When the C4 key on a piano keyboard is pressed, a string inside the piano is struck by a hammer and begins vibrating back and forth at approximately 260 cycles per second.
a. What is the frequency in Hertz of the sound wave?
b. What is the wavelength of the wave?
Answer:
Frequency = 260 Hz and wavelength = 1.31 m
Explanation:
Given that,
A hammer begins vibrating back and forth at approximately 260 cycles per second.
(a) The frequency of an object is the number of vibrations per unit time. The frequency of the sound wave is 260 Hz.
(b) The speed of sound in air is 343 m/s. So,
[tex]v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343}{260}\\\\\lambda=1.31\ m[/tex]
Hence, this is the required solution.
Select the correct answer from each drop-down menu.
Photosynthesis is a process in which plants prepare food using carbon dioxide, chlorophyll, and water in the presence of sunlight.
During photosynthesis,(blank)
energy is transformed into(blank)
1.Chemical,electrical,kinetic, Solar ?
2.Chemical, Electrical, Kinetic, Solar
Answer:
During photosynthesis solar energy is converted into chemical energy
Explanation:
During photosynthesis solar energy is converted into chemical energy in the form of energy rich bond of ATP molecule.
ATP (Adenosine triphosphate) and ADP (Adenosine diphosphate) molecules are termed currency of energy. ADP molecule is converted into ATP molecules, whenever energy is available in certain exothermic reactions of metabolism.
ATP molecules are store- house of energy. ATP molecule is broken down into ADP molecule in presence of enzyme ATPase, releasing energy whenever energy is required.
The synthesis of ATP molecules, utilizing solar energy during photosynthesis, is termed photo-phosphorylation.
These ATP molecules produced during light reaction of photosynthesis are utilized in dark reaction of photosynthesis (Calvin cycle).
ATP molecules synthesized during photo-phosphorylation may also be used in other metabolic reactions.
Photo-phosphorylation is of 2 types, i.e. Cyclic and Non-cyclic photo-phosphorylation.
Chlorophyll molecules entrap solar energy . There are 2 types of photo-systems in chlorophyll. These are photo-system -I and photo-system-II .
The electrons of chlorophyll molecule of photo-system I get excited which pass through series of electron carriers in electron transport system arranged in the order of decreasing energy level.
During the passage of electrons from carriers of higher energy level to the carriers of lower energy level, the energy is lost which is utilized for converting ADP molecule into ATP molecule.
Photo-system I is concerned with light reaction of photosynthesis only, constituting cyclic photo-phosphorylation.
The electron transport during Photo-system II results in the synthesis of NADPH2 in presence of enzyme NADP reductase. NADPH2 is used in reduction reaction of Calvin cycle.
Both Photo-systems participate in non-cyclic photo-phosphorylation that results in the synthesis of NADPH2 in addition to the synthesis of ATP molecules.
What is the acceleration of a 24 kg mass pushed by an 8 N force?
Answer:
0.25 m/s squared
Explanation:
Mass of the body (m)= 24kg
Applied force on the body(F)= 6N
Acceleration of the body (a)= ?
Solution
F = ma
a = F/m
a = 6N/24kg
a = 0.25m/s^2
Answer: The acceleration of the body is 0.25m/s^2
I hope this helps
Answer:
[tex]\boxed {\boxed {\sf a=\frac {1}{3} \ m/s^2}}[/tex]
Explanation:
Force is the product of mass and acceleration.
[tex]F=ma[/tex]
The mass is 24 kilograms and the force is 8 Newtons. Let's convert the Newtons to make the problem easier.
1 Newton is equal to 1 kilogram meter per square second. The force of 8 N equals 8 kg*m/s²Substitute the known values into the formula.
[tex]8 \ kg*m/s^2= (24 \ kg )*a[/tex]
Since we are solving for a, we must isolate the variable. It is being multiplied and the inverse of multiplication is division. Divide both sides by 24 kilograms.
[tex]\frac {8 \ kg*m/s^2}{24 \ kg}= \frac{(24 \ kg )*a}{24 \ kg}[/tex]
The kilograms will cancel, hence our earlier unit conversion.
[tex]\frac {8 \ m/s^2}{24 }= a[/tex]
[tex]\frac {1}{3} \ m/s^2=a[/tex]
The acceleration is 1/3 meter per square second.
A force of 1000 N is exerted on a golf ball for 0.005 s. The change in momentum of the golf ball is - a 200,000 kg m//s b 50 kg m//s c 5,000 kg m//s d 5 kg m//s
Answer:
d) 5 Ns
Explanation:
Impulse = Ft = 1,000(0.005) = 5
If the pelican was traveling 8.79 m/s but was only 2.7 m above the water, how far would the fish travel horizontally before hitting the water below?
Answer:
6.52m
Explanation:
The horizontal distance travelled is known as its range. This is expressed as;
Range = u* √2H/g
u is the speed of the pelican
H is the maximum height
g is the acceleration due to gravity
Range = 8.79*√2(2.7)/9.8
Range = 8.79 * √5.4/9.8
range = 8.79*√0.5510
Range = 8.79*0.7423
Range = 6.52
Hence the fish will travel 6.52m before hitting the water below
i really really need help with this so please help me for a better grade asap
Answer :
Imma just put it in the explanation
Explanation:
Electric to sound : Radio
Chemical to thermal+radiant+sound+kinetic : Fireworks
Gravitational to kinetic+sound : Waterfall
Chemical to thermal+kinetic : Drinking water (not sure what last answer is called but its supposed to match the girl drinking water lol)
hope this helps
Pls helppp. Is this right?
Answer:
yes you are totally right
An ant walks 15 m east, then 40 m north, and finally 20 m west. What is the total displacement from the starting point
Answer: 40.311 m
Explanation:
Given
Ant walks 15 m east
then 40 m North and finally 20 m west
from the figure, ant is 40 m North and 5 m west
Using Pythagoras, we can write
[tex]\Rightarrow d=\sqrt{40^2+5^2}\\\Rightarrow d=\sqrt{1625}=40.311\ m[/tex]
Which statements describe how heat flows in foil? Check all that apply.
Answer:
Heat flows from a warmer object to a cooler object.3. How does the wavelength of green different from violet-indigo?
Answer:
As the full spectrum of visible light travels through a prism, the wavelengths separate into the colors of the rainbow because each color is a different wavelength. Violet has the shortest wavelength, at around 380 nanometers, and red has the longest wavelength, at around 700 nanometers.
Explanation:
You flip a coin straight up if the coin reaches a high point of 0.25 m above where you released it what was the initial speed?
Answer: 2.21 m/s
Explanation:
Given
Coin reaches a height of 0.25 m above the launch point
Suppose u is the initial speed of the coin
Using the equation of motion
[tex]\Rightarrow v^2-u^2=2as\\[/tex]
Putting values
[tex]\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s[/tex]
Thus, the initial velocity is 2.21 m/s
which lever is human arm
Answer:
The human arm is a class 3 lever
Explanation:
Answer:
A bent arm is a Class 3 lever. The pivot is at the elbow and the forearm acts as the lever arm. The biceps muscle provides the effort (force) and bends the forearm against the weight of the forearm and any weight that the hand might be holding.
Explanation:
An egg sinks in fresh water but floats on concentrated salt solution
the salt solution exerts a greater up thrust on the egg which balances the weight of the egg, so the egg floats in a strong salt solution but sinks in fresh water
What is released when rocks shift or move along a tectonic plate boundary?
(It is a science question)
Answer:
juuhu
Explanation:
jjj
plssss helpppp it’s urgent
At t = 3 seconds, what is the velocity of the object
Answer:
NO ANSWER
Explanation:
there is no tragectory or diagram given
WHICH OBJECT?
You ride your bike 5 miles east to school, then 2 miles east to Wawa, return to school, then ride 2 miles west to the library to work on your homework. What is your displacement?
Answer:
3 miles
Explanation:
5 + 2 - 2 - 2 = 3 miles
Question 2
What measurements are needed to calculate your BMI?
A. Weight and shoe size
B. Height and weight
C. heart and breathing rate per minute
D. core temperature and height
Answer:
B
Explanation:
3. Determine the units of the quantity described by the following com-
binations of units:
a. kg (m/s) (1/s)
b. (kg/s) (m/s2)
c. (kg/s) (m/s)
d. (kg/s) (m/s)
1. Which of the following decreases with an increase in altitude?
a. air pressure
b. visibility
c. water vapor
d. none of the above
Answer: air pressure
Explanation:
A car traveled a distance of 30 km in 20 minutes (1/3 hours). What was the
speed of the car?
O A. 90 km/hr
O B. 60 km/hr
O c. 30 km/hr
O D. 10 km/hr
A centrifuge used in DNA extraction spins at a maximum rate of 7000rpm producing a "g-force" on the sample that is 6000 times the force of gravity. If the centrifuge takes 10 seconds to come to rest from the maximum spin rate: a) What is the angular acceleration of the centrifuge? b)what is the angular displacement of the centrifuge during this time
Answer:
A) a = 73.304 rad/s²
B) Δθ = 3665.2 rad
Explanation:
A) From Newton's first equation of motion, we can say that;
a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.
Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s
Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s
We are given; t = 10 s
Thus;
a = 733.04/10
a = 73.304 rad/s²
B) From Newton's third equation of motion, we can say that;
ω² = ω_o² + 2aΔθ
Where Δθ is angular displacement
Making Δθ the subject;
Δθ = (ω² - ω_o²)/2a
At this point, ω = 0 rad/s while ω_o = 733.04 rad/s
Thus;
Δθ = (0² - 733.04²)/(2 × 73.304)
Δθ = -537347.6416/146.608
Δθ = - 3665.2 rad
We will take the absolute value.
Thus, Δθ = 3665.2 rad
objects through which light can pass are referred to as dash objects
Answer:
Those objects are called transparent objects...
Explanation:
If only some light can pass through them ,it is called translucent....
If no light can pass through them ,it is called opaque.
Answer:
hii good morning
hey i am not good player but i wanted to give a triel to play duo in ff
A force of 100N stretches an elastic string to a total length of 20cm. if an additional force of 100N stretches the spring 5 cm further, find the natural length of the spring if the elastic limit is not exceeded. Pls help ASAP
Answer:
8cm
Explanation:
The general formula to find this is F/X where in this case the f is the total of the two forces (100+100) and x is the sum of the length ( 20+5) which together comes 200&25respectively then divide 200 with 25 which comes 8cm.
What are the mechanical advantage and mechanical efficiency of a lever that requires an input force of 40 N and lifts and lifts a boulder that weighs 80 N?
Answer:
2 , 200%
Explanation:
Mechanical advantage of a machine is defined as how much the machine multiplies the applied force.
It is given that :
Input force of the lever = 40 N
The weight of the boulder or the output force = 80 N
Therefore, the mechanical advantage = output force / input force
[tex]$=\frac{80}{40}$[/tex]
= 2
Mechanical efficiency is obtained by the dividing the output by the input and multiplying it with 100.
i.e. Efficiency = output / input x 100
[tex]$=\frac{80}{40}\times 100$[/tex]
= 200 %
two children of masses m1 = m2 = 20 kg , ride on the perimeter of a small merry-go- round . the merry -go-round us a disk of mass M = 30 kg answer
Answer:
c
Explanation:
Regina is making observations of waves from different sources. She wants to classify the waves as either mechanical or electromagnetic. Which question will BEST help Regina to classify the waves?
A.
Can the wave transfer matter?
B.
Can the wave transfer energy?
C.
Can the wave travel through a vacuum?
D.
Can the wave travel through a liquid?
Answer:
A. Can the wave transfer matter?
Explanation:
EMW is made by vibrations of the charged particles and they work on a mechanical waveform. The energy is transferred through a vacuum and thus they need a medium to pass the energy. Thus in order to transport the energy from one place to another, such as a sound wave. Hence first she should have knowledge about the chemical and physical properties of the waves such as can they transfer matter.QUESTION 1
(Show your work)
mi
R
Two children, of masses m1 = m2 = 20 kg,
ride on the perimeter of a small merry-
go-round. The merry-go-round is a disk
of mass M = 30 kg
and radius R = 3 m, as shown in the figure
below.
The moment of inertia of the system
(merry-go-round, child 1, child 2) about
the center of the merry-go-round is
equal to:
M M
m2
A 12 N [E] force is applied to a toy train with a mass of 2.7 kg. The toy train is attached by a light string to a wagon with a mass of 1.8 kg which is attached to a second wagon with a mass of 1.0 kg. If the train is pulled on a surface with a coefficient of kinetic friction of 0.05, determine the tension in the string between the first and the second wagon. (6T, 3C) Include free body diagrams for the three masses involved in the acceleration. (3 Comm.)
See the attached diagram for reference and free body diagrams. The acceleration a of each body will be the same since each connecting string is in tension.
By Newton's second law, we have
• net force on the train:
- - horizontal
[tex]\sum F = F - F_{k,T} - T_1 = m_Ta[/tex]
(where F = 12 N)
- - vertical
[tex]\sum F = N_T - m_Tg = 0[/tex]
• net force on wagon 1:
- - horizontal
[tex]\sum F = T_1 - T_2 - F_{k,1} = m_1a[/tex]
- - vertical
[tex]\sum F = N_1 - m_1g = 0[/tex]
• net force on wagon 2:
- - horizontal
[tex]\sum F = T_2 - F_{k,2} = m_2a[/tex]
- - vertical
[tex]\sum F = N_2 - m_2g = 0[/tex]
We want to determine T₂, the tension in the string connecting the two wagons.
For each body, the corresponding normal force has magnitude
N = mg
where m is the respective mass, and the kinetic friction has magnitude
Friction = 0.05 N = 0.05mg
So if µ = 0.05, then the frictional force on each body is
[tex]F_{k,T} = 0.05 (2.7\,\mathrm{ kg}) g = 1.323\,\mathrm N[/tex]
[tex]F_{k,1} = 0.05 (1.8\,\mathrm{ kg}) g = 0.882\,\mathrm N[/tex]
[tex]F_{k,2} = 0.05 (1.0\,\mathrm{ kg}) g = 0.49\,\mathrm N[/tex]
which leaves us with the system of equations,
[1] … 12 N - 1.323 N - T₁ = (2.7 kg) a
[2] … T₁ - T₂ - 0.882 N = (1.8 kg) a
[3] … T₂ - 0.49 N = (1.0 kg) a
Adding [1] and [2] eliminates T₁ :
(12 N - 1.323 N - T₁) + (T₁ - T₂ - 0.882 N) = (2.7 kg) a + (1.8 kg) a
[4] … 9.795 N - T₂ = (4.5 kg) a
Divide through both sides of [3] by 1.0 kg to solve for a :
a = (T₂ - 0.49 N) / (1.0 kg)
Substitute this into [4] and solve for T₂ :
9.795 N - T₂ = (4.5 kg) (T₂ - 0.49 N) / (1.0 kg)
(9.795 N - T₂) (1.0 kg) = (4.5 kg) (T₂ - 0.49 N)
9.795 N - T₂ = 4.5 T₂ - 2.205 N
12 N = 5.5 T₂
T₂ = (12 N) / 5.5 ≈ 2.1818 N ≈ 2.2 N
A potato is which part of the plant?
root
stem
leaf
flower