To calculate the amount of boiling water that must be added to the beaker, you need to use the heat capacity equation. This equation is given by:
Q = mcΔT
What is equation?An equation is a mathematical statement that expresses the equality of two expressions. It is typically used to describe the relationship between two variables or an expression and an unknown value. An equation is usually written as a statement of equality between two expressions separated by an equal sign.
Where Q is the amount of heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Since you are starting with 750 g of water at 10°C and you want to end up with a final temperature of 75°C, you can rearrange the equation to solve for m, the mass of boiling water:
m = Q/(cΔT) = (750g × 4.19 × 103 J/(kg•K) × 65°C)/(4.19 × 103 J/(kg•K)) = 1950 g
Therefore, you need to add 1950 g of boiling water at 100°C to the beaker in order to reach the desired final temperature of 75°C.
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question 4 a photon with a longer wavelength is more energetic than a photon with a short wavelength. travels slower than a photon with a short wavelength. is more blue than a photon with a short wavelength. has a lower frequency than a photon with a short wavelength.
A photon with a longer wavelength has a lower frequency than a photon with a short wavelength, the correct option is (d)
The wavelength and frequency of a photon are related to its energy and color. Photons with shorter wavelengths have higher frequencies and higher energy, while photons with longer wavelengths have lower frequencies and lower energy.
This is described by the equation E = hf, where E is energy, h is Planck's constant, and f is frequency. Therefore, a photon with a longer wavelength has a lower frequency than a photon with a shorter wavelength, the correct option is (d)
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The complete question is:
A photon with a longer wavelength
a) is more energetic than a photon with a short wavelength.
b) travels slower than a photon with a short wavelength.
c) is more blue than a photon with a short wavelength.
d) has a lower frequency than a photon with a short wavelength.
e) All of the above
Describe what happens as the hair dryer takes in cool air from one end and blows out warm air from other end TYYYY
When the hair dryer is turned on, it draws in cool air from its back end and passes it over a heating element, which increases the temperature of the air.
What happens when a hair dryer intakes cool air from one end and expels warm air from the other?Cool air is taken in and is heated using a heating element as described. The heated air is then forced out through the front end of the dryer by a fan. As the warm air blows over the hair, it causes the water molecules in the hair to evaporate, thus drying the hair. The hair dryer also helps to style hair by blowing it in different directions, causing it to move and create volume.
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the speedometer of my car reads v = 45 m/s. is this … group of answer choices instantaneous speed? average speed?
The speedometer of your car reading v = 45 m/s indicates the instantaneous speed of your car at that particular moment in time.
Instantaneous speed is the speed of an object at a specific moment in time and is often represented as the magnitude of the instantaneous velocity vector. In the context of your car's speedometer, the reading of 45 m/s indicates the speed of your car at the exact moment the reading was taken.
In contrast, the average speed is the total distance travelled by an object divided by the time it took to travel that distance. It represents the average rate at which the object covered the distance, and does not provide information about the object's speed at any particular moment in time.
Therefore, the reading on your car's speedometer represents instantaneous speed, not average speed.
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The speedometer of your car reading v = 45 m/s is the instantaneous speed of the car.
Instantaneous speed is the speed of an object at a particular moment in time, without taking into account any previous or future motion. In this case, the speedometer is providing a real-time reading of the car's speed at that moment.
The speedometer measures the speed of the car through a device called a speed sensor.
The sensor measures the rotation of the wheels and converts it into an electrical signal, which is then used to calculate the speed of the car.
The speedometer then displays this speed in m/s or mph on the dashboard of the car.
It's important to note that instantaneous speed can change rapidly as the car accelerates, decelerates, or changes direction. This means that the speedometer reading will change as the car's speed changes.
In contrast, average speed is calculated by dividing the total distance traveled by the total time taken to travel that distance.
It provides an average value of the speed over a period of time, such as the entire trip or journey.
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a bored student holds one end of a flexible ruler and sends it into simple harmonic motion. the free end of the ruler moves a total distance of 10.0 cm and makes 25 complete oscillations in 10 seconds. what is the maximum speed? (give the answer in cm/s to one decimal point)
The maximum speed is 62.8 cm/s.
We can start by finding the frequency of the oscillation:
f = (25 oscillations) / (10 s) = 2.5 HzThen, we can use the formula for the displacement of an object in simple harmonic motion:
x = A sin(2πft)Where x is the displacement (in meters), A is the amplitude (in meters), f is the frequency (in Hz), and t is the time (in seconds).
We are given that the displacement is 10.0 cm = 0.1 m, and we know that the amplitude is half of the total displacement (since the ruler moves symmetrically around its equilibrium position), so:
A = 0.1 m / 2 = 0.05 mUsing this information, we can find the maximum speed by taking the derivative of the displacement equation:
v = 2πfA cos(2πft)At the point of maximum displacement (when sin(2πft) = 1), the speed is:
vmax = 2πfA = 2π(2.5 Hz)(0.05 m) = 0.628 m/s = 62.8 cm/s (to one decimal point).
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if the distance between the thermopile sensor and the source is doubled and all other parameters remain the same, by what percentage will the thermopile reading increase or decrease?
If the distance between the thermopile sensor and the source is doubled and all other parameters remain the same, the thermopile reading will decrease by 75%.
The thermopile reading is a measure of the temperature difference between the thermopile sensor and the source. If the distance between the thermopile sensor and the source is doubled, the temperature difference between the two will decrease. This is because the heat will have to travel a longer distance to reach the thermopile sensor, resulting in a lower temperature difference. It is important to note that this calculation assumes that all other parameters remain constant.
The percentage decrease in the thermopile reading can be calculated using the inverse square law. According to this law, the intensity of the heat radiation is inversely proportional to the square of the distance between the source and the thermopile sensor. This means that if the distance is doubled, the intensity of the heat radiation will decrease by a factor of four (2 squared). Therefore, the thermopile reading will decrease by 75% (4/1) when the distance between the thermopile sensor and the source is doubled.
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An 81 kg football player moving 6. 5 m/s tackles and collides with a stationary 140 kg football player. What speed will the football players have the moment after impact?
The two football layers will have a velocity of 3.36 m/s (to the right) immediately after the collision.
Before the collision, the total momentum of the system is given by:
p = m1v1 + m2v2
Plugging in the numbers, we get:
p = (81 kg)(6.5 m/s) + (140 kg)(0 m/s)
p = 526.5 kg m/s
The total momentum of the system after the collision is:
p' = (81 kg + 140 kg) * v
Using the principle of conservation of momentum, we can equate p and p', and solve for v:
p = p'
(81 kg)(6.5 m/s) + (140 kg)(0 m/s) = (81 kg + 140 kg) * v
Solving for v, we get:
v = (81 kg)(6.5 m/s) / (81 kg + 140 kg)
v = 3.36 m/s
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dust-ignitionproof equipment must be designed and built in a manner that excludes dusts and prevents arcs, sparks, or heat that may be generated inside of the enclosure from causing ignition of ? of a specified dust on or in the vicinity of the enclosure.
Equipment that is designed to be dust-ignitionproof must be constructed in a way that prevents dust from getting inside and removes the possibility that heat, sparks, or arcs generated inside the apparatus would result in explosions or fires.
This is due to the fact that dust can be extremely hazardous in some working situations and can result in mishaps that could harm personnel or harm equipment.
In order to work safely in dusty environments, it is crucial to design and construct dust-ignitionproof equipment that can do so by avoiding the ignition of any dust that may be present inside or around the equipment. The ability to operate the machinery safely without endangering their health or safety is thus guaranteed.
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how do ice skaters get spinning so rapidly? where do they suddenly get the energy? are they violating conservation of energy?
Ice skaters get spinning rapidly by using the conservation of energy principle. They do not violate the conservation of energy.
When ice skaters begin their spin, they have their arms and one leg extended outwards. This extended position increases their moment of inertia, or the measure of how difficult it is to change the object's rotational motion. As they pull their arms and leg closer to their body, their moment of inertia decreases. According to the conservation of angular momentum, when the moment of inertia decreases, the angular velocity (or spinning speed) must increase to keep the angular momentum constant. This increase in angular velocity causes ice skaters to spin rapidly.
So, ice skaters gain their spinning energy by changing their body position, not by adding external energy, and they do not violate the conservation of energy.
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if a red giant appears the same brightness as a red main sequence star, which one is further away
If a red giant appears the same brightness as a red main sequence star, it is most likely that the red giant is further away.
Here's a step-by-step explanation:
1) Red giants and red main sequence stars are both types of stars that are similar in color, but they have different sizes and luminosities.
2) Red giants are much larger and more luminous than red main sequence stars. They are formed when a star like the sun runs out of fuel and begins to expand and cool.
3)Red main sequence stars, on the other hand, are smaller and less luminous than red giants. They are stars that are still burning hydrogen fuel in their cores.
4) The apparent brightness of a star depends on both its intrinsic luminosity and its distance from Earth. The farther away a star is, the dimmer it appears to us on Earth.
5) If a red giant appears the same brightness as a red main sequence star, this means that the red giant must be much farther away from Earth than the red main sequence star.
6) This is because the red giant is intrinsically much more luminous than the red main sequence star. If both stars were at the same distance from Earth, the red giant would appear much brighter than the red main sequence star.
7) However, since the red giant appears the same brightness as the red main sequence star, this means that the red giant must be much farther away from Earth and therefore appears dimmer.
Overall, by comparing the apparent brightness of a red giant and a red main sequence star, we can determine which star is farther away.
If the red giant appears the same brightness as the red main sequence star, then the red giant is likely to be much farther away.
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a wheel of radius 15 cm has sa rotational inertia of 2.3 kg m^2. the wheel is spinning at a rate of 6.5 revolutions per second. a frictional force is applied tangentially to the wheel to bring it to a stop. the work done by the torque to stop the wheel is most nearly:
The work done by the torque to stop the wheel is -1918 J.
The given parameters are:
- Wheel radius (r): 15 cm = 0.15 m
- Rotational inertia (I): 2.3 kg·[tex]m^{2}[/tex]
- Angular velocity (ω): 6.5 revolutions per second = 6.5 * 2π rad/s ≈ 40.84 rad/s
To find the work done by the torque to stop the wheel, we can use the rotational work-energy theorem: W = 0.5 * I * (ω_[tex]f^{2}[/tex] - ω_[tex]i^{2}[/tex]), where W is the work done, ω_f is the final angular velocity (0 rad/s), and ω_i is the initial angular velocity.
Plugging in the given values:
W = 0.5 * 2.3 kg·[tex]m^{2}[/tex] * (0^2 - 40.84 rad/s^2)
W = 0.5 * 2.3 kg·[tex]m^{2}[/tex] * (-1667.86 rad^2/s^2)
W ≈ -1918.24 J
Since work is done against the frictional force to bring the wheel to a stop, the work done is negative. Therefore, the work done by the torque to stop the wheel is most nearly -1918 J.
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What happens to the rate of heat conduction is the distance between two materials increases?
Answer:
Each individual particle on the surface of an object is involved in the heat conduction process. An object with a wider area has more surface particles working to conduct heat. As such, the rate of heat transfer is directly proportional to the surface area through which the heat is being conducted.
A student is constructing a stream table to investigate how erosion by a meandering stream is affected by the slope of the land. The student uses the equipment shown.
What should the student vary for the different trials of the experiment?
Responses
A The number of blocks stacked beneath the tray The number of blocks stacked beneath the tray
B The sediment size of sand used in the stream table The sediment size of sand used in the stream table
C The volume of water that enters the stream table and collects in the bucket The volume of water that enters the stream table and collects in the bucket
D The size of the hole in the bottom of the container of water
A student is constructing a stream table to investigate how erosion by a meandering stream is affected by the slope of the land should vary, the number of blocks stacked beneath the tray. Option A
What is the purpose of the experiment?The purpose of the experiment is to investigate how the slope of the land affects erosion by a meandering stream. By varying the number of blocks stacked beneath the tray, the student can change the slope of the land and observe how this affects the behavior of the stream and the resulting erosion.
Varying the sediment size, the volume of water, or the size of the hole in the bottom of the container would not directly address the question of how slope affects erosion by a meandering stream.
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(q017) what force causes the tidal bulge on the side of the earth opposite the moon (the secondary bulge)? group of answer choices the centrifugal force caused by the orbiting of the earth-moon system around its center of mass the sun's gravitational attraction the centripetal force caused by the orbiting of the earth-moon system around its center of mass the moon's gravitational attraction
The tidal bulge on the side of the Earth opposite the moon (the secondary bulge) is caused by a.the centrifugal force.
This force is the result of the orbiting of the Earth-Moon system around its center of mass. The gravitational attraction between the Earth and the Moon causes the tides, with the Moon's gravitational attraction being the primary cause of the tides. However, the centrifugal force also plays a role in creating the tides.
As the Earth-Moon system orbits around its center of mass, the centrifugal force causes the water on the far side of the Earth to bulge outward. This bulge is opposite to the Moon, and it creates the secondary bulge. The centripetal force, which is caused by the same orbiting motion, pulls the water on the near side of the Earth toward the Moon, creating the primary bulge. Together, these forces work to create the tides that we observe on Earth. The tidal bulge on the side of the Earth opposite the moon (the secondary bulge) is caused by a.the centrifugal force.
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what is the minimum number of rays needed to locate its image point? explain. match the words in the left column to the appropriate blanks in the sentences on the right.
At least two rays are required to find an object's image point.
When utilizing a convex or concave lens to determine the image point of an item, light rays from the object are refracted through the lens to create an image.
This spot, where the image is located, is where these two rays will intersect. The image's location will be confirmed if further rays are traced because they will all intersect there. Therefore, two rays are the bare minimum required to determine an object's image point at any point in front of the mirror.
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A computer hard disk starts from rest, then speeds up with
an angular acceleration of 190 rad/s until it reaches its final
angular speed of 7200 rpm. How many revolutions has the disk
made 10. 0s after it starts up?
The final angular speed of the hard disk is 766.9 rad/s, and it takes 4.04 s to reach this speed with an angular acceleration of 190.0 [tex]rad/s^2[/tex].
To take care of this issue, we want to utilize the equation that relates the rakish removal of a pivoting object to its precise speed increase, time, and beginning rakish speed. The equation is given by:
θ = 1/2 * α * [tex]t^2[/tex] + ω0 * t + θ0
Where θ is the complete point pivoted by the plate, α is the precise speed increase, t is the time slipped by, ω0 is the underlying rakish speed, and θ0 is the underlying point.In this issue, the circle begins from rest, so ω0 = 0. The rakish speed increase of the plate is given as 190 [tex]rad/s^2[/tex], and the last precise speed is 7200 rpm.
We want to change the last precise speed from rpm over completely to rad/s by increasing it with 2π/60. In this manner, the last precise speed is 240π rad/s.We can now substitute these qualities into the recipe and compute the absolute point pivoted by the circle after 10.0 seconds:
θ = 1/2 * 190 [tex]rad/s^2[/tex] * [tex](10.0 s)^2[/tex] + 0 rad/s * 10.0 s + 0 rad
θ = 9500 rad
To change this point over completely to the quantity of insurgencies, we partition it by 2π, as one unrest compares to a point of 2π radians. Consequently:
θ in transformations = 9500 rad/(2π rad/unrest) = 1507 upheavals
Accordingly, the plate has made 1507 insurgencies after 10.0 seconds from its underlying state.
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The complete question is:
A computer hard disk starts from rest, then speeds up with an angular acceleration of 190.0 [tex]rad/s^{2}[/tex]until it reaches a final angular speed of 7300.0 rpm.
(a) What is the final angular speed in units of rad/s? rad/s.
(b) How long does it take for the disk to reach this angular speed? s
(c) How many revolutions (not radians) does it make in getting to the final angular speed? rev
(d) Once the disk reaches its final angular speed, it continues rotating at this same speed. How many revolutions has the disk made 10.0 s after it started up from rest?
what is the charge q on the capacitor immediately after the switch is closed? express your answer to two significant figures and include the appropriate units.
The charge q on the capacitor immediately after the switch closed is 0.00 coulombs (C) to two significant figures, with the appropriate units included.
To determine the charge q on the capacitor immediately after the switch is closed, we must first consider the behavior of the capacitor during the charging process. When the switch is closed, the capacitor begins to charge up from an initial state of zero charge. During this charging process, the current flows through the circuit and the voltage across the capacitor gradually increases until it reaches the maximum voltage supplied by the source.
The charge q on the capacitor at any time during this process can be found using the formula q = CV, where C is the capacitance of the capacitor in Farads (F) and V is the voltage across the capacitor in volts (V). Immediately after the switch is closed, however, the capacitor has not yet had any time to charge. Therefore, the voltage across the capacitor is still zero. Applying the formula, we find that q = CV = C(0V) = 0. So, the charge q on the capacitor immediately after the switch is closed is 0.00 coulombs (C) to two significant figures, with the appropriate units included.
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what are some of the observational capabilities of the juno spacecraft as identified in the article?
According to the article, the Juno spacecraft has several observational capabilities. Juno's observational capabilities allow scientists to study Jupiter's atmosphere, magnetic field, and gravity field.
The Juno spacecraft has several observational capabilities that have been identified in various articles. Some of the observational capabilities of the Juno spacecraft are:
Studying Jupiter's atmosphere: Juno's primary mission is to study Jupiter's atmosphere, which includes measuring its temperature, composition, and cloud patterns.Mapping Jupiter's magnetic field: Juno has a magnetometer instrument that can map Jupiter's magnetic field to study its structure and dynamics.Measuring the planet's gravity field: Juno has a gravity science instrument that can measure the planet's gravitational field, which can help determine the planet's interior structure.Learn more about the Juno spacecraft: https://brainly.com/question/13753163
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if interstellar dust makes an rr lyrae variable star look 5 magnitudes fainter than the star should, by how much will you over- or underestimate its distance?
The distance to the RR Lyrae variable star will be underestimated by a factor of 10 due to the effect of interstellar dust.
The distance to an astronomical object can be determined using the inverse square law, which states that the apparent brightness of an object decreases as the square of the distance increases.
The apparent magnitude of an object is a measure of its brightness as seen from Earth. The lower the magnitude, the brighter the object.
If interstellar dust makes an RR Lyrae variable star look 5 magnitudes fainter than it should, then the apparent magnitude of the star as observed from Earth is 5 magnitudes greater than its true apparent magnitude.
Using the inverse square law, we can write:
Apparent brightness ~ 1 / (distance[tex])^2[/tex]
If the apparent brightness is 5 magnitudes fainter than it should be, we can express the distance to the star as:
distance = sqrt(100^(0.4 * 5)) x true distance
where 0.4 is the conversion factor from magnitudes to brightness ratios, and 100 is the ratio of the brightness of the star as observed from Earth to its true brightness.
Simplifying this expression, we get:
distance = 100^(0.5) x true distance
distance = 10 x true distance
Therefore, the distance to the RR Lyrae variable star will be underestimated by a factor of 10 due to the effect of interstellar dust.
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If someone ran 100 meters in 20 seconds, then ran another 100 meters in 25
seconds, what would the runner’s average speed be over the whole 200 meters?
pls help!!!
a solid hemisphere with mass equal to 10 kilograms and radius of 30 millimeters sits with its flat side against a horizontal surface. what pressure (in pascals) does it exert on the surface?
The solid hemisphere exerts a pressure of 17,350 Pascals on the surface.
To find the pressure exerted by the solid hemisphere, we need to consider the weight of the object and the surface area in contact with the surface. The weight of the solid hemisphere is equal to its mass times the acceleration due to gravity, which is 10 kg x 9.81 m/s^2 = 98.1 N.
The surface area in contact with the surface is the curved surface area of the hemisphere, which is half the surface area of a sphere with radius 30 mm. Using the formula for the surface area of a sphere, we get:
Surface area = 2πr^2 = 2π(30 mm)^2 = 5,655.6 mm^2
To convert this to square meters, we divide by 1,000,000, which gives us 0.0056556 m^2.
Finally, we can calculate the pressure exerted by the solid hemisphere using the formula:
Pressure = Weight / Surface area = 98.1 N / 0.0056556 m^2 = 17,350 Pa
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What benefits have you enjoyed personally from using the power of hydraulics and pneumatics?
The benefits enjoyed personally from using the power of hydraulics and pneumatics are:
Increased efficiencyEnhanced safetyCost effectiveVersatility andPrecisionHydraulics and Pneumatics ExplanationHydraulics and pneumatics are two powerful technologies that utilize fluids to create mechanical motion or force. Both technologies have a wide range of applications in various industries, from construction and manufacturing to aviation and transportation. Here are some benefits one can enjoy personally from using the power of hydraulics and pneumatics:
Increased efficiency: Hydraulic and pneumatic systems can deliver high power with relatively low input, resulting in improved efficiency and productivity. For instance, hydraulic and pneumatic-powered machines require less energy to operate and can perform heavy-duty tasks with ease, saving time and effort.
Enhanced safety: Hydraulic and pneumatic systems are designed to provide consistent, reliable performance, reducing the likelihood of mechanical failures or accidents. Additionally, these systems can operate at high speeds and under extreme conditions, making them ideal for use in hazardous environments.
Cost-effective: Hydraulic and pneumatic systems can be more cost-effective than electric or mechanical systems, as they require less maintenance and have a longer lifespan. These systems also use less energy and can perform heavy-duty tasks with minimal wear and tear.
Versatility: Hydraulic and pneumatic systems are highly versatile, and can be adapted to suit a wide range of applications. For instance, hydraulic systems can be used to power cranes, excavators, and other heavy machinery, while pneumatic systems can be used for automated manufacturing processes, such as assembly lines.
Precision: Hydraulic and pneumatic systems are highly accurate, and can be controlled to deliver precise and consistent results. This makes them ideal for applications that require a high degree of precision, such as in the aerospace and medical industries.
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A substance is boiled repeatedly and stirred, but the solute never mixes with the solvent. Which best describes why?
Answer:
The solute and solvent have distinct chemical characteristics.
Explanation:
The solute and solvent could not have been mixed at the current temperature. The solute and solvent have distinct chemical characteristics. There was more pressure. The mixture was fully saturated.
Hope this helped :)
Answer: The fact that the solute does not mix with the solvent even after boiling and stirring repeatedly could be due to various reasons:
Insolubility: The solute may be insoluble in the solvent, meaning it cannot dissolve in it. This could be because the solute particles are too large or have a different molecular structure compared to the solvent. For example, oil and water do not mix because oil is non-polar while water is polar.
Immiscibility: The solute and solvent may be immiscible, which means they cannot form a homogeneous mixture. Immiscibility occurs when there is a significant difference in polarity or density between the solute and solvent. An example of immiscible substances is oil and water, where they form separate layers instead of mixing.
Saturation: The solvent may already be saturated with the solute. Saturation occurs when the solvent can no longer dissolve any more of the solute at a given temperature. Further boiling and stirring would not result in any additional mixing.
Chemical reaction: There might be a chemical reaction occurring between the solute and solvent, leading to the formation of a new substance or a precipitate. This can prevent the solute from dissolving completely in the solvent.
To determine the specific reason why the solute is not mixing with the solvent, it would be helpful to know the nature of the solute and solvent, as well as any other conditions or factors involved in the process.
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after an intense earthquake, the earth "rings" with a period of 54 minutes. what is the frequency (in hz) of this oscillation? Express your answer in hertz.
Frequency = the rate per second of a vibration constituting a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light).
The frequency is = 0.00030864 Hz
Solution - To find the frequency of the oscillation after an intense earthquake, we need to use the formula:
Frequency (f) = 1 / Period (T)
Given that the period of the Earth's oscillation is 54 minutes, we first need to convert this to seconds:
54 minutes * 60 seconds/minute = 3240 seconds
Now, we can find the frequency:
Frequency (f) = 1 / 3240 seconds ≈ 0.00030864 Hz
the frequency of the oscillation after the intense earthquake is approximately 0.00030864 Hz.
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q6. the disk rolls without sliding on the fixed horizontal surface. at the instant shown, the instantaneous center of zero velocity for rod ab would be in which region?
1. Velocity: The rate of change of an object's position with respect to time.
2. Rod AB: A straight, rigid component connecting two points (A and B) within a mechanical system.
3. Region: A specific area where the instantaneous center of zero velocity might be located.
Now, let's analyze the scenario: The disk rolls without sliding on the fixed horizontal surface.
To find the instantaneous center of zero velocity for rod AB.
step by step explanation:
Step 1: Determine the point of contact between the disk and the horizontal surface. This point has zero velocity because the disk is rolling without sliding.
Step 2: Draw a line perpendicular to rod AB, passing through the point of contact.
Step 3: Identify the point where this perpendicular line intersects rod AB. This is the instantaneous center of zero velocity for rod AB.
In conclusion, the instantaneous center of zero velocity for rod AB would be located in the region along the line perpendicular to rod AB and passing through the point of contact between the disk and the horizontal surface.
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when the disk rolls without sliding on a fixed horizontal surface, the instantaneous center of zero velocity for rod AB would be at the point where rod AB contacts the surface.
In this case, the center of zero velocity is the point where the rod experiences no relative motion concerning the surface, and it acts as a pivot point for the rolling motion of the disk. Velocity is a physical quantity that describes the rate of change of an object's position over time. It is a vector quantity, meaning it has both magnitude (speed) and direction. Velocity can be calculated by dividing the change in position (displacement) of an object by the time it took for the change to occur. The SI unit of velocity is meters per second (m/s). Velocity is a fundamental concept in physics, as it is used to describe the motion of objects in relation to one another. In addition to velocity, other related concepts include speed, acceleration, and momentum. These quantities are important in understanding and predicting the behavior of objects in motion, as well as in many practical applications, such as transportation, sports, and engineering.
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after rock yy is released from rest several seconds after rock xx is released from rest, what happens to the separation distance s between the rocks as they fall but before they reach the ground, and why? take the positive direction to be downward.
The separation distance s between the rocks increases because both rocks are accelerating downward due to gravity at the same rate, regardless of their masses.
Since rock YY was released after rock XX, it has a lower starting velocity than rock XX. As both rocks continue to fall, the velocity of rock YY will gradually increase until it reaches the velocity of rock XX. However, since rock XX has been falling for a longer time than rock YY, it will have traveled a greater distance by the time rock YY reaches the same velocity.
As a result, the separation distance s between the rocks will increase over time until they hit the ground. This phenomenon is known as the independence of motion of falling objects, and it was first observed by Galileo Galilei in the late 16th century.
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type 1 cable consists of ? twisted pairs, each individually shielded with foil, with a braided outer shield surrounding the entire cable core and covered with a jacket.
Type 1 cable consists of a braided outer shield surrounding the entire cable core and covered with a jacket, the correct answer is c.
Type 1 cable is commonly used in high-frequency applications where signal interference is a concern. The braided shield provides excellent protection against electromagnetic interference (EMI) and radio frequency interference (RFI). It also helps to reduce signal loss and attenuation by keeping the signal within the cable and preventing it from escaping.
The jacket provides an additional layer of protection against environmental factors such as moisture, abrasion, and temperature extremes. Type 1 cable is a reliable and effective option for applications where signal integrity and protection against interference are critical factors, the correct answer is c.
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The complete question is:
Type 1 cable consists of ?
a. twisted pairs
b. each individually shielded with foil
c. with a braided outer shield surrounding the entire cable core and covered with a jacket.
a barometer indicates that the atmospheric pressure is actually 768.2 mm hg. what is the pressure in kpa? a. 1.011 b. 102.4 c. 7.784 x 104 d. 7.582 e. 14.85
The pressure in kPa is approximately 102.4 kPa, when a barometer indicates that the atmospheric pressure is actually 768.2 mm hg. The correct option is b.
To convert the atmospheric pressure from mmHg to kPa, we can use the following conversion formula:
1 mmHg = 0.133322 kPa.
Given that the barometer indicates the atmospheric pressure is 768.2 mmHg, we can find the pressure in kPa by multiplying the pressure in mmHg by the conversion factor.
Pressure in kPa = 768.2 mmHg * 0.133322 kPa/mmHg
Pressure in kPa ≈ 102.4 kPa
Therefore, the correct answer is (b) 102.4 kPa.
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Suppose a small car and a large truck run out of gas at the same location. Which vehicle will be
more difficult to push to the gas station? Explain your response in terms of Newton's second law.
According to Newton's second law of motion, the force required to accelerate an object is directly proportional to its mass. This means that the larger the mass of an object, the greater the force required to move it.
Which vehicle will be more difficult to push to the gas station?In this scenario, the large truck has a much greater mass than the small car. Therefore, the large truck would be more difficult to push to the gas station. It would require a much greater force to overcome its inertia and start its motion. Once the truck is in motion, it would also require a greater force to keep it moving at a constant speed.
On the other hand, the small car has a smaller mass and would require less force to push it to the gas station. Once in motion, it would require less force to maintain its speed.
Therefore, due to the larger mass of the truck, it would be more difficult to push to the gas station compared to the smaller car.
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a student with a mass of 55 kg rides a bicycle with a mass of 11 kg. a net force of 125 n to the east accelerates the bicycle and student during a time interval of 3.0 s. what is the final velocity of the bicycle and student? assume the student and bicycle are initially at rest.
The final velocity of the bicycle and student is 5.67 m/s to the east.
We can solve this problem by applying Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:
[tex]fnet = mtotal*a[/tex]
where fnet is the net force, mtotal is the total mass of the system, and a is the acceleration.
In this case, the net force acting on the bicycle and student is 125 N to the east, the total mass is the sum of the masses of the student and the bicycle, which is 55 kg + 11 kg = 66 kg, and the time interval is 3.0 s.
Therefore, the acceleration of the system is:
[tex]a = fnet / mtotal = 125 N/66kg = 1.89m/s^{2}[/tex]
Using the kinematic equation that relates the final velocity (v), initial velocity (u), acceleration (a), and time (t):
[tex]v= u+at[/tex]
Since the bicycle and student are initially at rest, the initial velocity is zero. Therefore, the final velocity is:
[tex]v= at = (1.89 \frac{m}{s}^{2})*(3.0s) = 5.67\frac{m}{s}[/tex]
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a cliff diver pushes off horizontally from a cliff and lands in the ocean 2.00 s later. how fast was he going when he entered the water?
The cliff diver was going at a speed of 5.00 m/s when he entered the water.
To find the speed at which the cliff diver entered the water, we need to use the equation:
v = d/t
where v is the speed, d is the distance traveled, and t is the time taken.
In this case, we know that the diver landed in the water 2.00 s after pushing off horizontally from the cliff.
However, we don't know the distance traveled.
We can use the fact that the diver is moving horizontally to our advantage.
Since there is no vertical motion, we can assume that the distance traveled is equal to the horizontal distance from the cliff to the point where the diver enters the water.
Let's assume this distance is d = 10 meters (you can adjust this value based on the actual height of the cliff).
Then, we can calculate the speed of the diver as follows:
v = d/t
v = 10 m / 2.00 s
v = 5.00 m/s
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