Answer: that guy
Explanation:
a transformer with an input emf of 240volts and output of 960volts has 720 turns in the secondary coil. what is the number of coil in the primary coil?
Answer:
180 turns
Explanation:
Given data
Vi= 240 volts
Vo= 960volts
Ns= 720 turns
Required
The amount of Primary turns Np
The expression relating voltage and turns in a transformer is given as
Np/Ns= Vi/Vo
substitute
Np/720= 240/960
cross multiply
720*240= Np*960
172800= Np*960
Np= 172800/960
Np= 180
Hence the primary turns is 180 turns
What is the IMA of an inclined plane that is 5m long and 2m high?
A. 0.4
B. 2.5
C. 0.4m
D. 2.5m
Answer:
B. 2.5
not 2.5m because IMA is unitless.
The identical mechanical advantage of the inclined plane is 2.5.
What is mechanical advantage of inclined plane ?The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane. The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.
Given parameters:
Length of the inclined plane; d = 5 m.
Height of the inclined plane; h = 2 m.
So, identical mechanical advantage (IMA) of the inclined plane is = Length of the inclined plane ÷ Height of the inclined plane
= 5 m/2 m
= 2.5.
Hence, the identical mechanical advantage (IMA) of an inclined plane that is 5m long and 2m high is 2.5.
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Please help ASAP! Will give brainliest! :)
Answer:
composition :))
Explanation:
Answer:
Both C and D are true, but it mainly depends on answer C, the composition of the star.
Explanation:
Hope This Helps!
An objects motion changes
Answer:
uh finish the question please lol.
Compounds Boiling point °C Elemental composition Type of compound H20 100.0 all nonmetals covalent CS2 46.3 all nonmetals covalent CH4 -161.5 all nonmetals covalent HCI -85.1 all nonmetals covalent NaCl 1413.0 a metal and a nonmetal ionic KCI 1420.0 a metal and a nonmetal ionic If the teacher asks about a different covalent compound, what can the student predict about its properties? Select all that apply. A. It consists of all metals. B. It has a high boiling point. C. It has a low boiling point. D. It consists of all nonmetals.
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A team of scientists is researching the best way to use tides to produce energy. One team includes environmental
scientists.
Which other branch of Earth science would these scientists most likely represent?
-geology
-astronomy
-meteorology
-oceanography
Answer:
agree with above answer
A prismatic bar AB of length L and solid circular cross section (diameter d) is loaded by a distributed torque of constant intensity t per unit distance .
(a) Determine the maximum shear stress tmax in the bar
(b) Determine the angle of twist between the ends of the bar.
Answer:
a) the maximum shear stress τ[tex]_{max}[/tex] the bar is 16T[tex]_{max}[/tex] /πd³
b) the angle of twist between the ends of the bar is 16tL² / πGd⁴
Explanation:
Given the data in the question, as illustrated in the image below;
d is the diameter of the prismatic bar of length AB
t is the intensity of distributed torque
(a) Determine the maximum shear stress tmax in the bar
Maximum Applied torque T_max = tL
we know that;
shear stress τ = 16T/πd³
where d is the diameter
so
τ[tex]_{max}[/tex] = 16T[tex]_{max}[/tex] /πd³
Therefore, the maximum shear stress τ[tex]_{max}[/tex] the bar is 16T[tex]_{max}[/tex] /πd³
(b) Determine the angle of twist between the ends of the bar.
let theta ([tex]\theta[/tex]) be the angle of twist
polar moment of inertia [tex]I_p}[/tex] = πd⁴/32
now from the second image;
lets length dx which is at distance of "x" from "B"
Torque distance x
T(x) = tx
Elemental angle twist = d[tex]\theta[/tex] = T(x)dx / G[tex]I_{p}[/tex]
so
d[tex]\theta[/tex] = tx.dx / G(πd⁴/32)
d[tex]\theta[/tex] = 32tx.dx / πGd⁴
so total angle of twist [tex]\theta[/tex] will be;
[tex]\theta[/tex] = [tex]\int\limits^L_0 \, d\theta[/tex]
[tex]\theta[/tex] = [tex]\int\limits^L_0 \,[/tex] 32tx.dx / πGd⁴
[tex]\theta[/tex] = 32t / πGd⁴ [tex]\int\limits^L_0 \, xdx[/tex]
[tex]\theta[/tex] = 32t / πGd⁴ [ L²/2]
[tex]\theta[/tex] = 16tL² / πGd⁴
Therefore, the angle of twist between the ends of the bar is 16tL² / πGd⁴
A 0.85 N force exists between a 7.1 * 10 ^ - 6 * C charge 5.4 m away. What is the magnitude of the second charge ? Please show work
Answer:
Explanation:
Force between charge is given by the following expression
F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .
Putting the given values ,
.85 = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²
Q₂ = .85 x 5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )
= .38788 x 10⁻³ C .
= 387.88 x 10⁻⁶ C .
what did classical physics predict would happen to the light given of by an object as its tempurtare increased
Answer:
The energy of the light would increase from visible light into the ultraviolet range.
Explanation:
blah blah blah, blah blah BLAH
Which of the models most accurately represents the structure of DNA?
A
B.
G
Answer:
It's A.
Explanation:
DNA is a double helix.
Model which accurately displays structure of DNA is model A as DNA is a double helical structure.
What is DNA?
DNA is a hereditary material which is present in human beings as well as all other living organisms. Every cell which is present in an organism's body has DNA which is the same. Most of the DNA is situated in the cell's nucleus and small amount of it can be found in the cell's mitochondria as well.
Information which is stored in DNA is stored as codes made up of four chemical bases namely, adenine, thymine , cytosine and guanine.Human DNA consists of 3 billion bases .The order of the bases determines information which is required for building and maintaining an organism.
DNA bases are capable of pairing up with each other. Adenine pairs with thymine and guanine pairs up with cytosine .Each base is also attached to a sugar molecule and a phosphate group. A base, phosphate sugar are together called as nucleotides.
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Two friends, Barbara and Neil, are out rollerblading. With respect to the ground, Barbara is skating due south at a speed of 4.6 m/s. Neil is in front of her. With respect to the ground, Neil is skating due west at a speed of 4.4 m/s. Find Neil's velocity (a) magnitude and (b) direction relative to due west, as seen by Barbara.
Answer:
a) the magnitude is 6.37 m/s
b) the direction relative to due west, as seen by Barbara is 46.37° north of west
Explanation:
Given the data in the question;
Barbara is skating due south at a speed of 4.6 m/s
Neil is skating due west at a speed of 4.4 m/s
so
[tex]u_{B}[/tex]→ = 4.6 (-j^)
[tex]u_{N}[/tex]→ = 4.4 (-i^)
[tex]u_{NB}[/tex]→ = [tex]u_{N}[/tex]→ - [tex]u_{B}[/tex]→ = 4.4 (-i^) - 4.6 (-j^)
= -4.4i^ + 4.6j^
a) magnitude
magnitude |([tex]u_{NB}[/tex]→ )| = √( (-4.4)² + (4.6)²)
= √( 19.36 + 21.16)
= √40.52
= 6.37 m/s
Therefore, the magnitude is 6.37 m/s
b) direction relative to due west, as seen by Barbara.
using SOH CAH TOA
tan = opp / adj
so direction will be;
∅ = tan⁻¹( 4.6 / -4.4)
∅ = tan⁻¹( - 1.0454545 )
∅ = - 46.37°
Therefore, the direction relative to due west, as seen by Barbara is 46.37° north of west
Can anyone help me with the Wet Lab Guide - Coulomb's Law report? I'm really having trouble with it. I have attached the worksheet
Answer:
Coulomb's law of Electrostatic Force states that a charged particle attracts or repels other charged particles with a force which is directly proportional to the product of their charges and inversely proportional to the square of the distance between their centers.
Explanation:
What distance will a car cover while uniformly accelerating from 12 m/s to 26 m/s in 14 seconds?
Answer:
266 m
Explanation:
A car travels the same distance at constant speed around two curves, one with twice the radius of curvature of the other. For which of these curves is the change in velocity of the car greater? Explain.
Answer:
The answer is below
Explanation:
Centripetal acceleration is the acceleration due to the movement of an object in a uniform circular motion. The acceleration is directed towards the center of the circle.
Centripetal acceleration is given by the formula:
a = v² / r; where v is the speed of the object and r is the radius of curvature (distance from object ot the center of circle).
Let us assume the car has a velocity of v m/s. For the curve with radius of curvature r:
a₁ = v² / r
For the curve with radius of curvature r = 2r:
a₂ = v² / 2r = (1/2)a₁
Therefore the centripetal acceleration is greater in the curve with radius pf curvature r and smaller in the curve with twice the radius of curvature of the other.
g Light is a traveling wave! The oscillations are oscillations of electric fields. The electric fields oscillate in the y-direction while the light travels in the x direction, so we can create a wave equation Ey(x,t); Ey is the y-component of the electric field, x is position in meters, and t is time in seconds. Consider light with a wave length of 550 nanometers, a wave speed of 3.00 x 108 m/s , and an amplitude of 10 V/m (volts/meters). Construct the traveling wave equation for this light if at t = 0 seconds, the light is at its maximum positive value and is traveling in the negative x-direction. Your equation, Ey(x,t) , should only have the variables x and t (i.e. calculate the values of the relevant traveling wave quantities to three sig figures and use those in the equation you are constructing, do not use the symbols in your final answer).
Answer:
[tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)
Explanation:
The general equation of a traveling wave on the x-axis is
[tex]E_{y}(x,t)[/tex] = E₀ cos (kx -wt)
the amplitude of the wave is E₀ = 10 V / m
the wave number is
k = 2π /λ
indicate the value of λ = 550 nm = 550 10⁻⁹ m
we substitute
k = 2π / 550 10⁻⁹
k = 1.15 10⁻¹¹ m⁻¹
angular velocity is related to frequency
w = 2πf
the speed of light is related to the wavelength and frequency
c = λ f
f = c /λ
we substitute
w = [tex]2\pi \frac{c}\lambda }[/tex]
w = 2π 3 10⁸/550 10⁻⁹
w = 3.427 10¹⁵ rad / s
we substitute in the electric field equation
[tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)
Let's test the value of this wave for t = 0 at the point x = 0, the wave is worth
Ey (0,0) = 10
which corresponds to its maximum positive value, therefore this is the expression of the traveling wave
You are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distance between the two of you remains the same, so you deduce that you are walking at the same speed of 1.17 m/s. Suddenly, you notice a wallet on the ground. You pick it up and realize it belongs to the person in front of you. To catch up, you start running at a speed of 2.75 m/s. It takes you 14.5 s to catch up and deliver the lost wallet. How far ahead of you was this person when you started running
Answer:
Δx = 23.0 m
Explanation:
Since we know the time passed from the moment you picked up the wallet till you catch the other person up, and assuming that he continued moving at 1.17 m/s, we can find the distance traveled by him during this time, applying the definition of average speed, and rearrranging terms as follows:[tex]x_{2} = v_{2} * t = 1.17m/s * 14.5 s = 17.0 m (1)[/tex]
Now, as we know the speed at which you started to run, assuming that the speed kept constant during all the time since you picked the wallet up, we can find the total distance till you got to deliver the wallet, as follows:[tex]x_{1} = v_{1} * t = 2.75 m/s * 14.5 s = 40.0 m (2)[/tex]
the distance that you were behind the other person when you started running, is just the difference between (2) and (1):Δx = x₂ - x₁ = 40.0 m - 17.0 m = 23.0 m (3)can someone help me :(
Answer:
1. This is a speed graph.
2. The slope represents how much the item/ thing is moving at how much distance it moved and the minutes it takes it too move how much distance, but the slope is representing the decrease and increase of it.
3. Increasing, kind of rapidly going up since the slope is rising not falling.
if a particle with a charge of +4.3 C is attracted to another particle by a force of 6.5 N, what is the strength of the electric field at this location?
Answer: 1.5 N/C
Explanation:
The equation is derived from Coulomb's Law, but is not exactly Coulomb's Law:
F = qE
q is the test charge
E is the electrical field produced by the source charge
F is the force in Newtons
In this problem, we were given the value of the test charge q, and the force acting on it due to the electric field from the source charge.
E = F/q
E = 6.5N/4.3C
E = 1.5 N/C
The voltage across the diode indicates the energy given to charge carriers (electrons and holes, but more about that later in the course.) If the diode turns on at X volts, then the charge carriers are getting X electron-volts of energy. The charge carriers can give up this energy by emitting a photon. How does the energy the charge carriers get at the turn-on voltage compare to the energy of a red photon
Answer:
the charge carriers have an energy 2.8 10⁻¹⁹ J
Explanation:
The energy in a diode is conserved so the energy supplied must be equal to the energy emitted in the form of photons.
The energy of a photon is given by the Planck expression
E = h f
the speed of light, wavelength and frequency are related
c = λ f
we substitute
E = [tex]\frac{h \ c}{\lambda}[/tex]
a red photon has a wavelength of lam = 700 nm = 700 10⁻⁹ m
we calculate the energy
E = 6.626 10⁻³⁴ 3 10⁸/700 10⁻⁹
E = 2.8397 10⁻¹⁹J
therefore the charge carriers have an energy 2.8 10⁻¹⁹ J,
HELP URGENT WILL GIVE BRAINLIEST
Why are rocks made of limestone usually an indication that an area was previously covered by ocean water
Answer:
what's the question? I don't understand
Answer:
Limestone can from form shell fragments of sea creatures
Explanation:
A commuter train passes a passenger platform at a constant speed of 39.6 m/s. The train horn is sounded at its characteristic frequency of 346 Hz. (a) What overall change in frequency is detected by a person on the platform as the train moves from approaching to receding
Answer:
Explanation:
We shall apply Doppler's effect to solve the problem .
Formula for apparent frequency for a source of sound approaching an observer is as follows .
f₁ = f₀ V / (V - v )
where f₁ and f₀ are apparent and real frequency of source , V and v is velocity of sound and velocity of approaching source respectively .
Putting the given values and knowing that speed of sound is 340 m /s
f₁ =346x 340 / (340 - 39.6 )
f₁ = 391.6 Hz
In case of receding train , the formula is
f₂ = f₀ V / (V + v )
Putting the values
f₂ = 346x 340 / (340 + 39.6 )
= 309.9 Hz
Change in frequency = 391.6 - 309.9
= 81.7 Hz .
To start a great night of doing physics homework, you sit down to pour yourself a good cup of coffee. Your coffee mug has a mass 137 g and a specific heat of 1089 J/kg K. The mug starts out at room temperature (23.8 o C). Your coffee has an initial temperature of 79.8 oC and has the same specific heat as water (4186 J/kg K).
1) Let's say you pour enough coffee into the mug so that the mass of coffee is equal to the mass of the mug. If we assume that no heat is lost to the outside room, once the mug and coffee reach the same temperature, will that temperature be closer to the initial temperature of the coffee or the initial temperature of the mug? (Notice that the mass of the coffee and the mass of the mug are the same.)
2) What is the final temperature of coffee and mug once they come to thermal equilibrium?
Tfinal = ____________ degrees c
3) Now lets assume that instead of the 137 g of coffee, you pour in 225 g of coffee. What is the final temperature of the coffee and mug? (Again, assume that you loose no heat to the outside.)
Tfinal = ____________ degrees c
4) Now lets say that along with the 225 g of coffee, you pour in 11.7 g of cream in your mug. The cream has an initial temperature of 5.2 oC and also has the same specific heat as water. What is the final temperature of the coffee, cream and mug? (Again, assume that you loose no heat to the outside.)
Tfinal = _____________ degrees c
Answer:
1) The temperature will be closer to water
2) T = 68.239°C
3) T = 72.142°C
4) T = 69.266 °C
Explanation:
1)
The temperature will be closer to water because the heat capacity of water > heat capacity of coffee.
2)
137(1.089)(T - 23.8) = 137(4.186)(79.8 - T)
⇒(1.089)(T - 23.8) = (4.186)(79.8 - T)
⇒1.089 T - 25.9182 = 334.0428 - 4.186 T
⇒1.089 T + 4.186 T = 334.0428 + 25.9182
⇒5.275 T = 359.961
⇒ T = 68.239°C
3)
137(1.089)(T - 23.8) = 225(4.186)(79.8 - T)
⇒(149.193)(T - 23.8) = (941.85)(79.8 - T)
⇒149.193 T - 3550.7934 = 75159.63 - 941.85 T
⇒149.193 T + 941.85 T = 75159.63 + 3550.7934
⇒1091.043 T = 78710.4234
⇒ T = 72.142°C
4)
137(1.089)(T - 23.8) + 11.7(4.186)(T - 5.2)= 225(4.186)(79.8 - T)
⇒(149.193)(T - 23.8) + 48.9762(T - 5.2) = (941.85)(79.8 - T)
⇒149.193 T - 3550.7934 + 48.9762 T - 254.67624= 75159.63 - 941.85 T
⇒149.193 T + 941.85 T + 48.9762 T = 75159.63 + 3550.7934 + 254.67624
⇒1091.043 T + 48.9762 T = 78710.4234 + 254.67624
⇒1140.0192 T = 78965.09964
⇒ T = 69.266 °C
A very long, solid cylinder with radius R has positive charge uniformly distributed throughout it, with charge per unit volume r. (a) Derive the expression for the electric field inside the volume at a distance r from the axis of the cylinder in terms of the charge density r. (b) What is the electric field at a point outside the volume in terms of the charge per unit length l in the cylinder
Answer:
Explanation:
From the given information.
The charge density of the cylinder can be computed as:
[tex]\rho = \dfrac{Q_t}{V_t}[/tex]
where:
[tex]Q_t[/tex] = total charge on cylinder
[tex]\rho[/tex] = density of the cylinder
[tex]V_t =[/tex] net volume on cylinder
Considering the charge enclosed by the Gaussian surface; we have:
Q = ρV
Now, determining the volume of the cylinder at a distance r from the axis of the cylinder as follows:
[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]
Here;
[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;
If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and q with [tex]\rho \pi r^2 l[/tex]; Then:
[tex]E ( 2 \pi rl ) = \dfrac{\rho \pi r^2 l}{\varepsilon _o}[/tex]
By rearrangement;
[tex]E = \dfrac{\rho \pi r^2 l}{ ( 2 \pi rl ) \varepsilon _o}[/tex]
[tex]\mathbf{E = \dfrac{\rho r}{ 2 \varepsilon _o}}[/tex]
(b)
Using the same formula:
[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]
where;
[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;
If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and [tex]Q_t[/tex] with q;
Then:
[tex]E ( 2 \pi rl ) = \dfrac{Q_t}{\varepsilon _o}[/tex]
[tex]E = \dfrac{Q_t}{( 2 \pi R l ) \varepsilon _o}[/tex]
Replacing [tex]\lambda[/tex] for [tex]\dfrac{Q_t}{l}[/tex].
From above [tex]\lambda[/tex] = the charge per unit length
∴
[tex]\mathbf{E = \dfrac{\lambda}{ 2 \pi R \varepsilon _o}}[/tex]
For a conductor in electrostatic equilibrium, which of the following properties are true? Choose all that apply. For a conductor in electrostatic equilibrium, which of the following properties are true? Choose all that apply. The electric field inside is zero. The entire conductor is at the same potential. Any excess charge is uniformly spread throughout the volume of the conductor.
Answer:
The entire conductor is at the same potential.
The electric field inside is zero.
Explanation:
For a conductor in electrostatic equilibrium, the properties are:
The electric field inside is zero.The entire conductor is at the same potential. What is electrical conductor?A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors.
It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads).
Instead, all that is required of the charged particle is a small amount of nudging from its neighbor, who in turn will nudging its neighbor, and so on, until a particle gets nudged into the consumer, so supplying it with power.
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What is the period of a wave with a wavelength of 8 cm and a frequency of 0.5 hertz?
A. 2 seconds
B. 0.125 seconds
C.0.0625 seconds
D. 4 seconds . (I think it's D).
{ cmmt if you want to be added to a Physics B connections acay ig gc}
Answer:
It is 2 seconds.
The period of a wave will bed 2 second. Frequency is the inverse of the time period;Option A is correct.
What is frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
Frequency is given by the formula as,
[tex]\rm f = \frac{1}{t} \\\\ t= \frac{1}{f} \\\\ t= \frac{1}{0.5} \\\\ t= 2\ second[/tex]
The period of a wave will be 2 second.
Hence, option A is correct.
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Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance ddd is
|F|=K|QQ′|d2|F|=K|QQ′|d2,
where K=14πϵ0K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2)ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.
Consider two point charges located on the x axis: one charge, q1q1q_1 = -11.5 nCnC , is located at x1x1x_1 = -1.675 mm ; the second charge, q2q2q_2 = 40.0 nCnC , is at the origin (x=0.0000)(x=0.0000).
What is the force exerted by these two charges on a third charge q3q3q_3 = 48.0 nCnC placed between q1q1q_1 and q2q2q_2 at x3x3x_3 = -1.215 mm ?
Your answer may be positive or negative, depending on the direction of the force.
Express your answer numerically in newtons to three significant figures.
Answer:
F_total = -65.5 N
Explanation:
Coulomb's law is
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]k q1q2 / r2
In this exercise the force on the charge q3 is asked, for this we use that the force is a vector
F_total = F₁₃ + F₂₃
let's look for every force
F₁₃ = [tex]k \frac{q_1 q_3}{r_{13}^2}[/tex]
it is indicated that charge 1 is equal to q₁ = -11.5 nC = -11.5 10⁻⁹ C, located at x₁ = -1.675 mm = -1.675 10⁻³ m and charge q₃ = 48.0 nC = 48.0 10⁻⁹ C located at x₃ this position is not written in the exercise, suppose the position x₃ = -0.5 mm = 0.5 10⁻³ m
the distance is
r₁₃ = [tex]\sqrt{(x_3 - x_1 )^2}[/tex]
r₁₃ = [tex]\sqrt{(0.5-1.675)^2} \ 10^{-3}[/tex]
r₁₃ = 1.175 10⁻³ m
we calculate
F₁₃ = [tex]\frac{9 \ 10^{9} 11.5\ 10^{-9} 48.0\ 10^{-9} }{(1.175 10^{-3})^2 }[/tex]
F₁₃ = 3.598 N
as the charge q₁ is negative and the charge q₃ is positive the force is attractive directed to the right
we look for F₂₃, where q₂ = 40 nC = 40.0 10⁻⁹ C located at x₂ = 0
F₂₃ = [tex]k \frac{q_2q_3}{r_{23}^2}[/tex]
r₂₃ = [tex]\sqrt{(x_3-x_2)^2}[/tex]
r₂₃ = [tex]\sqrt{(0.5 -0)} \ 10^{-3}[/tex]RA (-0.5 0) 2 103
r₂₃ = 0.5 10⁻³ m
F₂₃ = [tex]\frac{9 \ 10^{9}\ 40\ 10^{-9} \ 48.0\ 10^{-9} x}{(0.5 \ 10^{-3})^2 }[/tex]
F₂₃ = 6.912 10¹ N
F₂₃ = 69.12 N
as the two charges are of the same sign, the force is repulsive, therefore it is directed to the left
the total force is
F = total = 3.598 - 69.12
F_total = -65.5 N
the negative sign indicates that the force is to the left
People in a community are interested in constructing a hydroelectric dam in
order to get more affordable electricity. Which option is best described as an
engineering endeavor related to building a hydroelectric dam?
O A. Taking measurements and performing calculations to determine
how strong the dam needs to be
B. Making observations in order to determine what kinds of plants
grow near the proposed dam site
C. Studying the rocks around the proposed dam site to determine
how old they are
D. Performing an investigation to determine how the construction will
affect local ecosystems
SUBMIT
People in a community are interested in constructing a hydroelectric dam in order to get more affordable electricity, so the next best option is to take measurements and perform calculations to determine how strong the dam needs to be, that is option A.
What is the work of an engineer?For building a hydroelectric dam, the engineers must take accurate measurements and perform detailed calculations so that the strength and stability of the dam are maintained, so the work of the engineers is important in construction.
Hence, people in a community are interested in constructing a hydroelectric dam in order to get more affordable electricity, so the next best option is to take measurements and perform calculations to determine how strong the dam needs to be, that is option A.
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A 800-w iron is left on the ironing board with the base exposed to the air. About 85 percent of the heat generated by iron dissipate through its base with surface area of 0.15 ft2 . Calculate the amount of heat the iron dissipates in 2 hours, the heat flux on the surface of iron and total cost of electricity wasted in 2 hours if unit cost of electricity to be $0.11kwh.
Answer:
ΔQ = 4896 KJ
Heat Flux = 57407.55 W/m²
Cost = $ 0.176
Explanation:
The amount of heat dissipated in two hours can be given as:
[tex]Heat\ Dissipation = \Delta Q = Pt\eta[/tex]
where,
P = Power of Iron = 800 W
t = time taken = 2 hrs
η = Conversion efficiency = 85% = 0.85
[tex]\Delta Q = (800\ W)(7200\ s)(0.85)\\\\[/tex]
ΔQ = 4896 KJ
Now, for heat flux:
[tex]Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}[/tex]
Heat Flux = 57407.55 W/m²
Now, for total heat energy in KWhr in two hours:
[tex]Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh[/tex]
Now, for the cost:
[tex]Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)[/tex]
Cost = $ 0.176
1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of the electric force? The constant k = 9 x 109 N-m2/C2
Solution:
Answer:
F = 36 N
Explanation:
Given that,
Charge, q₁ = +8 μC
Charge, q₂ = -5 μC
The distance between the charges, r = 10 cm = 0.1 m
We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N[/tex]
So, the magnitude of the electrostatic force is 36 N.