1. Which of the following statements describe cations? Select all that apply.
Positively charged ions.
Negatively charged ions.
They have lost electrons.
They have gained electrons.

Answer:

0.02kg

Explanation:

Given parameters:

Amount of heat  = 5200J

Unknown:

Mass of ice that would be melted at 0°C = ?

Solution:

To solve this problem, use the expression below;

        H  = mL

H is the heat

m is the mass

L is the latent heat of fusion of ice  =  3.33 x 10⁵ J/kg.

 Insert the parameters and solve for m;

           5200  = m x 3.3 x 10⁵

             m  = [tex]\frac{5200}{3.33 x 10^{5} }[/tex]   = 0.02kg

Answer:

i got you stop doing work  and forget about this one class you will still pass trust me i did it it 8th grade and still made it to 9th but today im not even in school so just do better in your other classes

Explanation:

Answer:

No. All four hybrids are equivalent and the angles between them are all the same, so we can use any of the two to hold the nonbonding pairs.

Explanation:

Orbital hybridization has been the combination of the atomic orbitals for the formation of a new hybrid. No, it does not matter which orbitals are used to hold the nonbonding electron pairs.

Hybrid orbitals are said to be formed by the mixing of the atomic orbitals with different energy and geometrical shape that allows the understanding of the atomic bonding and molecular geometry of the compounds.

It includes sp, sp², sp³, sp³d, and sp³d² which have various arrangements, including linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. The hybrid orbitals are formed by the combination and overlapping of the s and p orbital.

It does not matter which sp³ orbital holds the two non-bonding electron pairs as all four hybrids have been known to have equivalent angles between them so it will not matter which hybrid has the non-bonded electrons in them.

Therefore, it will not matter which two sp³ hybrid holds the electron pairs that are not involved in bonding.

Learn more about orbital hybridization, here:

https://brainly.com/question/16251845

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Answer:

2.273M

Explanation:

What is the definition of molarity.

M = mols/L. So that's what we need to determine.

How much does a L weigh? That's

1.114 g/mL x 1000 mL = 1114 grams. Simple enough, eh?

How much of that 1114 g is H3PO4. It says it is 20% by mass, therefore, 1114 g x 0.20 = 222.8 g.

How many mols are there in 222.8 g H3PO4? That's mools = grams/molar mass = 222.8/98 = 2.273 mols.

The definition of M is what? M = mols/L. And you have 2.273 mol/L; that must be the molarity.

The formula is

density g/mL x 1000 mL x mass% x (1/molar mass) = M

1.114 x 1000 x 0.20 x (1/98) = 2.273 M.

Answer:

6

8

6

Explanation:

 Isotope given:

                       ¹⁴₆C

In specie written as this;  

   Superscript  = Mass number

   Subscript  = Atomic number

To find the protons, it is the same as the atomic number;

                Protons  = Atomic number  = 6

Neutrons have no charges;

 Neutrons  = Mass number - Atomic number  =

  Neutrons  = 14 - 6  = 8

The number of electrons is the same as the atomic number = 6

Answer:

1. There is no moles of water in 39g of chlorine.

2. 1.19x10²³ molecules of Au.

Explanation:

First, we need to remember that molar mass of a compound represents the mass of 1 mole (6.022x10²³ molecules) of molecules.

Molar mass of Chlorine, Cl₂ is 70.9g/mol

Molar mass of gold, Au, is 197g/mol

1. Moles of 39g of Cl₂ are:

39g Cl₂ * (1mol / 70.9g) = 0.55 moles moles of chlorine

But there is no moles of water in 39g of chlorine.

2. First, moles of Au are:

39g Au * (1mol / 197g) = 0.198 moles Au.

Molecules are:

0.198 moles Au * (6.022x10²³ molecules / 1 mol) =

Answer:

I think it would be b

Explanation: