a person sitting in a parked car, and a parking lot with vehicles entering and exiting indicate a school zone (Option C).

In conclusion, children walking on the sidewalk, a person sitting in a parked car, and a parking lot with vehicles entering and exiting indicate a school zone (Option C).

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Caption:it is used to display speaker's name and describe relevant sounds that are inaccessible to people of hard hearing or who are deaf

Back color: it is used to fill a section's interior. it contains numerical expressions that corresponds

Font: it is used to add style to a document or webpage

Alignment: it is used to describe how text is placed on a screen.

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Answer:

Confirmation biases impact how we gather information, but they also influence how we interpret and recall information. For example, people who support or oppose a particular issue will not only seek information to support it, they will also interpret news stories in a way that upholds their existing ideas.

Answer:

Here is the Python function readList:

def readList(filename):  #function definition of readList that takes a filename as a parameter and returns a list of integers in the file

   list = []  # declares an empty list

   with open(filename, 'r') as infile:  # opens the file in read mode by an object infile

       lines = infile.readlines()  # returns a list with each line in file as a list item

       for line in lines:   #loops through the list of each line

           i = line[:-1]  # removes new line break which is the last character of the list of line

           list.append(i)  # add each list item i.e. integers in the list

       return list  #returns the list of integers

#in order to check the working of the above function use the following function call and print statement to print the result on output screen

print(readList("file.txt")) #calls readList function by passing a file name to it

Explanation:

The program is well explained in the comments mentioned with each line of the code.

The program declares an empty list.

Then it opens the input file in read mode using the object infile.

Next it uses readLines method which returns a list with each line of the file as a list item.

Next the for loop iterates through each item of the file which is basically integer one per line

It adds each item of list i.e. each integers in a line to a list using append() method.

Then the function returns the list which is the list of integers in the file.

The program along with it output is attached. The file "file.txt" contains integers 1 to 8 one per line.

Answer:

Here is the JAVA code:

public class Main{

public static int solution(int[] A) { //method that takes non-empty array A consisting of 0s and 1s

           int N = A.length; // number of 0s and 1s in array A

           int r = 0; //result of adjacency

           for (int i = 0; i < N - 1; i++;   )   { // iterates through A

               if (A[i] == A[i + 1])  //if i-th element of A is equal to (i+1)th element

                   r = r + 1;   }     //add 1 to the count of r

           if (r == N-1)   //for test cases like {1,1}

           {return r-1; }

           int max = 0; //to store maximum possible adjacency

           for (int i = 0; i <N; i++)   { //iterates through array

               int c = 0;

               if (i > 0)    { //starts from 1 and  covering the last

                   if (A[i-1] != A[i]) //checks if i-1 element of A is not equal to ith element of A

                       c = c + 1;    //adds 1 to counter variable

                   else

                      c = c - 1;   } //decrements c by 1

               if (i < N - 1)     {//starting with 0

                   if (A[i] != A[i + 1])  //checks if ith element of A is not equal to i+1th element of A

                       c = c + 1; //adds 1 to counter variable

                   else

                       c = c - 1;   }      //decrements c by 1        

               max = Math.max(max,c);   }  //finds the maximum of max and c

           return r + max;         } //returns result + maximum result

        public static void main(String[] args) {

   int[] A = {1, 1, 0, 1, 0, 0}; //sample array to test the method

   System.out.println(solution(A));} } //calls the method passing array to it

Explanation:

The program works as follows:

A[] = {1, 1, 0, 1, 0, 0}

N = A.length

N = 6

The A has the following elements:

A[0] =  1

A[1] = 1

A[2] = 0

A[3] = 1

A[4] = 0

A[5] = 0

Program iterates through array A using for loop. Loop variable i is initialized to 0

if condition if (A[i] == A[i + 1]) checks

if (A[0] == A[0 + 1])

A[0] =  1

A[0 + 1] = A[1] = 1

They both are 1 so they are equal

r = r + 1;  

Since the above if condition is true so 1 is added to the value of r Hence

r = 1

At each iteration of the loop the if condition checks whether the adjacent elements of A are equal. If true then r is incremented to 1 otherwise not.

So after all the iterations value of r = 2

if (r == N-1) evaluates to false because r=2 and N-1 = 5

So program moves to the statement:

for (int i = 0; i <N; i++)

This loop iterates through the array A

if (i > 0) condition checks if value of i is greater than 0. This evaluates to false and program control moves to statement:

if (i < N - 1) which makes if(0<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1])  which means:

if (A[0] != A[0 + 1]) -> if (A[0] != A[1])

We know that

A[0] =  1

A[1] = 1

So this evaluates to false and else part is executed:

value of c is decremented to 1. So c=-1

max = Math.max(max,c) statement returns the max of max and c

max = 0

c = -1

So max = 0

value of i is incremented to 1 so i = 1

At next step:

if (i < N - 1) which makes if(1<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1]) which means:

if (A[1] != A[1 + 1]) -> if (A[1] != A[2])

A[1] = 1

A[2] = 0

So the statement evaluates to true and following statement is executed

c = c + 1; The value of c is incremented to 1. So

c = -1 + 1

Hence

Hence c= 0, max = 0 and i = 2

next step:

if (i < N - 1) which makes if(2<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1]) which means:

if (A[2] != A[2 + 1]) -> if (A[2] != A[3])

A[2] = 0

A[3] = 1

So the statement evaluates to true and following statement is executed

c = c + 1; The value of c is incremented to 1. So

c = 0 + 1

c = 1

Hence

The statement max = Math.max(max,c) returns the max of max and c

max = 0

c = 1

So max = 1

Hence  c= 1, max = 1 and i = 3

next step:

if (i < N - 1) which makes if(3<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1]) which means:

if (A[3] != A[3 + 1]) -> if (A[3] != A[4])

A[3] = 1

A[4] = 0

So the statement evaluates to true and following statement is executed

c = c + 1; The value of c is incremented to 1. So

c = 1 + 1

c = 2

Hence

The statement max = Math.max(max,c) returns the max of max and c

max = 1

c = 2

So max = 2

Hence c= 2, max = 2 i = 4

next step:

if (i < N - 1) which makes if(4<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1])  which means:

if (A[4] != A[4+ 1]) -> if (A[4] != A[5])

A[4] = 0

A[5] = 0

So this evaluates to false and else part is executed:

value of c is decremented to 1. So c=1

max = Math.max(max,c) statement returns the max of max and c

max = 2

c = 1

So max = 2

value of i is incremented to 1 so i = 5

next step:

if (i < N - 1) which makes if(5<5) This evaluates to false

if (i > 0) evaluates to true so following statement executes:

if (A[i-1] != A[i])

if (A[5-1] != A[5])

if (A[4] != A[5])

A[4] = 0

A[5] = 0

This statement evaluates to false so else part executes and value of c is decremented to 1

Hence

max = 2

c = 0

So max = 2

value of i is incremented to 1 so i = 6

The loop breaks because i <N evaluates to false.

Program control moves to the statement:

return r + max;

r = 2

max = 2

r + max = 2+2 = 4

So the output of the above program is:

4

Answer:

d

Explanation:

cause people need a care for there incedents that not expected thats why people need help prevent from a risk to save people lives

Answer:

In dynamic scoping the current block is searched by the compiler and then all calling functions consecutively e.g. if a function a() calls a separately defined function b() then b() does have access to the local variables of a(). The visible variables with the name of the function in which it was defined are given below.

Explanation:

In main() function three integer type variables are declared: a,b,c

In fun1() three int type variables are declared/defined: b,c,d

In fun2() three int type variables are declared/defined: c,d,e

In fun3() three int type variables are declared/defined: d,e,f

a. Main calls fun1; fun1 calls fun2; fun2 calls fun3

Here the main() calls fun1() which calls fun2() and fun2() calls func3() . This means first the func3() executes, then fun2(), then fun1() and last main()

Visible Variable:  d, e, f        Defined in: fun3

Visible Variable: c                 Defined in: fun2 (the variables d and e of fun2  

                                                                                                     are not visible)

Visible Variable: b                  Defined in: fun1 ( c and d of func1 are hidden)

Visible Variable: a                 Defined in: main (b,c are hidden)

b. Main calls fun1; fun1 calls fun3

Here the main() calls fun1, fun1 calls fun3. This means the body of fun3 executes first, then of fun1 and then in last, of main()

Visible Variable: d, e, f           Defined in: fun3

Visible Variable:  b, c              Defined in: fun1 (d not visible)

Visible Variable:  a                  Defined in: main ( b and c not visible)

c. Main calls fun2; fun2 calls fun3; fun3 calls fun1

Here the main() calls fun2, fun2 calls fun3 and fun3 calls fun1. This means the body of fun1 executes first, then of fun3, then fun2 and in last, of main()

Visible Variable:  b, c, d        Defined in: fun1

Visible Variable:  e, f             Defined in: fun3 ( d not visible)

Visible Variable:  a                Defined in: main ( b and c not visible)

Here variables c, d and e of fun2 are not visible

d. Main calls fun3; fun3 calls fun1

Here the main() calls fun3, fun3 calls fun1. This means the body of fun1 executes first, then of fun3 and then in last, of main()

Visible Variable: b, c, d     Defined in: fun1  

Visible Variable:   e, f        Defined in:  fun3   ( d not visible )

Visible Variable:    a          Defined in: main (b and c not visible)

e. Main calls fun1; fun1 calls fun3; fun3 calls fun2

Here the main() calls fun1, fun1 calls fun3 and fun3 calls fun2. This means the body of fun2 executes first, then of fun3, then of fun1 and then in last, of main()

Visible Variable: c, d, e        Defined in: fun2

Visible Variable:  f               Defined in: fun3 ( d and e not visible)

Visible Variable:  b               Defined in:  fun1 ( c and d not visible)

Visible Variable: a                Defined in: main ( b and c not visible)

f. Main calls fun3; fun3 calls fun2; fun2 calls fun1

Here the main() calls fun3, fun3 calls fun2 and fun2 calls fun1. This means the body of fun1 executes first, then of fun2, then of fun3 and then in last, of main()

Visible Variable: b, c, d       Defined in: fun1  

Visible Variable: e               Defined in: fun2  

Visible Variable: f                Defined in: fun3  

Visible Variable: a               Defined in: main

Answer:

s_string = 1357

Explanation:

character: index

1: 0

3: 1

5: 2

7: 3

 : 4

C: 5

o: 6

u: 7

n: 8

t: 9

r: 10

y: 11

 : 12

L: 13

n: 14

. : 15

s_tring  = special[:4]

s_tring = special[0] + special[1] + special[2] + special[3]

s_string = 1357