10. Which of the followings is not correct about Skull? A) Divided into two structural parts B) Facial skeleton holds 14 bones C) Neuro cranium holds 8 bones D) There are 2 maxilla bones E) Frontal is

Answers

Answer 1

The following is not correct about the skull is "D) There are 2 maxilla bones".

The skull, also known as the cranium, is the bony structure of the head that forms the main supporting framework of the face and jaws. It is divided into two distinct parts: the neurocranium and the facial skeleton. The neurocranium holds the brain and its coverings and comprises of eight bones. The facial skeleton consists of 14 bones that form the jaws, cheekbones, and orbits (eye sockets).

It also has a bone in the middle of the face, the vomer, which forms the nasal septum and a paired bone, the mandible, which is the lower jaw. There is only one maxilla bone, which is the upper jawbone in the skull, forming the central part of the facial skeleton. The two maxilla bones articulate with each other in the midline of the face. Hence, option D is incorrect as there are not two maxilla bones in the skull.

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Related Questions

Which of the following statement about gene interaction is true? Select the correct response: Gene interaction may result in modified phenotypic ratios deviating from those expected of independently assorting genes exhibiting complete dominance. Gene interaction could be allelic wherein the interaction is between alleles of different genes or non-allelic interaction involving alleles of a gene pair. Genes are simply separate elements producing distinct individual effects, but they could interact with each other giving entirely different phenotypes.

Answers

The true statement about gene interaction is that it may result in modified phenotypic ratios deviating from those expected of independently assorting genes exhibiting complete dominance.

Gene interaction refers to the phenomenon where genes interact with each other to influence the expression of traits or phenotypes. The statement that is true about gene interaction is that it may result in modified phenotypic ratios deviating from those expected of independently assorting genes exhibiting complete dominance.

In cases of gene interaction, the expression of genes and the resulting phenotypes may deviate from the expected ratios based on Mendelian genetics. Gene interaction can involve allelic interactions, where the interaction occurs between different alleles of different genes, or non-allelic interactions, which involve alleles of a gene pair.

The interaction between genes can lead to a variety of outcomes, including the production of entirely different phenotypes compared to what would be expected if the genes acted independently. This highlights the complex nature of genetic inheritance and the influence of gene interactions on trait expression.

Therefore, the true statement is that gene interaction may result in modified phenotypic ratios deviating from those expected of independently assorting genes exhibiting complete dominance.

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I just want answers without justification, I only have
10 minutes to solve them
Autonomic motor nerves innervate all 1 poir of the following except: The heart The small intestine The salivary glands The biceps muscle Which of these elements is a 1 poir compound of the parasympath

Answers

Autonomic motor nerves innervate all of the following except the biceps muscle. A compound of the parasympathetic division is acetylcholine (ACh).

Acetylcholine acts as a neurotransmitter in the parasympathetic nervous system, transmitting signals from the pre-ganglionic neurons to the post-ganglionic neurons and ultimately influencing various target tissues and organs.

It plays a crucial role in regulating rest, digestion, and relaxation. Acetylcholine is released by the pre-ganglionic neurons and binds to specific receptors on the post-ganglionic neurons and target cells, initiating the parasympathetic response. Its actions include slowing heart rate, stimulating gastrointestinal activity, promoting salivation, and other functions related to restorative processes in the body.

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a) Compare the mechanisms of nucleotide excision repair in E.coli and human cells. Discuss the mechanistic differences between transcription coupled repair and global genome repair in both organisms.

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In both organisms, E.coli and human cells, NER involves the recognition and removal of damaged DNA segments followed by DNA synthesis and ligation. However, the key difference lies in the additional process called transcription-coupled repair (TCR) that occurs in human cells.

In E. coli, NER operates globally throughout the genome to repair DNA damage. It involves the recognition of lesions by UvrA and UvrB proteins, followed by the recruitment of UvrC and UvrD for excision and DNA synthesis.

However, in human cells, in addition to global genome repair (GGR), TCR is employed to specifically repair DNA lesions that obstruct the progression of RNA polymerase during transcription.

TCR involves the recruitment of additional proteins such as CSA, CSB, and XAB2, which facilitate the removal of the stalled RNA polymerase and subsequent repair.

These mechanistic differences reflect the need for efficient repair of transcription-blocking DNA lesions in human cells, which is not observed in E. coli. TCR allows for the preferential repair of lesions in transcribed regions, ensuring the maintenance of genomic integrity during active transcription.

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what are the likely applications of both immunochromatography and Latex agglutination?
what are 1 limitation of each method?

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Immunochromatography is a technique that is used for detecting the presence of proteins and other substances in biological samples. Some likely applications of immunochromatography are:1. Pregnancy test.

This test utilizes immunochromatography to detect the presence of human chorionic gonadotropin (h CG) in urine samples to confirm pregnancy.2. Diagnosis of infectious diseases: Immunochromatography is used to detect specific antigens or antibodies in patient samples to diagnose diseases like HIV, malaria, and streptococcal infections.3. Drug testing: Immunochromatography is also used for drug screening in forensic and clinical laboratories. One limitation of immunochromatography is that it is not as sensitive as other methods such as enzyme-linked immunosorbent assays (ELISA) and polymerase chain reaction (PCR).Latex agglutination is a diagnostic technique that is used to detect the presence of antigens and antibodies in biological samples. Some likely applications of latex agglutination are:1. Blood typing: Latex agglutination is used to identify different blood groups by detecting specific antigens present on red blood cells.2. Diagnosis of infectious diseases: Latex agglutination is used to diagnose bacterial and viral infections by detecting specific antigens in patient samples.3. Detection of autoimmune diseases: Latex agglutination is used to detect autoantibodies in patient samples to diagnose autoimmune diseases like rheumatoid arthritis.One limitation of latex agglutination is that it requires the preparation of specific latex beads for each antigen or antibody being detected, which can be time-consuming and expensive.

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22.The imaginal discs create structures like the appendages in metamorphosis.
Select one:
a.
TRUE
b.
false
23. Mutations in the following gene turn antennae into legs:
Select one:
a.
Nanos
b.
bicoid
c.
antennapedia
d.
Decapentaplegic
e.
Flow
24.Which of the following genes shows seven bands of genetic expression, in which the expression of each band is controlled by its own "enhancer"?
Select one:
a.
hunchback
b.
Krupel
c.
Nanos
d.
Even skipped
e.
Wingless

Answers

The imaginal discs create structures like the appendages in metamorphosis.

Select one:

a. TRUE

Imaginal discs are groups of cells in the larvae of insects such as Drosophila that are responsible for the development of adult structures during metamorphosis. They give rise to structures like wings, legs, and antennae.

Mutations in the following gene turn antennae into legs:

Select one:

c. antennapedia

The antennapedia gene, also known as Antp, is responsible for the development of segments in the anterior part of the body in Drosophila. Mutations in this gene can result in transformations where antennae develop into legs.

Which of the following genes shows seven bands of genetic expression, in which the expression of each band is controlled by its own "enhancer"?

Select one:

d. Even skipped

The Even skipped gene in Drosophila exhibits seven bands of gene expression during embryonic development. Each band of expression is regulated by its own specific enhancer region, which controls the precise spatial pattern of gene expression along the anterior-posterior axis of the embryo.

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signal transduction- yeast genetics
In one sentence, what is the URA3- to URA3+ conversion with plasmid transformation? Why is it necessary to do this first?

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In yeast genetics, the URA3-to-URA3+ conversion is the use of plasmid transformation to introduce a plasmid containing the URA3+ gene into a strain lacking the URA3 gene that allows yeast to grow on media lacking uracil, which is necessary to do first to select for yeast containing the plasmid due to its ability to grow on media lacking uracil.

URA3 is a gene present in the yeast cell and involved in the synthesis of uracil and pyrimidine nucleotides. It encodes or produces or codes for or creates an enzyme or protein that converts or changes or turns uracil into an essential nucleotide for the cell's growth.URA3 gene deletion has been used extensively in genetic manipulations in yeast for the following reasons:

It is a simple method of introducing targeted gene deletions or modifications.It can be used to knock out or remove or delete any gene from the yeast genome, provided that the strain is URA3-positive.Its utilization allows for the creation of new strains or mutants with specific properties or features.It serves as a selective marker for the transformation of plasmids into yeast cells.

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Based on our current understanding of the planet and its ecosystem(s), explain the rationale of why we do not want to divert more Bio-available Net Primary Productivity to support societal energy needs in the form, of Human-appropriated Net Primary Productivity. What is the possible role of artificial or applied photosynthesis?
Give three reasons and explain why Photosystem I has been widely used in producing biological solar cells. Please consider the PSI protein/antenna structure, biological source, stability, and redox chemistry.

Answers

Based on our current understanding of the planet and its ecosystem(s), there are several rationales behind why we do not want to divert more Bio-available Net Primary Productivity (NPP) to support societal energy needs in the form of Human-appropriated Net Primary Productivity (HANPP).

Firstly, the diversion of bio-available NPP for energy consumption can alter the balance of ecosystems and harm the biodiversity. Secondly, bio-available NPP is also used for several other purposes like food production, and diverting a significant portion of it can lead to food shortages. Thirdly, NPP is the primary driver of several ecosystem services, including nutrient cycling, which is essential for maintaining the quality of soil, air, and water.

The possible role of artificial or applied photosynthesis is to develop sustainable energy systems that rely on photosynthetic technology, mimicking natural photosynthesis.

This approach aims to overcome the limitations of using fossil fuels, which are depleting and contribute to environmental degradation.Photosystem I (PSI) has been widely used in producing biological solar cells due to the following reasons:

• PSI has a high-efficiency rate of energy conversion.

• The structure of PSI protein/antenna is stable, allowing it to remain functional for an extended period.

• PSI's redox chemistry enables it to produce a high voltage that is ideal for use in solar cells.

• PSI has a large absorption cross-section, which means that it can efficiently absorb light from the sun.Artificial photosynthesis has the potential to provide a renewable and sustainable source of energy, and the use of PSI in biological solar cells is an important step towards achieving this goal.

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In each organism, there is approximately one guanine for every
thymine? true or false
In each organism, there is approximately one guanine for every
cytosine.? True or false

Answers

1. In each organism, there is approximately one guanine for every thymine: True. 2. In each organism, there is approximately one guanine for every cytosine: False.

In each organism, there is approximately one guanine for every thymine: True. This statement is based on the complementary base pairing rule in DNA. Guanine (G) always pairs with cytosine (C), forming a G-C base pair, while adenine (A) always pairs with thymine (T), forming an A-T base pair. These base pairs are connected by hydrogen bonds. The amount of guanine in an organism's DNA is expected to be approximately equal to the amount of thymine because of this complementary pairing.In each organism, there is approximately one guanine for every cytosine: False. This statement is not accurate because the ratio of guanine to cytosine (G:C) can vary among different organisms and even within different regions of an organism's genome. The G:C ratio is influenced by various factors, including the organism's genetic makeup, environmental factors, and evolutionary history. It is important to note that the G:C ratio is not necessarily 1:1 in all organisms.

Therefore, while the first statement regarding guanine and thymine is generally true due to the complementary base pairing in DNA, the second statement regarding guanine and cytosine is false as the ratio between guanine and cytosine can vary.

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Why do many diseases caused by bacteria and viruses last only 7-10 days?

Answers

Many diseases caused by bacteria and viruses last only 7-10 days due to various factors related to the immune response and the life cycle of the pathogens.

Firstly, the immune system plays a crucial role in fighting off infections. When the body is exposed to a pathogen, the immune system activates an immune response, including the production of specific antibodies and immune cells, such as T cells and B cells. These immune components work together to eliminate the invading pathogens and clear the infection. This coordinated immune response typically takes several days to effectively control and eliminate the pathogens from the body.

Secondly, bacteria and viruses have their own life cycles. During an infection, these pathogens replicate and spread within the host's body. However, their replication is not unlimited, and they eventually reach a peak level of infection. At this point, the immune response, along with other defense mechanisms in the body, starts to effectively control the infection and reduce the pathogen load. As a result, the symptoms of the disease start to improve, and the infection begins to resolve.

It is important to note that the duration of an infection can vary depending on several factors, including the specific pathogen, the individual's immune response, and the overall health of the person. In some cases, certain infections may last longer than 7-10 days or become chronic if the immune response is unable to completely eliminate the pathogen.

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Explain the relationships between the following types of energy. Include references to the Laws of Thermodynamics. (3 marks) a. free energy b. transition state c. activation energy

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Free energy, transition state, and activation energy are related. Free energy can perform work, transition state refers to a hypothetical state of maximum potential energy, and activation energy is the minimum energy required for a chemical reaction.
Free energy, transition state, and activation energy are all important concepts in the study of chemical reactions. Free energy is a measure of the amount of energy available to do work under certain conditions, such as constant temperature and pressure. Transition state is a hypothetical state in which the reactants are converted into products with maximum potential energy, and activation energy is the minimum energy required to initiate a chemical reaction.The relationship between these three types of energy can be understood through the Laws of Thermodynamics. According to the first law, energy cannot be created or destroyed, only transferred or converted from one form to another. In the case of chemical reactions, the total energy of the system is conserved, meaning that the energy present in the reactants must be conserved in the products.

The second law of thermodynamics states that the total entropy of a system will increase over time. Entropy is a measure of the disorder of a system, and an increase in entropy corresponds to a decrease in order. In the case of a chemical reaction, the transition state represents a high-energy, low-entropy state, while the products represent a lower-energy, higher-entropy state.

In conclusion, the relationships between free energy, transition state, and activation energy are important to understand in the context of chemical reactions. Free energy is a measure of available work, transition state represents a hypothetical state of maximum potential energy, and activation energy is the minimum energy required to initiate a reaction. These concepts are all related through the Laws of Thermodynamics, which describe how energy is transferred and converted between different forms.

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You have generated strains of Drosophila melanogaster that are
expected to show interesting developmental phenotypes such as
misplaced organs in the adult fly. However, some of these
phenotypes are no

Answers

Generating strains of Drosophila melanogaster with expected developmental phenotypes can result in some phenotypes not manifesting as anticipated.

When generating strains of Drosophila melanogaster with the aim of observing specific developmental phenotypes, it is common to encounter instances where certain expected phenotypes do not appear as intended. This can be due to a variety of factors, including genetic interactions, environmental influences, and the complex nature of developmental processes.

Drosophila melanogaster, commonly known as the fruit fly, has long been used as a model organism in genetics and developmental biology research due to its rapid life cycle, well-characterized genome, and easily observable phenotypes. Researchers often create strains with genetic modifications or mutations in specific genes to investigate the role of these genes in development.

However, despite careful design and selection of strains, it is not uncommon for certain anticipated phenotypes to be absent or different from what was predicted. This can occur due to genetic interactions, where the effects of one mutation may be masked or modified by the presence of other genes or mutations in the organism. Additionally, environmental factors such as temperature, nutrition, and stress can influence the expression of developmental phenotypes, leading to variations in the observed outcomes.

Understanding the complex interplay between genes, their interactions, and environmental factors is crucial in interpreting and analyzing developmental phenotypes in Drosophila melanogaster. Further investigations, including additional genetic crosses, environmental manipulations, and detailed phenotypic analyses, may be necessary to unravel the underlying mechanisms and gain a comprehensive understanding of the observed phenotypes.

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These resident bacteria co-evolved with their hosts, are present on body surfaces covered by epithelial cells, and are exposed to the external environment. Usually they are not pathogenic, but under specific conditions they are able to overcome protective host responses and exert pathologic effects.
a.commensal microflora
b.parasitism
c.oligotrophs
d.neutralism
e.amensal microflora

Answers

Commensal microflora refers to the population of microorganisms that reside in or on the body of a host organism without causing harm.

These microorganisms, including bacteria, fungi, and viruses, have co-evolved with their hosts and have established a mutually beneficial relationship.

They are typically found on body surfaces covered by epithelial cells, such as the skin, respiratory tract, gastrointestinal tract, and urogenital tract.

The commensal microflora play important roles in maintaining the health and functioning of the host organism. They contribute to various physiological processes, including digestion, vitamin synthesis, and immune system regulation.

The correct answer is option A: commensal microflora.

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9. (a) Where is the somatosensory area located in the brain? (1 mark) (b) Explain why the cortical homunculus indicates a distorted representation of the human body. (4 marks)

Answers

(a) The somatosensory area, also known as the primary somatosensory cortex, is located in the parietal lobe of the brain.

(b) The cortical homunculus indicates a distorted representation of the human body because it illustrates the relative amount of cortical area dedicated to different body parts in the somatosensory and motor cortex.

A) The somatosensory area, also known as the primary somatosensory cortex, is located in the parietal lobe of the brain. Specifically, it is found in the postcentral gyrus, which is situated just posterior to the central sulcus. The somatosensory area receives and processes sensory information related to touch, temperature, pain, and proprioception from different parts of the body.

B) In the cortical homunculus, body parts that have a higher density of sensory receptors or require finer motor control are represented with larger cortical areas.

The representation is distorted because it does not accurately reflect the actual physical size of body parts. For example, the hands and face occupy disproportionately large areas in the cortical homunculus compared to other body parts like the trunk or legs. This distortion arises from the fact that the representation is based on the relative sensitivity and complexity of sensory or motor functions associated with different body regions rather than their actual size.

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In your own understanding describe the location and function of the precentral gyrus

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The precentral gyrus is a prominent structure located in the frontal lobe of the brain that plays a crucial role in motor control and voluntary movements.

The precentral gyrus, also known as the primary motor cortex, is situated in the posterior part of the frontal lobe, just in front of the central sulcus. It is found in both cerebral hemispheres and is primarily responsible for initiating and controlling voluntary movements of the body.

The precentral gyrus contains a topographic map of the body known as the motor homunculus, where different regions of the gyrus correspond to specific body parts. The organization of the motor homunculus is such that larger areas represent body parts that require finer motor control and precision, such as the hands and face.

When we decide to perform a voluntary movement, such as reaching for an object or speaking, the precentral gyrus sends signals to the relevant motor neurons in the spinal cord, which in turn activate the muscles involved in the movement. This process is facilitated by the complex network of connections between the precentral gyrus and other brain regions involved in motor planning, coordination, and feedback.

In summary, the precentral gyrus, located in the frontal lobe of the brain, is responsible for initiating and controlling voluntary movements. It contains a motor homunculus that represents different body parts, and its activity is coordinated with other brain regions involved in motor control to execute precise and coordinated movements.

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A recording electrode inserted perpendicularly into the primary visual cortex finds that neurons within the same cortical column likely respond preferentially to: a. Cortical neurons at the surface respond to near objects and cortical neurons deep in the cortex respond to far objects b. cortical neurons arranged in columns do not typically respond similarly to the same stimulus c. a similar orientation of a light bar d. a similar color intensity of a light stimulus

Answers

Option C is the correct answer.The recording electrode inserted perpendicularly into the primary visual cortex will likely find that neurons within the same cortical column respond preferentially to a similar orientation of a light bar.

The human visual cortex is organized into columns that respond selectively to the orientation and direction of stimuli in the visual field. Neurons within a column have a similar orientation selectivity and are arranged in an orderly fashion.The specific orientation of the light bar that a neuron responds to is determined by the organization of receptive fields of neurons in the visual cortex. These neurons have receptive fields that are specific to certain orientations and can detect edges and contours of objects in the visual field. Therefore, neurons within the same cortical column are likely to respond preferentially to a similar orientation of a light bar.Therefore, option C is the correct answer.

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Describe
1)what causes an action potential
2) What ions are involved
3) why it's essential to know if you are going into a health
field.

Answers

An action potential is a rapid and brief electrical event that occurs in excitable cells, such as neurons and muscle cells. It is a crucial mechanism for communication within the nervous system and the contraction of muscles.

1. Action potential is a brief electrical charge that travels across the membrane of a neuron, which allows the signal to travel quickly along the cell membrane. An action potential is caused by the flow of ions such as sodium and potassium across the cell membrane of the neuron.

2. The ions involved in an action potential include potassium, sodium, and calcium. In the resting state, the inside of the neuron is negatively charged, and the outside is positively charged. When the neuron is stimulated, the permeability of the cell membrane changes and positive ions such as sodium and calcium enter the cell, resulting in depolarization. Once the action potential reaches its maximum, potassium ions exit the cell, returning the membrane to its resting state.

3. It is essential to know about action potential and ions involved if you are going into the health field because the nervous system is an essential component of the human body. Understanding the mechanism of an action potential and the ions involved helps healthcare providers diagnose, understand, and treat various neurological conditions. Additionally, it is necessary to understand the flow of ions in the human body to prescribe effective treatments for patients with neurological disorders.

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Describe the steps in meiosis and mitosis using the following terms: chromosome, chromatid, sister chromatid, homologous chromosomes, centromere, kinetochore, centrosome, centriole, tubulin, nuclear membrane, chiasmata, recombinant chromosomes, non recombinant chromosomes, haploid, diploid.

Answers

Mitosis and meiosis are two distinct ways in which cells divide. Both mitosis and meiosis consist of several steps that are essential for the successful division of cells. Mitosis is the division of somatic cells that have been duplicated, while meiosis is the division of gamete cells. The mitosis process is a simple and straightforward process that comprises several steps.

During meiosis, a diploid cell divides into four haploid cells. Meiosis includes the following steps: prophase I, metaphase I, anaphase I, telophase I, cytokinesis I, prophase II, metaphase II, anaphase II, telophase II, and cytokinesis II. Prophase I is characterized by the formation of homologous pairs of chromosomes that line up together. The chromosomes intertwine and exchange genetic information through a process called crossing over, which creates recombinant chromosomes. The non-recombinant chromosomes, which have not undergone the crossing over process, are known as parental chromosomes. In metaphase I, the homologous chromosomes align at the center of the cell, while the spindle fibers attach to the kinetochore located at the centromere of each chromosome. In anaphase I, the spindle fibers shorten, and the homologous chromosomes separate and migrate towards the poles. Telophase I results in the formation of two nuclei, each containing a single chromosome of the homologous pair.

Cytokinesis results in the division of the cytoplasm, which gives rise to two daughter cells. The second round of meiosis is similar to mitosis, resulting in the formation of four haploid daughter cells. In summary, both mitosis and meiosis are essential processes that allow cells to divide and ensure the proper development and growth of an organism.

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Describe the morphology of the cells the will give the following results in the following Osmotic Fragility tests: Inital Hemolysis Final hemolysis Cell Morphology a. 0.65 0.45 b. 0.35 0.20 c. 0.45 0.35 10. Performing a platelet estimate in a smear the results per field: 20, 22, 19, 18, 21, 17, 20, 19, 23, 21 The expected platelet count is:_ 11. If you have to perform a WBC count of a leukemic patient that his count usually runs approximately 200,000/ul. If you count the standard WBC area, which dilution should you use in order to get approximately 40 cells /square ?

Answers

Osmotic fragility test is a type of lab test that evaluates how much hemolysis occurs to red blood cells when subjected to hypotonic salt solutions. The morphology of cells is essential for the osmotic fragility test. Therefore, this article discusses the morphology of cells that will give the following outcomes in the osmotic fragility test. a. 0.65 0.45The cell morphology of this test result is spherocytosis.

The cells are more spherical and less flexible than normal cells and are susceptible to early destruction.b. 0.35 0.20The cell morphology of this test result is normal cells. The cells are resilient and maintain their structure in the hypotonic salt solutions.c. 0.45 0.35The cell morphology of this test result is elliptocytosis. The cells are more oval-shaped than the standard cells, and they tend to lyse early and are more susceptible to early destruction.10. Performing a platelet estimate in a smear the results per field: 20, 22, 19, 18, 21, 17, 20, 19, 23, 21 The expected platelet count is:The formula for estimating the platelet count is:Average number of platelets in 10 fields x 15,000Example:Average number of platelets per 10 fields = 20+22+19+18+21+17+20+19+23+21/10 = 199/10 = 19.9(0.9 is less than half, so we round it off to the lower number)Expected platelet count = 19 x 15,000= 285,00011. If you have to perform a WBC count of a leukemic patient that his count usually runs approximately 200,000/ul.

Therefore, to calculate the final volume,Total number of cells required = (Final volume x 40) / 200,000Final volume = (Total number of cells required x 200,000)/40Final volume = 5000 uL or 5 mL.

Therefore, the required dilution is 1:5 (0.1 mL of blood + 0.4 mL of diluent) which gives the required number of cells at 40 cells /square.

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Two nutrient broths are inoculated with 1,000 cells of Vibrio. You incubate one with shaking (generation time = 20 minutes) and one without shaking (generation time = 30 minutes).
After 3 hours which culture has more cells? Give your answer in correct scientific notation and show your working .
Use the equation:
Nt = No x 2n
where Nt is the final cell number
No is the original cell number
n is the number of generations

Answers

To determine which culture has more cells after 3 hours, we can use the equation Nt = No x 2^n, where Nt is the final cell number, No is the original cell number, and n is the number of generations.

For the culture with shaking:

Generation time = 20 minutes

Number of generations in 3 hours = (3 hours) / (20 minutes/generation) = 9 generations

For the culture without shaking:

Generation time = 30 minutes

Number of generations in 3 hours = (3 hours) / (30 minutes/generation) = 6 generations

Now let's calculate the final cell number for both cultures:

For the culture with shaking:

Nt = 1,000 cells x 2^9 = 1,000 cells x 512 = 512,000 cells

For the culture without shaking:

Nt = 1,000 cells x 2^6 = 1,000 cells x 64 = 64,000 cells

Therefore, after 3 hours, the culture with shaking has more cells. The final cell number for the culture with shaking is 5.12 x 10^5, and for the culture without shaking is 6.4 x 10^4.

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What are modes of natural selections (name them only) and of
them, which one is an ideal model for rapid speciation? Why?

Answers

The three modes of natural selection include stabilizing selection, directional selection, and disruptive selection. Out of these three, disruptive selection is the ideal model for rapid speciation. It has a significant impact on the distribution of a particular trait in a population.

If this mode of selection continues for a long time, then it can lead to the formation of a new species.

What is natural selection?

Natural selection is the process through which nature selects the most suitable and adaptive traits in a population. It is the most significant mechanism through which evolution takes place. The traits that increase an organism's chances of survival and reproduction are selected and are passed on to the next generation.

Over time, these changes accumulate, and the population evolves into a new species.Modes of natural selectionThe following are the three modes of natural selection:Stabilizing selection: This mode of selection is responsible for maintaining the status quo of a population. In this mode, individuals with traits closer to the average are favored. The extreme traits on either end of the distribution are eliminated.Directional selection: In this mode, individuals with traits that deviate from the norm are favored.

This can occur due to a change in the environment or migration. The distribution of the trait changes to one end of the spectrum.Disruptive selection: In this mode, the extreme traits on either end of the distribution are favored. This is often seen in populations with diverse habitats. This mode of selection can result in the formation of two new species.

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A. Explain why it is important that an energy producing pathway contains at least one regulatory enzyme, you can use either glycolysis or TCA enzymes to discuss this answer B. The first step in glycolysis involves the conversion of glucose to glucose-6- phosphate. Briefly explain how this reaction occurs as it is an endergonic reaction. C. Why is it important that the cell has a number of different high-energy biomolecules?

Answers

The presence of at least one regulatory enzyme in an energy producing pathway is crucial to ensure proper control and regulation of the pathway's activity. In glycolysis, the first step involves an endergonic reaction requiring the input of energy.

A. Regulatory enzymes play a vital role in energy producing pathways by controlling the rate of reactions and ensuring energy balance within the cell. These enzymes act as checkpoints, responding to signals and modulating the pathway's activity accordingly. By having at least one regulatory enzyme, the pathway can be fine-tuned, preventing excessive energy production or depletion. This regulation is crucial for maintaining cellular homeostasis and avoiding detrimental consequences such as energy wastage or energy deficiency.

B. In glycolysis, the initial step involves the conversion of glucose to glucose-6-phosphate. This reaction is considered endergonic because it requires the input of energy. Specifically, it utilizes one molecule of ATP to phosphorylate glucose, resulting in the formation of glucose-6-phosphate. This phosphorylation reaction requires the transfer of a phosphate group from ATP to glucose, and the breaking and formation of chemical bonds. The input of energy in the form of ATP allows this reaction to occur and drives the subsequent steps of glycolysis.

C. Having a variety of different high-energy biomolecules is essential for the cell's energy metabolism. It provides flexibility and diversity in energy sources, allowing the cell to adapt to varying conditions. Different biomolecules, such as glucose, fatty acids, and amino acids, can be metabolized to generate ATP through various pathways.

This diversity ensures that the cell can efficiently meet its energy demands under different physiological or environmental circumstances. Additionally, utilizing different energy sources helps prevent over-reliance on a single molecule, minimizing the risk of depletion or energy imbalance. Therefore, the presence of multiple high-energy biomolecules is vital for the cell's energy metabolism and overall functioning.

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Heparan sulfate, an example of a(n) ____ that goes on to form part of a ___
O GAG; proteoglycan O oligosaccharide; glycoprotein O proteoglycan; GAG O GAG; multiadhesive matrix protein

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Heparan sulfate is a type of GAG that forms part of the proteoglycan.

GAG stands for glycosaminoglycan. A GAG molecule comprises a lengthy chain of disaccharide units that are comprised of two monosaccharides. The phrase "GAG" stands for glycosaminoglycan, and heparan sulfate is a member of this family. Proteoglycans are a type of glycoprotein that are heavily glycosylated (modified by sugar residues), and they are critical components of the extracellular matrix (ECM).

Heparan sulfate is a GAG and a structural component of proteoglycans in a multi adhesive matrix protein.Heparan sulfate is a component of glycosaminoglycans (GAGs) that form proteoglycans. GAGs are lengthy chain-like structures made up of disaccharide units, each containing two monosaccharides.

Heparan sulfate is a kind of GAG that exists in all tissues and is involved in a wide range of biological processes. It is abundant in the extracellular matrix and on the surface of cells. It also acts as a cofactor for various enzymes and regulates the activities of growth factors and other signaling molecules.

Heparan sulfate is crucial for the formation of proteoglycans, a kind of glycoprotein that is heavily glycosylated. Proteoglycans are major constituents of the extracellular matrix, and they serve as a link between cells and the matrix. Heparan sulfate is a GAG, and it is a critical structural component of proteoglycans in a multi adhesive matrix protein.

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In their famous experiment, Alfred Hershey and Martha Chase concluded that DNA, not protein, is the genetic material. This conclusion was drawn from two complementary experiments: one with radioactive sulphur (S) and one with radioactive phosphorus (P). a) What conclusion could have been drawn if only radioactive P was used (not also radioactive S)? b) What conclusion could have been drawn if only radioactive S was used (not also radioactive P)? [2 marks]

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The results of the two experiments, they were able to definitively show that DNA was responsible for the transmission of genetic information.

a) If only radioactive phosphorus (P) was used and not radioactive sulfur (S), the conclusion that could have been drawn is that DNA, which contains phosphorus, is the genetic material. This is because radioactive phosphorus would label the DNA molecules, allowing the researchers to track the location of the radioactive material. If the radioactive phosphorus was found in the progeny of the infected bacteria, it would suggest that DNA was passed on and therefore is the genetic material.

b) If only radioactive sulfur (S) was used and not radioactive phosphorus (P), the conclusion that could have been drawn is that proteins, which contain sulfur but not phosphorus, are the genetic material. This is because the radioactive sulfur would label the protein molecules, allowing the researchers to track their location. If the radioactive sulfur was found in the progeny of the infected bacteria, it would suggest that proteins were passed on and therefore are the genetic material.

However, it's important to note that Hershey and Chase's experiment used both radioactive phosphorus and radioactive sulfur to demonstrate that DNA, not protein, is the genetic material. By comparing the results of the two experiments, they were able to definitively show that DNA was responsible for the transmission of genetic information.

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Is a Ventricular Assist Device or VAD is the most recommended
way to treat heart diseases, if not, then what is the most
recommended way to treat heart disease?

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A Ventricular Assist Device (VAD) is indeed a recommended treatment option for certain heart conditions, but it is not the most commonly recommended treatment for all heart diseases.

The most appropriate treatment for heart disease depends on the specific diagnosis, severity of the condition, and individual patient factors.

Here are some commonly recommended treatment approaches for various heart diseases:

Lifestyle modifications: For milder forms of heart disease, lifestyle changes may be the initial approach. This can include adopting a heart-healthy diet, regular exercise, smoking cessation, stress management, and weight management.

Medications: Medications are commonly prescribed to manage heart disease. The specific drugs prescribed will depend on the type of heart disease and its underlying causes. Common medications include beta-blockers, ACE inhibitors, statins, antiplatelet drugs, and diuretics, among others.

Percutaneous coronary intervention (PCI): PCI is a minimally invasive procedure used to treat blocked or narrowed coronary arteries. It involves the use of a catheter to place stents in the arteries, improving blood flow to the heart muscle. PCI is commonly performed in cases of coronary artery disease or heart attacks.

Coronary artery bypass grafting (CABG): CABG is a surgical procedure that involves bypassing blocked or narrowed coronary arteries using grafts taken from other blood vessels in the body. It is typically recommended for more severe cases of coronary artery disease.

Cardiac rehabilitation: Cardiac rehabilitation programs help individuals with heart disease improve their overall cardiovascular health through supervised exercise, education, and lifestyle counseling.

Heart transplantation: In cases where heart disease is severe and cannot be effectively managed by other treatments, heart transplantation may be considered. This involves replacing the diseased heart with a healthy heart from a donor.

It's important to note that the best treatment approach for a specific individual should be determined by a qualified healthcare professional who considers the patient's unique circumstances and medical history.

Treatment recommendations may vary based on the type and stage of heart disease, overall health, and individual preferences.

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If you are trying to count the number of ants per square meter in a field, the best survey technique to use would be: Select one: a. quadrat sampling. b. transects. c. genetic sequencing. d. census.

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Given that the problem is asking about counting the number of ants per square meter, and the term "square" is mentioned in the question, it becomes evident that the correct answer is "a. Quadrat sampling".Thus, quadrat sampling is the best survey technique to use to count the number of ants per square meter in a field.

the best survey technique to use would be quadrat sampling.Quadrat sampling is a classic tool used to quantify the abundance of organisms in a defined area. Scientists use it to estimate the density, frequency, and cover of species in a particular habitat.The quadrat sampling technique involves counting the number of ants in a defined area, usually a square meter. It is the best survey technique to use when counting the number of ants per square meter in a field since it helps estimate population density accurately. Given that the problem is asking about counting the number of ants per square meter, and the term "square" is mentioned in the question, it becomes evident that the correct answer is "a. Quadrat sampling". Thus, quadrat sampling is the best survey technique to use to count the number of ants per square meter in a field. use would be: Select one: a. quadrat sampling. b. transects. c. genetic sequencing. d. census.

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Endurance exercise performance is improved through aerobic (endurance) exercise training due to ...
a. an enhanced capacity of muscle fibres to generate ATP.
b. improvements in central and peripheral blood flow.
c. both an enhanced capacity of muscle fibres to generate ATP, and improvements in central and peripheral blood flow.
d. none of these answers.

Answers

So correct option is c. Endurance exercise performance is improve through aerobic exercise training due to both an enhanced capacity of muscle fibers to generate ATP & improvement central and peripheral blood flow.

Muscle are soft tissues in the human body that enable movement, stability, and support. They are composed of specialized cells called muscle fibers that contract and relax to generate force. There are three main types of muscles: skeletal, cardiac, and smooth muscles. Skeletal muscles are attached to bones and control voluntary movements. Cardiac muscles form the walls of the heart and facilitate its rhythmic contractions. Smooth muscles are found in organs and blood vessels, contributing to involuntary movements. Regular exercise helps maintain muscle strength, flexibility, and overall physical well-being.

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Neutrophils are one of the key cells involved with acute inflammation and resolving infections. Discuss the production, mobilisation, localisation and activity of neutrophils in this process, highlighting a clinical scenario where neutrophil number or function is impaired. (max 400 words)

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Neutrophils are white blood cells that make up the first line of defense against pathogens and invading microorganisms. Neutrophils are produced and released into the bloodstream from the bone marrow, where they are stored and are capable of being rapidly mobilized in response to infection, injury, or inflammation. Their primary role is to eliminate the pathogen by engulfing them in a process called phagocytosis, where they release enzymes and chemicals to break down and destroy the pathogen.

During infection or injury, neutrophils are recruited to the site of inflammation, where they accumulate and increase in number, as the endothelial cells lining the blood vessels produce cytokines, that triggers the release of chemokines and adhesion molecules that facilitate the migration and accumulation of neutrophils at the site of infection.
Once neutrophils arrive at the site of infection, they become activated and undergo degranulation, where they release toxic substances such as reactive oxygen species (ROS), neutrophil extracellular traps (NETs), and cytokines, that kill the invading microorganisms and recruit other immune cells to the site of infection.
A clinical scenario where neutrophil number or function is impaired is the rare congenital disease called leukocyte adhesion deficiency (LAD). LAD is a genetic disorder where the neutrophils lack the ability to migrate and accumulate at the site of infection, due to the absence or deficiency of adhesion molecules that facilitate neutrophil migration.

LAD patients have recurrent and severe bacterial infections, that are not responsive to antibiotics, and are associated with poor prognosis and high mortality rates.In conclusion, neutrophils are essential components of the innate immune system, that play a crucial role in acute inflammation and resolving infections. Their production, mobilization, localization, and activity are tightly regulated by various signals and molecules, that enable them to migrate and accumulate at the site of infection, and eliminate the pathogen. However, in certain clinical scenarios such as LAD, neutrophil number or function may be impaired, leading to recurrent and severe infections.

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Answer these discussion questions.
Topic # 1: Plant growth hormone and chemical complementation: Plant scientists postulate that a new class of plant growth hormones may control Arabidopsis growth. To confirm their idea, the scientists knock out a gene in Arabidopsis wildtype Ler-0 (Landsberg erecta) and succeed in generating a stunted mutant they call de-etiolated2 (det2). Using a purified form of the hormone "brassinosteroid," they rescue the mutant’s phenotype such that it is indistinguishable from Ler-0. What are the geneticists to make of their observations?
Topic #2: Plant flowering time control: Plants sense day length to determine the appropriate time for flowering. This is controlled mainly be phytochrome and its conversion from one for to another. Describe how this process works.

Answers

Plant growth hormone and chemical complementation: In the research, scientists discovered that a new class of plant growth hormones may control Arabidopsis growth. To confirm their idea, the scientists knocked out a gene in Arabidopsis wildtype Ler-0 (Landsberg erecta) and generated a stunted mutant called de-etiolated2 (det2).

Topic #1: The researchers applied a purified form of the hormone "brassinosteroid" and succeeded in rescuing the phenotype of the mutant to the point where it was indistinguishable from Ler-0.The researchers were able to confirm that the hormone “brassinosteroid” controls Arabidopsis growth and development, as well as serving as a chemical complement. The hormone helped to rescue the mutant’s phenotype, which was significantly stunted when compared to the wildtype Ler-0. The scientists were able to make observations about the control and growth of Arabidopsis, showing that plant growth hormones can control the growth of Arabidopsis and complement the function of genes.

Topic #2: Plant flowering time control:Plants sense day length in order to determine when it is appropriate to flower. This is mostly regulated by phytochrome and its conversion from one form to another.Phytochromes are photoreceptors that plants use to detect light. They exist in two different interconvertible forms, Pr and Pfr. The Pr form absorbs red light at around 660 nm, whereas the Pfr form absorbs far-red light at around 730 nm. When a plant is exposed to light, the phytochromes absorb either red or far-red light, and then they are interconverted from one form to the other, depending on the type of light absorbed.

Photoperiodism involves a complex signaling pathway that detects changes in day length, which is ultimately translated into the appropriate developmental response. The duration of the night is sensed by the phytochrome pigments, which can then control the production of flowering hormones in the plant.

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Suppose you have a mix of two bacteria in a broth culture, bacteria "A" and bacteria "B". You use a streak isolation technique to inoculate this culture onto a petri dish. After incubation, you see these two colony morphologies on your plate: . Colonies that appear smooth and are a yellow color Colonies that have a rough appearance and a tan color and are bigger than the yellow colonies. Draw your expected results of the STREAK ISOLATION, from the broth with two species that were mixed in the tube, here (using colored pencils or the computer drawing tools).

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The streak isolation technique is a procedure that is used to separate bacterial colonies from each other in the laboratory. In the experiment provided, the smooth, yellow-colored colonies and the rough, tan-colored, and bigger colonies were observed after incubation

. It can be inferred that the smooth, yellow colonies belong to species "A," while the rough, tan-colored and larger colonies belong to species "B." The following is an illustration of the expected results of the streak isolation technique.  [asy] draw((0,0)--(0,10)); draw((0,0)--(10,0)); draw((0,10)--(10,10)); draw((10,10)--(10,0)); draw((0,0)--(10,10), red); draw((0,3)--(10,13), blue); draw((0,6)--(10,16),green); draw((0,9)--(10,19),purple); filldraw((5,3)--(8,6)--(8,9)--(5,6)--cycle, yellow,black); filldraw((1.5,0)--(3,1.5)--(3,3)--(1.5,1.5)--cycle, brown,black); filldraw((2,3)--(5,6)--(5,8)--(2,5)--cycle, yellow,black); filldraw((5.5,9)--(7,10.5)--(7,7)--(5.5,7)--cycle, brown,black); filldraw((8.5,4.5)--(10,6)--(10,3)--(8.5,3)--cycle, brown,black); [/asy]

From the illustration, it can be seen that streak A yielded yellow colonies that were smooth, while streak B produced larger, rougher, and tan-colored colonies. This is because bacteria A is a gram-negative bacteria that grows in acidic environments, while bacteria B is a gram-positive bacteria that thrives in alkaline environments. The morphologies of the two colonies are not related in any way, and the growth of each colony is dependent on the type of bacterial species present in the broth culture.

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You can use your understanding of the nature of science to evaluate ongoing environmental issues. For example, the Montreal Protocol's phase-out of CFCs was made possible by the availability of working alternatives, But do these alternatives come with unacceptable trade-offs? The hydrocholorfluorocharbons (HCFCs) and hydrofluorocarbons (HFCs) that have largely replaced CFCs for industrial purposes don't damage stratospheric ozone, but it turns out they do have a negative impact on the environment. Should they now be phased out, too? Search the library or Intemet for information about the drawbacks of HCFCs and HFCs. 1. Are HCFCs and HFCs good altematives to CFCs with regard to stratospheric ozone depletion? 2. What environmental problems are associated with the use of HCFCs and HFCs? 3. What is your position on a possible ban of both of these chemicals? Support your answer and Cite your source(s) of information. We are a non-science majors class so any citation format is fine. just list it.

Answers

1) HCFCs and HFCs are considered better alternatives to CFCs in terms of stratospheric ozone depletion.

2)  Both HCFCs and HFCs are potent greenhouse gases (GHGs) that contribute to global warming.

3) Transitioning to more environmentally friendly alternatives with lower GWPs and improved energy efficiency would be a prudent step to mitigate these issues.

What are the HCFCs?

Strong greenhouse gases (GHGs) that contribute to global warming include HCFCs and HFCs. In comparison to carbon dioxide (CO2), HFCs have a higher warming effect per unit of mass due to their high global warming potential (GWP) values. The usage of these substances in more applications has accelerated climate change and global warming.

Considering the harmful effects HCFCs and HFCs have on the environment, I believe a phase-out of these chemicals would be an acceptable course of action. Even if they have been essential in halting ozone depletion, their impact on global warming and climate change cannot be disregarded.

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HCFCs and HFCs are considered better alternatives to CFCs with regard to stratospheric ozone depletion, as they do not contain chlorine atoms. However, they have negative environmental impacts as potent greenhouse gases, contributing to global warming and climate change. Therefore, a phased-out ban on HCFCs and HFCs, with a transition to more environmentally friendly alternatives, is necessary to address these concerns and promote a sustainable future.

1. HCFCs (hydrochlorofluorocarbons) and HFCs (hydrofluorocarbons) are considered better alternatives to CFCs (chlorofluorocarbons) with regard to stratospheric ozone depletion. Unlike CFCs, HCFCs and HFCs do not contain chlorine atoms, which are the main contributors to ozone depletion. Therefore, the use of HCFCs and HFCs has helped in reducing the damage to the ozone layer.

2. However, HCFCs and HFCs do have negative environmental impacts. They are potent greenhouse gases that contribute to global warming and climate change.

Their emissions have a high global warming potential, meaning they trap heat in the atmosphere more effectively than carbon dioxide. This can lead to increased temperatures, altered weather patterns, and other adverse effects on ecosystems and human health.

3. Considering the negative environmental impact of HCFCs and HFCs, there is growing support for their phased-out and replacement with more environmentally friendly alternatives.

Many countries and international agreements are already taking steps to reduce and eventually eliminate the use of these substances. The Kigali Amendment to the Montreal Protocol, for example, aims to phase down the production and consumption of HFCs worldwide.

My position is in favor of a ban on HCFCs and HFCs in the long run, in order to mitigate their negative environmental impact and address climate change concerns. The transition to safer alternatives and technologies that have lower or no impact on the ozone layer and contribute less to global warming is essential for the sustainable future of our planet.

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Other Questions
Mr. Twister produces a prepackaged assortment of screwdrivers ofvarious sizes and head styles and operates in a perfectlycompetitive market. Basically, all the firms in this competitivemarket have use the water that is available, the Prior Appropriation Doctrine is frequently applied. Essentially, Prior Appropriation states that whoever was using the water first owns the right to continued use of the water, provided it is put to some beneficial use. Is this a reasonable legal mandate to follow when awarding water rights? Or should whoever can put the water to the "best" use have priority over who was using the water first? How would you decide what the "best" use of water is? When answering these questions, consider the following scenario: A gold medal trout stream flows out of a mountain range near a growing western city into a valley. This supports a commercial guided sport fishing and tourism industry that directly or indirectly supports 22 businesses in the valley (fly shops, outfitters, guide services, lodges, restaurants, etc.) that collectively employ several hundred people. Obviously, this entire industry depends on having adequate streamflow to maintain the trout population. However, cattle-ranching is the oldest industry in the valley. Four ranches with a total beef production of 3000 head annually are located in the valley and are still owned and operated by the descendants of the first white settlers to occupy the valley. During normal years, stream flow is adequate to maintain the trout fishery and irrigate pasture for cattle. During dry years, however, the rancher's use of their water rights can reduce the stream to a trickle, threatening the continued existence of the trout fishery. Meanwhile, the growing city is looking for new sources of water to support continued growth and economic development, and wants to divert the stream into the urban water supply system. City planners argue that diverting the water to the city would benefit tens of thousands of people both directly and indirectly as a public water supply that would support new growth and economic development. The ranchers argue that they are guaranteed continued use of the stream under Prior Appropriation because their use of the water predates all others. Although the trout themselves have no legal right to the water they live in, the people who earn their livelihoods directly and indirectly from the sport fishing industry argue that enough water must remain in the stream to support the fishery and the people who benefit from it. What are the successes and failures of Prior Appropriation in this scenario? 7.What are they key differences between Cytotoxic T cells and HelperT cells? Explain how diversity of B and T cell receptors is generated,including the roles of Rag-1 and TdT. You are going to perform a Gram staining with two bacterial strains, Pseudomonas aeruginosa and Enterococcus faecium. Describe all necessary steps of Gram staining procedure including the biochemical principles behind each staining and de-staining steps. Discuss the expected colour and shape What is the definition of tissue? What is the definition of organ? Give an example? What is the definition of system? Give an example? Look at these slides under 4X, 10X and 40X. There are 4 different types of Human tissue: 1. Epithelial tissue Have different shapes: they are either columnar, cuboidal, or squamous (look at the models). Observe the slides of human skin, lung, kidney and intestine Look at the model of human skinWhat are the functions of epithelial tissue? 2. Nervous tissue are different types: but the ones that you should recognize are the neurons, which have: axons, dendrite, and cell body. Observe the slides and model of the neurons. What are the functions of nervous tissue? 3. Connective tissue are different than the rest of the tissues. They either have living cells or they are just a structure like the bone Observe the slide of the bone, you should be able to see: osteocytes, canaliculi. Haversian canals, Yolkmann's canal, and matrix. Look at the slide of skin and under epidermis and see the connective tissue (dermis layer). Can you find the adipocytes in the slide of skin? How many different tissue can you identify in the skin slide? Identify, epithelial tissue, adipocytes, connective tissue, epidermis and dermis.Look at the slide of blood and models of blood. The red blood cells are called erythrocytes. White blood cells are referred to as leukocytes. Identify neutrophils, basophils, cosinophils monocytes, and lymphocytes. Also look at the models of neutrophils, basophils, eosinophils and lymphocytes. What are the functions of connective tissue?Look at this slide under 10X and 40X. 4. Muscular tissue There are three different types of muscles:A. cardiac muscle: make sure you see striation and intercalated discs. The cardiac muscles are connected to each other by these discs. B. smooth muscles are NOT striated. They are our involuntary muscles. Where do you find smooth muscles in our body?C. Skeletal muscle which are striated. They are found in our voluntary muscles. One cell can have several nuclei. Observe the slide of the three different types of muscle. Be able to tell them apart.What are the functions of muscular tissue?Look at the models of skeletal tissue and smooth muscle tissue. There is not a model of cardiac muscle. Look at the slide of intestine and locate the smooth muscle? How many different types tissue can you identify in the slide of intestine? 28 16. A nurse is going to administer 2.5 mL of intramuscular pain medication to an adult client. The nurse notes that the previous injection was administered at the right ventrogluteal site. In which si 1) Which gene was duplicated in human that increased brain growth? 2) Most if not all primates have an insula a) True b) False 3) Which gene was mutated to increase cortex complexity? 2 kg of ice at 206 K is converted into steam at 416 K at constant atmospheric pressure. Note: Specific heat of liquid water = 4.18 kJ/kg.K Specific heat of water vapor & ice = 2.262 kJ/kg.K Latent heat of fusion of ice at freezing point (0C) = 334.7 kJ/kg Latent heat of vaporization of water at boiling point (100C) = 2230 kJ/kg . [0.5 mark] The entropy change of ice from 206 K to reach its freezing point is equal to ... kJ/K (1.0% accuracy & 5 s.f.) [0.5 mark] The entropy change when ice changes to water at freezing point is equal to ... kJ/K (11.0% accuracy & 5 s.f.) [0.5 mark] The entropy change of water from freezing point to boiling point is equal to ... kJ/K (+1.0% accuracy & 5 s.f.) [0.5 mark] The entropy change when water changes to steam at the boiling point is equal to ... kJ/K (11.0% accuracy & 5 s.f.) [0.5 mark] The entropy change of steam from boiling point to 416 K is equal to ... kJ/K (1.0% accuracy & 5 s.f.) [0.5 mark] The total entropy change when ice changes from 206 K to form steam at 416 K is equal to ... kJ/K (1.0% accuracy & 5 s.f.) [0.5 mark] The quantity of heat required for ice to change its temperature from 206 K to freezing point is equal to ... kJ (0.2% accuracy & 5 s.f.) [0.5 mark] The quantity of heat required for water to change its temperature from freezing point to boiling point is equal to ... kJ (+0.1% accuracy & 5 s.f.) [0.5 mark] The quantity of heat required for steam to change its temperature from boiling point to 416 K is equal to ... kJ (+0.2% accuracy & 5 s.f.) [0.5 mark] The total quantity of heat required to change ice at 206 K to convert into steam at 416 K is equal to ... kJ (1.0% accuracy & 5 s..) The formula CH3CH2CH2CH2CH2CH=CH2 represents:a. an alkaneb. an alkynec. an alcoholunsaturated hydrocarbone.a CFC Sam works at Glendale Hospital and earns $12 per hour for the first 40 hours and $18 per hour for every additional hour he works each week. Last week, Sam earned $570. To the nearest whole number, how many hours did he work? F. 32 G. 35 H. 38 J. 45 K. 48 - Alkaline phosphatase must NEVER be collected in which of the following tubes? A. Gray-topped tube B. Speckled-topped tube C. Red-topped tube D. Gold-topped tube For minor cuts you should stop the bleeding and then clean out the word finally protect the wind by? bill needs to grow the $3,970 he currently has to $15,880 in nine years. he has found an investment that offers quarterly compounding and an effective annual rate (ear) of 16%. what is the quarterly interest rate? (30 points) To practice thinking about different types of processes, draw the following diagrams for each of the different processes. Label your axes, the two states, and the path between them, just like we did in class. a. Isothermal process from 10 m to 5 m on a T-V diagram. b. Isochoric process from 400 K to 1000 K on a T-V diagram. c. Isobaric process from 400 K to 800 K on a P-T diagram. d. Isothermal process from 3,2 MPa to 0.2 MPa on a P-T diagram. e. Isobaric process from 1 m to 5 m on a P-V diagram. f. Isochoric process from 140 kPa to 650 kPa on a P-V diagram. when 85.0ml of nitric acid reacts with 150.0ml of 3.00m bariumhydroxide (excess)in a constant pressure calorimeter ,thetemperature of the mixture increases by 5.5 degrees celsius.calculate the mola how do people crowd source?A. By using a blog to get people to listen to youB. By getting a crowd to take political actionC. By asking a question on a social networking siteD. By sending surveys to every home in america The B-Vitamins in Red-Bull is what provides you with an IMMEDIATE boost of direct energy. Select one: O a. True. The ATP/CP energy system cannot generate ATP without B- Vitamins. O b. False. B-Vitamin Determine the weight in newton's of a woman whose weight in pounds is 130. Also, find her mass in slugs and in kilograms. Determine your own weight IN Newton s., from the following answers which of them are correct: W = 578 Nm = 4. 04 slugs and m = 58. 9 kg W = 578 Nm = 4. 04 slugs and m = 68.9 kg W= 578 N, m = 8. 04 slugs and m = 78. 9 kg W= 578 N, m = 8. 04 slugs and m = 48. 9 kg An insurance company is looking to insure a new line of4-Wheelers called the Grizzly. The Grizzly has a sales price of$20,000. If the 4-Wheeler was damaged in an accident, they wouldreplace the Gri