10. Question
Which statement is true about computer security?

The protocol is indeed a set of rules and principles for data transmission and the further discussion can be defined as follows:

Therefore, the answer is Option "b,d,f, and g".

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Answer and Explanation:

Using Javascript:

We could just use ES6 syntax and quickly get our result with no long coding. ECMA script 2015, the sixth version of javascript programming language has an array method that returns the unique values of an array in a new array.

var allValues = [ 1,3,4,1,3,9 ];

let uniqueValues = [...new Set(allValues)];

console.log(uniqueValues);

This will output only the unique values 1,3,4,9

Answer:

The function is as follows:

def concList(aList):

   retList = ""

   for i in aList:

       if(str(i).isdigit()):

           retList+=str(i)

       else:

           retList = "Not digits"

           break;

   return retList

Explanation:

This defines the function

def concList(aList):

This initializes the return string to an empty string

   retList = ""

This iterates through aList

   for i in aList:

This converts each element of the list to an empty list and checks if the string is digit

       if(str(i).isdigit()):

If yes, the element is concatenated

           retList+=str(i)

If otherwise

       else:

The return string is set to "No digits"

           retList = "Not digits"

And the loop is exited

           break;

This returns the return string

   return retList

Answer:

hope it is helpful to you

stay safe, happy and healthy

Formatted the text in a document can draw the reader's attention to specific parts of a document and it also emphasize important information. In the word file, a person may have several options for adjusting the text, including font, size, and color.

Document formatting can be referred to as the way in which a document is laid out on the page, it is the way in which it looks and is visually organized and it addresses all the things such as font selection, font size and presentation like bold or italics font, spacing, margins, alignment, columns, indentation, and lists.

Document formatting is the mechanics of how the words appear on the page or the document. A well formatting document is consistent, and it is correct in terms of meeting any stated requirements, and easy to be read by anyone.

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Answer:

Here the given problem is modeled as a Graph problem.

Explanation:

Input:-  n, k and the function d(pi,pj) which outputs an integer between 1 and n2

Algorithm:-We model each student as a node. So, there would be n nodes. We make a foothold between two nodes u and v (where u and v denote the scholars pu and pv respectively) iff d(pu,pv) > k. Now, Let's call the graph G(V, E) where V is that the vertex set of the graph ( total vertices = n which is that the number of students), and E is that the edge set of the graph ( where two nodes have edges between them if and only the drama between them is bigger than k).

We now need to partition the nodes of the graph into two sets S1 and S2 such each node belongs to precisely one set and there's no edge between the nodes within the same set (if there's a foothold between any two nodes within the same set then meaning that the drama between them exceeds k which isn't allowed). S1 and S2 correspond to the partition of scholars into two buses.

The above formulation is akin to finding out if the graph G(V,E) is a bipartite graph. If the Graph G(V, E) is bipartite then we have a partition of the students into sets such that the total drama <= k else such a partition doesn't exist.

Now, finding whether a graph is bipartite or not is often found using BFS (Breadth First algorithm) in O(V+E) time. Since V = n and E = O(n2) , the worst-case time complexity of the BFS algorithm is O(n2). The pseudo-code is given as

PseudoCode:

// Input = n,k and a function d(pi,pj)

// Edges of a graph are represented as an adjacency list

1. Make V as a vertex set of n nodes.

2. for each vertex  u ∈ V

[tex]\rightarrow[/tex]  for each vertex v ∈ V

[tex]\rightarrow\rightarrow[/tex]if( d(pu, pj) > k )

[tex]\rightarrow\rightarrow\rightarrow[/tex] add vertex u to Adj[v]   // Adj[v] represents adjacency list of v

[tex]\rightarrow\rightarrow\rightarrow[/tex] add vertex v to Adj[u] // Adj[u] represents adjacency list of u

3.  bool visited[n] // visited[i] = true if the vertex i has been visited during BFS else false

4. for each vertex u ∈ V

[tex]\rightarrow[/tex]visited[u] = false

5. color[n] // color[i] is binary number used for 2-coloring the graph  

6. for each vertex u ∈ V  

[tex]\rightarrow[/tex] if ( visited[u] == false)

[tex]\rightarrow\rightarrow[/tex] color[u] = 0;

[tex]\rightarrow\rightarrow[/tex] isbipartite = BFS(G,u,color,visited)  // if the vertices reachable from u form a bipartite graph, it returns true

[tex]\rightarrow\rightarrow[/tex] if (isbipartite == false)

[tex]\rightarrow\rightarrow\rightarrow[/tex] print " No solution exists "

[tex]\rightarrow\rightarrow\rightarrow[/tex] exit(0)

7.  for each vertex u ∈V

[tex]\rightarrow[/tex] if (color[u] == 0 )

[tex]\rightarrow\rightarrow[/tex] print " Student u is assigned Bus 1"

[tex]\rightarrow[/tex]else

[tex]\rightarrow\rightarrow[/tex] print " Student v is assigned Bus 2"

BFS(G,s,color,visited)  

1. color[s] = 0

2. visited[s] = true

3. Q = Ф // Q is a priority Queue

4. Q.push(s)

5. while Q != Ф {

[tex]\rightarrow[/tex] u = Q.pop()

[tex]\rightarrow[/tex] for each vertex v ∈ Adj[u]

[tex]\rightarrow\rightarrow[/tex] if (visited[v] == false)

[tex]\rightarrow\rightarrow\rightarrow[/tex] color[v] = (color[u] + 1) % 2

[tex]\rightarrow\rightarrow\rightarrow[/tex] visited[v] = true

[tex]\rightarrow\rightarrow\rightarrow[/tex] Q.push(v)

[tex]\rightarrow\rightarrow[/tex] else

[tex]\rightarrow\rightarrow\rightarrow[/tex] if (color[u] == color[v])

[tex]\rightarrow\rightarrow\rightarrow\rightarrow[/tex] return false // vertex u and v had been assigned the same color so the graph is not bipartite

}

6. return true

Answer:

Explanation:

The following code is written in Java. It creates the Bug class with the position and direction variables. Then it creates a constructor, move method, turn method, and getPosition method. Finally, a bug object called bugsy is created in the main method, and we move it once to the right, then again to the right, and then we turn it and move it 5 times to the left, printing out the position when it is done moving. Output can be seen in the attached picture below.

class Brainly {

   public static void main(String[] args) {

       Bug bugsy = new Bug(10);

       bugsy.move();

       System.out.println("Current bug position: " + bugsy.getPosition());

       bugsy.move();

       System.out.println("Current bug position: " + bugsy.getPosition());

       bugsy.turn();

       bugsy.move();

       bugsy.move();

       bugsy.move();

       bugsy.move();

       bugsy.move();

       System.out.println("Current bug position: " + bugsy.getPosition());

   }

}

class Bug {

   char direction = 'r';

   int position = 0;

   public Bug(int initialPosition) {

       this.position = initialPosition;

   }

   public void turn() {

       if (this.direction == 'r') {

           this.direction = 'l';

       } else {

           this.direction = 'r';

       }

   }

   public void move() {

       if (this.direction == 'r') {

           this.position += 1;

       } else {

           this.position -= 1;

       }

   }

   public int getPosition() {

       return this.position;

   }

}

In this exercise we want to use computer and Java knowledge to write the code correctly, so it is necessary to add the following to the informed code:

Output can be seen in the attached picture below

The following secret language system exist composed fashionable Java. It develop in mind or physically the bug class accompanying the position and direction variables. Then it develop in mind or physically a builder, move arrangement, turn means, and catch position procedure.

Finally, a bug object named bugsy happen develop in mind or physically usually pattern, and we fast once to the right, therefore another time to the right, and before we turn it and speedy 5 period to the abandoned, a process of reproduction out the position when it exist thoroughly cooked mobile. We have that:

class Brainly {

  public static void main(String[] args) {

      Bug bugsy = new Bug(10);

      bugsy.move();

      System.out.println("Current bug position: " + bugsy.getPosition());

      bugsy.move();

      System.out.println("Current bug position: " + bugsy.getPosition());

      bugsy.turn();

      bugsy.move();

      bugsy.move();

      bugsy.move();

      bugsy.move();

      bugsy.move();

      System.out.println("Current bug position: " + bugsy.getPosition());

  }

}

class Bug {

  char direction = 'r';

  int position = 0;

  public Bug(int initialPosition) {

      this.position = initialPosition;

  }

  public void turn() {

      if (this.direction == 'r') {

          this.direction = 'l';

      } else {

          this.direction = 'r';

      }

  }

  public void move() {

      if (this.direction == 'r') {

          this.position += 1;

      } else {

          this.position -= 1;

      }

  }

  public int getPosition() {

      return this.position;

  }

}

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Answer:

B

Explanation:

Adding Web pages helps Web designers Organize information. The correct option is B)

A website should be made such that anyone using it can quickly find what they're searching for and understand what each feature on the page performs without having to ask for assistance or go through a lengthy tutorial.

When users access the website for the first time, they should be able to do so right away and do so as frequently as they have in the past. Additionally, the website needs to be responsively constructed. Web design is crucial because it affects how potential customers see your company.

The first impression you provide them will determine whether they stay on your page to learn more about your company, or whether they click on a competitor's page instead.

Therefore, the correct option is B) Organize information.

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Answer:

Different types of biometric method used in AI are

Explanation:

Face Recognition.

Speaker (Voice) Recognition.

Fingerprint Recognition.

Behavioral Biometrics.

Crossmatch – 'Composite' Biometric Authentication.

Tygart Technology – Facial Recognition from Videos.

Onfido – Facial Biometrics.

EyeLock – Iris Recognition.

Answer:

(b) (int)(Math.random() * 101)

Explanation:

Given

[tex]min = 0[/tex] --- minimum

[tex]max =100[/tex] --- maximum

Required

Java expression to generate random integer between the above interval

The syntax to do this is:

(int)(Math.random((max - min) + 1) + min)

Substitute the values of max and min

(int)(Math.random((100 - 0) + 1) + 0)

Simplify the expression

(int)(Math.random(100 + 1) + 0)

(int)(Math.random(101) + 0)

(int)(Math.random(101))

Hence, the right option is:

(b) (int)(Math.random() * 101)

Answer:

Procreate

Explanation:

Answer:

Quick Analysis toolbar

Explanation:

it appears with the options formatting, chart, total, table, sparklines

Answer:

The program in Python is as follows:

num1 = int(input())

num2 = int(input())

if num2 < num1:

   print("Second integer can't be less than the first.")

else:

   for i in range(num1,num2+1,5):

       print(i,end=" ")

Explanation:

This gets the first integer from the user

num1 = int(input())

This gets the second integer from the user

num2 = int(input())

If the second is less than the first, the following prompt is printed

if num2 < num1:

   print("Second integer can't be less than the first.")

If otherwise, the number between the intervals is printed with an increment of 5

else:

   for i in range(num1,num2+1,5):

       print(i,end=" ")

Answer:

Windows 10 lets you quickly check your network connection status. And if you're having trouble with your connection, you can run the Network troubleshooter to try and fix it. Select the Start button, then select Settings > Network & Internet > Status.

Answer: i'd make a guess, not answer probably, but A1 +A2?

Explanation: it has plus sign?

Answer: SUM(A1:A3)

Explanation:

Answer:

SEO stands for “search engine optimization.” In simple terms, it means the process of improving your site to increase its visibility for relevant searches.

SEM, or search engine marketing, is the act of using paid strategies to increase search visibility.

Answer:B. File, New, Brochures

Explanation: Just took the test

Answer:

An effective Scrum Master is a team-based servant leader who: Exhibits Lean-Agile leadership – Exhibits the behaviors of a Lean-Agile Leader with a Lean-Agile Mindset. Helps the team embrace SAFe Core Values, adopt and apply SAFe Principles, implement SAFe practices.

Explanation:

Explanation:

Microsoft Excel Help Center

GCF learner free

Excel Central

Chandoo

Excel Hero

Contextures

Coursera

#Carryonlearning

Answer:

if-then-else

switch (expr) { case value: statements ;}

Explanation:

Required

Which do not represent loop

Literally, looping means repeating an action or sequence of actions as long as a given condition is true.

For options (a) to (d), we have:

(a): if-then-else:

if statements are used to test conditions; depending on the truth or falsity of the condition, only one block of code can be executed at once.

In summary, if statements are not loops

(b): switch statements

This is an alternate to if statements and can be used in place of if statements.

Hence, switch statements are not loops

(c) and (d): for and while:

The above represent loops, because they both involve repetition of operations until the condition is no longer satisfied.

Answer:

True

Explanation:

The Huawei developed Nanomemory Card (used for phones) can also be used for computers. A nanomemory card is just like an SD card, it provides you with extra storage space. Computer memory is also measured in nanomemory, so it can be used. Therefore, the answer to the question is True.

Best of Luck!

Answer:

The programs are written in python:

Version 1:

n = int(input("Numbers: "))

for i in range(n):

   num = int(input("Input integer: "))

   mylist = []

   while num>0:

       mylist.append(num%10)

       num= int(num/10)

   mylist.reverse()

   for i in mylist:

       print(i,end=" ")

   print()

Version 2:

num = int(input("Input integer: "))

while num > 0:

   mylist = []

   while num>0:

       mylist.append(num%10)

       num= int(num/10)

   mylist.reverse()

   for i in mylist:

       print(i,end=" ")

   print()

   num = int(input("Input integer: "))

Explanation:

Version 1:

This gets the number of inputs from the user, n

n = int(input("Numbers: "))

This iterates through n

for i in range(n):

For each iteration, this gets the integer input from the user, num

   num = int(input("Input integer: "))

This initializes a list

   mylist = []

This loop is repeated until num is 0

   while num>0:

This gets the individual digit and appends it to a list

       mylist.append(num%10)

This gets the other numbers

       num= int(num/10)

This reverses the list

   mylist.reverse()

This prints the individual digits from the list

   for i in mylist:

       print(i,end=" ")

Print a new line for the next integer input

   print()

Version 2:

The difference in both versions are the following lines

This gets the integer input from the user

num = int(input("Input integer: "))

This loop enables the user to input as many numbers as possible. But once the user inputs 0, the program will stop

while num > 0:

Unlike version 1 where the number of inputs in known at the initial stage of the program

Answer:

The program in Python is as follows:

mnths = ["january","february","march","april","may","june","july","august","september","october","november","december"]

days = int(input("Day: "))

month = input("Month: ")

if not(month.lower() in mnths):

   print("Invalid")

else:

   month_index = mnths.index(month.lower())

   if month_index == 0:

       if days<1 or days>31:            print("Invalid")

       else:            print("Winter")

   elif month_index == 1:

       if days<1 or days>28:            print("Invalid")

       else:            print("Winter")

   elif month_index == 2:

       if days<1 or days>31:            print("Invalid")

       elif days<= 19:            print("Winter")

       else:            print("Spring")

   elif month_index == 3:

       if days<1 or days>30:            print("Invalid")

       else:            print("Spring")

   elif month_index == 4:

       if days<1 or days>31:            print("Invalid")

       else:            print("Spring")

   elif month_index == 5:

       if days<1 or days>30:            print("Invalid")

       elif days<= 20:            print("Spring")

       else:            print("Summer")

   elif month_index == 6:

       if days<1 or days>31:            print("Invalid")

       else:            print("Summer")

   elif month_index == 7:

       if days<1 or days>31:            print("Invalid")

       else:            print("Summer")

   elif month_index == 8:

       if days<1 or days>31:            print("Invalid")

       elif days<= 21:            print("Summer")

       else:            print("Autumn")

   elif month_index == 9:

       if days<1 or days>31:            print("Invalid")

       else:            print("Autumn")

   elif month_index == 10:

       if days<1 or days>30:            print("Invalid")

       else:            print("Autumn")

   elif month_index == 11:

       if days<1 or days>31:            print("Invalid")

       elif days<21:            print("Autumn")

       else:            print("Winter")

Explanation:

See attachment for complete source file, where comments are used to explain difficult lines

Answer:

Option D

Explanation:

An Entitlement is an option to utilize, get to or devour an application or asset, commonly for a charge. For instance, a client may buy an Entitlement to utilize an application in ceaselessness (a "unending" permit), or they may buy a period restricted option to utilize an application, (for example, a one-year membership permit).

Answer:

La adopción del pensamiento computacional en los últimos tiempos en la educación empresarial es la nueva tendencia.

Explanation:

La adopción del pensamiento computacional en los últimos tiempos en la educación empresarial es la nueva tendencia. Esto implica el aprendizaje basado en proyectos para crear valor empresarial. Para mejorar los resultados del aprendizaje, se utiliza el modelo de negocio junto con las TIC para crear un marco de innovación.

Answer:

video - includes file formats AVI and WMV

graphics - includes maps and photographs  

animation - includes a rapid display of a sequence of static images

audio - includes file formats WAV and MPEG 3

Explanation:

The given elements of a web page have correctly been matched with their descriptions in order to define them adequately. The element that characterizes video data involves a common format of files like AVI(in Microsoft) and WMV(windows media video). While Graphics are described as the pictorial representation and manipulation of data and hence, it involves pictures, along with, photos. Animation involves the process of giving inanimate objects or drawings a motion form and hence, it includes a series of static images to show the movement. While audio lays focus on audible sound with formats like MPEG 3(audio file).

Answer:

video - includes file formats AVI and WMV

graphics - includes maps and photographs  

animation - includes a rapid display of a sequence of static images

audio - includes file formats WAV and MPEG 3

Explanation

Edmentum.

Answer: Reverse DNS zone

Explo: a reverse DNS zone needs a PTR record since it is in charge of resolving the IP address to a domain or a hostname.

Explanation:

its a laptop ☺️. . . . . .. . .

Answer:

High level programming language is a language that simplifies computer programming.

Examples are python, visual basic,java,JavaScript .It is a language with abstraction from details of the computer.

Answer:

To make the value 10 also part of the loop, the while statement must be "while x<=10" otherwise 10 is excluded. To have only even numbers, x should be increased by 2, not 1, i.e.: "x = x + 2".