10. The population of India is 1.353 billion, and expected to grow at the rate of one percent
annually for the forseeable future. Assuming population continues to grow at the same percent
rate, how long until the population reaches 2 billion people? Give your answer to the nearest
year. (4 minutes)

Answer:

1 year

Step-by-step explanation:

1. Convert 10% into a z-score, using a calculator or whateva

2. Z = -1.281551 ( you can find this by doing the following equation: (x - mean) / (standard deviation)

3. Hence -1.281551 = (x - 4) / 2 or, x = 1.436898, ( rounded to the nearest year ) = 1 year

Answer:

The second question

Step-by-step explanation:

The orca starts at -25 meters. She goes up 25 meters.

up 25 = +25

-25+25=0

Answer:

Option 2

Step-by-step explanation:

The orca swims at the elevation of -25 meters. The orca swims up 25 meters higher than before.

-25 + 25 = 0

Answer:

1000

Step-by-step explanation:

=> [tex]\frac{1}{10^{-3}}[/tex]

According to the law of exponents, [tex]\frac{1}{a^{-m}} = a^{m}[/tex]

So, it becomes

=> [tex]10^{3}[/tex]

=> 1000

Answer:

[tex] P(X \geq 3)= 1- P(X<3)= 1-P(X \leq 2)= 1- [P(X=0) +P(X=1) +P(X=2)][/tex]

And we can find the individual probabilites using the probability mass function and we got:

[tex] P(X=0) = (15C0) (0.08)^{0} (1-0.08)^{15-0}=0.286 [/tex]

[tex] P(X=1) = (15C1) (0.08)^{1} (1-0.08)^{15-1}=0.373 [/tex]

[tex] P(X=2) = (15C2) (0.08)^{2} (1-0.08)^{15-2}=0.227 [/tex]

And replacing we got:

[tex] P(X\geq 3) = 1-[0.286+0.373+0.227 ]= 0.114[/tex]

Step-by-step explanation:

For this case we can assume that the variable of interest is "drivers were involved in a car accident last year" and for this case we can model this variable with this distribution:

[tex] X \sim Bin (n =15, p =0.08)[/tex]

And for this case we want to find this probability;

[tex] P(X \geq 3)[/tex]

and we can use the complement rule and we got:

[tex] P(X \geq 3)= 1- P(X<3)= 1-P(X \leq 2)= 1- [P(X=0) +P(X=1) +P(X=2)][/tex]

And we can find the individual probabilites using the probability mass function and we got:

[tex] P(X=0) = (15C0) (0.08)^{0} (1-0.08)^{15-0}=0.286 [/tex]

[tex] P(X=1) = (15C1) (0.08)^{1} (1-0.08)^{15-1}=0.373 [/tex]

[tex] P(X=2) = (15C2) (0.08)^{2} (1-0.08)^{15-2}=0.227 [/tex]

And replacing we got:

[tex] P(X\geq 3) = 1-[0.286+0.373+0.227 ]= 0.114[/tex]

Part A

g(x) = 3x+1

g(-4) = 3(-4)+1 ... every x replaced with -4

g(-4) = -12+1

g(-4) = -11

Plug this into the f(x) function

f(x) = x^2 - 2x

f( g(-4) ) = (g(-4))^2 - 2( g(-4) )

f( g(-4) ) = (-11)^2 - 2(-11)

f( g(-4) ) = 121 + 22

====================================================

Part B

Plug the g(x) function into the f(x) function

f(x) = x^2 - 2x

f( g(x) ) = ( g(x) )^2 - 2( g(x) ) ... replace every x with g(x)

f( g(x) ) = (3x+1)^2 - 2(3x+1)

f( g(x) ) = (9x^2+6x+1) + (-6x-2)

f( g(x) ) = 9x^2+6x+1-6x-2

Note that we can plug x = -4 into this result and we would get

f( g(x) ) = 9x^2-1

f( g(-4) ) = 9(-4)^2-1

f( g(-4) ) = 9(16)-1

f( g(-4) ) = 144-1

f( g(-4) ) = 143 which was the result from part A

====================================================

Part C

Replace g(x) with y. Then swap x and y. Afterward, solve for y to get the inverse.

[tex]g(x) = 3x+1\\\\y = 3x+1\\\\x = 3y+1\\\\3y+1 = x\\\\3y = x-1\\\\y = \frac{1}{3}(x-1)\\\\y = \frac{1}{3}x-\frac{1}{3}\\\\g^{-1}(x) = \frac{1}{3}x-\frac{1}{3}\\\\[/tex]

Answer:

after 9 weeks it would become 9*1+10=19 inches

and after w weeks it will be w*1+10 inches tall

hope this helps

Step-by-step explanation:

Answer:

a) 19 inches

b) 10+w inches

Step-by-step explanation:

The equation for this problem is 10 + w.  In the first part, w = 9, so the plant is 19 inches tall.

Answer:

  see attached

Step-by-step explanation:

The limit as x gets large is the ratio of the highest-degree terms. In most cases, the limit can be found by evaluating that ratio. Where an absolute value is involved, the absolute value of the highest-degree term is used.

If the ratio gives x to a positive power, the limit does not exist. If the ratio gives x to a negative power, the limit is zero.

The arrangement of functions according to the given condition

[tex]m(x)=\frac{4x^{2}-6 }{1-4x^{2} }[/tex]

[tex]h(x)=\frac{x^{3} -x^{2} +4}{1-3x^{2} }[/tex]

[tex]k(x)=\frac{5x+1000}{x^{2} }[/tex]

[tex]i(x)=\frac{x-1}{|1-4x| }[/tex]

[tex]g(x)=\frac{|4x-1|}{x-4}[/tex]

[tex]l(x)=\frac{5x^{2} -4}{x^{2} +1}[/tex]

[tex]f(x)=\frac{x^{2} -1000}{x-5}[/tex]

[tex]j(x)=\frac{x^{2}-1 }{|7x-1|}[/tex]

A limit is the value that  a function approaches as the input approaches some value.

According to the given question

[tex]l(x)=\frac{5x^{2} -4}{x^{2} +1}[/tex]

⇒[tex]\lim_{nx\to \infty} \frac{5x^{2} -1}{x^{2} +1}[/tex]

⇒[tex]\lim_{x \to \infty} \frac{x^{2} }{x^{2} } \frac{5-\frac{1}{x^{2} } }{1+\frac{1}{x^{2} } }[/tex]

= 5           ([tex]\frac{1}{x^{2} } = 0[/tex] ,as x tends to infinity  [tex]\frac{1}{x^{2} }[/tex] tends to 0)

[tex]i(x)=\frac{x-1}{|1-4x|}[/tex]

⇒[tex]\lim_{x \to \infty} \frac{x-1}{|1-4x|}[/tex] =  [tex]\lim_{x \to \infty} \frac{x}{x} \frac{1-\frac{1}{x} }{|\frac{-1}{4}+\frac{1}{x} | }[/tex]  =[tex]\frac{1}{\frac{1}{4} }[/tex] =[tex]\frac{1}{4}[/tex]

As x tends to infinity 1/x tends to 0, and |[tex]\frac{-1}{4}[/tex]| gives 1/4

[tex]f(x)= \frac{x^{2} -1000}{x--5}[/tex]

⇒[tex]\lim_{x \to \infty} \frac{x^{2} -1000}{x-5}[/tex]= [tex]\lim_{x \to \infty} \frac{x^{2} }{x} \frac{1-\frac{1000}{x^{2} } }{1-\frac{5}{x} }[/tex]= [tex]\lim_{x \to \infty} x\frac{1-\frac{1000}{x^{2} } }{1-\frac{5}{x} }[/tex] ⇒ limit doesn't exist.

[tex]m(x)=\frac{4x^{2}-6 }{1-4x^{2} }[/tex]

⇒[tex]\lim_{x\to \infty} \frac{4x^{2} -6}{1-4x^{2} }[/tex]=[tex]\lim_{x\to \infty} \frac{x^{2} }{x^{2} } \frac{4-\frac{6}{x^{2} } }{\frac{1}{x^{2} } -4}[/tex]  [tex]= \lim_{n \to \infty} \frac{4}{-4}[/tex] = -1

As x tends to infinity [tex]\frac{1}{x^{2} }[/tex] tends to 0.

[tex]g(x)=\frac{|4x-1|}{x-4}[/tex]

⇒[tex]\lim_{x\to \infty} \frac{|4x-1|}{x-4}[/tex] = [tex]\lim_{x \to \infty} \frac{|x|}{x} \frac{4-\frac{1}{x} }{1 -\frac{4}{x} } }[/tex] = 4

as x tends to infinity 1/x tends to 0

and |x|=x ⇒[tex]\frac{|x|}{x}=1[/tex]

[tex]h(x)=\frac{x^{3}-x^{2} +4 }{1-3x^{3} }[/tex][tex]\lim_{x \to \infty} \frac{x^{3} -x^{2} +4}{1-3x^{3} }[/tex][tex]= \lim_{x \to \infty} \frac{x^{3} }{x^{3} } \frac{1-\frac{1}{x}+\frac{4}{x^{3} } }{\frac{1}{x^{3} -3} }[/tex]  = [tex]\frac{1}{-3}[/tex] =[tex]-\frac{1}{3}[/tex]

[tex]k(x)=\frac{5x+1000}{x^{2} }[/tex]

[tex]\lim_{x \to \infty} \frac{5x+1000}{x^{2} }[/tex] = [tex]\lim_{x \to \infty} \frac{x}{x} \frac{5+\frac{1000}{x} }{x}[/tex] =0

As x tends to infinity 1/x tends to 0

[tex]j(x)= \frac{x^{2}-1 }{|7x-1|}[/tex]

[tex]\lim_{x \to \infty} \frac{x^{2}-1 }{|7x-1|}[/tex] = [tex]\lim_{x \to \infty} \frac{x}{|x|}\frac{x-\frac{1}{x} }{|7-\frac{1}{x}| }[/tex]  = [tex]\lim_{x \to \infty} 7x[/tex] = limit doesn't exist.

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Answer:

(-2 ,3)

Step-by-step explanation:

Step 1: Rewrite first equation

x = 4 - 2y

-2x + y = 7

Step 2: Substitution

-2(4 - 2y) + y = 7

Step 3: Solve y

-8 + 4y + y = 7

-8 + 5y = 7

5y = 15

y = 3

Step 3: Plug in y to find x

x + 2(3) = 4

x + 6 = 4

x = -2

Answer:

y = 2x + 3

Step-by-step explanation:

Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Slope-Intercept Form: y = mx + b

Step 1: Find slope m

m = (-1 - 3)/(-2 - 0)

m = -4/-2

m = 2

y = 2x + b

Step 2: Rewrite equation

y = 2x + 3

*You are given y-intercept (0, 3), so simply add it to your equation.

Answer: the answer is d sin30degrees equal 5/x because sin is opposite over hyponuese

Answer:

50%

Step-by-step explanation:

Cost of 3 bananas= Rs. 5 ⇒ cost of 1 banana= Rs. 5/3

Selling price of 2 bananas= Rs. 5 ⇒ selling price of 1 banana= Rs. 5/2

Gain= Rs. (5/2- 5/3)= Rs. (15/6- 10/6)= Rs. 5/6

Gain %= 5/6÷5/3 × 100%= 50%

Answer:

c = 5.5

Step-by-step explanation:

We can find the slope of the line using the given points (5,5) and (-3,1) using rise over run:

-4/-8 = 1/2

Now, we can plug in the slope and a point into the equation y = mx + b to find b:

5 = 1/2(5) + b

5 = 2.5 + b

2.5 = b

Then, we can plug in 6 in the point (6,c) to find c:

y = (1/2)(6) + 2.5

y = 3 + 2.5

y = 5.5

c = 5.5

Answer:

c = 5.5

Step-by-step explanation:

Find the slope with two points

m = (y2-y1)/(x2-x1)

m = (1-5)/(-3-5)

   = -4/-8

   = 1/2

If all the points are on the same line, then they have the same slope

m = (y2-y1)/(x2-x1)

Using the first and third points

1/2 = (c-5)/(6-5)

1/2 =  (c-5)/1

1/2 = c-5

Add 5 to each side

5+1/2 = c

5.5 =c

Answer:

Therefore the x - coordinate of the minimum is x = -8

Step-by-step explanation:

[tex]y = 2x^2 + 32x + 56 = 2(x^2 + 16x ) + 56 = 2(x^2 + 16x +64 - 64) + 56 \\= 2(x^2 + 16x +64) - 128 + 56 = 2(x+8)^2 - 72[/tex]

Therefore the x - coordinate of the minimum is x = -8

Answer:

13 Compute using the 2 right angles, we know that m<FIG=90* and

Answer:  24

Step-by-step explanation:

Let's find one solution:

3x² + 7x + c = 0

a=3 b=7  c=c

First, let's find c so that it has REAL ROOTS.

⇒ Discriminant (b² - 4ac) ≥ 0

                         7² - 4(3)c ≥ 0

                         49 - 12c ≥ 0

                               -12c  ≥ -49

                                [tex]c\leq\dfrac{-49}{-12}\quad \rightarrow c\leq \dfrac{49}{12}[/tex]      

Since c must be a positive integer, 1 ≤ c ≤ 4

Example: c = 4

3x² + 7x + 4 = 0

(3x + 4)(x + 1) = 0

x = -4/3, x = -1         Real Roots!

You need to use Quadratic Formula to solve for c = {1, 2, 3}

Valid solutions for c are: {1, 2, 3, 4)

Their product is: 1 x 2 x 3 x 4 = 24

Answer:

$3x^2+7x+c=0$

comparing above equation with ax²+bx+c

a=3

b=7

c=1

using quadratic equation formula

[tex]x = \frac{ - b + - \sqrt{b {}^{2} - 4ac} }{ 2a} [/tex]

x=(-7+-√(7²-4×3×1))/(2×3)

x=(-7+-√13)/6

taking positive

x=(-7+√13)/6=

taking negative

x=(-7-√13)/6=

Answer:

A discrete data set because there are a finite number of possible values.

Step-by-step explanation:

We are given the following data set below;

When a car is randomly selected, it is found to have 8 windows.

Firstly, as we know that the discrete data is that data that have countable or finite values, and also we can observe at a point value.

On the other hand, the continuous data is that data in which there is a range of values and we can't count or observe each and every value.

So, in our question; as we can observe that we can count all the windows and it is also a finite number which means that the given data set is a discrete data set because there are a finite number of possible values.

Answer:

Hey!

Your answer is YES!

AKA the Last Option on your screen!

Step-by-step explanation:

It is this because...

They both have the angles 105 in it...

And looking at the other angle on the smaller one (25)

50 + 25 = 75 ... 180 - 75 = 105

WE HAVE 105 as an angle on the larger triangle...which makes them SIMILAR but congruent Angles!

It cant be the "corresponding sides" as we do not have the notations (lines intersecting the sides) that let us know that the lines are the same.

Hope this helps!

Answer:

452.4

Step-by-step equation:

surface area of a sphere formula= 4πr²

plug 6 in for r

4π(6)² =452.389 rounded  to 452.4

Answer:

This question is about:

sin(A/2) and cos(A/2)

First, how we know when we need to use the positive or negative signs?

Ok, this part is kinda intuitive:

First, you need to know the negative/positve regions for the sine and cosine function.

Cos(x) is positive between 270 and 90, and negative between 90 and 270.

sin(x) is positive between  0 and 180, and negative between 180 and 360.

Then we need to see at the half-angle and see in which region it lies.

If the half-angle is larger than 360°, then you subtract 360° enough times such that the angle lies in the range between (0° and 360°)

and: Tan(A/2) = Sin(A/2)/Cos(A/2)

So using that you can infer the sign of the Tan(A/2)

Now, why these relationships use the two signs?

Well... this is because of the square root in the construction of the relationships.

This happens because:

(-√x)*(-√x) = (-1)*(-1)*(√x*√x) = (√x*√x)

For any value of x.

so both -√x and √x are possible solutions of these type of equations, but for the periodic nature of the sine and cosine functions, we can only select one of them.

So we should include the two possible signs, and we select the correct one based on the reasoning above.

Answer:

104.93 in

Step-by-step explanation:

When we draw out a picture of our triangle, we should see that we need to use sin∅ to solve:

sin23° = 41/x

xsin23° = 41

x = 41/sin23°

x = 104.931

Answer:

A 95% confidence interval for the population mean score for all bowlers in this league is [86.64, 94.48].

Step-by-step explanation:

Since in the question only 9 random scores are given, so I am performing the calculation using 9 random scores.

We are given that the scores of bowlers in particular league follow a normal distribution such that the standard deviation of the population is 6.

The accompanying data set of 9 random scores in ascending order is given as; 75, 86, 86, 88, 89, 93, 93, 98, 107

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\bar X[/tex] = sample mean score = [tex]\frac{\sum X}{n}[/tex] = [tex]\frac{815}{9}[/tex] = 90.56

            [tex]\sigma[/tex] = population standard deviation = 6

            n = sample of random scores = 9

            [tex]\mu[/tex] = population mean score for all bowlers

Here for constructing a 95% confidence interval we have used a One-sample z-test statistics because we know about population standard deviation.

So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < 1.96) = 0.95

P( [tex]-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\bar X-\mu}[/tex] < [tex]1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95

P( [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95

95% confidence interval for [tex]\mu[/tex] =  [ [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] , [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ]

                                          = [ [tex]90.56-1.96 \times {\frac{6}{\sqrt{9} } }[/tex] , [tex]90.56+1.96 \times {\frac{6}{\sqrt{9} } }[/tex] ]

                                          = [86.64 , 94.48]

Therefore, a 95% confidence interval for the population mean score for all bowlers in this league is [86.64, 94.48].

Answer:

2. Precise but not accurate

Step-by-step explanation:

In a high precision, low accuracy case study, the measurements are all close to each other (high agreement between the measurements) but not near/or close to the center of the distribution (how close a measurement is to the correct value for that measurement)

Answer:

aaaaha pues

Step-by-step explanation:

Answer:

what happened

Step-by-step explanation:

Answer:

0.3174

Step-by-step explanation:

Z-score:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the area under the normal curve to the left of Z. Subtracting 1 by the pvalue, we find the area under the normal curve to the right of Z.

Left of z = -1

z = -1 has a pvalue of 0.1587

So the area under the standard normal curve to the left of z = -1 is 0.1587

Right of z = 1

z = 1 has a pvalue of 0.8413

1 - 0.8413 = 0.1587

So the area under the standard normal curve to the right of z = 1 is 0.1587

Left of z = -1 or right of z = 1

0.1587 + 0.1587 = 0.3174

The area is 0.3174

The probability of picking greens on both occasions will be 5/18.

The probability of picking greens cards will be:

= 5/9 × 4/8

= 5/18

The probability of picking at least one green will be:

= 1 - P(both aren't green)

= 1 - (4/9 × 3/8)

= 1 - 1/6.

= 5/6

From the tree diagram, the probability as a fraction of P(G2 | G1) will be:

= 4/8 = 1/2

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Answer:

D. Two-sample chi-square

Step-by-step explanation:

A chi-square test is a test used to compare the data that is observed, from the data that is expected.

In a two-sample chi-square test the observed data should be similar to the expected data if the two data samples are from the same distribution.

The hypotheses of the two-sample chi-square test is given as:

H0: The two samples come from a common distribution.

Ha: The two samples do not come from a common distribution

Therefore, in this case, the best statistical test to utilize is the two-sample chi-square test.

Answer:

z=0

x= -5

y=4

Step-by-step explanation:

Check the attachment please

Hope this helps :)

Step-by-step explanation:

x + 2y − z = 3

x + y − 2z = -1

There are three variables but only two equations, so this system of equations is undefined.  We cannot solve for the variables, but we can eliminate one of them and reduce this to a single equation.

Double the first equation:

2x + 4y − 2z = 6

Subtract the second equation.

(2x + 4y − 2z) − (x + y − 2z) = (6) − (-1)

2x + 4y − 2z − x − y + 2z = 7

x + 3y = 7

Answer:

b. The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.

Step-by-step explanation:

A square matrix is said to be invertible if the product of the matrix and its inverse result into an identity matrix.

3  0 -4

2  0  6

-3 0  8

Since the second column elements are all zero, the determinant of the matrix is zero ad this implies that the inverse of the matrix does not exist(i.e it is not invertible )

A square matrix is said to be invertible if it has an inverse.

The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.

The matrix is given as:

[tex]\left[\begin{array}{ccc}3&0&-4\\2&0&6\\-3&0&8\end{array}\right][/tex]

Calculate the determinant

The determinant of the matrix calculate as:

[tex]|A| = 3 \times(0 \times 8- 6 \times 0) - 0(2 \times 8 - 6 \times -3) -4(2 \times 0 - 0 \times -3)[/tex]

[tex]|A| = 3 \times(0) - 0(34) -4(0)[/tex]

[tex]|A| = 0 - 0 -0[/tex]

[tex]|A| = 0[/tex]

When a matrix has its determinant to be 0, then

Hence, the correct option is (b)

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Answer:

16

Step-by-step explanation:

X^2 + 8x= 11

Take the coefficient of x

8

Divide by 2

8/2 =4

Square it

4^2 = 16

Add 16 to each side

Answer:

The length of the third side of fence is 11.4 m

Step-by-step explanation:

Solution:-

- We are to mow a triangular piece of land. We are given the description of motion and the orientation of land-mower while fencing.

- From one corner of the triangular land, the land-mower travels H1 = 5.7 m at θ1 = 0.3 radians north of east. We will use trigonometric ratios to determine the amount traveled ( B1 ) in the east direction.

                                  [tex]cos ( theta_1 ) = \frac{B_1}{H_1}[/tex]

Where,

                          B1: Is the base length of the right angle triangle

                          H1: Hypotenuse of the right angle triangle

Therefore,

                                [tex]B_1 = H_1*cos ( theta_1 )\\\\B_1 = 5.7*cos ( 0.3 )\\\\B_1 = 5.44541 m[/tex]

- Similarly, from the other corner of the triangular land. The land-mower moves a lateral distance of H2 = 9m and directed θ2 = 0.9 radians north of west. We will use trigonometric ratios to determine the amount traveled ( B2 ) in the west direction.

                                [tex]cos ( theta_2 ) = \frac{B_2}{H_2} \\[/tex]

Where,

                          B2: Is the base length of the right angle triangle

                          H2: Hypotenuse of the right angle triangle

Therefore,

                                 [tex]B_2 = H_2*cos ( theta_2 )\\\\B_2 = 9*cos(0.9)\\\\B_2 = 5.59448 m[/tex]

- The total length of the third side of the fence would be the sum of bases of the two right angles formed by the land-mower motion at each corner.

                                [tex]L = B_1 + B_2\\\\L = 5.44541 + 5.59448\\\\L = 11.4 m[/tex]