1. Where are stars formed?
A. A planetary nebula
B. Near the center of the universe
C. A nebula
D. A dying planet

Answer:

Momentum is Mass x Velocity.

Its pretty obvious that the 80kg student Moving at 4ms-¹ has more momentum.

80x4 = 320kgms-1

0.001x250= 0.25kgms-¹

The Second student also Has More Inertia. Inertia is the resistance to motion offered by a Body. An Object with greater mass has more tendency to resist Motion .

So

The 80Kg student wins all.

Answer:

i think it is 80 kg

Explanation:

Answer with explanation:

Answer: 588 N

Explanation: pressure = force/area, or p = F/A. Then p1=p2

And F1//A1 = F2/A2 . F2 = F1·A2/A1 = 11760 N·0.0125 m²/ 0.25 m²

Answer:

D. 5m

Explanation:

fλ = c, where f is frequency, λ is wavelength and c is speed.

6λ=30

λ=30/6=5

electromagnetic induction?

Answer:

A. True, I think

Explanation:

Answer:

1)  T = 649.86 s, 2)   L₀ = L_f,   [tex]\frac{K_o}{K_f}[/tex] = 4.8

Explanation:

1) As the system of the two bodies is isolated, its angular momentum is conserved

initial instant.  r₀ = 155 m, T₀= 385.3 s

      L₀ = I₀ w₀

final instant. r = 119.35 m

      L_f = I w

      L₀ = L_f

      I₀ w₀ = I w

      w = [tex]\frac{I_o}{I} \ w_o[/tex]

let's consider each object as punctual

      I = m r²

at angle velocity and period are related

         w = 2pi / T

we substitute

      [tex]\frac{2\pi }{T} = \frac{m r^2}{m _o^2 } \ \frac{2\pi }{T_o}[/tex]

      [tex]\frac{1}{T} = ( \frac{r}{r_o} )^2 \ \frac{1}{T_o}[/tex]

       T = [tex](\frac{r_o}{r} )^2 \ T_o[/tex]

let's calculate

       T = [tex]( \frac{155}{119.35} )^2 \ 385.3[/tex]

        T = 649.86 s    

2) The angular momentum is conserved because the system is isolated.

Let's look for kinetic energy

        K_total = 2 K = 2 (½ I w²)

        K_total = I 4π² / T²

        K_total = 2m r² 4 π² / T²

for r = 155 m

         K₀ = 8π² m r₀² / T₀²

for r = 119.35 m

          K_f = 8π² m r² / T²

the relationship is

        [tex]\frac{K_o}{K_f} = ( \frac{r_o \ T}{ r \ \ T_o} )^2[/tex]

        [tex]\frac{K_o}{K} = ( \frac{ 155 \ \ \ 649.86}{ 119.35 \ 385.3})^2[/tex]

       [tex]\frac{K_o}{K_f}[/tex] = 4.8

Question: A car with a mass of 800 g and velocity of 15 m/s collided with a truck moving in opposite direction with a velocity of 20 m/s, if the momentum is conserved and they both move with a common velocity of 10 m/s, what is the mass of the truck?

Answer:

0.133 kg

Explanation:

Applying the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')................... Equation 1

Where m = mass of the car, m' = mass of the truck, u = initial velocity of the car, u' = initial velocity of the truck, V = common velocity.

From the question,

Given: m = 800 g = 0.8 kg, u = 15 m/s, u' = -20 m/s, V = 10 m/s

Substitute these values into equation 2

(0.8*15)+(m'*20) = 10(0.8+m')

Solve for m'

12-20m' = 8+10m'

-20m'-10m' = 8-12

-30m' = -4

m' = -4/-30

m' = 0.133 kg

Answer:

1) [tex]I=1.8*10^{-6}\: W/m^{2}[/tex]  

2) [tex]E=0.037 \: V/m[/tex]

Explanation:

1)

The intensity equation is given by:

[tex]I=\frac{P}{4\pi r^{2}}[/tex]

Where:

[tex]I=\frac{20000}{4\pi (30000)^{2}}[/tex]

[tex]I=1.8*10^{-6}\: W/m^{2}[/tex]  

2)

Now, the intensity and the electric field are related as:

[tex] I=0.5c\epsilon_{0}E^{2}[/tex]

Here:

We need to solve it for E.

[tex]E= \sqrt{\frac{2I}{c\epsilon_{0}}}[/tex]

[tex]E= \sqrt{\frac{2(1.8*10^{-6})}{(3*10^{8})(8.85*10^{-12})}}[/tex]

[tex]E=0.037 \: V/m[/tex]

I hope it helps you!

Answer

the medium does not change the speed of the on they should change.

Explanation:

The speed of the waves is constant for a given medium, depending on the physical properties of the medium,

When a wave is strapped on a wall of a medium it does not change the properties of the medium, the wave changes direction, but since the medium does not change the speed of the on they should change.

An Particle a has Weston practical.

The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab).

According to the book Soil Mechanics(opens in new tab), scientists started putting together the laws governing friction in the 1400s.

However, because the interactions are so complex, characterizing the force of friction in various circumstances typically requires experiments and can't be derived from equations or laws alone. There are numerous exceptions to every frictional general rule.

Therefore, An Particle a has Weston practical.

To learn more about friction, refer to the link:

https://brainly.com/question/13000653

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Answer:

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years. The period of orbit for the Earth around the Sun is approximately 365 days; it takes 365 days for the Earth to complete a cycle.

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

100 Earth masses.

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

Answer:

+1.46

Explanation:

acellus

Answer:

the vertical acceleration of the case is 1.46 m/s

Explanation:

Given;

mass of the clarinet case, m = 3.07 kg

upward force applied by the man, F = 25.60 N

Apply Newton's second law of motion;

the upward force on the clarinet case = its weight acting downwards + downward force due to its downward accelaration

F = mg + m(-a)

the acceleration is negative due to downward motion from the top of the piano.

F = mg - ma

ma = mg - F

[tex]a = \frac{mg - F}{m} \\\\a = \frac{(3.07 \times 9.8) \ - \ 25.6}{3.07} \\\\a = 1.46 \ m/s^2[/tex]

Therefore, the vertical acceleration of the case is 1.46 m/s²

Answer:

The weight of water displace is equal to the weight of boat i.e, 200kg.

Explanation:

Answer:

Explanation:

No sound is heard , that means there is destructive interference at the place where sound is heard .

Path difference of the source of sound = 1.425 m - 1.230 m

= 0.195 m

Let frequency of sound be n .

wave length = velocity of sound at 0°C / n

λ = 330 / n

for destructive interference ,

path difference = ( 2m+1) λ /2 , where λ is wave length of sound.

0.195 m = ( 2m+1) λ /2

0.195 m = ( 2m+1)330 / 2n

2n = 1692.3 (2m+1)

If m = 0

n = 846 . which is nearest to given frequency of 993 Hz

So 993 Hz is the answer.

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

Solution :

Placing the[tex]$3 \ kg$[/tex] mass at the [tex]$\text{origin}$[/tex] and line up the square up with the axes.

[tex]$x_{cm} = \frac{\sum_i x_i m_i}{\sum_i m_i }$[/tex]

     [tex]$=\frac{1.5 a + 1.5a +0 +0}{7.5}$[/tex]

     [tex]$=\frac{3a}{7.5}$[/tex]

    [tex]$=\frac{2a}{5}$[/tex]

[tex]$y_{cm} = \frac{\sum_i y_i m_i}{\sum_i m_i }$[/tex]

     [tex]$=\frac{1.5 a + 1.5a +0 +0}{7.5}$[/tex]

     [tex]$=\frac{3a}{7.5}$[/tex]

    [tex]$=\frac{2a}{5}$[/tex]

Therefore,  r = [tex]$\sqrt2 \left(\frac{2a}{5}\right)$[/tex]

                           [tex]$=\frac{2 \sqrt2}{5}a$[/tex]

It s given that the side of the square is a = 32.2 cm

So, r [tex]$=\frac{2 \sqrt2}{5}a$[/tex]

       [tex]$=\frac{2 \sqrt2}{5}\times 32.2$[/tex]

       = 18.21 cm

So the distance of the 3 kg mass from the center of mass, r= 18.21 cm

The proper time between two events is measured by clocks at rest in a reference frame in which the two events occur in Nashville occur at the same coordinates. So, option d.

The perspective from which you perceive and measure things is known as a reference frame. It's applied to describe how an object is moving or where it is.

Here,

Depending on the frame of reference, the time elapsed between two occurrences may vary, according to the Theory of Special Relativity.

The duration between two events occurring in the rest frame, as measured from a reference frame in motion relative to the rest frame, will always be longer than the correct time. Time dilation is a phenomenon that develops in accordance with the relativity of space and time.

A single clock that is present for both occurrences can be used to determine the right time difference between them.

The appropriate time between two events is the amount of time that elapses within a frame in which the two events take place at the same location, to put it another way.

Hence,

The proper time between two events is measured by clocks at rest in a reference frame in which the two events occur in Nashville occur at the same coordinates. So, option d.

To learn more about frame of reference, click:

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Answer:

F = 160.0 N

Explanation:

Given: Soccer payer with a mass = 80 kg, force = 20 N

To find: force

Formula: [tex]F=ma[/tex]

Solution: It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.

F = m × a

F = 20 kg - 10 = 2  

F = 80 × 2 = 160

F = 160.0 N

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

Answer:

A) s' = 18.85 cm

B) Height is 0.739 mm

C) the image is inverted.

Explanation:

We are given;

Diameter; D = 9 cm

Radius; R = d/2 = 9/2 = 4.5 cm = 0.045 m

Refractive Index of glass; n₂= 1.55

Height of object; y = 1.52 mm = 0.00152 m

Object distance s = 25 cm = 0.25 m

Now, Refractive index of air is 1 from online values.

Thus; n_1 = 1

A) To find the position of the image of the arrow formed by paraxial rays incident on the convex surface which is denoted by s', we will use the formula;

((n_1)/s) + n₂/s' = (n₂ - n_1)/R

Plugging in the relevant values, we have;

(1/0.25) + 1.55/s' = (1.55 - 1)/0.045

(1/0.25) + 1.55/s' = 12.222

1.55/s' = 12.222 - (1/0.25)

1.55/s' = 12.222 - 4

1.55/s' = 8.222

s' = 1.55/8.222

s' = 0.1885 m

s' = 18.85 cm

B) We will use the magnification formula to calculate the height of the image formed by paraxial rays incident on the convex surface denoted by y';

m = y'/y = -n_1•s'/n_2•s

Thus;

y' = -(y × n_1 × s')/(n_2•s)

y' = -(0.1885 × 1 × 0.00152)/(1.55 × 0.25)

y' = -0.739 mm

Height is 0.739 mm inverted.

C) Since the height of y' is negative, then it means the image is inverted.

Answer:

1) ngle of incidence and reflection are equal,  light carries does not change

2) the angle of this line with respect to the surface is 90º

3) protractor

4)    n₂  sin θ₂ = n_1 sin θ₁,  light ray must have a greater angle than the incident ray ,

Explanation:

1) When light falls on a reflective surface, the angle of incidence and reflection are equal and as it travels in the same medium, the speed that the light carries does not change

2) The normal is a line perpendicular to the point of incidence of light, so the angle of this line with respect to the surface is 90º

3) Angles are measured with a protractor

4) When light passes from one medium to another, the speed of the ray changes due to the difference in the refractive index in each medium, due to this change in speed the transmitted light ray must have a greater angle than the incident ray , since the speed increases as the density of the medium decreases

           [tex]\frac{sin \theta _2}{ sin \theta_1} = \frac{v_2}{v_1}[/tex]

          [tex]\frac{c}{v_2} \ sin \theta_2 = \frac{c}{v_1} \ sin \theta_1[/tex]

          n₂  sin θ₂ = n_1 sin θ₁

Answer:

All magnets have two poles: the North Pole and the South Pole.

Magnets attract ferromagnetic materials such as iron, nickel, and cobalt.

The magnetic force of a magnet is stronger at its poles than in the middle.

A freely suspended magnet always points in North-South direction.

Hope this helps

Answer:

The pressure of the solid on the surface depends on the area of contact. The area of contact between the two surfaces. The greater the force or the smaller the area the greater the pressure.

(credits to the rightful owner for these answers :)