1. What are the two (2) classes of matter?
A. Atom and molecule
B. Element and compound
C. Plant and animal cells
D. Substance and mixture
2. Which is true regarding water?
A. Compound of element
B. Element of gases
C. Mixture of
gases
D. Substances of gases
3. What is the difference between a substance and a mixture?
A. Substance can be separated while mixture cannot be separated.
B. Substance has many components while mixture has one only.
C. Substance is heterogeneous while mixture is homogeneous.
D. Substance is pure while mixture is impure.

Answers

Answer 1

Answer:

substance and mixture


Related Questions

my mom is dum and anoying asl, what should i do?

Answers

Answer:

stop being an annoying child and appreciate everything your mother does for you because she cares for you

Explanation:

its the right thing to do

Be thankful for everything your mom does bc one day she wont be here any more! Love her while you can

What are two ways that an object can have kinetic energy?

Answers

Answer:

The object has to have mass and speed

Explanation:

You can increase both speed and mass to increase the kinetic energy, hope this answers your question.

Happy Halloween!

If a projectile hits a stationary target, and the projectile continues to travel in the same direction, the mass of the projectile is less than the mass of the target. the mass of the projectile is equal to the mass of the target. the mass of the projectile is greater than the mass of the target. nothing can be said about the masses of the projectile and target without further information. this is an unphysical situation and will not actually happen.

Answers

The correct arrangement of the question is;

If a projectile hits a stationary target, and the projectile continues to travel in the same direction,

A) the mass of the projectile is less than the mass of the target.

B) the mass of the projectile is equal to the mass of the target.

C) the mass of the projectile is greater than the mass of the target.

D) nothing can be said about the masses of the projectile and target without further information.

E) this is an unphysical situation and will not actually happen.

Answer:

Option C: The mass of the projectile is greater than the mass of the target.

Explanation:

We want to find what will happen when a projectile continues in motion after it hits a target.

Now, for the projectile to keep moving in that direction after it hits the target, it means it had a force bigger than the force of the target to overpower it and force it to move with it.

Now, from law of inertia, Force = ma.

But in this case acceleration is 0 because the speed of the projectile is constant.

Thus, the force depends on the mass. So for a higher force, the mass of the projectile has to be more than that of the stationary object.

Thus, option C is correct

A squirrel drops an acorn from a tree. Starting from rest, it reaches the ground 22.0 meters
below. What is the acorn's velocity as it hits the ground?

Answers

Does it not tell you how long it took it to reach the ground? Constant Velocity should be distance over time

The elements in Groups 3 through 12 of the periodic table are the ______.

Answers

Answer:

Transition Metals

Explanation:

__________________________

What is the direction of the magnetic field if an electron moving in the positive x direction experiences a magnetic force in the positive z direction

Answers

Given :

An electron moving in the positive x direction experiences a magnetic force in the positive z direction.

To Find :

The direction of the magnetic field.

Solution :

We know, force is given by :

[tex]\vec{F}=q(\vec{v}\times \vec{B)}[/tex]

Here, q = -e.

[tex]\vec{F}=(-e)(\vec{v}\times \vec{B)}\\\\\hat{k}=(-e)(\hat{i}\times \vec{B})[/tex]

Now, for above condition to satisfy :

[tex]\hat{i}\times \vec{B}=-\hat{k}[/tex]

So, [tex]\vec{B}=-\hat{j}[/tex]

Therefore, direction of magnetic field is negative y direction.

Hence, this is the required solution.

If the speed of a car is increased by 75%, by what factor will its minimum braking distance be increased, assuming all else is the same

Answers

Answer:

breaking distance will increase by a factor 3.0625

Explanation:

From Newton's equation of motion, we can say that;

v² = u² + 2as

Where initial velocity is zero, we have;

v² = 2as

s = v²/2a

Where s is the distance and v is the final speed.

We will assume the deceleration(negative acceleration) is the same value,

Now, we see that the distance is directly proportional to the square of the velocity.

Now, 75% increase in speed means it has increased by a factor of 1.75

Thus means;

1.75²v² is directly proportional to the 1.75²d

Distance =

1.75²v² = 3.0625d

Thus, breaking distance will increase by a factor 3.0625

How did the Mayflower Compact influence colonists’ views on government?

Answers

Answer:

It demonstrated that the colonists were capable of local, self-government.  

Explanation:

this is the correct answer because i have already done this

King crimson vs DIO? for science of course. and for an essay

Answers

Answer:

king crimson

Explanation:

bc

Explanation:

It could go either way.

King crimsons ability is to see into the future and erase something, changing the outcome, while The Worlds ability is to Stop time. I believe DIO would beat Diavolo,but thats if certain requirements are met.Like, the fight being at night, but if Diavolo got a good combo of attacks on DIO, theres a high chance he would kill DIO, but DIO could end the fight in seconds by stopping time and killing him in his Stopped time, or his World, hope this helped

When a stretched rubber band snaps back it has increase

thermal energy.

potential energy.

kinetic energy.

elastic energy.

Answers

It increases the kinetic energy

Answer:

Kinetic

Explanation:

Because it has a force pushing on it

Explain why atoms only emit certain wavelengths of light when they are excited. Check all that apply. Check all that apply. Electrons are allowed "in between" quantized energy levels, and, thus, only specific lines are observed. The energies of atoms are not quantized. When an electron moves from one energy level to another during absorption, a specific wavelength of light (with specific energy) is emitted. Electrons are not allowed "in between" quantized energy levels, and, thus, only specific lines are observed. When an electron moves from one energy level to another during emission, a specific wavelength of light (with specific energy) is emitted. The energies of atoms are quantized.

Answers

Answer:

Explanation:

Electrons are allowed "in between" quantized energy levels, and, thus, only specific lines are observed. FALSE. The specific lines are obseved because of the energy level transition of an electron in an specific level to another level of energy.

The energies of atoms are not quantized. FALSE. The energies of the atoms are in specific levels.

When an electron moves from one energy level to another during absorption, a specific wavelength of light (with specific energy) is emitted. FALSE. During absorption, a specific wavelength of light is absorbed, not emmited.

Electrons are not allowed "in between" quantized energy levels, and, thus, only specific lines are observed. TRUE. Again, you can observe just the transition due the change of energy of an electron in the quantized energy level

When an electron moves from one energy level to another during emission, a specific wavelength of light (with specific energy) is emitted. TRUE. The electron decreases its energy releasing a specific wavelength of light.

The energies of atoms are quantized. TRUE. In fact, the energy of all subatomic, atomic, and molecular particles is quantized.

The reason why atoms emit only specific wavelengths is because the energy levels in atoms are quantized.

Max Plank introduced the idea of quantization of energy in the early 1900s. He introduced the idea that energy can only take on certain specific values. This idea was later extended to atoms by Neils Bohr.

The following statements explain why atoms only emit certain wavelengths of light when they are excited;

 When an electron moves from one energy level to another during emission, a specific wavelength of light (with specific energy) is emitted. Electrons are not allowed "in between" quantized energy levels, and, thus, only specific lines are observed. The energies of atoms are quantized.

Learn more: https://brainly.com/question/24381583

I need help with this answer

Answers

decomposition

A decomposition reaction is just the opposite of combination reaction

the peripheral nervous system is responsible for both sending and receiving signals to and from the brain

Answers

Answer:

its true trust me

Explanation:

Answer: true

Explanation: edge

Which statements about potential energy are true?
▫ Gaining potential energy is always associated with a force field.
▫ A change in position always means that an object gains potential energy.
▫ There's only one kind of potential energy.
▫ Some kinds of potential energy are related to electric forces exerted by atoms and molecules.​

Answers

Answer:

the answer is 1 and 4

Explanation

Plato users

For the potential energy, statement 1 and statement 4 are correct.

The potential energy of the object the energy of the object in its steady position. When the object is at rest, the energy of the object in that condition is called potential energy.

Let us consider an electron having charge [tex]e[/tex] is moving the distance [tex]d[/tex] in uniform electric field E.

Its potential energy can be written as,

[tex]P = eEd[/tex]

Where P is the potential energy and E is the electric field.

Hence, the potential energy of the electron is associated with the electric field.

The electric force can be written as,

[tex]F =eE[/tex]

Where [tex]F[/tex] is the electric force, [tex]E[/tex] is the electric field and [tex]e[/tex] is the charge on the electron.

So, the potential energy can be written as,

[tex]P=Fd[/tex]

Hence, the potential energy is related to electric force.

For more information, follow the link given below.

https://brainly.com/question/1413008.

A microwave oven operates at 2.50 GHzGHz . What is the wavelength of the radiation produced by this appliance? Express the wavelength numerically in nanometers.

Answers

Answer:

The wavelength is [tex]\lambda  =  1.2  * 10^8 nm[/tex]

Explanation:

From the question we are told that

   The frequency of operation of the microwave is  [tex]f =  2.50 GHz  =  2.50 *10^{9} \ Hz[/tex]

     Generally the wavelength is mathematically represented as

          [tex]\lambda  =  \frac{c}{f}[/tex]

Here c is the speed of light with value [tex]c =  3.0 *10^{8} \  m/s[/tex]

So  

         [tex]\lambda  =  \frac{3.0 *10^{8}}{  2.50 *10^{9}}[/tex]

=>       [tex]\lambda  =  0.12 \  m [/tex]

converting to nanometer

           [tex]\lambda  =  1.2  * 10^8 nm[/tex]

Street light in many communities are sodium vapor lamps. These lamps visually have an orange-yellow tint. The visible emission spectrum for sodium shows that two prominent bands are detected within the visible color change. These light waves are both yellow and have wavelengths of about 590nm. This explains why the light produced from sodium vapor lamps would appear yellow and not white. in comparison, mercury vapor lamps produce a blue-colored light due to intense light emission from the mercury atoms that have a wavelength of about 434nm. Without any calculation, which element would you expect to produce higher energy photons in the visible part of spectrum?

Answers

Answer:

Mercury light

Explanation:

The energy of a photon of light is inversely proportional to it's wavelength.

Therefore, as the wavelength increases, the energy decreases likewise.

This implies that the Mercury light having a lesser wavelength will possess more energy.

Based on the information in the table, which elements are most likely in the same periods of the periodic table?

Answers

Answer:

Just to help, periods on the periodic table are those running horizontally from left to right

Answer:

The answer is A.Boron and carbon are likely together in one period because they have very close atomic numbers, while gallium and germanium are likely together in another period because they have very close atomic numbers.

Explanation:

just took test

Two students measured the length of the same stick, each using a different 30 cm ruler. One student reported a length of 22 cm, and the other reported a length of 8 cm. The most likely explanation for the difference in the reported values is that one —

A. *student improperly read the ruler

B. ruler was metal and the other ruler was plastic

C. student viewed the ruler from a different angle

D. ruler was constructed with nonstandard cm marks

Answers

Answer:

C. student viewed the ruler from a different angle

Explanation:

It is the problem of viewing the scale from different sides or angles. If we assume the actual length of the stick to be 22 cm. Then the first student measured the length by reading the values from 1 cm towards 22 cm on the scale. While, the second student measured the length of the stick by reading the values from the other side or the other angle of the scale, that is, from 30 cm mark towards 1 cm. And in that case the the length of the 22 cm long stick will appear  as:

30 cm - 22 cm = 8 cm

Therefore, the second student read 8 cm on scale. So, the correct option is:

C. student viewed the ruler from a different angle

A plane travelling at 100 m/s accelerates at 5 m/s² for a distance of 125 m. What is the final velocity of the plane?

Answers

Analyzing the question:                                                                                        

We are given:

initial velocity (u) = 100 m/s

final velocity (v) = v m/s

distance (s) = 125 m

acceleration (a) = 5 m/s²

Solving for Final Velocity (v):                                                                              

from the third equation of motion:

v² - u² = 2as

v² - (100)² = 2(5)(125)

v² - 10000 = 1250

v² = 1250 + 10000

v² = 11250

v = 106.06 m/s

Given a force of 10 N and an acceleration of 5 m/s2, what is the mass?

Answers

Answer:

2kg

Explanation:

i think i found it yous welcom

A man walking at 0.5 m/s increases his pace to 0.8 m/s in 3 seconds. What is his acceleration?

Answers

Acceleration = (change in speed) / (time for the change)

Change in speed = (New speed) - (old speed)

Change in speed = (0.8 m/s - 0.5 m/s) = 0.3 m/s

Time for the change = 3 seconds

Acceleration = (0.3 m/s) / (3 s)

Acceleration = 0.1 m/s²

(a hair more than 1 percent of 1 G.)

Momentum of the 2 kg mass moving with velocity 10 m/s is *

A. 2 kg*m/s
B. 20 kg*m/s
C. 200 kg*m/s
D. 20000 kg*m/s

Answers

20 kg*m/s because there is 2 kg mass and 10 m/s so you can multiply.

A mass (m = 30 g) falls onto a spring (k = 7.3 N/m) from a height (h = 25 cm). The spring compresses an additional amount x before temporarily coming to a stop. What is the value of x?

Answers

Answer:

x₁ = 0.1878 m

Explanation:

For this exercise we will use conservation of energy

starting point. Highest point

         Em₀ = U = m g h

final point. Lowest point with fully compressed spring

         Em_f = K_e + U

         Em_f = ½ K x² + m g x

         

energy is conserved

         Em₀ = Em_f

        m g h = ½ K x² + m g x

       ½ K x² + mg (x- h) = 0

         

let's substitute

       ½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0

        3.65 x² + 0.294 (x- 0.25) = 0

        x² + 0.080548 (x- 0.25) = 0

        x² - 0.020137 + 0.080548 x = 0

        x² + 0.080548 x - 0.020137 = 0

let's solve the quadratic equation

      x = [0.080548 ±√ (0.080548² + 4   0.020137)] / 2

      x = [0.080548 ± 0.29502] / 2

      x₁ = 0.1878 m

      x₂ = -0.1072 m

These are the compression and extension displacement of the spring

A force of 41 N acts on an object which has a mass of 2.4 kg. What acceleration (in m/s2) is produced by the force

Answers

Answer:

The acceleration is [tex] a =  17.083 \ m/s^2 [/tex]

Explanation:

From the question we are told that

   The force is [tex]F =  41 \  N[/tex]

     The mass of the object is [tex]m  =  2.4 \  kg[/tex]

Generally the force is mathematically represented as

        [tex]F  =  m*  a[/tex]

=>      [tex] 41  = 2.4*  a[/tex]

=>      [tex] a =  17.083 \ m/s^2 [/tex]

If it takes you 5 minutes to dry your hair using a 1200-W hairdryer plugged into a 120-V power outlet, how many Coulombs of charge pass through your hair dryer

Answers

Answer:

The charge pass through your hair dryer is 3000 C.

Explanation:

Given that,

Power = 1200 W

Voltage = 120 V

Flow time = 5 min

We need to calculate the current

Using formula of power

[tex]P=VI[/tex]

[tex]I=\dfrac{P}{V}[/tex]

Put the value into the formula

[tex]I=\dfrac{1200}{120}[/tex]

[tex]I=10\ A[/tex]

We need to calculate the charge pass through your hair dryer

Using formula of current

[tex]I=\dfrac{Q}{t}[/tex]

[tex]Q=It[/tex]

Put the value into the formula

[tex]Q=10\times5\times60[/tex]

[tex]Q=3000\ C[/tex]

Hence, The charge pass through your hair dryer is 3000 C.

A coin rests on a record 0.15 m from its center. The record turns on a turntable that rotates at variable speed. The coefficient of static friction between the coin and the record is 0.30.

Required:
What is the maximum coin speed at which it does not slip?

Answers

Answer:

0.66m/s

Explanation:

We are expected to solve for the velocity with no slip condition

we know that the expression that relate coefficient of friction and velocity is given as

μs = v^2/rg

Given

coefficient of friction μs = 0.3

radius r= 0.15

assume g=9.81m/s^2

substituting into the expression we have

0.3= v^2/0.15*9.81

v^2=0.3*0.15*9.81

v^2=0.44145

v=√0.44145

v=0.66

therefore the velocity is 0.66m/s

Under the assumption that the beam is a rectangular cantilever beam that is free to vibrate, the theoretical first natural frequency of the beam in terms of the length, L, width, b, thickness, h, density, p, and Young's Modulus, E, in Hertz is given by:

fn= h/2πL^2 √E/rho

The density of steel used in the beam is 7800 kg/m^3, and its Young's Modulus is 210 GPa. You measure the dimensions of the clamped steel beam with a set of calipers and gather the following data:

L = 233.5 mm, b = 24.9 mm, h = 3.3 mm

The calipers used to measure the dimensions of beam have a resolution of 0.01 mm and therefore have an uncertainty of +0.005 mm.

Required:
a. What is the uncertainty of the natural frequency (in Hz) due to the uncertainty of the length measurement?
b. What is the uncertainty of the natural frequency (in Hz) due to the uncertainty of the width measurement?
c. What is the uncertainty of the natural frequency (in Hz) due to the uncertainty of the thickness measurement?
d. What is the total uncertainty of the natural frequency due to the beam measurements (in Hz)?
e. What is the theoretical first natural frequency of the beam including the measurement uncertainty?

Answers

Answer:

a) Δf = 0.7 n , e)   f = (15.1 ± 0.7) 10³ Hz

Explanation:

This is an error about the uncertainty or error in the calculated quantities.

Let's work all the magnitudes is the SI system

The frequency of oscillation is

        f = n / 2π L² √( E /ρ)

where n is an integer

Let's calculate the magnitude of the oscillation

       f = n / 2π (0.2335)² √ (210 10⁹/7800)

       f = n /0.34257 √ (26.923 10⁶)

       f = n /0.34257    5.1887 10³

       f = 15.1464 10³ n

a) We are asked for the uncertainty of the frequency (Df)

       Δf = | df / dL | ΔL + df /dE ΔE + df /dρ Δρ

in this case no  error is indicated in Young's modulus and density, so we will consider them exact

       ΔE = Δρ = 0

       Δf = df /dL  ΔL

       df = n / 2π   √E /ρ   | -2 / L³ | ΔL

       df = n / 2π 5.1887 10³ | 2 / 0.2335³) 0.005 10⁻³

       df = n 0.649

Absolute deviations must be given with a single significant figure

        Δf = 0.7 n

b, c) The uncertainty with the width and thickness of the canteliver is associated with the density

 

In your expression there is no specific dependency so the uncertainty should be zero

The exact equation for the natural nodes is

          f = n / 2π L² √ (E e /ρA)

where A is the area of ​​the cantilever and its thickness,

In this case, they must perform the derivatives, calculate and approximate a significant figure

        Δf = | df / dL | ΔL + df /de  Δe + df /dA  ΔA

        Δf = 0.7 n + n 2π L² √(E/ρ A) | ½  1/√e | Δe

               + n / 2π L² √(Ee /ρ) | 3/2 1√A23  |

the area is

        A = b h

        A = 24.9  3.3  10⁻⁶

        A = 82.17 10⁻⁶ m²

        DA = dA /db ΔB + dA /dh Δh

        dA = h Δb + b Δh

        dA = 3.3 10⁻³ 0.005 10⁻³ + 24.9 10⁻³ 0.005 10⁻³

        dA = (3.3 + 24.9) 0.005 10⁻⁶

        dA = 1.4 10⁻⁷ m²

let's calculate each term

         A ’= n / 2π L² √a (E/ρ A) | ½ 1 /√ e | Δe

         A ’= n/ 2π L² √ (E /ρ)      | ½ 1 / (√e/√ A) |Δe

        A ’= 15.1464 10³ n ½ 1 / [√ (24.9 10⁻³)/ √ (81.17 10⁻⁶)] 0.005 10⁻³

        A '= 0.0266  n

        A ’= 2.66 10⁻² n

       A ’’ = n / 2π L² √ (E e /ρ) | 3/2  1 /√A³ |

       A ’’ = n / 2π L² √(E /ρ) √ e | 3/2  1 /√ A³ | ΔA

       A ’’ = n 15.1464 10³ 3/2 √ (24.9 10⁻³) /√ (82.17 10⁻⁶) 3 1.4 10⁻⁷

       A ’’ = n 15.1464 1.5 1.5779 / 744.85 1.4 10⁴

       A ’’ = 6,738 10²

we write the equation of uncertainty

     Δf = n (0.649 + 2.66 10⁻² + 6.738 10²)

The uncertainty due to thickness is

    Δf = 3 10⁻² n

The uncertainty regarding the area, note that this magnitude should be measured with much greater precision, specifically the height since the errors of the width are very small

     Δf = 7 10² n

 d)    Δf = 7 10² n

e) the natural frequency n = 1

       f = (15.1 ± 0.7) 10³ Hz

Vector A has a magnitude of 6.0 m and points 30° north of east. Vector B has a magnitude of 4.0 m and points 30° west of south. The resultant vector A+ B is given by

Answers

Answer:

The resultant vector [tex]\vec R = \vec A+\vec B[/tex] is given by [tex]\vec R = 3.196\,\hat{i}-0.464\,\hat{j}\,\,\,[m][/tex].

Explanation:

Let [tex]\vec A = 6\cdot (\cos 30^{\circ}\,\hat{i}+\sin 30^{\circ}\,\hat{j})[/tex] and [tex]\vec B = 4\cdot (-\sin 30^{\circ}\,\hat{i}-\cos 30^{\circ}\,\hat{j})[/tex], both measured in meters. The resultant vector [tex]\vec R[/tex] is calculated by sum of components. That is:

[tex]\vec R = \vec A+\vec B[/tex] (Eq. 1)

[tex]\vec R = 6\cdot (\cos 30^{\circ}\,\hat{i}+\sin 30^{\circ}\,\hat{j})+4\cdot (-\sin 30^{\circ}\,\hat{i}-\cos 30^{\circ}\,\hat{j})[/tex]

[tex]\vec R = (6\cdot \cos 30^{\circ}-4\cdot \sin 30^{\circ})\,\hat{i}+(6\cdot \sin 30^{\circ}-4\cdot \cos 30^{\circ})\,\hat{j}[/tex]

[tex]\vec R = 3.196\,\hat{i}-0.464\,\hat{j}\,\,\,[m][/tex]

The resultant vector [tex]\vec R = \vec A+\vec B[/tex] is given by [tex]\vec R = 3.196\,\hat{i}-0.464\,\hat{j}\,\,\,[m][/tex].

Magnetic attraction is one of the chemical properties of matter *

True
False

Answers

False, because it can be observed, and does not have a chemical reaction that occurs. There is no chemical change taking place, therefore, the answer is false and it is a physical property.

While making some observations at the top of the 66 m tall Astronomy tower, Ron
accidently knocks a 0.5 kg stone over the edge. How long will a student at the bottom
have to get out of the way before being hit?

Answers

Analysing the question:

Since the stone was dropped, there was no initial velocity applied on it and hence it's initial velocity of the stone is 0 m/s

We are given:

height of the tower (h) = 66 m

mass of the stone (m) = 0.5 kg

initial velocity of the stone (u) = 0 m/s

time taken by the stone to reach the ground (t) = t seconds

acceleration due to gravity = 10 m/s²

** Neglecting air resistance**

Finding the time taken by the stone to reach the ground:

from the second equation of motion

h = ut + 1/2at²

replacing the variables

66 = (0)(t) + 1/2 (10)(t)²

66 = 5t²

t² = 13.2

t = 3.6 seconds

I initially wanted to subtract the height of the student from the height of the tower since the time i calculated is the time taken by the stone to reach the ground and that means that the stone has already hit the student before 3.6 seconds

but since we were NOT given the height of a student, the person who posed this question wants the time taken by the stone to reach the ground and that is what we solved

Other Questions
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